The mixture flow rate in lbm/h = 117.65 lbm/h
Further explanationGiven
15.0 wt% methanol
The flow rate of the methyl acetate :100 lbm/h
Required
the mixture flow rate in lbm/h
Solution
mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :
[tex]\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol[/tex]
mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :
[tex]\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol[/tex]
Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.
1 kg mixture = 0.85 .methyl acetate
So flow rate for mixture :
[tex]\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h[/tex]
which of the following elements has properties different than the rest?
Ac
Co
Cu
Sc
Answer:
Ac
Explanation:
Answer:
The answer is a
Explanation:
Ac
Identify the species that is oxidized and the species that is reduced in this reaction. Also, identify the oxidizing agent and the reducing agent.
Answer:
Given the equation of the reaction below:
3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)
The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.
Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.
Note: the question is incomplete. a related question is given as follows; Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfer reaction. 3Cl2 + 2Al → 6Cl - + 2Al3+ species oxidized:
Explanation:
An oxidation is a process in which there is a loss of electrons whereas reduction is a process involving the gain of electrons. A redox reaction is a reaction in which oxidation and reduction processes occur concurrently and to the same extent.
In a redox reaction reaction, the substance which is oxidized serves as the reducing agent by donating electrons to the substance which is reduced. On the other hand, the substance which is reduced serves as the oxidizing agent by accepting the electrons donated by the substance which is oxidized. In oxidation, the oxidation number of the substance oxidized increases, whereas in reduction, the oxidation number of the substance decreases.
For example, given the equation of the reaction below:
3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)
The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.
Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.
Why do you think plant cells need a cell wall as well as a cell membrane?
Answer:
to protect it from harm
Explanation:
a 22.44g sample of iron absorbs 180.8 J of heat, upon which the temperature of the sample increases from 21.1C to 39.0/ what is the specific heat of iron
Answer:
The specific heat of iron is 0.45 J/g.°C
Explanation:
The amount of heat absorbed by the metal is given by:
heat = m x Sh x ΔT
From the data, we have:
heat = 180.8 J
mass = m = 22.44 g
ΔT = Final temperature - Initial temperature = 39.0°C - 21.1 °C = 17.9°C
Thus, we calculate the specific heat of iron (Sh) as follows:
Sh = heat/(m x ΔT) = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C
based on slater's rule, what is the shielding constant experienced by a valance d- electron in a copper atom
Answer:
The general principle behind Slater's Rule is that the actual charge felt by an electron is equal to what you'd expect the charge to be from a certain number of protons, but minus a certain amount of charge from other electrons. Slater's rules allow you to estimate the effective nuclear charge Zeff from the real number of protons in the nucleus and the effective shielding of electrons in each orbital "shell" (e.g., to compare the effective nuclear charge and shielding 3d and 4s in transition metals). Slater's rules are fairly simple and produce fairly accurate predictions of things like the electron configurations and ionization energies.
Explanation:
The shielding constant of a d electron in copper is 22.15.
From Slaters's rule;
Zeff = Z - S
Where;
Z = Nuclear charge
S = Shielding constant
Now we are required to find the shielding constant for copper d - electrons;
The shielding contributed by the d electrons = (9 × 0.35) = 3.15
The shielding contributed by other electrons = (19 × 1.00) = 19
Total shielding constant = 3.15 + 19 = 22.15
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Which of the following is considered a compound?
Ag, silver
H2, hydrogen gas
CO2, carbon dioxide gas