A file manager is used for all of the following except ____. A. to move files and folders B. to reorder files and folders C. to name files and folders D. to navigate between folders

Answer:

for loop statement is not complete

Answer:

A bandwidth is the maximum rate of transfer of data across a given path

Latency refers to the delay of data to travel or move between a source and destination

An example of a high bandwidth and high latency network is the Satellite Internet connectivity.

An example of a low bandwidth and latency network is the telephone system connection.

Explanation:

Solution

Bandwidth: Bandwidth determines how fast data can be transferred for example, how many bits/sec it can transport.

Latency: It refers to the delay or how long it takes for data to travel between it's source and destination.

An example of a high bandwidth and high latency network is the Satellite internet connection.

Satellite internet connection: This is responsible for the connectivity of several systems, it has a high bandwidth, since satellite are in space, due to distance it has a high latency.

So, satellite internet connection is compensated with high latency and high bandwidth.

An example of a low bandwidth and low latency network is the Telephony network.

Telephone/telephony internet connection: This connection does not have much data for transfer. it has low size audio files of which a low bandwidth range. also for both end or end users to understand and talk to each other, it has low latency.

An example of a network that exhibits high bandwidth but also high latency is Satellite internet connection.

An example of one that has both low bandwidth and low latency is telephony internet connection.

Based on the provided information, we can say that Satellite internet connection posses high bandwidth but also high latency because, the fastness of data transfer is based on the bandwidth and how the data to travel between it's source and destination is based on its latency.

We can conclude that telephony internet connection has low bandwidth and low latency because of low data transfer is required.

Learn more about bandwidth at;

https://brainly.com/question/11408596

Answer:

d. Port mirror

Explanation:

Port mirroring is a method to monitor network traffic and it is used in the Intrusion Detection Systems. It is also called Switched Port Analyzer and is used to analyse the network errors. This technique basically copies the network packets and sends or transmits these copied packed from one port to another in a network device such as a switch. This means that this technique is used to copy the network packets from one switch port and send the copy of these packets to another port where these packets are monitored. This is how it analyses the network errors and incoming traffic for irregular behavior and also this can be done without affecting the normal operation of the switch and other network processes. It is simple, inexpensive and easy to establish and use. The most important advantage of using mirrored ports is that it catches the traffic on several ports at once or can capture all of the network traffic.

Answer:

current_price = int(input("Enter the current price: "))

last_months_price = int(input("Enter the last month's price: "))

print("This house is $" + str(current_price))

print("The change is $" + str(current_price - last_months_price) + " since last month")

print("The estimated monthly mortgage is ${:.2f}".format((current_price * 0.051) / 12))

Explanation:

Ask the user to enter the current price and last month's price

Print the current price

Print the change in the price, subtract the last month's price from the current price

Print the estimated monthly mortgage, use the given formula to calculate, in required format

Answer:

A template

Explanation:

The type of construct he should create is a Template.

Template: A template is a file that serves as a beginning point for a document that is new.

When you open a template, it is pre-formatted in a way. for instance you might make use of a template in Microsoft Word that is arranged as a business letter, the template would mostly have a space for your address also a name in the left (upper)corner, which is an area for the receivers's address.

Now a little below that on the left site, is an area for the message (body) and after that, is a spot for your signature at the bottom.

Answer:

Hello your question lacks some parts attached is the complete question and the solution is written in the explanation

Explanation:

VHDL CODE::::::

VHDL Code for RAM Design:

library IEEE;

use IEEE.STD_LOGIC_1164.ALL;

use IEEE.STD_LOGIC_ARITH.ALL;

use IEEE.STD_LOGIC_UNSIGNED.ALL;

entity RAM_32Bits is

port (

Clk: in std_logic;

CS: in std_logic;

RW: in std_logic;

Address: in std_logic_vector(3 downto 0);

Data_In: in std_logic_vector(31downto 0);

Data_Out: out std_logic_vector(31downto 0);

)

end entity RAM_32Bits;

architecture RAM_32 of RAM_32Bits is

// Declare Memory Array

type RAM is array (3 downto 0) of std_logic_vector(31 downto 0);

signal mem_array: ram;

// Signal Declaration

signal read_addr: std_logic_vector (3 downto 0);

begin

process (Clk)

begin

if (Clk’event and Clk=’1’) then

if (CS=’1’ and RW=’1’) then

ram(conv_integer(Address)) <= Data_In;

endif;

if (CS=’1’ and RW=’0’) then

read_addr <= Address;

endif;

else

read_addr <= read_addr;

endif;

endprocess

Data_Out <= ram[conv_integer(read_addr)];

end architecture RAM_32;

Answer:

This is the complete question:

for i ∈ {1,2,3,4,5,6} do  beep  

for j ∈ {1,2,3,4} do  beep  

for k ∈ {1,2,3} do

    for l ∈ {1,2,3,4,5} do beep  

for m ∈ {1,2,3,4} do  beep

Explanation:

I will explain the algorithm line by line.

for i ∈ {1,2,3,4,5,6} do  beep  

This statement has a for loop and i variable that can take the values from 1 to 6. As there are 6 possible values for i so the beep statement gets executed 6 times in this for loop.

for j ∈ {1,2,3,4} do  beep  

This statement has a for loop and j variable that can take the values from 1 to 4. As there are 4 possible values for j so the beep statement gets executed 4 times in this for loop.

for k ∈ {1,2,3} do

    for l ∈ {1,2,3,4,5} do beep  

There are two statements here. The above statement has a for loop and k variable that can take the values from 1 to 3. As there are 3 possible values for k so the beep statement gets executed 3 times in this for loop. The below statement has a for loop and l variable that can take the values from 1 to 5. As there are 5 possible values for l so the beep statement gets executed 5 times in this for loop. However these statement work like an inner and outer loop where the outer loop is k and inner one is l which means 1 gets executed for each combination of values of k and l. As there are three values for k and 5 possible values for l so the combinations of values of k and l is 15 because 3 * 5 = 15. Hence the beep statement gets executed 15 times.

for m ∈ {1,2,3,4} do  beep

This statement has a for loop and m variable that can take the values from 1 to 4. As there are 4 possible values for m so the beep statement gets executed 4 times in this for loop.

Now lets take the sum of all the above computed beeps.

for i = 6 beeps

for j = 4 beeps

for k and l possible combinations = 15 beeps

for m = 4 beeps

total beeps = 6 + 4 + 15 + 4 = 29 beeps

Answer:

Hello your question lacks the required options

A) Business impact analysis plan

B) Business continuity plan

C) Disaster recovery plan

D) Recovery point plan

answer : Disaster recovery plan ( c )

Explanation:

The Disaster recovery  plan is a comprehensive creation of a system/set procedures of recovery of the IT infrastructure from potential threats of a company. especially when the interruption is caused by a disaster, accident or an emergency.

The shutting down of the sever due to overheating and not able to restart for Business is an interruption in a critical business process and the plan to direct the recovery for this single server should be the " Disaster recovery plan"

Answer:

Explanation:

Firstly, declare the necessary variables and initialize them with zero (Line 4-8). Next create a Scanner object to get user input for score (Line 10). Create a while loop by using the counter as limit (Line 12). In the while loop, prompt user to input a number between 1 - 100 (Line 13-14). Create another while loop to check the input must be between 1 - 100 or it will print invalid message and ask for user input again (Line 15-19).

Next, create an if-else statement to check if the current score is equal or above 60. If so print pass if not print fail (Line 21-27). At the same time increment the fail and pass counter.

Create another two if statement to get the current highest and lowest score and assign them to highest and lowest variables, respectively (Line 29-35).

Increment the counter by one before proceeding to the next loop to repeat the same process (Line 37).

At last, print the required output after finishing the while loop (Line 40-43).

Answer:

The overview of the given question is described in the explanation segment below.

Explanation:

The number of casualties has occurred in recent years. The following are indeed the assaults:

Arbitrary Remote Code execution attacks:

It's also a very hazardous assault. Unsanitary working on implementing that used operating system including user actions could enable an attacker to execute arbitrary functions mostly on system files.

Sites become targeted with such a DOS assault that will cause them inaccessible whether they close the account to an offender who threatens them.

Prevention: We could protect this by preventing the call from additional assessment by the user. We will disinfect input validation if we transfer values to devise calls. The input data is permitted to transfer on requests, it should have been strictly regulated although restricted to a predetermined system of principles.

Injection attack:

The object of the Injection Attack seems to be to delete vital information from the server. Throughout the list, we have such a user, a code, as well as a lot of several other essential stuff. Assailants are taking vital data and doing the wrong stuff. This can have an impact on the web site or software application interface the SQL.

Prevention: Parameterized functions require developers must specify all of the SQL code, and afterward move the question in-parameter, allowing the server to distinguish between some of the code as well as the information. By decreasing the privilege allocated to each database. White list data validation has been used to prevent abnormal information.

Zero-day attack:

It corresponds to something like a vulnerability flaw undisclosed to the user. The security vulnerability becomes infected with malware. The attackers have access to inappropriate details.

Prevention: The organizations are releasing the patch fixes the found holes. The updated plugin is also a preventive tool.

Buffer overflow attack:

This is indeed a major security threat to the accuracy of the data. This overflow happens since more information becomes set to either a specified size than even the buffer could accommodate. Adjoining program memory is compromised. During that time, the attacker was indeed running obfuscated code. Two key forms of such attack are provided below:

Prevention: Standard library features, including such strcpy, should indeed be avoided. Standard testing should be performed to identify as well as resolve overflow.

Answer:

The program doesn't use comments; See explanation section for detailed line by line explanation

Program starts here

def lettergrade(subject,score):

     print(subject+": "+str(score))

     if score >= 90 and score <= 100:

           print("Letter Grade: A")

     elif score >= 80 and score <= 89:

           print("Letter Grade: B")

     elif score >= 70 and score <= 79:

           print("Letter Grade: C")

     elif score >= 60 and score <= 69:

           print("Letter Grade: D")

     elif score >= 0 and score <= 59:

           print("Letter Grade: F")

     else:

           print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

Line by Line explanation

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

     print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed

     if score >= 90 and score <= 100:

           print("Letter Grade: A")

This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed

     elif score >= 80 and score <= 89:

           print("Letter Grade: B")

This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed

     elif score >= 70 and score <= 79:

           print("Letter Grade: C")

This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed

     elif score >= 60 and score <= 69:

           print("Letter Grade: D")

This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed

     elif score >= 0 and score <= 59:

           print("Letter Grade: F")

If input score is less than 0 or greater than 100, "Invalid Score" is printed

     else:

           print("Invalid Score")

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Answer:

The cout<<numInsects<<""; statement should be placed before numInsects = numInsects * 2;  in the while loop.

Explanation:

Your program gives the following output:

16  32  64  128

However it should give the following output:

8  16  32  64

Lets see while loop to check what you did wrong in your program:

The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100.

So the body of while loop executes. numInsects = numInsects * 2;  statement in the body multiplies the value of numInsects i.e 8 with 2 and then cout << numInsects << " ";  prints the value of numInsects  AFTER the multiplication with 2 is performed. So 8 is not printed in output but instead 16 (the result of 8*2=16) is printed as the result of first iteration.

So lets change the while loop as follows:

while (numInsects < 100) {

cout << numInsects << " ";

numInsects = numInsects * 2;

Now lets see how it works.

The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100

So the body of while loop executes. cout << numInsects << " "; first prints the value of numInsects i.e. 8. Next numInsects = numInsects * 2;  multiplies the value of numInsects i.e 8 with 2. So first 8 is printed on the output screen. Then the multiplication i.e. 8*2=16 is performed as the result of first iteration. So now value of numInsects becomes 16.

Next the while loop condition numInsects < 100 is again checked. It is true again as 16<100. Now cout << numInsects << " "; is executed which prints 16. After this, the multiplication is again performed and new value of numInsects becomes 32 at second iteration. This is how while loops continues to execute.

So this while loop stops when the value of numInsects exceeds 100.

Answer:

The programming language is not stated;

For this, I'll answer your question using c++ programming language

The program does not make use of comments (See explanation for further details)

From the sample run, the input numbers are integer; So, this program assumes that all input will be integer...

Program starts here

#include<iostream>

using namespace std;

int main()

{

cout<<"Enter six numbers: ";

int Arr[6];

for(int i = 0;i<6;i++)

{

 cin>>Arr[i];

}

bool flag = true;

for(int i = 0;i<6;i++)  

{

for(int j = i;j<6;j++)

{

 if(Arr[i]>Arr[j])

 {

  flag = false;

 }

}

}

string isAscending;

if(flag)

{

isAscending = "True";

}

else

{

isAscending = "False";

}

cout<<isAscending;

return 0;

}

Explanation:

cout<<"Enter six numbers: ";  -> This line prompts the user for input

int Arr[6]; -> The input is stored in an array; This line declares the array

The following for loop iteration is used to iterate through the array

for(int i = 0;i<6;i++)

{

 cin>>Arr[i];  -> This line accepts user input

}

bool flag = true;  -> A boolean variable is initialized to true

The following nested loop checks if numbers are in ascending order

for(int i = 0;i<6;i++)  

{

for(int j = i;j<6;j++)

{

 if(Arr[i]>Arr[j])  -> This particular if statement checks if a number is greater than the next number

 {

  flag = false;  -> If yes, the boolean variable is changed to false

 }

}

}  - > The nested loop ends here

string isAscending  = "True";  -> Here, isAscending is declared as string

if(flag)  If boolean variable flag is true; i

{

isAscending = "True";  "True" is assigned to isAscending

}

else  -> Otherwise; if boolean variable flag is no longer true; i.e if it's false

{

isAscending = "False"; -> "False" is assigned to isAscending

}

cout<<isAscending;  -> The corresponding value of isAscending is printed

The complete program that reads 6 numbers and assigns True to variable isAscending if the numbers are in ascending order is as follows;

number = 0

list1 = []

while number < 6:

    x = input("enter six number: ")

    number += 1

    list1.append(x)

if sorted(list1)==list1:

    print("True")

else:

    print("False")

The code is written in python

learn more on python here: https://brainly.com/question/26104476

Answer:

(1) Carry flag (2) Overflow flag (3) Sign or negative Flag

Explanation:

Solution

(1) The carry flag : It refers to the adding or subtracting. a two registers has a borrow or carry bit

(2) The over flow flag: This flag specify that a sign bit has been modified during subtracting or adding of operations

(3) The sign flag: This is also called a negative sign flag is a single bit status in a register that specify whether the last mathematical operations  generated a value to know if the most significant bit was set.

Answer:

I am writing the Python program. Let me know if you want the program in some other programming language.

def convertMillis(millis):  #function to convert milliseconds to hrs,mins,secs

   remaining = millis  # stores the value of millis to convert

   hrs = 3600000  # milliseconds in hour

   mins = 60000  # milliseconds in a minute

   secs = 1000  #milliseconds in a second

   hours =remaining / hrs  #value of millis input by user divided by 360000

   remaining %= hrs  #mod of remaining by 3600000

   minutes = remaining / mins  # the value of remaining divided by 60000

   remaining %= mins  #mod of remaining by 60000

   seconds = remaining / secs  

#the value left in remaining variable is divided by 1000

   remaining %= secs  #mod of remaining by 1000

   print ("%d:%d:%d" % (hours, minutes, seconds))

#displays hours mins and seconds with colons in between

def main():  #main function to get input from user and call convertMillis() to #convert the input to hours minutes and seconds

   millis=input("Enter time in milliseconds ")  #prompts user to enter time

   millis = int(millis)  #converts user input value to integer

   convertMillis(millis)   #calls function to convert input to hrs mins secs

main() #calls main() function

Explanation:

The program is well explained in the comments mentioned with each line of code. The program has two functions convertMillis(millis) which converts an input value in milliseconds to hours, minutes and seconds using the formula given in the program, and main() function that takes input value from user and calls convertMillis(millis) for the conversion of that input. The program along with its output is attached in screenshot.

Answer:

Explanation:

The solution is written in Java.

Firstly, create an integer array with size 51. The array will have 51 items with initial value 0 each (Line 5).

Create a Scanner object and get user entry the number of input (Line 6-7).

Use the input number as the limit to control the number of the for loop iteration to repeatedly get integer input from user (Line 9-13). Whenever user input an integer, use that integer, k, as the index to address the corresponding items in the array and increment it by one (LINE 11-12).

At last, create another for loop to iterate through each item in the array and check if there is any item with value above zero (this means with occurrence at least one). If so, print the item value as number of occurrence (Line 14-17).

Answer & Explanation:

To print 10 on a line and each number separated by space; you make the following modifications.

print(str(i)+" ",end=' ')

str(i)-> represents the actual number to be printed

" "-> puts a space after the number is printed

end = ' ' -> allows printing to continue on the same line

if(count == 10):

     print(' ')

The above line checks if count variable is 10;

If yes, a blank is printed which allows printing to start on a new line;

The modified code is as follows (Also, see attachment for proper indentation)

count = 0

for i in range(100,201):

     if(i%6 == 0 and i%5!=0) or (i%5 ==0 and i%6!=0):

           print(str(i)+" ",end=' ')

           count = count + 1

           if(count == 10):

                 print(' ')

                 count = 0

Answer:

Explanation:

The degree of relationship can be defined as the number of occurrences in one entity that is associated with the number of occurrences in another entity. There is the three degree of relationship: One-to-one (1:1) One-to-many (1:M)

Answer:

c. role- or function-specific.

Explanation:

The Security Configuration Wizard was  firstly used by Microsoft in its development of the Windows Server 2003 Service Pack 1. It provides guidance to network security administrators, secure domain controllers, firewall rules and reduce the attack surface on production servers.

Security Configuration Wizard saves any changes that are made as a role- or function-specific security policy which can be used as a baseline and applied to other servers in the network.

After checking the Group policy by an administrator, any changes made as a role- or function-specific security policy by the Security Configuration Wizard (SCW) is used as a baseline and can be applied either immediately or sometimes in the future to other servers in the network after testing it in a well secured environment.

Basically, the Microsoft Security Configuration Wizard (SCW) typically help administrators in running the following;

1. Role-Based Service Configuration.

2. Registry settings.

3. Network and Firewall Security settings.

4. Auditing Policy settings.

Answer:

0.119

Explanation:

50 independent fair games

Mean will be 50/2 = 25

Standard deviation of the loosing probability is :

[tex]\sqrt{50*0.5*0.5}[/tex] * 10 = 33.536

we have to loose 33 times out of 50 games.

To find the approximate probability we use z- value table.

z value =  [tex]\frac{33-25}{3.35}[/tex]

z - value = 2.2659

Looking at the z-value table we get 0.119.

Answer:

This question is answered using C++ programming language.

This program does not make use of comments; However, see explanation section for detailed line by line explanation.

The program starts here

#include <iostream>

using namespace std;

int main()

{

 double quantity,seconds;

 int minutes;

 cout<<"Quantity (mph): ";

 cin>>quantity;

 minutes = int(60/quantity);

 cout<<minutes<<" minutes and ";

 seconds = (60/quantity - int(60/quantity))*60;

 printf("%.1f", seconds);

 cout<<" seconds per mile";

 return 0;

}

Explanation:

The following line declares quantity, seconds as double datatype

 double quantity,seconds;

The following line declares minutes as integer datatype

 int minutes;

The following line prompts user for input in miles per hour

 cout<<"Quantity (mph): ";

User input is obtained using the next line

 cin>>quantity;

The next line gets the minute equivalent of user input by getting the integer division of 60 by quantity

minutes = int(60/quantity);

The next statement prints the calculated minute equivalent followed by the string " minuted and " without the quotes

 cout<<minutes<<" minutes and ";

After the minutes has been calculated; the following statement gets the remainder part; which is the seconds

 seconds = (60/quantity - int(60/quantity))*60;

The following statements rounds up seconds to 1 decimal place and prints its rounded value

 printf("%.1f", seconds);

The following statement prints "seconds per mile" without the quotes

 cout<<" seconds per mile";

Following are the program to the given question:

Program Explanation:

Program:

#include<iostream>//header file

using namespace std;

int main()//defining main method

{

   double mph,sec,min_per_mile;//defining a double variable  

int min;//defining integer variable

cout<<"Enter the speed of the treadmill in mph:";//print message

cin>>mph;//input double value

min_per_mile=(1/mph)*60;//defining a double variable that calculates minutes per mile

min=static_cast<int>(min_per_mile);//defining int variable that converts min_per_mile value into integer

sec=(min_per_mile-min)*60;//defining double variable that calculates seconds per mile value  

cout<<"A common pace is the "<<min<<" minutes and "<<sec<<" seconds per mile"<<endl;//print calculated value with message  

return 0;

}

Output:

Please find the attached file.

Learn more:

brainly.com/question/21278031

Answer:

You absolutely should throw an exception from a constructor if you're unable to create a valid object. This allows you to provide proper invariants in your class. ... Throw an exception if you're unable to initialize the object in the constructor, one example are illegal arguments.

Explanation:

Error codes cannot be used in constructors since they lack a return type. Therefore, throwing an exception is the most effective technique to indicate constructor failure. Here is a workaround if you don't have or are unwilling to use exceptions.

When an exception is thrown in a constructor, memory for the actual object has already been set aside before the constructor is even invoked. Therefore, after the exception is thrown, the compiler will immediately deallocate the memory the object was using.

There are two solutions to that: Simple and conventional approach: Use arrows. To make use of a two-stage construction, use a custom “construct” function after a default constructor that cannot throw exceptions.

Therefore, The constructor has the ability to “zombie” an object if it fails.

Learn more about Constructors here:

https://brainly.com/question/18914381

#SPJ5

Answer:

Let f be a function  

a) f(n) = n²  

b) f(n) = n/2  

c) f(n) = 0  

Explanation:  

a) f(n) = n²  

This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.  

Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:

                               f(a) = f(b) ⇒ a² = b² ⇒ a = b  

The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number.  For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.  

b) f(n) = n/2  

The above function example is an onto function because every natural number, let’s say n is a natural number that belongs to N, is the image of 2n. For example:

                               f(2n) = [2n/2] = n  

The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:  

When the value of n=1, then

                                  n/2 = [1/2] = [0.5] = 1  

When the value of n=2 then  

                                   n/2 = [2/2] = [1] = 1  

c) f(n) = 0

The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image.  The above function example is also not an onto function because every positive integer is not an image of any natural number.

All of the following are true about hacksaws, except a coarse hacksaw blade (one with fewer teeth) is better for cutting thick steel than a fine blade. The correct option is b.

A hacksaw is a saw with fine teeth that were originally and primarily used to cut metal. Typically, a bow saw is used to cut wood and is the corresponding saw.

Hacksaw is used by hand, it is a small tool for cutting pipes rods wood etc that is very common and homes and in shops. The different types of hacksaws. The main three types of hacksaws are course-grade hacksaws, medium-grade hacksaws, and fine-grade hacks. The difference is just for the quality, and the design of the blade.

Therefore, the correct option is b. Cutting thick steel is easier with a coarse hacksaw blade (one with fewer teeth) than a fine one.

To learn more about hacksaw, refer to the below link:

https://brainly.com/question/15611752

#SPJ2

Answer:

#include <iostream>

#include <string>

using namespace std;

int main()

{

   double charge = 0.00;

   int numChars = 8;

   string color = "gold";

   string woodType = "oak";

   if(numChars > 5){

       charge += (numChars - 5) * 4;

   }

   if(woodType == "oak"){

       charge += 20;

   }

   if(color == "gold"){

       charge += 15;

   }

   charge += 35;

   cout << "The charge is: $" << charge << endl;

   return 0;

}

Explanation:

Include the string library

Initialize the variables as specified

Check if the number of characters is greater than 5 or not. If it is, add 4 to the charge for each character that is greater than 5

Check if the sign is made of oak or not. If it is, add 20 to the charge

Check if the color is gold or not. If it is, add 35 to the charge

Add the minimum cost to the charge

Print the charge

In this exercise we have to use the knowledge of the C++ language to write the code, so we have to:

The code is in the attached photo.

So to make it easier the code can be found at:

#include <iostream>

#include <string>

using namespace std;

int main()

{

  double charge = 0.00;

  int numChars = 8;

  string color = "gold";

  string woodType = "oak";

  if(numChars > 5){

      charge += (numChars - 5) * 4;

  }

  if(woodType == "oak"){

      charge += 20;

  }

  if(color == "gold"){

      charge += 15;

  }

  charge += 35;

  cout << "The charge is: $" << charge << endl;

  return 0;

}

See more about C++ at brainly.com/question/26104476

Answer:

The answer is The Cache Sets (S) = 32, Tag bits (t)=24, Set index bits(s) = 5 and Block offset bits (b) = 3

Explanation:

Solution

Given Data:

Physical address = 32 bit (memory address)

Cache size = 1024 bytes

Block size = 8 bytes

Now

It is a 4 way set associative mapping, so the set size becomes 4 blocks.

Thus

Number of blocks = cache size/block size

=1024/8

=128

The number of blocks = 128

=2^7

The number of sets = No of blocks/set size

=128/4

= 32

Hence the number of sets = 32

←Block ←number→

Tag → Set number→Block offset

←32 bit→

Now, =

The block offset = Log₂ (block size)

=Log₂⁸ = Log₂^2^3 =3

Then

Set number pc nothing but set index number

Set number = Log₂ (sets) = log₂³² =5

The remaining bits are tag bits.

Thus

Tag bits = Memory -Address Bits- (Block offset bits + set number bits)

= 32 - (3+5)

=32-8

=24

So,

Tag bits = 24

Therefore

The Cache Sets = 32

Tag bits =24

Set index bits = 5

Block offset bits = 3

Note: ←32 bits→

Tag 24 → Set index  5→Block offset 3

Answer:

This function (along with the main)is written using python progrmming language.

The function is written using for loop;

This program does not make use comments (See explanation section for detailed line by line explanation)

def is_prime(num):

    if num == 1:

         print(str(num)+" is not prime")

    else:

         for i in range(2 , num):

              if num % i == 0:

                   print(str(num)+" is not prime because it can b divided by "+str(i)+" and "+str(int(num/i))+" with no remainder")

                   break;

         else:

              print(str(num) + " is prime because only 1 and "+str(num)+" divide it with no remainder")

num = int(input("Number: "))

is_prime(num)

Explanation:

This line defines the function is_prime

def is_prime(num):

The italicize line checks if the user input is 1; If yes it prints 1 is not prime

    if num == 1:

         print(str(num)+" is not prime")

If the above conditional statement is not true (i.e. if user input is greater than 1), the following is executed

    else:

The italicized checks if user input is primer (by using for loop iteration which starts from 2 and ends at the input number)

         for i in range(2 , num):

              if num % i == 0:

This line prints if the number is not a prime number and why it's not a prime number

                   print(str(num)+" is not prime because it can b divided by "+str(i)+" and "+str(int(num/i))+" with no remainder")

                   break;

If otherwise; i.e if user input is prime, the following italicized statements are executed

         else:

              print(str(num) + " is prime because only 1 and "+str(num)+" divide it with no remainder")

The function ends here

The main begins here

num = int(input("Number: "))  This line prompts user for input

is_prime(num) This line calls the defined function

sorry I was testing something

Answer:

Following are the statement is given below

if(updateDirection ==1) // check condition

{

++numUsers; // increments the value

}

else

{

--numUsers; // decrement the value

}

Explanation:

Following are the description of statement

Answer: The answer is A: MFA