Answer:
hope that pic helps!! let me know!!
Explanation:
or this expert answers from expert
You are stirring some soup on the stove and you notice that the metal spoon is getting hot. What type of heat transfer?
Answer:the answer is conduction
A 5.00 kg block of metal with
c = 650 J/(kg*C) at 80.0 °C comes
in contact with a 1.25 kg glass
block at 20.0 °C. They come to
equilibrium at 63.9 °C. What is the
specific heat of the glass?
Answer:
953.5 J/kg.°C
Explanation:
From the question,
Heat lost by the metal = heat gained by the glass.
cm(t₁-t₃) = c'm'(t₃-t₂)................. Equation 1
Where c = specific heat capacity of the metal, m = mass of the metal, c' = specific heat capacity of the glass, m' = mass of the glass, t₁ = initial temperature of metal, t₂ = initial temperature of glass, t₃ = Equilibrium temperature
Make c' the subject of the equation
c' = cm(t₁-t₃)/m'(t₃-t₂)................ Equation 2
Given: m = 5 kg, c = 650 J/kg.°C, m' = 1.25 kg, t₁ = 80 °C, t₂ = 20 °C, t₃ = 63.9 °C
Substitute these values into equation 2
c' = 5×650(80-63.9)/1.25(63.9-20)
c' = (5×650×16.1)/(1.25×43.9)
c' = 52325/54.875
c' = 953.5 J/kg.°C
Answer:
960 J/(kg*C)
Explanation:
i got this right in acellus trust me :D
Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis.
The magnitude of q1 is 3 times the magnitude of q2. At which point a on the axis is the
electric field zero?
NEED ANSWERS NOW
Answer:
38 cm from q1(right)
Explanation:
Given, q1 = 3q2 , r = 60cm = 0.6 m
Let that point be situated at a distance of 'x' m from q1.
Electric field must be same from both sides to be in equilibrium(where EF is 0).
=> k q1/x² = k q2/(0.6 - x)²
=> q1(0.6 - x)² = q2(x)²
=> 3q2(0.6 - x)² = q2(x)²
=> 3(0.6 - x)² = x²
=> √3(0.6 - x) = ± x
=> 0.6√3 = x(1 + √3)
=> 1.03/2.73 = x
≈ 0.38 m = 38 cm = x
A
is done by lifting the ball without prior swing of the leg.
A. Dodge
B. Kick
C. Scoop
D. Remove up
I’ll give brainless
you can swing your leg so it can't be kick, and remove up doesn't make sense and dodging it won't get you anywhere, so scooping it
what does the gravitational attraction between earth and an object depend on
Answer:
the force of gravity acting between the earth and any other object is directly proportional to the mass of the earth, directly proportional to the mass of the object, and inversely proportional to the square of the distance that separates the centers of the earth and the object.
Explanation:
The observation that energy transformations are rarely 100% efficient is seen by scientists as a violation of the Law of Conservation of Energy.
true or false ???
Answer:
l
Explanation:
Answer:
true I believe
Explanation:
What is the impulse (change in momentum) from a 2N force acting on an object for 2 seconds?
Answer:
Impulse = 4Ns
Explanation:
Given the following data;
Force = 2N
Time = 2 seconds
To find the impulse experienced by the object;
Impulse = force * time
Impulse = 2*2
Impulse = 4Ns
Therefore, the impulse experienced by the object is 4 Newton-seconds.
We've seen that stout tendons in the legs of hopping kangaroos store energy. When a kangaroo lands, much of the kinetic energy of motion is converted to elastic energy as the tendons stretch, returning to kinetic energy when the kangaroo again leaves the ground. If a hopping kangaroo increases its speed, it spends more time in the air with each bounce, but the contact time with the ground stays approximately the same. Explain why you would expect this to be the case. Drag the terms on the left to the appropriate blanks on the right to complete the sentences._ stays the same) [doesn't depend on the amplitude] [decreases) is in inverse proportion with the amplitude is in direct proportion with the amplitude [increases) When in contact with the ground it is like a spring in simple harmonic motion. When kangaroo is hopping faster, the amplitude of the oscillation _____, while the period _____ because it _____, hence the time in contact with the ground
Answer:
Follows are the soplution to this question:
Explanation:
In the given scenario it would be like a fluid in a simple harmonic in contact with the earth. Whenever a cheetah hops quicker, oscillatory amplitude rises, while the duration stays the same since it does not depend on frequency, which mostly means that time will be the same if you're in contact with the substrate.
The man rolls the cupboard at a steady speed from the lorry to the house. The friction force in the wheels is 40 N. State the force with which the man has to push.
Answer:
40N
Explanation:
Using the newton's second law of motion
\sum Fx = max
Fm - Ff = max
Fm is the applied force
Ff is the frictional force
m is the mas of the cupboard
ax is the acceleration
Since the speed from the lorry is steady, ax = 0m/s^2
Also Ff = 40N
Substitute into the formula;
Fm - 40 = m(0)
Fm - 40 = 0
Add 40 to both sides
Fm - 40 + 40 = 0 + 40
Fm = 40N
Hence the force with which the man applied to push is 40N
Extra
A stone is dropped from a balloon that is descending at a uniform rate of
12 m/s when it is 1000 m from ground.
a. Calculate the velocity and position of the stone after 10 s and the time
it takes the stone to hit the ground.
b. Solve the same problem as for the case of a balloon rising at the given
velocity
Answer:
Assume that [tex]g =9.81\; \rm m\cdot s^{-1}[/tex], and that the air resistance on the stone is negligible.
a.
Height of the stone: [tex]389.5\; \rm m[/tex] (above the ground.)
Velocity of the stone: [tex]\left(-110.5\; \rm m \cdot s^{-1}\right)[/tex] (the stone is travelling downwards.)
b.
Height of the stone: [tex]629.5\; \rm m[/tex] (above the ground.)
Velocity of the stone: [tex]\left(-86.5\; \rm m \cdot s^{-1}\right)[/tex] (the stone is travelling downwards.)
Explanation:
If air resistance on the stone is negligible, the stone would be accelerating downwards at a constant [tex]a = -g = -9.81\; \rm m \cdot s^{-2}[/tex].
Let [tex]h_0[/tex] denote the initial height of the stone (height of the stone at [tex]t = 0[/tex].)
Similarly, let [tex]v_0[/tex] denote the initial velocity of the stone.
Before the stone reaches the ground, the height [tex]h[/tex] (in meters) of the stone at time [tex]t[/tex] (in seconds) would be:
[tex]\displaystyle h(t) = -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0[/tex].
Similarly, before the stone reaches the ground, the velocity [tex]v[/tex] (in meters-per-second) of the stone at time [tex]t[/tex] (in seconds) would be:
[tex]v(t) = -g\cdot t + v_0[/tex].
In section a., [tex]h_0 = 1000\; \rm m[/tex] while [tex]v_0 = -12\; \rm m\cdot s^{-1}[/tex] (the stone is initially travelling downwards.) Evaluate both [tex]h(t)[/tex] and [tex]v(t)[/tex] for [tex]t = 10\; \rm m \cdot s^{-1}[/tex]:
[tex]\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + \left(-12\; \rm m \cdot s^{-1}\right) \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 389.5\; \rm m \end{aligned}[/tex].
Indeed, the value of [tex]h(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is greater than zero. The stone hasn't yet hit the ground, and both the representation for the height of the stone and that for the velocity of the stone are valid.
[tex]\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s - 12\; \rm m\cdot s^{-1} \\ &= -110.5\; \rm m \cdot s^{-1} \end{aligned}[/tex].
The value of [tex]v(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is negative, meaning that the stone would be travelling downwards at that time.
In section b., [tex]h_0 = 1000\; \rm m[/tex] while [tex]v_0 = 12\; \rm m\cdot s^{-1}[/tex] (the stone is initially travelling upwards.) Evaluate both [tex]h(t)[/tex] and [tex]v(t)[/tex] for [tex]t = 10\; \rm m \cdot s^{-1}[/tex]:
[tex]\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + 12\; \rm m \cdot s^{-1} \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 629.5\; \rm m \end{aligned}[/tex].
Verify that the value of [tex]h(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is indeed greater than zero.
[tex]\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s + 12\; \rm m\cdot s^{-1} \\ &= -86.5\; \rm m \cdot s^{-1} \end{aligned}[/tex].
Similarly, the value of [tex]v(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is negative because the stone would be travelling downwards at that time.
Match the symbol of each element to its name :)
Answer:
H-Hydrogen
B-Boron
O-Oxygen
Au-Gold
Co-Cobolt
He-Helium
Na-Sodium
S-Sulfur
K-Potassium
Ag-Silver
Explanation:
Normally, chemical symbols are either the first letter or the first two letters of the element.
However, there are some exceptions where they use the Latin names e.g:
Aurum-Au-Gold
Natrium-Na-Sodium
Kalium-K-Potassium
Argentum-Ag-Silver
Hope this helps :)
⦁ When a force of 6O N is applied to a mass of 30 kg, the acceleration of the mass will be:
Answer:
2m/s^2
Explanation:
Force is equal to;
mass × acceleration
therefore;
acceleration equals
force divided by mass
acceleration = 2m/s ^2
Answer:
f = 60N
m = 30kg
f= m×a
60N= 30 × a
a = 60/30
a = 2
Is monosodium an element or compound?give a reason
Answer; Sodium 2-Aminopentanedioate The chemical formula of MSG is C5H8NO4Na and its IUPAC name is sodium 2-aminopentanedioate. Since it is known to intensify meaty flavours in food, monosodium glutamate is widely used as a flavour enhancer in the food industry. This compound was first produced by the Japanese chemist Kikunae Ikeda in the year 1908.
Explanation:
1) A plane whose airspeed is 220 km/h heads due
north. It suddenly encounters a 150 km/h cross wind
blowing due east. What is the resulting velocity of
the plane with respect to the ground?
Answer:
=(220^2 +150^2)
/
put this on a square root
for you to get 266.2705391
round it to a whole number =266km/h
Explanation:
p
How does convection play a role in ocean currents?
Please help i’ll give brainlist if i can
Answer:
yellow
Explanation:
yellow
make me brain
PLZ ANSWER FOR 25 POINTS AND BRAINLIEST
Answer:
the answer is all of the above
Explanation:
brainliest please
What does the change in momentum and impulse have in common?
Answer:
Momentum is a vector quantity that has the same direction as the velocity of the object. The quantity of force multiplied by the time it is applied is called impulse. Impulse is a vector quantity that has the same direction as the force. Momentum and impulse have the same units: kg·m/s
Explanation:
Hope it helps!
If you dont mind can you please mark me as brainlest?
A student wants to design an investigation to determine if an object contains potential energy. What are some questions the student could ask to determine if the object contains potential energy?
Does the object have kinetic energy?
Does the object move when it is released from a rest position?
Does work have to be done to hold the object in place?
Does a force act on the object?
Answer:
does work have to be done to hold the object in place
Answer:
Does the object move when it is released from a rest position? and Does a force act on the object?
Explanation:
i had the same quiz today and the other 2 are wrong
Which waves have oscillations parallel to their direction of motion?
sound waves from a stereo speaker
Answer:
sound waves
Explanation:
this is because sound waves are longitudinal waves, and longitudinal waves are waves that travel parallel to the direction of the wave motion
thus it cannot be light or electromagnetic waves but only sound waves
hope this helps, please mark it
what is the fullform of SMPS ?
A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.
Answer:
A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.
Explanation:
Which best explains why a storm that affects an area in the western United States may affect an area in the eastern
United States a few days later?
The jet stream winds blow storms from east to west.
The jet stream winds blow storms from west to east.
C Cool Gulf Stream water causes storms to form in the east
D Warm Gulf Stream water causes storms to form in the west.
I really need help, pls hurry I’m timed
Please help me In this question
Answer:
50 N
Explanation:
We are given;
Force on larger piston; F2 = 5000 N
Ratio of diameter of smaller piston to larger piston = 1:10
Now, formula for force on smaller piston which we will denote with F1 is gotten from;
F1 = F2 × A1/A2
Now, A1 = π(d1)²/2
A2 = π(d2)²/2
Thus:
F1 = F2 × (π(d1)²/2)/(π(d2)²/2)
This gives;
F1 = F2 × (d1/d2)²
Plugging in the relevant values;
F1 = 5000 × (1/10)²
F1 = 50 N
The speed of light in amber is
1.94*10^8 m/s. What is the index
of refraction for amber?
(No unit)
Answer:
1.55
Explanation:
that it is the standard refractive index.
how does displacement, acceleration, time, and velocity affect motion?
Answer:
The relation between velocity and time is a simple one during uniformly accelerated, straight-line motion. The longer the acceleration, the greater the change in velocity. Change in velocity is directly proportional to time when acceleration is constant.
~Hoped this helped~
~Brainiliest?~
Answer:
We describe motion in terms of velocity and acceleration. Velocity: The rate of change of displacement of an object (displacement over elapsed time) is velocity. Velocity is a vector since it has both magnitude (called speed) and direction. ... Acceleration: The rate of change of velocity is acceleration.
Explanation:
Displacement is a vector which points from the initial position of an object to its final position. ... Instantaneous velocity, on the other hand, describes the motion of a body at one particular moment in time. Acceleration is a vector which shows the direction and magnitude of changes in velocity.
Displacement is the vector difference between the ending and starting positions of an object. Velocity is the rate at which displacement changes with time. ... The average velocity over some interval is the total displacement during that interval, divided by the time.
Hope this helps :)
The Law of Conservation of Mass states that mass can be destroyed during a chemical change.
True
False
580 nm light shines on a double slit
with d = 0.000125 m. What is the
angle of the third dark interference
minimum (m = 3)?
(Remember, nano means 10-9.)
(Unit = deg)
Explanation:
Given that,
The wavelength of light = 580 nm
Slit separation, d = 0.000125 m
We need to find the angle of the third dark interference. For the dark fringe,
[tex]d\sin\theta=(m+\dfrac{1}{2})\lambda[/tex]
Put m = 3 and other values also.
[tex]d\sin\theta=(3+\dfrac{1}{2})\lambda\\\\d\sin\theta=\dfrac{7\lambda}{2}\\\\\sin\theta=\dfrac{7\lambda}{2d}\\\\\theta=\sin^{-1}(\dfrac{7\lambda}{2d})\\\\\theta=\sin^{-1}(\dfrac{7\times 580\times 10^{-9}}{2\times 0.000125 })\\\\\theta=0.93^\circ}[/tex]
So, the angle is 0.93°.
Answer: 0.665 deg
Explanation:
m=3
lambda= 580
d (converted to nanometers)= 125000
Using the equation of angle=arcsine of m-1/2 times lambda divided by d, filled in it would be arcsine of 3-1/2 times 580 over 125000.
PLEASE PLEASE HELP AND PUT A REAL ANSWER ;-;. ALSO WILL GIVE BRAINLEST!!
High pressure systems are found in the:
troposphere
stratosphere
mesosphere
thermosphere
Answer:
Troposphere
High-pressure areas form due to downward motion through the troposphere, the atmospheric layer where weather occurs.
Two cars approaching each other , first car moves at 72 km/h ,the second car moves at 90 km/h,the first car started its siren with a frequency of 650 Hz. If the speed of the sound is 350 m/s, then what is the frequency of the sound heard by the driver of the second car from the police car?
Answer:
Because the speed of sound travels at +- 1300 km/h and the car that is approaching isn't that fast. So u first hear the sound before the car reaches u.
i hope it helps
Explanation:
A projectile is fored vertically upward with an initial velocity of 190 m/s. Find the maximum height of the projectile.
Answer:
3683.67 m
Explanation:
Formula for maximum height of projectile is given by the equation;
h = u²/2g
Where u is initial velocity and g is acceleration due to gravity
We are given u = 190 m/s
Thus;
h = 190²/9.8
h = 36100/9.8
h = 3683.67 m