The difference between the fluid pressure at location 2 and the fluid pressure at location 1 is 119 kPa.
What is the equation of continuity?The mass balance of a fluid moving through a stationary volume element is all that the equation of continuity is about. It says that the rate of mass inflow less outflow equals the rate of mass buildup in this volume element.
According to equation of continuity:
[tex]A_{1} v_{1} =A_{2} v_{2} \\[/tex]
A₁ = Region 1 cross-sectional area
v₁ = flow velocity of region 1
A₂ = Region 2 cross-sectional area
v₂ = flow velocity of region 2
Here, [tex]A_{1} =\frac{\pi d_{1}^{2} }{4}[/tex] , [tex]A_{2} =\frac{\pi d_{2}^{2} }{4}[/tex]
Now, putting the values in the above equation we get,
[tex]v_{2} =\frac{A_{1} }{A_{2} } v_{1} \\[/tex]
[tex]=\frac{\frac{\pi d_{1}^{2} }{4}}{\frac{\pi d_{2}^{2} }{4}} v_{1}[/tex]
[tex]v_{2} =\frac{d_{1}^{2} }{d_{2}^{2} } v_{1}[/tex]
Using Bernoulli's equation, we get,
[tex]P_{2} + \rho gz_{2} +\frac{\rho v_{2 }^{2} }{2}= P_{1} + \rho gz_{1} +\frac{\rho v_{1 }^{2} }{2}[/tex]
The difference between the location 2 fluid pressure and the location 1 fluid pressure is :
[tex]P_{2}-P_{1} =\rho g(z_{1}-z_{2} )+\frac{\rho (v_{1}^{2}-v_{2}^{2}) }{2} =\rho g(z_{1}-z_{2} )+\frac{1}{2}\rho v_{1} ^{2} (1-(\frac{d_{1} }{d_{2} } )^{4} )[/tex]
[tex]P_{2}-P_{1} = 1330*9.81*9.15+\frac{1}{2} *1330*9.85^{2} (1-(\frac{10.1}{17.5} )^{2} )[/tex]
[tex]P_{2}-P_{1} = 1.19*10^5} Pa\\P_{2}-P_{1} = 119 kPa[/tex]
Hence, the difference between the fluid pressure at location 2 and the fluid pressure at location 1 is 119 kPa.
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how was the third law of motion discovered
Answer:
how was the third law of motion discovered
Explanation:
Isaac Newton discovered this law by exerting pressure on one object against another. The first object's force is felt and equally replicated by the second body. Thus, Isaac Newton proved that it's impossible to exert pressure on a single object without a similar reaction from the second object.
two 1-kg stationary cue balls are struck by cue sticks. the cues exert the forces shown. which ball has the greater final speed?
Both balls have the same final speed.
What is speed?The distance traveled by an object per unit time is defined as its speed. Speed is a scalar quantity because it has no direction and only magnitude. The SI unit is meter/second.Based on Newton's second law of motion,
Second Law of Motion of Newton (Force) The acceleration of an object is determined by its mass and the amount of force applied.force = momentum/time change
Momentum change = force time
(force time)/mass = change in speed
When two 1.0 kg stationary cue balls are struck by cue sticks with equal force and time.
Therefore both stationary cube balls will have the same final speed.
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a 4 lb b ball is traveling around a circle of radius r1 = 3 feet quickly v1 = 6 ft/s. if the attached rope is pulled down the hole with constant speed vr = 2 ft/s
Answer:
ur gay
Explanation:
i said so
with what tension must a rope with length 2.10 mm and mass 0.120 kgkg be stretched for transverse waves of frequency 45.0 hzhz to have a wavelength of 0.790 mm ?
The tension of a rope of length 2.10 mm and mass 0.120 kg which is stretched for transverse waves of frequency 45.0 hzhz to have a wavelength of 0.790 mm is 51.4 N
What is frequency ?
The quantity of waves that pass a set location in a predetermined period of time is known as frequency.
From the given information -
length =2.10 mm
mass = 0.120 kg
frequency = 45.0 Hz
wavelength = 0.790 mm
V = sqrt (T/u)
V = 40 *0.79 = 31.6 m/s
T/u = 900
Tension = 900* 0.12/2.1
Tension = 51.4 N
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what is the frequency of the second overtone if the fundamental frequency is 308 hz
A. 154hz
B. 924hz
C. 308hz
D 616hz
The frequency of the second overtone if the fundamental frequency is 308 Hz is equal to 1540 Hz.
What is overtone?An overtone can be described as any resonant frequency above the fundamental frequency of a sound. Overtones can be defined as all pitches higher than the lowest pitch within an individual sound. While the fundamental can be described as usually heard most prominently, overtones are present in any pitch except a true sine wave.
The lowest normal frequency is called the fundamental frequency, while the higher frequencies are known as overtones.
Given, the fundamental frequency, f₀ = 30 8 Hz
The relationship between the fundamental frequency and the second overtone is given by
f₂ = 5 f₀
f₂ = 5 × 308 = 1540 Hz
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A hockey puck has a coefficient of kinetic friction of = .20. If the puck feels a normal force of 5 N, what is the frictional force that acts on the puck?
Answer: 5 N
Explanation:
Friction is a force that prevents two solid objects from rolling or sliding over one another. Although frictional forces, like the traction required to walk without slipping, may be advantageous, they also pose a significant amount of resistance to motion.
The given parameters;
coefficient of kinetic friction, μk = 0.1normal force of the puck, Fₙ = 5 NBy multiplying the normal force and the coefficient of kinetic friction, the frictional force acting on the puck is calculated.
The frictional force that acts on the puck is calculated as follows;
F= u*f
Substitute the given parameters in the above equation and solve the frictional force.
F=0.2*5
F= 1 N
Thus, the frictional force that acts on the puck is 1 N.
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a plane flying with a constant speed of 300 km!h passes over a ground radar station at an altitude of 1 km and climbs at an angle of 30 . at what rate is the distance from the plane to the radar station increasing a minute later?
The rate of the distance from planar to radar is 150m.
A 300 mph aircraft will have traveled 300 miles in 30 minutes. The distance between the plane and the interceptor, which takes off a half-hour later, is 500 miles if we deduct the 300 miles from the 800 miles. The combined speeds of the two aircraft are what we need to look at next. 600 mph multiplied by 400 mph equals 1000 mph. Flying the remaining 500 miles will only take 30 minutes at those combined speeds.[tex]Distance= S\alpha sin\beta[/tex]=300 sin30
= 300 x 0.5
=150m
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who is responsible for testing electrical conductor insulation and keeping the test records?
The resistance to insulation is measured using an IR tester. This is a portable device that resembles an ohmmeter in many ways and has a built-in generator for creating a high DC voltage.
How do you test a conductor for insulation?An IR tester is used to assess insulation resistance. This is a portable device that resembles an ohmmeter in many ways and has a built-in generator for creating a high DC voltage. A current moves across the surface of the insulation as a result of the voltage, which is normally at least 500V.
Insulation testers evaluate the resistance in wires and motor windings using a high voltage, low current DC charge to find current leakage and defective or damaged insulation, which can result in arc faults, blown circuits, and the possibility of electrical shock or fire.
To help prevent risks like electric shock and short circuits created when the insulation in electrical devices, parts, and equipment is compromised, portable insulation resistance testers and megohmmeters are available.
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f. What happens if the Physics student is standing on ice?
g. What is the force between the student and the ground called?
Answer:
Explanation:
f. Student slips on ice
g. The force is called sliding friction force
an object is to the left of a thin lens. the lens forms an image on a screen that is 2.70 mm to the right of the object. the height of the image is 2.60 times the height of the object. part a is the image upright or inverted? is the image upright or inverted? the image is inverte
The image is inverted and real because the question tells us that the image was formed on a screen.
How to know if an image is real and inverted?When the rays come together, a true image is created. A virtual image is always formed above the principal axis, therefore it is always upright, as opposed to a real image, which is always formed below the principal axis and is always inverted.
An image that can be projected onto a screen is a real image. Behind the lens, a virtual image appears to emerge.
The image is inverted, magnified, and real for an object that is between one and two focal lengths from the lens.
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the transfer of electrical energy from one circuit to another without the aid of a conductor is called:
Answer:
Inductance or mutual inductance
Energy produced in one circuit induces energy in another
(such as high voltage produced by a coil from input by say, a 12V battery)
uniform circular motion what is the direction of the force that acts on the clothes in the spin cycle of a washing machine? what exerts the force?
The direction of the force that acts on clothes in the spin cycle of a washing machine is inwards. if the force would have been acting outwards then the clothes would have flown off, but this is not the case.
What is uniform circular motion?
when an object moves in a circle at a consistent speed in a motion, it is said to be in a uniform circular motion.
What is an example of uniform circular motion?
A satellite made by man is an example of uniform circular motion. Apart from that another example of uniform circular motion is a rotating ceiling fan, also a wheel of a moving car is an example of uniform circular motion.
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deep in the forest a 0.017kg leaf falls from a tree and drops straight to the ground. if its initial height was 5.3 m and its speed on landing was 1.3 m/s, how much nonconservative work was done on the leaf? what force does this nonconservative work?
So work done by non-conservative forces = -0.868 joules.
As per the data given in the question,
It is given that:
Weight of leaf = 0.017 Kg = 17 grams.
Initial height was 5.3 m
Speed on landing was 1.3 m/s,
So, to find the total non conservative work we will apply the work-energy theorem
The work-energy theorem states that the net work done on a system is equal to the change in kinetic energy, or that the work done by the sum of all forces acting on a particle equals the change in kinetic energy of the particle.
So, the value of energy lost [tex]=-\left(mgh-\frac{1}{2} m v^2\right)[/tex]
[tex]=-\left(17 \times 10^{-3} \times 9.8 \times 5.3-\frac{1}{2} \times 17 \times 10^{-3} \times(1-3)^2\right) \\& =-\left(882.98 \times 10^{-3}-14.365 \times 10^{-3}\right) \\& =-0.868 \mathrm{~J}[/tex]
Forces = -0.868 joules.
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The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.
The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.terminal velocity is 0.8 N .
Simply put, what is terminal velocity?As a result, a object achieves terminal velocity when its acceleration (or deceleration) are zero and its speed is no longer increasing or decreasing.
What is the Earth's terminal velocity?around 53 m/s Unaffected by its mass, an item in free fall inside a vacuum would accelerate at a velocity of about 9.8 m/s2 close to the Earth's surface.When an object is dropped, air resistance causes it to finally achieve its terminal velocity, which for a human skydiver is about 53 m/s (190 km/h or 118 mph).
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for a current ratio with a value greater than or equal to 1.0, the current ratio will increase if:
If a company's current ratio is larger than 1, it implies that its current liabilities exceed its current assets; conversely, if it is or less 1, it means that its current assets exceed its current liabilities.
What does an current ratio less than 1 indicate?If the ratio is less than 1, it means that the firm has more obligations due in the next year or less than it does in cash or other brief assets that are anticipated to be converted into money in the next year or less.
What ratio results from a reduction in current obligations and assets?Now The ratio would rise to 2.25:1 if current obligations and assets were both decreased by $1,000.
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the velocity of an object is given v(t), and the acceleration is given by a(t). what is the relationship between the total
The rate at which velocity changes is called acceleration. (Attensity exists when velocity varies.) If a moving object changes speed.
Why does time accelerate the rate at which velocity changes?
A motion's acceleration is the rate at which it changes from one velocity to another. A velocity's rate of change with respect to time is referred to as its acceleration. The amount and direction of acceleration are both properties of a vector quantity.
A change in velocity is known as what?
A velocity change's acceleration is measured. Acceleration is the measure of how quickly a velocity changes with time. The acceleration measure used in SI is M/s2.
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a noisy machine in a factory produces a decibel rating of 77 db. how many identical machines could you add to the factory without exceeding the 85 db limit?
A noisy machine in a factory produces a decibel rating of 77 dB. The Number of 10 machines add to the factory without exceeding the 85 db limit.
sound level in decibels is
β dB = 10 log ( I / I₀ )
where I is the intensity of sound
I₀ is the relative intensity
80 = 10 log ( I ÷ 10⁻¹² )
8 = log ( I ÷ 10⁻¹² )
10⁸ = I ÷ 10⁻¹²
I = 10⁸ × 10⁻¹² = 10⁻⁴ W /m2
if the sound level is 90 dB, the number of identical machines is n.
90 = 10 log ( n × I / I₀)
90 = 10 log ( n × 10⁻⁴ / 10⁻¹²)
9 = log ( n × 10⁸)
10⁹ = n × 10⁸
n = 10
Therefore, a number of 10 machines add to the factory without exceeding the 85 db limit.
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A laser used to weld detached retinas emits light with a wavelength of 658 nm in pulses that are 25.0 ms in duration. The average power expended during each pulse is 0.600 W.1) How much energy is in each pulse, in joules?2)How much energy is in each pulse, in electron volts?3)What is the energy of one photon in joules?4)What is the energy of one photon in electron volts?5)How many photons are in each pulse?
1) The energy in each pulse is 15 × [tex]10^{-3}[/tex] J 2) The energy in each pulse is E is 9.375 × [tex]10^{16}[/tex] eV 3) The energy of each photon in electron volt is 3.303 ×[tex]10^{-19}[/tex] J.
Wave length of the light λ = 658 nm = 658 × [tex]10^{-9}[/tex]
Time t = 25 ms = 25 × [tex]10^{-3}[/tex]
The energy in each pulse is E = power × time = (0.600) × ( 25 × [tex]10^{-3}[/tex])
E = 15 × [tex]10^{-3}[/tex] J
The energy in each pulse is E = 15 × [tex]10^{-3}[/tex] J = 9.375 × [tex]10^{16}[/tex] eV
The energy of each photon in electron volt is,
E = hc/V = (6.625 × [tex]10^{-34}[/tex]) ( 3 ×[tex]10^{8}[/tex]) / 658 × [tex]10^{-9}[/tex] = 3.303 ×[tex]10^{-19}[/tex] J
The energy of the photon in electron volts is
E = 3.303 ×[tex]10^{-19}[/tex] J = 3.303 ×[tex]10^{-19}[/tex] J(1/1.6 × [tex]10^{-19}[/tex] = 2.06 eV
Energy is characterized as having the "ability to accomplish work, which is the capacity to apply a force sufficient to move an object." Despite this unclear definition, the concept is actually quite straightforward: energy is just the force that moves objects. Potential and kinetic energy are the two different categories. The best approach to understand them is to think of potential energy as occurring before an action and kinetic energy as occurring during an action. Consider raising your physics textbook in the air. Simply due of its elevated elevation, it could fall. If you drop the textbook, the potential energy is converted into kinetic energy, which is the energy that drives the movement.
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. an object is launched straight up into the air from the ground with an initial vertical velocity of 30 m/s. the object rises to a highest point approximately 45 m above the ground in 3 seconds; it then falls back to the ground in 3 more seconds, impacting with a speed of 30 m/s. (a) the average speed of the object during the 6-second interval is closest to (a) 0 m/s. (b) 5 m/s. (c) 15 m/s. (d) 30 m/s. (b) the magnitude of the average velocity during the 6-second interval is closest to (a) 0 m/s. (b) 5 m/s. (c) 15 m/s. (d) 30 m/s
In the first case, the average speed of the object is 15 m/s.
Hence, Option C is correct.
In the second case the average velocity is 0 m/s.
Hence, Option A is correct.
Explain
a) avg. speed=total distance travelled/total time taken.
which is (45+45)/(3+3)=15m/sec.
b)avg. velocity= total displacement/total time taken.
which is (45+(-45))/(3+3)=0 m/sec.
Here the -ve sign indicates the change in direction(opposite).
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the mass of earth is 5.972 * 1024 kg, and the radius of earth is 6,371 km. a 750 kg satellite orbits 35,800 km above earth in a perfectly circular orbit. if the gravitational force is acting as the centripetal force to keep the satellite in orbit, what is the tangential velocity of the satellite in its orbit?
The speed or the tangential velocity of the satellite to keep it in its orbit is 3,073.5 meters per second.
The gravitational force between two objects is given by:
F = GMm/r²
Where:
G = constant of gravity = 6.674 x 10⁻¹¹ N.m²/kg²
M, m = mass of each object
r = distance between objects
Parameters given in the problem:
M = 5.972 x 10²⁴ kg
m = 750 kg
r = 6371 + 35,800 = 42,171 km = 42,171,000 m
Hence,
F = 6.674 x 10⁻¹¹ x 5.972 x 10²⁴ x 750 / 42,171,000²
= 168.1 N
This is equal to centripetal force:
F = m . v² / r
168.1 = 750 . v² / 42,171,000
v² = 9,446,304
v = 3,073.5 m/s
Hence, the tangential velocity of the satellite to keep it in its orbit is 3,073.5 m/s
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as an ideal fluid flows vertically upward through a uniform (constant radius) pipe, what happens to the fluid speed and fluid pressure?
A pipe's pressure is essentially comprised of two pressures: a kinetic pressure that is measured in the flow's center and a static pressure that is determined precisely at the pipe wall's interior.
What means fluid pressure?the force a fluid applies to any point inside of it. The sum of the difference in height, their density, and the rate of free fall determines the difference in pressure between two levels.
Why does fluid pressure exist?Similar to the air from the inside of a tire, all liquids exert pressure. Fluid particles constantly and randomly move in all directions. The particles constantly collide with one another and anything else that crosses their path as they advance. Pressure is produced by these impacts, and it is applied uniformly in all directions.
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estimate the amount of mass that is converted to energy when a proton combines with a deuterium nucleus to form 3he.
Answer:7.99
Explanation:
beats: the little brown bat is a common bat species in north america. it emits echolocation pulses at a frequency of 40 khz, well above the range of human hearing. to allow observers to "hear" these bats, an electronic bat detector combines the bat’s sound wave at a frequency f 1 with a wave of frequency f 2 from a tunable oscillator. the resulting beat frequency is isolated, amplified, and then played through a speaker. to what frequency f 2 should the oscillator be set in order to produce an audible beat frequency of 3.0 khz? hint: there are two possible oscillator frequencies
Beyond the audible range of humans, most bat echolocation occurs. Depending on their age, people have a hearing range of 20 Hz to 15-20 kHz. 9 kHz to 200 kHz is the frequency range for bat calls.
What is Bat Echolocation?Bats are able to see just as well as humans, but they have developed an advanced echolocation technique that allows them to move around and find food in the dark. Using their mouth or nose to emit high frequency sound pulses and listening for the echoes, bats use echolocation to find prey. The bat uses this echo to assess the size, shape, and texture of objects in its environment. Bat echolocation is so advanced that these animals can find something as small as a human hair.Shouting bats and whispering bats are two general descriptions of bats based on their echolocation calls. If we could hear them, big brown bats and little brown bats would be shouting at 110 decibels, which is about as loud as a smoke alarm. Northern long-eared bats have 60 decibel whispering voices. While whisperers collect insects from tree foliage and forage in the crowded conditions of forest interiors, shouters typically hunt for food in open areas.To Learn more About bat echolocation refer to:
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what is the escape speed on a spherical asteroid whose radius is 823 km and whose gravitational acceleration at th surface is 1.38 m/s^2.
A spherical asteroid with a radius of 823 km has an escape speed of 4 103 m/s.
Explain about the gravitational acceleration?Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational force acting on it. Its symbol is "g," and its unit is m/s2. Gravitational acceleration is a vector quantity, having a magnitude and a direction.
(a) The given values are
[tex]$$r=500 \mathrm{~km}$$[/tex]
[tex]$$\Rightarrow a=3.0 \mathrm{~ms}^{-2}$$[/tex]
[tex]$$\Rightarrow v=1000 \mathrm{~ms}^{-1}$$[/tex]
[tex]$$\Rightarrow h=1000 \mathrm{~km}$$[/tex]
We know that the formula for gravitational acceleration is given as
[tex]$$a_g=\frac{G M}{r^2}$$[/tex]
And the formula for the escape velocity is given by
[tex]$$v=\sqrt{\frac{2 G M}{r}}$$[/tex]
Substituting for gravitational acceleration in the above formula we get
[tex]& \Rightarrow v=\sqrt{\frac{2 a_g r^2}{r}} \\[/tex]
[tex]& \Rightarrow v=\sqrt{2 a_g r}[/tex]
Substituting the given values for the radius and gravitational acceleration.
[tex]$$\Rightarrow v=\sqrt{2(3.0)\left(500 \times 10^3\right)}$$[/tex]
[tex]& \therefore v=1.732 \times 10^3 \mathrm{~ms}^{-1}[/tex]
The complete question is,
(a) What is the escape speed on a spherical asteroid whose radius is 5 (lind whose gravitational acceleration at the surface is 3.0 [tex]\mathrm{~ms}^{-2}$[/tex]
(b) How far from the surface will a particle go if it leaves the asteroid's surface with a radial speed of[tex]$1000 \mathrm{~ms}^{-1}$[/tex]
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comets travel around the sun in elliptical orbits with large eccentricities. if a comet has speed 2.0×104 m/s when at a distance of 2.4×1011 m from the center of the sun, what is its speed when at a distance of 5.2×1010 m . express your answer in meters per second.
Comets are small asteroid-like bodies when they are far from the Sun, traveling in highly ellipical orbits about the Sun. Comets go around the Sun in a highly elliptical orbit
How to find speed of a comet?
Speed of the comet can be determined by using conversation of energy = initial kinetic energy + initial potential energy of comet = final kinetic energy + final potential energy of comet
We know,
M = mass of sun = 1.989 x 1030 kg
m = mass of comet
vi = initial speed of comet = 20000 m/s
ri = initial distance from center of sun = 2.4 x 1011 m
vf = final speed of comet = ?
rf = final distance from center of sun = 5.2x 1010 m
Using conservation of energy
initial kinetic energy + initial potential energy of comet = final kinetic energy + final potential energy of comet
(0.5) m vi2 - GMm/ri = (0.5) m vf2 - GMm/rf
(0.5) vi2 - GM/ri = (0.5) vf2 - GM/rf
(0.5) (20000)2 - (6.67 x 10-11)(1.989 x 1030)/(2.4 x 1011) = (0.5) vf2 - (6.67 x 10-11)(1.989 x 1030)/(5.2x 1010)
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a substance absorbs wavelengths of light in the range of 550 - 750 nm. a) approximately what wavelength range in the visible region is being transmitted?
The wavelengths of visible light are really not interfere constructively affected with by reflected waves.
What does constructive interference entail?When the maximum of two waves are combined together in a way that makes the amplitude of the resulting constructive wave equal to the sum of the separate waves, this is known as constructive interference, or doppler effect is the interference.
Briefing :
The constructive interference for two waves, in same phase can be find out as,
λ = [tex]\frac{2'nd}{m}[/tex]
Here, m=1,2,3,....
The range of wavelengths of visible light given from 550 nm to 750 nm. It has to be found out that, for which visible wavelengths of light, do the reflected waves interfere constructively,
Visible wavelength of light is a range of electromagnetic spectrum, which can be visible by human eyes. This ranges from 550 nm to 700 nm (approx). In the problem given, the range of wavelengths of visible light is from 550 nm to 750 nm.
Put the value of the 2nd wavelength (750 nm) in the above formula for m equal to 1 as,
λ = [tex]\frac{750}{1}[/tex]
λ = 750nm
For m equal to 2,
λ =[tex]\frac{750}{2}[/tex]
λ = 375nm
Both the values does not fall under the range of visible light. Hence, The visible wavelengths of light do not reflected waves interfere constructively.
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what is the allowable ampacity for each of the following conductors, if all conductors are to be installed in the same raceway? (assume all conductors to be current carrying thwn copper) qty: (2)
Ampacity can be calculated by dividing the Wattage by the rated voltage.
What is the ampacity of each conductor?
The highest continuous current that a conductor may carry under normal use settings without going above its temperature rating is known as ampacity. The unit of measurement for current is one amp. To avoid the wire overheating, you must choose the proper size wire for the circuit's current (load) requirements.
Divide the Wattage by the rated voltage to get the ampacity. The predicted Amperage of the circuit is the quotient. Many times, a circuit's particular application correction factors (as mentioned above) will make ampacity necessary.
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a coin is placed on a flat, horizontal turntable which makes 3 revolutions in 3.14s. a. what is the speed of the coin when it rides without slipping at a distance of 5.0cm from the center of the turntable?
The speed of the coin when it rides without slipping at a distance of 5.0cm from the center of the turntable is 0.49 m/s.
No of revolutions made in 3.14s = 3rev
No of revolutions made in 1s = 3/3.14 = 0.96rev
Frequency = 0.96Hz
Time period T = 1/f = 1/0.96 = 1.05s
Angular velocity ω = 2π / T = 2π / 1.05 = 5.98 rad/s
Speed v = rω = 0.05 * 5.98 = 0.49m/s
The distance traveled rel.ative to the time it took to travel that distance is how fast s0mething is moving. As it just has a direction and no magnitude, speed is a scalar quantity. When an object travels an identical distance in an identical amount of time, it is said to be moving at uniform speed.
If an object travels a varied distance at regular intervals while maintaining the same speed, the speed is said to be variable.
Average speed is the average speed that is determined by the ratio of an object's total distance traveled to its total time traveled.
Instantaneous speed is the speed of an object while it is travelling at any given moment at a changeable pace.
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at what speed does a 1600 kg compact car have the same kinetic energy as a 20000 kg truck going 24 km/h ? express your answer in kilometers per hour.
A 1600 kilogram small vehicle and a 20 000 kg truck traveling at a speed of 84.74 km/h have same amounts of kinetic energy .
What causes kinetic energy to move?A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, gets done on it by exerting a net force.
Briefing :
Kinetic energy is that which is due to the movement of bodies and is calculated like this:
K = (1/2)mv² Formula (1)
Data for the truck
m = 20000 kg
v = 24 km/h
= 24 *(1000m)/ (3600s)
v = 6.66m/s
Calculation of the kinetic energy of the truck
We replace data in the formula (1)
K = (1/2)mv²
K = (1/2)(20000)(6.66)²
K = 443556J
Data for the compact car
K = 443556 J
= 443556 (N*m)
m = 1600 kg
Calculation of the speed of the compact car
We replace data in the formula (1)
K = (1/2)mv²
443556 = (1/2)( 1600)(v)²
443556 = ( 800)(v)²
v² = 443556/ (800)
[tex]v=\sqrt{\frac{443556}{800} }[/tex]
v = 23.54m/s
1 km = 1000 m
1 h = 3600 s
v =23.54*(3600/1000)km/h
v =84.74 km/h
Therefore , speed of car is is 84.74 km/h
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block a has weight of 40 lb and vlock b has weight of 8 lb.the coefficient of kinetic friction between all surfaces of contact is u_k = 0.15. Knowing theta = 20 and P = 50 lb, determine (a) the acceleration of block B, (b) the tension in the cord.
The acceleration of block B is 0.5 and tension is 42.8 lb.
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
mass = 40 lb
u_k = 0.15.
P = 50 lb
theta = 10
Length of the rope
L=s + s+ Constant + s,
differentiate with respect to time
0=2a,+a,
a = 2a, (magnitude only)
a=0.5
At equilibrium, V = 0
N =40 + 8
N = 48 lb
K=μk
f, =0.15%48 = 7.2 1b
D Alembert principle
Σ F x = ma
P-T-T-f₁ = (40+8/32.2)a
50 - 2T - 7.2 = 1.4907a
2T +1.4907a, = 42.8
2T +1.4907x0.5a, = 42.8 lb
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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