A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 41.5-gram mass is attached at the 28.5-cm mark, the fulcrum must be moved to the 39.2-cm mark for balance. What is the mass of the meter stick

Answers

Answer 1

Answer:

The value is  [tex]M = 42.3 \ kg[/tex]

Explanation:

From the question we are told that

    The first  position of the fulcrum  is  x = 49.7 cm

    The mass  attached is [tex]m = 41.5 \ g[/tex]

    The position of the attachment is  [tex]x_1 = 28.5 \ cm[/tex]  

    The second position of the fulcrum is  [tex]x_2 = 39.2 \ cm[/tex]

Generally the sum of clockwise torque =  sum of anti - clockwise torque

So  

       [tex]CWT = m (x_2 - x_1)[/tex]

Here CWT  stands for clockwise torque

       [tex]ACWT = M ( x - x_2)[/tex]

So

      [tex]m (x_2 - x_1) = M ( x - x_2)[/tex]

=>   [tex]41.5 (39.2 - 28.5 ) = M ( 49.7 -39.2 )[/tex]

=>    [tex]M = 42.3 \ kg[/tex]


Related Questions

An airplane cruising at a constant velocity and altitude. Which of the following diagrams best represents the four forces of the airplane?

Answers

Answer:

You need to put the diagrams. repost and include the diagrams

A block and tackle consisting of 5 pulleys is used to raised a load of 400N through a height of 10m.If the work done against friction is 100j.
Calculate;
1)The work done by the effort
2)The efficiency of the system
3)The effort applied​

Answers

Answer:

1) 4000Joules

2) 25%

3) 320N

Explanation:

A block and tackle consisting of 5 pulleys is used to raised a load of 400N through a height of 10m.If the work done against friction is 100j.

Calculate;

1)The work done by the effort

2)The efficiency of the system

3)The effort applied

1) Workdone by the effort is the work input = Load * distance moved by the Load

Workdone by the effort = 400 * 10

Workdone by the effort = 4000Joules

2) Efficiency = Work output/Work input * 100

Work output = work done against friction = 100 Joules

Efficiency = 100/4000 * 100

Efficiency = 10000/4000

Efficiency  = 25%

Hence the Efficiency of the system is 25%

3) Using the efficiency formula:

efficiency = MA/VR * 100

Velocity ratio = 5

MA = Load/Effort

efficiency = (L/E)/5 * 100

25 = 400/E/5 * 100

25/100 = 400/5E

0.25 = 400/5E

0.25 * 5E = 400

1.25E = 400

E = 400/1.25

E = 320N

hence the effort applies is 320N

Solid solutions containing two or more metal are commonly called alloys. True or false

Answers

Answer:

True

Explanation:

An alloy is a combination of metals or metals combined with one or more other elements. For example, combining the metallic elements gold and copper produces red gold, gold and silver becomes white gold, and silver combined with copper produces sterling silver.

Answer:

this is true

Explanation:

yes yes true

A race car makes one lap around a track with a radius of 41 meters in 8 seconds. What is the velocity?

Answers

Answer:

31.21 m/s

Explanation:

radius=41m

time = 8 sec

circumference=2πr

from formula

circumference=2×22/7×41

=257.71m

now

velocity=total distance( circumference)/total time

=257.71/8

= 32.21m/s

The velocity of race car makes one lap around a track with a radius of 41 meters in 8 seconds is 32.19 m/s

What is velocity ?

Velocity is "rate of change of displacement with respect to time".

i.e. v= dx/dt

it is also defined as displacement over time. i.e. v=Displacement/Time.

Velocity shows how much distance can be covered in unit time. It's SI unit is m/s. It is vector quantity ( having both direction as well as momentum). where displacement is distance from mean position.

Given,

Radius of the track r= 41m

time taken by car to complete one lap T = 8s

velocity v = ?

we know that ω = 2π÷T

ω = 2×3.14 ÷ 8

ω = 0.785 rad/s

v=rω

v= 41×0.785

v= 32.185 ≅32.19 m/s

Hence velocity of the car is 32.19 m/s

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A car weighing 19600N is moving with a speed of 30 m/sec on a level road. If it is brought to rest in a distance of 100 m. Find the average distance friction force acting on it

Answers

Answer:

F = -8820 N

Explanation:

Given that,

The weight of a car, W = 19600 N

Initial speed of the car, u = 30 m/s

It is brought to rest, final velocity, v = 0

Distance, d = 100 m

We need to find the average friction force acting on it.

Firstly we find the acceleration of the car using third equation of motion. Let it is a.

[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0)^2-(30)^2}{2\times 100}\\\\=-4.5\ m/s^2[/tex]

Average frictional force,

F = ma

m is mass, [tex]m=\dfrac{W}{g}=\dfrac{19600\ N}{10\ m/s^2}=1960\ kg[/tex]

F = 1960 kg × -4.5 m/s²

= -8820 N

So, the average friction force acting on it is 8820 N.

MUSIC

Progressions can start on any number of chords but usually end on the I.
true or false

Answers

Answer:

true

Explanation:

Answer:

false

Explanation:


a 5.00 kg plane is speeding up on the ground with an applied force of 706 N. If the net force is 450 N, what would be the force due to air resistance

Answers

Answer:

The force due to air resistance is 256 N.

Explanation:

Given;

mass of the plane, m = 5 kg

applied force on the plane, Fa = 706 N

the net force on the plane, ∑F= 450 N

Let the force due to air resistance = Fr

The net force on the plane is given as;

Net force = applied force - force due to air resistance

∑F = Fa - Fr

Fr = Fa - ∑F

Fr = 706 - 450

Fr = 256 N.

Therefore, the force due to air resistance is 256 N.

will you help me please

Answers

Answer: True

Explanation: It's true because the definition of a Command economy states that it's an economy in which production, investment, prices, and incomes are determined CENTERALLY by a GOVERNMENT.

at constant pressure by what fraction of its volume will aquantity of gas change if the temperature changes from -173degree C to 27degree C

Answers

Answer:

The volume of the gas becomes three times the initial volume.

Explanation:

Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.

So, the initial temperature, [tex]T_1[/tex] = -173 degree C = -173+273 = 100 K.

The final temperature, [tex]T_2[/tex]= 27 degree C = 27+273=300 K.

As the pressure is constant, so [tex]P_1=P_2[/tex].

Let V_1 and V_2 be the initial and final volume respectively.

Assuming that the given gas is ideal gas.

So, applying the ideal gas equation

PV=nRT

where n is the number of moles of the gas and R is the universal gas constant.

For the initial state, [tex]P_1V_1=n_1RT_1\cdots(i)[/tex]

and for the final state, [tex]P_2V_2=n_2RT_2 \cdots(ii)[/tex]

Dividing the equation (i) by (ii), we have

[tex]\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}[/tex]

As the mass of the gas is not changing, so [tex]n_1=n_2[/tex], then

[tex]\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}[/tex]

As the pressure is not changing, so [tex]P_1=P_2[/tex], then

[tex]\frac {V_1}{V_2}=\frac {100}{300}[/tex]

[tex]V_2=3V_1[/tex]

So, the volume of the gas becomes three times the initial volume.

pls help me with this

Answers

Answer:

A screw

Explanation:

Answer:
Screw
Explanation :
I hope it helps !

A sign is attached to the side of a building as seen below. The sign is attached to a steel rod. A wire connects to the end of the rod for support. The mass of the sign is 50 kg. Determine the supporting force exerted by the cable

Answers

Answer:

500N

Explanation:

50kgx10N/kg

= 500N

PLZ HELP MEEEEEEE,;-;

Answers

Answer:

thxs for the points

Explanation:

because just started

help plz The sum of all chemical reactions that take place within an organism is known as ______________. *

Answers

Answer:

Metabolism

Explanation:

metabolism is the sum of all chemical reactions that take place within an organism

Answer:

Metabolism

Explanation:

The law of __________________________ says that people think of similar objects as belonging together.

Answers

Answer:

Explanation:is the law means that the police are the law

I think the answer would be the principle of similarity.. It states that when things appear to be similar to each other that people tend to group the objects together. Also they tend to think of them as the same function. Not totally sure, but I hope this helped.

1. A book is at rest on a tabletop. Diagram the forces acting on the book. ​

Answers

When you place a book on a table, the book exerts a downward force on the table and the table exerts an upward force on the book.

The free-body diagram of the forces acting on a book resting on a table is shown in the figure.

When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.

So, the forces acting on a book resting on a tabletop are:

1. Weight of the book, W(downward)

2. Normal force (N) perpendicular to the surface in contact.

Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.

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a beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3

Answers

Answer:2.47

Explanation:

So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!

what is the function of brushes in D.C motor​

Answers

Answer:

to transfer the voltage

Explanation:

The brushes make physical contact with the commutator. When a DC voltage is applied to the brushes, that voltage is transferred into the commutator which, in turn, powers the windings. This electrical input generates a magnetic field around the armature.

Why do you think it is colder during the winter than the summer?

Answers

Answer:

As the earth travels around the sun during the year it maintains this tilt. Because of this tilt, in the summer we (north of the equator) are slanted more directly towards the sun so it's hotter. In the winter, we're slanted away so the sun's rays are less direct, making it colder.

1. A race starts out at rest and accelerates to 30m/s over a period of 10s. What is the acceleration of the car?
O 3.0 m/s
O 3.0 m.s2
O 2.0 m/s2
O 5.0 m/s2

Answers

Answer:3.0m/s

Explanation:

I need help with the questions when it says what is the topic and rest

Answers

It should be a and f would I you like me to explain

define light?it's types​

Answers

Answer:

Light or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that can be perceived by the human eye. Visible light is usually defined as having wavelengths in the range of 400–700 nm, or 4.00 × 10⁻⁷ to 7.00 × 10⁻⁷ m, between the infrared and the ultraviolet.

Explanation:

This is one type of light.

How much energy is required to raise the temperature of 5.0 g of silver from 298 K to
334 K?

Answers

Answer:

43.2J

Explanation:

Q = m × c × ∆T

Where:

Q = amount of energy

m = mass (grams)

c = specific heat capacity

∆T = change in temperature

Mass = 5.0g

Specific heat capacity of Silver (Ag) = 0.240 J/g°C

We need to convert the temperature from Kelvin (K) to °C

Initial temperature = 298 - 273 = 25°C

Final temperature = 334 - 273 = 61°C

Q = 5 × 0.240 × (61°C - 25°C)

Q = 1.2 × 36

Q = 43.2J

A ball of radius R and mass m is magically put inside a thin shell of the same mass and radius 2R. The system is at rest on a horizontal frictionless surface initially. When the ball is, again magically, released inside the shell, it sloshes around in the shell and eventually stops at the bottom of the shell. How far does the shell move from its initial contact point with the surface

Answers

Answer:

[tex]x =\frac{-R}{2}[/tex]

Explanation:

From the question we are told that mass

Thin layer radius [tex]= 2R[/tex]

Generally the expression for ths solution is given as

Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2

the center of mass will not move at initial state  

Considering the center of mass of both bodies

[tex]xcm=\frac{m*x+m*x)}{2m} =x[/tex]

[tex]x =\frac{-R}{2}[/tex]

Therefore the enclosing layer moves [tex]x =\frac{-R}{2}[/tex]                          

The shell move from its initial contact point with the surface is,

[tex]x =\dfrac{-R}{2}[/tex]

Given-

Radius of the ball is [tex]R[/tex].

the mass of the ball is [tex]m[/tex].

The mass of the thin shell is [tex]m[/tex].

The radius of the thin shell is [tex]2 R[/tex].

For the two bodies with mass [tex]m[/tex], the center of mass can be given as,

[tex]x_{cm}=\dfrac{m_{1} x_{1}+m_{2} x_{2} }{m_{1} +m_{2}}[/tex]

In the given question, the mass of both the bodies are equal and the given distance of center of mass for both bodies are also equal. Therefore,

[tex]x_{cm}=\dfrac{m x_+mx }{m +m}[/tex]

[tex]x_{cm}=\dfrac{2mx }{2m}[/tex]

[tex]x_{cm} =x[/tex]

Distance for center of mass can also be given as,

[tex]x_{cm} =m\times o[/tex]

[tex]x_{cm} =m\times \dfrac{-R}{2m}[/tex]

[tex]x_{cm} =\dfrac{-R}{2}[/tex]

Comparing both the values of the distance of center of mass we get,

[tex]x =\dfrac{-R}{2}[/tex]

Hence, The shell move from its initial contact point with the surface is,

[tex]x =\dfrac{-R}{2}[/tex]

For more about the center of mass follow the link below,

https://brainly.com/question/8662931

the center of mass of a donut is located ?
a. in the hole
b. in material making up the donut
c. near the center of gravity
d. over a point of support ​

Answers

Answer:

A

Explanation:

where the hole is because it's a rigid object with uniform density.

Calculate the aceleration of a vehicle of 100 kg when applicates 400 N

Answers

Answer:

For this we applicate 2nd law of Newton:

F = ma

Replacing:

400 N = 100 kg * a

a = 400 N / 100 kg

a = 4 m/s²

The aceleration is 4 meters per second squared.

Answer:

....................

Explanation:

---------------------

a small balloon containing baking soda has a mass of 4 grams. A student adds 10 ml. of vinegar
to a 100 gram glass bottle. The student stretches the opening of the balloon over the mouth of
the bottle, mixing the baking soda and vinegar inside the bottle. Once the balloon is inflated, the
student finds the mass of the balloon, bottle, and their contents to be 116 grams. What was the
mass of the vinegar originally in the bottle
F.10g G.12g J.16g

Answers

Answer:

10 grams

Explanation:

I took a test with this question earlier.

Calculate the displacement of the following components:
1 units North
2 units South
2 units North
2 units North
3 unit South

Answers

Answer:

zero displacement

its returnin to the starting point.

5 north 5 south

A force of 900N acts on
a stationary body
for 40sec and the body acquires the velocity of360 m/s calculate mass a body.

Answers

Answer:

Explanation:

It is still using F = m*a -- just in a disguised form.

Givens

F = 900 N

vf = 360 m/s

vi = 0

t = 40 second

Formulas

a = (vf - vi)//t

F = m * a

Solution

a = (360 - 0)/ 40

a = 9

F = m * a

900 = m * 9

m = 900/9

m - 100 kg.          Doesn't seem high enough.

Answer:

a= V- u/t

a= 360 - 0 /40 = 9 m/sec2

F = MA

900 = M * 9

M = 900/9

M= 100 kg

A ball has a mass of 0.1 kg and an initial velocity of 20 m/s. The ball is given an acceleration of 30 m/s2 for 5 s. What is the net force on the ball during acceleration?

Answers

Answer:

acceleration = v-u /t

30- 20/5

= 10/5 = 2m/sec²

Force = mass * acceleration

Force = 0.1 * 2

Force = 0.2 Newton

Answer:

I hope the above pic will help you

I will always help you understanding your assingments

have a great day #Captainpower:)

what is the uses of space weather data?​

Answers

Answer:

Space Weather Data

They are used to produce forecasts, such as the monthly sunspot number forecast. Most notably, sunspot numbers represent one of the longest continuous climate records available. The data give scientists the means to make many forecasts and issue space weather advisories and alerts.

Explanation:

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