A gas in a sealed container has an initial pressure of 125 kPa at 25.0∘C. If the pressure is increased to 150.0 kPa, what will the new temperature be?

Answers

Answer 1

Answer:

[tex]T'=30^{\circ} C[/tex]

Explanation:

Initial pressure, P = 125 kPa

Initial temperature, T = 25.0°C

If new pressure is increased to P' = 150.0 kPa

We need to find new temperature. According to Gay-Lussac's law,

P ∝ T

or

[tex]\dfrac{P}{T}=\dfrac{P'}{T'}\\\\T'=\dfrac{P'T}{P}\\\\T'=\dfrac{150\times 25}{125}\\\\=30^{\circ} C[/tex]

So, the new temperature will be [tex]30^{\circ} C[/tex].


Related Questions

Which of the following set of properties is most likely for a liquid with large, attractive intermolecular forces?

Answers

Answer:

is it ok na I hope this answers are ok

Answer:

Answer is: C) high melting point and high boiling point.

Explanation:

HOPE IT HELPS

Your Welcome

Mark me Brianly!!!

Total enthalpy of formation of reactants and products, enthalpy of reaction. Cmon goons you’ll be rewarded handsomely

Answers

Answer:

am going to work it out

Explanation:

i am going to work it out and then tell you the answer ok

Which will require more heat, increasing the temperature of 1 mol of C8H18(l) by a certain amount or increasing the temperature of 1 mol of H2O(l) by the same amount?

Answers

Answer:

Increasing the temperature of 1 mol of C8H18(l) requires more energy

Explanation:

To answer this question, we need to define molar heat capacity that is the amount of heat required to increase in 1K the temperature of 1 mole of substance.

That means the substance with higher molar heat requires more energy to increase its temperature

Molar heat of octane, C8H18 is 255.68J/Kmol

Molar heat of water is 75.38J/Kmol

That means increasing the temperature of 1 mol of C8H18(l) requires more energy

Consider the following reaction:2 HgCl2(aq) + C2O42-(aq) 2 Cl-(aq) + 2 CO2(g) + Hg2Cl2(s)(a) The rate law for this reaction is first order in HgCl2(aq) and second order in C2O42-(aq). What is the rate law for this reaction?Rate = k [HgCl2(aq)] [C2O42-(aq)]Rate = k [HgCl2(aq)]2 [C2O42-(aq)]Rate = k [HgCl2(aq)] [C2O42-(aq)]2Rate = k [HgCl2(aq)]2 [C2O42-(aq)]2Rate = k [HgCl2(aq)] [C2O42-(aq)]3Rate = k [HgCl2(aq)]4 [C2O42-(aq)](b) If the rate constant for this reaction at a certain temperature is 0.0169, what is the reaction rate when [HgCl2(aq)] = 0.158 M and [C2O42-(aq)] = 0.202 M?Rate = M/s.(c) What is the reaction rate when the concentration of HgCl2(aq) is doubled, to 0.316 M while the concentration of C2O42-(aq) is 0.202 M?Rate = M/s

Answers

Answer:

b

Explanation:

After an afternoon party, a small cooler full of ice is dumped onto the hot ground and melts. If the cooler contained 6.60 kg of ice and the temperature of the ground was 42.5 °C, calculate the energy that is required to melt all the ice at 0 °C. The heat of fusion for water is 80.0 cal/g.

Answers

Answer:

The quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J

Explanation:

Latent heat of fusion  is the heat absorbed by a unit mass of a given solid at its melting point that completely converts the solid to a liquid at the same temperature. Its unit is Joules/kg or Joules/g.

1 calorie = 4.184 Joules

Therefore , 80.0 cal/g = 80.0 cal/g * 4.184 J/cal = 334.72 J/g

1 g = 0.001 kg; Heat of fusion in J/kg = 334.72 J/g * 1g /0.001 kg = 3.35 * 10⁵ J/kg

Quantity of heat, Q = mass * latent heat of fusion of ice

quantity of heat required = 6.60 kg * 3.35 * 10⁵ J/kg

Quantity of heat required = 2.21 * 10⁶ J

Therefore, the quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J

the position-time graph shows the motion of four people. label the lines on graph need on the motion description in this table.​

Answers

Line 1: straight horizontal line
Line 2: straight line at a slope
Line 3: exponential growth curve
Line 4: the topmost curve (the one that initially increases but then starts levels out)

Answer:

4,2,3,1

Explanation:

Heavier compounds tend to have higher boiling points. However, sulphur dichloride (Mr= 103.1 gmol-1) and sulphur hexafluoride (Mr = 146.1 g mol-1) have the boiling point of 59 °C and -50.8 °C respectively. Explain this phenomenon.​

Answers

Hm im not sure maybe c

2. If 4c-3= -31, what is the value of -2c+11

Answers

Explanation:

see the pic for the answer

Fluorine gas and water vapor react to form hydrogen fluoride gas and oxygen. What volume of oxygen would be produced by this reaction if 2.6em of were consumed? Also, be sure your answer has a unit symbol, and is rounded to the correct number of significant digits

Answers

Answer:

The reaction is 2F_2 (g) + 2H_2 O (g) rightarrow 4HF (g) + O_2 (g) 2 moles of fluorine gas (F_2) reacts with 2 moles of water vapors (H_2 O) to produce 4 moles of hy

The compound F20 has two lone pairs on the central oxygen atom. What's the structure of an F2O molecule? Is this compound polar or non-polar?
A. Trigonal planar, polar
B. Bent or angular non-polar
C. Bent or angular polar
D. Trigonal planar non-polar​

Answers

Answer:

Bent or Angular, Polar

Explanation:

I just took the test!

Answer:

C. Bent or angular polar

Explanation:

If the concentration of a reactant is tripled (all other things remain constant), and the reaction rate increases nine times, what is the reaction order with respect to the tripled reactant? Enter your answer as a number.If the concentration of a reactant is increased 1.5 times (all other things remain constant), and the reaction rate increases 2.25 times, what is the reaction order with respect to the reactant? Enter your answer as a number.If the concentration of a reactant is tripled (all other things remain constant), and the reaction rate remains constant, what is the reaction order with respect to the tripled reactant? Enter your answer as a number.When 29.0 mL of 0.220 M KIO3 is combined with 38.0 mL of H2SO3 and 50.0 mL of water, what is the resulting concentration of KIO3?

Answers

Answer:[tex] \sqrt{ \times { - {2 { \times x3 \times \frac{?}{?} }^{2} }^{2} \times \frac{?}{?} }^{2} \times \frac{?}{?} } \\ [/tex]

The reaction order for the following conditions are:

a. two

b. two

What do you mean by reaction order?

Reaction order is the number of reactants, whose concentration affects the reaction rate.

The reaction order can be determined by adding the exponents of each reactant.

The rate equation is [tex]v^0 = k[A]^x + k[B]^y[/tex]

The first-order reaction is in which the reaction is dependent on one variable concentration.

The second-order reaction is that in which the reaction is dependent upon the concentration of two variables.

Thus, the correct options are a. two, b.two.

Learn more about reaction order

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A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.60 atm. What is the partial pressure of Ar

Answers

The partial pressure of Ne is 1.06 atm. The answer is a. 1.1 atm

Answer:

0.53 atm

Explanation:

First we have to obtain the number of moles of each gas.

Number of moles of Ne = 10g/20g/mol = 0.5 moles

Number of moles of Ar = 10 g/40 g/mol = 0.25 moles

Total number of moles = 0.5 moles + 0.25 moles = 0.75 moles

Partial pressure of Ar = number of moles of Ar/Total number of moles * total pressure

Partial pressure of Ar = 0.25 moles/ 0.75 moles * 1.60 atm

Partial pressure of Ar = 0.53 atm

Calculate the final temperature (once the ice has melted) of a mixture made up initially of 70.0 mL liquid water at 28 oC and 5.0 g ice at 0.0 oC.

Answers

Answer:

21.52° C

Explanation:

From the given information:

mass of the liquid water = 70.0 mL

Initial temperature = 20°C

mass of the ice = 5.0 g

temperature of ice = 0.0°C

Using the calorimetric function:

heat lost by water = heat gained by ice.

mass of water × specific heat of water (s) × ΔT = mass of ice × specific heat of ice (s) × ΔT + n (ΔH_fusion}

⇒ 70 × 4.184 × (28 -x) = 5 × 2.108(x - 0) + [tex](\dfrac{5}{18})[/tex] × 6.01 × 10³

By solving the above equation,

x = 21.52° C

The final temperature of the mixture of water and ice is 21.5 ⁰C.

The given parameters;

initial volume of the liquid = 70 mL initial temperature of the water, = 28⁰Cmass of the ice, = 5.0 gtemperature of the ice, = 0⁰ Cspecific heat capacity of ice = 2.09 J/g ⁰Cheat of fusion of ice = 333.55 J/gspecific heat capacity of water = 4.184 J/g⁰ Cdensity of water = 1 g/ml

Let the final temperature of the mixture = t

mass of the liquid water = 1 g/ml  x 70 ml = 70 g

Apply the principle of conservation of energy to determine the final temperature of the mixture;

heat lost by water = heat gained by ice

[tex]70 \times 4.184(28 - t) = 5\times 2.09(t - 0) \ + \ 5 \times 333.55\\\\8200.64 - 292.88t = 10.45 t + 1667.75\\\\303.33t = 6532.89\\\\t = \frac{6532.89}{303.33}\\\\t = 21.5 \ ^0C[/tex]

Thus, the final temperature of the mixture of water and ice is 21.5 ⁰C.

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A 45.0 mL solution of 0.0450 M hydroxylamine is extracted with 125 mL of solvent. The distribution constant for the reaction is 5.00 and the pKa of the protonated form of hydroxylamine is 5.960. Calculate the concentration of hydroxylamine remaining in the aqueous phase at pH=4.50 and pH=6.50 .

Answers

Answer:

pH = 4.5, concentration = 0.045 M.

pH = 6.5, concentration = 0.175 M.

Explanation:

The ka for the can be calculated by using the formula below;

Ka = 10^-pka = 10^-5.960 = 1.1 × 10^-6

The concentration of hydrogen ion at pH = 4.50 can be calculated as given below;

{H^+ } = 10^-4.50 = 3.2 × 10^-5 M.

(NB=> 10 in this regards means the inverse of log).

The next step is to determine the distribution coefficient which can be calculated by using the formula below;

distribution coefficient = (partition coefficient) × ka / ka + ( concentration of Hydrogen ion,H^+).

distribution coefficient =( 5 × 1.1 × 10^-6 ) / 1.1 × 10^-6 + 3.2 × 10^-5 M. = 5.5 × 10^-6/ 3.2 = 0.00000171875

The fraction remaining from the compound = 45.0 mL / 45.0 mL + (0.00000171875 × 125).

= 0.999995.

Thus, the concentration at pH = 4.5 = 0.999995 × 0.0450 M = 0.045 M

(B). pH=6.50, thus the concentration of Hydrogen ion = 10^-6.5 = 3.2 × 10^-7 M.

distribution coefficient = (partition coefficient) × ka / ka + ( concentration of Hydrogen ion,H^+).

distribution coefficient = (5 × 1.1 × 10^-6)/ 1.1 × 10^-6 + 3.2 × 10^-7 M).

distribution coefficient = 5.5 × 10^-6/ 1.42 × 10^-6 = 3.9.

Therefore, the concentration = 3.9 × 0.0450 M = 0.175 M.

A flask containing 100 g of water is heated, and the temperature of the water increases from 21°C to 90°C. How much heat did the water absorb if the
specific heat capacity of water is 4.184 J/gºC?
A. 289 J
B. 418.4 J
C. 28,870 J
D. 10,000 J​

Answers

Answer:

28869.6J

Explanation:

Given parameters:

Mass of water in flask = 100g

Initial temperature   = 21°C

Final temperature  = 90°C

Specific heat capacity  = 4.184J/g°C

Unknown:

Amount of heat the water absorbed  = ?

Solution:

The amount f heat the water absorbed can be determined using the expression below:

 H  = m x C x Δt

m is the mass

C is the specific heat capacity of water

Δt is the change in temperature

Now insert the parameters and solve;

    H = 100 x 4.184 x (90 - 21)  = 28869.6J

Answer:

So its c

Explanation:

Write a balanced half-reaction for the oxidation of gaseous nitric oxide (NO) to aqueous nitrous acid (HNO2) in acidic aqueous solution.

Answers

Answer:

NO + H₂O → HNO₂ + 1 e- + 1 H⁺

Step-by-step explanation:

NO ⇒ oxidation number of N = +2

HNO₂ ⇒ oxidation number of N= +3

Therefore, NO has to lose 1 electron to be oxidized to HNO₂. We write the half-reaction with 1 electron (1 e-) in the products side.

NO → HNO₂ + 1 e-

Now, we have 0 electrical charges in the reactants side, and a total of -1 electrical charge in the products side. As the reaction is in acidic aqueous solution, we have to add H⁺ ions to balance the charges. We perform the balance by adding 1 H⁺ (positive charge) to neutralize the negative charge in the side of the products:

NO → HNO₂ + 1 e- + 1 H⁺

Now, we perform the mass balance. We have:

N: 1 atom in both sides

O: 1 atom in reactants side and 2 atoms in products side

H: 0 atoms in reactants side, 2 atoms in products side.

Thus, we have to add 1 H₂O molecule to the reactants side to equal the masses:

NO + H₂O → HNO₂ + 1 e- + 1 H⁺

Finally, the oxidation half-reaction is:

NO + H₂O → HNO₂ + 1 e- + 1 H⁺

determine moles of 1.5g of sodium carbonate.

Answers

Answer:

0.014mol

Explanation:

Given parameters:

Mass of Na₂CO₃  = 1.5g

Unknown:

Number of moles  = ?

Solution:

Number of moles of a compound is mathematically expressed as;

  Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

 Molar mass of  Na₂CO₃  = 2(23) + 12 + 3(16) = 106g/mol

 Number of moles = [tex]\frac{1.5}{106}[/tex]   = 0.014mol

Which is the best example and explanation that a physical change has occurred?
fireworks exploding, because energy is released as light and heat
gasoline burning, because it forms water vapor and carbon dioxide
O crushing an ice cube, because the chemical structure of the ice cube is changed
dicing potatoes, because the molecules are separated but remain the same substance

Answers

dicing potatoes, because the molecules are separated but remain the same substance

Answer:

For the people wondering, yes, dicing potatoes is the correct answer. Because a new substance has not formed.

A gaseous compound is placed in a rigid container of volume 10.0 L at temperature 300.0 K and at pressure 1.0 atm. The container is placed in an evacuated chamber and a small hole of area 2.65 mm2 is made in one of the container walls. It takes 1.00 minutes for the gas pressure in the container to fall to half of its original value. Determine the molar mass of the gas.

Answers

The answer to that amazing question is 20.54

find the percent yield,if 6.0g of Lithium chloride are actually produced and the theoretical yield is 35.4g of Lithium chloride.​

Answers

Answer:

Percent yield = 17%

Explanation:

Given data:

Actual yield of lithium chloride = 6.0 g

Theoretical yield of lithium chloride = 35.4 g

Percent yield = ?

Solution:

Formula:

Percent yield = (actual yield / theoretical yield )× 100

Now we will put the values in formula.

Percent yield = (6.0 g/ 35.4 g)× 100

Percent yield = 0.17 × 100

Percent yield = 17%

The nucleus of an atom is made up of which of the following combinations of particles?

Answers

Answer:  Atoms of different elements are found to have different number    of protons, neutrons, and electrons. To distinguish one atom from another or to classify the various atoms, a number which indicates the number of protons in the nucleus of a given atom, is assigned to the atoms of each identified element. This number is known as the atomic number of the element. The atomic numbers for some of the elements which are associated with the study of semiconductors are given in the following table.

Explanation:

Element Symbol Atomic Number

Silicon Si 14

Germanium Ge 32

Arsenic As 33

Antimony Sb 51

Indium In 49

Gallium Ga 31

Boron B 5

Answer:

[tex]\boxed {\boxed {\sf Protons \ and \ neutrons}}[/tex]

Explanation:

The atom is made up of two main parts: the nucleus and the electron cloud.

The nucleus is the center and has two subatomic particles: the protons (positive charge) and the neutrons (no/neutral charge). The nucleus as a whole has a positive charge, since the neutrons don't provide a charge.

The electron cloud surrounds the nucleus and houses the negatively charged electrons in a "cloud" of energy levels.

So, the nucleus of the atom is made up of protons and neutrons.

How many seconds are in 100 years(factor label conversion)

Answers

Answer:

0.0166

Explanation:

This conversion of 100 seconds to minutes has been calculated by multiplying 100 seconds by 0.0166 and the result is 1.6666 minutes.

I hope this helps,

even a little bit

0. 0166 is how many seconds are in the year

Sunday
Monday
What
The
Freak
Saturday

Answers

Answer
Long live Pop smoke
Explanation

How many milliliters of 6.2 M M HCl H C l solution are needed to obtain 0.18 mol m o l of HCl H C l ?

Answers

Answer:

29 mL HCl

General Formulas and Concepts:

Chem

Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define

6.2 M HCl

0.18 mol HCl

x L mol HCl

Step 2: Define conversions

1 L = 1000 mL

Step 3: Find L

6.2 M HCl = 0.18 mol HCl / x L HCl

(x L HCl)(6.2 M HCl) = 0.18 mol HCl

x L HCl = 0.18 mol HCl / 6.2 M HCl

x = 0.029032 L HCl

Step 4: Convert

[tex]0.029032 \ L \ HCl(\frac{1000 \ mL \ HCl}{1 \ L \ HCl} )[/tex] = 29.0323 mL HCl

Step 5: Check

We are given 2 sig figs. Follow sig fig rules.

29.0323 mL HCl ≈ 29 mL HCl

Answer:

29 mL HCl

Explanation:

What mass of glucose (C6H12O6) should be dissolved in 12.0 kg of water to obtain a solution with a freezing point of -5.8 ∘C?

Answers

Mass of glucose : 6.7356 kgFurther explanation  

Solution properties are the properties of a solution that don't depend on the type of solute but only on the concentration of the solute.  

Solutions from volatile substances have a higher boiling point and lower freezing points than the solvent  

For freezing point can be formulated

[tex]\tt \Delta T_f=K_f.m[/tex]  

K = molal freezing point constant  

m = molal solution  

A solution with a freezing point of -5.8 ∘C

[tex]\tt \Delta T_f=T_f~solvent-T_f~solution=0-(-5.8)=5.8[/tex]

[tex]\tt mass~of~glucose:\\\\\Delta T_f=K_f.m\\\\5.8=1.86^oC/m.\times \dfrac{mol~glucose}{12}\\\\mol~glucose=\dfrac{5.8\times 12}{1.86}=37.42[/tex]

[tex]\tt mass=mol\times MW=37.42\times 180=6735.6~g=6.7356~kg[/tex]

The density of krypton gas at 1.35 atm and 54.1°C is ________ g/L.

a. 4.21
b. 0.304
c. 8.42
d. 0.0503
e. 0.237

Answers

a.

Explanation: I saw it on another website.

4. One mole of oxygen contains 6.02 x 102 molecules. How many oxygen molecules are in

5.55 moles of oxygen gas?|

Answers

Answer:

3.34x10²⁴ molecules of oxygen

Explanation:

1 Mole of particles of any kind of gases or particles are always 6.022x10²³.

1 mole of electrons are 6.022x10²³ electrons

1 mole of any gas are 6.022x10²³ molecules

1 mole of oxygen are 6.022x10²³ molecules. Thus, 5.55 moles are:

3.34x10²⁴ molecules of oxygen

What forces cause mechanical weathering? Choose more than one
answer.

Answers

Answer:

mineral crystal growth

acid rain

carbonic acid

Answer:

Mineral crystal growth, Acid rain, Carbonic acid

12oz of water initially at 75oF is mixed with 20oz of water intiially at 140oF. What is the final temperature?

Answers

Answer:

[tex]115.625^{\circ}\text{F}[/tex]

Explanation:

[tex]m_1[/tex] = First mass of water = 12 oz

[tex]m_2[/tex] = Second mass of water = 20 oz

[tex]\Delta T_1[/tex] = Temperature difference of the solution with respect to the first mass of water = [tex](T-75)^{\circ}\text{F}[/tex]

[tex]\Delta T_2[/tex] = Temperature difference of the solution with respect to the second mass of water = [tex](T-75)^{\circ}\text{F}[/tex]

c = Specific heat of water

As heat gain and loss in the system is equal we have

[tex]m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow m_1\Delta T_1=m_2\Delta T_2\\\Rightarrow 12(T-75)=20(140-T)\\\Rightarrow 12T-900=2800-20T\\\Rightarrow 12T+20T=2800+900\\\Rightarrow 32T=3700\\\Rightarrow T=\dfrac{3700}{32}\\\Rightarrow T=115.625^{\circ}\text{F}[/tex]

The final temperature of the solution is [tex]115.625^{\circ}\text{F}[/tex].

write the chemical formula of tetraphosporus osctasulfide

Answers

Answer:

P4S8 .

the chemical formula of Tetraphosporus osctasulfide is p4S8

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