A building with a wall 50m long by 4m high with sixty percent (60%) of the wall area occupied by 10 mm thick plate glass and the remainder is of 20 cm thick concrete blocks with solid concrete cores is being designed. If expected condition for site of the building has average dally air temperatures of 35°C and the interior temperature of the building will be kept at 25 °C by designed air conditioning syster, calculate the rate of heat transfer from outside to inside (heat load) due to this wall.

Answers

Answer 1

Answer: If you have "A, B, C" as answers chose the answer: "A".

Explanation:

Trust me.


Related Questions

The L-shaped object in the figure(Figure 1) consists of three masses connected by light rods.
Part A
What torque must be applied to this object to give it an angular acceleration of 1.00 rad/s2 if it is rotated about the xaxis?
Part B
If it is rotated about the y axis?
Part C
If it is rotated about the z axis (which is through the origin and perpendicular to the plane of the figure)?

Answers

The torque required, obtained by finding the product of the moment of inertia and the angular acceleration are as follows;

The torque, τ, that must be applied to the object to give it an angular acceleration of 1.00 rad/s² are;

Part A

τₓ = 9.0 N·m

Part B

[tex]\tau_y[/tex] = 10.0 N·m

Part C

[tex]\tau_z[/tex] = 19 N·m

What is an angular acceleration?

Angular acceleration is the rate of change of angular velocity with time.

The torque is found from the product of the moment of inertia and the angular acceleration, therefore;

τ = I·α

Where;

τ = The torque

I = The moment of inertia of the mass

α = The angular acceleration

The moment of inertia of a point mass is; I = m·r²

Part A

The mass rotating about the x-axis, m = 9.0 kg

The distance to the point mass, r = 1.0 m

Therefore;

Iₓ = 9.0 kg × (1.0 m)² = 9.0 kg·m²

At α = 1.00 rad/s², we get;

τₓ = 9.0 kg·m² × 1.00 rad/s² = 9.0 N·m

The torque that must be applied to give it an angular acceleration of 1.00 rad/s² if it is rotated about the x-axis is; 9.0 N·m

Part B

If it is rotated about the y-axis, we get;

m = 2.5 kg

r = 2.0 m

[tex]I_y[/tex] = 2.5 kg × (2.0 m)² = 10.0 kg·m²

[tex]\tau_y[/tex] = 10.0 kg·m² × 1.00 rad/s² = 10.0 N·m

Part C

The combined moment of inertia of the point masses are therefore;

[tex]I_z[/tex] = (9.0 + 10.0) kg·m² = 19.0 kg·m²

The torque required is therefore;

[tex]\tau_z[/tex] = 19.0 kg·m² × 1.00 rad/s² = 19.0 N·m

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The separation distance in B is _____ times greater than in A, the force of attraction is _______ than A.

Answers

The separation distance in B is two times greater than in A, the force of attraction is greater than A.

What is force of attraction?

Force of attraction is described as a force that pulls the body near due to its attraction. Some of these force of attraction include:

magnetic force, electric force, electrostatic force and gravitational force.

The force of attraction is given by the formula:

Fg = G* m1m2/r2

where

Fg is the force of attraction,

G is the gravitational constant with the value of 6.67 ×10−11 Nm2/kg2,

m1 is the mass of a body,

m2 is the mass of other body.

r is the distance between the two bodies.

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Expert help me i will mark the brainliest​

Answers

Floods are the most common type of natural disaster, occurring when an overflow of water submerges normally dry land.

What is flood about?

Floods are frequently caused in coastal areas by heavy rainfall, rapid snowmelt, or a storm surge from a tropical cyclone or tsunami.

Flooding has a negative impact on people's lives. Damage to property and infrastructure Road closures, erosion, and landslides are all possible.

It leads to destruction of houses and properties.

In order to control flooding, it is important to clear the gutters and have an adequate channel for water to pass.

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Only the first problem below please thank you so much

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The initial speed of the second ball is c. 26.8 m/s

What is speed?

Speed is the distance per unit time moved by an object/

How to find the initial speed of the ball?

Since the ball is a projectile, to find the initial speed of the second ball, we need to find the maximum height of the first ball using

h = u²sin²Ф/2g where

u = initial velocity of ball = 32 m/s, Ф = angle of projection = 57° and g = acceleration due to gravity = 9.8 m/s²

Substituting the values of the variables into the equation, we have

h = u²sin²Ф/2g

h = (32 m/s)²× (sin57°)²/(2 × 9.8 m/s²)

h = 1024 m²/s²× (0.8387)²/(19.6 m/s²)

h = 1024 m²/s²× (0.7034)/(19.6 m/s²)

h = 720.249 m²/s²/(19.6 m/s²)

h = 36.75 m

Now, since a second projectile is thrown vertically to the same maximum height, we need to find its initial speed.

Using the equation of motion v² = u² - 2gh where

u = initial speed, v = speed at maximum height = 0 m.s, g = acceleration due to gravity = 9.8 m/s² and h = maximum height = 36.75 m

Making u subject of the formula, we have

u = √(v² + 2gh)

Substituting the values of the variables into the equation, we have

u = √(v² + 2gh)

u = √[(0 m/s)² + 2 × 9.8 m/s² × 36.75 m]

u = √[0 m²/s² + 19.6 m/s² × 36.75 m]

u = √[720.3 m²/s²]

u = 26.84 m/s

u ≅ 26.8 m/s

So, the initial speed of the second ball is c. 26.8 m/s

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HURRY
Water boils at 100°C and freezes at 0°C. What best describes the molecules of water at 25°C?
A.
The particles are spread very far apart.
B.
The particles are close together and do not move.
C.
The particles are free to move easily past each other.
D.
The particles are in fixed positions.

Answers

Answer:

In be either B or C ! :))

Explanation:

Ik its not much but hope it helped for now :D

probably D because the water is close to freezing therefore it is not free to move past the other particles and the particles in ice are fairly close together but they’re not completely frozen so D would be the only logical answer

Earth's third atmosphere (atmosphere III) was a thick atmosphere of primarily water vapor and carbon dioxide.

What occurred during the third atmosphere on Earth?
Responses


a Increased oxygen allowed reptiles to thrive.

b Helium and hydrogen gases escaped Earth's gravity.

c Heat energy was retained, and water vapor condensed.

d Ultraviolet light split water vapor into hydrogen and oxygen.

Answers

During the third atmosphere on Earth, the same effect on Earth as it did on Mars. Heat energy was retained while water vapor was condensed.

What was the third atmosphere of Earth-like?

The third atmosphere on the planet was created by volcanic outgassing and comet ice. This atmosphere had no oxygen, but plenty of carbon dioxide, water vapor, nitrogen gas, and methane gas.

When Earth's crust started to cool 2.5 billion years ago, there was less water vapor in the atmosphere, and more water condensed as liquid, resulting in the formation of Earth's third atmosphere.

This atmosphere was produced by volcanic outgassing, and it was the first to survive on Earth. A planet's atmosphere did not form through accretion while the formation of the planet's star.

Instead, its atmosphere forms as a result of internal volcanic activity or the aggregation of material from comet impacts.

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6. Mikey can kick the ball to Sage with a force of 20 N, making it travel 60m. Give the work done on the ball.

Answers

Answer:

Explanation:

Given:

F =20 N

D = 60 m

________

W - ?

W = F·D = 20·60 = 1 200 J

When an object experiences balanced forces on Earth, it would be?
A)at rest
B)moving northward
C) moving southward
D) floating around.

Answers

When an object experiences balanced forces on Earth, it would be at rest (option A).

What is a balanced force?

Balanced forces are those forces that are opposite in direction and equal in size. They are considered as a state of equilibrium. Balanced forces are unable to change the motion or direction of an object i.e. they keep an object moving at a constant velocity. 

When forces are balanced, they cancel each other out, resulting in no change in motion for the object they are acting on. Unbalanced forces do not cancel each other out, and result in a change in motion for the object they are acting on.

The characteristics of balanced forces are as follows:

The condition of rest or movement of an item does not change with balanced forcesBalanced forces do not permit a moving item to shift direction or speedThe net forces acting are zero with balanced forces. 

This suggests that an object on Earth will remain at rest if it experiences balanced forces.

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The rate of decay of a radioactive sample is given by R1 at time t1 and R2 at a later time t2 . The mean life of this radioactive sample is:​

Answers

Hope this answer helps you

A boy rides his bicycle 2.08 km. The wheels have radius 25.5 cm. What is the total angle (in rad) the tires rotate through during his trip?

Answers

The total angle the tires rotate through during his trip is 8156 radian.

What is angle?

The study of shapes and their measurements falls under the umbrella of geometry, a subfield of mathematics. It also emphasises how the shapes are arranged in relation to one another and their spatial characteristics. We are aware that geometry is divided into 2D and 3D categories.

All geometrical shapes are first created by the intersection of points, lines, rays, and plane surfaces. The distance between the two lines is known as a "Angle" when the two lines or rays converge at a single location.

Given that:

A boy rides his bicycle 2.08 km.

The wheels have radius 25.5 cm.

So, perimeter of the wheel = 2πr = 2π×25.5 cm = 160.22 cm.

Total angle  the tires rotate through during his trip

= ( 2.08 km/ 160.22 cm)× 2π

=  8156 radian.

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A uniform 1.2-kg rod that is 0.67 m long is suspended at rest from the ceiling by two springs, one at each end of the rod. Both springs hang straight down from the ceiling. The springs have identical lengths when they are unstretched. Their spring constants are 65 N/m and 30 N/m. Find the angle that the rod makes with the horizontal.

Answers

The angle that the rod makes with the horizontal is 9⁰.

What is the vertical direction for left spring?

The vertical direction of the left spring is determined  by applying the principle of equilibrium force as shown below.

The given parameters;

mass of the rod, m = 1.2 kgweight of the rod, w = mg = 1.2 x 9.8 = 11.76 Nspring constant for left spring, K_L = 65 N/mspring constant for right spring, K_r = 30 N/mstretch in the left spring, = X_Lstretch in the right spring, = X_r length of the rod, L  = 0.67 mangle the rod makes with the horizontal, θ = ?

Apply the principle of equilibrium of force in vertical direction for left spring;

K_L(X_L) = 0.5(W)

65(X_L) = 0.5(11.76)

X_L = 5.88/65

X_L = 0.09 m

Apply the principle of equilibrium of force in vertical direction for right spring;

K_r(X_r) = 0.5(W)

30(X_r) = 0.5(11.76)

X_r = 5.88/30

X_r = 0.196 m

The angle made with the horizontal is calculated as;

θ = arc tan(X_r - X_L) / L

θ = arc tan[(0.196 - 0.09) / 0.67]

θ = arc tan(0.158)

θ = 8.99⁰

θ ≈ 9⁰

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A 12 kg chair initially at rest on a horizontal floor requires a 112 N horizontal force to set it in motion.

Calculate the coefficient of static friction.

Round your answer to two decimal places (the hundredth place). You do not need to include units.

Answers

Explanation:

0.98

The coefficient of static friction is calculated by dividing the force required to set the chair in motion (112 N) by the weight of the chair (12 kg). This gives us 112/12 = 9.3. The coefficient of static friction is equal to the ratio of the force required to set the chair in motion to the weight of the chair, so 9.3/9.8 = 0.98.

Which statement about dwarf planet locations is correct

Answers

The correct statement about dwarf planet locations is :

Ceres is found in the asteroid belt and Eris, Makemake, Haumea, and Pluto are found in the Kuiper Belt.

What are  dwarf planets?

A dwarf planet is described as a small planetary-mass object that is in direct orbit of the Sun, smaller than any of the eight classical planets but still a world in its own.

There are as of now five formally grouped dwarf planets in our solar system and they include:

Ceres, Pluto, Haumea, Makemake and Eris.

Ceres location is that it is situated inside the asteroid belt between the orbits of Mars and Jupiter, while the other smaller person planets are situated in the external nearby planetary group in, or close to, the Kuiper belt.

Another six articles are in all likelihood predominate planets, yet are sitting tight for official grouping, and there might be upwards of 10,000 diminutive person planets in the solar system.

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Complete question:

Which statement about dwarf planet locations is correct?

Eris is found in the Kuiper Belt and Makemake, Haumea, Ceres, and Pluto are found in the asteroid belt.

Ceres is found in the asteroid belt and Eris, Makemake, Haumea, and Pluto are found in the Kuiper Belt.

Ceres and Pluto are found in the Kuiper Belt and Makemake, Eris, and Haumea are found in the asteroid belt.

Haumea and Makemake are found in the asteroid belt and Pluto, Ceres, and Eris are found in the Kuiper Belt.

heat flow occurs between two bodies in thermal contact. which property determines the direciton of heat flow

Answers

When two items with different temperatures come in contact with one another, energy moves from the hotter (higher temperature) object to the cooler (lower temperature) object until both objects reach the same temperature.

What is thermal contact?

Once the temperatures are identical, there is no net heat transfer since the quantity of heat transported from one object to the next and the amount of heat radiated are equal.

Temperature change is one of the main consequences of heat transfer: Cooling brings down the temperature while heating brings it up.

Experiments reveal that three factors—the change in the substance's temperature, its mass, and specific physical characteristics associated to the substance—have an impact on how much heat is transported to or from a substance.

Therefore, When two items with different temperatures come in contact with one another, energy moves from the hotter (higher temperature) object to the cooler (lower temperature) object until both objects reach the same temperature.

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31. Box A of mass m sits on the floor of an elevator, with box B of mass 2 m on top of it, as shown in the figure above. The elevator is moving upward and slowing down. F_A is the magnitude of the force exerted on box A by box B, F_B is the magnitude of the force exerted on box B by box A, and F_g is the magnitude of the gravitational force exerted on box B. Which of the following ranks the forces in order of increasing magnitude?
(A) F_B=F_A=F_g
(B) (F_B=F_A) (C) F_B<(F_A=F_g)
(D) F_g

Answers

The rank of the forces in order of increasing magnitude is Fg < FB < FA.

option D is the correct answer.

What is the net force on elevator moving upwards?

The net force on an elevator moving upwards is determined by the force of gravity acting downwards and the normal force of the elevator acting upwards.

That is, the two forces acting on a person when he is moving in an elevator are:

the force of gravity and the normal force by the elevator.

When the two forces are of equal magnitude, the elevator will be static or moving with constant velocity.

When the magnitude of the two force are unequal, then the elevator will be accelerating upward or downward.

Since the elevator is moving upwards, it implies that the normal force is greater than the force of gravity acting downwards.

the normal force = FB + FAForce of gravity = Fg

The box at the bottom will feel much heavier due to the weight of box and gravity acting downwards.

FA = FB + Fg

Thus, the force exerted on box A is the greatest, followed by the force on box B and then, the smallest is force of gravity.

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An ice hockey player begins at one goal and skates forward at constant speed to the other goal, 54 meters away, in a time of 9
seconds. He then instantly reverses direction and and skates 27 m backwards, in an additional 6 seconds.
Considering "forwards" to be the positive direction, what is the player's total displacement and average velocity over the whole 15
seconds?

Answers

Answer:21

Explanation:

it is trust

The speeds of a 600-kg roller coaster car at the top of three consecutive hills are shown below. The radii of the hills are shown. Determine the acceleration, net force, and normal force experienced by the car at the top of each hill.

Answers

Answer:

they will fly

Explanation:

yes flying is fun

The acceleration, net force, and normal force by the car at the top of hill A are 4.5  meter/second² , 3180 N and 3180 N.

The acceleration, net force, and normal force by the car at the top of hill B are 4.17  meter/second² , 3379N and 3379 N.

The acceleration, net force, and normal force by the car at the top of hill C are 4.0  meter/second² , 3480 N and 3480 N.

What is centripetal acceleration?

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

On hill A;

The centripetal acceleration = v²/r = 6²/8 meter/second² = 4.5  meter/second² .

The net force = m(g -a) = 600 (9.8 - 4.5) N = 3180 N.

The  normal force = 3180 N

On hill B;

The centripetal acceleration = v²/r = 5²/6 meter/second² = 4.17 meter/second² .

The net force = m(g -a) = 600 (9.8 - 4.17) N = 3379 N.

The  normal force = 3379 N.

On hill A;

The centripetal acceleration = v²/r = 4²/4 meter/second² = 4.0 meter/second² .

The net force = m(g -a) = 600 (9.8 - 4.0) N = 3480 N.

The  normal force = 3480 N.

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I NEED ASAP
What part of the water cycle involves convection transporting water?
A.
rainfall being absorbed by the ground
B.
rain forming and falling from the sky
C.
water evaporating and rising into the air
D.
flow of water down a stream

Answers

I believe its C because heat is being transferred by the movement of water.

I NEED ASAP

Heat energy in the atmosphere always moves _____.

A.
from cloudy to clear regions
B.
from low pressure to high pressure regions
C.
from high temperature to low temperature areas
D.
from low temperature to high temperature areas

Answers

Answer:

from high temperature to low temperature areas

Explanation:

If it is correct, could you please give me brainliest? I would really appreciate it! Thank you!

You measure the period of a pendulum and get 25s. What is the length of the pendulum?

Answers

Answer:

Explanation:

T = 25 s

25 = 2*pi*sqrt(L/9.8)

L = 155.14 m

a 0.2 kg vase has a potential energy of 100j

Answers

The height above the ground in which the vase is raised is 51.02 m.

What is the height of the vase?

The height above the ground in which the vase is raised is calculated by applying the formula for gravitational potential energy.

Gravitational potential energy of an object is the energy possessed by the object due to the object's position above the ground.

Mathematically, the formula for gravitational potential energy is given as;

P.E = mgh

where;

m is the mass of the objectg is acceleration due to gravityh is the height above the ground in which the object is raised

The given parameters include;

mass of the vase = 0.2 kg

potential energy of the vase = 100 J

acceleration due to gravity = 9.8 m/s²

h = P.E / mg

h = (100) / (0.2 x 9.8)

h = 51.02 m

Thus, the height of the vase is a function of the potential energy and mass of the vase.

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The complete question is below:

a 0.2 kg vase has a potential energy of 100j. What is the height of the vase?

Bryan rolls a 2kg ball across a rough, grassy field. The field slows the ball with an acceleration of -0.5 m/s^2.
a. Draw the FBD
b. Determine the frictional force the field acts on the ball.

Answers

The drawing of free body diagram is attached in answer.

The frictional force the field acts on the ball is 1 newton.

What is acceleration?

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Mass of the ball: m = 2 kg.

Acceleration of the ball during slow down: a =   -0.5 m/s².

We have to find:  the frictional force the field acts on the ball: f =?

In this case,   the frictional force the field acts on the ball: f = mass × acceleration = 2 kg × 0.5 m/s² = 1 newton.

Hence, the frictional force the field acts on the ball is 1 newton.

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There are 100 g of lodine-131. After 16 days, how many grams of lodine-131 is left?

Answers

Answer:

25g

Explanation:

According to a quick internet search, the half-life of I-131 is 8 days.

The amount left after 16 days can be calculated with the radioactive exponential decay formula:

[tex]A_(_t_)=A_0e^(^\frac{\ln(.5)}{T}^)^t[/tex]

Where:

[tex]A_(_t_)[/tex] = the amount left as a function of time

[tex]A_0[/tex] = the original amount (100g)

T = the half-life of the isotope (8d)

t = time (16d)

So:

[tex]A_(_t_)=A_0e^(^\frac{\ln(0.5)}{T}^)^t\\A_(_t_)=(100g)e^(^\frac{\ln(0.5)}{8d}^)^(^1^6^d^)\\A_(_t_)=(100g)e^-^2^(^\ln(2))[/tex]

[tex]A_(_t_)=25g[/tex]

This answer is intuitive because the isotope has been through two half-lives:

[tex]100g(\frac{1}{2})(\frac{1}{2})=25g[/tex]

Franscisco wants to invesitgate how changing the shape makes the same amount of ice melt faster or slower when placed in a water bath. Which two column headings describe controlled variable?

Answers

The two column headings describe controlled variable be: pressure and temperature.

What is control variable?

Anything kept constant or constrained in a research study is referred to as a control variable. Despite not being relevant to the study's objectives, this variable is controlled because it might have an impact on the results.

Variables can be controlled either directly by maintaining their value throughout a study (for example, by maintaining a constant room temperature in an experiment) or indirectly by using techniques like randomization or statistical control (e.g., to account for participant characteristics like age in statistical tests). Research biases like omitted variable bias can be avoided by including control variables in your analysis.

In the case of Franscisco wants to investigate how changing the shape makes the same amount of ice melt faster or slower when placed in a water bath, the two column headings describe controlled variable be: pressure and temperature.

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Earth’s surface contains a variety of landforms, formed by weathering and erosion. Which of the following describes a change to Earth’s surface due to weathering? Choose the three that apply.

Answers

The following describes a change to Earth’s surface due to weathering include the following below:

A. plants creating a crack in a rock formation

B. rocks along the beach being reshaped by wave action.

F. glaciers scraping rocks across the land

What is Weathering?

This is referred to as the process which involves the breaking down of rocks and minerals on Earths surface as a result of certain factors such as rain, glacier etc. They form cracks when they come in contact with rocks afterf a given period of time before they are disintegrated.

Weathering occurs when plants creating a crack in a rock formation and also when the rocks along the beach are being reshaped by wave action.It also involves the  glaciers scraping rocks across the land which is therefore the reason why option A, B and F was chosen as the correct choice.

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The options are:

A. plants creating a crack in a rock formation

B. rocks along the beach being reshaped by wave action

C. sand being blown to a new location by the wind

D. sediments moved from place to place by a river

E. rain washing soil down a steep hill

F. glaciers scraping rocks across the land

The moon's gravity is one-sixth that of the earth. How does the period of a 0.50m long pendulum on the moon compare to the period of the same pendulum on Earth?
Question 20 options:

The period is the same on the moon and on Earth.

The period on Earth is longer.

There isn't enough information to answer the question.

The period on the moon is longer.

Answers

The period on the moon is longer. So, the option(D) is correct.

What is a simple pendulum?

A basic pendulum is a machine in which the point mass is hung from a fixed support by a light, inextensible string. The mean position of a simple pendulum is shown by a vertical line flowing through a fixed support.

The length of the simple pendulum, abbreviated L, is the vertical distance between the point of suspension and the suspended body's center of mass (when it is in mean position). The resonant mechanism supporting this type of pendulum has a single resonant frequency.

Time period of a pendulum is given by: T = 2π√(l/g)

Where:  l =  length of the pendulum and g = acceleration due to gravity.

As the moon's gravity is one-sixth that of the earth, we can conclude from the expression of pendulum that  the period on the moon is longer.

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Help me please I need it as soon as possible

Answers

Answer: B im sorry if its wrong

Explanation:

I think the answer would be D

A frozen salmon is sliding across the sea in ice in the +X^ direction. A hungry polar bear does -40J of the work and stops the salmon. If the polar bear applied its force over 0.5m, what force did it apply (include direction)?

Answers

A hungry polar bear does -40J of the work and stops the salmon. If the polar bear applied its force over 0.5m. The force is 80 Newton.

What is Force?

A force is an effect that can alter an object's motion according to physics. A force can cause an object with mass to accelerate when it changes its velocity, for as when it moves away from rest. An obvious way to describe force is as a push or a pull.

A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F. (formerly P).

The net force acting on an object is equal to the rate at which its momentum varies over time, according to Newton's second law in its original formulation. This law says that an object's acceleration is constant if the object's mass is constant.

Therefore,  A hungry polar bear does -40J of the work and stops the salmon. If the polar bear applied its force over 0.5m. The force is 80 Newton.

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A space probe of mass 1,000 kg is launched to Jupiter. How much would it weigh once at Jupiter? (Assume Jupiter's gravitational acceleration to be 24.79 m/s².)
View Available Hint(s) for Part A
A space probe of mass 1,000 kg is launched to Jupiter. How much would it weigh once at Jupiter? (Assume Jupiter's gravitational acceleration to be 24.79 m/s².)
24,790 N
10,000 N
1,000 N
247.9 N

Answers

The weight of the space probe of mass 1000 kg is 24790 N.

What is weight?

Weight is the product of mass and gravitational acceleration

To calculate the weight of the Jupiter, we use the formula below.

Formula:

W = mg............. Equation 1

Where:

W = Weight of the space probem = Mass of the Space probeg = Acceleration due to gravity of Jupiter

From the question,

Given:

m = 1000 kgg = 24.79 m/s²

Substitute these values into equation 1

W = 1000×24.79W = 24790 N

Hence, The weight of the space probe is 24790 N.

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A person stands in an elevator. The elevator starts from rest and travels from the first floor to the fifth floor of the building. Which of the following forces has a magnitude equal to the person's weight during the entire elevator ride?
The gravitational force exerted by the elevator on the person.
The gravitational force exerted by the person on Earth.
The normal force exerted by the elevator on the person.
The normal force exerted by the person on the elevator.

Answers

The person's weight during the entire elevator ride is equal to magnitude  of the normal force exerted by the elevator on the person.

What is normal force?

Every day, we experience the typical force. For instance, when a book is placed on a table, the usual response force prevents the book from falling through the table, even though gravity is pulling the book downward. That implies that there is a force acting to push it upward. The word "normal force" refers to the force. Normal in this context refers to being perpendicular to the ground.

The person's apparent weight  during the entire elevator ride is equal to magnitude  of the normal force exerted by the elevator on the person.

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