A man is picked up by a tornado and dropped a quarter mile away from his home. Even though authorities estimate that his body was dropped at 30 mph he suffered no major injuries. What factors contributed to the fact that his body was able to withstand this drop?

Answer:

false....

Explanation:

brainliest

Answer:

Workdone = 147Nm

Explanation:

Given the following data;

Mass = 5kg

Height = 3m

We know that acceleration due to gravity is 9.8m/s²

First of all, we would find the force applied;

[tex] Force = mass * acceleration [/tex]

Force = 5*9.8

Force = 49N

Now, to find the workdone;

[tex] Workdone = force * distance [/tex]

Substituting into the equation, we have;

Workdone = 49 * 3

Workdone = 147Nm

Question:

A small rocket is launched vertically upward from the edge of a cliff 80 ft off the ground at a speed of 69 ft/s. Its height (in feet) above the ground is given by  [tex]h(t) = - 25t^2 + 200t + 400[/tex] where t represents time measured in seconds.

Assuming the rocket is launched at t=0, what is an appropriate domain for h?

Answer:

[tex]0 \le t \le 9.66[/tex]

Explanation:

Given

[tex]h(t) = - 25t^2 + 200t + 400[/tex]

Required

Determine the domain of h

The initial value of t is 0.

i.e.

[tex]t = 0[/tex] --- This is given in the question

To determine the final value, we simply solve for t in [tex]h(t) = - 25t^2 + 200t + 400[/tex]

Rewrite the expression:

[tex]- 25t^2 + 200t + 400=0[/tex]

Divide through by -25

[tex]\frac{-25t^2}{-25} + \frac{200t}{-25} + \frac{400}{25}=\frac{0}{-25}[/tex]

[tex]t^2 - 8t - 16 = 0[/tex]

Using quadratic formula:

[tex]t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

Where

[tex]a= 1[/tex]    [tex]b = -8[/tex]  and [tex]c = -16[/tex]

The expression becomes:

[tex]t = \frac{-(-8)\±\sqrt{(-8)^2 - 4*1*(-16)}}{2*1}[/tex]

[tex]t = \frac{8\±\sqrt{64+ 64}}{2}[/tex]

[tex]t = \frac{8\±\sqrt{128}}{2}[/tex]

[tex]\sqrt{128} = 11.31[/tex]

So, we have:

[tex]t = \frac{8\±11.31}{2}[/tex]

Split

[tex]t = \frac{8+11.31}{2}\ or\ t = \frac{8-11.31}{2}[/tex]

[tex]t = \frac{19.31}{2}\ or\ t = \frac{-3.31}{2}[/tex]

[tex]t = 9.66\ or\ t = -1.66[/tex]

But time can't be negative.

So:

[tex]t = 9.66[/tex]

Hence, the domain is:

[tex]0 \le t \le 9.66[/tex]

Given that,

Distance travelled, d = 3.06 m

Final velocity, v = 0.18 m/s

Average velocity of the object, V = 0.34 m/s

To find,

The acceleration of the object.

Solution,

Let t is the time in which it covers distance d. Average velocity is given by distance covered divided by time.

[tex]V=\dfrac{d}{t}\\\\t=\dfrac{d}{V}\\\\t=\dfrac{3.06}{0.34}\\\\t=9\ s[/tex]

Let a is the acceleration of the object. Using equation of motion to find it :

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0.18-0}{9}\\\\a=0.02\ m/s^2[/tex]

So, the acceleration of the object is 0.02 m/s².

Answer:

46 degrees

Explanation:

90+44+x=180

44+x=90

x=46

Answer:well isn't it 90 like it said on the image?

Explanation?????

Answer:

Force is measured using either the English System of Measurements or the International System of Units A force can cause an object with mass to change its velocity It is measured in the SI unit of newtons and represented by the symbol F.

Explanation:

–0.2 m/s2 I did it on edge 2020

Answer:

the answer is C

Explanation:

i got it wrong the first time because the answer above says -0.2 but its actually 0.2

i hope this helps

Answer:

40 000 units of momentum

Explanation:

Assuming that the mass is doubled and the velocity stays constant the new momentum will be doubled the original momentum.