A copper alloy cylinder that is 1.3 feet long with a diameter of 45.27 inch is subjected to a tensile stress of 1,140 psi along its length. Assuming this applied stress is purely elastic, calculate the diameter, in inches, of the cylinder under this load. For this alloy, the elastic modulus is 904,672 psi and the Poisson's ratio is 0.33.

Answers

Answer 1

Answer:

diameter = 45.251 inches

Explanation:

initial length = 1.3

initial diameter = 45.27

tensile stress = σ = 1140

modulus E = 904672

v = 0.33

we calculate longitudinal strain = σ/E

= 1140/904672

= 0.0012601252

general relation for

v = -Ed/El

[tex]0.33=\frac{-Ed}{0.0012601252}[/tex]

we cross multiply

-Ed = 0.33 x 0.0012601252

= -0.00041584132in

[tex]\frac{df - 45.27}{45.27} =\frac{-0.00041584132}{1}[/tex]

when we cross multiply,

df - 45.27 = -0.00041584132*45.27

df - 45.27 = -0.018825136

df = -0.018825136 + 45.27

df = 45.251 inches


Related Questions

May you tell me the meaning of "Tolerance is a bitter tree, but its fruit is sweet "by Aristotle

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Answer:

“Patience is bitter, but its fruit is sweet. With patience you can bear up under any adversity and survive any defeat. With patience you can control your destiny and have what you will. Patience is the key to contentment, for you and for those who must live with you. To be brave without patience can kill you.

Explanation:

Aristotle’s Ethical Doctrine of the Mean. According to Aristotle’s ethical rule about the Golden Mean, to use a thing with virtue is a kind of moderation, as it leads the particular thing being in a good condition, and allows for its functions to be performed in a proper manner.

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Can you help me by solving this question

explain the working and performance of a centrifugal clutch with a sketch​

Answers

Answer:

A centrifugal clutch works, as the name suggests, through centrifugal force.

One of the most common methods is by mounting the clutch onto the parallel or taper crank shaft of the engine.

When the crank shaft rotates the shaft of the clutch rotates at the same speed as the engine

The tensile strength of brittle materials may be determined using a variation of Equation 8.1. Compute the critical crack tip radius for an Al2O3 specimen that experiences tensile fracture at an applied stress of 275 MPa (40,000 psi). Assume a critical surface crack length of 2 × 10−3 mm and a theoretical fracture strength of E/10, where E is the modulus of elasticity.

Answers

Answer:

0.39 nM

Explanation:

The critical crack tip radius from the equation

attached below

for fracture to occur the бm will have to reach the fracture strength of material

i.e.  бm =  E/10

from equation 2 attached below

St = ( 400 * a * бo^2 ) / E^2 ------ 3

Given : a = 2*10^-3 mm , бo = 275 MPa, E = 393 * 10^3 MPa ( gotten from table)

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St = 3.9 * 10^-7 ≈ 0.39 nM

Two kilograms of air in a piston-cylinder assembly undergoes an isothermal
process from an initial state of 200 K, 300 kPa to 600 kPa.
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Answers

Answer:

a) 0.39795 kJ/K

b) 79.589.37 kJ

Explanation:

m = Mass of air = 2 kg

Temperature = 200 K

P₁ = Initial pressure = 300 kPa

P₂ = Final pressure = 600 kPa

R = mass-specific gas constant for air = 287.058 J/kgK

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∴ Entropy is generated in the process is 0.39795 kJ/K

b)

∴ Amount of lost work is 79.589.37 kJ

You deposit $5,000 in a savings account that earns 8% simple interest per year. What is the minimum number of years you must wait to double your balance?

Answers

Answer:

It will take 12.5 years double  the balance

Explanation:

As we know

A = P (1 + rt)

where A is the amount

P is the principal sum of money deposited

r is the rate of interest (per annum)

t is the time in years

Substituting the given values we get -

2P = P ( 1+ 0.08 * t)

2 = 1+ 0.08 * t

1 = 0.08 * t

t =

[tex]\frac{1}{0.08} \\\frac{100}{8} \\12.5[/tex] years

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Answers

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Explanation:

1. Which of these materials is the strongest?
O CHIPBOARD
O PLYWOOD
PINE
O BLOCKBOARD
MDF

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Answers

Answer : MDF
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True

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Answers

True,My good sir/maam

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Answers

Answer:

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Explanation:

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Answers

Answer:

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Edmentum/Plato

two ways in accepting responsibility can help teenagers to maintain coach relations with parents​

Answers

Answer:

1. It will help the teenagers gain the trust of their parents

2. It will help the teenagers obtain more privileges from their parents.

Explanation:

Responsibility is the state of accepting blame for a particular thing. A teenager who accepts responsibilities owns up to his mistakes and takes control over situations he is assigned to.

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Answers

Answer:

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Explanation:

A current value of 0.000005 A is equal to
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Answers

The correct answer is letter C

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A current value of 0.000005 A is equal to 5 HA.

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A transformer is to be used to provide power for a computer disk drive that needs 6.4 V (rms) instead of the 120 V (rms) from the wall outlet. The number of turns in the primary is 300, and it delivers 500 mA (the secondary current) at an output voltage of 6.4 V (rms). (a) Should the transformer have more turns in the secondary compared to the primary, or fewer turns

Answers

Answer:

The secondary coil should have fewer turns compared to the primary coil.

Explanation:

[tex]N_p[/tex] = Number of turns in primary coil = 300

[tex]N_s[/tex] = Number of turns in secondary

[tex]V_p[/tex] = Voltage in primary coil = 120 V

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We have the relation

[tex]\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}\\\Rightarrow N_s=\dfrac{N_p}{V_p}\times V_s\\\Rightarrow N_s=\dfrac{300}{120}\times 6.4\\\Rightarrow N_s=16[/tex]

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An axial flow pump is to discharge 5 cusecs at an operating speed of 1450 rev/min. The inner and outer diameters of the impeller are to be 5.5 in. and 11 in. respectively. If the head developed according to the vector triangles is 20 ft, determine the angle of the vane tips at the inner and outer diameters and the corresponding diffuser blade angle (the diffuser blades are the stationary blades after the impeller).

Answers

Answer:

if you want it to go faster add chain

Explanation:

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Answers

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https://www.slader.com/discussion/question/an-insulated-rigid-tank-is-divided-into-two-equal-parts-by-a-partition-initially-one-part-contains-4/



there will be the answer

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Answers

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Design a filter that has infinite DC gain, a gain of one from 1Hz to 100 Hz and filters (1storder) any signals above 100 Hz.a) Sketch the bode plotb) Sketch the s-planec) write the transfer function of the filterd) write the differential equatione) write out the unforced transient responsef) write out the frequency response

Answers

Answer:

Attached below are the  sketches

answer :

c) G(s) = 100 / ( s + 100 )

d) y'(t)  + 100Y(s) = 100 X(s)

e) g(t) = e^-100t  u(t)

Explanation:

a) Sketch the bode plot

The filter here is a low pass filter

b) Sketch the s-plane

attached below.     pole ( s ) is at 100

c) write the transfer function of the filter

Transfer function ; G(s) = 100 / ( s + 100 )

d) write the differential equation

Y(s) / X(s) = 100 / s + 100

Y(s) [ s + 100 ] = 100 X(s)

= sY(s) + 100Y = 100 X(s)

∴ differential equation = y'(t)  + 100Y(s) = 100 X(s)

e) write out the unforced transient response

g(t) = e^-100t  u(t)

f) write out the frequency response

attached below

A composite shaft with length L = 46 in is made by fitting an aluminum sleeve (Ga = 5 x 10^3 ksi) over a
steel core (Gs = 11 x10^3 ksi). The composite shaft is fixed against rotation at the wall A and has outside diameter da = 5 in. The steel core has diameter ds = 4 in. A torque TB = 3 kip. in is applied at B. % Matlab input: L = 46 Ga = 5 * 10^3 Gs = 11 * 10^3; da = 5; ds = 4; Tb = 3;
Determine the magnitude of the angle of twist at end B.

Answers

Answer:

Explanation:

Given the data in the question;

L = 46 in

Ga = 5 × 10³ ksi

Gs = 11 × 10³ ksi

Outside diameter da = 5 in

ds = 4 in

Tb = 3 kip.in

Now,

Ja = polar moment of Inertia of Aluminum;

Ja ⇒ π/32( 5⁴ - 4⁴ ) = π/32( 625 - 256 ) = π/32( 369 ) [tex]in^u[/tex]

Js = polar moment of inertia of steel

Js ⇒ π/32 ds⁴ = π/32( 4⁴ ) = π/32( 256 )

Ta is torque transmitted by Aluminum  

Ts is torque transmitted by steel  

{composite member }

T = Ta + Ts ------ let this be equation m1

Now, we use the relation;

T/J = G∅/L

JG∅ = TL

∅ = TL/GJ

so, for aluminum rod ∅[tex]_{alu[/tex] = TaLa/GaJa

for steel rod ∅[tex]_{steel[/tex] = TsLs/GsJs

but we know that, ∅a = ∅s = ∅[tex]_B[/tex]

so

[TaLa/GaJa]  =  [TsLs/GsJs]

also, we know that, La = Ls = L

∴ [Ta/GaJa]  =  [Ts/GsJs]

we solve for Ta

TaGsJs = TsGaJa  

Ta = TsGaJa / GsJs

we substitute

Ta = [Ts(5 × 10³)( π/32( 369) )] / [ (11 × 10³)( π/32( 256 ) ) ]

Ta = 0.66Ts

now, we substitute 0.66Ts for Ta and 3 for T in equation 1

T = Ta + Ts

3 = 0.66Ts + Ts

3 = 1.66Ts

Ts = 3 / 1.66

Ts = 1.8072 ≈ 1.81 kip-in

so

∅[tex]_{steel[/tex] = TsLs / GsJs

we substitute

∅[tex]_{steel[/tex] = (1.81 × 46 ) / ( 11 × 10³ × π/32( 256 ) )

∅[tex]_{steel[/tex] = 83.26 / 276460.1535

∅[tex]_{steel[/tex]  = 0.000301

∅[tex]_{steel[/tex] = 3.01 × 10⁻⁴ rad

so

[tex]_{steel[/tex] = ∅[tex]_B[/tex] = 3.01 × 10⁻⁴ rad

Therefore, the magnitude of the angle of twist at end B is 3.01 × 10⁻⁴  rad

Technician A says that ultra-high-strength steels (UHSS) are generally defined as those steels with tensile strengths greater than 700 MPa.
Technician B says that advanced high-strength steels (AHSS) are generally defined as those steels with tensile strengths from 375 MPa up to 1700
Who is right?
O A only
OB only
O Both A and B
O Neither A norb
Table of Contents

Answers

b only i think i’m not fully sure.

multimeter and the LCD is showing Hz. What's she measuring?
A. Resistance
B. Amplitude
C. Voltage
D. Frequency

Answers

Answer:

i think its d frequency

Explanation:

hz on a multimeter means frequency setting

A steam power plant is represented as a heat engine operating between two thermal reservoirs at 800 K and 300 K. The temperature of the steam in the boiler is 550 K and the temperature of the saturated water in the condenser is 330 K. The rates of heat transfer in the boiler and condenser are 4 MW and 2 MW, respectively. Please answer the following.

Required:
a. Represent the devices present in the heat engine and include their name along with the data given in the problem.
b. If this steam power plant were to operate as a reversible heat engine, with the boiler and condenser temperatures, what would be its thermal efficiency?
c. Use your result from part (b) to determine if the actual steam power plant can achieve such thermal efficiency. Justify your answer.
d. For the actual steam power plant is the Clausius inequality satisfied? Show you computation and discuss whether your result agrees or disagrees with your answer in part (c).

Answers

Yeet is the answer .....

..................................................

Answers

..................................................

Answer: yayyyy free sh.it

Explanation:

The inverted U-tube is used to measure the pressure difference between two points A and B in an inclined pipeline through which water flows. The differenceof level h=0.4m ; X=0.2; and Y=0.3m. Calculate the pressure difference between point B and A if the top of the manometer is filled with:
i) Air
ii) paraffin of relative density of 0.75

Answers

Answer:

i) 0.610 m or 610 mm

ii) 0.4 m or 400 mm

Explanation:

The pressure difference between the pipes is

a) Air

Pa + πha +Ha = Pb + πhb +Hb

Pa - Pb = π(hb-ha) + Hb-Ha

Relative density of air = 1.2754 kg /m3

Pa - Pb = 1.2754 * 0.4 + (0.3-0.2) = 0.610 m or 610 mm

b) paraffin of relative density of 0.75

Pa - Pb = π(hb-ha) + Hb-Ha

Pa - Pb = 0.75 * 0.4 + (0.3-0.2) = 0.4 m or 400 mm

Horizontal shear forces and, consequently, horizontal shear stresses are caused in a flexural member at those locations where the internal bending moment is changing along the beam span. The imbalance in the bending stress resultant forces acting on a portion of the cross-section demands an internal horizontal shear force for equilibrium.
a. True
b. False

Answers

Answer:

False

Explanation:

When the horizontal shear forces act on the surface there is transverse shear stress at a particular point which is equal in magnitude. Pure bending is less common than a non uniform bending because the beam is not in equilibrium.

Q.14
What is the most common way to isolate the CPU from the external circuit?
Select one:
A. OPTICAL ISOLATION
B. SMALL RELAYS
C. BRIDGE RECTIFIERS
D. RHEOSTATS

Answers

Answer:

A. optical isolation

Explanation:

well I can't really give a good explanation because I also saw the same question in my exams and option A was the correct answer

A hydrological system consists of five horizontal formations with an equal thickness of 10 m each. The hydraulic conductivities of the formations are 20, 10, 15, 50, and 1 m/day, respectively. Calculate equivalent horizontal and vertical hydraulic s conductivities. If the flow in the uppermost layer is at an angle of 30 away from the normal direction relative to the boundary, calculate flow directions in all the formations.

Answers

Answer: Hello The required formula is attached below

answer:

A) KH =  19.2 m/day ,  Kv = 4.045 m/day

B) flow directions : ∝1 = 30°, ∝2 = 16.102°, ∝3 = 23.62, ∝4 = 55.55°,

∝5 = 1.66°

Explanation:

Given data :

Thickness of five horizontal formations ( K )  = 10 m each

Hydraulic conductivities of formations ( b )  =

b1= 20,  b2= 10,  b3= 15,  b4= 50 and b5  = 1        (m/day)

a)Determine the equivalent horizontal and vertical conductivities

kH ( equivalent  horizontal conductivity )

   = ∑ Kb / b  = ( K1b1 + K2b2 + k3b3 + k4b4 + k5 b5 ) / b1 + b2 +b3+b4+b5

input given values into the above equation

kH = 960 / 50  = 19.2 m/day

Kv ( equivalent vertical conductivity )

= ∑( b / (b/k) ) = ( b1 + b2 + b3 + b4 + b5 ) / ( b1/k1 + b2/k2 + b3/k3 + b4/k4 + b5/k5 )

input given values into equation above

Kv = 50 / 12.36 = 4.045 m/day

b) Determine the flow directions in all the formations

given that ∝1 = 30°  and Ki / kj = bi / bj

k1 /k2 = tan ∝1 / tan ∝2

20 / 10 = tan 30 / tan ∝2

∝2 = 16.102°

K2/k3 = tan 16.102 / tan ∝3

= 10 / 15 = tan 16.102 / tan ∝3

∝3 = 23.62

K3/k4 = tan ∝3 / tan ∝4

= 15 / 50 = tan 23.62 / tan ∝4

∝4 = 55.55°

k4 /k5 = tan ∝4 / tan∝5

= 50 / 1 = tan 55.55 / tan ∝5

∝5 = 1.66°

write three ways of soil investigation of a site​

Answers

Methods of Soil Exploration
Open excavation.
Borings.
Subsurface soundings.
Geographical methods.
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