A cylindrical container is filled with oil to a depth of 32cm. If the pressure exerted at the base of the container is known to be 2560pa then, how much is the density of the oil?

Answers

Answer 1

Answer:

Ro = 815.5 [kg/m³]

Explanation:

We must use the following equation to find the hydrostatic pressure exerted on the bottom of the cylinder.

[tex]P=Ro*g*h[/tex]

where:

P = pressure = 2560 [Pa]

Ro = density [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 32 [cm] = 0.32 [m]

[tex]2560=Ro*9.81*0.32\\Ro=815.5 [kg/m^{3} ][/tex]

Answer 2

Answer:

800kg/m^3

Explanation:

roh=2560/0.32m×10m/s^2

800kg/m^3

Change 32 cm to m to make it more easier.

Gravitational acceleration is 10m/s^2.

HOPE THAT I HELPED YOU!


Related Questions

Calculate the work done in lifting 200 kg of water through a vertical height of 6 metres
(g = 10 m/s)
(A) 5000 J
(B) 12000 J
(C) 25000 J
(D) 15000 J​

Answers

Answer:

[tex]\bf\pink{(C)\:12000\:J}[/tex]

Explanation:

Given :-

[tex]\sf\red{Mass = 200 \ kg}[/tex][tex]\sf\orange{Gravity = 10 \ m/s}[/tex][tex]\sf\green{Height = 6 \ m}[/tex]

Need to find :-

[tex]\sf\blue{Work \ done}[/tex]

Formula required :-

[tex]\sf\purple{Work \ done = Mass \times Gravity \times Height}[/tex]

Solution :-

[tex]\to\:\:\sf\red{Work \ done = Mass \times Gravity \times Height}[/tex]

[tex]\to\:\:\sf\orange{Work \ done = 200 \times 10 \times 6}[/tex]

[tex]\to\:\:\sf\green{Work \ done = 2000 \times 6}[/tex]

[tex]\to \:\ \sf\blue{ Work \ done = {\bf{\blue{1200\:J}}}}[/tex]

Hence, [tex]\bf\green{(B)}[/tex] is the correct option.

The displacement along the number line below is
a.) -6
b.) -3
c.) 0
d.) +3
e.) not shown

Answers

Answer:

d: +3

Explanation:

X1 is going +3 meters to arrive to X2. More scientifically -6+3= -3 which is the value of X2 which tells us that the correct answer is +3.

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