Question:
A lighthouse is located on an island 3 miles from the closest point on a straight shoreline. If the lighthouse light rotates clockwise at a constant rate of 9 revolutions per minute, how fast does the beam of light move towards the point on the shore closest to the island when it is 52 miles from that point
Answer:
The beam of light moves at [tex]16278\pi[/tex] miles/min
Step-by-step explanation:
This question is illustrated with the attached image
Taking the instructions in the question, one at a time.
A revolution of 9 per minute implies that:
[tex]\frac{d\theta}{dt} = \frac{9 * 2\pi\ rad}{1\ min}[/tex]
[tex]\frac{d\theta}{dt} = 18\pi \frac{rad}{min}[/tex]
Take tan of the angle in the attachment:
[tex]tan(\theta) =\frac{52}{3}[/tex]
Differentiate both sides with respect to time
[tex]\frac{d\ tan(\theta)}{dt} =\frac{52}{3} * \frac{dx}{dt}[/tex]
Rewrite as:
[tex]\frac{d\ tan(\theta)}{d\theta} * \frac{d\theta}{dt} =\frac{52}{3} * \frac{dx}{dt}[/tex]
In calculus:
[tex]sec^2(\theta) =\frac{d\ tan(\theta)}{d\theta}[/tex] -- Chain rule
So:
[tex]sec^2(\theta) *\frac{d\theta}{dt} =\frac{52}{3} * \frac{dx}{dt}[/tex]
In trigonometry:
[tex]sec^2(\theta) = tan^2(\theta) + 1[/tex]
So:
[tex](tan^2(\theta) + 1)\frac{d\theta}{dt} =\frac{52}{3} * \frac{dx}{dt}[/tex]
Recall that:
[tex]tan(\theta) =\frac{x}{3}[/tex]
[tex]((\frac{52}{3})^2 + 1)\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}[/tex]
[tex](\frac{52^2}{9} + 1)\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}[/tex]
[tex](\frac{2704}{9} + 1)\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}[/tex]
[tex](\frac{2704+9}{9})\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}[/tex]
[tex](\frac{2713}{9})\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}[/tex]
Recall that: [tex]\frac{d\theta}{dt} = 18\pi \frac{rad}{min}[/tex]
[tex](\frac{2713}{9}) * 18\pi =\frac{1}{3} * \frac{dx}{dt}[/tex]
[tex]2713 * 2\pi =\frac{1}{3} * \frac{dx}{dt}[/tex]
Multiply both sides by 3
[tex]3 * 2713 * 2\pi =\frac{1}{3} * \frac{dx}{dt} * 3[/tex]
[tex]3 * 2713 * 2\pi =\frac{dx}{dt}[/tex]
[tex]16278\pi =\frac{dx}{dt}[/tex]
[tex]\frac{dx}{dt} = 16278\pi[/tex] miles/min
Hence:
The beam of light moves at [tex]16278\pi[/tex] miles/min
If n = 5, which of the following is not equivalent to 24?
Answer:
there is no picture?
Step-by-step explanation:
Solve the inequality:
8+4x≥12
Select one:
x≤1
x≥5
x≥1
x≤5
Answer:
x >_ 1
Step-by-step explanation:
Solving an inequality is a lot like solving an equation. Just pretend the inequality symbol is an equal sign!
(also i wont be using the _ or equal to symbol because I'm too lazy, so you'll get >_ or <_ for those, sorry)
8 + 4x >_ 12
-8 -8
4x >_ 4
/4 /4
x >_ 1
Can anyone help me on this please
find the sum of the odd numbers between 100 and 200
Answer:
50
Step-by-step explanation:
there are 100 numbers between 100 and 200
50 that are even 50 that are odd
Answer:
137 + 63 = 200
Step-by-step explanation:
Is this question correct? I know the 96 part is but i'm not sure about part A
What is the distance between point A and point B on the coordinate plane?
HELP PLSS
Answer:
3
Step-by-step explanation:
If you count the units its three units away from each other.
(7^3)^3
Simplify.
Rewrite the expression in the form 7^n
Step-by-step explanation:
✧ [tex] \underline{ \underline{ \large{ \tt{R\: E \: M \: E \: M \: B \: E \: R}}} }: [/tex]
If [tex]( {x}^{a} )^{b} [/tex] is an algebraic term then [tex] {(x}^{a} )^{b} = {x}^{a \times b} [/tex] i.e When an algebraic term in the index form is raised to another index , the base is raised to the product of two indices.
⟶ [tex] \large{ \tt{( {7}^{3} ) ^{3} = {7}^{3 \times 3} = {7}^{9}}} [/tex]
☥ [tex] \boxed{ \boxed{ \large \tt{Our \: Final \: Answer : \underline{ \tt{ {7}^{9}}}}}} [/tex]
Hope I helped ! ♡
⋆ Have a wonderful day / night ! ♪
Let me know if you have any questions regarding my answer! ツ
[tex] \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}[/tex] !! ✎
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
what is 1 times 89what is 1 * 17
Answer:
1 times 89 = 89 lol 1 x 7= 7
Step-by-step explanation:
hope this helps lol
Simplify
(7x^2 - 11 + 16x) + (5x - 3x^2 - 7)
Answer:
4x^2 + 21x -18
Answer:
4x^2 + 21x -18Hope it helps ❤️
Sweet corn of a certain variety is known to produce individual ears of com with a mean weight of 8 ounces. A farmer is testing a new fertilizer designed to produce larger ears of com, as measured by their weight. He selects a random sample of 10 ents of com and determines their weight (in ounces). The data are as follows: 8.25 7359,05 8.00 8.25 8.75 9.00 7.60 8.45 8.55
Do the data provide convincing evidence at the a=0.05 level that the fertilizer had a positive impact on the weight of the com cars?
Answer:
We can conclude that there is significant evidence that dL fertilizer has a positive impact on larger weight of coms
Step-by-step explanation:
Given the data :
8.25 7.35 9.05 8.00 8.25 8.75 9.00 7.60 8.45 8.55
Using calculator :
Mean, x = 8.325
Standard deviation, s = 0.560
Null hypothesis :
H0: μ = 8
H1 : μ > 8
The test statistic,
(x - μ) / (s/sqrt(n))
(8.325 - 8) / (0.56 / sqrt(10))
0.325 / 0.177
= 1.835
The Pvalue ; using the Tstatistic calculator ;
α = 0.05 ; df = 10 - 1 = 9
Pvalue = 0.04985
Reject H0 ; if Pvalue is < α
Hence, since 0.04985 < 0.05 ; we reject H0
. We can conclude that there is significant evidence that dL fertilizer has a positive impact on larger weight of coms
Please help! (I also put what a median is)
Answer:
Step-by-step explanation:
1. 2
2. 3
3. 6
4. 2
5. 4
you can see that there is 8 cm in middle of the trapezoid. above the trapezoid, it says 6 cm, below the trapezoid, it says 11 cm. find the area of the trapezoid and answer this question in square cm.
Answer:
Step-by-step explanation:
The area of a trapezoid is the average of the parallel bases times the height or distance between the two bases
A=h(b1+b2)/2
Here we have h=8cm, b1=6cm, and b2=11cm so
A=8(6+11)/2
A=8(17)/2
A=4(17)
A=68 cm^2
What is the solution to the expression
i don’t understand when it is all the same number
Answer:
5 preschoolers
Step-by-step explanation:
So this question states that yesterday, 10 preschoolers chose to play with stuffed animals and 10 different preschoolers chose to so other activities.
We can assume that there were 20 preschoolers at school yesterday (10 + 10 = 20).
From this given information, we can conclude that the preschoolers who would chose to play with stuffed animals would be the same amount at the preschoolers who would chose to do other activities.
Using all of the given information, we can also find that:
10/20 or 1/2 of the preschoolers would chose to play with the stuffed animals
and
10/20 or 1/2 of the preschoolers would chose to do other activities
We are then given that there are 10 preschoolers at school today. We are asked to find out how many of the preschoolers are expected to chose to play with the stuffed animals.
Previously, we found that 1/2 of the preschoolers yesterday chose to play with the stuffed animals. We can use this to find the expected amount of preschoolers who will chose to play with the stuffed animals today.
We can do this by multiplying 1/2 with the number of preschoolers today, or 10:
10 × 1/2 = 10/2 = 5
So it is expected that 5 preschoolers would chose to play with the stuffed animals today.
I hope you find my answer to be helpful. Happy studying.
Solve for x.
Your answer must be simplified.
17x>−17
Answer:
x>-1
Step-by-step explanation:
[tex] \frac{17}{17}x > - \frac{17}{17} \\x > - 1 [/tex]
When 2(3/5x+2 3/4y- 1/4x -1 1/2y+3) is
is simplified, what is the resulting expression?
Enter an algebraic expression for the word expression.
The quotient of -5 and y
The expression is
9514 1404 393
Answer:
-5/y
Step-by-step explanation:
The wording "the quotient of A and B" is used to signify A/B.
Here, we want the quotient of -5 and y:
-5/y
An ice cream truck sells ice cream between 2 pm and 10 pm each night in the summer. At the end of the night the driver calculates his profits and makes a graph to analyze the data. What is the average rate of change for the 1st hour to the 4th hour?
A. $24
B. $24 per hour
C. 8 hours
D. $8 per hour
20 points pizzazz help
Answer:
the answer is B hope it helps
Answer:
answer is B
Step-by-step explanation:
heyy pls help ty lol
Answer: 5/12
Step-by-step explanation:
Answer:
5/12
Step-by-step explanation:
We are going to change both number so they have the same denominators.
1/4x3/3= 3/12
2/3x4/4=8/12
Once we changed the number we are going to subtract the numbers.
8/12-3/12=5/12
We can't simplify 5/12 so the answer is 5/12.
Please help I’m struggling
Answer:
y=3x+19
Step-by-step explanation:
x=3
(-4,7)(x,y)
y-7/x_-4=3
y-7=3(x+4)
y=3x+12+7
y=3x+19
Step-by-step explanation:
here you have the answer
ANSWER ASAP PLZ BRAINLYIST WILL BE GIVEN IF RIGHT
What is the value of x?
Answer:
8 × [tex]x[/tex] = 12 x 18
8[tex]x[/tex] = 216
[tex]x[/tex] = 27cm
Step-by-step explanation:
I use that formula because they are similar triangles! :)
Hope this helps!
Solve the equation square root of the quantity x plus 3 plus 4 equals 5 for the variable. Show each step of your solution process
Answer:
x=-2
Step-by-step explanation:
[tex]\sqrt{x+3}+4=5[/tex]
subtract 4 from each side
[tex]\sqrt{x+3} +4-4=5-4[/tex]
square both sides
[tex]\sqrt{x+3}^2=1^2[/tex]
so we have
[tex]x+3=1[/tex]
subtract 3 from each side
[tex]x+3-3=1-3[/tex]
so our answer is [tex]x=-2[/tex]
Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane is measured in meters. A particle is moving clockwise around the circle of radius 1 m centered at the origin at the constant rate of 2 m/sec.How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point?
Missing information:
How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point
[tex]P = (\frac{1}{2}, \frac{\sqrt 3}{2})[/tex]
Answer:
[tex]Rate = 0.935042^\circ /cm[/tex]
Step-by-step explanation:
Given
[tex]P = (\frac{1}{2}, \frac{\sqrt 3}{2})[/tex]
[tex]T(x,y) =x\sin2y[/tex]
[tex]r = 1m[/tex]
[tex]v = 2m/s[/tex]
Express the given point P as a unit tangent vector:
[tex]P = (\frac{1}{2}, \frac{\sqrt 3}{2})[/tex]
[tex]u = \frac{\sqrt 3}{2}i - \frac{1}{2}j[/tex]
Next, find the gradient of P and T using: [tex]\triangle T = \nabla T * u[/tex]
Where
[tex]\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j[/tex]
So: the gradient becomes:
[tex]\triangle T = \nabla T * u[/tex]
[tex]\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j][/tex]
By vector multiplication, we have:
[tex]\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}[/tex]
[tex]\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)[/tex]
[tex]\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5[/tex]
[tex]\triangle T = 0.935042[/tex]
Hence, the rate is:
[tex]Rate = \triangle T = 0.935042^\circ /cm[/tex]
Need help plzzzzzzz!!!!
Answer:
there is no image
Step-by-step explanation:
solve for 26 - 4s = 9s.
26-4s=9s
⇔26=9s+4s
⇔26=13s
⇔s=2
Answer:
s = 2
Step-by-step explanation:
26 - 4s = 9s
add 4s to 4s and 9s
that equals 13
26/13 = 13s/13
s = 2
Expand the following expression 8(3x+10y)
Select one:
104xy
24x+10y
8xy(13)
24x+80y
Answer:
8(3x+10y)
the answer is 24x+80y
Can someone help me? I'll reward points + brainalist
The answer for the following question is 12
as
Circumference of the circle = 2TTr
= 2 x 22/7 x 12
= 44 / 7 x 12
= 75.4285714286
this is what I need help with
Answer:
well thats high school stuff so pay attention in ur classes.
Step-by-step explanation:
need help with question 4
Answer:
Perimeter: 18u^2
Area: 18u^2
Step-by-step explanation:
perimeter is just adding all the sides together so 6+3+6+3
area is multiplying length by width so 6•3
both give us 18
hope this helps chu <3
Evaluate the expression where x=5 and y =2
Answer:
6
Step-by-step explanation: