A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from the bulb, the amplitude of the electric field is 3.78 V/m. What is

Answer:

Independent, then dependent

Explanation:

Just took this on Edge 2021

Answer:

773.25 Hz

Explanation:

Concept : In an open organ pipe in fundamental mode of vibration

wave length of wave λ = 2L

where L  is length of  the pipe

frequency   = velocity of sound / λ

Given values: fundamental frequency = 288 Hz

fluid is air. velocity of sound = 340 m/s

⇒ 288 = 340/2L

⇒L = 59.02 cm

The point to be noted is if the pipe is filled with helium initially at the same temperature, there would be change in the sound velocity .Then,  frequency of note produced will also be changed .

We know that velocity of sound is inversely proportional to  square root of molar mass of gas

velocity of sound in air / velocity of sound in helium = Square root of (Molar mass of Helium/ molar mass of air)

[tex]\frac{V_a}{V_{He}} = \sqrt{\frac{4}{28.8} } \\\frac{340}{V_{He}} =0.3725\\V_{He} =912.5 m/s[/tex]

Now, frequency  = velocity of sound / λ

= 912.75 / (2 x 0.5902)

= 773.25 Hz

Answer:

40*C

Explanation:

This question is incomplete, the complete question  is;

Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies the initial conditions specified. Units are mks; γ is the damping coefficient, with units of kg/sec

m = 0.2, γ = 1.6 and k = 4

Initial displacement is 1 and initial velocity is -2

x" + _____ x' ____x = 0

x(t) =

Answer:

the solution that satisfies the initial conditions specified is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

Explanation:

Given the data in the question ;

m = 0.2, γ = 1.6, k = 4

x(0) = 1, x'(0) = -2

Now, the differential equation that governs the motions of spring mass system is;

mx" + γx' + kx = 0

so we substitute

0.2x" + 1.6x' + 4x = 0

divide through by 0.2

x" + 8x' + 20x = 0

hence, characteristics equation will be;

m² + 8m + 20 = 0

we find m using; x = [ -b±√(b² - 4ac) ] / 2a

m = [ -8 ± √((8)² - 4(1 × 20 )) ] / 2(1)

m = [ -8 ± √( 64 - 80 ) ] / 2

m = [ -8 ± √-16 ) ] / 2

m = ( -8 ± 4i ) / 2

m = -4 ± 2i

Hence, the general solution of the differential equation is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

From the initial conditions;

c₁ = 1, c₂ = 1

the solution that satisfies the initial conditions specified is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

This question is incomplete, the complete question is;

A woman is 160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing upright.

Hint: Consider the ray diagram below, of the rays that enable her to see her feet and the top of her head.

Use what you know about the law of reflection, together with a bit geometry.

The missing Image is uploaded along this answer below.

Answer:

the minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm

Explanation:

Given the data in the question and illustrated in the image below,

From image 2;

The distance from the woman's eyes to the top of her head is represented as b and a represent the distance from her eyes to her feet.

Therefore, since her height is 160 cm

a + b = 160 ------ let this be equation 1

i.e AD + DG = 160 cm

Now, from the same image 2, we will notice that triangle ABC and tringle CBD are similar, so

∠ABC = ∠CBD

AC = CD

since AD = a and AC + CD = A

AC = CD = a/2

Also, triangle DEF and FEG are si,ilar

∠DEF = ∠FEG

so

DF = FG

since DG = b and DF + FG = b

DF = b/2

so the minimum vertical length of a mirror in which the woman can see her entire body while standing upright will be;

⇒ a/2 + b/2  

⇒ a + b / 2

from equation 1, a + b = 160

so

⇒ a + b / 2 = 160 / 2 = 80

Therefore, the minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm

The minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm.

The minimum vertical length of a mirror in which she can see her entire body while standing upright is calculated as follows;

u + v = 160 cm

where;

For mirror, u = v

2u = 160 cm

u = 160 cm/2

u = 80 cm

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Answer:

[tex](a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]

[tex](b)\ F_{No} = 771.125N[/tex]

Explanation:

Given

[tex]d_D = 6000ft[/tex] ---- Altitude of container in Denver

[tex]A = 0.0155m^2[/tex] -- Surface Area of the container lid

[tex]P_D = 79000Pa[/tex] --- Air pressure in Denver

[tex]P_{No} = 100250Pa[/tex] --- Air pressure in New Orleans

See comment for complete question

Solving (a): The expression for [tex]F_{No[/tex]

Force is calculated as:

[tex]F = \triangle P * A[/tex]

The force in New Orleans is:

[tex]F_{No} = \triangle P * A[/tex]

Since the inside pressure is half the pressure at sea level, then:

[tex]\triangle P = P_{No} - \frac{P_{area}}{2}[/tex]

Where

[tex]P_{area} = 101000Pa[/tex] --- Standard Pressure

Recall that:

[tex]F_{No} = \triangle P * A[/tex]

This gives:

[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]

Solving (b): The value of [tex]F_{No[/tex]

In (a), we have:

[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]

Where

[tex]A = 0.0155m^2[/tex]

[tex]P_{No} = 100250Pa[/tex]

[tex]P_{area} = 101000Pa[/tex]

So, we have:

[tex]F_{No} = [100250 - \frac{101000}{2}] * 0.0155[/tex]

[tex]F_{No} = [100250 - 50500] * 0.0155[/tex]

[tex]F_{No} = 49750* 0.0155[/tex]

[tex]F_{No} = 771.125N[/tex]

Answer:

61.8

Explanation:

It must be going at a speed of 61.81 m/s when it reaches the plain below

The kinematic equations are a set of equations that describe the motion of an object with constant acceleration. Kinematics equations require knowledge of derivatives, rate of change, and integrals.

using  Kinematics equations

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2gs                         ( a = g)

   = [tex](53.7)^{2}[/tex] + 2 * 9.8 * 47.8 m

 v  = 61.81 m/s

It must be going at a speed of 61.81 m/s when it reaches the plain below

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Answer:

D)parallel circuit

Explanation:

the components are placed parallel from eachother

Explanation:

Impacts of large meteorites have never been observed by humans. Much of our knowledge about what happens next must come from scaled experiments. As the solid object plows into the Earth, it will compress the rocks to form a depression and cause a jet of fragmented rock and dust to be expelled into the atmosphere.

Answer:To explian the exact calculation of this pruduct we must not try!

Answer:

B

Explanation:

Answer:

The carpet has a buildup of electrons in it that get released onto your body when you rub across the floor while the hardwood doesn't have electrons built up inside of it.

Explanation:

I study that

Answer:

B. Radio Waves

Explanation:

There are several characteristics that show what kind of electromagnetic radiation you're dealing with. This graph they've provided you only shows wavelengths in the positive area (10^4 through 10^18). Every other choice they give you is either higher on the spectrum, or in the negative area.

Radio waves are at the front of the electromagnetic spectrum. They have the longest wavelength, lowest energy and lowest frequency. The graph below is something they should have showed you in the class and is the key to remembering each component of electromagnetic radiation and their properties.

Answer:

A.

X-rays

Explanation:

In order of wave spectrum band, Gamma rays have the highest frequency and shortest wavelength and that's in region A, it is followed by x-rays in region B

Answer:

[tex]P_c=-4v[/tex]

Explanation:

From the question we are told that:

Inner radius [tex]r_1=0.2[/tex]

Outer radius[tex]r_2=0.4[/tex]

Potential at the outer surface is [tex]P_o= -2 V[/tex]

Generally the equation for Potential at the outer surface P_o  is mathematically given by

[tex]P_o=\frac{KQ}{r_2}[/tex]

[tex]-2=\frac{KQ}{0.4}[/tex]

Therefore

[tex]KQ=-0.8v[/tex]

Generally the equation for Potential at Center of outer cavity [tex]P_c[/tex]  is mathematically given by

[tex]P_c=\frac{KQ}{r_1}[/tex]

[tex]P_c=\frac{-0.8}{0.2}[/tex]

[tex]P_c=-4v[/tex]

Therefore the potential at the center of cavity

[tex]P_c=-4v[/tex]

The potential at the center of the cavity of the spherical conducting shell is -0.4 V.

Electric potential of spherical shell is the total amount of work required to move a charge in s spherical shell from one point to other.

Electric potential of spherical shell at outer surface can be given as,

[tex]P_{outer}=k\dfrac{Q}{r_o}[/tex]

Electric potential of spherical shell at center of outer gravity can be given as,

[tex]P_{cavity}=k\dfrac{Q}{r_i}[/tex]

Here, (Q) is the charge, (k) is the constant and [tex](r_o, r_i)[/tex] is the outer and inner radius.

A spherical conducting shell has an outer radius of 0.4 m and the potential at the outer surface is -2 V. Thus, the potential at the outer surface can be find out using the above formula as,

[tex]-2=k\dfrac{Q}{0.4}\\kQ=-0.8\rm V[/tex]

The spherical conducting shell has an inner radius of 0.2 m. Thus, the potential at the outer surface can be find out using the above formula as,

[tex]P_{cavity}=k\dfrac{Q}{0.2}\\P_{cavity}=\dfrac{-0.8}{0.2}\\P_{cavity}=-0.4\rm V[/tex]

Thus, the potential at the center of the cavity of the spherical conducting shell is -0.4 V.

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It increases

Explanation:

The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between object

Answer:

C: Gravity decreases

Explanation:

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

We have

[tex]a = \frac{39}{5.6} \\ = 6.964285...[/tex]

We have the final answer as

Hope this helps you

Answer:

[tex]f_{U}= 1019.72hz[/tex]

Explanation:

From the equation we are told that:

Velocity of French sub [tex]V_{U}= 43.00km/h[/tex]

Velocity of U.S. sub at [tex]V_{F}|=64.00 km//h[/tex]

French Wave Frequency  [tex]F_{F}=1000Hz[/tex]

Velocity of wave  [tex]V_{s}=5470 km/h[/tex]

Generally the equation for Signal's frequency as detected by the U.S. is mathematically given by

Doppler effect

 [tex]f_{U} = \frac{ f_F (vs + v_{U})}{(v_s - v_F) }[/tex]

 [tex]f_{U}= \frac{ 1000 x ( 5470+64)}{(5470-43)}[/tex]

 [tex]f_{U}= 1019.72hz[/tex]

Answer:

2633.7 s

Explanation:

From the question,

Heat lost by the water heater = Heat gained by the water

Applying,

P = cm(t₂-t₁)/t.................. Equation 1

Where P = power of the heat, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature, t = time

make t the subject of the equation

t = cm(t₂-t₁)/P.............. Equation 2

From the question,

Given: c = 4190 J/kgK, P = 3.5 kW = 3500 W, m = 40 kg, t₁ = 20°C, t₂ = 75°C

Substitute these values into equation 2

t = 4190×40(75-20)/3500

t = 9218000/3500

t = 2633.7 s

Answer:

The torque produced is 9.8 Nm.

Explanation:

Given;

mass of the bucket filled with water, m = 20 kg

radius of the cylinder, r = 0.05 m

The torque produced by the weight of water and bucket is the product of force and the perpendicular distance from a point on the line of action of the applied force. (since the cylinder is not permitted to rotate).

τ = F x r

τ = (mg) x r

τ = (20 x 9.8) x 0.05

τ = 9.8 Nm

Therefore, the torque produced is 9.8 Nm.

Answer:

A) 11.2 s

B) is 56 s

C) 170.8 s

Answer:

Rain water carries sediment and then these accumulate on the bottom of ponds, lakes and wetlands. This accumulation build up over time and eventually, the water disappears (because they sink into the ground) and the area once covered with water becomes land.

Explanation:

The voltage sensitivity of  a galvanometer is given by :

[tex]\dfrac{NBA}{RK}[/tex]

Where

N=Number of turns

A=Area of coil

B=Magnetic field produced in coil

K=Torsion constant of galvanometer

R=Resistance of galvanometer

The current sensitivity of  a galvanometer is given by :

[tex]\dfrac{NBA}{K}[/tex]

Hence, this is the required solution.

Answer:

The moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

Explanation:

Given;

radius of the turnable, r = 60 cm = 0.6 m

rotational kinetic energy, E = 0.25 J

angular speed of the turnable, ω = 45 rpm

The rotational kinetic energy is given as;

[tex]E_{rot} = \frac{1}{2} I \omega ^2[/tex]

where;

I is the moment of inertia about the axis of rotation

ω is the angular speed in rad/s

[tex]\omega = 45 \frac{rev}{\min} \times \frac{2 \pi \ rad}{1 \ rev} \times \frac{1 \ \min}{60 \ s} \\\\\omega = 4.712 \ rad/s[/tex]

[tex]E = \frac{1}{2} I \omega ^2\\\\I = \frac{2E}{\omega ^2} \\\\I = \frac{2 \ \times \ 0.25}{(4.712)^2} \\\\I = 0.0225 \ kg.m^2[/tex]

Therefore, the moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

Answer:

c. Both require the same amount of work

Explanation:

GPE = mgh

50 * 10 * 2 = 1000 J

25 * 10 * 4 = 1000 J

Therefore, both are same and require the same amount of work.

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Both require the same amount of work. The correct option is C.

The potential energy that a massive object has in relation to another massive object due to gravity is known as gravitational energy or gravitational potential energy. When two objects fall toward one another, potential energy associated with the gravitational field is released.

Given that there are two activities,

1) lifting a 50 kg sack vertically 2 meters.

2)  lifting a 25 kg sack vertically 4 meters.

The energy required to lift the weight will be calculated as:-

GPE = mgh

50 x 10 x 2 = 1000 J

25  x  10 x  4 = 1000 J

So we can conclude that both activities require the same amount of work.

Therefore, both require the same amount of work. The correct option is C.

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Answer:

in decimal form x = 1.5

in exact form x = 3/2

and as a mixed number x = 1  1/2

Explanation:

Answer:

As long as there is rain, a rainbow is possible. Rain is possible on a sunny day, and is known as a sunshower.The rainbow can be observed in a sunny day if the water droplets are present in air and the sun rays pass through it reaches the eye of the observer. In this situation, the observer can see a rainbow.

or

If you happened to look up at the sky this past weekend, you might have noticed a rare and beautiful sight: iridescent rainbow clouds, but not a drop of rain in sight. This phenomenon is known, fittingly, as cloud iridescence or irisation. The effect is not unlike seeing a rainbow painted on the clouds.

Answer:

um let me know what i can do to try get you full access

Explatnation: