b. The enzyme and substrate would be stuck together.
Gases are formless fluid that expands to occupancy the space or enclosure they are contained in ? True or false
Answer:
true
Explanation:
Gases are in fact formless liquid that expands to occupancy the space or enclosure they are contained in.
Which of the following example(s) does NOT cause bias in a research study.
A) Measuring body temperature with an oral thermometer in half of subjects and an ear thermometer in others
B) Counting the number of firefighters at your house to predict if it will be destroyed
C) Using a set of standardized questions to measure food intake in children
D) Studying workers to see the effects of a new health care law on unemployed
name two major vessels that return oxygen-poor blood to the heart. What are the damages for each? Where do they terminate?
Answer:
1. Head, neck, upper limb, thorax - super vena cava - top of the right atrium.
2. Lower limb - inferior vena cava - bottom of the right atrium.
Explanation:
The Heart pumps the oxygen-rich blood to the different parts of the body to Otake oxygen and nutrients to these organs and then takes the oxygen-poor blood returns from the body to the heart.
The two major vessels that return oxygen-poor blood to the heart are 1. superior vena cava (SVC) that drainages Head, neck, upper limb, thorax and terminate at top of the right atrium, and 2. inferior vena cava (IVC), Lower limb and terminate at bottom of the right atrium.
1. Head, neck, upper limb, thorax - super vena cava - top of the right atrium.
2. Lower limb - inferior vena cava - bottom of the right atrium.
Indicate the steps of eukaryotic DNA replication in order, from when a germ cell enters gap 1 (G1) phase to the cell cycle termination.
a. RNA primers are added to provide a 3 end for elongation.
b. RNA is replaced with DNA and lagging strands are joined,
c. Prereplication complex forms at one of many origins of replication.
d. DNA polymerase synthesizes both the leading and lagging strands from 5' to 3'.
e. Active telomerase can extend the lost telomere region.
f. The initiation complex creates an active replication fork as helicase unwinds DNA.
Answer:
Explanation:
1. Prereplication complex forms at one of many origins of replication.
2. The initiation complex creates an active replication fork as helicase unwinds DNA.
3. RNA primers are added to provide a 3 end for elongation.
4. DNA polymerase synthesizes both the leading and lagging strands from 5' to 3'.
5. RNA is replaced with DNA and lagging strands are joined.
6. Active telomerase can extend the lost telomere region.
All these process are the steps involved in the replication of DNA. The replication of DNA involves the biological production of two identical copies of DNA from one original DNA molecule. This is a very important biological process of life as it is involved in the inheritance pattern of life. It is essential in that the 2 daughter cells formed must contain the same sets of chromosome as the original parent.
Which statement describes one aspect of an earthquake's magnitude?
It is measured by the Mercalli scale.
It is based on the size of seismic waves.
O It is not usually affected by the amount of fault movement.
It is used to determine damage caused by earthquakes.
Answer:
b. It is based on the size of seismic waves
Explanation:
just did the test
The statement that describes one aspect of an earthquake's magnitude is: "It is based on the size of seismic waves."
What is an earthquake's magnitude?An earthquake's magnitude is a measure of the amount of energy released by the earthquake, and it is determined by measuring the amplitude (height) of the seismic waves generated by the earthquake. The size of the seismic waves is directly related to the amount of energy released by the earthquake, and this is used to calculate the earthquake's magnitude.
The most commonly used scale for measuring earthquake magnitude is the Richter scale, which is based on the amplitude of the largest seismic wave recorded on a seismogram. Other scales, such as the moment magnitude scale, are based on the seismic moment, which takes into account the size of the fault rupture and the amount of slip on the fault.
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what kind of molecule is represented in the diagram?
Answer:
The answer is option B.
TriglycerideHope this helps you
150 ml of 54% CaCI2 solution contains how many grams of CaCI2?
Answer:
mass of CaCl₂ = 67.4 g of CaCl₂
Explanation:
A 45% CaCl₂ Solution contains 45 g of solute per 100 mL of solution.
mass concentration = mass of solute (g)/ volume of solution (L)
100 mL of solution = 100 * 1L /1000 = 0.1 L
Mass concentration of solution = 45 g/0.1 L = 450 g/L
Molar concentration of solution = mass concentration / molar mass
molar mass of CaCl₂ = 111 g/mol
molar concentration = 450 g/L / 111 g/mol = 4. 05 mol/L
Number of moles of CaCl₂ present in 150 ml of 4.05 mol/L solution = molar concentration * volume (L)
number of moles of CaCl₂ = 4.05 * 150 * 1 L/1000 = 0.6075 moles
mass of CaCl₂ present in 0.6075 moles = number of moles * molar mass
mass of CaCl₂ = 0.6075 * 111 = 67.4 g of CaCl₂
What is the average life span of juvenile upland game birds
Answer:
90 percent
Explanation:
Based on average estimated juvenile and adult survival rate for each species
When ______ is released, the subsequent receiving neuron ________ fire because that neurotransmitter is _______.
Answer:
When a neurotransmitter is released, the posterior receptor neuron has the receptor to bind to it because that neurotransmitter is a stimulator of the postsynaptic membrane.
Explanation:
The neurotransmitters that are released from the motor plate, that is, from the postsynaptic membrane to the presynaptic space, are captured by receptors of the postsynaptic membrane, which can be another neuronal structure to transmit an impulse or a muscle to be able to execute the contraction.
I leave you an image that draws up the stimulation of the postsynaptic membrane by means of a neutrotranismor, these are called as: adrenaline, norepinephrine, acetylcholine, etc.
Number 1 is the presynaptic membrane that releases the neurotransmitter (yellow balls), number 2 is the intersynaptic space, 3 is the postsynaptic membrane that in number 4 can be seen to be activated by relating to the neurotransmitter
DNA is found in the nucleus of our cells, bundled together into structures called
Answer:
chromatin
Explanation:
DNA is normally found as a loosely contained structure called chromatin within the nucleus. When a cell is about to divide, the chromatin coils tightly and condenses to form chromosomes.
A researcher with a reputation for yelling at graduate students wants to know how the seed yield of transgenic plants (that are constructed specifically with the objective of increasing seed yield) she is growing in a plot compares to that of the wild-type plants growing in another plot. The entire population of the wild-type plants have been characterized, but she only has enough funding to measure a sample of the transgenics. Her null hypothesis is that the average seed yield of the transgenics will not differ from the wild-type. Her graduate student secretly has an arm injury, and hasn't told her for fear of inciting the researcher's reputed wrath. Because his arm hurts, the graduate student inadvertently collects less heavy samples. This type of non-random sampling would increase the likelihood of committing a Type II error.
a. True
b. False
Answer:
False, it is a Type I error.
Explanation:
A Type II error is produced by not reject the null hypothesis when the alternative hypothesis is true, thereby the null hypothesis is false, but is erroneously not rejected. On the other hand, the Type I error may be caused by random variation in the data or errors in the research techniques to be used when the sample is obtained.
In this case, it is a Type I error caused when the sample was obtained (i.e., due to the graduate worker collected less heavy samples).
As we continue to learn, what allows our brain to reformat and adapt by developing new neural pathways?
Answer:
Developing new neural pathways
Deficiency of which material leads to anaemia ?
Answer:
iron
Explanation:
iron is present in red blood cells. Without it the RBC's start to die and are less in number. Which causes anaemia.
Which explanation provides support for continental drift theory?
O Dinosaurs lived on many continents.
Coal fields match up across continents.
Tropical plant fossils were found in warm areas.
Similar rock types are found across continents.
Answer and explanation:
Among the main evidences of the theory of continental drift, we can mention the fit of the lines of the coasts of several continents, In addition to the similarity between several relief structures and rocks in different continents (such as mountain ranges found in South America and on the east coast of Africa).
There are also records of fossils of identical extinct plants, found on the African continent and also in countries like Australia, India and Brazil, for example.
Identical reptile fossils have also been found in Africa and South America, in addition to several correlations in the distribution of aquatic dinosaur fossils that lived in common areas of the ancient supercontinent.
Answer:
Similar rock types are found across continents.
Explanation:
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Conjugated enzymes are a key component of ELISA. To what are these enzymes conjugated, and why is that important?
Answer:
To the antigen so the enzymes are only present when the molecule of interest is also present
To the plastic of the reaction well so the enzymes can concentrate the molecule of interest
To the capture antibody so the enzymes are only present when the molecule of interest is also present
To the detection antibody so the enzymes are only present when the molecule of interest is also present
Explanation:
Describe how the end product of digestion of fats and oils is absorbed in humans
Answer:
Hello
In the small intestines bile emulsifies fats while enzymes digest them. The intestinal cells absorb the fats. Long-chain fatty acids form a large lipoprotein structure called a chylomicron that transports fats through the lymph system.
hope this answer is correct
In the small intestines bile emulsifies fats while enzymes digest them. The intestinal cells absorb the fats.
What is the end product of digestion of fats and oils?Lipids (fats and oils) are broken down in the small intestine. The enzyme lipase is responsible for breaking down lipids into fatty acids and glycerol.
How are the end products of fat digestion absorbed?Micelles transport the end products of lipid digestion (free fatty acids and monoglycerides) to the digestive tract lining for absorption.
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which proteins serves as a chemical messenger
Answer:
Neuropeptides
Explanation:
They are proteins that function as chemical messengers and are released by neurons. They contain 3 to 36 amino acids.
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What factor about cellular respiration are you testing? (What makes the three bottles different?)
Answer:
The factor under study here is the gas inside of the bottles.
Explanation:
Cellular respiration is one of the key biological processes that are literally sustaining life. It occurs in every living cell in order to provide it the energy (in the form of ATP) to carry out the several processes required to function as a cell or as an organism as a whole.
Why does the pattern recognition strategy affect prokaryotic and eukaryotic pathogens as well as hosts
Answer:
A Because all are complex cells with certain functions that cannot be greatly altered without affecting fitness.
B Because VSG switching may not be restricted to trypanosomes.
C Because all have proteins in their cell walls or cell membranes.
D None of these answers are correct.
The answer is C .Because all have proteins in their cell walls or cell membranes.
Explanation:
Pattern recognition strategy employs the use of pattern recognition receptors which are proteins for the recognition of molecules frequently found in pathogens. When they are recognized, the body then marks the cells for destruction.
Pattern recognition strategy affect prokaryotic and eukaryotic pathogens as well as hosts because all have proteins in their cell walls or cell membranes and they help in the recognition of pathogens or host for further action on them.
Which of the following group of bones in the human body categorized according to shape is correct?
Group of answer choices
skull bones-flat bones
arm and leg bones-short bones
coxal bone- short bone
wrist and ankle -long bones
Answer:
The answer is skull bones-flat bones
Hope this helps you
Most hurricanes will originate a. near the North Pole. b. in the equatorial region. c. when the water and air are cold. d. below the ocean’s surface currents.
Answer:
The answer is c.
Explanation:
Answer:
c
Explanation:
1. which pair of bacteria can be differentiated by oxidase test?
A. Pseudomonas and E. coli
B. Salmonella and Proteus
C. Proteus and E. coli
D. Shigella and Salmonella
2. Colonies of which color would you expect on HE agar if shigellosis is suspected?
A. Pink
B. Red with black center
C. Red without black center
D. Green with black center
E. Green without black center
3. Colonies of which color would you expect on HE agar if Enterococcus sp. is suspected?
A. Pink
B. Salmon/orange
C. Red with black centers
D. Green with black centers
E. None of the above
Answer:
1. A. Pseudomonas and E. coli
2. B. Red without black center
3. B. Salmon/orange
Explanation:
Pseudomonas is referred to as an oxidase positive bacteria while E. Coli is an oxidase negative bacteria. The use of the oxidase test will be helpful in the differentiation of the two Bacteria according to their oxidase activity/properties.
Colonies of Red without black center color is what is expected on HE agar if shigellosis is suspected.
Colonies of Salmon/Orange color is what is expected on HE agar if Enterococcus sp. is suspected.
Streptomyces griseus produces the antibiotic Streptomycin, which inhibits protein synthesis by binding to ribosomes and preventing the binding of fMet‐tRNA. Why isn’t S. griseus harmed by its own antibiotic?
Answer:
See the answer below.
Explanation:
Antibiotic-producing bacteria are generally known to have a mechanism that enables them to be resistant to their own antibiotics. The mechanism that enables them to be resistant to their own antibiotic depends largely on the mode of action of the antibiotic substance.
Some of the popular mechanisms used by bacteria to counter their own antibiotic substance include a mutation in the target gene, production of enzymes that inactivate the antibiotic compounds, or efflux of the compounds.
In the case of Streptomyces griseus, the inactivity of streptomycin has been linked with the production of a phosphatase inhibitor that prevents streptomycin from getting access to the target site. Hence, the organism is not harmed by its own antibiotic.
When a scientist is designing an experiment, _____ groups are made.
1
2
3
4
Answer:
Scientist makes 2 groups.
Explanation:
One experimentle group and other is controle group.
How does music affect plant growth? To answer this question
select the choices that are true statements of the similarities between dna and rna
Answer:
They are both acids
DNA is deoxyribonucleic acid, while RNA is ribonucleic acid.
What is the average life span of juvenile upland game birds
Answer:
27 years
Explanation:
Specialized cells such as white blood cells interact with foreign particles in the body. A particular cell belonging to this category recognizes bacteria and forms a covering around it, pinching off the vacuole. The cell then performs . The foreign particles recognized by the particular type of cells differ from the ones recognized by another type of white blood cell. This situation indicates that the receptors are .
Answer:
specific
Explanation:
The immune system contains different types of cells that act in both innate and acquired (adaptive) immune responses to destroy pathogenic microorganisms that invade our body. The immune cells include B and T cells, dendritic cells, macrophages, neutrophils, eosinophils, monocytes, etc. These cells contain specific receptors that play different roles in the immune response. For example, macrophages and dendritic cells contain receptors required for antigen presentation, while white blood cells (B and T cells) have receptors required for antigen recognition.
Answer: I just took the test
Explanation:
Here's the answer
Use the completed Punnett square in Part B to answer the questions below about the F2 generation.
Note that questions 3 and 4 require a more advanced evaluation of probabilities than do questions 1 and 2 because you have to consider all possible groupings and orders of three F2 seeds. If you need help with these calculations, use Hint 3.
Complete question:
Part C: Using the Punnett square to make predictions
Use the completed Punnett square in Part B to answer the questions below about the F2 generation.
Note: You will find the Punnet square in the attached files.
Note that questions 3 and 4 require a more advanced evaluation of probabilities than do questions 1 and 2 because you have to consider all possible groupings and orders of three F2 seeds. If you need help with these calculations, use Hint 3.
1) What is the probability that an F2 seed chosen at random will be yellow?
2) What is the probability that an F2 seed chosen at random from along the yellow seeds will breed true when selfed?
3) What is the probability that three F2 seeds chosen at random will include at least one yellow seed?
4) What is the probability that three F2 seeds chosen at random will include one green seed and two yellow seeds?
Answer:
1) 3/4
2) 1/3
3) 63/64
4) 27/64
Explanation:
Y is the dominant allele and expresses yellow color y is the recessive allele and expresses green colorSeeds with YY and Yy genotype are yellowSeeds with yy genotype are greenParental) Yy x Yy
Gametes) Y y Y y
Punnet Square)
(1/2) Y (1/2) y
(1/2) Y (1/4) YY (1/4) Yy
(1/2) y (1/4) yY (1/4) yy
F2) 1/4 YY
2/4 = 1/2 Yy
1/4 yy
1) There will be 3/4 of probabilities of getting a yellow F2 seed
1/4 YY + 2/4 Yy = 3/4 Y-
The symbol "-" means that in its position there might be either a Y or y allele.
2) As there are only three yellow possible genotypes for yellow seeds, the fourth genotype for green seeds is not considered. Our pool now is only yellow seeds. So the probability of getting a pure breeding yellow seed among all yellow seeds is 1/3.
1/3 YY
1/3 Yy
1/3 yY
In the pool of yellow seeds, there are three genotypes, and only one of them corresponds to pure breeding yellow seed.
3) To calculate the probability of getting at least one yellow seed among the three seeds randomly chosen, we need to multiply and then perform addition. This is, when we take three seeds from the pool, we have different possibilities of getting seeds with different genotypes. So:
the three chosen seeds could be yellow. In this case, we multiply their probabilities. The probability of getting one yellow seed is 3/4, so, the probabilities of getting three yellow seeds are: 3/4 x 3/4 x 3/4 = 27/64There might also be one green sees and two yellow seed, so we multiply their probabilities in the order in which we might get them. This is:
Two yellow seeds and one green seed: 3/4 x 3/4 x 1/4 = 9/64One yellow seed, one green seed, and one yellow seed: 3/4 x 1/4 x 3/4 = 9/64one green seed, and two yellow seeds: 1/4 x 3/4 x 3/4 = 9/64And we could also get two green seeds and only one yellow seed:
Two green and one yellow seed: 1/4 x 1/4 x 3/4 = 3/64one green, one yellow and one green: 1/4 x 3/4x 1/4 = 3/64one yellow seed and two green seeds: 3/4 x 1/4 x 1/4 = 3/64Now, having all the possibilities, we just need to add all the possibilities:
27/64 + 9/64 + 9/64 + 9/64 + 3/64 + 3/64 + 3/64= 63/64.
Note that we did not include the possibility of getting three green seeds (1/4 x 1/4 x 1/4). This is because we were asked to calculate the probabilities of getting AT LEAST one yellow seed.
4) To calculate the probability of getting two yellow seeds and one green seed among the three seeds randomly chosen, we should multiply probabilities and then sum them up.
The orders in which we could get the seeds are:
Two yellows and one green: 3/4 x 3/4 x 1/4 = 9/64One yellow, one green, and one yellow: 3/4 x 1/4 x 3/4 = 9/64one green seed and two yellow seeds: 1/4 x 3/4 x 3/4 = 9/64Now, having all the possibilities, we just need to add all the possibilities:
6/64 + 9/64 + 9/64 = 27/64.
Answer:
1) 3/4
2) 1/3
3) 63/64
4) 27/64
Explanation:
1) yellow seed could either be GG, Gg or Gg from Punnett square, therefore, there is a 3/4 probability
2) true-breeding = either GG or gg. Therefore, out of the 3 yellow seed options, only 1 is true-breeding, therefore, it's a 1/3 probability
3) "there are 7 possible groupings that have at least 1 yellow seed; the sum of their individual probabilities yields the final answer of 63/64. Note that you could have also calculated this answer by subtracting the probability of the one category that doesn’t fit the criterion (Green, Green, Green) from the total probability (1 – 1/64 = 63/64)"
4) "there are 3 possible groupings that have 1 green and 2 yellow seeds; the sum of their individual probabilities yields the final answer of 27/64"
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What precautionary measure should be taken when storing oil and fats at home?why homogenization and pasteurization of milk are performed at an industrial scale?what are the possible hazards that come across while determining protein content of the meat by kjeldhal appratus?
Answer:
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