A chemist wishes to mix a solution that is 12% acid. She has on hand 6 liters of a 4% acid solution and wishes to add some 16% acid solution to obtain the desired
12% acid solution. How much 16% acid solution should she add?
Complete the table.
Liters of
Solution
Percent Acid Liters of
(as a decimal) Pure Acid
0.04
6
Х
0.16
0.12

Answers

Answer 1

Answer:

25 liters of the 16% solution should be added.

Step-by-step explanation:

pure acid amount + pure acid amount = total pure acid amount

0.02*10          + 0.16*x           = 0.12*(10+x)     <<<---=== it is your balance equation;  x is the amount (in liters) of the 16% solution.

0.02*10 + 0.16x = 0.12*10 + 0.12*x

0.16*x - 0.12*x = 0.12*10 - 0.02*10

(0.16 - 0.12)*x = 0.12*10 - 0.02*10

x = %280.12%2A10-0.02%2A10%29%2F%280.16-0.12%29 = 25.

Answer.  25 liters of the 16% solution should be added.

Check.   %280.02%2A10+%2B+0.16%2A25%29%2F%2810+%2B+25%29 = 0.12 = 12% of concentration of the final mixture.   ! Correct !


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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Since Alex and 4 friends are playing baseball on the same team, and each time they play a game, they switch the batting order to a sequence that has not yet been used, to determine what is the maximum number of games they can play before they have to repeat a batting order they have already used, the following calculation must be performed:

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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answer:

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Question 1
If a coin is flipped 3 times, what is the probability that it will show all heads?
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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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->
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Answers

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

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Answers

Answer:

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E. Cos Z = 20 / 29

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Step-by-step explanation:

A. Determination of Sine Y

Opposite = 20

Hypothenus = 29

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Sine Y = Opposite / Hypothenus

Sine Y = 20 / 29

B. Determination of Cos Y

Adjacent = 21

Hypothenus = 29

Cos Y =?

Cos Y = Adjacent / Hypothenus

Cos Y = 21 / 29

C. Determination of Tan Y

Opposite = 20

Adjacent = 21

Tan Y =?

Tan Y = Opposite / Adjacent

Tan Y = 20 / 21

D. Determination of Sine Z

Opposite = 21

Hypothenus = 29

Sine Z =?

Sine Z = Opposite / Hypothenus

Sine Z = 21 / 29

E. Determination of Cos Z

Adjacent = 20

Hypothenus = 29

Cos Z =?

Cos Z = Adjacent / Hypothenus

Cos Z = 20 / 29

Determination of Tan Z

Opposite = 21

Adjacent = 20

Tan Z =?

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Answers

Answer:

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Step-by-step explanation:

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