Answer:
(A) the thermal efficiency of this engine is 66.44 %
(B) the power delivered by the engine in watts is 664,400 W
(C) The rate at which heat is rejected to the cold temperature sink is 335.6 kJ/s.
Explanation:
Given;
Input Heat received by the engine, [tex]P_{in}[/tex] = 1000 kJ/s
hot temperature, [tex]T_H[/tex] = 600 ⁰C = 600 + 273 = 873 K
cold temperature, [tex]T_C[/tex] = 20 ⁰C = 20 + 273 = 293 K
(A) the thermal efficiency of this engine;
[tex]\eta = 1 - \frac{T_C}{T_H} \\\\\eta = 1 - \frac{293}{873} \\\\\eta = 1 - 0.3356\\\\\eta = 0.6644 = 66.44 \%[/tex]
(B) the power delivered by the engine in watts;
[tex]P = \eta P_{in}\\\\P = 0.6644 \times \ 1000kJ/s \ \times \ \frac{1\ kW}{1\ kJ/s} \\\\P = 664.4 \ kW \\\\P = 664,400 \ W[/tex]
(C) The rate at which heat is rejected to the cold temperature sink;
[tex]Q_C = Q_H(1-\eta)\\\\Q_C = 1000\ kJ/s(1-0.6644)\\\\Q_C = 335.6 \ kJ/s[/tex]
what is the relationship of waste management and bioremediation?
Answer:
In the simplest terms, bioremediation is a waste management process using live organisms to neutralize or remove harmful pollutants from contaminated areas. Bioremediation is an environmental science that amplifies natural biological actions to remedy or remediate polluted groundwater and contaminated soil.
Explanation:
In the simplest terms, bioremediation is a waste management process using live organisms to neutralize or remove harmful pollutants from contaminated areas. Bioremediation is an environmental science that amplifies natural biological actions to remedy or remediate polluted groundwater and contaminated soil.
During a storm, gage station A was inoperative but the surrounding stations, B, C, and D, recorded rainfall of 5.2, 4.5, and 6.1 in., respectively. The average annual precipitation for stations A, B, C, and D are 48, 53, 59, and 67 in., respectively. Estimate the storm precipitation for station A.
Answer:
4.247 in
Explanation:
Precipitation at A is P_a
similarly at P_b= 5.2 in, P_c= 4.5 in and P_d= 6.1 in
Normal annual rainfall at station A, B, C, D are
N_a = 48 in, N_b= 53, N_c= 59 in and N_d= 67 in
From the formula we have
P_a/N_a = 1/3( P_b/N_b+P_c/N_c+P_d/N_d)
⇒ P_a = 48/3(5.2/53+4.5/59+6.1/67)
P_a= 16×0.2654 = 4.247 in
HURRY :)) In low light, it's _____ to see details, colors, and distant objects. FYI it's ed drivers!!!! A. Easier B. Harder C. Just as easy D. Impossible
Answer:
harder
Explanation:
Answer:
light
Explanation: