A deer is running at 7.29 m/s. He hears a wolf and accelerates at 3.22 m/s/s. 2.8
seconds after hearing the wolf, how far has he travelled?

Answers

Answer 1

Answer:

V=16.306m/s

Explanation:

Use V=vi+at

So V= 7.29m/s+(3.22)(2.8s)= 16.306m/s


Related Questions

What is the wavelength of a wave?

Answers

The wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.

A 2000 Kg car going 20 m/s crashes into a wall. What is the force of the car on the wall? ​

Answers

Answer:

40,000N

Explanation:

Force = Acceleration × Mass

2000×20=40,000

state two precautions to be taken when using a density bottle​

Answers

Explanation:

(i) The density bottle must be held by the neck to avoid expansion. (ii). The outside must be wiped clean. (iii).

Answer:

The density bottle must be held by the neck to avoid expansion The outside must be wiped clean

Explanation:

hope this help

If the initial velocity of a ball is sent straight upward at 10.5m/s from the ground what will its final velocity be when it hits the ground at the end of its flight?

Answers

Answer: -10.08 m/s

Explanation:

Here we only need to analyze the vertical problem.

When the ball is in the air, the only force acting on it will be the gravitational force, this means that the acceleration of the ball, is equal to the gravitational acceleration, then:

a(t) = -9.8m/s^2

Where the negative sign is because gravity pulls the ball down.

To get the velocity equation we need to integrate over time, we get:

v(t) = (-9.8m/s^2)*t + v0

Where v0 is the initial vertical velocity, here it is v0 = 10.5 m/s

Then the velocity equation is:

v(t) =  (-9.8m/s^2)*t + 10.5 m/s

To get the position equation, we need to integrate again over time, we get:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t + p0

Where p0 is the initial position, we know that the ball is sent upward from the ground, so p0 = 0m

Then the position equation is:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

Now we need to find the value of t such that the position is equal to zero (this means that the ball hits the ground again).

Then we need to solve:

p(t) = 0 =  (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

If we divide both sides by t, we get:

0 =   (1/2)*(-9.8m/s^2)*t + (10.5 m/s)

Now we can solve it:

(1/2)*(9.8m/s^2)*t = 10.5 m/s

t = (10.5 m/s)/((1/2)*(9.8m/s^2)) = 2.14 s

This means that after 2.14 seconds, the ball will hit the ground again.

The velocity of the ball when it hits the ground is equal to:

v(2.14s) = (-9.8m/s^2)*2.14s + 10.5 m/s = -10.08 m/s

A gazelle is running at 17.46 m/s. He sees a lion and accelerates at -1.49 m/s/s,
How fast is he running 2.39 seconds later?

Answers

Answer:

V=21.0211m/s

Explanation:

Use V=vi+at

So, V=17.46m/s+(1.49m/[tex]s^{2}[/tex])(2.39s)= 21.0211m/s

Answer=21.0211m/s

Explanation v=17.46/

STUDY QUESTIONS
1. (a) You are provided with a 15 cm long steel strip,
By using a permanent bar magnet explain how
you will magnetise the steel strip​

Answers

Answer:

The blade of sharpener is made up of iron. Iron is a magnetic material because of this pencil sharpener gets attracted by the poles of a magnet although the body is made up of plastic.

PLEASE HELP!!!!!!




Is this correct?

Answers

The answer is A the wavelength of the waves do in fact change
change your awnser!! to a

PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!





Do you think that Franklin actually performed the kite experiment? Why or why not?

Answers

there’s no image ???

Answer:

He not only hypothesized that lightning and electricity were linked, but that metal objects could be used to draw lightning in order to protect homes from being hit. But Franklin didn't feel that he could get his conductor high enough into the clouds to do any good, so he never completed the experiment.

Explanation:

there ya go :)

A locomotive is pulling 19 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (with its load) is 37,000 kg. If the train is accelerating at on a level track, what is the tension in the coupling between the second and third cars? (The car nearest the locomotive is counted as the first car, and friction is negligible.)

Answers

Explanation:

The tension between cars 2 and 3 accelerates cars 3 through 17. That is a total of 15 cars.F = M*a, with M = 15*37,000 = 555*10^3 kga = 0.7 m/s^2Solve for F, in Newtons

Emma draws another diagram showing how adding energy affects this wave. How does her new diagram compare to this diagram?
A
Her diagram shows higher wavelengths.
B
Her diagram shows lower wave amplitudes.
С
Her diagram shows lower wave frequencies.
D
Her diagram shows higher wave amplitudes.

HELPPPP MEEE PLEASEEEE 55 POINTS!!!

Answers

Skansen ah w very video ne lol lay

Block A of mass 2.0 kg is released from rest at the top of a 3.6 m long plane inclined at an angle of 30o, as shown in the figure above. After sliding on the horizontal surface, block A hits and sticks to block B, which is at rest and has mass 3.0 kg. Assume friction is negligible. The speed of the blocks after the collision is most nearly

Answers

The speed of the blocks after the collision is most nearly will be Vf= 2.376 m/s.

What is collision?

Collision is defined as when two bodies of different masses move towards each other with a particular speed, then there will be three cases after the collision.

Elastic collision, in which the kinetic energy of the object remains constant.

Inelastic collision in which the kinetic energy is not conserved after the collision.

Completely elastic collision, in which the masses stick together after the collision and  move with a final speed.

It is given in the question that

Mass of body A= 2 kg

Velocity of body A= ?

Mass of body B=3 kg

Velocity of body B= 0 m/s

since the body is coming from the inclined place at an angle 30 so the height will be calculated as:

[tex]\rm Sin\theta=\dfrac{h}{H}[/tex]

Inclined plane H=3.6 m

[tex]\rm Sin30=\dfrac{h}{3.6}[/tex]

[tex]h=1.8 m[/tex]

Now the initial velocity of the object from the conservation of energy

[tex]m_Agh=\dfrac{1}{2}m_Av_A^2[/tex]

[tex]v_A=\sqrt{2gh[/tex]

[tex]v_A=\sqrt{2\times9.81\times 1.8}=5.94\ \frac{m}{s}[/tex]

Now form the collision is completely elastic so the momentum before collision will be equal to after collision.

[tex]m_Av_A+m_Bv_B=(m_A+m_B)v_f[/tex]

[tex](2\times 5.94)+(3\times0)=(2+3)v_f[/tex]

[tex]v_f=\dfrac{11.88}{5}=2.376\ \frac{m}{s}[/tex]

Thus the speed of the blocks after the collision is most nearly will be Vf= 2.376 m/s.

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The kinetic energy of an object is equal to one half Its mass multiplied by its
speed
A squared
B cubed
C to the fourth power
D to the fifth power

Answers

the answer is B cubed

what is resistance ​

Answers

Answer:

Resistance is the measure of the opposition to current flow in an electrical circuit

Resistance refers to the opposition or hindrance that a material or object offers to the flow of electric current. It is a fundamental concept in the field of electrical engineering and physics.

Resistance is measured in ohms (Ω) and is denoted by the symbol "R."

In electrical circuits, resistance is caused by various factors, including the type of material, its dimensions, and its temperature.

The primary element contributing to resistance is the collisions between electrons and atoms within the material through which the current is passing.

When an electric current flows through a conductor, such as a wire, the electrons move along the path of the conductor. However, as they do so, they encounter resistance.

This resistance causes the electrons to collide with atoms, which generates heat and dissipates energy.

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This glass of lemonade is sitting in the hot summer sun. As time passes, in which direction will heat transfer take place?



A.
ice → lemonade
B.
lemonade → air
C.
air → lemonade
D.
ice → straw
E.
ice → air

Answers

Answer:

c

Explanation:

Answer:

the answer to your question is c

Explanation:

Tell me, Is universe created due to big bang???? Plz I want a bunch of para​

Answers

Answer:

shreya Sister's answer is correct hope it's help you have a good day

PLEASE HELP ME WITH THIS ONE QUESTION
The speed of sound at an elevation of 40,000 feet, where many aircraft fly, is 295 m/s. If an airplane is flying at Mach 0.92 at this altitude, how fast is the airplane traveling in meters per second?

Answers

Answer:

The plane travels at a rate of 313 meters per second.

Explanation:

Since the speed of sound at an elevation of 40,000 feet, where many aircraft fly, is 295 m / s, if an airplane is flying at Mach 0.92 at this altitude, to determine how fast is the airplane traveling in meters per second you must perform the following calculation:

1 Mach = 1,225.04 km / h

1 km = 1,000 m

1 h = 3,600 sec

1 = 1225.04

0.92 = X

0.92 x 1225.04 = X

1,127.03 = X

(1,127.03 x 1,000) / 3,600 = X

1,127,030 / 3,600 = X

313.06 = X

Thus, the plane travels at a rate of 313 meters per second.

A 1500 kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2500 kg SUV traveling from east to west. The two cars become enmeshed due to the impact and slide as one thereafter. On-the-scene measurements show that the coefficient of kinetic friction between the tires of these cars and the pavement is 0.750, and the cars slide to a halt at a point 5.48 m west and 6.37 in south of the impact point. How fast was sedan traveling just before the collision? How fast was SUV traveling just before the collision?

Answers

Answer:

v = 19.33 m / s   South

Explanation:

To solve this exercise we must use the conservation of momentum, for which we must define a system formed by the two cars, therefore the forces during the collision are internal and therefore the moment is conserved.

Since it is a vector quantity, we are going to work on each axis, the x axis is in the East-West direction

initial instant. Before the crash

        p₀ = m 0 + M v₂ₓ

final instant. Right after the crash

        p_f = (m + M) vₓ

        p₀ = 0_pf

        M v₂ₓ = (m + M) vₓ

In this case m is the mass of the car and M the mass of the SUV

        vₓ = [tex]\frac{M}{m+My}[/tex]  v₂ₓ            (1)

in the Y axis (North - South direction)

initial instant

       p₀ = m v_{1y} + M 0

final moment

       p_f = (m + M) v_y

       p₀ = p_f

       m v_{1y} + M 0 = (m + M) v_y

       v_y = [tex]\frac{m}{m+M} \ v_{1y}[/tex]       (2)

With these speeds we can use the relationship between work and the variation of kinetic energy, in this part the two cars are already united.

         W = ΔK

friction force work is

         W = - fr d

the friction force is described by the equation

         fr = μ N

Newton's second law

         N-W = 0

         N = W

         

we substitute

         W = - μ (m + M) g d

as the car stops the final kinetic energy is zero and

the initial kinetic energy is

         K₀ = ½ (m + M) v²

we substitute

         - μ (m + M) g d = 0 - ½ (m + M) v²

            μ g d = ½ v²

            v² = 2 μ g d

the distance traveled can be found with the Pythagorean theorem

        d = [tex]\sqrt{x^2+y^2}[/tex]

        d = [tex]\sqrt{5.48^2 + 6.37^2}[/tex]

        d = 8.40 m

let's calculate the speed

         v² = 2 0.75 9.8 8.40

         v = √123.48

         v = 11.11 m / s

this velocity is in the direction of motion so we can use trigonometry to find the angles

          tan θ = y / x

          θ = tan⁻¹ y / x

          θ = tan⁻¹ (-5.48 / -6.37)

          θ = 40.7º

Since the two magnitudes are negative, this angle is in the third quadrant, measured from the positive side of the x-axis in a counterclockwise direction.

          θ'= 180 + 40.7

          θ’= 220.7º

In the exercise they indicate the the sedan moves in the y-axis, therefore

          sin θ'= v_y / v

          v_y = v sin 220.7

          v_y = 11.11 sin 220.7

          v_y = -7.25 m / s

the negative sign indicates that it is moving south

To find the speed we substitute in equation 2

          v_y = [tex]\frac{m}{m+M} \ v_{1y}[/tex]

          v_{1y} = v_ y   [tex]\frac{m+M}{m}[/tex]

           

let's calculate

         v_{1y} = -7.25    [tex]\frac{1500+2500}{1500}[/tex]

         v_{1y} = - 19.33 m/s

therefore the speed of the sedan is v = 19.33 m / s with a direction towards the South

A 10.0 kg mass is lifted 5.0 m above the ground.
Find the change in gravitational energy.

Answers

Answer:

500 J

Explanation:

formula of Energy is: E=mass*height*g, where g≈10 (m/s²).

according to the formula above: E=10*5*10≈500 (J)

A lever was used to life heavy rock. The input force was 150 N and the output force was 500 N. What was the mechanical advantage of the pulley?

Answers

MA = fo / fi = 500 N / 150 N = 3.3. So C.

If Manuel exerts a force of 10 N to push a desk to the right at the same time Lynn exerts a force of 15 N to push the desk to the left, the desk will move to the
left
right
sideways
it won't move

Answers

Answer:

The desk will move to the left.

Explanation:

Since Manuel is exerting a force of 10 N to the right, and Lynn is exerting a force of 15 N to the left, it means that Lynn is exerting a force of 5 N more than Manuel, meaning that the desk will move to the left, the direction Lynn is pushing it too.

Please like and mark brainliest!

Hope it helps!

Antonym for Radiation lol

Answers

Answer:

convergence is the correct answer

Answer:

absorption, concealment, containment, refrain, repression, suppression, withholding, confinement, restriction, constraint

wait no....

diffusion, emission, polarization, spread, ramification, divarication, propagation, transmission, broadcast, circulation and dissipation.

LOL

A student determines that a sample has a mass of 157.2 g and a volume of 20 cm^3. Which
substance from the table is the student analyzing?

Answers

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

linkcutter.ga/gyko

While riding a horse, the horse suddenly comes to an abrupt stop. You fly forward and
fall over the front of the horse.
What is the Newton law?

Answers

Answer:

For every action there is an opposite reaction.

Explanation:

Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.

Answers

Answer:

sorry I didn't get it, my apologies

A geosynchronous satellite orbits Mars (mass = 6.42 x 1023 kg) once every Martian day, 88640 s. At what radius does it orbit?

Answers

Answer:

angular speed ω = 2PI / T rad/sec  

ω^2*r = M*G/r^2

r = ³√ M*G/ω^2 = ³√6.42*10^23*6.67*10^-11*88640^2/39.5 = 2.04*10^7 m

Explanation:

A geosynchronous satellite orbits Mars once every Martian day, 88640 s then the radius of the orbit will be equal to 2.04 × 10⁷ m.

What is gravity?

The fundamental force of attraction operating on all matter is recognized as gravity, also spelled gravity, in mechanics. It has no impact on identifying the interior properties of common matter because it is the weakest force known to exist in nature.

As per the given data in the question,

Mass, m = 6.42 x 10²³ kg

Time, T = 88640 s

Use the formula of velocity for satellite,

v = 2πR/T

Where R represents the radius

Use the formula of centripetal acceleration,

[tex]a_c[/tex] = v²/R

Thus;

[tex]a_c[/tex] = (2πR/T)²/R

= 4π²R/T²

The formula for gravitational acceleration is:

[tex]a_g[/tex] = Gm/R²

G = 6.674 × 10⁻¹¹ m³/kg. s²

Now, the satellite's gravitational acceleration is what is responsible for its centripetal acceleration. Thus,

Centripetal acceleration = gravitational acceleration.

Thus;

4π²R/T² = Gm/R²

Making R the subject gives;

R = ∛(GmT²/4π²)

Substitute the values in the above equation,

R = ∛((6.674 × 10⁻¹¹ × 6.42 x 10²³ × 88640²)/(4 × π²))

R = 2.04 × 10⁷ m

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PLEASE HELP ME WITH THIS ONE QUESTION
A tuning fork of 500 Hz is struck in a room with a speed of sound of 340 m/s. What is the distance between a point of rarefaction and the next compression point, in the resulting sound?

Answers

Answer:

Wavelength = 0.68 meters.

Explanation:

Wavelength gives the distance between a point of rarefaction and the next compression point, in the resulting sound.

Given the following data;

Frequency = 500 Hz

Speed of sound = 340 m/s

To find the wavelength;

Wavelength = speed/frequency

Wavelength = 340/500

Wavelength = 0.68 meters

the long-term average weather for a region is called

Answers

Answer:

Climate.

Explanation:

Weather can be defined as the atmospheric conditions of a particular area over a short period of time.

The elements of weather include precipitation, wind, temperature, atmospheric pressure, relative humidity, cloud, and wind speed.

The long-term average weather for a region is called climate.

This ultimately implies that, when the average atmospheric conditions prevailing in a specific region persists for a very long period of time, it is known as climate.

Which statement best defines constructive interference? O Energy reflects back toward the source of its power. O Two waves with identical crests and troughs meet. thing O A wave appears to be at a standstill and vibrates in place O The trough of one wave matches the crest of another.​

Answers

Answer:

when the trough of one wave matches the crest of another

Explanation:

just took the test

PLEASE HELP ME WITH THIS ONE QUESTION
What is the final temperature when 625 grams of water at 75.0° C loses 7.96 x 10^4 J? (cwater = 4186 J/kg°C)

Answers

Answer: 44.57°C

Explanation:

The following can be deduced from the question:

Specific heat of water = 4.186 J/kg

From the question, we can infer that 625 × 4.186 joules of heat will be lost when there's a 1°C drop of water.

We then calculate the amount if degrees that it'll take to cool for 7.96 x 10⁴J. This will be:

= 7.96 × 10⁴ /(625 × 4.186)

= 79600/(625 x 4.186)

= 79600/2616.25

= 30.43°C

The final temperature will then be:

= 75.0°C - 30.43°C

= 44.57°C

How does wavelength change depending on whether the pipe is open or closed?

Answers

Answer:

* in a tube with both ends open

        λ = 2L / n                    n = 1, 2, 3,…

* tube with one end open and the other closed.  

         λ = 4L / n                     n = (2n ’+ 1 )

Explanation:

When a sound wave enters a pipe, a resonance process occurs, whereby only some wavelengths can occur.

 

* in a tube with both ends open

in this case there are maximums at each end, so if the length of the had is L

              λ = 2L 1st harmonic

              λ = 2 L / 2 2nd harmonic

              λ = 2L / 3

              λ = 2L / n                    n = 1, 2, 3,…

* In the case of a tube with one end open and the other closed.

At the open end there is a belly and at the closed end a node

              λ = 4L 1st harmonic

              λ = 4L / 3 3rd harmonic

              λ = 4L / 5

              λ = 4L / n                  n = 1, 3, 5,… odd

                                       n = (2n ’+ 1 )      where n’ are all integers

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