A car is traveling at 20.0 m/s on tires with a diameter of 70.0 cm. The car slows down to a rest after traveling 300.0 m. If the tires rolled without slipping, what was the magnitude of the average angular acceleration of the tires during the time the car slowed to a rest

Answers

Answer 1

Answer: deceleration of [tex]1.904\ rad/s^2[/tex]

Explanation:

Given

Car is traveling at a speed of u=20 m/s

The diameter of the car is d=70 cm

It slows down to rest in 300 m

If the car rolls without slipping, then it must be experiencing pure rolling i.e. [tex]a=\alpha \cdot r[/tex]

Using the equation of motion

[tex]v^2-u^2=2as\\[/tex]

Insert [tex]v=0,u=20,s=300[/tex]

[tex]0-(20)^2=2\times a\times 300\\\\a=\dfrac{-400}{600}\\\\a=-\dfrac{2}{3}\ m/s^2[/tex]

Write acceleration as [tex]a=\alpha \cdot r[/tex]

[tex]-\dfrac{2}{3}=\alpha \times 0.35\\\\\alpha =-\dfrac{2}{1.05}\\\\\alpha =-1.904\ rad/s^2[/tex]

So, the car must be experiencing the deceleration of [tex]1.904\ rad/s^2[/tex].

Answer 2

The angular accelaration of a car traveling at 20.0 m/s on tires with a diameter of 70.0 cm, when car slows down to rest after traveling 300.0 m is 1.91 m/s

Angular acceleration: This can be defined as the rate of change of angular velocity. The s.i unit of angular acceleration is  rad/s²

In other to solve the problem above, we will use the formula for calculating angular acceleration

a = αr.............. Equation 1

Where a = acceleration of the car's tires, α = angular acceleration of the car's tires, r = radius of the car's tires

Therefore,

α = a/r................. Equation 2

But, we need to calculate a using the equations of motion

v² = u²+2as................ Equation 3

Where v = final velocity = 0 m/s (rest), u = initial velocity= 20m/s, s = distance = 300 m

Substitute these values into equation 3

0² = 20²+2(300²)a

-400 = 600a

a = -400/600

a = -0.67 m/s²

going back to equation 2,

Given: r = 70/2 = 35 cm = 0.35 m

Substitute this values into  equation 2,

α = -0.67/0.35

α = -1.91 rad/s²

Hence, the magnitude of the angular acceleration is 1.91 rad/s²

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Related Questions

g An electron moves on a direction perpendicular to this page, into this page . The arrow below shows the direction of the magnetic field B present in this region. ----------------> B The direction of the magnetic force acting on the electron is directed

Answers

Answer:

force on the electron is upwards

Explanation:

The magnetic force is given by the relation

        F = q v x B

the bold indicates vectors, we can write the module of this expression

        F = q v  B sin θ

the direction of the force is given by the right hand rule.

If we have a positive charge, the flea points in the direction of velocity, in this case towards the inside of the page.

fingers extended in the direction of the magnetite field, in our case to the right and

the palm gives the direction of the force for a positive charge, for a negative charge it is in the opposite direction. The palm points downwards, so the force on the electron is upwards

Positive electric charges are always attracted to ________ charges.

Answers

Answer:

Negative electric charges

A pendulum that was originally erected by Foucault at the Pantheon in Paris for the Paris Exhibition in 1851 was restored in 1995. It has a 28.0 kg sphere suspended from a 67.0-m light cable. If the amplitude of the swing is 5.00 m, what is the maximum speed of the sphere

Answers

Answer:

13.1 m/s

Explanation: Given that a pendulum that was originally erected by Foucault at the Pantheon in Paris for the Paris Exhibition in 1851 was restored in 1995. It has a 28.0 kg sphere suspended from a 67.0-m light cable. If the amplitude of the swing is 5.00 m, what is the maximum speed of the sphere

The formula to use is :

W = sqrt ( L/g )

Where

L = 67m

g = 9.8m/s^2

A = 5m

Substitute all the parameters into the formula

W = sqrt ( 67 / 9.8 )

W = 2.6

To get the maximum velocity, we use the below formula.

V = wA

V = 2.6 × 5

V = 13.07 m/s

Therefore the maximum speed of the sphere is 13.1 m/s approximately.

What is reflection of light

Answers

Answer: When a ray of light approaches a smooth polished surface and the light ray bounces back, it is called the reflection of light. The incident light ray which lands upon the surface is said to be reflected off the surface. The ray that bounces back is called the reflected ray.

Have a great day and stay safe !

example of nuclear fission and nuclear fusion​

Answers

Answer:

In fission, energy is gained by splitting apart heavy atoms, for example uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. However, fusion is combining light atoms, for example two hydrogen isotopes, deuterium and tritium, to form the heavier helium.

Explanation:

I hope this helped you

(Sorry If it didn't)

5. Which of the following is velocity? *
2 points
A. 20 m/s
B. 40 m/s east
C. 40 m
D. 20 m

Answers

A. 20m/s because the unit for velocity is m/s

131_I_53 is an artificially made radioactive isotope of iodine, produced during the operation of nuclear power plants and the detonation of nuclear bombs. Exposure to high concentrations of 131 53I represents a serious risk for human health. However, small doses of this radioactive isotope are put to good use in medical studies. 131 53I is widely used in treating thyroid cancer and in diagnosis of abnormal liver and kidney function.

Required:
What is emitted when the radioactive nucleus of 131_I_53 decays to form the stable isotope of xenon 131_Xe_54?

Answers

Answer:

one beta particle

Explanation:

Since the atomic number of 131_I_53 increases by one to 131_Xe_54, we have the release of a beta particle since only a beta particle can cause a change in atomic number without a change in mass number. Since a beta particle is one electron, ₋₁⁰e, our nuclear equation is

¹³¹I₅₃ → ¹³¹X₅₄ + ₋₁⁰e

The atomic and mass numbers on both sides are balanced

mass number 131 = 131 + 0 = 131

atomic number 53 = 54 - 1 = 53

Thus a beta particle is emitted

please help me with this question​

Answers

Answer:

Answer is option d

Explanation:

,Mark as brainlist

A box has a mass of 3 kg. The box is lifted from the floor and placed
on a shelf. If the box gains a Potential Energy of 100 J, then how high
is the shelf?
a 2.34 m
b 1.20 m
C 1.50 m
d 3.40 m
HALP

Answers

Explanation:

Potential energy=MGH

100=3×10×H.

H=100/30

H=3.40m

Questions on the photo

Answers

Answer:

Option C: Third Class

Explanation:

This is third class because the effort or the input force is in the middle between the fulcrum and the load.

To solve this, we must be knowing each and every concept related to lever.  Therefore,  due to the effort or input force being in the center between the edge as well as the load, the supplied lever is of 3rd class. The correct option is option C.

What is lever?

A lever is a basic device that consists of a beam or stiff rod located at a set tight, or edge. It is used to apply force to a load and often offers a mechanical advantage.

A stiff object that can rotate about a spot on itself is called a lever. The three types of levers are categorized according to where the edge, weight, and effort are located. Due to the effort or input force being in the center between the edge as well as the load, the supplied lever is of  3rd class.

Therefore,  the correct option is option C.

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A new planet has been discovered and given the name Planet X . The mass of Planet X is estimated to be one-half that of Earth, and the radius of Planet X is estimated to be twice that of Earth. The estimated mass and radius of Planet X are used to calculate the minimum escape speed, vc , for an object launched from the surface of the planet. If the actual mass and/or radius of the planet are slightly different from the estimated values.

Required:
How will the actual escape speed va for the surface of Planet X compare to vc?

Answers

Answer:

    vₐ = v_c  [tex]( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )[/tex]

Explanation:

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

          Em₀ = K + U = ½ m v_c² - G Mm / R

final point. At a very distant point

         Em_f = U = - G Mm / R₂

energy is conserved

           Em₀ = Em_f

           ½ m v_c² - G Mm / R = - G Mm / R₂

           v_c² = 2 G M (1 /R -  1 /R₂)

if we consider the speed so that it reaches an infinite position R₂ = ∞

           v_c = [tex]\sqrt{\frac{2GM}{R} }[/tex]

now indicates that the mass and radius of the planet changes slightly

            M ’= M + ΔM = M ( [tex]1+ \frac{\Delta M}{M}[/tex] )

            R ’= R + ΔR = R ( [tex]1 + \frac{\Delta R}{R}[/tex] )

we substitute

           vₐ = [tex]\sqrt{\frac{2GM}{R} } \ \frac{\sqrt{1+ \frac{\Delta M}{M} } }{ \sqrt{1+ \frac{ \Delta R}{R} } }[/tex]

         

let's use a serial expansion

           √(1 ±x) = 1 ± ½ x +…

we substitute

         vₐ = v_ c ( [tex](1 + \frac{1}{2} \frac{\Delta M}{M} ) \ ( 1 - \frac{1}{2} \frac{\Delta R}{R} )[/tex])

we make the product and keep the terms linear

        vₐ = v_c  [tex]( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )[/tex]

The minimum escape speed, vc , for an object launched from the surface of the planet will be    [tex]v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})[/tex]

What is escape velocity of the planet?

The escape velocity is defined as the velocity required to send the object out of the gravitational influence of the earth.

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

    [tex]E_{mo} = K + U = \dfrac{1}{2} m v_c^2 - \dfrac{G Mm} { R}[/tex]

final point. At a very distant point

      [tex]E_{mf} = U = \dfrac{- G Mm }{ R_2}[/tex]

energy is conserved

         [tex]E{mo} = E{mf}[/tex]

          [tex]\dfrac{1}{2}m v_c^2 - \dfrac{G Mm} {R} = \dfrac{- G Mm }{ R_2}[/tex]

[tex]v_c^2 = 2 G M (\dfrac{1} {R} - \dfrac{ 1 }{R_2})[/tex]

if we consider the speed so that it reaches an infinite position R₂ = ∞

[tex]v_c = \sqrt{\dfrac{2GM}{R}[/tex]

         

now indicates that the mass and radius of the planet changes slightly

[tex]M ’= M + \Delta M = M(1+\dfrac{\Delta M}{M})[/tex]  

[tex]R ’= R + \Delta R = R (1+\dfrac{\Delta R}{R} )[/tex]

we substitute

   [tex]vₐ = \sqrt{\dfrac{2GM}{R} }\dfrac{\sqrt{1+\dfrac{\Delta M}{M}}} {\sqrt{1+\dfrac{\Delta R}{R}}}[/tex]

let's use a serial expansion

√(1 ±x) = 1 ± ½ x +…

we substitute

      [tex]v_a=v_c(1+\dfrac{1}{2}\dfrac{\Delta M}{M})(1-\dfrac{1}{2}\dfrac\Delta R}{R})[/tex]

Hence the minimum escape speed, vc , for an object launched from the surface of the planet will be    [tex]v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})[/tex]

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A 3 Volt battery is connected in series to three resistors: 4,6, and 2. Find the total resistance.

Answers

Answer:

The same current flows through each resistor in series. Individual resistors in series do not get the total source voltage, but divide it. The total resistance in a series circuit is equal to the sum of the individual resistances: RN(series)=R1+R2+R3+…

Why might the current in a short circuit be higher than the current in the original circuit?

Answers

Answer:

Hope this helps =)

Explanation:

The current in a short circuit may be very high because the resistance in the short circuit is probably less than the resistance in the original circuit.

Donna and Dave were participating in a lab on the properties of water. First, they tried to see how many drops of water they could fit on a penny. Then they dropped water and alcohol on waxed paper and observed what happened. Next they made a streak of water and then alcohol on the lab bench. The alcohol streak dried up and disappeared first. Donna and Dave had to write an explanation for everything that happened during the lab. How can they explain the disappearing alcohol? A) Alcohol is flammable. B) Alcohol has a lower boiling point than water. C) Alcohol has a lower melting point than water. D) Alcohol has a higher boiling point than water.

Answers

Answer:

D

Explanation:

D ok ok ok ok bye

The correct statement is that the alcohol has lower boiling point than water. The correct option is B.

What is boiling point?

At the boiling point, the pressure exerted by the surroundings on a liquid equals the pressure exerted by the liquid's vapor, under this condition, adding heat outcomes in the transformation of the liquid into its vapor without raising the temperature.

The boiling point of alcohol is low. Because there is less hydrogen bonding between ethanol molecules than between water molecules.

The ethanol requires less energy to vaporize than water, and water has a higher boiling point than ethanol.

The boiling point of a liquid can be known by utilizing the capillary method, that encompasses placing an inverted capillary in the liquid of interest as well as heating it.

Thus, the correct option is B.

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PLS ANSWER I NEED HELP

How is an electromagnetic wave (such as a radio wave) different from an ocean wave?

A) An electromagnetic wave cannot travel through empty space, but an ocean wave can.

B) An electromagnetic wave does not require a physical medium to travel through.

C) An electromagnetic wave is a longitudinal wave and an ocean wave is an oblong wave.

D) An electromagnetic wave travels more slowly than an ocean wave.

Answers

Answer:

mmmm im going to say B but i’m not sure

Explanation:

Electromagnetic waves can travel through air and unlike ocean waves or sound waves they do not need physical molecules for like a medium to travel

A 0.8 kg bead slides on a curved wire, starting
from rest at point A as shown in the figure.
The segment from A to B is frictionless, and
the segment from B to C is rough. The point
A is at height 7.1 m and the point C is at
height 2.5 m with respect to point B.

Find the speed of the bead at B. The acceleration due to gravity is 9.8 m/s2
Answer in units of m/s.

If the bead comes to rest at C, find the change
in mechanical energy due to friction as it
moves from B to C.
Answer in units of J.

Answers

a) The speed of the bead at B is 11.79m/s.

b) The change in mechanical energy due to friction as it  moves from B to C is 36.064 J.  

If we drop the object from the shelf or release the spring, that potential energy is converted back into kinetic energy. Kinetic energy can also be transferred from one body to another in a collision, which can be elastic or inelastic.

a)

Potential energy is converted  to kinetic energy

[tex]\frac{1}{2} mv^2=mgh\\\\v=\sqrt{2gh} \\\\v_B=\sqrt{2(9.8)(7.1-0)} \\\\v_B=11.79m/s[/tex]

The speed of the bead at B is 11.79m/s.

b)

[tex]W = mg(h_A) - mg(h_B) = 0.8(9.8)(7.1 - 2.5) = 36.064 J\\\\W=36.064J[/tex]

The change in mechanical energy due to friction as it  moves from B to C is 36.064 J.

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Z. A force that gives a 8-kg objet an acceleration of 1.6 m/s^2 would give a 2-kg object an
acceleration of
a. 0.2 m/s2
b. 0.4 m/s2
c. 1.6 m/s2
d. 6.4 m/s2

Answers

Answer:

[tex]\boxed {\boxed {\sf D.\ 6.4\ m/s^2}}[/tex]

Explanation:

We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.

1. Force of 1st Object

First, we can find the force of the first, 8 kilogram object.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=m \times a[/tex]

The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.

m= 8 kg a= 1.6 m/s²

Substitute these values into the formula.

[tex]F= 8 \ kg * 1.6 \ m/s^2[/tex]

Multiply.

[tex]F= 12.8 \ kg*m/s^2[/tex]

2. Acceleration of the 2nd Object

Now,  use the force we just calculated to complete the second part of the problem. We use the same formula:

[tex]F= m \times a[/tex]

This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.

F= 12.8 kg *m/s²m= 2 kg

Substitute the values into the formula.

[tex]12.8 \ kg*m/s^2= 2 \ kg *a[/tex]

Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.

[tex]\frac {12.8 \ kg*m/s^2}{2 \ kg}= \frac{2\ kg* a}{2 \ kg}[/tex]

[tex]\frac {12.8 \ kg*m/s^2}{2 \ kg}=a[/tex]

The units of kilograms cancel.

[tex]\frac {12.8}{2}\ m/s^2=a[/tex]

[tex]6.4 \ m/s^2=a[/tex]

The acceleration is 6.4 meters per square second.

En un viaje ida y vuelta de 10 kilómetros, el desplazamiento y la distancia recorrida son respectivamente.

(Respuestas en la imagen)

Answers

Answer: creo que es A o D

Explanation:

During an observation, it was noticed that light diffracts as it passes through small slits in a barrier. What does this evidence reveal about light?

It can travel in various wavelengths.
It can travel through the vacuum of space.
It demonstrates a behavior of energy.
It demonstrates a behavior of waves.

Answers

Answer:

It can travel in various wavelengths. brainliest?

Explanation:

The evidence that reveals about the light is that  It can travel in various wavelengths.

What is diffraction?

It is the wave property that should be blending of the wave related to the corners.

At the time when the wave is bending so it passed via the openings.

Also, the light diffracted via the small slits and it should be shown to arise in the water waves and the sound waves.

hence, the first option is correct.

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Which exercise type will improve a person's range of motion?

Answers

Answer:

stretching prior to an exercise is a great way to improve a range of motion, along with yoga and Pilates!

A double-slit interference pattern is created by two narrow slits spaced 0.25 mm apart. Thedistance between the first and the fifth minimum on a screen 60 cm behind the slits is 5.5mm. What is the wavelength (in nm) of the light used in this experiment

Answers

Answer:

Explanation:

Slit distance d = .25 x 10⁻³ m .

Distance of screen D = 60 x 10⁻² m

Distance between first and fifth minimum = 5.5 x 10⁻³ m .

There will be four bright fringes between first and 5 th minimum so

distance between them = 4 x λ D / d  where λ is the wavelength of light .

Substituting the values

4 x λ x 60 x 10⁻² m  /  .25 x 10⁻³ m = 5.5 x 10⁻³ m

4 x λ x 60 x 10⁻² m =  .25 x 10⁻³ m x  5.5 x 10⁻³ m = 1.375 x 10⁻⁶ m

λ = .005729 x 10⁻⁴

= 572.9 x 10⁻⁹ m

= 572.9 nm .

what do folds on a strip of paper mean

Answers

There are creases. Or just origami

Can’t figure out this problem who can figure this out and give me the answer?

Answers

According the the booklet of 1298 the amnswe will be letter B
I believe the answer i s true

What happens to matter when it reaches absolute zero?
A. Its particles speed up.
O B. Its particles have no kinetic energy.
O C. Its particles vibrate slightly.
D. Its particles gain kinetic energy.

Answers

Answer:

O C. Its particles vibrate slightly.

Explanation:

At absolute zero, atoms would occupy the lowest energy state.They move much less than at higher temperatures, but they still have small vibrations at absolute zero.

Answer:

The answer is B its particles have no kinetic energy

Explanation:

trust the big brain

The photo shows a person pumping gasoline into a car
Which TWO of these energy transformations will occur when the car’s engine starts?

A. Chemical energy —> thermal energy

B. Chemical energy —> mechanical energy

C. Mechanical energy —> Chemical energy

D. Thermal energy —> chemical energy

Choose TWO

Answers

Answer:

A&B

Explanation:

Answer:

Chemical to mechanical(b) and Chemical to Thermal(a)

How many complete wavelengths are present in the sound wave shown? O 1 o 2 4 O 6 09. ​

Answers

Answer:

2

Explanation:

What example is given of a location on Earth where this is occurring?

Answers

place's absolute location is its exact place on Earth, often given in terms of latitude and longitude. For example, the Empire State Building is located at 40.7 degrees north (latitude), 74 degrees west (longitude).

Place's absolute location is its exact place on Earth, often given in terms of latitude and longitude.

What is longitude?

A point's longitude, which might refer to the east-west position of a point on the surface of the Earth or another celestial body, is a geographic coordinate. The Greek symbol lambda is used to represent the angular measurement, which is often given in degrees.

Latitude is a coordinate used in geography that describes a point's north-south location on the surface of the Earth or another celestial body. Latitude is measured as an angle, with 0° at the Equator and values ranging from -90° at the south pole to 90° at the north pole.

Place's absolute location is its exact place on Earth, often given in terms of latitude and longitude.

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Ablock of mass m2 on arough horinzontal surfaceis connected to aball of mass m1 by alight weight cord over alight weight friction pulley as shownin figure .aforce of magnitude f at an angle

Answers

dndncbsnsndkdkksdkdndnsndnkckd

pleaaaseeeee helppppp meeeee
pleaaaseeeee helppppp meeeee
pleaaaseeeee helppppp meeeee

Answers

Answer:

The Republican party was formed because they wanted??????

Explanation:


What is the best explanation for how the plates move?

Answers

Answer:

Explanation:

Some geologists favor convection currents in the mantle as the best explanation for plate tectonic movement. It is reasonable to assume that the heat radiated from the core creates convection currents in the mantle, and the mantle rocks begin to move plastically.

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