a candle is located 12 cm from a concave mirror. The focal point of the mirror is 3.0 cm from the mirror, where is the image located?

Answers

Answer 1

Answer:

v = -4 cm

Explanation:

We have,

Distance between candle and the concave mirror, u = -12 cm

Focal length of the mirror is, f = -3 cm

It is required to find the distance from the distance where image is located. Using mirror's formula to find it:

[tex]\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}[/tex]

v is image distance

[tex]\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(-3)}-\dfrac{1}{(-12)}\\\\v=-4\ cm[/tex]

So, the image will formed at a distance of 4 cm.


Related Questions

In a parallel circuit, the blank
is the same for every leg in the circuit

Answers

Answer:

In  a parallel circuit, the blank

is the same for every leg in the circuit why?

Explanation:

Because the voltage is common across the elements of a parallel circuit, the voltage drops are all equal to each other, and the ap- plied voltage is equal to any one of thJ individual voltage drops. are also 60v. In a series circuit, the same current flows. through every component.

Answer:

voltage

Explanation:

a    p    e    x

1. Light from a laser shines through two narrow slits 0.300 mm apart and produces an interference pattern on a screen 4.35 m away consisting of 9 bright fringes over a distance of 6.4 cm. a) Draw a labeled diagram of this scenario and briefly explain how the interference pattern is created b) Calculate the wavelength of the laser. What color is it?

Answers

Answer:

Explanation:

slit separation d = .3 x 10⁻³ m

screen distance D = 4.35 m

fringe width = 6.4 x 10⁻² / 9

= .711 x 10⁻² m

a ) Interference pattern on the screen is created due to interference of two light waves coming from two slits and falling in screen . When they fall on different points on the screen they travel different distance . This is called path difference . When their path difference is equal to their wave length or its integral multiple , they reinforce each other and at that point the brightness increases . On the other hand when at a point the path difference is equal to odd multiple of half wavelength , they kill or destroy each other and darkness is found at that point . In this way dark band and bright band appear on the screen . This is called interference pattern .

b )

Fringe width  = λ D / d

Putting the values

.711 x 10⁻² = λ x 4.35 /  0.3 x 10⁻³

λ = .049 x 10⁻⁵

= 490 x  10⁻⁹

= 490 nm

The colour of this wavelength will be blue .

What are matter, particle and atom? How can you explain matter using the terms particle and atom?

Answers

Answer:

Matter is matter. Particles are particles. Atoms are atoms. You can explain matter using particles and atoms.

JK!

Real Answer:

The term matter refers to anything that occupies space and has mass—in other words, the “stuff” that the universe is made of. An atom is the smallest unit of matter that retains all of the chemical properties of an element. Most atoms contain all three of these types of subatomic particles—protons, electrons, and neutrons.

Hope this helps!

An anti-aircraft gun fires at an elevation of 60° at an enemy aircraft at 10000m above the ground At what speed must the cannon be shot to hit the plane at that height?(g=10m/s^2)​

Answers

Answer:

516m/s^2

Explanation:

Given the following :

Height of aircraft = 10000m

Acceleration due to gravity (g) = 10m/s^2

Angle of projection (θ) = 60°

Height of aircraft = maximum height

Maximum height of a projectile:

H = (u^2sin^2θ) / 2g

Where H = height

u = initial velocity

10000 = [(usinθ)^2] / 2g

10000 = [(u * sin60°) ^2] / 2*10

10000 = (0.866 * u)^2 / 20

20 * 10000 = 0.749956 * u^2

200000 = 0.749956u^2

u^2 = (200000/0.749956)

u^2 = 266,682.31

u = √266,682.31

u = 516.41292

Initial velocity (u) = 516m/s^2

Explain what the purpose of projectile motion is, and the different equations used. Explain what each equation does.

Answers

Answer:

MY friend has already described the purpose of projectile motion so I will quickly go through the uses of each equation ...

Explanation:

TIME OF FLIGHT = it is given as 2Usin tita/g...it is the total time taken to and fro...it is 2x of the time taken ....

TIME taken ..t= Usin tita / g.....is the time taken to reach the maximum height which is 1/2 the TOTALTIME OF FLIGHT GIVEN ABOVE ..

MAXIMUM HEIGHT: the maximum height is the height attained by the projectile when projected ...it is calculate using the formula = U^2 sin^2 tita / 2g

Range =Search Results

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An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin ⁡ 2 θ i g .

In an obstacle course, runners must jump hurdles that are .84 m high. If the speed of one of the athletes when he is 1.63 meters from the fence is 4m / s on the horizontal axis and 4m / s on the vertical axis. Calculate the maximum height reached and indicate whether or not the jump was successful for that runner. Help :c

Answers

Answer:

0.82 m

Explanation:

Given:

v₀ᵧ = 4 m/s

aᵧ = -9.8 m/s²

Find: Δy when vᵧ = 0 m/s

vᵧ² = v₀ᵧ² + 2aᵧΔy

(0 m/s)² = (4 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 0.82 m

The maximum height reached by the athlete is 0.82 meters.  The jump is not successful.

A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V household electricity, decreasing the resistance of the filament will _____ the current through the bulb and _____ the power dissipated by the bulb. A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V household electricity, decreasing the resistance of the filament will _____ the current through the bulb and _____ the power dissipated by the bulb. Decrease, decrease Decrease, increase Increase, increase Increase, decrease

Answers

Answer:

Increases, increases

Explanation:

The current is directly proportional to the voltage and inversely proportional to the resistance. The implication of this is that, whenever the voltage is increased, the current increases simultaneously. On the other hand, if the resistance is increased, the current will decrease accordingly and vice versa.

Recall that power is given by P= V^2/R where;

P= power, V= voltage and R= resistance

We can see that power and resistance are inversely related hence decreasing the resistance increases the power output of the lightbulb.

Answer:

Increase, increase

Explanation:

Ohm's law states that R=V/I .

This can be rearranged as I = V/R , showing that current is inversely proportional to resistance. When resistance decreases, current increases (with constant voltage).

Power dissipated by a resistor is given by the equation P = RI^2 . Showing that as R decreases and increases I, the increase to I is exponential while the decrease in resistance is not, which leads to increased power dissipation.

Evelyn walked to the store a distance of 1.6 km in 30 min. What is her average speed in m/s?

Answers

Average speed = (distance covered) / (time to cover the distance)

Average speed = (1.6 km) / (30 min)

Average speed = 0.0533 km/min

This is the true average speed, but it's not in the units that the question asked for.  So we have to massage it and convert it to ' meters/sec '.

Speed = (1.6 km) / (30 min)

Speed = (1.6 km / 30 min) x (1,000 m / 1 km) x (1 min / 60 sec)

Speed = (1.6 x 1,000 x 1) / (30 x 1 x 60) (km-m-min / min-km-sec)

Speed = (1,600 / 1,800) (m / sec)

Speed = 0.89 m/s    

A 85 kg student stands on a bridge with a 12-m-long bungee cord tied to her feet. You can assume that the bungee cord is massless and has a spring constant of 250 N/m. The student jumps off the bridge and falls until the bungee cord is fully stretched, where she comes to a stop. How far below the bridge does the student fall before coming to a stop

Answers

Answer:

  15.33 m

Explanation:

According to Hooke's law "provided the elastic limit of a material is not exceeded the extension e is directly proportional to the applied force"

Given data

mass m= 85 kg

spring constant k= 250 N/m

assuming g= 9.81 m/s^2

extension e= ?

We know that

[tex]F= ke \\mg= ke[/tex]

solving for the extension e

[tex]85*9.81= 250*e\\\e= \frac{833.85}{250} \\\e= 3.33m[/tex]

to get how far bellow the bridge the student falls before coming to stop, we have to add the extension e to the length of the bungee cord.

=12+3.33= 15.33 m

The student fall  below the bridge(12+3.33 = 15.33 m ) before coming to a stop. Where 12 is the length of bungee cord.

 

According to Hooke's law in the elastic limit of a material the the strain in the spring is directly proportional to the applied force or stress.  

Formula

[tex]\bold {F_s = -kx}[/tex]

Where,

= spring force

k = spring constant =  250 N/m

x = spring stretch or compression = ?

The force,

F = mg

[tex]\bold {F = 85 \times 9.18}\\\\\bold {F = 833.85 }[/tex]

So,

[tex]\bold {x = \dfrac {F_s }{k} }\\\\\bold {x = \dfrac {833.85} {250} }\\\\\bold {x = 3.33}[/tex]  

Therefore, the student fall  below the bridge(12+3.33 = 15.33 m ) before coming to a stop. Where 12 is the length of bungee cord.

 

To know more about Hook's Law,

https://brainly.com/question/10991960

 

   

A student of mass 40kg takes 10s to run up a flight of 50steps. If each step is 15cm high, calculate the Potential Energy of the student at the maximum height.​

Answers

Answer:

2943 J

Explanation:

Potential energy = mass x acceleration due to gravity x height in meters

(P.E. = mgh)

Substitute the given numbers: (I take acceleration due to gravity as 9.81 m s^-2)

PE = 40 x 9.81 x (0.15x50)

PE = 2943 J

State Archimedes' principle.​

Answers

Answer:

Archimedes Principle states that "any body completely or partially submerged in water is acted upon by an upthrust force which is equal to the magnitude of Weight of the body."

Answer:

We know that due to upthrust ,objects tend to lose weight when immersed in liquid.

Archimedes principle states that " If an object is partially or completely immersed in the liquid, the weight of liquid displaced by the object is its upthrust.

This law is applicable for the gaseous medium too.The weight of the displaced liquid =pgv where p is density of liquid ,g is acceleration due to gravity and v is volume of displaced liquid.

Hope this helps...

Good luck on your assignment..

Algunas fabricas de balones de fútbol ubicadas en la costa inflan los balones que van a ser vendiéndose las ciudades como pasto,tunja o bogota por debajo de su capacidad normal y cuando los balones llegan a los estudiantes, se encuentran firmes. ¿por que sucede esto? Por favor necesito su ayuda doy hartos puntos es para hoy esta tarea por fa

Answers

Answer:

balloon is rigid the amount of gas is constant inside the interior pressure of the balloon is constant and in these cities it becomes equal to or slightly higher than atmospheric pressure

Explanation:

Este ejercicio es referente a la mecánica de fluidos, usemos la expresión para la presión  

       P = ρ g h

En es el caso del balón  usemos la presión en la pared extrema, llamemos P la presión por el gas en el interior y P_ext la presión atmosférica del lugar

        cuando se llena el valor en una ciudad de baja altura la presión atmosférica es mas alta

          P_int1 < P_ext1

por lo cual la pared del balón no se mantiene rígida.

Cuando el balón es trasladado a una ciudad con mayor altura sobre el nivel del mar la presión exterior disminuye

       P_ext2 = ρ g h₂ < P_ext1

en promedio la presión disminuye con la altura  en 0,029 atm cada 250 m

por lo tanto como la cantidad de gas es constante en el interior la presión interior del globo es constante y en esta ciudades se hace igual o un poco mayor que la presión atmosférica, en consecuencia la pared del globo esta rígida

        P_int2 >P_ext2

Traslate

This exercise is related to fluid mechanics, let's use the expression for pressure

       P = ρ g h

In the case of the balloon, let's use the pressure on the extreme wall, let's call P the pressure for the gas inside and P_ext the atmospheric pressure of the place

        when the value is filled in a low-lying city the atmospheric pressure is higher

          P_int1 <P_ext1

therefore the wall of the ball does not remain rigid.

When the ball is transferred to a city with higher altitude above sea level, the external pressure decreases

       P_ext2 = ρ g h <P_ext1

on average the pressure decreases with height by 0.029 atm every 250 m

therefore as balloon is rigid the amount of gas is constant inside the interior pressure of the balloon is constant and in these cities it becomes equal to or slightly higher than atmospheric pressure, therefore the wall of the

        Pint 2> Pe

An object has a mass of 23.40 kg. If its acceleration is 28.10 m/s? what is the amount of force causing the acceleration?
A. 657.5 N
B. 0.8327 N
C. 51.50 N
D. 1.201 N​

Answers

Answer:

[tex] \boxed{\huge {\sf A. \ 657.5 \ N}} [/tex]

Given:

Mass = 23.40 kg

Acceleration = 28.10 m/s

To Find:

Amount of force causing acceleration

Explanation:

[tex] \sf Force = Mass \times Acceleration \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 23.40 \times 28.10 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 657.54 \ N \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \approx 657.5 \ N [/tex]

which statement best describes metallic bonding

Answers

Answer:

It's a type of chemical bonding that rises from the electrostatic attractive force between conduction electrons and positively charged metal bars. It can also be described as the sharing of free electrons among a structure of positively charged ions

Your question is incomplete. Please read below to find the missing content.

Metallic bonds end result because of electrostatic forces of enchantment which results while the definitely charged atoms and negatively charged atoms interaction to form an everyday electron sea version.

What is true approximately steel bonding?

Metallic bonds occur among metallic atoms. Whereas ionic bonds are part of metals to non-metals, metal bonding joins a bulk of metallic atoms. A sheet of aluminum foil and a copper cord are both places where you could see metallic bonding in action.

Learn more about electrostatic forces here: https://brainly.com/question/17692887

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What climate conditions occur during La Niña?
A.stronger prevailing winds and more hurricane activity
B.warmer Pacific waters and warmer winters
C.more hurricane activity and warmer Pacific waters
D.warmer winters and stronger prevailing winds

Answers

Answer:

A. stronger prevailing winds and more hurricane activity

Explanation:

edg2020

Answer:A

Explanation:

Find the enthalpy change per mole of sodium when sodium reacts with water. 8 grams of sodium reacts with 227 cm3 of water, producing a temperature change from 298 K to 308.4 K. The specific heat capacity of water is 4.18 J/K g. A. -28.36 kJ B. 9868.1 J C. 62.75 kJ D. -28356.7 kJ

Answers

Answer:

The correct answer to the following question will be Option A (-28.36 KJ). The further explanation is given below.

Explanation:

The given values are:

Sodium's mass = 8 grams

Water's volume = 227 cm³

Molar mass = 23 g/mol

Density of water = 1 g/cm³

Specific heat capacity ([tex]C_{w}[/tex]) = 4.18 J/Kg

As we know,

⇒  [tex]Moles \ of \ Na =\frac{mass \ of \ Na}{Molar \ mass \ of \ Na}[/tex]

On putting the estimated values, we get

⇒                        [tex]=\frac{8}{23}[/tex]

⇒                        [tex]=0.348 \ mol[/tex]

Now, Water's mass will be:

⇒  [tex]M_{w} = density\times volume[/tex]

           [tex]=1\times 227[/tex]

           [tex]=227 \ g[/tex]

Change in temperature will be:

⇒  [tex]\Delta T=(308.4-298)K[/tex]

           [tex]=10.4 \ K[/tex]

Heat released will be:

⇒  [tex]q=M_{w}\times C_{w}\times \Delta T[/tex]

On substituting the estimated values, we get

       [tex]=227\times 4.18\times 10.4[/tex]

       [tex]=9.87\times 10^3[/tex]

       [tex]=9.87 \ KJ[/tex]

So that the change in the solution of Na will be:

⇒  [tex]\Delta H=\frac{-q}{Moles \ of \ Na}[/tex]

            [tex]=\frac{-9.87}{0.348}[/tex]

            [tex]=-28.36 \ KJ/mol[/tex]

As part of previous adventures, formerly conjoined identical twin, Sue, is now 13.4 years younger than her identical twin Lou. (The anniversaries of their birth are no longer the same day.) It is Lou's turn to travel, and he goes away and back at 0.96c. During his round trip, Lou ages 1 year. What is the the difference in the twin's ages when he returns.

Answers

Answer:

Difference in Twin's Ages = 12.68 years

Explanation:

Using special theory of relativity's time dilation phenomenon, we first find the time that is passed on earth during Lou's trip.

t = t₀/[√(1 - v²/c²)]

where,

t = time measured by the person in relative motion = 1 year

t₀ = time measured by the person at rest = ?

v = speed of relative motion = 0.96 c

c = speed of light  

Therefore,

1 year = t₀/[√(1 - 0.96² c²/c²)]

1 year = t₀/[√(1 - 0.9216)]

(1 year)(0.28 year) = t₀

t₀ = 0.28 year

Let,

y = Sue's age

x = Lou's age

so,

x - y = 13.4 years

but, after this trip Lou has aged 1 year, and on earth only 0.28 years passed so, Sue has aged only 0.28 years. Therefore,

x = x + 1

y = y + 0.28

Therefore,

(x + 1 year) - (y + 0.28 year) = 13.4 years

x - y = 13.4 years - 0.72 year

x - y = 12.68 years

Difference in Twin's Ages = 12.68 years

A ball thrown straight up into the air with a speed of 10m/s. If the ball has a mass of 0.3 Kg, how high does the ball go? Acceleration due to gravity is g=9.8 m/s2

Answers

Answer:

5.10 m

Explanation:

Given that:

Initial velocity given to the ball, v = 10 m/s

Mass of the ball, m = 0.3 kg

Acceleration due to gravity, g = 9.8m/[tex]s^2[/tex]

To find: The height upto which the ball will go =  ?

Solution:

Initially, the ball will have kinetic energy and at top point the velocity will be zero, it will have only potential energy due to height.

Formula for kinetic energy and potential energy:

[tex]KE = \dfrac{1}{2}mv^2\\PE = mgh[/tex]

Applying conservation of energy principle:

[tex]\dfrac{1}{2}mv^2=mgh\\\Rightarrow \dfrac{1}{2}v^2=gh[/tex]

Putting the values of v and g to find h:

[tex]\Rightarrow \dfrac{1}{2}10^2=9.8\times h\\\Rightarrow h = \dfrac{50}{9.8}\\\Rightarrow h = 5.10\ m[/tex]

The ball will go 5.10 m high.

An alternating-current (AC) source supplies a sinusoidally varying voltage that can be described with the function v of t is equal to V times cosine of begin quantity omega times t end quantity, where V is the maximum voltage, omega is the angular frequency, and t is the time. If the frequency of this source is 60 Hz, what is omega equal to

Answers

Answer:

ω, the angular frequency of the source equals 377 rad/s

Explanation:

From the question, V(t) = V cosωt.

Now, ω = the angular frequency of the sinusoidal wave is given by

ω = 2πf where f = the frequency of the source = 60 Hz

So, the angular frequency of the source ,ω = 2π × the frequency of the source.

So, ω = 2πf

ω = 2π × 60 Hz

ω = 120π rad/s

ω = 376.99 rad/s

ω ≅ 377 rad/s

So, ω, the angular frequency of the source equals 377 rad/s

the blank waves in the electromagnetic spectrum are gamma rays

Answers

Answer:

Gamma-rays. Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions. Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells.

Explanation:

mark me brainliest if my answer is helpful.....

A body of volume 100cc immersed completely in water contained in a jar. The weight of water and jar before immersion of the body was 700gm. After immersion, what will be the weight of water and jar?

Answers

Answer:

800gm

Explanation:

Archimedes principle states that when an object is immersed in a liquid there is an apparent loss of weight of the object. This apparent loss of weight is also the upthrust experienced by the liquid. The upthrust is equal to the weight of the liquid displaced.

Following from the above statement, when the body of volume 100c.c is immersed in the water contained in the jar, the upthrust experienced is equal to the weight of the water displaced.

Note: In the question, weight is measured just using the mass.

Mass (m) is the product of density (ρ) of liquid (which is water in this case) and volume (v) of body immersed. i.e

m = ρ x v

Where;

ρ = 1 gm/cm³

v = 100c.c = 100cm³

=> m = 1 gm/cm³ x 100cm³

=> m = 100gm

Therefore the weight of water displaced is 100gm

Now, the weight of the water and jar after immersion is the sum of the weight of water and jar before immersion, and the weight of the water displaced. i.e

Weight of water and jar after immersion = 700gm + 100gm = 800gm

Generate an explanation for the following formula: P = I²R . Explain.

Answers

Answer:

Ohm's Law:

[tex]V = I R[/tex]     ------------------(1)

Where V is voltage, I is current and R is resistance.

Whereas,

P = I V   --------------------(2)

Where P is power, I is current and V is Voltage.

Putting (1) into (2)

=> P = I (I R)    [∴ V = I R]

=> P = I²R    (Derived!)

What distance does a mobile travel that with a constant acceleration of 3m / s increases its speed from 6m / s to 12m / s

Answers

Answer:

18 m

Explanation:

Given:

v₀ = 6 m/s

v = 12 m/s

a = 3 m/s²

Find: Δx

v² = v₀² + 2aΔx

(12 m/s)² = (6 m/s)² + 2 (3 m/s²) Δx

Δx = 18 m

Help Please



Energy unit conversions between electron volts (eV) and joules, (J); Einstein's photon energy equation;
Compton's momentum equation;
de Broglie's wavelength equation
Using your knowledge of these equations, quantitatively compare a 3.1 eV photon and a 3.1 eV electron by completing the following data table:
Energy (J)
Rest mass (kg)
Speed (m/s)
Wavelength (m)
Momentum (kg•m/s)

Answers

Answer:

Energy=3.1times 10^-17 J

Rest mass: 6.2 kg

Speed: 47.5 m/s

Wavelength: 2.659 times 10^-6

Momentum: 67.3 kg(m/s)

Explanation:

A particle starts to move in a straight line from
a point with velocity 10 m/s and acceleration - 20 m/s²? Find the position and velocity of the
particle at (i) t = 5s, (ii) t' = 10 s.​

Answers

Answer: s(5) = -200,  v(5) = -90

              s(10) = -900, v(10) = -190

Explanation:

Position: s(t)

Velocity:  s'(t) = v(t)                ⇒      [tex]s(t)=\int {v(t)} \, dt[/tex]

Acceleration     v'(t) = a(t)      ⇒      [tex]v(t)=\int {a(t)} \, dt[/tex]

We are given that acceleration a(t) = -20   and velocity v(t) = 10

[tex]v(t)=\int {a(t)} \, dt\\\\v(t)=\int{-20}\, dt\\\\v(t)=-20t + C \\\\v(t)=10\quad \longrightarrow \quad C=10\\\\v(t)=-20t+10[/tex]

[tex]s(t)=\int {v(t)} \, dt\\\\s(t)=\int {(-20t+10)} \, dt\\\\s(t)=-10t^2+10t\\\\[/tex]

(a) Input t = 5 into the s(t) and v(t) equations

   s(5) = -10(5)² + 10(5)           v(5) = -20(5) + 10

          =  -250  +  50                     = -100   +  10

          =       -200                          =        -90

(b) Input t = 10 into the s(t) and v(t) equations

     s(10) = -10(10)² + 10(10)           v(10) = -20(10) + 10

            =  -1000  +  100                     = -200   +  10

            =       -900                          =        -190

give four example each for newton's first,second,and thirdlaw of motion​

Answers

1st: [An airplane midflight] will maintain its direction unless maneuvered by a pilot
Kicking a ball. Driving a car, any stationary object.
2nd: [Pushing a box] the more force you put into moving the box the faster the box will move.
Ball rolling down a hill, riding a bike, batting a ball
3rd: [Jumping] your feet push against the ground
Moving car, running into a wall, paddling

Consider two sizes of disk, both of mass M. One size of disk has radius R; the other has radius 4R. System A consists of two of the larger disks rigidly connected to each other with a common axis of rotation. System B consists of one of the larger disks and a number of the smaller disks rigidly connected with a common axis of rotation. If the moment of inertia for system A equals the moment of inertia for system B, how many of the smaller disks are in system B?

Answers

Answer:

4 smaller disks

Explanation:

We are given;

Mass of smaller and larger disks = M

Radius of smaller disk = R

Radius of larger disk = 4R

Formula for moment of inertia about cylinder axis is:

I = ½MR²

Thus;

For small disk, I_small = ½MR²

For large disk, I_large = ½M(2R)² = 2MR²

We are told that moment of inertia of System A consists of two of the larger disks. Thus;

I_A = 2 × I_large = 2 × 2MR²

I_A = 4MR²

We are also told that System B consists of one of the larger disks and a number of the smaller disks. Thus;

I_B = I_large + n(I_small)

Where n is the number of smaller disks.

I_B = 2MR² + n(½MR²)

I_B = MR²(2 + n/2)

We are told that the moment of inertia for system A equals the moment of inertia for system B. Thus;

I_A = I_B

So;

4MR² = MR²(2 + n/2)

MR² will cancel out to give;

4 = 2 + n/2

Multiply through by 2 to give;

8 = 4 + n

n = 8 - 4

n = 4

2/​A mains electricity hairdryer has a resistance of 46 Ω and a current of 5 A flows through it when in use. What is the voltage across the hairdryer? (This is the mains voltage in the UK)




3/ What is the voltage across a lamp of resistance 4 Ω if a current of 2.5 A flows through it?

Please help :)

Answers

Answer:

I hope this answer will help you

Find the velocity. 10 points. Will give brainliest!

Answers

Answer:

6.060606...

Explanation:

To figure out velocity, you divide the distance by the time it takes to travel that same distance, then you add your direction to it. So the distance would be 1000m and the time would be 2 minutes and 45 seconds and if you convert the minutes into fractions you would get 165 seconds than you would divide 1000m by 165 seconds and you would get 6.060606... seconds as her average velocity

Identify the base quantities un the following
Speed
Area
Force
Distance
Plz help it's urgent

Answers

Answer:

Distance

Explanation:

Distance is the base quantity (measured in lengths) while speed, Area and Force are all derived quantities derived from base quantities.

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