Answer:
34.6 cm³
Explanation:
A chemistry student needs 55.0 g of carbon tetrachloride for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of carbon tetrachloride is 1.59 g/cm³. Calculate the volume of carbon tetrachloride the student should pour out. Be sure your answer has the correct number of significant digits.
Step 1: Given data
Mass of carbon tetrachloride (m): 55.0 gDensity of carbon tetrachloride (ρ): 1.59 g/cm³Step 2: Calculate the required volume of carbon tetrachloride
Density is an intrinsic property of matter. It can be calculated as the quotient between the mass of the sample and its volume.
ρ = m/V
V = m/ρ
V = 55.0 g/(1.59 g/cm³)
V = 34.6 cm³
The chemistry student should pour 34.6 cm³ of carbon tetrachloride.
A diamond can make permanent marks on glass. It can also cut glass. Most other materſals cannot do this.Which property of a diamond allows it to make cuts or marks on glass? a. Hardness b. Heaviness c. Roughness d. transparency
Please help me out for this question.
Answer:
I wish i could help but I don't understand it .so maybe someone can come and help u
Answer:
b
Explanation:
Question List (4 items) (Drag and drop into the appropriate area) Find the volume of HCl that will neutralize the base. Find the mass (in grams) of Ca(OH)2. Calculate the number of moles of Ca(OH)2. Calculate the number of moles of H required to neutralize the base.
The question is incomplete, the complete question is:
The solubility of slaked lime, [tex]Ca(OH)_2[/tex], in water is 0.185 g/100 ml. You will need to calculate the volume of [tex]2.50\times 10^{-3}[/tex]M HCl needed to neutralize 14.5 mL of a saturated
Answer: The volume of HCl required is 290mL, the mass of [tex]Ca(OH)_2[/tex] is 0.0268g, the moles of
Explanation:
Given values:
Solubility of [tex]Ca(OH)_2[/tex] = 0.185 g/100 mL
Volume of [tex]Ca(OH)_2[/tex] = 14.5 mL
Using unitary method:
In 100 mL, the mass of [tex]Ca(OH)_2[/tex] present is 0.185 g
So, in 14.5mL. the mass of [tex]Ca(OH)_2[/tex] present will be =[tex]\frac{0.185}{100}\times 14.5=0.0268g[/tex]
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Given mass of [tex]Ca(OH)_2[/tex] = 0.0268 g
Molar mass of [tex]Ca(OH)_2[/tex] = 74 g/mol
Plugging values in equation 1:
[tex]\text{Moles of }Ca(OH)_2=\frac{0.0268g}{74g/mol}=0.000362 mol[/tex]
Moles of [tex]OH^-[/tex] present = [tex](2\times 0.000362)=0.000724mol[/tex]
The chemical equation for the neutralization of calcium hydroxide and HCl follows:
[tex]Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O[/tex]
By the stoichiometry of the reaction:
Moles of [tex]OH^-[/tex] = Moles of [tex]H^+[/tex] = 0.000724 mol
The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(2)
Moles of HCl = 0.000724 mol
Molarity of HCl = [tex]2.50\times 10^{-3}[/tex]
Putting values in equation 2, we get:
[tex]2.50\times 10^{-3}mol=\frac{0.000724\times 1000}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.000725\times 1000}{2.50\times 10^{-3}}=290mL[/tex]
Hence, the volume of HCl required is 290mL, the mass of [tex]Ca(OH)_2[/tex] is 0.0268g, the moles of
1. What is the solubility of cerium sulfate at 10 degrees Celsius?
2. What is the solubility of cerium sulfate at 50 degrees Celsius?
Answer:
1. 10 g / 100 g H₂O
2. 2 g / 100 g H₂O
Explanation:
Both questions ask about the solubility of cerium sulfate (Ce₂(SO₄)₃), meaning we need to focus on the dark blue line.
1. When X = 10 °C, the value in the Y axis is 10. So the solubility of cerium sulfate at 10 °C is 10 g/100 g H₂O.2. Simmilarly, when x = 50 °C, Y is equal to 2 g / 100 g H₂OUse one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation.
slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)
Answer:
The correct answer is 5.61 × 10⁻⁵.
Explanation:
Based on the given information, let us consider the experimentally determined value of K as 0.000717, with the value of T₁ as 45 degree C, the value of T₁ in Kelvin would be,
T₁ = 273 +45 = 318 K
The value of T₂ is 25 degree C, or (25+273) = 298 K
Based on Arrhenius equation:
ln(K₂/K₁) = -Ea/R(1/T₂ - 1/T₁)
Now putting the values in the equation we get,
ln(K₂/0.000717) = -12070 (1/298 - 1/318)
ln(K₂/0.000717) = -2.54738
K₂/0.000717 = e^-2.54738 = 0.078286
K₂ = 0.078286 × 0.000717
K₂ = 5.61 × 10⁻⁵
presented by Machar
Phosphorus pentachloride decomposes according to the chemical equation
PCI (9) PCI, (g) + Cl, (9) K = 1.80 at 250 °C
A 0.3723 mol sample of PCI; (g) is injected into an empty 4.25 L reaction vessel held at 250 °C.
Calculate the concentrations of PCI; (g) and PCI, (9) at equilibrium.
[PCI) =
M
[PC1,1 =
M
Answer:
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What is the volume in milliliters of 7.92 g of acetone?
Answer:
The volume of acetone is 9.24 mL
Explanation:
first law of the thermodynamic indicates.?
Answer:
The first law of thermodynamics states that energy can neither be created nor destroyed, only altered in form. For any system, energy transfer is associated with mass crossing the control boundary, external work, or heat transfer across the boundary. These produce a change of stored energy within the control volume.
Explanation:
A student in CEM143 was doing a fractional distillation when she noticed that the temperature suddenly started to drop. What could have caused the decrease in the temperature
Explanation:
A process where two or more number of miscible liquids present in different fractions are separated by boiling at different temperatures is called fractional distillation.
The sudden decrease in temperature is because the compounds having lower boiling point have completed the distillation before vapor of the higher boiling point can actually fill the distillation head.
Suppose 0.879 g of ammonia reacts with 28.5 mL of a hypobromite solution. Calculate the concentration of the hypobromite solution.
Answer:
0.877 M
Explanation:
Number of moles of ammonia = 0.879 g /17 g/mol = 0.05 moles
The reaction equation is ;
2NH3 + OBr-→ N2H4 + Br- + H2O
2 moles of NH3 reacts with 1 mole of hypobromite
0.05 moles of NH3 reacts with 0.05 moles ×1 mole/2 moles
= 0.025 moles
Number of moles = concentration × volume
Concentration = Number of moles / volume
Concentration = 0.025 moles × 1000/28.5
Concentration = 0.877 M
Find the pH of 0.05M Pyridine C 6 H 5 N solution. Know the base dissociation constant K C6H5N = 1.7.10 -9 .
Answer: 10
Explanation:
What’s the correct answer
Answer:
I think it's 2-methylhept-2-ene
Explanation:
Hope this will help and correct me if I'm wrong.
Draw the R enantiomer of CFClBrI as a 3-D (wedge and dotted line) structure and as a Fischer projection (putting the I at the top and the F to the right). Be able to draw Fischer projections for other simple compounds with a single chiral carbon.
The 3D structure of R- CFClBrI is drawn using wedges and dotted line with I in the top and F right to I and Fischer projection is drawn using lines for bonds where C is placed at center and I in the top with F right to it.
What is an enantiomer?An enantiomer is a spatial isomer of a compound having different spatial configuration but the same formula. Enantiomers are non-superimposable mirror images of each other.
In R- enantiomer, the elements are arranges in a way that on numbering in clockwise direction, the priority of group decreases from 1 to 2 to 3 and follows. The highest priority group is numbered first.
If the count 1..2..3 goes in anti-clockwise direction, then the enantiomer is termed as S. In 3D projection, wedges and dotted lines are used for representing bonds.
In Fischer projection, lines are used for bonds as shown in the uploaded image. Where the chiral carbon is shown in center and other groups are allotted as per the R or S configuration.
Therefore, the 3D image and Fischer projection of CFClBrI is drawn as in the image uploaded.
To learn more about, enantiomers, refer the link below:
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a) When magnesium forms a compound with oxygen, electrons are transferred from the atom to the atom. b) What type of bonding exists between the magnesium and oxygen atoms? c) Indicate the electrical charge on each of the ions and the total electrical charge on the compound.
Answer and Explanation:
Magnesium = Mg (metal) ⇒ oxidation number = +2 (it loses 2 electrons)
Oxygen = O (non-metal) ⇒ oxidation number in oxides = -2 (it gains 2 electrons)
a) We first write the chemical elements with their oxidation numbers in superscripts:
Mg⁺² O⁻²
Then, the oxidation numbers are written crossed as subscripts:
Mg₂O₂
Finally, we divide by a common denominator (2):
MgO
b) Between a metal (Mg) and a non-metal (O), the formed bond is an ionic bond. The metallic element (Mg) loses 2 electrons that are accepted by the non-metallic element (O).
c) Mg : loses 2 electrons ⇒ +2
O: gains 2 electrons ⇒ -2
The total electrical charge is: +2 + (-2) = 0
Solution A is yellow when alizarin yellow is added and blue when thymol
blue is added. Which of the following correctly identifies Solution A?
A. 3.2 x 10-4 mol/L HCI
B. 3.2 x 10-4 mol/L NaOH
C. 6.3 x 10-5 mol/L HCI
D. 6.3 x 105 mol/L NaOH
Answer:
D. 6.3 x 10-5 mol/L NaOH
Explanation:
Alizarin yellow is an indicator that is yellow when pH < 10.1. In the same way, thymol blue is blue when pH > 9
That means the pH of the solution is between 9 - 10.1
Any acid as HCl could have a pH of these.
The solution of 3.2x10⁻⁴M NaOH has a pH of:
pOH = -log[OH-] = 3.49
pH = 14-pOH = 10.51. The pH of the solution is not 10.5
Now, the solution of 6.3x10⁻⁵M NaOH has a pH:
pOH = -log[OH-] = 4.2
pH = 14-pOH = 9.8
The pH of the solution could be 9.8. Right option is:
D. 6.3 x 10-5 mol/L NaOHWhat volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g
Answer:
[tex]V'=1040ml[/tex]
Explanation:
From the question we are told that:
Initial Volume [tex]V_1=10.5mL[/tex]
Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]
Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]
Generally the equation for Acidity &Volume Relationship is mathematically given by
[tex]N_1V_1=N_2V_2[/tex]
Therefore
[tex]V_2=\frac{N_1V_2}{N_2}[/tex]
[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]
Therefore
Change in Water volume is
[tex]V'=V_2-V_1[/tex]
[tex]V'=1050ml-10ml[/tex]
[tex]V'=1040ml[/tex]
If you test an unknown organic compound and find it to be soluble in 5% aqueous NaHCO3, what functional group does it probably contain?
Answer:
carboxylic acid
Explanation:
Phenols will not be water-soluble unless a strong base is used (10% NaOH), and amines are only water-soluble if acid is used.
1. Write the structural formulas and give IUPAC names for all isorneric alcohols of molecular formula
С4Н9OH
Explanation:
Butanol (С4Н9OH)
Structural formula is :-
CH3-CH2-CH2-CH2-OH
how much reactant (KClO3) is required to produce 3.5 mil of O2
Answer:
[tex]2.3molKClO_3[/tex]
[tex]285.95gKClO_3[/tex]
Explanation:
Hello there!
In this case, according to the balanced chemical equation:
[tex]2KClO_3\rightarrow 2KCl+3O_2[/tex]
We can observe the 2:3 mole ratio in order to calculate the moles of KClO3 required for such production:
[tex]3.5molO_2*\frac{2molKClO_3}{3molO_2} \\\\2.3molKClO_3[/tex]
And in grams:
[tex]2.3molKClO_3*\frac{122.55gKClO_3}{1molKClO_3} \\\\=285.95gKClO_3[/tex]
Regards!
Regards!
A postulate is a statement recognized as a truth. The kinetic molecular theory has five postulates. Which of the following is NOT a postulate regarding the behavior of ideal gases in terms of kinetic molecular theory?
Ideal gas particles are small compared to the space between them.
Particles must not be able to move in any fixed or open container.
Their collisions must be elastic and versatile.
There are no significant interactions among the particles of a gas.
Answer:
2nd option is NOT a postulate of kinetic theory of gases
Explanation:
actually particles move in straight random motion and create bombardment with the molecules and container
The pKa of a certain weak acid is 5.0. Calculate the ratio of proton acceptor to proton donor at pH 7.0.
A) 1000:1
B) 20:1
C) 100:1
D) 40:1
Answer:
C) 100:1
Explanation:
To solve this question we must use H-H equation:
pH = pKa + log [A-] / [HA]
Where pH = 7.0, pKa = 5.0, A- is proton aceptor and HA proton donor.
Replacing:
7 = 5 + log [A-] / [HA]
2 = log [A-] / [HA]
100 = [A-] / [HA]
That means the ratio of proton aceptor:proton donor is:
C) 100:1Which sequence contains elements listed from most reactive
to least reactive?
Answer:
Transition metals, alkali metals, alkaline earth metals Transition metals - Middle of the periodic chart, only average reactivity. alkali metals - As mentioned above, very reactive. Bad choice, going from lower reactivity to higher reactivity.
Hope this answer is right!
Which formula represents a ketone?
A. CH3COCH
B.C2H5COOCH3
C. C2H5COOH
D. CH3CHO
Answer:
The simplest ketone is acetone (R = R' = methyl), with the formula CH3COCH3
CH₃COCH represent a ketone.
Hence, Option (A) is correct answer.
What is Ketone ?A ketone is functional group which contains the carbonyl group that is -C = O. The structure for ketone is R¹ - C = O - R² where R¹ and R² are alkyl group or aryl group.
Now lets check all options one by one
Option (A): CH₃COCH
CH₃COCH contains the carbonyl group with alkyl/aryl group. So it represent a ketone.
So, it is correct option.
Option (B): C₂H₅COOCH₃
C₂H₅COOCH₃ contain a -COOR which is a functional group of ester. So it does not represent a ketone.
So, it is incorrect option.
Option (C): C₂H₅COOH
C₂H₅COOH contain carboxylic group. So it does not represent a ketone.
So, it is incorrect option.
Option (D): CH₃CHO
CH₃CHO contain aldehyde group. So it does not represent a ketone.
So, it is incorrect option.
Thus, from above conclusion we can say that CH₃COCH represent a ketone.
Hence, Option (A) is correct answer.
Learn more about the Ketone here: brainly.com/question/18433258
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3. Identify the spectator ion(s) in the following reaction.
Cu(OH)2(s) + 2H+ (aq) + 2Cl(aq) → Cu2+(aq) + 2Cl(aq) + 2H2O(1)
a. Cu2+ and CV
b. Cu2+
C. Cu(OH)2
d. CT
e. Ht and CT
The spectator ion in a reaction is the one which have no role on precipitate or product formation. Here the product is water and aqueous copper chloride. Where copper ions and chloride ions are spectator ions undergoing no state change.
What is spectator ion?A spectator ion in a reaction is the ion which does not undergo any change in state and remains so in the reaction system. To identify the spectator ion we have to write the balanced complete ionic equation.
An ionic equation of a reaction represents all the ions in the reaction with their states of matter given in brackets. The charges of each ions have to be written correctly and they have to balanced in both side.
If the same ions in same state are there in both side, they can be canceled and the net ionic equation does not contain these ions. Therefore, these ions which can be canceled from the net equation is called spectator ions.
In the given reaction copper ions and Cl- ions are aqueous state on both side. Thus, they can be cancelled from net equation representing the formation of water. Hence, Cu²⁺ and Cl⁻are the spectator ions.
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Ayuda plissss es para hoy
alimientos procesados:
cereales, queso ,verduras enlatadas, un pan bocadillos salados, como patatas fritas, panecillos de salchicha, tartas y empanadas productos cárnicos, como tocino, salchicha, jamón, salami y paté comidas para microondas o comidas preparadas pasteles y galletas bebidas, como leche o refrescos
alimientos naturales
1. Pescado · 2. Brócoli o cualquiera de las verduras crucíferas · 3. Remolacha · 4. Espinacas y otras verduras de hoja verde · 5. Col rizada · 6. Mantequilla de maní · 7. Almendras.pechugas de pollo, Cordero, Salmón, Camarón,Aceite de coco,Nueces y semillas
Answer:
what
Explanation:
Based on a specific example of titration method. How do titration methods play a role in agriculture industry?
Answer:
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
Answer:
How is titration used in the industry?
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
Find the mass, in grams, of 1.40 x 1023 molecules of Nz. *
Explanation:
hi sorry I wasn't able to find Nz on periodic Table may be just missed it so just find mr of Nz and times it by moles hope this helps
Arrange the following aqueous solutions in order from smallest to greatest freezing point depression: 0.400 m CaCl2, 0.400 m glucose or 0.400 m NaCl, Then determine the freezing point depression for each. For water, Kf = 1.86°C/m.
Answer:
glucose<NaCl<CaCl2
Explanation:
Hello there!
In this case, since the general equation for the calculation of the freezing point depression is:
[tex]\Delta T=-i*m*Kf[/tex]
Whereas m and Kf are the same for the given salts, then we conclude that the greatest freezing point is exhibited by the salt with the greatest Van't Hoff's factor and the smallest freezing point with the smallest Van't Hoff's factor. In such a way, since this factor is equal to the number of ionized species, we infer that CaCl2 has i=3, glucose i=1 (nonionizing) and NaCl i=2; therefore, the order from smallest to greatest is:
glucose<NaCl<CaCl2
Regards!
what is the formula for trioxocarbonate (IV)
Answer:
[tex]CO_3^{2-}[/tex]
Explanation:
Trioxocarbonate (iv) salts result from the reaction of trioxocarbonate(iv) acid with metals and metal oxides.
All sodium, potassium, and ammonium of trioxocarbonate(iv) salts appearas to be soluble, while all others are insoluble.
Apart from Na and K, all trioxocarbonate (iv) salts breakdown to release CO2 when heated.
The formula for Trioxocarbonate (iv) is: [tex]CO_3^{2-}[/tex]
So, we can have Sodium trioxocarbonate as [tex]Na_2CO_3[/tex] and sodium hydrogen trioxocarbonate (iv) [tex]NaHCO_3[/tex]
What is the molar mass of a substance
A) the mass in grams of one mole of a substance
B) the number of particles in one gram of a substance
C) the number of moles in one gram of a substance
D) the mass in grams of one particle of a substance
thank you :)
Answer:
A) the mass in grams of one mole of a substance.
Explanation:
The molar mass of a substance is the mass in grams of 1 mole of the substance. As shown in this video, we can obtain a substance's molar mass by summing the molar masses of its component atoms. We can then use the calculated molar mass to convert between mass and number of moles of the substance.