A hover craft also known as a air cushion vehicle glides on a cushion of air allowing it to travel with equal is land or water. The first commercial hovercraft to cross the English channel the V. A-3 had a average speed of 26.7 M/S. Its momentum at the speed was 4.8×10^4 KGM/S. What was the mass of the V. A-3?

Answer: frequency is the answer to this question

Answer:

frequency

Explanation:

c a n v a s / a p e x :))

Answer:

see explanation

Explanation:

A,B,C,E

B.

Because its copper

Answer:1) the total distance is the sum of the two distances

60 km +  45 km = 105 km

2) The displacement is the net movement, or the difference between the initial position and the final position

Call x the initial position, then the final position is x + [60km - 45km]

And the displacement is x + (60km - 45km) - x =60km -45 km = 15 km

Explanation:

Answer: momentum = 40kgm/s

Explanation:

Given that the

Mass M = 10kg

Height H = 80 cm = 0.8m

g = 10m/s^2

The velocity of the dumbbell as it fall can be calculated by using the formula;

V^2 = U^2 + 2gH

Since the dumbbell fell from rest, initial velocity U = 0

Substitute g and H to get final velocity V

V^2 = 0 + 2 × 10 × 0.8

V^2 = 16

V = sqrt(16)

V = 4 m/s

Momentum is the product of mass and velocity. That is,

Momentum = MV

Substitute mass M and V into the formula

Momentum = 10 × 4 = 40kgm/s

Therefore, 40 kgm/s momentum will be transferred as the dumbbell fall to the floor.

Answer:The starting angle of a pendulum does not affect its period for .

Explanation: however, the period increases with increasing . The starting angle of a pendulum does not affect its period for.

Answer:

A.The direction in which light is bent

Explanation:

That why I the topic thin lenses we learn how to draw Ray's of light

Answer:

a

Explanation:

Answer: 80

Explanation:

The question is incomplete, There is no specific time for the specific velocity, which is not provided in this question instead of giving the total time interval from 0sec to 80 sec. According to my assumption, I think the net displacement will be 20 m. The correct answer will be option D.  

Net displacement is the total change in the position of an object, taking into account both the magnitude and direction of its motion. It is a vector quantity and is expressed in terms of distance and direction.

In other words, it is the final position of an object relative to its initial position, irrespective of the path taken. It is calculated by finding the vector difference between the final and initial positions of the object.

For example, if an object moves 10 meters to the east and then 5 meters to the north of its starting position, then its net displacement would be the vector sum of these two displacements, which is the diagonal distance between its starting and final positions.

Here in the Question,

To calculate the net displacement of the particle between 0 seconds and 80 seconds based on the given options, we can use the fact that the net displacement is the same as the final position minus the initial position.

Let's assume that the initial position is zero.

Option A. If the net displacement is 160 meters, the final position would be 160 meters. However, looking at the velocities given, we can see that the particle goes back and forth, so it does not make sense for the net displacement to be larger than the maximum displacement in one direction.

Option B. If the net displacement is 80 meters, the final position would be 80 meters. This option could be possible if the particle moves in one direction for a while and then moves back to its initial position. This is incorrect.

Option C. If the net displacement is 40 meters, the final position would be 40 meters. This option is also possible if the particle moves in one direction for a shorter period of time. This is not relevant to the question.

Option D. If the net displacement is 20 meters, the final position would be 20 meters. This option could be possible if the particle moves in one direction for a very short period of time. This is most relevant to the Question.

Option E. If the net displacement is 0 meters, the final position would be the same as the initial position, which is zero. This option could be possible if the particle moves back and forth such that the positive displacements cancel out the negative displacements.

Therefore, based on the given options, the correct answer for the net displacement of the particle between 0 seconds and 80 seconds is option D: 20 meters.

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Answer:

13.4 m/s

Explanation:

Write down what you have, so:

V0=8 m/s

a=2.7 m/s^2

t=2 seconds

We are trying to find final velocity, so we will use vf = v0 + at

From there, we plug in the given values.

vf = 8 m/s + (2.7 m/s^2 x 2 seconds)

vf = 13.4 m/s

Answer:

about 13s

Explanation: