a dulcimer string is supposed to vibrate at 247 hz. instead it is vibrating at 260 hz. ef picup part description answer save status a. determine the percent decrease in tension in the dulcimer string so that it vibrates at the correct frequency. (include units with answer) format check click here to check your answer 7.14 pts.100% 2% try penalty

Answers

Answer 1

The percentage decrease in the tension of the dulcimer string vibration is 99.09%.

Current vibration = 247 Hz

Required vibration = 260 Hz

We know that'

= V = vμ

= √ (T/μ)

Combining the two equations of two different vibrations'

= (T₁ / T₂) = (v₁/v₂)²

The percentage decrease is =

= [ 1 - (T₁ / T₂) ] X 100%

= [ 1 -  (v₁/v₂)² ] X 100%

= [ 1 -  (247/260)² ] X 100%

= [ 1 - 0.009025] X 100 %

= 99.09 %

The string with is supposed to vibrate at 260 Hz is vibrating at 247 Hz, thus the percentage decrease required to reduce the tension so that it vibrates at correct frequency is 99.09%.

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Related Questions

How does plasma, the fourth state of matter, differ from gas?

Answers

Answer: Plasma is made up of groups of positively and negatively charged particles but particles of a gas are mostly uncharged.

Explanation:

Because unlike ordinary gases, plasmas are made up of atoms in which some or all of the electrons have been stripped away and positively charged nuclei, called ions, roam freely.

45 hard student solutions manual starting with an initial speed of 5.00 m/s at a height of 0.300 m, a 1.50-kg ball swings downward and strikes a 4.60-kg ball that is at rest, as the drawing shows. image described by surrounding text. problem 45 (a) using the principle of conservation of mechanical energy, find the speed of the 1.50-kg ball just before impact. (b) assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision. (c) how high does each ball swing after the collision, ignoring air resistance

Answers

The speed of the 1.50-kg ball just before impact is 5.557 m/s . After assuming that the collision is elastic, the velocities of both balls just after collision is -2.873 m/s and 2.684 m/s. After ignoring the air resistance, the ball swings up to the height of 0.420 m and 0.367 m.

(a) Initial speed = u = 5 m/s

Height = h = 0.3 m

Using the principle of conservation of mechanical energy, find the speed of the 1.50-kg ball just before impact,

=  V = √ (2gh + u²)

= V = √ (2 X 9,81 X 0.3 + 5²)

= V = 5.557 m/s

(b) Initial speed = u = 5 m/s

Height = h = 0.3 m

Weight of the ball = 4.6 Kg

Velocity of 1.50 Kg ball = u'

Velocity of 4.60 Kg ball = v

Now, assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision,

= 1.50(5.557 - u) = 4.60v

= 5.557 - u = 3.14v    [let this be equation 1]

and,

= 1.50(5.55² - u²) = 4.60v²

= 5.557² - u² = 3.14v²    [let this be equation 2]

By dividing 1 and 2,

= 5.557 + u = v  [let this be equation 3]

Now, adding 1 and 3,

= 11.114 = 4.14v

Substituting this in equation 3,

= u = -2.873m/s

Thus, for 1.50 kg ball, velocity is -2.873 m/s and that of 4.60 Kg ball is 2.684 m/s.

(c) To find the height,

For a 1.50 Kg ball, h =

= h = u² / 2g

= h = -2.873² / 2 X 9.8

= h = 0.420 m

For a 4.60 Kg ball, h =

= h = u² / 2g

= h = 2.684² / 2 X 9.8

= h = 0.367 m

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calculate the displacement current id between the square plates, 7.0 cm on a side, of a capacitor if the electric field is changing at a rate of 3.0×106 v/m⋅s .

Answers

The separation between the plates is [tex]8.51*10^{-8}[/tex].

Information: The distance between the square plates is 8.6 cm, and the rate at which the electric field changes is 1.3 x 106 V/m.s.

using formula: d=eA(E/t), d=8.85*10¬¹²*(0.086)²*1.30*10⁶

d=8.51*10⁻⁸m.

What do you mean by Current?

A flow of electrical charge carriers, often electrons or atoms deficient in electrons, is referred to as current. The capital letter I is a typical sign for current. The ampere, represented by the letter A, is the common unit.

Does "current" refer to the present time?

It is current if it is true at the moment, right now, and in the present. The term current's origins all relate to its "present" sense. Things that are current are now occurring; they are a part of the present. Since past events are history and no longer news, news reporting focuses on "present affairs."

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After glycolysis, the potential energy of glucose is now in the potential energy of.

Answers

After glycolysis, the potential energy of glucose is now in the potential energy of two pyruvate molecules.

How does glycolysis works?The eleven steps of glycolysis are used to obtain energy from glucose molecules.The process of glucose metabolism begins here.Both aerobic and anaerobic circumstances can cause it.Pyruvic acid joins the citric acid cycle in aerobic conditions. It passes through an oxidative phosphorylation process, which produces ATP.Pyruvic acid changes into lactic acid in anaerobic conditions, producing a net of two ATP molecules.Two ATP molecules are used by one glucose molecule, while four ATP, two NADH, and two pyruvates are also produced. The citric acid cycle or other reactions use this pyruvate molecule as a precursor.What is glycolysis?

When glucose (a 6-carbon molecule) is broken down into two molecules of pyruvate (a 3-carbon molecule) under aerobic conditions or into lactate under anaerobic conditions, a tiny quantity of energy is also produced.

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you drive a car forwrd with a constant speed. which of the following is true about the direction of the angular velocity of the wheels, w, relative to the direction the car is moving

Answers

The correct answer from the problem above about direction of the angular velocity of the wheels, ω, relative to the direction the moving car is:

The angular velocity of the wheels, ω is used to derive how quickly the wheel can rotate in a given period.

The correct answer choice is option b.

What is meant by angular velocity?

An angular velocity can simply be defined as a vector quantity which determines how fast or the time rate a particular object revolve in relation to another point. From the context of the problem given above, the wheels of this moving object moves forward in a linear velocity below:

v = rω

Where:

v = linear velocity

r = radius

ω = angular velocity.

In conclusion, it can be therefore deduced from the explanation given above that angular velocity is the velocity along a circular path with respect to time rate.

Complete question:

You are driving a car forwrd with a constant speed. Which of the following is true about the direction of the angular velocity of the wheels, ω, relative to the direction the car is moving.

a. The greater the angular velocity of the wheels, ω, the lower the velocity of the car.

b. The angular velocity of the wheels, ω is used to derive how quickly the wheel can rotate in a given period.

c. a and b

d none of the above

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A block with a mass M compresses a spring a distance A and is then released. The block travels along a horizontal surface and encounters a rough region with friction. The block comes to a stop after traveling a distance L along the rough region. How far along the rough region would the block travel if it had a mass of 2M? 4L L/2 OL OL L/4 O 2LPrevious question

Answers

The rough region would the block travel if it had a mass of 2M is L/2. Option B.

Solution:

[tex]\frac{1}{2}[/tex] KA² =  MGL 2

Similarly, for the second case, we can write (let the distance traveled is x)

[tex]\frac{1}{2}[/tex]kA²= 2u Mgx  

Dividing the above equations we can write,

[tex]2x = L \Rightarrow x = \frac{L}{2}[/tex]

A property of a body that is a measure of inertia is usually viewed as a measure of the amount of matter contained in the body that causes it to have weight in a gravitational field. Mass is a dimensionless quantity that describes the amount of matter in a particle or object.

The mass of an object is a measure of its inertial properties or the amount of matter it contains. The weight of an object is a measure of the force exerted on it by gravity, or the force required to support it. Mass can best be understood as the amount of matter present in an object or body. Everything around us has mass.

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a 600-kg satellite is in a circular orbit about earth at a height above earth equal to earth’s mean radius. find (a) the satellite’s orbital speed,

Answers

The satellite has an orbital speed of 5.59*103m/s, a revolution lasts 3.98 hours, and a gravitational force of 1.47*103N pulls on it.

What does orbital speed mean?

The rate at which an object orbits central habitable zone of a system, which is often a large body, is known as its orbital speed. The earth orbits the sun at a speed of 108,000 km/h.

Briefing:

(a). V² = Gm/R+h

Therefore

V² = 6.667*10⁻¹¹*5.98*10²⁴/2*6.38*10⁶

V = 5.59*10³m/s

(b). V = 2π (R + h)/T

Hence

T = 2π (R + h)/V

T = 2π (R + h)/2*3.14*6.38*10⁶/5.59*10³

T = 3.98 hours

(c). F = GMm/R+h²

Therefore

F = 6.67*10⁻¹¹*5.98*10²⁴*650/2*6.38*10⁶

F = 1.47*10³N

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The complete question is-

A 650-kg satellite is in a circular orbit about Earth at a height above Earth equal to earth’s mean radius. Find (a) the satellite’s orbital speed, (b) the period of its revolution, and (c) the gravitational force acting on it.

When you view a distant rainbow, you view from each single water drop that contributes to the bow.

Answers

Answer:

Yes the light travelling gets refracted through the tiny water droplets suspended in the air.

Explanation:

There are 2 types of rainbow which includes - Primary and secondary rainbow.

A primary rainbow is a coloured bow or arc that appears on a “screen” of water drops when light from a bright light source (the Sun or Moon) falls upon them. A thick “screen” of raindrops will produce more vivid colours than a thin curtain of fewer drops.

A secondary rainbow is appears outside of a primary rainbow and develops when light entering a raindrop undergoes two internal reflections instead of just one.

Therefore whatever we see comes from each single water drop due to refraction.

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while a-2 is dribbling, player a–1 sets a rear screen closer than one normal step, on stationary b-2. as b-2 turns and, prior to placing a foot to the floor, contacts a–1. official rules this is a team-control foul on a-1. is the official correct?

Answers

Yes, the official is correct. The rules state that when a player sets a rear screen he or she must give the defender enough time to avoid contact by making a move to the side of the screener.

What is contact?
Contact
is the act of making physical contact or exchanging words with another person or object. More and more, the question is how on earth we would ever make contact with extraterrestrial life, not whether there's some other life in the universe. To establish communication, whether it be verbal, physical, or another type, is to "make contact" (the noun). It means to establish a certain communication to contact (the verb). Good luck if you're trying to get in touch with Madonna. She employs individuals whose sole responsibility it is to keep people like you from contacting her. Positive and negative contacts are present on batteries. They are the points of contact between the battery and the object receiving power.

Since B-2 had not yet placed a foot on the floor, A-1 did not give them enough time to avoid contact, therefore it was a team-control foul.

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A rock with density 2300 kg/m3 is suspended from the lower end of a light string. When the rock is in air, the tension in the string is 38.0 N. What is the tension in the string when the rock is totally immersed in a liquid with density 750 kg/m3?

Answers

The tension in the string when the rock is totally immersed in a liquid with density 750 kg/m3 is 25.6 N

How to solve for the tension

The upward buoyant force of a given object can be said to be the same as the weight that it has.

The formula that would be used to get the tension is given as

[tex]mg [1 - \frac{P_{u} }{P_{object} } ][/tex]

Where we have Pu = 750 this is the liquid density

mg = 38.0 N. This is the tension in the string

P object is the rock density = 2300

[tex]38[1-\frac{750}{2300} ][/tex]

38 * 1 - 0.3260

38 * 0.674

= 25 . 6N

The tension is 25.6N

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A proton and an electron are placed in an electric field. Which undergoes the lesser acceleration?.

Answers

Among proton and an electron which are placed in an electric field a proton will undergo lesser acceleration.

Why proton undergoes lesser acceleration?

According to Newton's 2nd law ;

F[tex]net[/tex] = ma

m is the object's mass

a is its acceleration

F[tex]net[/tex]  is the net force acting on it.

∴The electric force on a charged object is given by

F[tex]e[/tex] = Eq

Where,

F[tex]e[/tex] is the electric force

E is the electric field at the point where the object is

q is the object's charge.

Here, we assume that if the only force acting on the proton and electron is the electric force due to the electric field, that for both particles,

F[tex]net[/tex] = F[tex]e[/tex]

F[tex]e[/tex] = Eq

Eq = ma

a = Eq/m

We'll also suppose that the proton and electron are both subject to the same electric field. The charge of the proton and electron is the same (1.6 10⁻¹⁹ C). Their masses determine how differently they accelerate.

∴mass of proton = 1.67×10⁻²⁷kg

∴mass of electron = 9.11×10⁻³¹kg

Since an object's acceleration is inversely proportional to its mass, the electron will accelerate more slowly than the electron.

What is acceleration?The rate at which velocity varies with respect to time is referred to as acceleration. Since acceleration has both a magnitude and a direction, it is a vector quantity. Additionally, it is the first derivative of velocity with respect to time or the second derivative of position with respect to time.

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consider that 224.0 j of work is done on a system and 313.9 j of heat is extracted from the system. in the sense of the first law of thermodynamics, what is the value (including algebraic sign) of w, the work done by the system?

Answers

The work done by the system including the algebraic sign is  -89.9 J.

Work done on the system = W = 224.0 J

Heat extracted from the system =  Q = - 313.9 J

Using the first law of thermodynamics,

The work done by the system is = U =

= U = Q + W

= U = -313.9 + 224.0

= U = -89.9 J

The First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy. This means that heat energy cannot be created or destroyed.

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You are the same age as someone in your group, is this absolute age or relative age?

Answers

The age comparison given between my age and the age of an individual n my group is a relative age.

What are relative age and absolute age?

The relative age of an individual is the age of that individual when compared to the age of other people.

The Absolute age of an individual is the exact age of an individual given in years.

Considering the statement above:

You are the same age as someone in your group

The age given here is a comparison of the ages of two individuals without giving the exact age in years. Hence, the age given is a relative age.

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describe the relationship between the force and length and how the curves differ between a weak spring and a strong spring

Answers

The relationship between the force and length is given by  F = -kx.

What is hooke's law?

The force a spring applies to items fastened to its ends is proportional to the distance the spring travels from its equilibrium length and is always pointed in the direction of equilibrium.

The equilibrium point of the spring's free end is at x = 0, and if the x-axis of a coordinate system is selected to be parallel to the spring, then

F = -kx.

The term "spring constant" refers to the proportional constant k.

So,

K will be large if the spring is stiff or powerful, and it will be little if the spring is weak.

According to hooke's law

ΔF / Δx = k

Slope of the graph gives "spring constant"

So,

If we consider strong spring, then curve will have high slope.

and if we consider weak spring, then the curve will have low slope.

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suppose astronomers built a 140-meter telescope. how much greater would its light-collecting area be than that of the 10-meter keck telescope? express your answer using two significant figures. nothing request answer

Answers

The light collecting area of 140 m telescope is 196 times greater than 10 m telescopes.

The light collecting area is directly proportional to square of aperture:

A ∝ l²

Aperture of Keck Telescope = l₁ = 10 m

Aperture of 11 m telescope, l₂ = 140 m

Light collecting area of Keck telescope = A₁

Light collecting area of 110 m telescope = A₂

A₁ ∝ l₁²

A₂ ∝ I₂²

A₂/A₁ = I₂²/ l₁² = (140 m)²/(10 m)² = 196

Therefore, the light collecting area of 140 m telescope is 196 times greater than 10 m telescope.

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Fill in the blanks. Convert c (speed of light) from m/s to ft/min using convvel in MATLAB.c is speed of light in m/s. cfpm is speed of light in ft/min. No space for this canvas code.c=physconst(_____);cfpm=convvel( _____,

Answers

Using MATLAB's convvel function, the formula c=physconst(lightspeed); cfpm = convvel(c, "m/s," "ft/min") converts the lightspeed from m/s to ft/min. In milliseconds per second.

C represents the lightspeed. In feet per minute, the definition of cfpm is the speed of light. A fundamental physical constant, typically abbreviated as c, the speed of light in a vacuum is significant in many branches of physics. 299,792,458 metres per second (about 300,000 kph; 186,000 mph) is the exact value for the speed of light.

The MathWorks company created the proprietary multi-paradigm programming language and computer environment known as MATLAB (short for "MATrix LABoratory"). With MATLAB, you may manipulate matrices, plot functions and data, employ algorithms, build user interfaces, and interact with other programming languages.

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A glider on an air track is connected by springs to either end of the track. Both springs have the same spring constant, k, and the glider has mass M
a) Determine the frequency of the oscillation, assuming no damping, if k = 125 N/m and M = 210 g .
b) It is observed that after 55 oscillations, the amplitude of the oscillation has dropped to one-half of its initial value. Estimate the value of γγ, using x(t)=A* e^γt * cosω′t
c) How long does it take the amplitude to decrease to one-quarter of its initial value?

Answers

After 102.7 oscillations, the amplitude decreases to one-fourth of the initial value.

What do amplitude and frequency mean?

Amplitude is the separation between the wave's resting position and its maximum displacement. Frequency is the number of waves that cross a particular point in a second. Period is the length of time it takes for a wave cycle to complete.

λ = 1/51⋅0.20slog(1/2)

λ = −0.68⁻¹s

Using the previous finding, we can calculate the amplitude as a function of time to determine how long it will take before it reaches one-fourth of its initial value.

1/4=Aeλt

Solving for the time,

t = 1/λlog(1/4)

t = 20.4s

Comparing this result with the period,

t = 102.7T.

The amplitude is the largest displacement or distance that a point on a vibrating body or wave can move away from its equilibrium location. It is equal to dividing by two the length of the vibration path. The distance between a wave's resting position and its greatest displacement is known as amplitude. The frequency is the number of waves that pass through a specific location in a second. Period: the time required to complete a wave cycle to complete.

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a particular light photon carries an energy of 3.4x10^-19 j. what are the frequency, wavelength, and color of this light

Answers

51.3 x 10^14 is the frequency and the wavelength is 0.58 x 10^-7 m .

What are frequency and wavelength?

The distance between two wave crests, which also applies to troughs, is known as the wavelength. The frequency is measured in microseconds (Hz), which is the quantity of vibrations that cross a specific area in a second (Hertz).

Briefing :

Well use the Planck’s equation to find the frequency of the laser;

E = hν  where;

E = energy

h = Planck's constant = 6.626 x 10-34 J·s

ν = frequency

3.4x10^-19 j = 6.626 x 10-34v

v = 3.4x10^-19 j −19/6.626 x 10-34

v = 51.3 x 10^14

To find wavelength;

v  =c / λ where;

c = speed of light = 3 x 10^8 m/sec

51.3 x 10^14 = 3 x 10^8 / λ

λ = 3 x 10^8/51.3 x 10^14

=0.58 x 10^-7 m

Based on the wavelength of the laser which is 0.58 x 10^-7 m, the color of the laser is RED.

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a type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair. what spring constant is needed to produce a period of 0.5 s for a 0.015 kg mass?

Answers

According to the information available in the question, the force constant is 2.37N/m.

Using the relation;

T = 2π√m/k

T = period = 0.500 s

m = mass in kilograms = 0.0150-kg

k = spring constant = ?

Making k the subject of the formula;

k = 4π^2m/T^2

k = 4 × (3.142)^2 ×  0.0150/(0.500 )^2

k = 2.37N/m

What is force?

A mass object's velocity changes when it is pushed or pulled. Its SI unit is Newton and its base SI unit is [tex]kgm/s^{2}[/tex]. A device, spring balance is used to measure force.

There are two effects of force, it changes the speed and the direction.

How much force is 1 newton?

1 newton is the amount of force, is the force required to accelerate a mass of 1 kg at 1 m per second with respect to time.

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what is the angular momentum if the force is 66 n, the moment arm is 7.7 m, and the time is 1.2 seconds?

Answers

The angular momentum is 609.84 kgm²/s². if the period is 1.2 seconds, then power is 66 n, and the attached please find is 7.7 m.

What in science is a force?

The phrase "force" has a specific meaning in science. At this level, calling a force a push or perhaps a pull is entirely appropriate. A energy is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living organisms and non-living objects in the concept of a force.

Briefing:

x = m1x1 + m2x2 + m3x3 & y = m1y1 + m2y2 + m3y3/m1 + m2 + m3

x = 6*6 + 5*5 + 4(-4)/15

= 36 + 25 - 16/15

= 3

y = 6*0 + 5*5 + 4(-3)/15

25-12/15 = 13/15

(x,y) = (3, 13/15)

Let L = mvr - (i)

Also F = mu = mdv/dt

∫Fdt = m∫dv = Ft = mv + c -(ii)

When t = 0, v = 0, ⇒ c= 0

u becomes Ft = mv - (iii)

1/tu = L/Ft = r

L= Ftr

L = 66*1.2*7.7

L= 609.84 kgm²/s²

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what is the multiple of the eenjrgy needed to escape from earth gives the energy needed to escape from the moonon andn jpitier

Answers

The ratio of energy needed to escape from the surface of the moon to the energy needed to escape from the earth is 0.045

The ratio of energy needed to escape from the surface of Jupiter to energy needed to escape from the earth is  28.5

Calculation:-

Mass of earth = 5.95 *10²⁴ kg

Mass of moon = 7.36*10²² kg

Mass of Jupiter = 1.89 * 10²⁷kg

The radius of the earth = 6.37 * 10⁶ m

The radius of the moon = 1.74 *10⁶ m

The radius of Jupiter = 6.99 *10⁷

The amount of energy needed to escape from the surface is the same as its gravitational potential energy at the original position.

The formula is as follows:

K = GMm/R

where, M, and m are masses, R is the radius, G is the gravitational constant and K is energy.

DetermiNE the ratio of energy needed to escape from the surface of the moon to energy needed to escape from the earth.

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suppose that a flat loop of wire with an area of 0.050 m2 lies in a magnetic field normal to the loop. if the magnetic field changes at a uniform rate from 0.30 t to 1.5 t it induces an emf of 1.2 volts in the loop. find the time interval for the change.

Answers

The total time interval of magnetization is 6.28sec.

Given - Area is 0.050 m²

Magnetic field is perpendicular to loop.

M1=0.30 T and M2= 1.5T

electromotive force V=1.2 volt

To find the time interval for the change following concept used-

The Biot-Savart law can be used to determine the magnetic field caused by a current. To demonstrate in a qualitative way that the net magnetic field direction is along the central axis from the loop, we first take into consideration arbitrary segments on the opposite sides of the loop.For a strong uniform field to exist in the middle of the loops, Helmholtz coils typically have equal-radius loops with current flowing in the same direction. A magnetic bottle that can momentarily hold charged particles in place uses a similar application of the magnetic field distribution produced by Helmholtz coils.

[tex]T=2\pi \frac{M2-M1}{V}[/tex]

T= 2 x 3.14 x 1.20/1.2

=6.28sec

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a 2 ω resistor is connected to a battery with an emf of 6.30 v. what is the total power dissipated by the resistor?

Answers

The total power dissipated by the resistor is 6.30 V x 3.15 A = 19.845 W.

What is power?
The quantity of energy transferred as well as converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power inside the International System of Units. Power is sometimes referred to as activity in older works. A scalar quantity is power.

Power has been related to other factors; for instance, the power required to move a ground vehicle is equal to the product of the vehicle's velocity, traction force on its wheels, and aerodynamic drag. A motor's output power is calculated by multiplying its torque output by the angular velocity of its driveshaft.

The total power dissipated by the resistor is equal to the voltage of the battery multiplied by the current through the resistor.

Since the voltage of the battery is 6.30 volts, and the resistance of the resistor is 2ω, then the current through the resistor is equal to 6.30 V/2ω = 3.15 A.
Therefore, the total power dissipated by the resistor is 6.30 V x 3.15 A = 19.845 W.

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a 140 nf capacitor is used in a standard 120 volt ac circuit with a frequency of 60 hz, what is the capacitive resistance?

Answers

A one hundred forty nf capacitor is utilized in a preferred one hundred twenty volt ac circuit with a frequency of 60 hz, the capacitive resistance  = 18956 ohms.

What is a capacitor?

A capacitor is a device that stores electrical energy in an electric field by virtue of accumulating electric charges on two close surfaces insulated from each other. It is a passive electronic component with two terminals. The effect of a capacitor is known as capacitance.

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a line in the spectrum of atomic mercury has a wavelength of 254 nm. when mercury emits a photon of light at this wavelength, the frequency of this light is

Answers

The frequency of the light emitted by the mercury is 1.18×10¹⁵ Hz.

What is frequency?

Frequency is the number of complete cycle covered by a wave in one seconds.

To calculate the frequency of the light, we use the formula below.

Formula:

f = v/λ.................. Equation 1

Where:

f = Frequency of the light v = Speed of light wave λ = Wavelength of the light

From the question,

Given:

λ = 254 nm = 2.54×10⁻⁷ mv = 3×10⁸ m/s

Susbtitute these values into equation 1

f = 3×10⁸/2.54×10⁻⁷ f = 1.18×10¹⁵ Hz

Hence, the frequency of the light is 1.18×10¹⁵ Hz.

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two lamps have different resistances. (a) if the lamps are connected in parallel, which one is brighter, the lamp with greater resistance or the lamp with less resistance? (b) if the lamps are connected in series, which one is brighter? note that the brighter lamp dissipates more power.

Answers

The correct option is (D). The (a) lamp with less resistance and (b) lamp with greater resistance.

(A) The total resistance reduces in comparison to the resistance of each individual lamp when the lamps are connected in parallel. Compared to the bulb with greater resistance, the lamp with less resistance will draw more current and become brighter.

(b) Compared to the resistance of each individual lamp, the total resistance rises when the lamps are connected in series. In comparison to the bulb with less resistance, the lamp with greater resistance will draw more current and become brighter.

Hence, the correct option is (D). The (a) lamp with less resistance and (b) lamp with greater resistance.

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#Complete question is:

Two lamps have different resistances. (a) If the lamps are connected in parallel, which one is brighter, the lamp with greater resistance or the lamp with less resistance? (b) If the lamps are connected in series, which one is brighter? Note that the brighter lamp dissipates more power.

A. (a) lamp with greater resistance; (b) lamp with less resistance

B. (a) lamp with greater resistance; (b) lamp with greater resistance

C. (a) lamp with less resistance; (b) lamp with less resistance

D. a. lamp with less resistance; b. lamp with greater resistance

adisk of mass 2 kg and radius o.26 m hangs in the xy plane froma horizontal low-friction axle. the axle is o.07 m from the center of the disk. what is the frequency f of small-angle oscillations of the disk?

Answers

The frequency f of small-angle oscillations of the disk is:

f= 0.955Hz.

T = 2(π)²([tex]I_{s}[/tex] / mgh)

Given:

m = 2kg

r = 0.26m

h = 0.07m

[tex]I_{s}[/tex] = [tex]I_{c}[/tex] + md²

[tex]I_{c}[/tex] = [tex]\frac{mr^{2} }{2}[/tex] ( disk moment of Inertia)

d = h = 0.07

T = 2(π)²(  [tex]\frac{mr^{2} }{2}[/tex] + [tex]\frac{m\frac{h^{2} }{2} }{mgh}[/tex] )

T = 2(π)² ( [tex]\frac{( r^{2} + 2h^{2} )}{2g}[/tex] )

T = 1.047s

f = [tex]\frac{1}{T}[/tex]

f = 0.955Hz

period

T = 1.047s

What is the definition of a frequency simple?

Frequency is the number of waves that pass a specific area in a defined amount of time. As a result, the frequency is 2 per second if a wave travels through in half a second.

What other names does frequency go by?

Cycles per second or temporal frequency are other terms for frequency. Frequency is often represented by the Greek letter ν or the Latin letter f. (nu).

Which five types of frequency are there?

Frequency Distribution Types

frequency distribution for groups.

Frequency distribution without grouping.

frequency distribution that is cumulative.

Frequency distribution relative.

distribution of the relative cumulative frequency.

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Which describes one way that aristarchus's explanation of the movement of objects in the sky was different from other scientists' earlier explanations.

Answers

Aristarchus argued that Earth rotates on its axis.

Who was Aristarchus of Samos?

Ancient Greek astronomer and mathematician Aristarchus of Samos proposed the first known heliocentric model, according to which the Sun is at the center of the known universe and the Earth revolves once a day around the Sun.

Aristarchus believed the stars to be very distant suns, and as a result, he believed there was no detectable parallax—the movement of the stars with respect to one another as the Earth revolves around the Sun. Aristarchus determined that planets circled around the Sun after discovering that the Sun was much larger than the Earth and the other planets.

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a 1,000-mw (el) power plant working at 35% thermal efficiency 100% of the time (base load) uses coal with formula ch and a heating value of 30 mj/kg. how much co2 does this plant emit (metric tons/y)?

Answers

A 1,000-mw (el) energy plant running at 35% thermal performance 100% of the time (base load). The quantity of CO₂ emitted through the plant is 7773579.832 metric tones consistent with year.

What is thermal efficiency?

The thermal efficiency of a heat engine is the percentage of heat energy that is transformed into work. Thermal efficiency is defined as. The efficiency of even the best heat engines is low; usually below 50% and often far below. So the energy lost to the environment by heat engines is a major waste of energy resources.

The amount of CO₂ emitted by the plant is 7773579.832 metric tonnes per year.

Power of the plant = Capacity of the plant = 1000 MW

Working efficiency = 35%

Time = 100%

Heating value of coal = 30 mj/Kg

One year KWh of the plant =

= 1000 X 1000 X 365 X 24

= 31536 X 10¹² metric tonnes per year

Amount of coal =

= (31536 X 10¹² ) / (30 X 10⁶ X 0.35)

= 3003428571 Kg

Thus, the amount of CO₂ emitted by the plant =

= (3003428571 X 44) / 17

= 7773579832 Kg/ year

= 7773579.832 metric tonnes per year

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A meterstick of negligible mass is placed on a fulcrum at the 0. 4 m mark, with a 1 kg mass hung at the zero mark and a 0. 5 kg mass hung at the 1. 0 m mark. The meterstick is held horizontal and released. Immediately after release, the magnitude of the net torque on the meterstick about the fulcrum is most nearly.

Answers

After release, the magnitude of the net torque on the meterstick about the fulcrum is  nearly 1 N middot  m.

What is fulcrum?

The term fulcrum refers to the point or support on which a lever rotates, or to the center of a key activity.

Given, distance between fulcrum and mark , d = 0.4 m

mass hung with fulcrum , m = 1 kg.

Value of another mass , m = 0.5 kg.

distance kept , d' = 1.0 m.

torque= F d- F1 (d1- d)

Torque = m g - m g(d1 - d)

= 1 * 9.8 * 4 - 0.5 * 9.8(1 - 0.4)

Torque = 1N

Thus,  the magnitude of the torque on the meterstick about the fulcrum is  nearly 1 N middot  m.

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