Answer:
a= 1 m/s^2
Explanation:
Average acceleration can be found by dividing the change in velocity by the time.
a= ΔV/t
The change in velocity is the difference of the final velocity and initial velocity.
ΔV= final velocity - initial velocity
The final velocity is 30 m/s and the initial velocity is 25 m/s
ΔV= 30 m/s- 25 m/s
ΔV= 5 m/s
The time is 5 seconds.
Now we know the two values.
ΔV= 5 m/s
t= 5 s
Substitute the values into the formula.
a= 5 m/s / 5 s
Divide.
a= 1 m/s/s
a= 1 m/s^2
The average acceleration of the car is 1 meter per second squared.
A skier rides horizontally off of a 200 meter high cliff. If he lands 25 meters away from the base of the cliff, how fast was he skiing as he went off the edge?
A. 0.91 m/s
B. 2.91 m/s
C. 3.91 m/s
D. 25.91 m/s
Answer:
the answers, the correct one is C, v₀ₓ = vₓ = 3.91 m / s
Explanation:
This is a projectile launching exercise, in this case they indicate that when leaving the cliff it goes horizontally, therefore the initial vertical speed is zero, let's find the time to reach the base
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
at the base the height is zero (y = 0 m)
0 = y₀ + 0 - ½ g t²
t = √ (2y₀ / g)
we calculate
t = √ (2 200 / 9.8)
t = 6.389 s
with this time we calculate the horizontal speed
v₀ₓ = x / t
v₀ₓx = 25 / 6,389
v₀ₓ = vₓ = 3.91 m / s
When checking the answers, the correct one is C
Uniform Circular Motion: You need to design a wheel for testing purposes such that its rim will have an acceleration of 1.5 g when the rim is moving at 37 m/s while spinning. What should be the diameter of this wheel?
Answer:
We want to have an acceleration of:
A = 1.5*g = 1.5*9.8m/s^2 = 14.7 m/s^2
When the rim is moving at 37m/s while spinning.
Now, in circular motion we have two accelerations.
Tangential acceleration, that is the one related to the change of speed, as we have a speed of 37m/s, we can assume that is constant, then the tangential acceleration is zero.
Centripetal acceleration, is the one related to the change in direction, is perpendicular to the velocity vector and is the one that allows the circular motion.
I suppose that in this problem we want to have a centripetal acceleration of 14.7m/s^2
The equation for the centripetal acceleration is:
Ac = v^2/r
Where v = velocity and r = radius.
then we must solve:
14.7m/s^2 = (37m/s)^2/r
r = (37m/s)^2/14.7m/s^2 = 93.13 m
Which of the following has the greatest mass?
A. star
B. moon
C. planet
D.galaxy
Answer: I think the answer is d
Explanation: sry if wrong
A complex arrangement of pulleys forms what is called the block in a block and tackle. The rope used to lift the pulleys and the load is the tackle. A block and tackle is used to lift a truck engine, which has a weight and output force of nearly 8000 N. The input force required to lift this weight using the block and tackle is 400N. What is the mechanical advantage of the block and tackle?
Answer:
Mechanical advantage = 20
Explanation:
Given:
Output force = 8,000 N
Input force = 400 N
Find:
Mechanical advantage
Computation:
Mechanical advantage = Output force / Input force
Mechanical advantage = 8,000 / 400
Mechanical advantage = 20
18) Why do you think divergent plate boundaries and transform fault boundaries only occur at places where the crust is the same on both plates?
Answer:
A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth's mantle to the surface, solidifying to create new oceanic crust. When two plates come together, it is known as a convergent boundary.
Explanation:
plz help i really need this
Answer:
The reactivity of metals increases as you move left in a period and as you move down in a group, so Marie needs to know the period and group of the element inside each box. Boxes that show locations in groups 1 or 2 or in period 8 contain the most reactive elements.
Explanation:
Answer:
The Group Number of the elements.
Explanation:
If Marie knew the group number of the elements, then she could determine the amount of valence electrons each element has and their reactivity rate. For example, if one box tells her that an element is located in group 18, then she could determine that the element is not very reactive. This is because elements in group 18 have 8 valence electrons, which makes them stable/unreactive.
Hope this helps!
What are the Laws of conservation of atoms?
Answer:
Both the initial and final substances are composed of atoms because all matter is composed of atoms. According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and kind of atoms after the chemical change as were present before the chemical change.
Explanation:
Answer:
The law of conservation of atoms is simple but it has a great affect. An atom cannot be destroyed by such a force. Matter/atoms can't be created by any means. An atom exits only by nature and not by force.
Hope this helped! Please mark brainliest! Have a great day!
A cow standing atop a building in Times Square recalled a funny joke and began to laugh. The uncontrollable laughter caused the cow to fall over the side of the building. He fell for a time period of 3.5 s and landed in a bed of bushes. How fast was the cow moo-ving when he reached the bushes?
Which equation should be used to solve the problem?
Answer:
Vf = 34.3 m/s
1st equation of motion was used to solve.
Explanation:
In order to find the final speed of the cow, when it hits the bushes, we can use first equation of motion:
Vf = Vi + gt
where,
Vf = Final Velocity of Cow = ?
Vi = Initial Velocity of Cow = 0 m/s
g = acceleration due to gravity = 9.8 m/s²
t = time taken = 3.5 s
Therefore,
Vf = 0 m/s + (9.8 m/s²)(3.5 s)
Vf = 34.3 m/s
1st equation of motion was used to solve.
Which phrase best describes the dorsal nerve cord?
A. A group of interconnected neurons that enables response to stimuli
B. A group of similar nerve cell bodies grouped together
C. A stiff, nonconducting rod that develops down the back of all chordate embryos
D. A thick grouping of nerves that runs down the back of the embryo
Answer:
D
Explanation:
I t0ook the test and chose B and it was wrong and the answer was D.
Answer:
A thick grouping of nerves that runs down the back of the embryo
Explanation:
What made "Lunar Orbit Rendezvous" such an attractive method to get to the Moon that it was selected by NASA in July, 1962
Answer:
I don't know the answer
if the net force of 15 N is exerted on an encyclopedia to cause it to accelerate at a rate of 5 m/s2. what is the mass of the encyclopedia
Answer:
3 kg
Explanation:
F = ma
(15) = m(5)
m = 3 kg
10. Scientists created models that show a rocky asteroid crashing into a moon (less mass) a
planet (more mass). In both crashes, the asteroid was the same mass. Scientists want to kno
happened to the asteroid. Use the information in the diagram to answer.
In which crash did the asteroid experience a stronger force? How do you know?
a
Crash 2; the force on the planet was stronger in this crash, so the force on the astero
also stronger.
There was no force on the asteroid. Only the moon and planet experienced a force in
Answer:
The diagram doesn’t tell you anything about the force on the asteroid. It only gives information about the force on the planet and the moon.
Explanation:
An airplane flies north at 300.0 km/h relative to the air and the wind is blowing south at 15.0 km/h. What is the airplane’s velocity relative to the ground? *
315 km/h North
15 km/h south
285 km/h North
300 km/h South
Answer:
285
Explanation:
read and alot jbgdxtffhgdae
Calculate the acceleration of gravity that the moon has, if an astronaut has a mass of 87 kg and the weight force he experiences on the moon is 141 N
Answer:
the acceleration of gravity is 1.62
Explanation:
w=mg
141=87g
141/87=87g/87
1.62=g
May someone please help?
Air is cooled and
becomes
[denser/less dense).
Less dense air
[rises/sinks).
Denser air
(rises/sinks).
The process repeats, producing a
Air is heated and
becomes
[denser/less dense]
within the gas
Air is cooled and
becomes denser.
Denser air sinks.
The process repeats, producing a (i wasn't sure about this one)
Air is heated and becomes less dense.
Less dense air rises.
hope this helps!
PLSSSS HELPPP What effects do mutations have? Check all that apply.
A) could change protein shape
B)never change protein shape
C)might be neutral
D)always change the way a trait is observed
E)might be harmful
F)might be beneficial
Answer:
E, F, A, C
Explanation:
They cannot change the way a trait is observed
Mutations could change protein shape(A), could cause genetic disorders and harm you(E), could actually be beneficial and cause adaptations to your environment(F), or they could be neutral in which no changes are observantly notable(C).
Hope this helps
When does an object reach its terminal velocity?
Answer: Terminal velocity is achieved, therefore, when the speed of a moving object is no longer increasing or decreasing; the object's acceleration (or deceleration) is zero.
Explanation:.
Answer: Terminal velocity is achieved, therefore, when the speed of a moving object is no longer increasing or decreasing; the object's acceleration (or deceleration) is zero.
As others have said, 8 seconds to get to 90% of terminal velocity. But if you're falling from outer space, you could reach speeds much higher than terminal velocity, and slow down when you reach the atmosphere. If coming in from a long distance, you'll burn up like a meteorite.
Explanation:
At a picnic, there is a contest in which hoses are used to shoot water at a beach ball from three different directions. As a result, three forces act on the ball, F1, F2, and F3. The magnitudes of F1 and F2 are F1=50.0N and F2=90.0N. F1 acts under the angle of 60degrees with respect to the x axis and F2 is directed along the x-axis. Find the magnitude and direction of F3 such that the resultant force acting on the ball is zero.
Answer:
F₃ = 122.88 N
θ₃ = 20.63°
Explanation:
First we find the components of F₁:
For x-component:
F₁ₓ = F₁ Cos θ₁
F₁ₓ = (50 N) Cos 60°
F₁ₓ = 25 N
For y-component:
F₁y = F₁ Sin θ₁
F₁y = (50 N) Sin 60°
F₁y = 43.3 N
Now, for F₂. As, F₂ acts along x-axis. Therefore, its y-component will be zero and its x-xomponent will be equal to the magnitude of force itself:
F₂ₓ = F₂ = 90 N
F₂y = 0 N
Now, for the resultant force on ball to be zero, the sum of x-components of the forces and the sum of the y-component of the forces must also be equal to zero:
F₁ₓ + F₂ₓ + F₃ₓ = 0 N
25 N + 90 N + F₃ₓ = 0 N
F₃ₓ = - 115 N
for y-components:
F₁y + F₂y + F₃y = 0 N
43.3 N + 0 N + F₃y = 0 N
F₃y = - 43.3 N
Now, the magnitude of F₃ can be found as:
F₃ = √F₃ₓ² + F₃y²
F₃ = √[(- 115 N)² + (- 43.3 N)²]
F₃ = 122.88 N
and the direction is given as:
θ₃ = tan⁻¹(F₃y/F₃ₓ) = tan⁻¹(-43.3 N/-115 N)
θ₃ = 20.63°
which two actions would strengthen an electromagnet?
A. Add and ammeter into the circuit.
B. Decrease the size of the permanent magnet in the circuit.
C. increase the number of wraps of wire around the core.
D. Replace the magnetic core with aluminum nails.
E. Connect a second battery in the circuit.
please help!!!!, ONLY ANSWER IF YOU KNOW IT
Answer:
C. increase the number of wraps of wire around the core.
E. Connect a second battery in the circuit.
Explanation:
got the question current on a p e x
increase the number of wraps of wire around the core and Connect a second battery in the circuit are the two actions would strengthen an electromagnet.
what are the types of wiring ?
The distribution electrical power through wires in a perfect manner inside a building or a room with better load control is known as electrical wiring.
Different types of wiring such as Tee system or Joint box system where the connection of appliances is done with this wiring, which does not consume too much cable size.
Loop-in system means the system is used in lamps and other appliances are parallelly connected so that each appliance is controlled individually.
Cleat Wiring consists of ordinary VIR or PVC insulated wires is compounded on walls and ceilings by means of porcelain cleats, wood, or plastic, temporary system and is not suitable for domestic usage. For example, used in an under-construction building.
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Use the following v-t graph to answer the next questions
5
B
Velocity )
neters/second(s)
4
A
3
2
1
Time (1)
0
1
2
3
4
5
2
8
10
11
12
13
1015
16
second(s)
.1
D
-2
C С
3
5
Answer:
mag aral ka bubu
Explanation:
ang tanga mu hahahahhaha luko nandyan lang naman yan hahahhahahahahahahhahahahahahahahhahahahahahaahahahahahahahhahahahahahahahahahahahahaahhahahaahahhaahha09561782
Can two spheres of different diameters and different
masses have the same moment of inertia?
Answer:
NO
Explanation:
I=mr^2 this means moment inertia depends upon mass and square of radius or distance.
I will give 14 points & make you the brainiest
Terrestrial planets are primarily composed of what two materials?
a. hydrogen and helium
b. silicate rocks and metals
c. frozen water and methane
d. helium and iron
Answer:
B. silicate rocks and metals
Terrestrial planets, such as Earth, are primarily composed of silicate rocks and metals. The correct answer is b. silicate rocks and metals.
Silicate rocks, which are made up of silicon and oxygen, are the dominant building blocks of these planets. They include minerals like quartz, feldspar, and mica. Terrestrial planets contain significant amounts of metals such as iron, nickel, and other heavy elements. These metals are found in the planet's core, providing structural strength and contributing to the planet's magnetic field.
This composition differentiates terrestrial planets from gas giants like Jupiter and Saturn, which are predominantly composed of hydrogen and helium. The combination of silicate rocks and metals forms the solid, rocky surfaces that characterize terrestrial planets.
Therefore, The correct answer is b. silicate rocks and metals.
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Balanced Forces acting on an object will not change the object's motion. Unbalanced Forces acting on an object will change the change the object's motion.
Answer:
TRUE
Explanation:
The answer is true.
Balance forces acting on a body will not change the motion of the body because the body experiences no net resultant force in one direction. When any body experiences equal forces with opposite directions, the net force or the resultant force experience by the body is zero.
In case of an unbalanced forces, there is a net force acting in one direction and so it causes the body to change in its state of motion in the direction of the net force.
In a container of negligible mass, 0.0400 kg of steam at 100∘C100 ∘ C and atmospheric pressure is added to 0.200 kg of water at 50.0∘C50.0 ∘ C.
(a) If no heat is lost to the surroundings, what is the final temperature of the system?
(b) At the final temperature, how many kilograms are there of steam and how many of liquid water?
If no heat is lost to the surroundings, the final temperature of the system is 100 C°, At the final temperature, 0.0214 kg and 0.219 kg kilograms are there of steam and how many of liquid water
What is heat ?heat can be defined as the form of energy that is spontaneously transferred from one object to another object as the differences in temperatures is otherwise called as heat transfer.
The Heat transfer occurs upto the equilibrium point of an object has been reached.
Internal Energy is the total amount of energy of all the molecules of a body is the internal energy within the object.
Specific Heat or heat capacity, is the amount of energy required to produce a unit change in its temperature.
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The total mechanical energy of a system is 950 J and the gravitational potential energy is 350 J. What is the kinetic energy?
Answer:
The kinetic energy is 600 J
Explanation:
Mechanical Energy
The principle of the conservation of mechanical energy states that the total mechanical energy in a system remains constant as long as the only forces acting are conservative forces.
The mechanical energy is defined as the sum of the potential plus kinetic energies:
E = U + K
Where E is the total mechanical energy, U is the gravitational potential energy and K is the kinetic energy.
Solving for K:
K = E - U
The system described has a total mechanical energy of E=950 J and gravitational potential energy of U=350 J, thus:
K = 950 J - 350 J
K = 600 J
The kinetic energy is 600 J
1
Assertion (A): Potential energy of a body depends upon height of the body from the surface of earth.
Reason (R): Potential energy and height of the body from ground are directly proportional to each
other (h«<r)
a) Both A and R are true and R is the correct explanation of A
[ ]
b) Both A and R true and R is not the correct explanation of A
c) A is true but Ris false
d) A is false but R is true
beha
Answer:
a
Explanation:
it increases with increasing height
Ahmad is riding his bicycle. He finds that he can accelerate from rest at 0.44 m/s^2 for 5 s to reach a speed of 2.2 m/s. The total mass of Christian and his bicycle is 54 kg. Later, he straps some cargo onto the back of his bicycle. The mass of the cargo is 12 kg.• Calculate the force that Christian can exert on his bicycle before picking up the cargo and exerts the same force on his bicycle.
Answer:
1) The force Christian can exert on his bicycle before picking up the the cargo is 529.74 N
2) The force Christian can exert on his bicycle after picking up the the cargo is 647.46 N
Therefore, Christian has to exert more force on his bike after picking up the cargo
Explanation:
The given parameters are;
The mass of Christian and his bicycle = 54 kg
The mass of the cargo = 12 kg
1) The force Christian can exert on his bicycle before picking up the the cargo = Mass of Christian and his bicycle × Acceleration due to gravity
∴ The force Christian can exert on his bicycle before picking up the the cargo = 54 kg × 9.81 m/s² = 529.74 N
2) The force Christian can exert on his bicycle after picking up the the cargo = (54 + 12) kg × 9.81 m/s² = 647.46 N
Therefore, Christian has to exert more force on his bike after picking up the cargo.
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional questions.
Online Content: Site 1
Fitness Log
Name each of the five steps in the PRICE treatment. (Site 1)
Answer:
Protection – Protect the wounded area with a support or something similar.
Rest – Do not continue to exercise while your wound is healing. It may take a few weeks or months to recover. You may need crutches or a sling.
Ice – Wrap a bag of ice or a bag of frozen peas in a towel and apply it to the wounded area for 15–20 minutes every two to three hours.
Compression – Apply elastic compression bandages to the wounded area during the day to reduce swelling.
Elevation – Make sure the injured body part is elevated above the height of your heart as much as possible to help reduce swelling.
Explanation:
Just did it.
Answer:
The five-step process for treating a muscle or joint injury such as an ankle sprain is called "P.R.I.C.E." which is short for Protection, Rest, Ice, Compression, and Elevation).
It can be used even by someone without first-aid training, and should be used immediately when an injury occurs – the earlier, the better – while further medical attention is being sought.
If the athlete experiences too much pain during the process, stop immediately.
"P" is for Protection
Protect the injured person and the area being treated but also protect yourself. If the injury occurs on the sports field, stop the game.
Protect the area being treated with a splint if possible.
If the athlete can move, carefully move them to a safer area using a stretcher or a crutch, but if there is any doubt, do not move the injured athlete.
"R" is for Rest
When a child is injured, the body responds in an effort to defend, localize, protect, and clean up the injured area, a response called inflammation. At the time of injury small blood vessels at the injury site rupture and cause tissue bleeding, which, in turn, can cause bruising and swelling.
Explanation:
There are five warning signs of inflammation:
Pain
Redness;
Tissue hotness;
Swelling, and
Loss of function.
Not every injury exhibits all these signs, but if your child is in pain then it is important to stop exercising immediately to avoid further damage.
"I" is for Ice
As soon as possible after injury, begin applying ice continuously for the first 15-20 minutes to decrease swelling and pain.
An ice bag can be applied directly to the skin (except on the outside of the knee) unless the child has a known cold allergy.
The safest form of icing is to use a plastic bag with ice cubes or crushed ice, or instant cold packs. Do not use “blue ice” or “gel packs”.
While icing will be uncomfortable at first, in 2 to 3 minutes, the skin will go numb and the ice bag will feel more comfortable.
If the child is very uncomfortable with ice bag, then a barrier like a wet towel can be placed between the ice and skin.
The ice bag can be secured in place using an elastic bandage, but the compression should not be too tight.
During the application of the ice, ask the child to wiggle their fingers/toes and monitor tissue around area that is being iced to ensure that they are not experiencing a lost of sensation.
Icing for 15-20 minutes with an ice bag is unlikely to cause nerve damage or frostbite; however, any loss of sensation and any changes in tissue coloration in areas other than the area that is being iced indicate that the application is no longer safe.
Because ice and plastic bags are so important, make sure that someone brings these to every practice and game. Better yet, to be on the safe side, bring your own!
Snails crawl very slowly. If a garden snail crawls at 0.013 m/s north, how far will it travel in 60 seconds?
Answer:
.78 m/s north
Explanation:
Pls give brainliest if I correct
(NEED HELP ASAP)
In a lab investigation one group of students (group a) measures the speed of a 0.1 toy car to be 2.5 m/s at the bottom of a ramp another group of students (group b) measures the speed of the car to be 3 m/s at the bottom of the ramp the cars starting position at the top of the ramp is 1 m high.
a. what is the potential energy of the car at the beginning of the experiment before it's speed is measured?
b. Calculate the kinetic energy of the car for group a.
C. Calculate the kinetic energy for the car for group b.
Answer:
a = 0.98J
Explanation:
PE = mgh
PE = 0.1 x 9.8 x 1
PE = 0.98J
(a) The potential energy of the car at the beginning of the experiment is 9.8(m) J.
(b) The kinetic energy of the car for group a is 3.125(m) J.
(c) The kinetic energy of the car for group b is 4.5(m) J.
Potential energy of the car at the beginning of the experimentThe potential energy of the car is calculated as follows;
P.E = mgh
where;
m is mass of the carg is accleration due to gravityh is height of the carP.E = m x 9.8 x 1
P.E = 9.8(m) J
Kinetic energy of the car for group aK.E = ¹/₂mv²
K.E = ¹/₂ x m x (2.5)²
K.E = 3.125(m) J
Kinetic energy of the car for group bK.E = ¹/₂mv²
K.E = ¹/₂ x m x (3)²
K.E = 4.5(m) J
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