The acceleration it's the difference of speed (final speed - initial speed) divided by the time. So:
a = Δv/t
In this case the initial speed is equal to 0. The final speed is equal to 80 miles/hour. The time is 10s.
a = 80 miles/hour divided by 10 = 8 miles/hour
Answer:
8
Explanation:
Because as you can see 80/10= 8
Answer is 8
Scientists have invented the equipment to harness the power of lighting for energy use. True or false
If Newton's third law was true, then why does a table move when I push it? If the table exerted the same amount of force to me, why does it move?
A man is pulling on a rope with a force of 72 N
directed at an angle of 36◦
to the horizontal.
What is the x-component of this force?
Answer in units of N.
Answer:
57,6N
Explanation:
To find the component of a force on the x-axis we can simply do:
F * cos(36) = 72N * 0.8 = 57,6N
A 30 kg object has a frictional force of 60 N. It's coefficient of friction must be...?
A) 0.2
B) 2
C) .002
D) 20
mass = 30kg
frictional force = coefficient of friction * (mass * g)
g = 9.8 m/s^2
So:
60N = x * 294 N
x = 60 N / 294 N = 0,2
If you are in a car at a stop sign and then the driver
presses on the gas pedal really hard, which way is the car
accelerating?
Answer:
it wont be because the hand brake would be on
Jen had an average speed of 2.5 m/s when hopping on one foot. If she hopped for 5.0 seconds, for what distance was she hopping?
Explanation:
distance
speed =_________
time
distance = speed × time
= 2.5 × 5.0
distance = 12.5 m
In which situation is the net force on the object equal to zero?
A.) a bicycle moving at a constant speed on a straight, level road
B.) an automobile braking to a stop
C.) a satellite moving at a constant speed around Earth in a circular orbit
D.) a pitched baseball being hit by a bat
Answer:
A.) a bicycle moving at a constant speed on a straight, level road.
Explanation:
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
[tex] F = ma[/tex]
Where;
F represents force measured in Newton.
m represents the mass of an object measured in kilograms.
a represents acceleration measured in meter per seconds square.
In Physics, when the net force acting on a body or an object is equal to zero (0); the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.
In this scenario, the situation in which the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.
The net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.
The given problem is based on the Newton's second law to define net force. The net force on any object is an external effort by which the object change its speed with respect to time or tends to change the state of its motion. The mathematical expression for the net force is,
F = ma
Here, F is the net force, m is the mass of object and a is the acceleration of object.
When the net force acting on a body or an object is equal to zero , then the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.In the given problem the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.
Thus, we conclude that the net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.
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Name three ways you could increase the strength of an
electromagnet:
Answer:
adding more turns to the coilwrapping the coil around an iron, more specially a nail ironincreasing the current flow into the coilExplanation:
Why is it so important to train your core muscles?
Answer:
It helps prevents falls and supports your body. So having a strong core is beneficial to everyone because it allows your body to function properly. Improved Balance and Stability. Core exercises train the muscles in your pelvis, lower back, hips and abdomen to work together.
Rickey Henderson, baseball's record holder for stolen bases, approaches third base. He dives head first, hitting the ground at 6.75 m/s and reaching the base with a speed of 5.91 m/s, accelerating at -5.11 m/s 2 . Determine the distance Rickey slides across the ground before touching the base. How much time is he sliding for before touching the base?
Answer:
The distance is 1.04 m and time is 0.16 seconds.
Explanation:
Initial speed, u = 6.75 m/s
Final speed, v = 5.91 m/s
Acceleration, a = -5.11 m/s²
We need to find the distance Rickey slides across the ground before touching the base and the time he sliding for before touching the base.
Let d is the distance. It can be calculated using third equation of motion as follows :
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(5.91)^2-(6.75)^2}{2\times (-5.11)}\\\\d=1.04\ m[/tex]
Let t is the time he slides for before touching the base. Using first equation of motion as follows :
[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{5.91-6.75}{-5.11}\\\\t=0.16\ s[/tex]
So, the distance is 1.04 m and time is 0.16 seconds.
A satellite was in two separate crashes. In both crashes, the satellite had the same mass. Engineers want to know about the speed and direction of the satellite after the crashes. Why would the crash affect the motion of the satellite, and which crash caused a greater change in motion for the satellite?
Answer & Explanation:
Crashing into the asteroid would cause the satellite to slow down, stop, or reverse direction, because it is a force in the opposite direction to the satellite's motion. Whichever crash was a stronger force would cause it to change motion more. It takes a stronger force to change the velocity of a more massive object.
PLZ HELP ME
1. A stone is thrown horizontally from a cliff 30m high with an initial speed of 20m/s. How far from the cliff does the stone strike the ground?
2. A ball rolls off the edge of a table 1.44m above the floor and strikes the floor at a point 2m horizontally from the edge of the table.
A) What is the time the ball was in the air?
B) What is the initial velocity of the ball?
3. A golfer hits a ball and gives it an initial velocity of 40 m/s, at an angle of 30º above the horizontal.
A) How long does the ball stay in the air?
B) How far horizontally (the range) does the ball travel before hitting the ground?
Answer:
1. The stone will strike the ground 49.46 m from the base of the cliff
2. A) Approximately 0.542 seconds
B) Approximately 3.69 m/s
3. A) The time the ball spends in the air is approximately 4.0775 s
B) The horizontal range is approximately 141.25 m.
Explanation:
1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)
∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds
The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m
The stone will strike the ground 49.46 m from the base of the cliff
2. A) The time the ball spends in the air = t = √(h/(1/2 × g)
∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds
B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s
The initial horizontal velocity ≈ 3.69 m/s
3. A) The time the ball spends in the air is given by the following equation;
t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s
t ≈ 4.0775 s
B) The horizontal range, R, of the ball is given by the equation for the range of a projectile as follows;
[tex]Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}[/tex]
Substituting the known values, gives;
[tex]Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m[/tex]
The horizontal range ≈ 141.25 m.
to calculatw the power produced by a force, the size of the force must be known. What else needs to be known to calculate the power
-- The distance the force moved through
-- How long the force lasted
The other thing we need to calculate the power is the "Velocity".
A quantity of labor or work done to be accomplished within a particular period of timeframe is determined as power. It is denoted by "P".According to the given query, we are talking about the relation between Power and Force. Along with simple instances where such an item is moved at continuous speed by a constant force.
The relation can be shown as:
→ [tex]P= Fv[/tex]
where,
P = PowerF = Forcev = VelocityThus the above is the right response.
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A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 53.9 m/s2 . The acceleration period lasts for time 6.00 s until the fuel is exhausted. After that, the rocket is in free fall.
Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant free-fall acceleration equal to 9.80 m/s2 .
Answer:
maximum height reach by rockect =970.2metre
Explanation:
Choose ALL that apply: Read the story below and choose every sphere shown directly in the story. A volcano erupts on a mountain side. It creates a huge cloud of smoke and ash which block out the sun, making it harder for plants to grow.
Question 3 options:
Biosphere
Geosphere
Hydrosphere
Atmosphere
Answer:
biosphere
Explanation:
pretty sure bc it is ground
What is the height of a 50 kg person that has a potential energy of 4900J?
245,000m
98 m
10 m
Answer:
10 m
Explanation:
PE = mgh
m = 50kg
g= 9.8 m/s^2
h=?
so,
4900= 50×9.8× h
50h = 4900/9.8
50h = 500
h = 10 m
A dumptruck filled with sand moves 1.8 km/h when it begins to accelerate uniformly at a constant rate. After traveling 4.0 102 m, the truck's speed is 24.0 km/h. What is the magnitude of the truck's acceleration?
The acceleration of the truck is obtained from the calculation done as 0.055 m/s^2.
What is the magnitude of the truck's acceleration?We know that the acceleration is defined as the rate of the change of the velocity of the object with time and we can be able to obtain the acceleration by the use of the equations of kinematics as usual.
Initial velocity = 1.8 km/h or 0.5 m/s
Final velocity = 24.0 km/h or 6.67 m/s
Distance covered = 4.0 * 10^2 m
Then;
v^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance covered
a = v^2 - u^2/2s
a = (6.67)^2 - (0.5)^2/2 * 4.0 * 10^2
a = 44.4 - 0.25/800
a = 0.055 m/s^2
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The different odds of survival between a preterm and a full-term newborn involve: cephalic development.
the maturation of the skeletal system.
the maturation of the neurological, respiratory, and cardiovascular systems.
proximo-distal development.
Answer: B
Explanation:
A sample of oxygen gas occupies a volume of 5.0L at 90kPa pressure. What volume will it occupy at 145kPa?
A. 3.10
B. 5.10
C. 7.0
D. 2.5
Answer:
The answer is option AExplanation:
The new volume can be found by using the formula for Boyle's law which is
[tex]P_1V_1 = P_2V_2[/tex]
Since we are finding the new volume
[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]
From the question we have
[tex]V_2 = \frac{5 \times 90000}{145000} = \frac{450000}{145000} = \frac{450}{145} \\ = 3.103448...[/tex]
We have the final answer as
3.10 LHope this helps you
40 points and brainliest plz helppp luv yah thxx
A car moving at 10 m/s slows to a stop. It moves 25 meters forward while braking.
1. What is its braking acceleration?
Explain how you found your answer.
2. How much time does it take to slow to a stop?
Explain how you found your answer.
Answer:
hey want you to separate the energy’s and put them in the categories they go in like why are They different what is chemically different about them? Etc.why do they act differently.. do they act the same in some ways? Think about that
Explanation:
A stunt man launches a car from the edge of a cliff horizontally. If he is launching off a
30-meter high cliff and must hit a mark 268-meters down range, with what speed
must he leave the cliff?
Answer:
All i got to say is that he is dead dead
Explanation:
You push against a wall and the wall pushes back on you.
O Newton's 1st Law of Motion
O Newton's 2nd Law of Motion
Newton's 3rd Law of Motion
Answer:
Its the third law of motion.
Explanation:
Newton's third law of motion states that every action has equal and opposite reaction.
Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the
material.
We have that for the Question "Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material." it can be said that
From the question we are told
Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material.
Generally the equation for the index of refraction is mathematically given as
[tex]n=\frac{C}{v}\\\\Therefore\\\\n=\frac{3*10^8}{2.5 * 10 }\\\\n=12000000\\\\[/tex]
Therefore
The index of refraction of the material is
n=12000000
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A stone is thrown straight up in the air. If g represents the acceleration due to
gravity, which one of the following statments about the stone is false?
When the stone reaches the top of its flight, its acceleration is still g.
As the stone rises, its potential energy decreases.
When the stone reaches the top of its flight, its energy is zero.
As the stone rises, it is accelerated downward.
As the stone rises, its kinetic energy decreases.
Answer:
The correct false statement is;
As the stone rises, its potential energy decreases
Explanation:
When the stone is thrown straight up into the air, the initial velocity, u, progressively decreases according to the following equation;
v = u - g·t
Where;
v = The final velocity
g = The acceleration due to gravity = 9.81 m/s²
t = The time taken
Therefore whereby, the kinetic energy. K.E. is given by the equation , K.E. = 1/2 × m × u², as u reduces, the kinetic energy reduces
However, the potential energy, P.E. is given as P.E. = m × g × h
Where;
h = Height
m = The mass of the stone
Therefore, as the stone rises, the potential energy increases.
Which of the following best describes applying a force over a period of time?
power
energy
Impulse
why would a rocket fall vertically downwards if it was launched vertically upwards
Answer:
It would because the shape of the rocket is designed to be able to slice through the air as smooth as possible and now you may be thinking that air is already smooth but when you try to push something as large and heavy like a rocket then the shape of the rocket will be very important. The bottom of the rocket is flatter then the top so it is not designed to fly smoothly through the air. So the rocket would fall vertically downward(If it was still in one piece)because of it's shape. It is easier for the top of the rocket to go smoothly through the air then the bottom.
Explanation:
I am 90% sure this is correct but if I'm not please tell me
To solve this we must be knowing each and every concept related to rocket. Therefore, a rocket fall vertically downwards if it was launched vertically upwards because the bottom of a rocket is flatter than the top.
What is rocket?A rocket is indeed a vehicle that accelerates by employing jet propulsion rather than the surrounding air. A rocket engine generates thrust by reacting to high-speed exhaust.
The reason would be that the shape of a rocket is meant to slice through air as smoothly as possible. You may assume that air already is smooth, but when we try to push anything as massive and heavy as a rocket, the shape of a rocket becomes quite crucial.
Because the bottom of a rocket is flatter than the top, it isn't designed to glide through the air gracefully. Because of its form, the rocket will fall vertically downward . The tip of the rocket travels more smoothly in the air than the bottom.
Therefore, a rocket fall vertically downwards if it was launched vertically upwards because the bottom of a rocket is flatter than the top.
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Similarities and differences between natural and synthetic for sugar
Answer:
THE REAL STUFF
For starters, sugar is sugar, no matter how it’s marketed, priced or packaged. All sugar offers the same number of calories, although some may be less processed. It seems like every third day a “new” natural sugar emerges as the next best thing. Take for example, the increasingly popular coconut sugar or maple sugar, which are actually just fancy names with a heftier price tag for one ingredient: sugar. Your body can’t tell the difference between raw coconut sugar or processed table sugar, all sugar is metabolized and digested the same. While some more natural forms of sugar may contain a bit more minerals and haven’t undergone as much refinement, they really aren’t any healthier.
THE ARTIFICIAL STUFF
The most popular artificial sweeteners include sucralose (Splenda), aspartame (Equal) and saccharin (Sweet’N Low), neotame, and acesulfame-K are found in diet sodas, light yogurts or ice creams, sugar-free chewing gums and candies among other products. They’re oftentimes marketed as diet, sugar-free, calorie-free, low-calorie, skinny or light.
Artificial sweeteners are man-made, unnatural chemical compounds that our body doesn’t understand or know how to metabolize. Some scientific evidence suggests artificial sweeteners may cause brain cancer or slow down metabolism – although most of these studies have been tested on animals, never humans.
Or what about the theory that eating alternative sweeteners makes you more inclined to eat a) a whole bag of sugar-free candies at one time, and b) overindulge in junk food later. Plus, certain types of sugar alcohols or sugar substitutes contain hard-to-digest ingredients that can manifest in symptoms of gastrointestinal discomfort, like bloating, gas, cramping, diarrhea, or even constipation.
find acceleration of block and tension in strings if m1 =8kg m2= 4kg and take g=10m/s²
[tex]\sf{m_1}[/tex] = 8kg
[tex]\sf{m_2}[/tex] = 4kg
g = 10m/s²
[tex]\large\bold{\underline{\underline{To \: Find:-}}}[/tex]→Acceleration of block
→Tension in strings
[tex]\large\bold{\underline{\underline{Solution:-}}}[/tex]Let, the two equation will be ,
[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)
[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)
Putting the value of equation no (1) and (2) we get,
[tex]\implies[/tex] 4g = 12a
[tex]\implies[/tex] 4 × 10 = 12a
[tex]\implies[/tex] 40 = 12a
[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]
[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]
Again, we have to putting the value of a in the equation no (2) we get,
[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]
[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]
[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]
[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40
[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]
[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N
[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².
And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N
How much time does it take an object to fall 4.9 meter?
A) less than 1 second
B) 1 second
C) more than 1 second
Answer:
C more than 1 second
Explanation:
it will take time since its 4.9 meters and how hard you throw it down
You are making s'mores with a friend. When you heat the marshmallow over the fire, what happens to the volume of the air bubbles inside the marshmallows? *
Answer:
Heat was trapped within the marshmallow.
Explanation:
Increasing temperatures make air contained within the marshmallow extend to fill up more room, causing the versatile sugar combination to spread. Eventually, if there is so much tension? It's small explosion. But take the marshmallow out from the heat, and it's going to deflate even if the extended gelatin does not really recover quickly.
Answer:
Heat gets trapped within the marshmallow.
Explanation: