A general rule that the two protons of a CH2 group will be chemically equivalent if there are no chirality centers in the compound. An example of an exception is 3-bromopentane. This compound does not possess a chirality center. Nevertheless, the two highlighted protons are not chemically equivalent. Write down its explaination.

Answer:

C

Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor.

Answer:

nice

Explanation:

how is it

Answer: Frequency

Explanation: Without a doubt my answer is Frequency, none of the other options have nothing to do with sound waves so Frequency is my best bet.

Answer:

The given equation [tex]Al(OH)_3[/tex] →[tex]Al_2O_3+H_2O[/tex] is the type of decomposition reaction.

Explanation:

DECOMPOSITION REACTION-: A decomposition reaction occurs when a single compound decomposes into two or more elements or new compounds. These reactions take place when energy is supplied in the form of heat, electricity, or light, which allows the material to break down into simpler substances.

The most common form of decomposition reaction is -

      [tex]AB[/tex] → [tex]A+B[/tex]

TYPES OF DECOMPOSITION REACTION IS -

    Example- As calcium carbonate (limestone or chalk) is heated, it breaks down into calcium oxide and carbon dioxide. The following is the chemical reaction:

                [tex]CaCO_3[/tex] →[tex]CaO+CO_2[/tex]

      Example -: When electricity is passed through an aqueous solution of sodium chlorine (NaCl), sodium and chlorine are created.

                   NaCl → Na + Cl

    Example - As silver chloride is exposed to light, it decomposes into silver metal and chlorine.

              [tex]2AgCl[/tex] →[tex]2Ag+Cl_2[/tex]

Answer:

A. Ba(OH)₂ (aq) <==> Ba²⁺ (aq) + 2OH¯ (aq)

B. The molar concentration of OH¯ is 0.072 M

C. The pH of the solution is 12.86

Explanation:

A. Dissociation equation

Barium hydroxide Ba(OH)₂ dissolves in water by the following equation:

Ba(OH)₂ (aq) <==> Ba²⁺ (aq) + 2OH¯ (aq)

B. Determination of the molar concentration of OH¯.

We'll begin by calculating the number of mole in 1.5 g of Ba(OH)₂. This can be obtained as follow:

Mass of Ba(OH)₂ = 1.5 g

Molar mass of Ba(OH)₂ = 137 + 2(16 + 1)

= 137 + 2(17)

= 137 + 34

= 171 g/mol

Mole of Ba(OH)₂ =?

Mole = mass / Molar mass

Mole of Ba(OH)₂ = 1.5 / 171

Mole of Ba(OH)₂ = 0.009 mole

Next, we shall determine the molarity of Ba(OH)₂. This can be obtained as follow:

Mole of Ba(OH)₂ = 0.009 mole

Volume of solution = 0.250 L

Molarity of Ba(OH)₂ =?

Molarity = mole / Volume

Molarity of Ba(OH)₂ = 0.009 / 0.250

Molarity of Ba(OH)₂ = 0.036 M

Finally, we shall determine the molar concentration of OH¯.this can be obtained as follow:

Ba(OH)₂ (aq) <==> Ba²⁺ (aq) + 2OH¯ (aq)

From the balanced equation above,

1 mole of Ba(OH)₂ produced 2 moles OH¯.

Therefore, 0.036 M Ba(OH)₂ will produce = 0.036 × 2 = 0.072 M OH¯.

Therefore, the molar concentration of OH¯ is 0.072 M

C. Determination of the pH.

We'll begin by calculating the pOH of the solution. This can be obtained as follow:

Concentration of OH¯, [OH¯] = 0.072 M

pOH =?

pOH = –Log [OH¯]

pOH = –Log 0.072

pOH = 1.14

Finally, we shall determine the pH. This can be obtained as follow:

pOH = 1.14

pH =?

pH + pOH = 14

pH + 1.14 = 14

Collect like terms

pH = 14 – 1.14

pH = 12.86

Answer:

D.  The reaction described by curve B is occurring with a catalyst.

Explanation:

The peak in the curve is the activation energy.  According to this graph, the activation energy was lowered.  A catalyst is what you can use to lower the activation energy.

The most likely accounts for the difference between curve A and curve B on the energy diagram is the reaction described by curve B is occurring with a catalyst,  therefore  option (d) is correct.

A catalyst is a chemical substance which alters the rate of a reaction without itself undergoing any permanent chemical change.

A catalyst does not initiate a chemical reaction. A catalyst does not be consumed in the reaction.

Catalysts tend to react with reactants to form intermediates and at the same time facilitate the production of the final reaction product. After the whole process, a catalyst can regenerate.

Catalysts encourage molecules to react and make the whole reaction process easier and efficient.

The most likely accounts for the difference between curve A and curve B on the energy diagram is the reaction described by curve B is occurring with a catalyst,  ,hence option (d) is correct.

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0.017 moles PbNO₃

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 4.5 g PbNO₃

[Solve] moles PbNO₃

Step 2: Identify Conversions

[PT] Molar Mass of Pb - 207.2 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of PbNO₃ - 207.2 + 14.01 + 3(16.00) = 269.21 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

0.016716 moles PbNO₃ ≈ 0.017 moles PbNO₃

Answer:

Nose

Explanation:

Because every time I touch it's nose, it will hide itself into the shell faster than other places

Hi!the main weakness of the tortoise is it's shell.The most shell of tortoise are so hard that most animals can't even make a scratch on it But flip one over and getting up will be a huge problem. They can suffer from dehydration or get picked off by predators. And even though reptiles are sun loving, they still can't regulate their body temperature and this could lead to over heating and death.

Answer:

Lithium shows anomalous behavior due to its small size. The polarizing power of lithium ion is highest of all the alkali metal ion . Because of small size, Lithium is very hard, less reactive as compare to other alkali metals like sodium and potassium.

Hope this helps:)

Answer:

I would say c

Explanation:

A chocalate chip cookie is a combination of both the dough and the chocalate chips seperately physically combined so it cannot be a pure substances (as pure substances are one type of substance only, such as just Methane). It is also homogeneous because to be homogeneous, you have to be uniform throughout and a chocalate chip cookie has an uneven placing of chocalate chip cookies.

The category in which a chocolate chip cookie can be included is a heterogenous mixture. Because it contains different component which are in different phases.

Mixtures are combination of two or more individual components. They can be mixed by physically or can be reacted together chemically. The components of a mixture can be separated using techniques based on their physical properties.

The mixtures in which all components are mixed uniformly and form a single phase is called a homogenous mixture. Mixtures with different phases and random distribution of components are called heterogenous mixtures.

A chocolate chip cookie is contains solid substances which are non-uniformly mixed together like chocolate chips in between solid cookie. Hence, it is heterogenous mixture. Thus, option c is correct.

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Answer:

7.2 mol * (6.02*10^23)= 4.3*10^24 atoms

Explanation:

The number of atoms in one mole of chlorine contains 6.022 × 10²³ . Therefore the number of Cl atoms in 7.2 moles is 4.3 × 10²⁴.

One mole of every substance contains 6.022 × 10²³ atoms. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.

Chlorine is 17th element in periodic table. Cl is a non-metal with high electronegativity. The atomic mass of Cl is 35.5 g. Thus, 35.5 g contains Avogadro number of Cl atoms.

One mole of Cl contains  6.022 × 10²³  atoms. Tus, number of atoms in 7.2 mol is Avogadro number times the number of moles.

no.of atoms =  6.022 × 10²³  × 7.2 =  4.3 × 10²⁴ atoms.

Therefore, 7.2 moles of Cl contains 4.3 × 10²⁴ atoms.

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Answer:

True

Explanation:

Answer:

There are 6 atoms of oxygen

Explanation:

The total oxygen used here is represented as molecule. One molecule of oxygen as two atoms.

In this chemical equation, total three oxygen molecule reacts with the iron.

Hence, total number of atoms in 3 molecules of oxygen with two oxygen per molecule = [tex]3 * 2 = 6[/tex]

There are 6 atoms of oxygen

Answer:

158.35 K

Explanation:

Using the general gas law

P₁V₁/T₁ = P₂V₂/T₂ where P₁ = 150.4 kPa, V₁ = 12.2 L, T₁ = 22.7 °C = 273 + 22.7 = 295.7 K, P₂ = 101.3 kPa, V₂ = 9.7 L and T₂ = unknown.

Making T₂ subject of the formula, we have

T₂ = P₂V₂T₁/P₁V₁

Substituting the values of the variables into the equation, we have

T₂ = P₂V₂T₁/P₁V₁

T₂ = 101.3 kPa × 9.7 L × 295.7 K/150.4 kPa × 12.2 L

T₂ = 290,557.777 K/1,834.88

T₂ = 158.35 K

Hey there! :

Molar mass:

Al = 26.9815 g/mol

AlCl₃ = 133.3405 g/mol

Reaction stochemistry ,calculates the mass of AlCl3 produced

2 Al + 3 Cl₂ =  2 AlCl₃

2 * 26.9815 g Al ---------------------  2 *  133.3405 g AlCl₃

8.82 g Al -------------------------------  ( mass of AlC₃ )

mass of AlCl₃  =  ( 8.82 * 2 * 133.3405 ) /  ( 2 * 26.9815 )

mass of AlCl₃ = 2352.12642 / 53.963

mass of AlCl₃ = 43.58 g of AlCl₃

Hope this helps!

Answer:

2

Explanation:

75.0 g of ammonium sulfate

Answer:

b. in the middle

Explanation:

your answer choice is correct!

I always was bad at science

Answer:

Dry friction. Dry friction resists relative lateral motion of two solid surfaces in contact. The two regimes of dry friction are 'static friction' ("stiction") between non-moving surfaces, and kinetic friction (sometimes called sliding friction or dynamic friction) between moving surfaces.

Answer:

the action or process of adapting or being adapted.

Answer: Adaptation is the physical or behavioral characteristic of an organism that helps an organism to survive better in the surrounding environment. Living things are adapted to the habitat they live in. This is because they have special features that help them to survive.

Explanation: Hope this helped :)

Answer:

coa;

Explanation:

n

Answer:

2CO2 (g) + 2H2O (l) → 2H2CO3 (aq)

Explanation:

Answer:

d.

Explanation:

It is a force that occurs when surfaces touch each other.

Answer:

a) % of excess =  236 %

b) Conversion of benzene = 0.27

c) Yield = 83.8%

d) ratio = 0.265

Explanation:

Step 1: Data given

The liquid output from the reactor contains:

65.0 wt% C6H6

32.0 wt% C6H5Cl

2.5 wt% C6H4Cl2

0.5 wt% C6H3Cl3

Molar mass of C6H6 = 78.11 g/mol

Molar mass of C6H5Cl = 112.56 g/mol

Molar mass of C6H4Cl2 = 147.01 g/mol

Molar massof C6HCl3 = 181.45 g/mol

Step 2: The equations

General form: A + B → C +D

C6H6 + Cl2 → C6H5Cl + HCl

C6H5Cl + Cl2 → C6H4Cl2 + HCl

C6H4Cl2 + HCl → C6H3Cl3 + HCl

Step 3: Calculate number of moles

Lets suppose the total mass in the reactor is 100 grams

Number of moles =mass / molar mass

Number of moles C6H6 = 65.0 grams / 78.11 g/mol

Number of moles C6H6 = 0.832 moles C6H6

Number of moles C6H5Cl = 32.0 grams / 112.56 g/mol

Number of moles C6H5Cl = 0.284 moles C6H5Cl

Number of moles C6H4Cl2 = 2.5 grams / 147.01 g/mol

Number of moles C6H4Cl2 = 0.017 moles C6H4Cl2

Number of moles C6H3Cl3 = 0.50 grams / 181.45 g/mol

Number of moles C6H3Cl3 = 0.0028 moles C6H3Cl3

Total number of moles = moles C6H6 + moles C6H5Cl + moles C6H4Cl2 + moles C6H3Cl3

Total number of moles = 0.832 + 0.284 + 0.017 + 0.0028

Total number of moles = 1.14 moles

Liquid part: C6H6 + Cl2 → C6H5Cl + HCl

n1 → n3 + n4 ( HCl)

Gas part: n2 (Cl2) + n3 → nTotal (1.14 moles)

Moles of carbon = 6*n1 = 1.14 moles of A

moles of Hydrogen = 6*n1 = 6* moles of C6H6 + 5*moles of C6H5Cl + 4* moles of C6H4Cl2 + 3* moles of C6H3Cl3 + moles of HCl ( = n4)

moles of Hydrogen =6*n1 = 6*0.832 + 5*0.284 + 4*0.017 + 3*0.0028 + n4

n4 = 0.352 moles of D (HCl)

Moles of Chlorine: 2*n2 = 1* moles of HCl + 1* moles of C6H5Cl + 2* moles of C6H4Cl2 + 3* moles C6H3Cl3

Moles of Chlorine: 2*n2 = n4 + 1*0.284 moles + 2* 0.017 moles + 3* 0.0028 moles

Moles of chlorine = 0.339 moles B

Step 4: Calculate the excess of benzene

For 1 mol benzene we need 1 mol Cl2

For 0.339 moles Cl2 we have 0.339 moles benzene

% of excess = (total amount of moles - moles of benzene) / moles of benzene

% of excess = ((1.14 - 0.339)/ 0.339) * 100 % = 236 %

Step 5: Calculate the conversion of benzene

Conversion of benzene = (1.14 moles - 0.832 moles ) / 1.14 moles

Conversion of benzene = 0.27

Step 6: the fractional yield of monochlorobenzene

Yield = ( moles of monochlorobenzene produced / total moles) * 100%

Yield = (0.284 moles / 0.339 moles ) * 100 %

Yield = 83.8%

Step 7: Calculate mass of gass

Mass of gass (Cl2) = (Moles of Cl2 * molar mass of Cl2) * 98%

Mass of gass (Cl2) = (0.339 moles*70.9 g/mol ) * 0.98

MAss of gass = 23.6 grams

Step 8: Calculate mass of liquid

Mass of liquid = total amount of moles * molar mass of C6H6

Mass of liquid = 1.14 moles * 78.11 g/mol

Mass of liquid = 89.0 grams

Step 9: Calculate the mass ratio

Mass ratio = mass gass / mass liquid

Mass ratio = 23.6 grams / 89.0 grams

Mass ratio = 0.265

In this exercise we have to use the knowledge of chemistry to calculate the compositions of benzene, in this way we find that

a) 236 %

b) 0.27

c)  83.8%

d) 0.265

First, let's punctuate the information given in the text, which can be summarized in:

Now writing the equations of the compositions given above, we can find that, general form:

[tex]A + B \rightarrow C +D[/tex]

equations of the compositions form:

from the informed data and equations we can now calculate the number of moles in each of the forms, so lets suppose the total mass in the reactor is 100 grams, in that case we have:

[tex]Number of moles = mass / molar\ mass[/tex]

The liquid part can be rewritten as:

[tex]C6H6 + Cl2 \rightarrow C6H5Cl + HCl\\n1 \rightarrow n3 + n4 ( HCl)[/tex]

The gas part can be rewritten as:

[tex]n2 (Cl2) + n3 \rightarrow 1.14 moles[/tex]

Now we can calculate the excess benzene from the equations described above, thus we find:

[tex]\% \ of \ excess = (total \ amount \ of \ moles - moles \ of \ benzene) / moles \ of \ benzene[/tex]

[tex]\% \ of \ excess = ((1.14 - 0.339)/ 0.339) * 100 = 236 \%[/tex]

Calculate the conversion of benzene, we have:

[tex]Conversion \ of \ benzene = (1.14 moles - 0.832 moles ) / 1.14 moles = 0.27[/tex]

The fractional yield of monochlorobenzene, that can be say:

[tex]Yield = ( moles\ monochlorobenzene / total\ moles) * 100\\Yield = (0.284 moles / 0.339 moles ) * 100 \\Yield = 83.8%[/tex]

Calculate mass of gass, we have:

[tex]Mass of gass (Cl2) = (Moles of Cl2 * molar mass of Cl2) * 98\\Mass of gass (Cl2) = (0.339 moles*70.9 g/mol ) * 0.98\\Mass of gass = 23.6 grams[/tex]

Calculate mass of liquid, we have that:

[tex]Mass \ of \ liquid = total \ amount \ of \ moles * molar \ mass \ of \ C6H6\\Mass \ of \ liquid = 1.14 moles * 78.11 g/mol\\Mass \ of\ liquid = 89.0 grams[/tex]

Calculate the mass ratio, we can say that:

[tex]Mass \ ratio = mass \ gass / mass \ liquid\\Mass \ ratio = 23.6 grams / 89.0 grams\\Mass \ ratio = 0.265[/tex]

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Answer:

[tex]2LiCl +Br_2 \rightarrow 2LiBr +Cl_2[/tex]

Single displacement reaction.

Explanation:

Hello!

In this case, by firstly rearranging the chemical reaction as shown below:

[tex]LiCl +Br_2 \rightarrow LiBr +Cl_2[/tex]

It is also necessary to balance it at follows:

[tex]2LiCl +Br_2 \rightarrow 2LiBr +Cl_2[/tex]

Thus, since bromine and chlorine are being exchanged as a result of the atoms rearrangement, we infer this is a single displacement reaction.

Best regards!

Answer:

[tex]2.19x10^{-19}gCs[/tex]

Explanation:

Hello there!

In this case, it is possible to know that the amount of atoms of cesium are related to moles by means of the Avogadro's number, for that reason we first compute the moles in 992 atoms of this element:

[tex]992atomsCs*\frac{1molCs}{6.022x10^{23}atomsCs}=1.65x10^{-21}molCs[/tex]

Next, given its molar mass, we can compute the mass:

[tex]1.65x10^{-21}molCs*\frac{132.91gCs}{1molCs}\\\\2.19x10^{-19}gCs[/tex]

Best regards!

Answer:

First one is a compound.  Second one is single atom and single element. third one is a molecule.

Explanation: