The impedance of the circuit is 193.9 ohms. The result is obtained by dividing the applied voltage by the total current.
What is the impedance of a parallel circuit?In a parallel RC (resistance and reactance) circuit, impedance can be expressed as
[tex]Z = \frac{RX_{c} }{\sqrt{R^{2} + X_{c}^{2} } }[/tex]
Z = V/I
Where
Z = impedanceR = resistanceXc = capacitive reactanceV = voltageI = total currentWe have:
R = 470 ohmsXc =330 ohmsV = 470 voltsThe impedance should be found by determining the branch currents and the total current.
The branch currents are
Ir = V/R = 470/470 = 1 A
Ic = V/Xc = 470/330 = 1.424 A
In the parallel circuit, the total current is
I = Ir + Ic = 1 + 1.424 = 2.424 A
By using the total current, the impedance is
Z = V/I
Z = 470/2.424
Z = 193.9 ohms
Hence, the impedance of the parallel RC circuit is 193.9 ohms.
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A uniform solid 5.25-kg cylinder is released from rest and rolls without slipping down an inclined plane inclined at 18° to the horizontal. How fast is it moving after it has rolled 2.2 m down the plane? O 3.0 m/s O 4.3 m/s O 5.2 m/s O 3.7 m/s O 2.6 m/s
A uniform solid 5.25-kg cylinder is released from rest and rolls without slipping down an inclined plane inclined at 18° to the horizontal. Its speed while rolling down is 3.0 m/s.
The mass of the solid cylinder, [tex]m=5.25 kg[/tex]
The inclination of the plane, θ=[tex]18^{0}[/tex]
The speed of a solid cylinder rolling down an inclined surface is calculated using the following formula:
The kinetic energy of the cylinder
[tex]K=3/5 mgh[/tex]
[tex]1/2mv^{2} =3/5 mgh[/tex]
[tex]v=\sqrt{6gh/5}[/tex]
Substituting for the values h as [tex]h=mgcos[/tex]θ
we get the speed as
[tex]v=3.0 m/s[/tex]
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4. A 20-kg box sits on an incline of 30° from the horizontal. The coefficient of friction between the box and the incline is o.30. Find the acceleration of the box down the incline.
The box accelerates down the incline at 2.4m/s^2.
How do you find the acceleration of an incline box?A mass m particle will slide down a smooth inclined plane if it is released onto it with a friction force F=0. We resolve in the direction of motion to determine the particle's acceleration as it slides. F = ma, mg cos(90) = ma, gg cos(90) = a, gg sin() = a.
By using zigmaFx = max, we will determine the acceleration.
However, we must first determine the friction force Ff.
Because cos 30 degree = 0.866 and Fy = ma y = 0 result in FN - 0.87mg = 0, we may calculate FN as (0.87)(20Kg)(9.81 m/s2) = 171N.
From Ff = mue FN = 0.30)(171 N)= 51N, we can now calculate Ff.
We get Ff - 0.50mg = ma x 51N - (0.50)(20)(9.81)N = (20kg)(ax) from the expression zigmaFx = max, where ax = -2.35 m/s2.
At 2.4 m/s2, the box quickens its descent of the hill.
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Strength training is beneficial because it decreases your risk of injury. Which statement BEST describes why this is true? A. Muscular fitness training can prevent or improve diabetes and sarcopenia. B. Muscular fitness training increases muscle mass, which increases your metabolism. C. Muscular fitness training strengthens tendons, ligaments, and cartilage. D. Muscular fitness training improves self-image and athletic performance. Please select the best answer from the choices provided. A B C D
Answer: B. Muscular fitness training increases muscle mass, which increases your metabolism
1. If a car travels 40m in 30 seconds how fast is it
going?
Answer: 80 mph
Explanation:
how much work must the spacecraft engines perform to move the spacecraft to a circular orbit that is 4500 km above the surface? express your answer with the appropriate units.
The amount of work that the engine of the spacecraft must do to move above the circular orbit is 1.48 x 10⁻¹⁷ mM (Joules).
Why is an orbit circular?The established fact that the gravitational attraction between two objects varies also on square of their distance leads to the geometry of planetary orbits. The attractive product of two items decreases to a fourth of its initial amount when the distance between them is doubled.
Briefing:W = Fd
where;
F is the spacecraft's gravitational field,
d is the displacement of the spacecraft.
The spacecraft's gravitational pull is specified as;
F = GmM/R²
where;
m is the planet's mass (for the circular orbit)
M is the spacecraft's mass.
R is the spacecraft's displacement.
The tasks that the spacecraft must complete are as follows:
W = FR
W = GmM/R² x R
W = GmM/R
W = (6.67 x 10⁻¹¹ x mM) / (4500000)
W = 1.48 x 10⁻¹⁷ mM (Joules)
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A parallel-plate air-filled capacitor is being charged as in the figure (Figure 1) . The circular plates have radius 4.00 cm , and at a particular instant, the conduction current in the wires is 0.570 A .
a) What is the displacement current density jD in the air space between the plates?
b)What is the rate at which the electric field between the plates is changing?
c) What is the induced magnetic field between the plates at a distance of 1.93 cm from the axis?
d) What is the induced magnetic field between the plates at a distance of 1.10 cm from the axis?
a) Displacement current density for the capacitor is 113.4 A/m²
b) Rate of change of the electric field is 1.48157826 V/m.s
c) Magnetic field between plates at r of 1.93 cm is 5.563×10⁻6 Tesla
d) Magnetic field between plates at r of 1.10 cm is 7.833 x 10-7 Tesla
Since we are given the radius of a parallel-plate capacitor which is 4.00 cm( 0.04 m) and the Conduction current = Ic = 0.570 A .we know the formula for the Displacement current density is
JD = Id/A, where Id is the conduction current and A is the area of the capacitor, and A= πr² = π(0.04)²= 0.005024 m². As we know conduction current has equal displacement between the capacitor plates so Id = Ic
JD = 0.570/0.005024 = 113.4 A/m²
For the second case, we know the rate of change of the electric field is:
dE/dt = JD/ε₀ , where JD is the displacement current density and ε₀ is the permittivity of free space ( 8.854×10⁻¹² C²/N.m²)
so, dE/dt = 113.4/8.854×10⁻¹² =1.48157826 V/m.s
for the third case, the formula for The induced magnetic field between the plates will be :
B = (μ₀/2)*JD*r, μ₀ is the permeability of free space(4π×10⁻⁷ T.m/A)and r is the distance from the axis.
B = (4π×10⁻⁷/2)*113.4 *0.01953
B = 5.563× 10⁻⁶ Tesla ,and for the last case, for the radius of 1.10 cm (0.011 m)
B = (μ₀/2)*JD*r
B = (4π×10⁻⁷/2)*113.4 *0.011
B = 7.833 x 10⁻⁷ Tesla
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monochromatic light falls on two very narrow slits 0.044 mm apart. successive fringes on a screen 6.30 m away are 8.9 cm apart near the center of the pattern. part a determine the wavelength of the light.
The wavelength of the light is 6.21 × 10⁻⁷ m.
Single-slit diffraction has an equation
d sin θ = m λ
where
d = the width of slits = 0.044 mm = 4.4 × 10⁻² mm = 4.4 × 10⁻⁵ mm = the ordeFor a small angle, sin θ = tan θ.
θ is the angle where the opposite of the angle is the width apart near the center of the pattern (x) and the adjacent is the distance between the screen from the slits (L). So [tex]tan \: \theta = \frac{x}{L}[/tex]
x = 8.9 cm = 8.9 × 10⁻³ mL = 6.30 md sin θ = m λ
d tan θ = m λ
[tex]d \: \frac{x}{L} \:=\: 1 \times \lambda[/tex]
[tex]\lambda \:=\: 4.4 \times 10^{- 5} \times \frac{8.9 \times 10^{- 2}}{6.3}[/tex]
λ = 4.4 × 10⁻⁵ × 1.41 × 10⁻²
λ = 6.21 × 10⁻⁷ m
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supose that a student pulls with two large forces in order to life a 1 kg book by two cables if cables make 1 degree angle with horizontal then what is tension in the cable
If a student uses two strong forces to lift a 1 kg book using two cables, the tension in the cable will be 562.1 N if the cables are at a 1 degree angle with the horizontal.
Tension is a pulling force that operates in one dimension along the cables' axes in the opposite direction from the direction of the applied force. The combined weight of the elevator box and the person riding inside it, in the case of an elevator, provides the pulling force in the cables is called as Tension.
There are four basic interactions that encompass all known forces in the cosmos. The interactions between subatomic particles are caused by the strong and weak forces, which only operate over very small distances.
F1 sin(tetha)+F2 sin(tetha) = F3
F1 cos(tetha) = F2cos(tetha)
2F1 sin (tetha) = 2*9.81
F1 sin (1) = 9.81
F1 = 9.81/sin(1)
=562.1N
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how does the image distance (the distance from the lens to the focused image) change with the object distance (the distance from psy to the lens?)
Image distance changes with change in object distance.
What is object and image distance?
The object distance is the distance of the object to the center line of the lens
The image distance is the distance of the image to the center line of the lens
Now lets discuss the image variation with change in distance:
As the distance between an object and a lens is increased, the image size decreases. This is due to the fact that the light rays from the object are diverging more at a greater distance, and thus the lens is not able to focus them as much. The result is a smaller image.
Moving the object further from the lens causes the image to become smaller and closer to the lens. The image becomes smaller and smaller as we move the object further and further away. It will move closer and closer to the focal point of the image as it approaches.
A lower distance between an object and a lens can increase the size of an image.
In other words, as the object distance decreases , the image distance increases; in other words, the image height rises as well.
When the distance of an object from one’s eye is increased, the image distance remains the same as the original size of the image.
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Find the magnitude of the acceleration of the block after the system is released from rest.
Express your answer in terms of the variables , , and appropriate constants.
ANSWER:
ablock = 3.27
The magnitude of the acceleration of the block after the system is released from rest is: ablock = 3.27
What is magnitude?
Just as the magnitude of an earthquake indicates its strength, the magnitude of a mathematical term indicates its magnitude. In mathematics, this means how far a mathematical term is from zero.
For numbers like 1, 2, 3, the magnitude is simply the number itself. If the number is negative, the magnitude is the absolute value of the number. For example, the magnitude of 10 is 10. The magnitude of -10 is the absolute value of -10, which is 10. In both cases, the magnitude is the distance from zero of the mathematical term. Both 10 and -10 are 10 distances from zero.
Thus, The magnitude of the acceleration of the block after the system is released from rest is: ablock = 3.27
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an lrc series circuit consists of an 85.0- ω resistor, a 14.0-μf capacitor, a 1.50-mh inductor, and a variable frequency ac source of voltage amplitude 13.25 v. at what angular frequency will the inductive reactance be 4.00 times as large as the capacitive reactance?
The inductive reactance is 4.00 times as large as the capacitive reactance is 10.1 Hz or 6.26 radians/sec.
What is inductive reactance?
The resistance provided by the inductor inside an AC circuit to a flow of ac current is known as inductive reactance. Its measurement unit is the ohm (Ω), and its symbol is (XL). For lower frequencies, inductive reactance is typically low, and for higher frequencies, it is high. However, it is insignificant for constant DC current.
The angular frequency (ω) at which the inductive reactance (XL) is 4.00 times as large as the capacitive reactance (XC) is given by the following equation:
XL = 4.00 XC
ωL= 4.00 ωC
where ωL is the angular frequency for the inductor and ωC is the angular frequency for the capacitor.
The angular frequency for the capacitor is given by the following equation:
ωC = 1/(2πRC)
where R is the resistance in ohms and C is the capacitance in farads.
Therefore, substituting the given values of R = 85.0 ohms and C = 14.0 μF, we have:
ωC = 1/(2π*85.0*14.0*10-6) = 2.47 radians/sec
The angular frequency for the inductor is given by the following equation:
ωL = 2πFL
where F is the frequency of the AC source in hertz and L is the inductance in henries.
Therefore, substituting the given values of F = variable and L = 1.50 mH, we have:
ωL = 2π*variable*1.50*10-3 = 6.28*variable radians/sec
Combining the two equations, we have:
6.28*variable = 4.00*2.47
Solving for the variable, we get:
variable = 6.28*4.00/2.47 = 10.1 Hz
Therefore, the angular frequency at which the inductive reactance is 4.00 times as large as the capacitive reactance is 10.1 Hz or 6.26 radians/sec.
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a straight wire segment that is 0.65 meters long has a current of 1.4 amps. the wire segment is oriented so that the current us travelling in the y direction. the wire is placed in a uniform magnetic field of strength 0.65 tesla in the z direction. find the force acting on the wire.
Force acting on the wire is 0.243N
What is magnetic Force ?One of the four fundamental forces of nature, the electromagnetic force, results in the magnetic force, which is brought about by the motion of charges. When two charge-containing objects move in the same direction, a magnetic attraction pulls them together.
According to the given information
We are given that
Current in, the segment is [tex]$I=1.8$[/tex] amps
Length of segment is[tex]$l=0.3 \mathrm{~m}$[/tex]
Magnetic field [tex]$B=0.45 T^2$[/tex]
In vector form
[tex]$I \vec{l}=1.8 \times 0.3 \hat{j}$[/tex]
[tex]=0.54 \hat{\jmath} \mathrm{A} \cdot \mathrm{m}$[/tex]
[tex]B$\vec{B}=0.45 \hat{k} T$[/tex]
So
Magnetic force on wire is
[tex]& \vec{F}=\overrightarrow{I l} \times \vec{B}=(0.54 \hat{\jmath} \times 0.45 \hat{k}) \mathrm{N} \\[/tex]
[tex]& \vec{F}=0.54 \times 0.45 \hat{\jmath} \times \hat{k} \mathrm{~N} \\[/tex]
[tex]& \vec{F}=(0.243 \mathrm{~N}) \hat{\imath}[/tex]
So
[tex]$F=0.243[/tex] in the positive x - axis direction
Force acting on the wire is 0.243N
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a 230kv, 60hz, three phase completely tranposed overhead line has one acsr 954 kcmil conductor per phase and flat horizontal phase spacing, with 8 m between adjacent conductors. determine the inductance and the inductive reactance
The Inductance and Inductive Reactance of the conductor is 1.315 x 10⁻⁶H/m and 0.496ohm/km respectively.
A type of inductor is a device that runs on magnetism or magnetic fields. Transformers, coils, motors, and generators are examples of inductors. Current and voltage can become out of phase and inefficient when an inductor is used in a circuit if the problem isn't fixed.An EMF is continuously produced in an inductive AC circuit where the current is constantly changing. This EMF's impact is measured in ohms because it fights against the ongoing change in the flowing current. Inductive reactance (XL) is the term used to describe this resistance of the inductance to the flow of an alternating current.The inductance of the circuit and the rate at which the current is changing through the circuit both affect the value of XL in any circuit. The applied voltage's frequency affects this rate of change.The mathematical illustration of XL is shown in the equation below.
XL = 2πfL.
Ds=0.0123mDe=8.819m
L= 2 x 10⁻⁷ x log [8.819/0.0123]
L=1.315 x 10⁻⁶H/m
XL=2 x 3.14 x 60 x 1.315 x 10⁻⁶=0.496ohm/km
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Imagine a ball that is pushed off a desk completely horizontal and falls 9.47 m down to the floor. If it landed 3.32 m away from the edge of the desk, how fast was it moving in the horizonal direction just before it hit the ground? Round to 1 decimal.
The ball was moving at 11.1 m/s in the horizontal direction just before it hit the ground.
What is horizontal direction?
Horizontal direction is a term used to describe a direction parallel to the horizon. It is an important concept in navigation and surveying, since it helps to determine a person's geographic location. Horizontal direction is usually expressed as an angle, measured clockwise from the direction of true north. It is important to remember that the angle for horizontal direction increases as the person turns clockwise from true north. For example, if a person were facing north, their horizontal direction would be 0°. If they were facing northeast, their horizontal direction would be 45°. In addition to its use in navigation, horizontal direction is also used in architecture and engineering. For example, when designing a building, architects use horizontal direction to determine which way the building should face in order to maximize the amount of natural light that enters the building.
We can use the equation vf^2=vi^2 + 2ad, where vf is the final velocity, vi is the initial velocity, a is the acceleration due to gravity (9.8 m/s^2) and d is the displacement.
In this case, vf = 0 m/s (since the ball has stopped moving at the end of its fall), vi = unknown, a = 9.8 m/s^2, and d = 3.32 m.
We can rearrange this equation to solve for vi: vi = sqrt(vf^2 - 2ad)
vi = sqrt(0^2 - 2(9.8)(9.47)) = -11.1 m/s
Since the velocity is negative, it is moving in the opposite direction of the displacement. Therefore, the ball was moving at 11.1 m/s in the horizontal direction just before it hit the ground.
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this buoy is located 260 km from the coast of new jersey. based on the wave speed at the time of maximum wave height it would take about 4.5 hours for these waves to travel from the buoy to the coastline. does that seem slow or fast to you?
That seems relatively fast to me. Wave speed is typically between 160 to 320 km/h, so the 4.5 hours it would take for these waves to travel from the buoy to the coastline is in line with the expected wave speed.
What is Wave?
A wave is a spreading dynamic disturbance (transition from equilibrium) with one or even more quantities in physics, mathematics, as well as related fields. When a wave is periodic, its constituent parts repeatedly oscillate around an equilibrium (resting) valuation at a given frequency. A travelling wave is defined as one in which the a whole waveform moves inside one direction; in contrast, a standing wave is defined as a pair of superimposed promotes the flow moving in the opposite directions. In a standing wave, the vibration's amplitude nulls out at certain locations where the wave's amplitude appears smaller and even zero. Wave equations, which are standing wave fields of two opposing waves, or one-way wave equations, which describe the propagation of a single wave in a specific direction, are frequently used to describe waves.
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by what factor does the gravitational force between two objects increase if one object doubles in mass and the distance between them decreases by half?(1 point)
The gravitational force between two objects increase if one object doubles in mass and the distance between them decreases by half F = 8G m1 m2 / r^2.
Because F = G*m1*m2/r2,
G * 2m1 * m2 / (r/2)2 = 8G m1 m2 / r2, which is the right answer if m1 doubles and r falls by half.
Objects with mass are drawn toward one another by the gravitational attraction, also known as the force of gravity. The gravitational force of the Earth is something we consider frequently. Your body is kept stationary on the ground by this force. However, every other mass-containing item experiences a gravitational pull from every other mass-containing object. Gravity is a fundamental interaction in physics that produces mutual attraction between all things having mass or energy (from the Latin gravitas, "weight". By far the weakest of the four fundamental interactions, gravity is 1038 times weaker than the strong interaction, 1036 times weaker than the electromagnetic force, and 1029 times weaker than the weak interaction. As a result, it has no discernible impact on the level of subatomic particles. But the most important relationship is gravity.
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Consider points A, E, and G. Of these three points, which one corresponds to the greatest magnitude of acceleration of the particle?
Answer: A
A one corresponds to the greatest magnitude of acceleration of the particle.
What is acceleration?
Any procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.
The graph given is of Kinetic energy rs position. Kinetic energy [tex]$K \cdot[/tex] [tex]E=\frac{1}{2} m v^2$[/tex]. Since mass ' m ' is Constant we can write K.E [tex]$\propto v^2$[/tex]
So when kinetic energy is maximum, speed is maximum. when kinetic energy is changing/increasing at maximum rate implies speed is also increasing at maximum rate implies acceleration is maximum. So when acceleration of the particle is zero, slope is zero. ie rate of change of kinetic energy is zero. So the answers ave:
1) Acceleration zero: B, D, F & H.
2) A, E, G; out of these 3 points, at[tex]$A^{\prime}$[/tex] the slope is maximum.
[tex]$\Rightarrow$[/tex]At 'A', acceleration is maximum.
3) Maximum[tex]$K \cdot E \Rightarrow$[/tex] highest point : 'B' Corresponds to highest K.E.
4) Lowest speed corresponds to lowest kinetic energy. [tex]$\Rightarrow$[/tex] ' D '
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a heat engine is operating between 317 c and -3 c. if the engine extracted 100 mj of energy from fuel, how many mj of energy could be used as mechanical energy?
54.2 MJ of energy could be used as mechanical energy from heat engine operating between 317 c and -3 c and if the engine extracted 100 mj of energy from fuel.
What is mechanical energy ?
Mechanical energy, also known as kinetic energy or potential energy, is the energy that an object possesses when it is in motion or the energy that an object stores due to its location.
According to the given information:
T(high) = -3 °C
T (low) = 317 °C
Fuel extracted = 100 MJ
First we need to convert temperature into kelvin
T(high) = 270 K
T(low) = 590 K
Efficiency = 1 - [tex]\frac{T(high)}{T(low)}[/tex]
Efficiency = 1 - [tex]\frac{270}{590}[/tex]
Efficiency = 1 - 0.458
Efficiency = 0.542
Hence maximum useful work done = 0.542 x 100 MJ
Maximum work done or the amount of energy used as mechanical energy = 54.2 MJ
Hence the maximum amount of useful work extracted from the heat engine is 54.2 MJ
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What is the energy, in j, of light that must be absorbed by a hydrogen atom to transition an electron from n = 3 to n = 6?.
The energy absorbed by Hydrogen atom to transit an electron from n = 3 to n = 6 is 1.815x10-19 Joules
What is Energy level ?Energy Level: According to the Bohr atomic model, energy levels—also known as electron shells—are thought of as the orbits that electrons in an atom's nucleus take. Electrons must always be in one of the energy levels and never in the space between them since the energy levels represent defined distances.
According to the given information
Change in energy = [tex]-13.6eV \frac{1}{n_{f} ^{2} }-\frac{1}{n_{i} ^{2} }[/tex]
= -13.6 × 1.6 × [tex]10^{-19}[/tex] ( [tex]\frac{1}{6^{2} }[/tex] - [tex]\frac{1}{3^{2} }[/tex] )
= 21.76 × [tex]10^{-19}[/tex] × 0.084
= 1.815 × [tex]10^{-19}[/tex] J
Change in Energy level = 1.815 × [tex]10^{-19}[/tex] J
The energy absorbed by Hydrogen atom to transit an electron from n = 3 to n = 6 is 1.815x10-19 Joules
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for laminar flow of air over flat plates with uniform surface temperature, the curve that most closely describes how the average heat transfer coefficient changes with the length of the plate is
For a laminar airflow over flat plates with a constant surface temperature, the curve that best represents how the average heat transfer coefficient declines with plate length increases.
In fluid dynamics, laminar flow is characterized by fluid particles passing each other in layers along straight paths with little to no mixing in between. When the fluid is traveling at moderate speeds, it tends to Laminar flow without lateral mixing, which causes adjacent layers to slip past one another like playing cards. The heat transfer coefficient measures the convective heat transfer between a fluid medium (a fluid) and the surface (a wall) it flows over. The Newton-Richmann relation shows the heat transfer coefficient as a proportionality factor.
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Physic: A yo-yo of total mass m consists of two solid cylinders of radius R, connected by a small spindle of negligible mass and radius r. The top of the string is held motionless while the string unrolls from the spindle freely under gravity. Given the angular momentum of a cylinder L = πmR2/T, find the linear acceleration of the yo-yo. 8. A yo-yo of total massmconsists of two solid cylinders of radiusR, connected by a small spindle of negligible mass and radiusr. The top of the string is held motionless while the string unrolls from the spindle freely under gravity. Given the angular momentum of a cylinderL=πmR 2/T, find the linear acceleration of the yo-yo.
The moment of inertia can be given as the sum of the moments of inertia of each of the end cylinders plus the moment of inertia of the axle is[tex]{a_y = \frac{g}{1+\frac{R^2}{2r^2}}}[/tex]
Imagine the YoYo When yoyo is falling
In Linear downward direction,
mg-T=ma_y
ay = is linear acceleration
now
[tex]T*r=I_c_m \alpha[/tex]
but from we also know [tex]\alpha =\frac{a_y}{r}[/tex]
[tex]T*r=I_c_m \frac{a_y}{r}[/tex]
substiting above equation in beggining eqyation.
[tex]mg-I_c_m \frac{a_y}{r^2} = ma_y[/tex]
[tex]a_y = \frac{mg}{m+\frac{I_c_m}{r^2}} .......................(1)[/tex]
Icm --> The moment of inertia can be given as the sum of the moments of inertia of each of the end cylinders plus the moment of inertia of the axle:
and mass ofcylinders will half of total mass as spindle mass is negigible. i.e cylinders masses = m/2
[tex]I_c_m =2* \frac{\frac{m}{2}R^2}{2} = \frac{mR^2}{2}...............(2)[/tex]
Substituting 2 in 1 we get
[tex]{ a_y = \frac{g}{1+\frac{R^2}{2r^2}}}[/tex]
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what happens to the shape of a wire that is part of a circuit with a battery when the switch is closed and the direction of the current is reversed in the wire?
The wire bends more than it did before when the switch is closed and the direction of the current is reversed in the wire.
A stream of charged particles such as electrons or ions moving through a conductor for electricity or into empty space is known as an electric current. The net rate of passage of electric charge through a surface or into a control volume is used to measure it. Charge carriers are the moving particles, which depending on the conductor could be any number of different types of particles. Often, electrons flowing over a wire serve as the charge carriers in electric circuits. They may be holes or electrons in semiconductors. Ions are the charge carriers in an electrolyte, while electrons and ions make up plasma, an ionized gas.
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an object with a mass of 13.29 kg experiences force of 14.35 N . What is the acceleration of the object?
____________________________________________________
We are given the following:
[tex]Mass=13.29kg[/tex][tex]Force=14.35N[/tex][tex]Question:[/tex] What is the acceleration of the object?Given the formula for finding acceleration, we fill in the blanks.
[tex]A=14.35*13.29[/tex]
[tex]A=190.7115=190.7[/tex] ← Acceleration/Final Solution
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Hope this helps!
a small light fixture on the bottom of a swimming pool is 1.22 m below the surface. the light emerging from the still water forms a circle on the water surface. what is the diameter of this circle? (give your answer, in m, to at least two decimal places.)
1.22 m below the surface of a swimming pool's bottom lies a little light fixture. The circumference of this circle is 2.27 m.
What does life's light mean?One of the fundamental and common symbols is light. It is the holy and the spiritual; it is wisdom and insight. Light is the wellspring of kindness and the true truth; according to Buddhist belief, it also follows transcendence into Nirvana.
Briefing:The critical angle is found by imagining the refracted ray just grazing the surface (θ₂ = 90°). The index of refraction of water is n₁ = 1.333, and n₂ =1.00
for air, so n₁ sin∅c = n₂ sin90° gives ∅c =sin⁻¹ (1/1.333)= sin⁻¹ (0.750)=48.6°
The radius then satisfies
tan∅c = r/1.00m
So the diameter is
d=2[(1.00m)tan∅c]
d=(2.00m)tan48.6° = 2.27m
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an image of the lateral skull taken at 68 kvp, 20 mas and is repeated. if the kvp is increased to 78 kvp, what should be the new mas?
Half of 20mAs is 10mAs, should be the new mAs.
What is kVp and mAs?In the first experiment, it was shown that, when the film density is maintained constant, the resolution decreases with rising kVp and increases with increasing mAs, respectively, and that the picture contrast percentage increases with increasing kVp.
Several mAs were chosen for the second part of the experiment, and several kVps were used for each mAs. Five observers read the radiographs.
The second experiment showed that when the film density was not kept constant, the correlations between kVp and resolution and between kVp and the picture contrast percentage were the same as in the first experiment.
However, there was little correlation between MAs and picture contrast % and MAs and resolution.
So when the lateral skull is 68kvp then 20mas and when kvp is increased to 78kvp then new mas will be half that is 10mas
Half of 20mas is 10mas, should be the new mas.
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Given the discussion above, can you argue that the propagation of error/uncertainty formula for a non-linear model is more general and can be used for a linear model?
Statisticians say that this type of regression equation is linear in the parameters. However, it is possible to model curvature with this type of model. While the function must be linear in the parameters, you can raise an independent variable by an exponent to fit a curve.
Define Linear regression?
Linear regression is easier to use, simpler to interpret, and you obtain more statistics that help you assess the model. While linear regression can model curves, it is relatively restricted in the shapes of the curves that it can fit. Sometimes it can’t fit the specific curve in your data.
Define Nonlinear regression?
Nonlinear regression can fit many more types of curves, but it can require more effort both to find the best fit and to interpret the role of the independent variables.
Thus, Statisticians say that this type of regression equation is linear in the parameters. However, it is possible to model curvature with this type of model. While the function must be linear in the parameters, you can raise an independent variable by an exponent to fit a curve.
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Each of the following statements was either true for Mars in the distant past (early Mars) or is true for Mars today. Sort the statements by dragging each into the correct bin.Early Mars (more than 3 billion years ago):
Strong greenhouse effect.
Substantial volcanism and outgassing.
Strong magnetosphere.
Some craters held lakes of water.
Core convection.
Mars Today:
Surface pressure too low for stable liquid water.
Solar wind strips atmospheric gas.
Very weak greenhouse effect.
Early Mars (extra than three billion years in the past) strong greenhouse effect. Substantial volcanism and outgassing. Strong magnetosphere.
*Some craters held lakes of water.
*Core convection.
Mars Today:
*Surface pressure too low for stable liquid water.
*Solar wind strips atmospheric gas.
*Very weak greenhouse effect.
A gas is a substance that has no constant size or form. Whilst inside a closed container, gasoline will amplify to fill the field. An instance of gas is the air you breathe. The gas interior of your digestive tract is fabricated from the air and different gases.
Traits of Gases :
* Gases have neither definite shape nor particular volume.
* Gases are fluid and go with the flow effortlessly.
* Gases have low density, except compressed.
* Gases diffuse (mix and unfold out) and effuse (tour thru small holes).
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An 82.0-kg person rides on a carnival ride in a 45.0-kg basket supported by a single chain. When the ride reaches its top speed, the basket moves at a constant speed in a horizontal circle with a radius of 7.10 m. At this point, the chain supporting the basket is at a 45.0 angle to the vertical.
The chain supporting the basket is at a 45° angle to the vertical and horizontal component is 1244.6N.
What is constant speed?When an object's speed stays the same and neither increases nor decreases, we say it is moving at a constant speed.
Mass of the person is 82kg and mass of the basket is 45 kg.
New total mass, M = 82+45 = 127kg.
Here, Fe is centrifugal force
v is velocity of the person
r is radius of the circle,
r = 7.1m
Now, Tsin 45° = Mg [ here Mg is weight of person and basket]
T = Mg/sin 45° = Mg√2
Now, vertical component of the tension,
Fy = Tsin 45° = Mg = (127×9.8)kg-m/s²
Fy = 1244.6N
Now, horizontal component,
Fx = Tcos 45°
Fx = Mg/Tan 45°
Fx = Mg/1
Fx = 1244.6N
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each of these frames shows the migration (due mostly to solar rotation) of sunspots across the face of the sun with the earliest sketch at the top. if the north pole of the sun is at the top of each frame, in which direction does the sun rotate?
The sun rotates in the counterclockwise direction when viewed from above the North Pole of the Sun.
The Sun rotates on its axis approximately once in 27 days. This rotation was first discovered by observing the motion of the Sun. The Sun's axis of rotation is tilted by about 7.25 degrees from the axis of Earth's orbit, so we see most of the Sun's north pole in September and most of its south pole in March each year. The Sun's "surface" that is visible, up to the photosphere. The powerful magnetic fields in the vicinity of sunspots produce active regions on the Sun that often generate disturbances such as solar flares and coronal mass ejections (CMEs). Because they are colder than their surroundings, sunspots seem "black.". The average number of spots on the face of the Sun is not constant, but varies over a multi-year cycle.
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shows two masses at rest. the string is massless and the pullies are frictionless. the spring scale reads in kg. what is the reading of the scale?
The reading of the scale due to the two masses, massless string and the frictionless pullies is 0.
When the strings have frictionless pullies, they perform a rotary motion with the pulleys.
Net force of the masses
The two masses are connected by massless spring.
Since the masses are at rest, the sum of all the forces acting on the scale will be zero.
Fnet = o
T + M1g - M2g = 0
M1 and M2 are the masses at rest respectively.
T = M2g - M1g
Reading on the scale
Since the two given masses have same mass then their product with 'g' is and their difference is zero.
The reading of the scale is equal to the tension in the pulley connecting the two masses.
The tension on the pulley is calculated as follows;
T = Mg - Mg
T = 0
Thus, the reading of the scale due to the given masses is 0.
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