A clarinetist, setting out for a performance, grabs his 3.070 kg clarinet case (including the clarinet) from the top of the piano and carries it through the air with an upward force of 25.60 N. Find the case's vertical acceleration. Indicate an upward acceleration as positive and a downward one as negative. Use for =9.810 m/s2 for the acceleration due to gravity.

Answers

Answer 1

Answer:

the vertical acceleration of the case is 1.46 m/s

Explanation:

Given;

mass of the clarinet case, m = 3.07 kg

upward force applied by the man, F = 25.60 N

Apply Newton's second law of motion;

the upward force on the clarinet case = its weight acting downwards + downward force due to its downward accelaration

F = mg + m(-a)

the acceleration is negative due to downward motion from the top of the piano.

F = mg - ma

ma = mg - F

[tex]a = \frac{mg - F}{m} \\\\a = \frac{(3.07 \times 9.8) \ - \ 25.6}{3.07} \\\\a = 1.46 \ m/s^2[/tex]

Therefore, the vertical acceleration of the case is 1.46 m/s²


Related Questions

A uniform rod of length 80cm rotated in the xy plane about a frictionless pin passing through one end (as shown in figure). If the angular
velocity of the rod is 4rad/s, find the linear velocity (in m/s) of its mid-point C
Rod
Pin
С
Select one:
O a. 0.5
O b. 1.6
O c. 1.3
O d. 0.8​

Answers

Answer:

Linear velocity (in m/s) = 1.6 m/s

Explanation:

Given:

Length of rotational plane = 80 cm

Angular  velocity of the rod = 4rad/s

Find:

Linear velocity (in m/s)

Computation:

Radius from mid point C = Length of rotational plane / 2

Radius from mid point C = 80 / 2

Radius from mid point C = 40 cm

Radius from mid point C = 0.4 m

Linear velocity (in m/s) = Angular  velocity of the rod x Radius from mid point C

Linear velocity (in m/s) = 0.4 x 4

Linear velocity (in m/s) = 1.6 m/s

A system is in liquid-vapor mixture of 0.5 kg of saturated water vapor and 0.5 kg
of saturated liquid. Calculate the quality.​

Answers

Answer:

x = 0.5 = 50%

Explanation:

The quality of a water liquid-vapor mixture can be defined as the fraction of water vapor present in the water liquid-vapor mixture. Therefore, it can be calculated by the use of the following formula:

[tex]x = \frac{m_{vap}}{m}[/tex]

where,

x = quality = ?

m_vap = mass of saturated water vapor = 0.5 kg

m = total mass = mass of saturated vapor + mass of saturated liquid

m = 0.5 kg + 0.5 kg = 1 kg

Therefore,

[tex]x = \frac{0.5\ kg}{1\ kg}[/tex]

x = 0.5 = 50%

The instrument measuring the temperature change between inspired cool air and expired warm air is called?​

Answers

Answer:

It's called a Spirometer

а)
In figure below, assume that a 20-mm-diameter rivet joins the plates that are each 110 mm
wide. The allowable stresses are 120 MPa for bearing in the plate material and 60 MPa for
shearing of rivet. Find the followings. Express your final answer in N/mm².
110 mm
20-mm
P
(1) Determine the minimum thickness of each plate and largest average tensile stress in the
plates.
(6 marks)

Answers

Image of the plate is missing, so i have attached it.

Answer:

A) t = 7.854 mm

B) σ = 26.67 MPa

Explanation:

A) From shearing of rivet, formula for pressure is;

P = τ•A_rivets

Where;

τ is allowable stress

A_rivets is Area of rivet

We are given:

τ = 60 MPa

Diameter; d = 20 mm

A_rivets = πd²/4 = π × 20²/4 = 100π

Thus;

P = 60 × 100π

P = 6000π N

From bearing of plate material, we can calculate pressure as;

P = σ_b•A_b

We are given;

σ_b = 120 MPa

A_b is area of plate = 20t

Where t is the thickness

Thus;

6000π = 120 × 20t

t = 6000π/(120 × 20)

t = 7.854 mm

B) Largest average tensile stress is given by the formula;

σ = P/A

Where A = 110t - 20t

A = 90t

A = 90 × 7.854

Thus;

σ = 6000π/(90 × 7.854)

σ = 26.67 MPa

The light which is produced in the core of the sun passes through layers of comparatively cold gas clouds on the surface of the sun. These clouds absorb some of the sun's light producing dark lines in the spectrum of the sun and sky. Two of the lines, called Fraunhofer C and I) lines after their discoverer, are found at about 656 nm and 587 nm, respectively. Looking at your atomic spectroscopy data, which elements that you examined would absorb at these wavelengths

Answers

Answer:

the two lines observed correspond to Hydrogen and Helium

Explanation:

One of the great principles of atomic physics is that the emission and absorption lines of atoms are the same, in addition, each different element has a series of characteristic lines with which we can identify it.

Bohr's atomic model allows to fully explain the spectrum of lines and absorption of Hydrogen, in this case the line

            λ = 656 nm

corresponds to a hydrogen trasition of the Balmer series from state n = 3 to state n = 2

The other line identified λ = 587 nm does not correspond to any hydrogen line and neither to heavy element lines, so this line when it was discovered was assigned to a new element, which was called Helium.  This line is explained this element was assigned an atomic number (charge) of +2 and a mass of + 4 u, specifically it is a transition from level n = 3 to level n = 2

therefore the two lines observed correspond to Hydrogen and Helium

What does the potential energy diagram of a chemical reaction tell you?
O A. Whether atoms are being created or destroyed
O B. Whether the reaction is endothermic or exothermic
C. Whether there are more reactants or products
D. Whether the law of conservation of matter is being obeyed

Answers

Answer:

B

Explanation:

I'm learning about this now actually and it can be a little confusing but it would be endothermic or exothermic. if endothermic the products have less energy than the reactants and if exothermic products have more energy than reactants


What are 3 facts you learned about the periodic table:

Answers

Answer: the rarest element is Francium. J is not on the periodic table. also Dmitri Mendeleev proposed the periodic table.

Explanation: Kinda looked the last one up.

Which refers to the density of the medium’s particles at the compression of a sound wave?

Answers

Answer:

Explanation:

Amplitude. the density of a mediums particles at the compression of the wave. Rarefaction. the part of a wave where the particles of the medium are farther apart.

Answer: amplitude

Explanation:

a 4 kg block is moving at 12 m/s on a horizontal frictionless surface. a constant force is applied such that the block slows with an acceleration of 3 m/s^2. how much work must this force do to stop the block?
a. -576 J
b. -360 J
c. -288 J
d. 360 J
e. 576 J
walk me through this please. NO LINKS. ​

Answers

Answer:

Is there a picture?

Explanation:

A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms. Two hours later, the numbers of the two atoms are equal. The half-life of A is 0.77 hours. What is the half-life of B in hours?

Answers

Answer:

Explanation:

Initially no of atoms of A = N₀(A)

Initially no of atoms of B = N₀(B)

5 X N₀(A)  = N₀(B)

N = N₀ [tex]e^{-\lambda t}[/tex]

N is no of atoms after time t , λ is decay constant and t is time .

For A

N(A) = N(A)₀ [tex]e^{-\lambda_1 t}[/tex]

For B

N(B) = N(B)₀ [tex]e^{-\lambda_2 t}[/tex]

N(A) = N(B) , for t = 2 h

N(A)₀ [tex]e^{-\lambda_1 t}[/tex] = N(B)₀ [tex]e^{-\lambda_2 t}[/tex]

N(A)₀ [tex]e^{-\lambda_1 t}[/tex] = 5 x N₀(A)  [tex]e^{-\lambda_2 t}[/tex]

[tex]e^{-\lambda_1 t}[/tex] = 5  [tex]e^{-\lambda_2 t}[/tex]

[tex]e^{\lambda_2 t}[/tex] = 5  [tex]e^{\lambda_1 t}[/tex]

half life = .693 / λ

For A

.77 =  .693 / λ₁

λ₁ = .9 h⁻¹

[tex]e^{\lambda_2 t}[/tex] = 5  [tex]e^{\lambda_1 t}[/tex]

Putting t = 2 h , λ₁ = .9 h⁻¹

[tex]e^{\lambda_2\times 2}[/tex] = 5  [tex]e^{.9\times 2}[/tex]

[tex]e^{\lambda_2\times 2}[/tex] = 30.25

2 x λ₂ = 3.41

λ₂ = 1.7047

Half life of B = .693 / 1.7047

= .4065 hours .

= .41 hours .

This picture represents the electric field diagram between two particles with static charges. Do the two particles have the same charge? If the particles are free to move, what affect will the two particles have on each other? If a third particle was added to this field with a positive charge, what would it be attracted to? If an uncharged particle was placed between A and B, which way would it move?​

Answers

Answers:

No, They will attract each other, B, and neither direction

Explanation:

Since the two already presented particles in the diagram represent both opposing charges due to the direction of the arrows (the arrows facing away from the particle shows a positive charge and the particles facing towards the particle show a negative charge), not only because of this but as the arrows between the particles show an attracting magnetic field, then it can be concluded that the particles will attract to each other and if another particle was introduced into the diagram of a positive charge, then it would attract to the negatively charged particle. If you have any questions or need further explanation, please comment below. E2021, have a great day.

Answer:

No, They Will Attract Each Other, B, and Neither Direction

Explanation: Im an edge student

DESCRIBE THE REQUIREMENTS OF AN INTERNET CONNECTION?
please tell me the answer​

Answers

Answer: The basic requirements for connecting to the Internet are a computer device, a working Internet line, and the right modem for that Internet line. In addition, software programs such as Internet browsers, email clients, Usenet clients, and other special applications are needed in order to access the Internet.

Explanation: brainleist pls :)

If I have a sphere rolling on a table with an initial velocity and then it falls off the edge of the table, from this point on it is taken as if my initial velocity were zero, or it starts from the initial velocity that I had before in the table?

Answers

Answer:

The initial velocity after leaving the table is the same as it was before leaving the table (nothing is present to produce discontinuties in the velocity).

Before leaving the table the vertical velocity was zero and is zero when it leaves the table.

The horizontal velocity is constant with no forces present to change the velocity.

what determines the strength of a base?

Answers

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

Aluminum has an alpha value of 25 x 10^-6 1/degrees C. What is the change in
length of a 4850 cm wire at 2 degrees C when the temp increase to 55 degrees
C?

Answers

Answer:

0.25705 cm or 2.5705×10⁻³ m

Explanation:

Applying,

α = ΔL/(LΔT)................. Equation 1

Where α = coefficient of linear expansivity, ΔL = Increase in length, L = Original length, ΔT = Increase in temperature

make  ΔL the subject of the equation

ΔL = α(LΔT)............... Equation 2

From the question,

Given: α = 10⁻⁶ C⁻¹, L = 4850 cm, ΔT = T₂-T₁ = (55-2) = 53 °C

Substitute these values into equation 2

ΔL = (10⁻⁶)(4850)(53)

ΔL = 0.25705 cm or 2.5705×10⁻³ m

Explain the mode of operation of x-ray​

Answers

Answer:

If x-rays get in touch with our body tissues, they create a picture of a metal film. The high energizing rays are unable to penetrate soft tissue, such as skin and organs and travel through the laser. The places where the x-rays pass soft tissues are Black areas of an X-ray.

Answer:

Explanation:

Mode of Operation: In the X-ray tube a Low voltage high p.d is applied between the hot cathode and the anode. Electrons are emitted from the cathode and are accelerated to an extremely high speed. ... They are produced by increasing the p.d. between the cathode and anode.

A 6.00 kg object at rest is suddenly broken apart into two fragments by an explosion. The fragment with mass 3.50 kg is moving 24.0m/s to the left. The other fragment is moving _______m/s to the right. Group of answer choices

Answers

Answer: 33.6 m/s

Explanation:

Given

The initial mass of the object is [tex]6\ kg[/tex]

It breaks into two fragments of 3.5 and 2.5 kg

3.5 kg part moves at 24 m/s towards left

Suppose 2.5 kg part moves with a speed of v towards the right

As the center of mass is at rest before the collision, it continues to remain at rest after the collision.

[tex]\therefore 6\times 0=3.5\times 24-2.5\times v\\\Rightarrow 3.5\times 24=2.5\times v\\\\\Rightarrow v=33.6\ m/s[/tex]

Therefore, the velocity of 2.5 kg mass is 33.6 m/s towards right.

the statement that current is equal to the voltage difference divided by the resistance is known as what

Answers

Answer:it is known as (Ohm's law)

Explanation:

a particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity​

Answers

Answer:

vi =2

Explanation:

Δx = 1/2 (vi + vf) t

10 = 1/2 ( vi + 8 ) 2

10 = vi + 8

10-8 = vi

vi = 2 m/s

vi= initial velocity

vf= final velocity

Δx= distance

t= time

An object has one force acting on it. It is a 33- Newton force pointing downward. To create a net force of zero on the object, which force must be applied to it?

Answers

As soon as I see "Which...", I know that the last part of the question is the list of answer choices, but you decided not to let us see them.

The answer is: A 33-Newton force pointing upward.

If the height is 10m, what is the potential energy? Asuming that the mass is 10

Answers

[tex]\huge{\textit{\sf{{\color{m}{Answer}}{\color{b}{࿐}}}}}[/tex]

we know,

[tex] \boxed{potential \: energy = mgh}[/tex]

So,

[tex]\longmapsto10 \times 9.8 \times 10[/tex]

[tex]\longmapsto980 \: joules[/tex]

A horizontal wire supports it weight in a 0.001T magnetic field, oriented orthogonally to the wire. This is due to current running from left to right in the wire. Calculate the current through this wire that will just support the weight of the wire (over the length of the wire). The length of the wire is 0.5 m, and the mass of the 0.5 m section is 50 g. [give your answer in units of Amps]

Answers

Answer:

Explanation:

Force on a current carrying wire in a magnetic field

= B i L where B is magnetic field , i is current and L is length of the wire .

Putting in the given values in the question

force on a current carrying wire in a magnetic field  = .001 T x i x .5 m

5 x 10⁻⁴ i  N .

weight of the wire = .050 kg x 9.8 m/s²

= .49 N .

For equilibrium

5 x 10⁻⁴ i  = .49

i = 980 A .

Un corredor hace los 400 metros lisos en 50 seg. Calcula la velocidad en la carrera.

Answers

Answer:

8 meters/second

Explanation:

Rate x Time = Distance

R x T = D

R x 50sec = 400meters

R x 50sec/50sec = 400meters/50sec

R = 8meters/sec

Drag each label to the correct location on the image. Not all labels will be used, Classify the sides of the mountain range based on the direction of the prevailing winds leeward side windward side Jake-effect side
WILL MARK BRAINLIEST!​

Answers

Answer:

The picture didn't go thruuuuuuu

Answer:

hi

Explanation:

hi

If you cut a permanent magnet into four pieces,
you will have what?

A) four temporary magnets
B) four smaller permanent magnets
C) two north poles and two south poles
D)four objects that are no longer magnets

Answers

you would have C) two north poles and two south poles

If a body of mass 2 kg is moving with a velocity of 30 m/s, then on doubling its velocity the momentum becomes______.
a-60kgm/s
b-120kgm/s
c-90kgm/s
D-30kgm/s​

Answers

I think it’s B. So 120kgm/s

What is the term for the force that holds protons and neutrons together in the nucleus of
an atom?
a electromagnetism
b. gravity
c. the strong force
d the weak force

Answers

Protons and neutrons are held together in a nucleus of an atom by the strong force. C hope this helped!
C is the answer I took the test

What is the frequency of microwaves of wavelength 3 cm?
Give your answer to the
nearest GHz and without units.

Answers

Answer:

10 GHz

Explanation:

Applying,

v = λf.................... Equation 1

Where v = speed of microwave, λ = wavelength, f = frequency.

make f the subject of the equation

f = v/λ................ Equation 2

Note: Microwave is an electromagnetic wave, and all electromagnetic wave have the same speed, which is 3×10⁸ m/s

From the question,

Given: λ = 3 cm = 0.03 m

Constant; v = 3×10⁸ m/s

Substitute these values into equation 2

f = 3×10⁸/(0.03)

f = 10¹⁰ Hz

f = (10¹⁰/10⁹) GHz

f = 10 GHz

A solid, uniform sphere of mass 2.0 kg and radius 1.8 m rolls from rest without slipping down an inclined plane of height 7.5 m. What is the angular velocity of the sphere at the bottom of the inclined plane

Answers

Answer:

[tex]w^2=5.5rads/s[/tex]

Explanation:

From the question we are told that:

Mass [tex]m=2.0kg[/tex]

Radius [tex]r=1.8m[/tex]

Height [tex]h=7.5m[/tex]

Generally the equation for Potential energy is mathematically given by

Potential energy=Kinetic energy+Rotational energy

 [tex]mgh=\frac{1}{2}mv^2+\frac{1}{2}Iw^2[/tex]

Since there is no slipping

 [tex]v=rw[/tex]

Therefore

 [tex]mgh=\frac{1}{2}mr^2w^2+\frac{1}{2}Iw^2[/tex]

Where

      [tex]I=\frac{1}{2}mr^2[/tex]

      [tex]l=3.24m[/tex]

 [tex]2*9.81*7.5=\frac{1}{2}(2)(1.8)^2w^2+\frac{1}{2}(3.24)w^2\\\\[/tex]

 [tex]147.15=3.24w^2+1.62w^2[/tex]

 [tex]w^2=\frac{147.15}{4.86}[/tex]

 [tex]w^2=\sqrt{\frac{147.15}{4.86}}[/tex]

 [tex]w^2=5.5rads/s[/tex]

The planets and the asteroid belt orbit the Sun in __________. Multiple Choice a spherical distribution, whereas the Oort cloud of comets orbits in a plane planes, whereas the Oort cloud of comets has a spherical distribution orbits nearly identical to the Oort cloud of comets planes tilted at an angle to the plane of the Oort cloud of comets a spherical distribution similar to that of the Oort cloud of comets

Answers

Answer:

planes, whereas the Oort cloud of comets has a spherical distribution.

Explanation:

A planet can be defined as a large celestial body having sufficient mass to allow for self-gravity and make it assume a nearly circular shape (hydrostatic equilibrium), revolves in an orbit around the Sun in the solar system and has a cleared neighborhood.

Basically, the planets are divided into two (2) main categories and these includes;

I. Outer planets: these planets are beyond the asteroid belt and comprises of jupiter, saturn, uranus and neptune, from left to right of the solar system.

II. Inner planets: these planets are the closest to the sun and comprises of mercury, venus, earth and mars.

These outer planets are made mostly of gases (hydrogen and helium) causing them to be less dense than the solid inner planets. These gases are generally known to be less dense in terms of physical properties.

Oort cloud is also referred to as Opik and it typically comprises of icy pieces of planetesimals (space debris) that spherically surrounds the sun at distances ranging from about 3000 to 100,000 AU.

Hence, the planets and the asteroid belt orbit the Sun in planes, whereas the Oort cloud of comets has a spherical distribution.

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