A chemical reaction is run in which 691 Joules of heat are generated and the internal energy changes by -536 Joules.

Calculate w for the system.
w =
Joules

Answers

Answer 1

The work done for the system, given that the internal energy changes by -536 Joules, is 1227 joules

How do i determine the work done for the system?

From the question given above, the following data were obtained:

Heat generated (q) = 691 JoulesChange in internal energy (ΔU) = -536 JoulesWork done (W) = ?

The work done for the system can be obtained as illustrated below:

ΔU = q - w

Inputting the given parameters, we have:

-536 = 691 - w

Collect like terms

-536 - 691  = -w

-1227 = -w

Multiply through by -1

w = 1227 joules

Thus, we can conclude that the work done for the system is 1227 joules

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Related Questions

Please help!
- Which of the following compound is insoluble in water?
A. BaS
B. Hg2Cl2
C. MgSO4
D. (NH4)2CO3
E. All of these compounds are soluble in water.

thank you :)

Answers

D would be your answer !!!!
Of the compounds you listed, the correct answer is B. Hg2Cl2 (mercury(II) chloride). It is insoluble in water. The rest of the compounds (A. BaS, C. MgSO4, and D. (NH4)2CO3) are soluble in water.

What is percent abundance of 18 medium nails 5 cm long?

Answers

From the attached image, the percentage abundance of 18 medium nails 5 cm long is 19%

Understanding Percentage Abundance

The percent abundance refers to the proportion or percentage of a certain type or category within a given sample or population.

In the case of 18 medium nails that are 5 cm long, we have the information presented in the table and we do not need to do any mathematical calculations.

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