A car travels 15m east, then 5 m north, then 15m west. What is the car's
displacement?

Answer:

2 days 2 hours or 50 hours

Explanation:

800/16=50

Answer:

Explanation:

Initial velocity u = V₀ in upward direction so it will be negative

u = - V₀

Displacement s = H . It is downwards so it will be positive

Acceleration = g ( positive as it is also downwards )

Using the formula

v² = u² + 2 g s

v² = (- V₀ )² + 2 g H

= V₀² + 2 g H .

v = √ ( V₀² + 2 g H )

Answer:

4kg

Explanation:

pressure=50pa

force=200N

Area=?

now,

pressure=force/area

50=200/area

area=200/50

area=4kg

The pressure is the forces acting on a given area. Hence, the area of the surface with a pressure of 50 Pa by a force of 200 N is 4 m².

Force is an external agent acting on a object to deform it or to change its state form motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction. The unit of force is Newton (N).

Pressure is the force applied on unit area. Thus, as the force increases, pressure increases. Pressure can have the units in atm, pa, N/m² etc.

Pressure = Force / area.

Given that force = 200 N

pressure = 50 Pa = 50 N/m²

Therefore, area =  force/pressure

                          = 200 N / 50 Pa

                          = 4 m²

Therefore, the area of the surface is 4 m².

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Answer:

it all depends on the protons and the neutrons of that element.

Answer:

It starts from rest so Vi=0

Vf=10 m/s

t=5 seconds

Explanation:

a=Vf-Vi/t

a=10-0/5

a=10/5

a=2m/s^s

Answer: A. Overweight and obesity

Explanation:

Overweight and obesity are labeled for ranges of weight that are greater than what is generally considered healthy for a given height. Hence, option A is correct.

Overweight and obesity are calculated by Body Mass Index (BMI). BMI is a person's weight in kilograms divided by the square of height in meters. The healthy adult human BMI ranges from 18.5 to 25.

If BMI is less than 18.5, it falls within the underweight range. If the BMI ranges from 25.0 to 29.9, it falls within the overweight range. If the BMI is greater than 30, it comes under the obesity range. A high BMI indicates high fatness.

Obesity and overweight are determined as an abnormal growth or excessive fat accumulation in the healthy range. It is caused by an energy imbalance between calories consumed and calories expended.

Obesity and Being overweight can cause certain diseases and health issues. It increases the risk of high blood pressure, heart disease, diabetes, and stroke.

It is important to maintain a healthy range BMI. Obesity and overweight are reduced by making the choice of healthier foods and regular physical activities like yoga and exercise.

Hence, The correct option is A) Overweight and Obesity.

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The answer to your question is law.

Explanation:

maaf kalau saya salah pada jawaban anda

Answer:

690.8895705521 × 10^8 is the perfect answer of your question.

Answer:

Explanation:

Muons in the atmosphere, a component of cosmic rays. Atmospheric muons are an essential component of cosmic ray showers. When a high energy primary particle coming from space collides with a nucleus of the upper atmosphere, it generates a spray of particles which later interact in their turn.

Answer:

The answer is C

Explanation:

I ave K12 and i just finished it.

The phrase which is not an example of intracellular communication is :

C) Molecule in a cell changes function of cell.

The phrase which is not an example of intracellular communication is the molecule in a cell changes function of cell.

The intracellular communication could be a sort of communication which takes put inside a cell or interior a cell.

The intracellular speaks to inside a cell, subsequently, the development of the particle inside a cell may be with cytoplasmic gushing, cargo vesicle transport or any other instrument will speak to the intracellular communication.

Thus, the correct answer is C.

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Answer:

I think it is acute angle.

Explanation:

Because it is an angle between 0° and 90°. Hope this answer wil help you.

Answer:

A

Explanation:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased

Answer:

The correct answer is t = 0.92s

Explanation:

Initial velocity v​0 = 3.0 m/s

Displacement Δy = ?

Acceleration a = -9.8m/s2

Final velocity v = -6.0m/s

Time t=? Target unknown

We can use the kinematic formula missing Δy to solve for the target unknown t:

V=v0+at

We can rearrange the equation to solve to t:

V-v0=at

t= v-v0/a

Substituting the known value into the kinematic formula gives:

t= (-6.0m/s)-(3.0m/s)

————————————

-9.8m/s2

= -9m/s

—————-

-9.8m/s2

=0.92s

Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 m/s.  It lands on the ground with a final speed of 6.0 m/s.

How long is the ball in the air?

Answer: 0.92

Answer:

B. I looked it up I hope it's right

Explanation:

i hope this helps.

Answer:

its obviously C

Explanation:

i smart like dat

Complete Question

A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.

Answer:

The value for static friction is [tex]\mu_s = 0.60[/tex]

The value for static friction is [tex]\mu_k = 0.70[/tex]

Explanation:

From the question we are told that

The mass of the clock is [tex]m = 95 \ kg[/tex]

The first horizontal force is [tex]F _s = 560 \ N[/tex]

    The second horizontal force is    [tex]F _k  =  650  \  N[/tex]

Generally the static frictional force is equal to the first  horizontal force

So

     [tex]F _s  =  m  *  g  *  \mu_s[/tex]

=>   [tex]560  =  95  *  9.8  *  \mu_s[/tex]

=>    [tex]\mu_s =  0.60[/tex]

Generally the kinetic frictional force is equal to the second horizontal force

So

      [tex]F _k  =  m  *  g  *  \mu_k[/tex]

      [tex]650 =  95  *  9.8  *  \mu_k[/tex]

     [tex]\mu_k =  0.70[/tex]

Answer:

159 ofc

Explanation:

T1 = 2×W / squrt (3) +1

T2 = squrt(6) ×W/ squrt (3) +1

Here, T1 is along A.

T2 is along B

W = 250N.

Yo can directly use above formula to find solution.

Answer:

To reduce pressure - decrease the force or increase the area the force acts on. If you were standing on a frozen lake and the ice started to crack you could lie down to increase the area in contact with the ice. The same force (your weight) would apply, spread over a larger area, so the pressure would reduce.

Answer:

You can use the following things

Explanation:

Rubber ball - A rubber ball can decrease pressure if you throw it against the wall and catch it.

Rubber squeezy toy - If you squeeze this in your hands also you can decrease pressure.

Hope this helps....

Have a nice day!!!!

Answer:

the answer in the paper

Answer:

5a. 11m, 5b. 16m, 5c. 9m, 5d. 7m        6a. 3m, 6b. 0m, 6c. 2m, 6d. 5m

Explanation:

I hope this helped and plz make brainliest!

Answer:18 m/s

Explanation:

Take=speed=distance /time

Explanation:

The coefficient of friction = tanθ,

 the angle would be 30∘

Answer:

Tan¯¹ /3=60 degree

Explanation:

you know coefficient is friction is equal to tan 0 equal to square root of 3 is equal to tan of civil 20 skills equal to 60 degree

Answer:

What was not required by the Massachusetts Education law of 1642 is;

Children were to be sent to designated schoolmaster for their learning

Explanation:

The Law of 1642 required that parents and master see to it that their children knew the principles of religion and the capital laws of the commonwealth.

The important aspects of the 1642 Law includes;

1) The responsibility for the basic education and literacy of a child are those of the parents and masters of child apprentices

2) Reading and writing competency of all children and servants are a requirement

3) It is the duty of the government, where a parent or master are unable to meet their tutoring responsibility, to see that a child is placed where the basic educational requirement will be met.

The role of a schoolmaster or the setting of a formal school were yet to be formed as at that time.

Answer:

The correct answer is Children were to be sent to designated schoolmasters for their learning

The responsibility of educating children was on parents and apprenticeship masters, not on designated teachers or schoolmasters. However, the law did allow the government to step in if the supervising adults failed in their responsibilities.

Explanation:

Explanation:

This problem is on the motion of a car.

given data.

acceleration a=7.55m/s

time t= 4.25 sec

1. Determine the final velocity of the car.

we know that

acceleration= velocity/time

substituting our given data we have

7.55= v/4.25

v=7.55*4.25

v=32.08m/s

2.  calculate the cars displacement.

we also know that

velocity= distance/time

distance= velocity*time

distance= 32.04*4.25

distance= 136.37m

Answer:

A hydraulic braking system transmits brake-pedal force to the wheel brakes through pressurized fluid.

Explanation:

Answer:

If the height of the ramp is changed at a different height then the  speed of the car will change.

Answer:

Option (D) : - 3 m/s^2

Explanation:

Acceleration = Slope of v-t graph

= 18/6

= - 3 m/s^2 (-ive since the car is decelerating )

Answer:11

Explanation: because is the number that repeted 2 times

Answer:

The answer is

Explanation:

The velocity of w given body given the distance and time taken can be found by using the formula

[tex]velocity = \frac{distance}{time} \\ [/tex]

From the question

distance = 5 m

time = 20 s

The velocity of the ball is

[tex]velocity = \frac{5}{20} = \frac{1}{4} \\ [/tex]

We have the final answer as

Hope this helps you

Formula: v = d/t

v = velocity

d = distance

t = time

We are given the distance (5 meters) and the time (20 seconds). Solve with these given values.

v = 5/20

v = 1/4 m/s

Best of Luck!