HELP!! WILL GIVE BRAINIEST

The required reasons statements to prove the congruency of the angles  the value of x, and the measures of ∠2 and ∠4 are as follows;

Problem 1

The question and the diagram indicates that ∠1 and ∠3 are vertical angles formed by two lines, therefore, ∠1 and ∠3 are both a linear pair and therefore supplementary to ∠2, indicating that m∠1 = m∠3, therefore;

∠1 ≅ ∠3

Problem 2

Supplementary angles are angles that have a sum of 180°

The reasons for the statements in the completed table of the two column method used to prove ∠1 ≅ ∠3 are as follows;

Statement         [tex]{}[/tex]                                      Reasons

1. ∠1 and ∠3 are vertical angles [tex]{}[/tex]       1. Given

2. ∠1 and ∠2 form a linear pair [tex]{}[/tex]        2. Definition of linear pair

∠2 and ∠3 form a linear pair

3. ∠1 and ∠2 are supplementary [tex]{}[/tex]     3. Linear pair ∠s are supplementary

∠2 and ∠3 are supplementary

4. m∠1 + m∠2 = 180°        [tex]{}[/tex]                 4. Definition of supplementary ∠s

m∠2 + m∠3 = 180°

5. m∠1 + m∠2 = m∠2 + m∠3        [tex]{}[/tex]    5. Substitution property

6. m∠1 = m∠3        [tex]{}[/tex]                            6. Subtraction property      

7. ∠1 ≅ ∠3        [tex]{}[/tex]                                  7. Definition of congruency

Problem 2

∠2 = 4·x - 4

∠4 = x + 50

∠2 and ∠4 are vertical angles, therefore;

∠2 ≅ ∠4 (Vertical angle theorem)

m∠2 = m∠4 (definition of congruency)

4·x - 4 = x + 50 (substitution property)

4·x - x = 4 + 50 = 54

3·x = 54

x = 54 ÷ 3 = 18

x = 18°

m∠2 = (4 × 18 - 4)° = 68°

m∠3 = (18 + 50)° = 68°

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The probability having of 3 boys and 4 girls is 33 or 0.33

what is probability?

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a proposition to be true. A number between 0 and 1 is the probability of an event, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

solution:

Assuming 50/50 chance on boy/girl we see following outcome:

(1/2^7).

Since there is only one way you can have 3 girls, followed by 4 boys.

If you would tell the boys apart, and the girls, for instance by their names, the probability would be:

6 * (1/2)^3 *(1/2)^4 * 24.

6 Times because the girls would then have 6 orders of having been born.

24  Times because then the boys would have 24 orders of having been born.

Therefore, The probability of 3 boys and 4 girls is 33 or 0.33

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Answer:

x = 4√104/2

Step-by-step explanation:

Answer:

11/12 chance of the probability of rolling a 6 with 2 dice

The answer is: A) Tasha, because she has the lowest ratio since 0.75 < 0.8

Explain:

i did the test

Answer:

Step-by-step explanation:the answer is a

Answer is NO!

hope this helps! Have an amazing and blessed day! :)

Answer: yes

Step-by-step explanation:

The data shows a negative linear association between the number of magazines checked out and the number of books checked out.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Scatter plots are used to plot data points on a horizontal and a vertical axis in the attempt to show how much one variable is affected by another.

If one variable tends to increase as the other decreases, the association is negative.

By observing the scaterplot we understand that the value is decreasing as the other value is increasing.

Hence, The data shows a negative linear association between the number of magazines checked out and the number of books checked out.

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The CY in the given Parallelogram WXYZ is 15 ft.

A parallelogram is defined as, "A geometrical figure whose sides are parallel to each other. "
In the given Parallelogram WXYZ, the length of the sides is not given. Although, the length of the two diagonal sides is given which are CY and CW with a variable x. The following are the values of these two diagonals:
CY = (2x -  7) ft                  .....(1)
CW = (x + 4) ft                   ......(2)

In this given question, we need to find the value of CY. So, we can find the value of CY by finding the value of variable x.

To find the value of x, we follow the theorem:
"In the parallelogram, The diagonals bisect each other"
We get that,
CY = CW                       ......(3)
By putting the value equation (1) and (2) in equation (3), we get
2x - 7 = x + 4                    ......(1)
By subtracting 'x' and adding '7' on both sides of the equation.
x = 11,
So we get,

x = 11.
By putting the value of 'x' in equation (1), we get:

CY  = 2(11) - 7 =  11 - 7
CY = 4.

Hence, the value of CY is 4.

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Answer:

b. 8.33

Step-by-step explanation:

"mean" is the math word for what non-math people call average. This is where you add up all the numbers and divide by however many there are.

3+5+8+11+11+12 is 50

There are 6 numbers in the data set. So 50/6 is 8.3333...

b. 8.33 is the correct answer.

Mean means add and divide.

The surface area of each brace of the cabinet is 30 square inches

Surface area of the first brace = 2 (lh +wh + lw )

= 2{(3×1) + (3 × 1) + (3 × 3)}

= 2(3 + 3 + 9)

= 2(15)

= 30 square inches

Surface area of the second brace = 2 (lh +wh + lw)

= 2{(3×1) + (3 × 1) + (3 × 3)}

= 2(3 + 3 + 9)

= 2(15)

= 30 square inches

Total surface area of the cabinet = Surface area of the first brace + Surface area of the second brace

= 30 square inches + 30 square inches

= 60 square inches

Consequently, the total surface area of the cabinet is 60 square inches

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Answer:

c

Step-by-step explanatio

We get

(A) The probability that her winnings will exceed zero is 0.50.

(B) The probability that her winnings will be less than zero is 0.25.

(c) Her winnings' estimated worth is 0.

Given that,

A player engages in a game where the odds of winning or losing one dollar are equal. The games are stand-alone. The game will be played until the first win occurs, at which point the player will instantly stop.

We have to find

(A) determine the probability that her winnings will exceed zero.

(B) calculate the probability that her winnings will be less than zero.

(c) calculate her winnings' estimated worth.

We know that,

a) probability that her winnings are greater than zero =P(wins 1st game) =1/2 =

b) probability that her winnings are less than zero =P(lose 1st 2 games) =(1/2)×(1/2 )=1/4 =0.25

c) below is pmf of X (gain from the game)

P(X=1)=P(win 1st game) =1/2

P(X=0)=P(lose 1st and win 2nd) =(1/2)×(1/2) =1/4

P(X=-1)=P(lose 1st two and wins 3rd)=(1/2)×(1/2)×(1/2) =1/8

P(X=-2)=1/16

therefore expected value E(X )=ΣxP(x) =1×1/2+0×1/4-1×1/8-2×1/16........

= (1/2)+0-(1×1/8+2×1/16+3×1/32+4×1/64+...)

=(1/2)-(1/4)×(1/(1/2))

=(1/2)-(1/2)

=0

Therefore,

(A) The probability that her winnings will exceed zero is 0.50.

(B) The probability that her winnings will be less than zero is 0.25.

(c) Her winnings' estimated worth is 0.

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The correct statements regarding the graph of the exponential function y = 2.60(1.07)^x are given as follows:

The definition of an increasing exponential function is given as follows:

y = a(1 + r)^t.

In which the parameters are given as follows:

In the context of this problem, the values of these parameters are given as follows:

a = 2.6, r = 0.07.

Hence the function is given as follows:

y = 2.6(1.07)^x.

The features of the function are given as follows:

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the null and alternative hypotheses for the above scenario This is a left failed test.

What is confidence interval?

In frequentist statistics, a confidence interval (CI) is a range of estimates for an unknown parameter. Although 95% is the most common confidence level, confidence intervals can also be calculated at other levels, such 90% or 99%. The confidence level is the proportion of linked CIs over the long run which really contain the true value of the parameter. The breadth of the CI may be influenced by a number of variables, including sample size, sample variability, and degree of confidence. If all other factors were same, a larger sample would lead to a narrower confidence interval. A sample with greater variability would result in a broader confidence interval and a higher level of confidence.

a newsletter publisher believes that less than 46% of their readers own a rolls Royce.

there is sufficient evidence at the 0.01 level to substantiate the publisher's claim

The null hypothesis (Mo) in this case has a P value of 0.46. P 0.46 Alternative Hypothesis (Ha) (claim)

The left test failed here.

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Based on the box plots, the statement which is correct is that: A. The median score of Class A is greater than the median score of Class B.

In Mathematics, a box plot is also referred to as box and whisker plot and it can be defined as a type of chart that can be used to graphically or visually represent the five-number summary of a data set with respect to locality, skewness, and spread.

Additionally, the five-number summary of any box plot (box and whisker plot) include the following:

By critically observing the box plot (box and whisker plot) which represent the math scores of students in in two different classes, we can reasonably and logically deduce the following median scores;

Median score of class A = 80

Median score of class B = 75

Therefore, a median score of 80 in Class A is greater than the median score of 75 in Class B.

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We keep the first number 11/3, change ÷ to ×, and flip 2/3 to 3/2:

11/3 x 3/2 = 33/6

33/6 ÷ 3/3 = 11/2

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A) Yes , there is there sufficient evidence in the sample data to support the claim that the mean water temperature is not acceptable at α.

Hypothesis test for the given  population mean :

The claim is that the mean water temperature is significantly below 100 °F.

Then, the null and alternative hypothesis are:

H0 : Ц = 100

H1 : Ц < 100

The significance level is 0.05.

The sample has a size n=9.

The sample mean is M=98.

The standard deviation : σ=2

Standard error = 0.667

Z = -3

Therefore,  P-value (0.001) is smaller than the significance level (0.05)

The null hypothesis is rejected.

The hypothesis that there is no significant difference between specified populations, any observed difference being due to sampling or experimental error is known as null hypothesis.

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Answer:

statistical methods

Step-by-step explanation:

Data analyst uses to "Database organization" to decide which data is relevant to their analysis and which data types and variables are appropriate.

A database is a structured information collection that is often kept electronically in a computer system. Typically, a database management system is in charge of managing a database (DBMS).

It is a system, frequently abbreviated to just database, is the collective term for the data, the DBMS, and the applications that are connected to it.

The most popular forms of databases, today usually describe their data in rows and columns in a collection of tables to facilitate processing and data querying.

Also the information may then be accessed, managed, changed, updated, regulated, and organized with ease. SQL is a structured query language that is used by the majority of databases to write and query data.

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Yes, the given data provide convincing evidence that the Nuthatches prefer particular types of trees while searching for seeds and insects.

A statistical hypothesis test used to examine if a variable is likely to come from a given distribution is the Chi-square goodness of fit test. It is frequently used to assess how well sampling data represents the entire population.

Given that the number of red-breasted nuthatches (n) is 156. By convention, the significance level is α=0.05.

First, let's state the null hypothesis and alternate hypothesis.

Null hypothesis H₀: Nuthatches don't prefer particular types of trees while searching for seeds and insects.

Alternate hypothesis H₁: Nuthatches prefer particular types of trees while searching for seeds and insects.

Given: p₁=54%=0.54, p₂=40%=0.40, p₃=6%=0.06

The expected frequency (E) for each probability is:

[tex]\begin{aligned}E_1&=np_{1}\\&=156\times0.54\\&=84.24\\E_2&=np_{2}\\&=156\times0.40\\&=62.4\\E_3&=np_{3}\\&=156\times0.06\\&=9.36\end{aligned}[/tex]

The observed values (O) are given as 70, 79, and 7. Calculating chi-square, we get,

[tex]\begin{aligned}\chi^{2}&=\sum\frac{(O-E)^2}{E}\\&=\frac{(70-84.24)^2}{84.24}+\frac{(79-62.4)^2}{62.4}+\frac{(7-9.36)^2}{9.36}\\&=7.4182\end{aligned}[/tex]

And the degree of freedom is given by df = n-1, where, n is the sample size. Here, the sample size is 3.

[tex]\begin{aligned}df&=n-1\\&=3-1\\&=2\end{aligned}[/tex]

Then, the P-value from the table is given by, [tex]P(\chi^{2} > 7.4182) = 0.0245[/tex].

This value is less than the significance level.  Therefore, the null hypothesis is rejected. So, an alternate hypothesis is accepted.

Therefore,  nuthatches prefer particular types of trees while searching for seeds and insects.

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It cannot be concluded that there is a statistically significant difference between Mr. Goodman’s evaluations and the History Department’s

H₀: There is no difference in Mr. Goodman’s evaluations and the History Department’s

H: there is a significant difference between Mr. Goodman’s evaluations and the History Department’s

Applying chi-square test

relative  observed Expected residual Chi-square

1's 0.100 11.000 12.500 -0.42 0.180

2's 0.150 14.000 18.750 -1.10 1.203

3's 0.340 47.000 42.500 0.69 0.476

4's 0.410 53.000 51.250 0.24 0.060

total 1.000 125 125   1.9196

test statistic  X²=1.9196

p-value =0.5893

Hence it cannot be concluded that there is a statistically significant difference between Mr. Goodman’s evaluations and the History Department’s as we fail to reject the null hypothesis.

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To compare the weight of a flea and an ant, we first need to convert the weight of the flea and the ant to the same units. Since the weight of the flea is given in decigrams and the weight of the ant is given in milligrams, we can convert the weight of the flea to milligrams by multiplying it by 10.

We can use the following equation to calculate the weight of the flea in milligrams:

weight of flea in milligrams = 8 decigrams * 10 = 80 milligrams

Once we have the weight of the flea and the ant in the same units (milligrams), we can subtract the weight of the ant from the weight of the flea to find the difference in their weights.

We can use the following equation to calculate the difference in weight between the flea and the ant:

difference in weight = weight of flea - weight of ant

difference in weight = 80 milligrams - 3 milligrams

difference in weight = 77 milligrams

Therefore, a flea weighs 77 milligrams more than an ant.

The following statements make a false statement.

Given that,

A function argument  a exists until the function's end is reached.

A local variable 

can only share a name with another variable inside the function and exists only until the function's end.

Answer C : Can not share a name with variable outside a function.

Because the function is considered as a single line of code.

Answer True

They have same presidence but they are evaluated from left to right

Answer D : The calculation totals both positive (Profits) and negative (loss) earnings

Code doesn't check if the number of positive or not before adding

Answer D.

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The value of the expression  8.1p plus 7.9r when p=6 and r=7 will be 103.9.

A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.

A statement expressing the equality of two mathematical expressions is known as an equation.

An expression is a mathematical proof of the equality of two mathematical expressions.

8.1p + 7.9r = 8.1(6) + 7.9(7)

⇒ 103.9

Hence "The value of the expression  8.1p plus 7.9r when p=6 and r=7 will be 103.9".

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Answer:

it is 5 you don't add the 3 in it

Answer:D

Step-by-step explanation:D

After solving, the observed statistic for this study is 2.5.

In the given question, a professor collected data.

After fishing a test, the 27 students in the class wrote their pedicted scores on their tests and these were compared with the actual scores after they were graded.

The mean predicted score was 83.7. So SD = 83.7.

The mean actual score was 81.2. So SD = 15.6

the aen of the difference was 2.5. So SD = 8.6

Null: The average difference in test score (predicted-actual) is 0. μ = 0

Alternative: The average difference in test score (predicted-actual) is greater than 0. μ > 0

We have to find the observed statistic for this study.

predict mean = 83.7   S.D = 8.6

actual mean = 81.2    S.D = 15.6

n = 27

x = (predict mean - actual mean )

x = 83.7 - 81.2

x = 2.5

Hence, the observed statistic for this study is 2.5.

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The right question is given below:

Answer:

7 {No choices are given}

Step-by-step explanation:

Given problem,

→ (-5) - (-12)

Let's solve the problem,

→ (-5) - (-12)

→ (-5) + 12

→ (-5 + 12) = 7

Thus, the answer is 7.