A Nichrome wire 50 cm long and 0.27 mm in diameter is connected to a 1.5 V flashlight battery. What is the electric field inside the wire

Answers

Answer 1

Answer:

E=3V/m

Explanation:

The electric field here is simply the voltage running through the wire divided by its length. (Meaning E is independent of the diameter of the wire.)

Short work is in the attachment.

A Nichrome Wire 50 Cm Long And 0.27 Mm In Diameter Is Connected To A 1.5 V Flashlight Battery. What Is

Related Questions

what do u mean by the activity series of metals ??

Answers

Answer:

An activity series is a list of substances ranked in order of relative reactivity. For example, magnesium metal can knock hydrogen ions out of solution, so it is considered more reactive than elemental hydrogen. The activity series is a useful guide for predicting the products of metal displacement reactions.

Two long wires hang vertically. Wire 1 carries an upward current of 1.20 A. Wire 2, 20.0 cm to the right of wire 1, carries a downward current of 4.20 A. A third wire, wire 3, is to be hung vertically and located such that when it carries a certain current, each wire experiences no net force.
(a) Is this situation possible?
A. Yes
B. No
Is it possible in more than one way?
A. Yes
B. No
(b) Describe the position of wire 3.
distance ________ cm
direction: left of wire 1
(c) Describe the magnitude and direction of the current in wire 3.
magnitude
direction
down

Answers

Answer:

Explanation:

A, yes

b,

The force(per unit length) on wire 1 by 2 is to the left and

= μo*I1*I2/2πr

= 2*10^-7 * 1.2 * 4.2/0.20

= 5.04*10^-6N/m

From third law we have the force on wire2 by wire 1 is 5.04*10^-6N/m and to the right

So the magnitude of the force on each wire by wire 3 must be 4.2*10^-6N/m

Since the current in wire 2 is > wire 1 then wire 3 must be closer to wire 1 than 2

and wire 3 must be to the left of wire 1

Let x be the distance from wire 3 to wire 1 so x + 0.20 = distance from wire 3 to wire 2

Now μo*I1*I3/2πx = μo*I3*I2/2π(x + 0.20)

so solving for x we get

I1/x = I2/(x+0.20)

or x +0.20 = 4x

so x = 0.20/3 = 0.0667m

Now μo*I1*I3/2πx = 4.2*10^-6

so I3 = 4.2x10^-6 * 0.0667/(2.0x10^-7 * 1.2) = 1.167 A and its direction is down

Sabiendo que la velocidad de la luz en el Cuarzo es de 194.166.099 m/s y de 203.525.090 m/s en la glicerina: a) Hallar los índices de refracción absolutos en la glicerina y en el cuarzo. b) Hallar el índice de refracción relativo del agua respecto al diamante.

Answers

Answer:

a) glycerin  n = 1.5440 , quartz n = 1.4730

b)  n₂₁ = 0.550

Explanation:

The refractive index is

        n = c / v

where c is the speed of light in a vacuum and v the speed of light in the material medium

Let's use this expression to find the indexes of refraction

a) glycerin of v= 194166099 m / s

           n = 2,998 10 8/194166099

           n = 1.5440

quartz v = 203525090 m / s

          n = 2,998 108/203525090

         n = 1.4730

b) the relative refractive index is the relationship between the absolute refractive indices of two materials

      diamond n₁ = 2.417

      water n₂ = 1.33

   

the relative refractive index

              n₂₁ = n_water / n_diamond

              n₂₁ = 1.33 / 2.417

              n₂₁ = 0.550

A 145 lb diver stands at the end of a rigid 7 ft long diving board. What is the magnitude of the torque the diver exerts on the diving board

Answers

Answer:

Torque = 1015 ft.lb

Explanation:

Torque is defined as the turning effect of force. It is the force that can cause an object to rotate and gain some angular acceleration. Torque is basically an angular analog of force. The method to calculate torque is simple. Take the perpendicular distance from the line of action of force to the axis of rotation. Multiply this distance with the magnitude of force. The magnitude of this product gives the torque. Therefore,

Torque = (Force)(Perpendicular Distance)

Since, the diver is standing at the end of diving board.

Therefore,

Perpendicular Distance = 7 ft

Force = 145 lb

Therefore,

Torque = (145 lb)(7 ft)

Torque = 1015 ft.lb

An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.200 rev/s . The magnitude of the angular acceleration is 0.883 rev/s2 . Both the the angular velocity and angular accleration are directed counterclockwise. The electric ceiling fan blades form a circle of diameter 0.760 m .A. Compute the fan's angular velocity magnitude after time 0.204 s has passed.Express your answer numerically in revolutions per second.B. Through how many revolutions has the blade turned in the time interval 0.204 s from Part A?Express the number of revolutions numerically.C. What is the tangential speed vt of a point on the tip of the blade at time t = 0.204 s?Express your answer numerically in meters per second.D. Calculate the magnitude atat of the tangential acceleration of a point on the tip of the blade at time t = 0.204 s.Express the acceleration numerically in meters per second squared.

Answers

Answer:

(A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

Explanation:

Given that,

Initial angular velocity = 0.200 rev/s

Angular acceleration = 0.883 rev/s²

Diameter = 0.760 m

Time = 0.204 s

(A). We need to calculate the angular velocity of fan

Using equation of angular motion

[tex]\omega_{f}=\omega_{i}+\alpha t[/tex]

Put the value into the formula

[tex]\omega_{f}=0.200+0.883\times0.204[/tex]

[tex]\omega_{f}=0.380\ rev/s[/tex]

(B). We need to calculate the number of revolution

Using formula of angular displacement

[tex]\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2[/tex]

Put the value into the formula

[tex]\theta=0.200\times0.204+\dfrac{1}{2}\times0.883\times(0.204)^2[/tex]

[tex]\theta=0.059\ rad[/tex]

(C). We need to calculate the tangential speed of the blade

Using formula of speed

[tex]v=\dfrac{d}{2}\omega_{f}[/tex]

Put the value into the formula

[tex]v=\dfrac{0.760}{2}\times0.380\times2\pi[/tex]

[tex]v=0.907\ m/s[/tex]

(D). We need to calculate the tangential acceleration of the blade

Using formula of tangential acceleration

[tex]a_{t}=\alpha r[/tex]

Put the value into the formula

[tex]a_{t}=0.883\times0.38\times2\pi[/tex]

[tex]a_{t}=2.10\ m/s^2[/tex]

Hence, (A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

A radio technician measures the frequency of an AM radio transmitter. The frequency is . What is the frequency in megahertz? Write your answer as a decimal.

Answers

Complete Question

A radio technician measures the frequency of an AM radio transmitter. The frequency is 14603 kHz . What is the frequency in megahertz? Write your answer as a decimal.

Answer:

The value is  [tex]x = 14.6 \ MHz[/tex]

Explanation:

From the question we are told that

  The  frequency is  [tex]f = 14603 \ kHz = 14603 *1000 = 14603000 \ Hz[/tex]

Generally  

       [tex]1 Hz \to 1.0 *10^{-6} \ MHz[/tex]

       [tex]14603000 \ Hz \to x MHz[/tex]

=>   [tex]x = \frac{14603000 * 1.0*10^{-6}}{1 }[/tex]

=>    [tex]x = 14.6 \ MHz[/tex]

Explain how your weight can change even though your mass remains the same.

Answers

Answer:

See explanation below

Explanation:

Recall that Weight is a Force that results from the action of a gravitational field on our body mass. Therefore if one changes locations to places where the acceleration of gravity is different, our weight can change although the mass of our body stays the same.

For example, going to a high mountain, where the acceleration of gravity is a little smaller than at sea level, will produce such change. Also, going to another planet with different gravitational field, or going to the Moon (where the acceleration of gravity is about 1/6 of that on Earth which therefore will reduce our weight without reducing our mass)

Since weight is calculated with the equation:

Q=mg

the weight can also change when the gravitational acceleration (g) changes.

g can change at example when you travel to a different planet or (slightly) when gaining attitude on Earth (e.g. when climbing a mountain or flying on a plane you get lighter).

What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms of F

Answers

Answer:

1.5F

Explanation:

Using

E= F/q

Where F= force

E= electric field

q=charge

F= Eq

So if qis tripled and E is halved we have

F= (E/2)3q

F= 1.5Eq=>> 1.5F

Describe the motion of an object:
a. for which the direction of the acceleration is the same as the direction of motion of the object.
b. for which the direction of the acceleration is opposite to the direction of motion of the object.
c. for which the change in velocity is zero.
d. for which the initial velocity is zero but the acceleration is not zero.

Answers

Answer:

A. Here object is moving with increasing velocity

B. Here the object is moving with decreasing velocity that is it is decelerating

C. Here the initial and final velocity are the same so the object moves at constant velocity

D. Here the object started from rest but reached a certain velocity with time so a non zero acceleration was attained

Answer:

Answer:

A. Here object is moving with increasing velocity

B. Here the object is moving with decreasing velocity that is it is decelerating

C. Here the initial and final velocity are the same so the object moves at constant velocity

D. Here the object started from rest but reached a certain velocity with time so a non zero acceleration was attained

Explanation:

The simplest branched-chain hydrocarbon is

A ethane

B ethene

C  propane

D  butane

Answers

Answer:

Butane

Explanation:

Help me please !!!!!

Answers

Answer:

confounding cause they had exposure to many programmes

Answer:

Confounding should be your answer please mark brainliest

An electron is located on the x ‑axis at x0=−2.05×10−6 m . Find the magnitude and direction of the electric field at x=2.77×10−6 m on the x ‑axis due to this electron.

Answers

Answer:

The  value is  [tex]E =  62 \  N/C[/tex]

Explanation:

From the question we are told that

   The initial position of the electron  [tex]x_o  =  -2.05*10^{-6} \  m[/tex]

     The  position that is  considered [tex]x=  2.77*10^{-6} \  m[/tex]

Generally the electric field is mathematically represented as

       [tex]E =  k * \frac{q}{r^2 }[/tex]

Here k is the coulombs constant  with value  [tex]k  =  9*10^9  \  \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]

r is  the distance covered which is mathematically represented as

         [tex]r =  x- x_o[/tex]

        [tex]r =  2.77*10^{-6} -(-2.05*10^{-6})[/tex]

         [tex]r =  4.82 *10^{-5}[/tex]

So

     [tex]E  = \frac{9*10^9 *  1.60*10^{-19}}{ (4.82 *10^{-6})}[/tex]

      [tex]E =  62 \  N/C[/tex]

     

Answer:

Direction: Negative x-direction

Explanation:

The question tells you that both lie on the   ‑axis, and the data indicate that the electron is in the negative   ‑direction from the field point ( 0< ). Because the field produced by a negative source charge points toward the source, the field in this case points in the negative   ‑direction.

URGENT!!!!!! Assume that a wire has 1.5 ohms of resistance. If the wire is connected to two batteries with a total voltage of 3.0 V, how much current will flow through the wire? 3.0 amps 2.3 amps 2.0 amps 1.0 amps

Answers

Answer:

  2.0 amps

Explanation:

Current is the ratio of voltage to resistance:

  I = V/R = (3.0)/(1.5) = 2.0

The current in the wire is 2.0 amps.

While John is traveling along a straight inter-
state highway, he notices that the mile marker
reads 241 km. John travels until he reaches
the 145 km marker and then retraces his path
to the 174 km marker.
What is John's resultant displacement from
the 241 km marker?
Answer in units of km.

Answers

Answer:

His displacement is 260 – 169  = 91 km

His distance traveled is (260 – 134) + ( 169 – 134 ) = 161 km

Explanation:

what are the x and y components of the vector that has a magnitude of 4N and a direction of 30 degrees

Answers

Answer:

We are given

vector as 4N and direction 30°

So since X-component is

adjacent /hypotenuse which is cosine we have

= 4 cos 30 = 3.46 N

And Y-component which is opposite/hypotenuse we have

= 4 sin 30 = 2N

What are the magnitude and direction of the net force on the third spider (S3) when it is resting at the origin

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  magnitude is  [tex]F_3 =0.62\ N[/tex]

Explanation:

From the question we are told that

    The distance between the spiders is  [tex]a =0.59\ m[/tex]

    The  charge on the [tex]S_1\ and\ S_3[/tex] is  [tex]q_{1}=q_{3}=q =+4.9\mu \ C[/tex]

     The  charge on [tex]S_2[/tex] is  [tex]q_2 = 4.9\mu \ C[/tex]

Given that the charge are arranged in an equilateral triangle, it implies that the angle at each vertices of the triangle is  60°

Generally the magnitude of net force on [tex]S_3[/tex] is mathematically represented as

   [tex]F_3= F_{13} cos(60)+ F_{21} cos(60)[/tex]

So

  [tex]F_{13} =\frac{k* q^2 }{a^2}[/tex]

Here k is the columns constant with value   [tex]k =  9*10^9 \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]

So

    [tex]F_{13}=\frac{9*10^9*((4.9*10^{-6})^2)}{0.59^2}[/tex]

=>  [tex]F_{13} =  0.62 \  N[/tex]

From the diagram we see that [tex]F_{13}= F_{23} =  0.62\  N[/tex]

So

    [tex]F_3=0.62cos(60)+0.62cos(60)[/tex]

     [tex]F_3 =0.62\ N[/tex]

Now from the diagram the ls [tex]270^o[\tex] counterclockwise from x-axis

     

what is achmedis principle

Answers

Answer:

Archimedes principle states that when a body is partially/wholly/completely immersed in fluid (liquid or gas),it experiences an upthrust which is equal to the weight of the fluid displaced....

In a particular wire in a circuit, conventional current flows in the z direction. What is the direction of electron current in the wire

Answers

Answer:

Electron current will flow in the negative z axis

Explanation:

This is because flow of conventional current is opposite that if electron current so since conventional is in +z axis electron will be -z axis

According to Newton's Third Law, if someone jumps off a skateboard, the
skateboard will roll backwards because

Answers

Answer:

every action has a same an equal reaction

If someone jumps off a skateboard, the  skateboard will roll backwards because action and reaction are equal and opposite.

Newton's third law states that action and reaction are equal and opposite. That is, for every action there is a resulting reaction equal in magnitude to the action but opposite in direction.

If someone jumps off a skateboard, he will exert an action force downwards while the skate board exerts a reaction force upwards on him. This causes the skateboard to move backwards while he moves upwards.

Thus,  if someone jumps off a skateboard, the  skateboard will roll backwards because action and reaction are equal and opposite.

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A stretched string is 2.11 m long and has a mass of 19.5 g. When the string oscillates at 440 Hz , which is the frequency of the standard A pitch, transverse waves with a wavelength of 15.3 cm travel along the string. Calculate the tension T in the string.

Answers

Answer:

The tension of the string is 41.876 N

Explanation:

Given;

length of the string, L = 2.11 m

mass of the string, m = 19.5 g = 0.0195 kg

frequency of the wave, f = 440 Hz

wavelength, λ = 15.3 cm = 0.153 m

The velocity of the wave is given by;

v = fλ

v = 440 x 0.153

v = 67.32 m/s

Also the velocity of the wave is given by

[tex]v = \sqrt{\frac{T}{\mu} }[/tex]

where;

μ is mass per unit length = 0.0195 / 2.11 = 0.00924 kg/m

T is the tension of the string

T = v²μ

T = (67.32)²(0.00924)

T = 41.876 N

Therefore, the tension of the string is 41.876 N

Most scientific experiments are what type experiment, mostly because it is simpler and easier to test single variables? a) Natural experiment. b) Controlled experiment. c) Forced experiment. d) Redundant experiment.

Answers

Answer:

The correct answer is : option B. controlled experiments.

Explanation:

A scientific experiment which deals with a single variable at a time and compared the independent variable to a controlled variable after measuring the change in dependent variable.

It is a very simple and easy test for single variable. In these experiments subjects are divided in two groups one one, with independent variable and other variable.

Thus, the correct answer is : option B. controlled experiments.

A billiard ball moves with 3 kg⋅m/s of momentum and strikes three other billiard balls. What is the total momentum of the balls after the collision? A. less than 3 kg⋅m/s B. It depends on the mass of each ball. C. 3 kg⋅m/s D. more than 3 kg⋅m/s

Answers

Answer:

It should be C

Explanation:

It depends on the mass of each ball

Remember the formula for momentum, mass X velocity

Momentum depends on the mass of the object

The momentum of the billiard balls after the collision is 3 Kgm/s.

Let the billiard ball be B.

Given the following data:

Momentum B = 3 Kgm/s

To find the momentum of the balls after the collision:

Momentum is simply a multiplication (product) of the mass of an object with its velocity.  Also, momentum is a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

[tex]Momentum = Mass[/tex] × [tex]Velocity[/tex]

[tex]Total \; momentum = Momentum \; B + Momentum \;of \;the \;other\; balls.[/tex]

Since the other billiard balls were at rest (not experience any motion), there velocities would be zero (0) m/s.

Substituting the values, we have:

[tex]Total \; Momentum = 3 + 0[/tex]

Total momentum = 3 Kgm/s.

Therefore, the momentum of the billiard balls after the collision is 3 Kgm/s.

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what is systematic error ?​

Answers

Explanation:

Systematic error (also called systematic bias) is consistent, repeatable error associated with faulty equipment or a flawed experiment design. These errors are usually caused by measuring instruments that are incorrectly calibrated or are used incorrectly.

Powerful sports cars can go from zero to 25 m/s (about 60 mph) in 6 seconds. What is the magnitude of the acceleration, including units

Answers

Answer:

The magnitude of the acceleration is 4.2 m/s²

Explanation:

Given;

initial velocity of the powerful sports car, u = 0

final velocity of the powerful sports car, v = 25 m/s

time of motion, t = 6 seconds

Acceleration = Δv / Δt

Δv is change in velocity

Δt is change in time

The magnitude of the acceleration of the powerful sports car during the motion is given by;

[tex]a = \frac{v-u}{t}\\\\a = \frac{25-0}{6}\\\\a = 4.2 \ m/s^2[/tex]

Therefore, the magnitude of the acceleration is 4.2 m/s²

The magnitude of the acceleration is 4.2 m/s²

The calculation is as follows:

Given that

initial velocity of the powerful sports car, u = 0

final velocity of the powerful sports car, v = 25 m/s

time of motion, t = 6 seconds

Now the magnitude should be

[tex]= (25 - 0) \div 6[/tex]

=  4.2 m/s²

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A bus took 8 hours to travel 639 km. For the first 5 hours, it
travelled at an average speed of 72 km/h. What was the
average speed for the remaining time of the journey?

Answers

Answer:

93

Explanation:

explain the different methods that can be used to model the motion of an object.

Answers

Answer:Even things that appear to be at rest move.

When we describe the motion of one object with

respect to another, we say that the object is moving

relative to the other object.

• A book that is at rest, relative to the table it lies

on, is moving at about 30 kilometers per second

relative to the sun.

• The book moves even faster relative to the center

of our galaxy.

Explanation:

Which of Jafar's statements are correct regarding distance and displacement?

Answers

Answer:The distance and magnitude of displacement are sometimes equal." Jafar is correct. The distance traveled and the magnitude of displacement are equal if and only if the path is a straight line in one direction.

Explanation:

The gravitational pull of the sun on Earth keeps Earth orbiting around the sun. Which statement is correct about the force that Earth exerts on the sun?


A. Earth pulls the sun away from itself with a force equal to the ratio of the mass of the sun to the mass of Earth.

B. Earth pulls the sun toward itself with a force equal to the ratio of the mass of the sun to the mass of Earth.

C. Earth pulls the sun away from itself with an equal force.

D. Earth pulls the sun toward itself with an equal force,​

Answers

Answer:

Earth pulls the sun towards itself with a force equal to the ratio of the mass of the sun to the mass of Earth

The Earth pulls the sun toward itself with an equal force. (Option D)

According to the 3rd Newton's Law, forces existing in the universe are shown in pairs, that is to say, for all action force, there is a corresponding reaction force of equal magnitude and opposite direction. By the Newton's Law of Gravitation we understand that gravitation between the Sun and the Earth is done because of a gravitational field created by mutual interaction, in terms of their masses and distance among them. The pair of forces is not based on direct contact.

Hence, we conclude that the Earth pulls the sun toward itself with an equal force.

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The horizontal and vertical components of the initial velocity of a projectile are 50 m/s and 120 m/s respectively. What is the magnitude of the initial velocity

Answers

Answer:

50 m/s

Explanation:

In a projectile motion, acceleration is only on the vertical plane, that is, the vertical velocity is the only velocity component that undergoes acceleration under gravitational force. The horizontal component of velocity dos not change with time, and hence is the same as the initial velocity of the projectile.

A 400 N steel ball is suspended by a light rope from
the ceiling. The tension in the rope is​

Answers

Answer:

As force = tension in string so tension in string is 400N

Explanation:

Tension in the rope is "400 N".

Tension is the force developed inside a flexible material or medium, such as a cable, wire, or rope. This force depends upon the externally applied load. In the case of equilibrium, the tension in a rope or string is equal to the load applied to the rope or string, externally.

Since the steel ball and the rope system is in equilibrium in our case. Therefore, the tension in the rope must be equal to the load (weight) of the steel ball:

Tension = Weight of Steel Ball

Tension = 400 N

Learn more about Tension here:

https://brainly.com/question/19802859?referrer=searchResults

https://brainly.com/question/2008782?referrer=searchResults

The attached picture shows the tension on a steel ball hung by a rope.

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