A heavy bank-vault door is opened by the application of a force of 300 N directed perpendicular to the plane of the door at a distance of 0.80 m from the hinges. What is the torque?

Question 4 options:

1.) 120 Nm
2.) 240 Nm
3.) 375 Nm
4.) 300 Nm

Answers

Answer 1

Answer:

240Nm

Explanation:

Given parameters:

Force on the bank vault = 300N

Distance to the plane of the vault  = 0.8m

Unknown:

Torque = ?

Solution:

Torque is the component of force that causes an object to rotate about an axis;

  Torque  = Fr x sinФ

Here Ф  = 90°

         r  = distance

   Torque  = 300 x 0.8 x Sin 90°

    Torque  = 240Nm


Related Questions

What is the average emf between the ends of the wings of a plane flying at a speed of 500 km/hr when the vertical component?

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete because there are some parameters that are missing. However, when calculating the average emf and speed/velocity is provided, then

average emf = Brvl

where Br is the vertical component of the earth's magnetic field (in weber per square meter, Wb/m²)

v is velocity (in m/s)

l is the length (in meter) of the wing span

Which of the following best describes the relationship between the speed of light and the type of medium through which it travels?

A.
Light travels fastest in solids

B.
Light travels fastest in liquids

C.
The less dense the medium, the slower a light wave travel

D.
The more dense the medium, the slower a light wave will travel

Answers

Answer:

D

Explanation:

When light makes contact with any object it naturally slows down, and the more dense the object the slower it travels.

describe the motion of the fireball in the air

Answers

Explanation:

doesn't get the question and the answer to

Answer:

(this is the sample answer:After the launch, the fireball moves upward, than it falls back down to EarthEartEarthEarthEarthEarth

Explanation:

Harnessing tidal power would involve:_______.a) letting in-flowing and/or out-flowing tide flow through turbines in a dam.b) huge floats mechanically hooked to generators.c) electrodes in the water.d) bioluminescence of marine organisms.e) all of the above

Answers

Answer:

a) letting in-flowing and/or out-flowing tide flow through turbines in a dam.

Explanation:

Tidal power makes use of the energy from the tidal force and wave action in order to generate electricity. it is a predictable source of energy.

Tidal Barrages

The system allows tides to enter, seawater flows via the dam and is trapped into the basin when the tides subside and system’s gates close.

When the tides start to move out, the gates in the dam are opened up this consist of turbines and water begins to flow out, hitting the turbines this eventually turn to produce energy.

Power is produced when the tidal range, which is the difference between low and high tide, has to be more than 5 meters.

As the rate of radioactive decay becomes smaller half life become...

Answers

the decay half-life of a radioactive material can be changed. Radioactive decay happens when an unstable atomic nucleus spontaneously changes to a lower-energy state and spits out a bit of radiation. This process changes the atom to a different element or a different isotope.

Why is struggling an important part of the process of learning?

Answers

Answer:

Students need a safe environment to take risks and struggle. It’s uncomfortable to struggle, but struggling—falling down and getting back up—is an important facet to learning. Productive struggle is not about being in pain or becoming frustrated.

Please mark branliest!

Explanation: it shows that your really trying your best and when you mess up its telling you that your actually learning from your mistakes.

Which form of energy has the most potential globally

a) Solar energy

b) Bio energy

c) Wind energy

d) Geothermal energy

Answers

Answer:

i think the answer is solar,

Explanation:

because it is a natural resource im sorry if im wrong

Need help ASAP please help

Answers

Answer:

.....

Explanation:

Bicyclist travels at an average velocity of 11.2 km/h [W]. How far will the bicyclist travel in 175 minutes?

Answers

Answer:

32.67km

Explanation:

~= round off

11.2km/h~3.11m/s

175minutes=10500s

10500*3.11~32, 666.67m

=32.66667km

~ 32.67km

Which action would decrease the strength of attraction between a magnet and an iron object
A. Moving the magnet farther away from the iron object
B. Moving the iron object closer to the magnet
C. Decreasing the number of electrons on the magnet
D. Increasing the number of electrons on the magnet

Answers

Answer:

a. moving the magnet farther away and an iron object.

Explanation:

Answer:A

Explanation:

A p e x

If a second planet were of the same radius R and made of the same material but had a hollow center of radius 0.50 R , what would be the acceleration of gravity at its surface

Answers

Answer:

[tex]g_2=\dfrac{7}{8}g[/tex]

Explanation:

G = Gravitational constant

M = Mass of planet

R = Radius of planet

Acceleration due to gravity on first planet

[tex]g=\dfrac{GM}{R}[/tex]

Assuming that the planets have the same mass density [tex]\rho[/tex]

Density of first planet

[tex]\rho=\dfrac{M}{V}\\\Rightarrow \rho=\dfrac{M}{\dfrac{4}{3}\pi R^3}\\\Rightarrow M=\rho \dfrac{4}{3}\pi R^3[/tex]

Density of second planet

[tex]\rho=\dfrac{M_2}{V_2}=\dfrac{M_2}{\dfrac{4}{3}\pi R^3-\dfrac{4}{3}\pi (0.5R)^3}\\\Rightarrow \rho=\dfrac{M_2}{\dfrac{4}{3}\pi R^3(1-\dfrac{1}{2^3})}\\\Rightarrow \rho=\dfrac{M_2}{\dfrac{4}{3}\pi R^3(1-\dfrac{1}{8})}\\\Rightarrow \rho=\dfrac{M_2}{\dfrac{4}{3}\pi R^3(\dfrac{7}{8})}\\\Rightarrow M_2=\rho\dfrac{4}{3}\pi R^3(\dfrac{7}{8})\\\Rightarrow M_2=M\dfrac{7}{8}[/tex]

Acceleration due to gravity on the second planet

[tex]g_2=\dfrac{GM_2}{R}\\\Rightarrow g_2=\dfrac{GM\dfrac{7}{8}}{R}\\\Rightarrow g_2=\dfrac{7}{8}g[/tex]

The acceleration due to gravity of the planet would be [tex]\dfrac{7}{8}[/tex] times the acceleration due to gravity on the first planet.

The graph below shows the velocity of a car as it attempts to set a speed
record.
Velocity vs. Time
1400
1300
1200
1100
1000
4 45
3
1 (s)
At what point is the car the fastest?
A. t = 1.0 s
B. t = 4.2 s
C. t = 3.0 s
D. t = 4.5 s

Answers

Guessing (A) because it had the highest velocity number on the graph and it matched 1s

From the graph, it is clear that, the velocity is at a time of 1 s is highest. The velocity at 1 second corresponds to 1250 km/hr. Then it decreases with time.

What is velocity - time graph ?

The velocity - time graph shows the change in velocity with respect to time. The velocity is placed in y -axis and time is given in x - axis. The slope of the curve in velocity - time graph gives the acceleration of the object.

Similarly, the position of the object in meter after a t seconds can be determined from the velocity - time graph. It is the rate of change in velocity of the object.

From the graph, it is clear that, the curve has its peak at 1 second. After that the peak descends down. Hence, the maximum velocity of the car is at a time of 1 second at which the velocity is 1250 km/hr.

Find more on velocity - time graph :

https://brainly.com/question/28357012

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A car starts from rest and reaches a velocity of 30 m/s in 10 s. If the car
has a mass of 1500 kg, what net force is exerted upon the car?

Answers

Answer:

f= ma

Explanation:

v-u/ t

30-0/10

3m/s

maas 1500

1500*3

4500


Which of the following is NOT a correct statement?*
As the volume of a contained gas increases, the pressure in the container will
decrease.
As the temperature decreases, the kinetic energy of the particles decreases.
As pressure increases with a constant temperature, the volume decreases.
O As temperature increases, the kinetic energy of the particles decreases.

Answers

AnswerAmontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas (Figure 1).:

Explanation:

a. A remote-control car with a constant velocity drives off the top of a wall that is 10.0 m high and lands 4.60 m from the base of the wall. Draw a diagram of the problem. Label the known and unknown quantities. b. What is the car's speed before it drives off the top of the wall? c. What is the car's vertical speed just before impact? d. How far from the base of the wall would the remote-control car have landed if it had been subject to the gravitational field on the Moon (1.7 N/kg) ?

Answers

Answer:

a. Please see the attached graph and drawing combined created with Microsoft Excel

b. Approximately 3.2217 m/s

c. Approximately 14.0 m/s  

d. Approximately 11.05 meters

Explanation:

a. The given parameters are;

The height of the wall, h = 10.0 m

The distance from the base of the wall the car lands = 4.60 m

The time, t, it takes the car to land is given by the equation for free fall as follows;

h = 1/2·g·t²

Where;

g = The acceleration due to gravity = 9.81 m/s²

From the equation for free fall, we have;

h/(1/2·g) = t²

∴ t = √(h/(1/2·g) ) = √(10/(1/2·9.81) ) ≈ 1.4278

The time it takes the car to land, t ≈ 1.4278 seconds

b. The horizontal speed of the car = Horizontal distance/(Time) = 4.6/1.4278 ≈ 3.2217 m/s

The horizontal speed of the car before it drives off the wall  ≈ 3.2217 m/s

c. The car's vertical speed just before impact is given by the following equation;

v = u + gt

Where;

u = The initial vertical speed = 0

t = The time it takes before impact ≈ 1.4278 seconds

∴ v = 9.81 × 1.4278 ≈ 14.0 m/s  

The car's vertical speed just before impact, v ≈ 14.0 m/s  

d. Whereby the car is subject to the gravitational field of the moon, we have;

Gravitational force per kilogram = 1.7 N/kg

∴ Gravitational acceleration = 1.7 m/s².

The time it takes the car to land whilst subject to the gravitational field of the moon is therefore;

[tex]t_{Moon}[/tex] = √(h/(1/2·g)) = √(10/(1/2 × 1.7)) ≈ 3.43

[tex]t_{Moon}[/tex] ≈ 3.43 seconds

The horizontal distance covered, at the car's horizontal speed in the time of free fall ≈ 3.2217 m/s ×  3.43 seconds ≈ 11.05 meters

The horizontal distance covered, at the car's horizontal speed in the time of free fall  = The distance the car will land from the base of the wall ≈ 11.05 meters

The distance the car will land from the base of the wall ≈ 11.05 meters.

You tie the loose end of a 0.1 kg yo-yo string to your finger and then release the yo-yo so that it spins down toward the ground (the yo-yo is released from rest and the end of the string tied to your finger remains motionless). After the yo-yo falls a distance of 0.9 m, it has a translational speed of 4 m/s and an angular speed of 180 rad/s. What is the moment of inertia of the yo-yo

Answers

Answer:

The answer is "[tex]5.06 \times 10^{-6} \ kg \ m^2[/tex]"

Explanation:

[tex]\to E_1=0..............(i)\\\\\to E_2= \frac{mV^2}{2} +\frac{Iw^2}{2} - mgh.............(ii)\\\\ \Delta E=0\\\\\to mgh= \frac{mV^2}{2} +\frac{Iw^2}{2} \\\\ \to 2 \ mgh= mV^2 +Iw^2\\\\ \to 2 \ mgh- mV^2 =Iw^2\\\\ \to m(2gh- V^2) =Iw^2\\\\ \to I= \frac{m(2gh- V^2)}{w^2}[/tex]

       [tex]= 5.06 \times 10^{-6} \ kg \ m^2[/tex]

What are the 6 basic machines, and what are they and what can the be, and look like.

Answers

Answer:

Pulleys, levers, inclined planes, wedges, screws, and wheel and axle.

Explanation:

How much tension must a rope withstand if it is used to accelerate a 1200-kg car vertically upwards at 0.8m/s2?

Answers

Answer:

T = 12732 [N]

Explanation:

To solve this problem we must use newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

By means of the attached free body diagram, we can better understand the solution to this problem.

As we see in the diagram the tension Force T lifts the car upwards so the movement is upwards. Therefore we have two forces one upward (positive) of the force T and the other negative downward due to the weight of the vehicle.

As the movement is up the acceleration is also up (with a positive sign).

ΣF = m*a

where:

F = forces [N] (units of Newtons)

m = mass = 1200 [kg]

a = acceleration = 0.8 [m/s²]

T - 1200*9.81 = 1200*(0.8)

T = 12732 [N]

Answer:

12,720

Explanation:

Which of the following is how the substance in a longitudinal wave flows?

A. Up and Down

B. At Random

C. Perpendicular to the direction of the wave

D. In the direction of the wave

Please help I need this turned in tonight.

Answers

Answer:

The answer is D. In the direction of the wave

Explanation:

I took the test, hope this helps! :)

What is the momentum of 100 kg running at 4m/s north?

Answers

The momentum is known as mass x velocity then u should say that it will be 400 kg m/s

At 96° F the saturation density of air is 0.04 kg/m3. If the weather report says the relative humidity is 90 % when the temperature is 96°F, the humidity is

Answers

Answer:

The value is  [tex]H = 0.036 \ kg/m^3[/tex]

Explanation:

From the question we are told that

   The saturation density of air is [tex]\rho = 0.04 \ kg/m^3[/tex]

   The temperature for this saturation density to occur  [tex]T_s = 96^o F[/tex]

    The relative humidity at this temperature is  [tex]R_h = 90\% = 0.90[/tex]

Generally the relative humidity is mathematically represented as

      [tex]R_H = \frac{H}{\rho}[/tex]

Here H represents humidity

=> [tex]0.90 = \frac{H}{0.04}[/tex]

=>  [tex]H = 0.90 * 0.04[/tex]

=>  [tex]H = 0.036 \ kg/m^3[/tex]

what can you infer from the statement. velocity is an object is zero

Answers

The object is moving at a constant speed

What type of numbers in a measurement are always significant?

Answers

Answer:

Non-zero digits

Explanation:

umm (ꏿ﹏ꏿ;)

Answer:

There's three rules on determining how many important quantities are in a number: Non-zero digits are always predominant. Any zeros between two significant digits are always major. The final zero or dangling zeros in the decimal segment are really only important.

I hope this answered your question, have a nice day!

During the slowing down process, there is a time when the angular speed is 0.5 rev/s. The fan arm is 0.8 m long. What is the speed of a point on the end of the fan arm at this time

Answers

Answer:

2.51 m/s

Explanation:

Given that,

Angular speed of a fan, [tex]\omega=0.5\ rev/s = 3.14\ rad/s[/tex]

Length of the fan arm, r = 0.8 m

We need to find the speed of a point on the end of the fan arm at this time. Let v is the speed. It is given in terms of angular speed is given by :

[tex]v=r\omega\\\\v=0.8\times 3.14\\\\v=2.51\ m/s[/tex]

So, the required speed is 2.51 m/s.

Which factors affect the rate of deposition? Check all that apply.
color of the sediment
density of the sediment
size of the sediment
texture of the sediment
velocity of the agent of erosion

Answers

Answer:

density of the sediment, size of the sediment, and velocity of the agent of erosion.

Explanation:

Have a nice day!

Answer: b., c., e.

Explanation:

which property of potential energy distinguishes it from kinetic energy

Answers

Answer:

Shape and position

Explanation:

Hope this helps! :)

HELP PLEASE!!!! :( Does anyone have Lab: Conservation of Linear Momentum for online Physics class?? WILL GIVE YOU 80 PTS

Answers

Answer:

this is it

Explanation:

the control and experiemental groups i didnt know

Maybe I’ll make one more question. What type of electricity is made when you spin something really fast?

Answers

Answer:

i didnt know ther was differnt types

Explanation:

1500 POINTS TO WHOEVER ANSWERS THIS FIRST!!!!!!!!!!

1. You drop a bowling ball 15m from the top of the science building. What is its
velocity as it impacts the ground?

2. A cheetah accelerates from 0 to 13m/s in 3 seconds. How far does it travel
during that time?

3. Your foolish friend shoots a bullet straight in the air at a muzzle velocity of
380 m/s. How high does the bullet go (neglecting air resistance)?

4. Your foolish friend shoots a bullet straight in the air at a muzzle velocity of
380 m/s. What is the bullets velocity when it falls back down and hits your
friend?

Answers

Answer: Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.

Explanation:

asheed and Sofia are riding a merry-go-round that is spinning steadily (uniform circular motion). Sofia is twice as far from the axis as is Rasheed. Sophia's acceleration is _________ that of Rasheed. *

Answers

Answer:

The same as

Explanation:

First of all, they are in a merry go round, which is a circular one. And thus, we would be dealing with circular motions.

The angular velocity of a merry go round, in this instance, is given by

w = Δ/Δt

The formula has nothing whatsoever to do with distance, and as such, both Rasheed and Sofia would have the same angular velocity.

Transferring this further, the angular acceleration is given as

α = Δw/Δt

Remember I said the velocity has nothing to do with distance, well, so does the acceleration as we can see from the formula stated. And therefore, both Rasheed and Sofia would have the same angular acceleration

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