Consider a Carnot heat-engine cycle executed in a closed system using 0.025 kg of steam as the working fluid. It is known that the maximum absolute temperature in the cycle is twice the minimum absolute temperature, and the net work output of the cycle is 60 kJ. If the steam changes from saturated vapor to saturated liquid during heat rejection, determine the temperature of the steam during the heat rejection process. The temperature of the steam during the heat rejection process is
Answer:
The temperature of the steam during the heat rejection process is 42.5°C
Explanation:
Given the data in the question;
the maximum temperature T[tex]_H[/tex] in the cycle is twice the minimum absolute temperature T[tex]_L[/tex] in the cycle
T[tex]_H[/tex] = 0.5T[tex]_L[/tex]
now, we find the efficiency of the Carnot cycle engine
η[tex]_{th[/tex] = 1 - T[tex]_L[/tex]/T[tex]_H[/tex]
η[tex]_{th[/tex] = 1 - T[tex]_L[/tex]/0.5T[tex]_L[/tex]
η[tex]_{th[/tex] = 0.5
the efficiency of the Carnot heat engine can be expressed as;
η[tex]_{th[/tex] = 1 - W[tex]_{net[/tex]/Q[tex]_H[/tex]
where W[tex]_{net[/tex] is net work done, Q[tex]_H[/tex] is is the heat supplied
we substitute
0.5 = 60 / Q[tex]_H[/tex]
Q[tex]_H[/tex] = 60 / 0.5
Q[tex]_H[/tex] = 120 kJ
Now, we apply the first law of thermodynamics to the system
W[tex]_{net[/tex] = Q[tex]_H[/tex] - Q[tex]_L[/tex]
60 = 120 - Q[tex]_L[/tex]
Q[tex]_L[/tex] = 60 kJ
now, the amount of heat rejection per kg of steam is;
q[tex]_L[/tex] = Q[tex]_L[/tex]/m
we substitute
q[tex]_L[/tex] = 60/0.025
q[tex]_L[/tex] = 2400 kJ/kg
which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)
q[tex]_L[/tex] = h[tex]_{fg[/tex] = 2400 kJ/kg
now, at h[tex]_{fg[/tex] = 2400 kJ/kg from saturated water tables;
T[tex]_L[/tex] = 40 + ( 45 - 40 ) ( [tex]\frac{2400-2406.0}{2394.0-2406.0}\\}[/tex] )
T[tex]_L[/tex] = 40 + (5) × (0.5)
T[tex]_L[/tex] = 40 + 2.5
T[tex]_L[/tex] = 42.5°C
Therefore, The temperature of the steam during the heat rejection process is 42.5°C
A wave with a speed of 9 m/s and a frequency of 0.5 Hz has a λ of what?
Wave speed = (wavelength) x (frequency)
Wavelength = (wave speed) / (frequency)
Wavelength = (9 m/s) / (0.5 Hz)
Wavelength = 18 m
A block with mass m1m1m_1 is placed on an inclined plane with slope angle ααalpha and is connected to a second hanging block that has mass m2m2m_2 by a cord passing over a small, frictionless pulley. The coefficient of static friction is μsμsmu_s and the coefficient of kinetic friction is μkμkmu_k. Find the smallest value of m2 when the blocks will remain at rest if they are released from rest.
Answer:
Explanation:
m₂ is hanging vertically and m₁ is placed on inclined plane . Both are in limiting equilibrium so on m₁ , limiting friction will act in upward direction as it will tend to slip in downward direct . Tension in cord connecting the masses be T .
For equilibrium of m₁
m₁ g sinα= T + f where f is force of friction
m₁ g sinα= T + μsx m₁ g cosα
m₁ g sinα - μs x m₁ g cosα = T
For equilibrium of m₂
T = m₂g
Putting this value in equation above
m₁ g sinα - μs x m₁ g cosα = m₂g
m₂ = m₁ sinα - μs x m₁ cosα
A wave takes 0.5 seconds to complete one cycle. Which characteristic of the wave does this description represent? A. period B. wavelength C. amplitude D. frequency
Answer:
period
Explanation:
A wave takes 0.5 seconds to complete one cycle. It is called the time period of the wave. It is the time taken by the wave to complete one cycle.
The relation between the time period and the frequency is given by :
T = 1/f
Where
f is frequency of the wave
Hence, the correct option is (a) "period".
Which one is it? Help ASAP
Answer:
extreme heat, because no physical damage can demagnetize a magnet
Explanation:
Answer:
the 3rd one
Explanation:
Suppose that white light strikes a flat piece of flint glass in air, coming in at an angle of 60 degrees to the surface (30 degrees from the normal or perpendicular). The index of refraction of this dense glass for red light is 1.710, for green light is 1.723, and for blue light is 1.735. What is the order of colors you would see in the refracted light inside the glass as they leave the surface
Answer:
The order of the light starting from the light closest to the normal line is
Blue light, followed by green ight and then lastly red light
Explanation:
White light travels from one medium to another such as from air to glass is refracted according to Snell's law as follows
n₁·sin(θ₁) = n₂·sin(θ₂)
The given parameters of the white light are;
The angle the incident (incoming) light makes with the surface = 90°
The angle of incidence of the light, θ₁ = 30°
The index of refraction of red light for the glass, n₂ = 1.710
The index of refraction of green light for the glass, n₃ = 1.723
The index of reaction of blue light for the glass, n₄ = 1.735
The refractive index of air, n₁ = 1
The angle of refraction of the red light, θ₂ is given as follows;
1 × sin(30°) = 1.710 × sin(θ₂)
sin(θ₂) = 1 × sin(30°)/1.710
θ₂ = sin⁻¹(1 × sin(30°)/1.710) ≈ 17°
The angle of refraction (to the surface's normal line) of the red light, θ₂ ≈ 17°
The angle of refraction of the green light, θ₃ is given as follows;
1 × sin(30°) = 1.723 × sin(θ₃)
sin(θ₃) = 1 × sin(30°)/1.723
θ₃ = sin⁻¹(1 × sin(30°)/1.723) ≈ 16.869°
The angle of refraction of the green light, θ₃ ≈ 16.869°
The angle of refraction of the green light, θ₄ is given as follows;
1 × sin(30°) = 1.723 × sin(θ₄)
sin(θ₄) = 1 × sin(30°)/1.735
θ₄ = sin⁻¹(1 × sin(30°)/1.735) ≈ 16.749°
The angle of refraction of the green light, θ₄ ≈ 16.749°
The order of colors we see as the in the refracted light inside the glass as the light leave the surface are;
The red light, with an angle of refraction of approximately 17° will be furthest from the normal
The green light which has an angle of refraction of 16.869° will follow and will be intermediate between the red and the blue light
The blue light which has an angle of refraction of 16.749° will follow next and it will be closest to the normal
The order of the light from the normal line will be blue, followed by green and then red light
If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.
My Response:
If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.
Sample Response:
If the speed of an object increases, then its kinetic energy will increase proportionally because speed and kinetic energy have a linear relationship when graphed.
Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water
at 6◦ C. How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the
specific heat is 4190 J/kg · K.Immersive Reader
Answer:
7.55 g
Explanation:
Using the relation :
Δt = temperature change = (6° - 0°) = 6°
Q = quantity of heat
C = specific heat capacity = 4190 j/kg/k
1000 J = 1kJ
333 KJ = 333000 j
The quantity of ice that will melt ;
= 0.419 * 6 * 100 / 333000
= 2514000 / 333000
= 7.549 g
The mass of ice that will melt :
2.514 / 0.333
= 7.549 g
A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating over one period of the waveform. Hint: the equation for a square wave will be a piecewise function and it will be convenient to start the integration where the voltage changes; for example in this problem we could define that during the first half of the period the voltage is 0 V and for the second half of the period the voltage is 4 V
Answer:
V_{average} = [tex]\frac{1}{2} V_o[/tex] , V_{average} = 2 V
Explanation:
he average or effective voltage of a wave is the value of the wave in a period
V_average = ∫ V dt
in this case the given volage is a square wave that can be described by the function
V (t) = [tex]\left \{ {{V=V_o \ \ \ t< \tau /2} \atop {V=0 \ \ \ \ t> \tau /2 } } \right.[/tex]
to substitute in the equation let us separate the into two pairs
V_average = [tex]\int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt[/tex]
V_average = [tex]V_o \ \int\limits^{1/2}_0 {} \, dt[/tex]
V_{average} = [tex]\frac{1}{2} V_o[/tex]
we evaluate V₀ = 4 V
V_{average} = 4 / 2)
V_{average} = 2 V
How much heat is needed to boil 5.30 kg of water at its boiling point?
Use Q = mass x latent heat of vaporization.
A. 1760 kJ B. 22.2 kJ C. 530 kJ D. 12,000kJ
Answer:
Required heat Q = 11,978 KJ
Explanation:
Given:
Mass = 5.3 kg
Latent heat of vaporization of water = 2,260 KJ / KG
Find:
Required heat Q
Computation:
Required heat Q = Mass x Latent heat of vaporization of water
Required heat Q = 5.3 x 2260
Required heat Q = 11,978 KJ
Required heat Q = 12,000 KJ (Approx.)
A bicycle wheel has a diameter of 63.0 cm and a mass of 1.75 kg. Assume that the wheel is a hoop with all of the mass concentrated on the outside radius. The bicycle is placed on a stationary stand and a resistive force of 121 N is applied tangent to the rim of the tire. (a) What force must be applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2
Answer:
F2 = 834 N
Explanation:
We are given the following for the bicycle;
Diameter; d1 = 63 cm = 0.63 m
Mass; m = 1.75 kg
Resistive force; F1 = 121 N
For the sprocket, we are given;
Diameter; d2 = 8.96 cm = 0.0896 m
Radius; r2 = 0.0896/2 = 0.0448 m
Radial acceleration; α = 4.4 rad/s²
Now moment of inertia of the wheel which is assumed to be a hoop is given by; I = m(r1)²
Where r1 = (d1)/2 = 0.63/2
r1 = 0.315 m
Thus, I = 1.75 × 0.315²
I = 0.1736 Kg.m²
The torque is given by the relation;
I•α = F1•r1 - F2•r2
Where F2 is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².
Thus;
0.1736 × 4.4 = (121 × 0.315) - (0.0448F2)
>> 0.76384 = 38.115 - (0.0448F2)
>> 0.0448F2 = 38.115 - 0.76384
>> F2 = (38.115 - 0.76384)/0.0448
>> F2 = 833.73 N
Approximately; F2 = 834 N
The force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N
What is force?
Force is an external agent applied on any object to displace it from its position. Force is a vector quantity, so with magnitude it also requires direction. Direction is necessary to examine the effect of the force and to find the equilibrium of the force.
We are given the following for the bicycle;
Diameter; d1 = 63 cm = 0.63 m
Mass; m = 1.75 kg
Resistive force; F1 = 121 N
For the sprocket, we are given;
Diameter; d2 = 8.96 cm = 0.0896 m
Radius; r2 = 0.0896/2 = 0.0448 m
Radial acceleration; α = 4.4 rad/s²
Now the moment of inertia of the wheel which is assumed to be a hoop is given by;
[tex]I=mr_1^2[/tex]
Where
r1 = 0.315 m
I = 1.75 × 0.315²
I = 0.1736 Kg.m²
The torque is given by the relation;
[tex]I\alpha=F_1\times r_1-F_2\times r_2[/tex]
Where [tex]F_2[/tex] is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².
0.1736 × 4.4 = (121 × 0.315) - (0.0448[tex]F_2[/tex])
0.76384 = 38.115 - (0.0448[tex]F_2[/tex])
[tex]F_2= \dfrac{38.115-0.7638}{0.0448}[/tex]
[tex]F_2=833.73\ N[/tex]
Approximately; F2 = 834 N
Thus the force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N
To know more about Force follow
https://brainly.com/question/25239010
Fossil clues are one of the _____________ clues that support the theory of continental drift.
A. crust B. resource C. climate D. rock
Answer:
a
Explanation:
I think don't get mad if I'm wrong
Part D Here is one last question as a final check on your understanding of your work for this problem, looking at this problem as an example of the Conservation of Energy. The action in this problem begins at location A , with the block resting against the uncompressed spring. The action ends at location B, with the block moving up the ramp at a measured speed of 7.35 m/s . From A to B, what has been the work done by non-conservative forces, and what has been the change in the mechanical energy of the block-Earth system (the ramp is a part of the Earth)
Answer:
The answer is "39.95 J".
Explanation:
Please find the complete question in the attached file.
[tex]\to W_{AC}=(\mu \ m \ g \ \cos \theta ) d[/tex]
[tex]=(0.45 \times 1.60 \times 9.8 \times \cos 26^{\circ}) 6.30 \\\\=(7.056 \times \cos 26^{\circ}) 6.30 \\\\=6.34189079\times 6.30\\\\=39.95 \ J\\\\[/tex]
[tex]\therefore \\\\\bold{\Delta E =39.95 \ J}[/tex]
HELP PLEASE DUE IN 3 MINUTES
Answer:
tectonic plate movement
Explanation:
plz help me with my career!!!
part one...
Answer:
#1 Yes
Explanation: #1: The rest of them are used mainley by farmers, and crops are used by common citizens in the world.
Question 1: Crops.
Question 2: Diagnostic Services.
Question 3: A cable company needs to lay new fiber optic cable to reach its customers across a large lake.
Question 4: A bachelor's degree in energy research.
Question 5: Environmental Resources.
If any of these answers are incorrect, please tell me, so I can fix my mistake. Thank you.
1) A man leans against the wall and...
a) The man's shoulder pushes against the wall
b) The wall pushes against the man
c) Bricks in the wall push against each other
d) The ground pushes against the man, supporting him.
Answer:
I thinks its a, but its really about gravity im not sure
Explanation:
:)
In an effort to be the star of the half-time show, the majorette twirls a highly unusual baton made up of four mases fastened to the ends of light rods. Each rod is 1.0 m lone. Find the moment of inertia of the system about an axis perpendicular to the page and passing through the point where the rods cross.
Answer:
"0.25 kg-m²" is the appropriate answer.
Explanation:
The diagram of the question is missing. Find the attachment of the diagram below.
According to the diagram, the values are:
m₁ = 0.2
m₂ = 0.3
m₃ = 0.3
m₄ = 0.2
d₁ = d₂ = d₃ = d₄ = 0.5 m
As we know,
The moment of inertia is:
⇒ [tex]I=\Sigma M_id_i^2[/tex]
then,
⇒ [tex]I=m_1d_1^2+m_2d_2^2+m_3d_3^2+m_4d_4^2[/tex]
⇒ [tex]=d^2(m_1+m_2+m_3+m_4)[/tex]
On substituting the values, we get
⇒ [tex]=0.5^2\times (0.2+0.3+0.3+0.2)[/tex]
⇒ [tex]=0.25\times 1[/tex]
⇒ [tex]=0.25 \ Kg-m^2[/tex]
Jim and Sally both do identical jobs. Jim works quickly while Sally works slowly. Which of the following is true?
A) Sally uses more energy.
B) Jim uses more energy.
C) Jim uses more power.
D) Sally uses more power.
Fat Albert (the TV show character) runs up the stairs on Monday. On Tuesday, he walks up the same set of stairs. Which day did he do more work?
Answer:
Tuesday bc instead of running he/she was walking bc he/she might not have as much energy
Explanation:
Aunt Jane weights 45 Newtons. What is her mass?
Answer:
10.116 Pounds/45 newtons = 10.1164024 pounds/force
Explanation:
Divide the newtons by the rate of acceleration, which will give you the mass of the object. The mass will be in kilograms, because a single newton represents the amount of force needed to move one kilogram one meter. For our example, we will divide 10 N by 2 m/s/s, which give us a mass of 5 kg
Two blocks are placed at the ends of a horizontal massless board, as in the drawing. The board is kept from rotating and rests on a support that serves as an axis of rotation. The block on the right has a mass of 5.8 kg. Determine the magnitude of the angular acceleration when the system is allowed to rotate.
Answer:
The answer is "[tex]- 0.5747\ \frac{rad}{s^2}[/tex]"
Explanation:
Let
[tex]M_L = 12\ kg\\\\M_R = 5.8\ kg[/tex]
While it is in balance, its net force mostly on a machine is zero where the board will rotate an upward torques were given by:
[tex]\to M_L \times g \times R_L - M_R \times g \times R_R = \tau[/tex]
[tex]\to 12 \times 9.8 \times 0.6 - 5.8 \times 9.8 \times 1.4 = \tau[/tex]
[tex]\to \tau= 70.56-79.576\\\to \tau = -9.016[/tex]
let,
[tex]\tau = I \alpha[/tex]
where
[tex]\alpha =[/tex]angular acceleration
I = moment of inertia of the system
[tex]\to I = M_L \times r \times L_2 + M_R \times r \times R_2\\\\\to I = 12 \times 0.6 \times 0.6 + 5.8 \times 1.4 \times 1.4\\\\\to I= 4.32+11.368\\\\\to I = 15.688\ kg\ m2\\\\[/tex]
Calculating the angular acceleration:
[tex]\alpha = \frac{\tau}{I}\\\\[/tex]
[tex]= \frac{-9.016}{15.688}\\\\=- 0.5747\ \frac{rad}{s^2}\\\\[/tex]
What happens to voltage if the resistance goes up
Answer:
This means that if the voltage is high the current is high, and if the voltage is low the current is low. Likewise, if we increase the resistance, the current goes down for a given voltage and if we decrease the resistance the current goes up.
Match the following:
Answer:
iron metal :chromiummachinery part :nickel or chromiumornamentation and decoration pieces :silver and goldprocessed food :tin coated iron canbridges and automobiles :zinc metaldistilled water:bad conductorAn electric field of 1.27 kV/m and a magnetic field of 0.490 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed
Answer:
v = 2591.83 m/s
Explanation:
Given that,
The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,
[tex]qE=qvB\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.27\times 10^3}{0.49}\\\\v=2591.83\ m/s[/tex]
So, the speed of the electron is 2591.83 m/s.
The power of an engine is a measure of
A) the total amount of work it can perform.
B) the rate at which it can perform work.
C) its ability to outperform a horse.
D) its volume.
Answer:
d
Explanation:
Answer:
C
Explanation:
Horsepower refers to the power an engine produces. It's calculated through the power needed to move 550 pounds one foot in one second or by the power needs to move 33,000 pounds one foot in one minute. The power is gauged by the rate it takes to do the work.
Ps:Can I be brainliest.
Have a nice day
A trough is 10 meters long, 1 meters wide, and 2 meters deep. The vertical cross-section of the trough parallel to an end is shaped like an isoceles triangle (with height 2 meters, and base, on top, of length 1 meters). The trough is full of water (density 1000kg/m3 ). Find the amount of work in joules required to empty the trough by pumping the water over the top. (Note: Use g
Answer:
The amount of work required to empty the trough by pumping the water over the top is approximately 98,000 J
Explanation:
The length of the trough = 10 meters
The width of the through = 1 meter
The depth of the trough = 2 meters
The vertical cross section of the through = An isosceles triangle
The density of water in the through = 1000 kg/m³
Let 'x' represent the width of the water at a depth
x/y = 1/2
∴x = y/2
The volume of a layer of water, dV, is given as follows;
dV = 10 × y/2 × dy = 5·y·dy
The mass of the layer of water, m = ρ × dV
∴ m = 1000 kg/m³ × 5·y·dy m³ = 5,000·y·dy kg
The work done, W = m·g·h
Where;
h = The the depth of the trough from which water is pumped
g = The acceleration due to gravity ≈ 9.8 m/s²
[tex]\therefore \, W \approx \int\limits^2_0 {5,000 \times y \times 9.8 \, dy} = \left[24,500\cdot y^2 \right]^2_0 = 98,000[/tex]
The work done by the pump to pump all the water in the trough, over the top W ≈ 98,000 J
The ballistic pendulum is a device used to measure the speed of a fast - moving projectile such as a bullet. The bullet is fired into a large block of wood suspended from some light wires. The bullet embeds in the block, and the entire system swings up to a height h. A Walther PPK, the gun used by James Bond, has an average muzzle velocity of 950 m/s. In a ballistic pendulum, how high would we expect the block to travel when shot by a Walther PPK, given the mass of a 0.32 ACP is 5 grams, a the mass of the block is 2kg
Answer:
h = [tex](\frac{m}{m+M} )^2 \ \frac{v_o^2}{2g}[/tex]
Explanation:
To solve this problem, let's work in parts, let's start with the conservation of the moment, for this we define a system formed by the block and the bullet, in such a way that the forces during the collision have been internal and the moment is conserved.
initial instant. Before the crash
p₀ = m v₀
final instant. Right after the crash, but before the pendulum started to climb
m_f = (m + M) v
the moment is preserved
p₀ = p_f
m v₀ = (m + M) v
v = [tex]\frac{m}{m+M} \ v_o[/tex]
Now we work the pendulum system with embedded block, we use the concept of conservation of energy
starting point. Lower
Em₀ = K = ½ (m + M) v²
final point. higher, when it stops
Em_f = U = (m + M) g h
as there is no friction, energy is conserved
Em₀ = Em_f
½ (m + M) v² = (m + M) g h
h = [tex]\frac{v^2}{2g}[/tex]
we substitute the speed value of the block plus bullet set
h = [tex]( \frac{m}{ m+M} \ v_o )^2 \ \frac{1}{2g}[/tex]
h = [tex](\frac{m}{m+M} )^2 \ \frac{v_o^2}{2g}[/tex]
What are the units of work?
What is an electric current?
a
a potential difference
b
a piece of wire
c
A flow of charge within a circuit
d
A light bulb
What is an electric current?
a
a potential difference
b
a piece of wire
c
A flow of charge within a circuit
d
A light bulb
Answer:
c
Explanation:
mark brainleyest plz if right
To understand the relationship between the force and the potential energy changes associated with that force and to be able to calculate the changes in potential energy as definite integrals. Imagine that a conservative force field is defined in a certain region of space. Does this sound too abstract
Answer:
This does not sound too abstract
Explanation:
An example of an Imaginative conservative force field defined in terms of a certain region of space is : A gravitational field and it can be expressed as
[tex]Fx = - \frac{dU_{x} }{dx}[/tex] and this is because the potential energy in a gravitational field is determined only by the initial and final position of the objects found with the Gravitational field
To determine the change in potential energy ΔU we will integrate the above equation
hence : ΔU = [tex]\int\limits^2_1 {F} \, ds[/tex]
Hence this does not sound too abstract