Answer: The maximum velocity of the object if the object bounces 3.45 cm above and below its equilibrium position is 4.62 m/s.
Reason:
The maximum velocity of the object is 4.62 m/s. This can be calculated by using the equation v = sqrt(2 * g * x), where g is the acceleration due to gravity (9.8 m/s2) and x is the displacement from the equilibrium position (3.45 cm), or 0.0345 m.
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Find its moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its two ends.
A) Moment of inertia about an axis passing through the point where the two segments meet : [tex]$I_A=\frac{1}{12} M L^2$[/tex]
B) Moment of inertia passing through the point where the midpoint of the line connects to its two ends: [tex]$I x=\frac{1}{3} M L^2$[/tex]
What is Moment of inertia?
The term "moment of inertia" refers to a physical quantity that quantifies a body's resistance to having its speed of rotation along an axis changed by the application of a torque (turning force). The axis might be internal or exterior, fixed or not.
A) The moment of inertia about an axis passing through the point where the two segments meet is [tex]$I_A=\frac{1}{12} M L^2$[/tex]given that the rod is bent at the center and distance from all the points to the axis remains the same, the moment of inertia about the center will remain the same.
B) Determine the moment of inertia about an axis passing through the point midpoint of the line which connects the two ends
First step: determine the distance between the ends ( d )
After applying Pythagoras theorem[tex]$\mathrm{d}=\frac{\sqrt{2}}{2} L$[/tex]
Next step : determine distance between the two axis [tex]$(\mathrm{x})$[/tex]
After applying Pythagoras theorem
[tex]\mathrm{x}=\frac{\sqrt{2}}{4} L$$[/tex]
Final step : Calculate the value of [tex]$\mathrm{I}_{\mathrm{x}}$[/tex]
applying Parallel Axis Theorem
[tex]$$I_x=I_8+M x^2$$[/tex]
[tex]$$\begin{aligned}& =\frac{1}{12} M L^2+\frac{1}{4} M L^2 \\& \therefore \quad I x=\frac{1}{3} M L^2 \\&\end{aligned}$$[/tex]
Hence we can conclude that Moment of inertia about an axis passing through the point where the two segments meet: [tex]$I_A=\frac{1}{12} M L^2$[/tex], Moment of inertia passing through the point where the midpoint of the line connects its two ends: [tex]$I x=\frac{1}{3} M L^2$[/tex]
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how fast (in rpm ) must a centrifuge rotate if a particle 3.1 cm from the axis of rotation is to experience an acceleration of 200000 g 's?
The value of the speed will be [tex]2.7\times 10^4rm[/tex]
We have,
Radius of particle = 3.1 cm
Acceleration of particle = 20000 g's
As we know,
The value of acceleration can be determined by using the formula:
[tex]a & =v^2 / r \\v & =\sqrt{a r}{ }^2=a r \\[/tex], where, v = velocity, a = acclreation, and r = radius of particle
So, putting the value of "a" and 'r" in the above formula:
[tex]$$\begin{aligned}& =\sqrt{(200000 \mathrm{~g})\left(3.1 \times 10^2 \mathrm{~m}\right)} \\v & =\sqrt{(200000)\left(9.8 \mathrm{~m} / \mathrm{s}^2\right)\left(3.1 \times 10^{-2} \mathrm{~m}\right)} \\v & =1.745 \times 10^2 \mathrm{~m} / \mathrm{s} \\& =\left(1.745 \times 10^2 \mathrm{~m} / \mathrm{s}\right) \frac{1 \mathrm{rev}}{(2 \pi)\left(6.2 \times 10^{-2} \mathrm{~m}\right)}\left(\frac{60 \mathrm{~m}}{1 \mathrm{~min}}\right) \\& =2.7 \times 10^4 \mathrm{rm}\end{aligned}$$[/tex]
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the area of a typical eardrum is about 5.0 10-5 m2. (a) calculate the sound power (the energy per second) incident on an eardrum at the threshold of hearing
The sound power at the threshold of hearing is 5* 10⁻¹⁷ W.
The sound power at the threshold of hearing:
Given that,
Area of the eardrum = 5* 10⁻⁵ m²
We know that, I = power/area
Threshold of hearing I = 1* 10⁻¹² W/m²
Form the above formula, we can write
Power = I* area = 1* 10⁻¹² * 5* 10⁻⁵ = 5* 10⁻¹⁷ W
The sound power incident on an eardrum at the threshold of pain is
We know that, I = power/area
Threshold of pain = 1 W
Power = I* area = 1* 5* 10⁻⁵ W
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The solar system is 25,000 light years from the center of our Milky Way galaxy. One light year is the distance light travels in one year at a speed of 3.0 x 108 m/s. Astronomers have determinedthat the solar system is orbiting the center of the galaxy at a speed of 230 km/s.
a. Assuming the orbit is circular, what is the period of the solarsystem’s orbit? Give your answer in years.
b. Our solar system was formed roughly 5 billion years ago. How many orbits has it completed?
c. The gravitational force on the solar system is the net force due to all the matter inside our orbit. Most of that matter is concentrated near the center of the galaxy. Assume that the matter has a spherical distribution, like a giant star. What is the approximate mass of the galactic center?
d. Assume that the sun is a typical star with a typical mass. If galactic matter is made up of stars, approximately how many stars are in the center of the galaxy?
a. The period of the solar system's orbit, assuming the orbit is circular, is [tex]2.05X10^{8} years[/tex].
b. There have been 24.4 completed revolutions.
c. The star has a mass of [tex]1.87X10^{41}[/tex] kg.
d. There are [tex]9.45X10^{10}[/tex] stars in the galaxy's center.
a. Distance equals 25,000 light years.
[tex]3X10^{8}[/tex]m/s equals the speed of light (c)
230 m/s is the astronomers' speed.
Using the time period formula,
[tex]t=\frac{d}{v}[/tex]
[tex]t= \frac{2\pi r}{v}[/tex]
r = distance
t = time, and v = speed.
Fill out the formula with the value
[tex]t = \frac{2\pi * 25000 * 9.46 * 10^{15} }{230 * 10^{3} }[/tex]
[tex]t= 6.460*10^{15} sec[/tex]
Number of years
[tex]t= \frac{6.460*10^{15} }{3.15*10^{7} } \\t= 2.05*10^{8} years[/tex]
Consequently, the solar system's orbit lasts [tex]2.05*10^{8}[/tex].
b. The solar system's average age is Tn=5 billion years, or [tex]5* 10^{9}[/tex] years.
The number of completed revolutions can be computed as
[tex]N=\frac{T^{n} }{T} \\N= \frac{5*10^{9}years }{2.05*10^{8}years } \\N=24.4[/tex]
24.4 revolutions have been completed.
c. The solar system's radius, r=25000 light years
velocity = 230 km/s
We can determine the big star's mass as
[tex]M= \frac{v^2r}{G} \\[/tex]
By substituting values, we obtain
[tex]M= \frac{(230*10^{3})^2* (25000*3*10^{8}*365*24*60*60m) }{(6.67*10^{-11} N/kg^2.m^2)}[/tex]
[tex]M= 1.87*10^{41} kg[/tex]
The star has a mass of [tex]1.87*10^{41} kg[/tex].
d. The sun's mass, [tex]M_{s}[/tex], is [tex]1.99*10^{30} kg[/tex]
The star's number can be computed using
[tex]N=\frac{mass of glactic center}{mass of sun} \\N= \frac{1.88*10^{41} }{1.99*10^{30} } \\N= 9.45*10^{10}[/tex]
There are [tex]9.45*10^{10}[/tex] beginnings, or around 94.5 billion, each year.
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A solenoidal coil with 30 turns of wire is wound tightly around another coil with 310 turns. The inner solenoid is 20.0 cm long and has a diameter of 2.50 cm. At a certain time, the current in the inner solenoid is 0.150 A and is increasing at a rate of 1700 A/s.
Part A For this time, calculate the average magnetic flux through each turn of the inner solenoid.
Part B For this time, calculate the mutual inductance of the two solenoids.
Part C For this time, calculate the emf induced in the outer solenoid by the changing current in the inner solenoid.
Mutual inductance is the property by which one coil affects the current and voltage of the other coil.
Magnetic flux us the total magnetic field around both the coils.
EMF are invisible energy around the coils, which are mainly referred to as radiation.
How to find mutual inductance, magnetic flux and EMF around two coils?
We know
N = 30 turns
N¹= 310 turns
Inner solenoid length L¹= 20 CM= 0.2m long
Diameter d¹= 2.5 CM= 0.025m
Current i¹= 0.150 A
Rate of increase in current = di¹/dt= 1700A/s
Part A : magnetic flux = ∅¹= B¹A¹
B¹= ûⁿ × n¹ × i¹ = 2.92× 10↑-4T
Thus, ∅= 2.92×10↑-4× π/4×0.025²
= 1.432×10↑-7 Wb
Part B
Magnetic flux in one coil× number of turns in second coil = mutual inductance× current in the first coil
∅¹ × N² = Mi¹
= 1.432×10^-7 ×30
M × 0.150=1.432×10^-7×30
M=2.86×10^-5H
Part C
E = M di¹/dt
= 2.86×10^-5×1700 V
= 0.048 V
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In view of both the given query The inner solenoid's mean flux density per rotation is 1.43 * 10⁻⁷ Wb, or the two solenoids' mutual coupling is 2.86 x 10⁻⁴ H. The induced emf in the exterior loop is 4.86 * 10⁻¹ V.
How do solenoids function?A solenoid operates by creating an electromagnetic field surrounding an armature, which is a moving core. The electromagnetic field causes the armature to move, and when it does, it opens and closing valves or switches, converting mechanical energy into electrical movements and force.
Briefing:Given:
N1 = 310 revolutions in the inner solenoid.
N2 = 30 is the number of revolutions in the outer solenoid.
The inner solenoid's length is 20 cm, or 0.2 meters.
Inner solenoid radius = r = diameter/2 = 2.50/2 = 1.25 cm = 0.0125 m
The inner solenoid's current I is equal to 0.150 A.
1700 A/s is the current growth rate, di/dt.
A). Average magnetic flux across the inner solenoid's turns is equal to BA.
Include the values:
Average magnetic flux via the inner solenoid's turns:
= [4π x 10⁻⁷][310/0.2][0.150]π(0.0125)²
= 1.43 * 10⁻⁷ Wb
B). The two solenoids' mutual inductance is given by M = N2 x (average flux) / current.
= (30 x 1.43 * 10⁻⁷) / 0.150
= 2.86 x 10⁻⁴ H
C). The change in current there in inner solenoid causes an induced emf in the outer magnet that is equal to M*di/dt.
= 2.86 x 10⁻⁴ * 1700
= 4.86 * 10⁻¹ V
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Two strings are made of the same material and have waves of equal speed. String 1 is thick; string 2 is thin.
Is the tension in string 1 greater than, less than, or equal to the tension in string 2?
greater than the tension in string 2
equal to the tension in string 2
less than the tension in string 2
PART B
Choose the best explanation from among the following:
Equal wave speeds implies equal tensions.
String 1 must have a greater tension to compensate for its greater mass per length.
String 2 will have a greater tension because it is thinner than string 1.
The tension in string 1 is lesser than to the tension in string 2.
What is meant by tension in a string?
It is possible to refer to tension as the action-reaction pair of forces acting at each end of the aforementioned elements. Tension is defined as the pulling force transmitted axially by a string, rope, chain, or other similar object, or by each end of a rod, truss member, or other comparable three-dimensional object.
The tension in the string has a square root relationship with wave speed, while the linear density of the wire has a square root relationship with wave speed. v=sqrt(T/u)
A larger thickness suggests a higher linear density (mass per length. Thus, the speed would be slower. The wave in string 1 moves slower than the wave in string 2, and vice versa.
According to a thick string, there is a lot of mass per length and the wave speed is slow.
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a ball is shot from the ground straight up into the air with initial velocity of 48 ft/sec. assuming that the air resistance can be ignored, how high does it go?
The ball goes up to 35.83 ft high. The result is obtained by using the formula of motion with constant acceleration.
What is motion with a constant acceleration?A motion along a straight line with a constant acceleration is a motion which the initial and final velocity change. There are 3 important formulas in this case for vertical motion.
v₁ = v₀ + gt
v₁² = v₀² + 2gh
h = v₀t + 1/2 gt²
Where
v₀ = initial velocity (m/s)v₁ = final velocity (m/sg = acceleration due to gravity (9.8 m/s²)t = time (s)h = height (m)Note: If the object goes up, the value of g is (-).
A ball moves from the ground straight up with a velocity of 48 ft/sec. Find the height of the ball!
First, we change the unit of initial velocity.
v₀ = 48 ft/sec
v₀ = 48 × 0.3048 m/s
v₀ = 14.63 m/s
The ball will go up to a certain height. At the maximum height, the velocity of the ball is 0. Thus, we can use the following formula to find h.
v₁² = v₀² - 2gh
0 = (14.63)² - 2(9.8)h
214.04 = 19.6h
h = 10.92 m
h = 10.92/0.3048 ft
h = 35.83 ft
Hence, the ball will go straight up to a height of 35.83 ft.
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In addition to science courses like physics and chemistry, what other types of courses are becoming increasingly relevant to space science careers?.
Structural engineering is the other course that are increasingly becoming relevant to space science careers
What are Space science careers ?Investigating how gravity affects the human body, building the telescopes of the future. providing accessible explanations of solar system discoveries. These are just a few examples of the projects that people involved in space exploration employment work on.
Learning how to repair space stations, aircraft, or even make space shuttles or items you'll need in space requires knowledge in civil engineering, which is the notion of designing large transportation projects.
Structural engineering is the other course that are increasingly becoming relevant to space science careers
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"Which of the following characteristics of Earth's relationship to the Sun explains the existence of Earth's seasons? Choose all that apply: ANSWER: Earth's axis always points in the same direction relative to the stars_ Earth spins on its axis completing one rotation each day: Earth orbits around the Sun, completing one orbit each year: Earth's axis is tilted relative to its orbital plane. Earth has a satellite called the Moon, which rotates around Earth. Correct art B What is the June solstice? ANSWER: The time of the year when Earth's geographic North and South Poles are leaning in similar ways toward the Sun the time of the year when Earth's geographic North Pole is leaning most directly toward the Sun the time of the year when Earth's geographic North Pole is leaning most directly away from the Sun Correct art C How does the inclination of Earth's axis change over the course of a year? ANSWER:"
The following characteristics of Earth's relationship to the Sun explain the existence of Earth's seasons is:
Earth orbits around the Sun, completing one orbit each yearEarth spins on its axis completing one rotation each dayEarth's axis is tilted relative to its orbital plane.Earth's axis always points in the same direction relative to the stars.The tilt of the earth's axis creates the seasons. Throughout the year, different parts of the world receive the most direct sunlight. So when the North Pole tilts toward the Sun, it's summer in the Northern Hemisphere. And when the Antarctic tilts toward the Sun the northern hemisphere will be in winter.
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what is the greatest average speed ????v of blood flow at 37∘c37∘c in an artery of radius 2.25 mm2.25 mm if the flow is to remain laminar? take the density of blood to be 1025 kg/m3,1025 kg/m3, and the viscosity to be 2.084×10−3 pa·s.
Average speed of blood flow is given by:
V = n*Re/(rho*d)
n = viscosity of blood = 2.084*10^-3 Pa.s
Re = max reynolds number for which flow remains laminar = 2000
rho = density of blood = 1025 kg/m^3
d = diameter of artery = 2*radius = 2*2.50 mm = 5.0*10^-3 m
So,
V = 2.084*10^-3*2000/(1025*5.0*10^-3)
V = 0.813 m/sec
what is the power output, in watts, of the combined resistance when the motor is operating at full speed?
A watt is equivalent to an amp multiplied by a volt. All done! Therefore, watt = amp X volt. This equation is also sometimes written as W=A X V.
What does watt mean?The power unit is the watt. It refers to the quantity of energy required for a given object to operate as well as the rate during which energy is used up. A joule of energy (or one watt) is equal to one joule of electricity flowing for one second.
What distinguishes one watt from another?Watts, which are determined by multiplying Amps by Volts, are used to measure energy. As the wattage rises, the appliance produces more power and output. This is the amount of water that the hosepipe example would emit.
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A 1500-kg car moving at 25 m/s hits an initially uncompressed horizontal spring with spring constant of 2. 0 ? 106 n/m. What is the maximum compression of the spring? (neglect the mass of the spring. ).
A 1500-kg car moving around 25 m/s collides with a horizontal spring that is initially uncompressed but has a spring stiffness of 2.0?106 n/m as well as a max compress of x = 0.68 meters.
What is another word for compression?Compress, constrict, contract, inflate, and shrink are a few words that frequently replace the word compress. While all of these phrases refer to "decreasing in bulk or area," compress indicates squeezing over resistance into a constricted area with a certain shape.
Briefing:Considering that,
The automobile weighs 1500 kg.
Vehicle speed, v = 25 m/s
spring's spring constant, k=2×10⁶ N/m
Let x be the greatest distance the spring may compress before breaking,
1/2mv²=1/2kx²
1/2mv²=1/2kx²
x=[tex]\sqrt{mv^{2} /k}[/tex]
x=[tex]\sqrt{1500*25x^{2} /2*10^{6} }[/tex]
x = 0.68 meters
The spring is thereby compressed by 0.68 meters.
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A diverging lens has a focal length of magnitude 21.8 cm.
(a) Locate the images for each of the following object distances.
43.6 cm
distance cm
location ---Select--- in front of the lens behind the lens
21.8 cm
distance cm
location ---Select--- in front of the lens behind the lens
10.9 cm
distance cm
location ---Select--- in front of the lens behind the lens
(b) Is the image for the object at distance 43.6 real or virtual?
realvirtual
Is the image for the object at distance 21.8 real or virtual?
realvirtual
Is the image for the object at distance 10.9 real or virtual?
realvirtual
(c) Is the image for the object at distance 43.6 upright or inverted?
uprightinverted
Is the image for the object at distance 21.8 upright or inverted?
uprightinverted
Is the image for the object at distance 10.9 upright or inverted?
uprightinverted
(d) Find the magnification for the object at distance 43.6 cm.
Find the magnification for the object at distance 21.8 cm.
Find the magnification for the object at distance 10.9 c
A diverging lens has a focal length of magnitude 21.8 cm and the images are located behind the lens.
(a) u = -10.9 cm
1/v= 1/10.9 - 1/21.9
v= 21.8cm
Behind the lens.
(b) 1. Virtual
2. Virtual
3. Real
(c) m = v/u
1. Erect/ Upright
2. Upright
3. Inverted
(d) m = v/u
1. m = -43.6/-43.6 = 1. Magnification = 1.
2. infinity.
3. m = 21.8 / -10.9 = -2. Magnification = -2.
Therefore, these are the answers for above given question.
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given the mass of the rubber in the balloon is 1.10 g, what is the net vertical force (in n) on the balloon if it is let go? you can neglect the volume of the rubber. n (upward)
The vertical component of force is 10.78N
The need is to find what would be the net vertical force (in n) on the balloon if it were released, given that the rubber in the balloon weighs 1.10g.The relationship between an object's mass and the amount of force required to accelerate it is outlined in Newton's second law of motion. F=ma, or the force acting on an object is equal to its mass times acceleration, is a common way to express Newton's second law. Therefore, more force is required to accelerate an object with more mass. Neglecting the volume of rubber , additionally, an object accelerates more quickly the more force it is under.[tex]F=ma\\\\F=1.10 * 9.81\\\\F=10.78N[/tex]To learn more about Newton's second law of motion-
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if a jumper falls for one minute through upper winds averaging 30 knots from the west, how far will the jumper drift? in what direction?
A jumper will drift half a mile if they fall for one minute through winds that are blowing from the west at an average speed of 30 knots.
Explain about the Distance?Distance is an object's overall movement, regardless of direction. Regardless of an object's starting or ending point, distance can be defined as the amount of ground it has travelled.
The distance between two objects, points, lines, etc., in any direction. the condition or occurrence of being away from another object or person in space; distance. an area that is linear: Seven miles is too far to go in an hour of walking.
The entire path an object has taken can be used to define the distance of an object. an illustration If a car drives 5 km east, then turns to head north for 8 km, the final distance driven by the car must be 13 km.
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A boy is watching his grandfather fire an old cannon. He notices that whenever the cannonball is fired, it moves with a very high velocity to the right. He also notices that when the cannonball is fired, the cannon moves very slowly to the left. How does conservation of momentum explain these observations?.
Since the system's total momentum was zero before the cannon was fired, the momentum of the projectile and the cannon must be equal and opposing. The cannon will have a lower velocity since it has a lot greater mass.
Law of conservation of momentum states that total momentum of system remains conserved in the absence of external force.
As we know that know external no force is acting in the on the system therefore momentum should be conserved according to the law of the conservation of momentum.
As we know that momentum is given by the formula
momentum = mass × velocity
initially momentum of the system is equal to zero because the velocity of the system is zero.
After fire ball move with high velocity means we have some momentum in the direction of the ball's motion but according to the law of the conservation there should be some momentum in the opposite direction which will cancel out the momentum of the ball therefore cannon will also move in opposite direction.
But as we know that momentum = mass × velocity
As the mass of the cannon is much higher than the mass of the ball therefore less velocity can generate the same amount of the momentum that is required to the cancel the momentum of the ball .
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suppose you were to find all of the angles 8 at which two very narrow slits separated by a/2 would produce minimum. how would this set of angles be different from the set of angles given by your equation in part iii above?
This set of angles would be the angles at which destructive interference occurs, which is 180° apart from the angles at which constructive interference occurs.
What is Intensity?
The power transmitted per unit area is known as the intensity as well as flux of radiant energy.
Uses of Intensity
Intensity is most frequently used to describe the average power transfer above one period of the wave. Other situations where energy is transmitted can also be described in terms of intensity.
Hence, The set of angles given by the equation in Part III is the set of angles at which the maximum intensity of light is produced.
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This set of angles would be the angles at which destructive interference occurs, which is 180° apart from the angles at which constructive interference occurs.
What is Intensity?
The power transmitted per unit area is known as the intensity as well as flux of radiant energy.
Uses of Intensity
Intensity is most frequently used to describe the average power transfer above one period of the wave. Other situations where energy is transmitted can also be described in terms of intensity.
Hence, The set of angles given by the equation in Part III is the set of angles at which the maximum intensity of light is produced.
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A truck is traveling at 25 m/s on a slippery road. The driver slams on the brakes and the truck starts to skid. If the coefficient of kinetic friction between the tires and the road is 0. 20, how far will the truck skid before stopping?.
If the coefficient of kinetic friction among the tires and the street is 0. 20, 312.5m far will the truck skid before stopping.
What is kinetic friction?
Kinetic friction is defined as a force that acts between moving surfaces. A body moving on the surface experiences a force in the opposite direction of its movement. The magnitude of the force will depend on the coefficient of kinetic friction between the two materials.
m = the mass of the truck
N = normal reaction
g = 9.8 m/s²
μ = 0.2, the coefficient of kinetic friction
The resistive force on the truck is
F = μN = μmg = 0.2*(9.8)m = 1.96m N
The acceleration (actually deceleration) is
a = F/m = -1.96 m/s²
Let d = distance for the truck to come to rest from an initial velocity of u = 35 m/s.
Then
u² + 2ad = 0
(35 m/s)² + 2(-1.96 m/s²)(d m) = 0
d = 35²/3.92 = 312.5 m
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he purpose of low beam headlights is to provide better visibility to a driver driving in fog, rain and smoke. a) true b) false
Answer: True
Explanation:
Any external force that acts against movement is called __________. A. Gravityb. Efficiencyc. Resistanced. Momentum.
Answer:
the answer is resistance
(b) Explain the behaviour of the light at points Y and Z.
ray of
light
not to scale
Help
At a point, Y refraction is observed and the light ray is moving away from the normal means going from the denser to the rarer medium, at point Z, the light ray is moving towards the normal, which means travelling in the denser medium.
What is Refraction?The redirection of a wave as it travels through one medium and into another is called refraction. The wave's altered speed or a shift in the medium might both result in a redirection. Refraction of light is governed by Snell's rule, which states that for a given set of media, the ratio of the sines of the angle of incidence and angle of refraction is equal to the phase velocities (v1/v2) or, alternatively, the refractive indices (n2/n1) of the two media.
What is a Denser medium?A medium is said to be optically denser if the speed of light is lower in it. In terms of optical density, glass is a denser medium than air.
Hence, at a point, Y refraction is observed and the light ray is moving away from the normal means going from the denser to the rarer medium, at point Z, the light ray is moving towards the normal, which means travelling in the denser medium.
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Match each term with its definition.MorphemePhonemeGrammarSyntax1)smallest units of sound that carry meaning on their own2)smallest units of sound that make a difference in meaning3)combined set of rules that govern use of a particular language4)rules for forming speech sounds into phrases and sentences
All the terms are related to languages.
Morpheme - smallest units of sound that carry meaning on their own
Phoneme -smallest units of sound that make a difference in meaning
Grammar - a combined set of rules that govern the use of a particular language
Syntax - rules for forming speech sounds into phrases and sentences
The smallest linguistic unit capable of meaning modification is the phoneme.
Morphemes are divided into two distinct types, bases (or roots) and affixes.
Most people think of grammar as a set of rules that help us form sentences.It covers a variety of language-related topics, such as Parts of speech (verbs, adjectives, nouns, adverbs, prepositions, conjunctions, modifiers, etc.) Clauses (e.g. independent, dependent, compound) (e.g. independent, dependent, compound)
The sequence of grammatical elements like subjects, verbs, direct and indirect objects, etc. is determined by syntax in English.
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the mechanical advantage for a machine is defined as the output force divided by the input force. since the output force is typically greater than the input force, this value is normally greater than one. for an ideal machine, what would be another way of representing the mechanical advantage? the mechanical advantage for a machine is defined as the output force divided by the input force. since the output force is typically greater than the input force, this value is normally greater than one. for an ideal machine, what would be another way of representing the mechanical advantage? (output distance)/(input distance)
The mechanical advantage can also be represented as the ratio of output work divided by input work. This ratio is usually greater than one, indicating that the machine is doing more work than the input force is providing.
What is mechanical advantage?
The force amplified by using a device, mechanical device, or machine system is known as mechanical advantage. To achieve the desired output force amplification, the device trades off input troops against movement. The law of the lever serves as a model for this. Mechanisms are machine parts made to control forces and motion in this way. An ideal transmission system does not increase or decrease power. Consequently, the ideal machine is devoid of a power source, frictionless, and built from rigid materials that do not flex or wear.
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An ideal gas is initially in a state that corresponds to point 1 on the graph above, where it has pressure P1 volume V1, and temperature T1. The gas undergoes an isothermal process represented by the curve shown, which takes it to a final state 3 at temperature T3. If T2 and T4 are the temperatures the gas would have at points 2 and 4, respectively, which of the following relationships is true? a. t1
b. t1
c. t1
d. t1=t2
e. t1=t4
The following relationship is true T1 < T2.
An ideal gas is defined as a gas in which all collisions between atoms or molecules are perfectly elastic and no intermolecular attractive forces occur. It can be thought of as a collection of perfectly rigid spheres that collide but do not interact.
The volume of gas particles is negligible. Gas particles are the same size and have no intermolecular forces as other gas particles. Gas particles move randomly according to Newton's laws of motion. Gas particles undergo perfectly elastic collisions without losing energy. This is the relationship between four variables and describes the state of the gas.
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A 0,200-kg piece of lead at 100.0°C is dropped into a calorimeter. The calorimeter is a copper can of mass
5.00 x 102 kg and already contains 0.100 kg of water at 20.0°C. Calculate the final temperature if the specific heats of water, lead, and copper are 4.20 x 103 J/kg.K, 1.30 x 102 J/kg.K, and 4.00 x 103 J/kg:K respectively.
Answer:
24.5°C
Explanation:
an explosion in a rigid pipe shoots out three pieces. a 6 g piece comes out the right end. a 4 g piece comes out the left end with twice the speed of the 6 g piece. from which end does the third piece emerge?
In an explosion a 6 g piece comes out of the right end and a 4 g piece comes out of the left end at twice the speed of the 6 g piece and the third piece comes out of the right end.
Initially all three balls are at rest so u = 0
Given m1 = 6g and m2=4g where m is the mass of balls
Let v1 be the velocity of the first ball = v(i) (denoted as (i) since the right end points to the positive X axis)
Let velocity v2 of second ball = 2(v)(-i) (denoted as (-i) since left end points negative X axis)
Mass of the third ball m3 = m and its velocity v3 = v'
By applying conservation of momentum
m1(u1) + m2(u2) + m3(u3) = m1(v1) + m2(v2) + m3(v3)
Since all balls are initially at rest u1 = u2 = u3 = u = 0
0 = (6×10⁻³)(v)(i) + (4×10⁻³)(2v)(-i) + m(v')
m(v') = (2×10⁻³)(v)(i)
v’ = (2×10⁻³)(v)(i)/(m)
So positive (i) indicates right end
So the third ball comes from the right end.
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how much work does an elevator motor do to lift a 1500 kg elevator a height of 100 m ? express your answer with the appropriate units.
1.47 MJ work does an elevator motor do to lift a 1500 kg elevator a height of 100 m.
What is work in a physics?In physics, the term "work" refers to the energy transfer that takes place when an item is displaced over a distance by such an external force, at least a portion of which is supplied in the displacement direction. Stimulates into an object to cause some displacement is what is referred to as work. The ability to perform tasks is referred to as energy. The work is consistently the same.
Briefing:Work is simply the result of force multiplied by distance, so:
Work = Force * Distance
In this instance, force is simply equal to the elevator's weight, so:
Work = mass * gravity * distance
Work = 1500 kg * 9.8 m/s^2 * 100 m
Work = 1,470,000 J = 1.47 MJ
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if the moon rises around 3 a.m., its phase must be a) full. b) first quarter. c) third quarter. d) waning crescent. e) waxing crescent.
if the moon rises around 3 a.m., its phase must be Waning crescent .
What is meant by Waning crescent?The moon will look as a half moon, or third quarter moon, when the light level drops. The shadow cast by a third quarter moon will increase until it resembles a crescent form, which is known as a fading crescent.
A fading crescent moon has an illuminated area of less than 50% but is still growing.
You'll notice that the energy is waning as the moon begins to move back into the new phase, allowing you to calm down and devote more attention to your inner thoughts.
When the moon is transitioning from a full moon to a new moon, it is said to be in its declining phase. The declining moon, keep in mind sympathetic magick, is wonderful for banishing work, or cutting ,
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a 4 kg ball is thrown straight up in the air. what is the net force acting on the ball when it reaches its maximum height? g
A 4 kg ball is launched vertically into the air. The net force exerted on the ball at its highest point is 39.24N.
Given data
Ball mass m=4 kilogram
Gravitational acceleration is [tex]9.81 m/sec^{2}[/tex] , or g.
The location of the ball has no bearing on the net force applied to it in vertical projectile motion. As a result, the ball experiences a net downward force throughout its travel, and the size of this force is equal to the mass times the acceleration caused by gravity.
[tex]F_{net} = mg\\F= 4*9.81\\F= 39.24 N[/tex]
Therefore, the ball is subject to a net force of 39.24 N.
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On a train moving , 75 m/s you roll a ball towards the front of the train with a speed of 5m/s. Your friend standing some unknown distance away from you catches it. To a person outside the train, the ball traveled 220m until it was caught. How far away is your friend standing from you?
The distance of your friend from you is 15.7 m.
What is the time of motion of ball?
The time take for the ball to travel to you friend is calculated by applying the principle of relative velocity as shown below.
( Vt - Vb ) t = d
where;
Vt is the velocity of the trainVb is the velocity of the ballt is the time of motion of the balld is the distance travelled by the ball( Vt - Vb ) t = d
(75 - 5) t = 220
70t = 220
t = 220 / 70
t = 3.14 s
The distance of your friend from you is calculated as;
d1 = 5 m/s x 3.14 s
d1 = 15.7 m
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