Answer:
[tex]5.08\times 10^{-9}\ \text{m}[/tex]
Explanation:
h = Planck constant = [tex]6.626\times 10^{-34}\ \text{Js}[/tex]
[tex]\lambda[/tex] = Wavelength
m = Mass of electron = [tex]9.11\times 10^{-31}\ \text{kg}[/tex]
[tex]\Delta V[/tex] = Potential difference = 14.6 kV
e = Charge of electron = [tex]1.6\times 10^{-19}\ \text{C}[/tex]
d = Distance between slits
[tex]\sin\theta=\dfrac{8.8\times 10^{-3}}{4.4}[/tex]
We have the relation
[tex]\dfrac{h}{\lambda}=\sqrt{2me\Delta V}\\\Rightarrow \lambda=\dfrac{h}{\sqrt{2me\Delta V}}\\\Rightarrow \lambda=\dfrac{6.626\times 10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 14.6\times 10^3}}\\\Rightarrow \lambda=1.016\times 10^{-11}\ \text{m}[/tex]
Wavelength is given by
[tex]d\sin\theta=\lambda\\\Rightarrow d=\dfrac{\lambda}{\sin\theta}\\\Rightarrow d=\dfrac{1.016\times 10^{-11}}{\dfrac{8.8\times 10^{-3}}{4.4}}\\\Rightarrow d=5.08\times 10^{-9}\ \text{m}[/tex]
The distance between the slits is [tex]5.08\times 10^{-9}\ \text{m}[/tex].
uses of generator
pls in points
if you answer correct i will mark you as brainliest
Answer:
Electric generator, also called dynamo, any machine that converts mechanical energy to electricity for transmission and distribution over power lines to domestic, commercial, and industrial customers. Generators also produce the electrical power required for automobiles, aircraft, ships, and trains.
Answer:
Electric motors are used in a broad range of industrial, commercial, and residential, applications, such as fans, pumps, compressors, elevators, and refrigerators. ... DC motors are used for variable speed control applications such as industrial machinery and motor vehicles.
In electricity generation, a generator is a device that converts mechanical energy to electrical energy for use in an external circuit. Generators provide nearly all of the power for electric power grids.
Hope it helps
A 5.0-m radius playground merry-go-round with a moment of inertia of 1,630 kg m2 is rotating freely with an angular speed of 1.6 rad/s. Two people, each having a mass of 69.5 kg, are standing right outside the edge of the merry-go-round and step on it with negligible speed. What is the angular speed of the merry-go-round right after the two people have stepped on
Answer:
The right solution is "0.511".
Explanation:
Given:
Initial moment of inertia,
= 1630 kg.m²
Radius,
= 5 m
Angular speed,
= 1.6 rad/s
Now,
The moment of inertia after stepping on will be:
= [tex]1630+2\times (69.5\times (5)^2)[/tex]
= [tex]1630+2\times (69.5\times 25)[/tex]
= [tex]5105 \ Kg.m^2[/tex]
hence,
As per the question, the angular speed is conserved, then
⇒ [tex]1630\times 1.6=5105\times \omega'[/tex]
[tex]2608=5105\times \omega'[/tex]
[tex]\omega'=\frac{2608}{5105}[/tex]
[tex]=0.511[/tex]
Grace is playing with her dolls and decides to give them a ride on a merry-go-round. She places one of them on an old record player turntable and sets the angular speed at 33.3 rpm. What is their angular speed in rad/s
Answer: [tex]3.48\ rad/s[/tex]
Explanation:
Given
Angular speed in rpm is 33.3 rpm
To convert it into rad/s, multiply it with [tex]\frac{2\pi}{60}[/tex]
Angular speed(rad/s)
[tex]\Rightarrow \dfrac{2\pi \times 33.3}{60}\\\\\Rightarrow 3.48\ rad/s[/tex]
A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What is the longest wavelength that forms an intensity maximum in the fifth order
Answer:
377 nm
Explanation:
Number of lines per meter is, [tex]N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}[/tex]
Grating element is, [tex]d=\frac{1}{N}[/tex]
[tex]=1.8868 \times 10^{-6} \mathrm{~m}[tex]
Order is, n=5
Condition for maximum intensity is, [tex]d \sin \theta=n \lambda[/tex]
[tex]\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\ &=0.377 \times 10^{-6} \mathrm{~m} \\ &=377 \mathrm{~nm}[/tex]
An old fashioned string of 80 Christmas lights is wired in series. Each bulb has a resistance of 2 Ohms and the entire string is plugged into a 120V outlet. What is the current passing through each of the bulbs?
The sum of the resistance = 2 ohms x 80 lights = 160 ohms.
Current = Total voltage / total resistance:
Current = 120V / 160 ohms
Current = 0.75 Amps
A gyroscope slows from an initial rate of 34 rad/s at a rate of 0.619 rad/s2. The angular displacement when it stops moving is _
Answer: [tex]933.76\ rad[/tex]
Explanation:
Given
The initial rate of gyroscope is [tex]\omega_o=34\ rad/s[/tex]
Angular deceleration [tex]\alpha =0.619\ rad/s^2[/tex]
Using angular equation of motion
[tex]\Rightarrow \omega^2-\omega_o^2=2\alpha \theta[/tex]
Insert the values
[tex]\Rightarrow 0-34^2=2(-0.619)\theta \\\\\Rightarrow \theta =\dfrac{34^2}{2\times 0.619}\\\\\Rightarrow \theta =933.76\ rad[/tex]
Thus, the angular displacement is [tex]933.76\ rad[/tex]
An irrigation canal has a rectangular cross section. At one point where the canal is 18.2 m wide and the water is 3.55 m deep, the water flows at 2.55 cm/s . At a second point downstream, but on the same level, the canal is 16.3 m wide, but the water flows at 11.6 cm/s . How deep is the water at this point
Answer:
Explanation:
Rate of volume flow at two points will be same at two points .
A₁ V₁ = A₂V₂
A₁ and A₂ are area of cross section at two points and V₁ and V₂ are velocities .
A₁ = 18.2 x 3.55 = 64.61 m²
V₁ = 2 .55 x 10⁻² m/s
A₂ = 16.3 x d = 16.3 d m²
d is depth at second point .
V₂ = 11.6 x 10⁻² m/s
64.61 m² x 2 .55 x 10⁻² m/s = 16.3 d m² x 11.6 x 10⁻² m/s
d = .87 m
so canal is .87 m deep.
4- What force must be applied to a surface area of 0.0025m , to create a pressure ol
200.000Pa?
When was the most gravitational potential energy stored between the model and Earth? Assume that the model's mass did not change.
Answer:
As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy
Explanation:
Answer:As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy
Explanation:
Explain gravitational implicit energy in terms of work done against graveness.Show how knowledge of the implicit energy as a function of position can be used to simplify computations and explain physical marvels. Show that the gravitational potential energy of an object of mass m at height h on Earth is given by PEg=mgh.What is the speed of a wave if it has a wavelength of
42 m and a frequency of 7 hertz?
Answer:
♕ [tex]\large{ \red{ \tt{Step - By - Step \: Explanation}}}[/tex]
☃ [tex] \underline{ \underline{ \blue{ \large{ \tt{G \: I \: V \: E\: N}}}}} : [/tex]
Frequency ( f ) = 7 HertzWavelength ( λ ) = 42m♨ [tex] \underline {\underline{ \orange{ \large{ \tt{T \: O \: \: F \: I \: N\: D}}}} }: [/tex]
Wave velocity ( v )☄ [tex]\underline{ \underline{ \large{ \pink{ \tt{S\: O \: L \: U \: T\: I \: O \: N}}}}}: [/tex]
✧ [tex] \red{ \boxed{ \large{ \purple{ \sf{Wave \: velocity(v) = Frequency(f) \times Wavelength(λ)}}}}}[/tex]
~Plug the known values and then multiply!
↦ [tex] \large{ \tt{7 \times 42}}[/tex]
↦ [tex] \boxed{ \boxed{ \large{ \bold{ \tt{294 \: m {s}^ {- 1} }}}}}[/tex]
☥ [tex] \large{ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer : \underline{ \large{ \tt{294 \: m {s}^{ - 1}}}}}}}}} [/tex]
---------------------------------------------------------------
❁ [tex] \underline{ \large{ \red{ \tt{D\: E\: T \: A \: I \: L\: E \: D \: \: I\: N \: F \: O}}}} : [/tex]
Frequency ( f ) : The number of complete waves , set up in a medium in one second is called frequency of the wave. The SI unit of frequency is Hertz ( Hz ). For example : if a sound wave completes 15 compressions and 15 rarefactions in one second , it's frequency is 15 Hz.Wavelength ( λ ) : The distance between two consecutive troughs or crests in a transverse wave or the distance between two consecutive compressions or rarefactions in a longitudinal wave us called wavelength. It is the distance travelled by a wave in a time equal to it's time period. It's SI unit is metre ( m ).Wave velocity ( v ) : The velocity with which a wave propagates in a medium is called wave velocity. It's SI unit is m/s.# KILL : Excuses
KISS : Opportunities
MARRY : Goals
♪ Hope I helped! ♡
☂ Have a wonderful day / night ! ツ
✎ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ✔
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
A copper wire has a diameter of 4.00 x 10-2 inches and is originally 10.0 ft long. What is the greatest load that can be supported by this wire without exceeding its elastic limit
Complete question is;
A copper wire has a diameter of 4.00 × 10^(-2) inches and is originally 10.0 ft long. What is the greatest load that can be supported by this wire without exceeding its elastic limit? Use the value of 2.30 × 10⁴ lb/in² for the elastic limit of copper.
Answer:
F_max = 28.9 lbf
Explanation:
Elastic limit is simply the maximum amount of stress that can be applied to the wire before it permanently deform.
Thus;
Elastic limit = Max stress
Formula for max stress is;
Max stress = F_max/A
Thus;
Elastic limit = F_max/A
F_max is maximum load
A is area = πr²
We have diameter; d = 4 × 10^(-2) inches = 0.04 in
Radius; r = d/2 = 0.04/2 = 0.02
Plugging in the relevant values into the elastic limit equation, we have;
2.30 × 10⁴ = F_max/(π × 0.02²)
F_max = 2.30 × 10⁴ × (π × 0.02²)
F_max = 28.9 lbf
Which of the following is form of energy:
a) Power
b) Light
C) pressure
d) None
Answer:
Explanation:
b) light
A vertical spring with a spring constant of 450 N/m is mounted on the floor. From directly above the spring, which is unstrained, a 0.30-kg ball is dropped from rest. It collides with and sticks to the spring, which is compressed by 2.5 cm in bringing the block to a momentary halt. Assuming air resistance is negligible, from what height (in cm) above the uncompressed spring was the block dropped
Answer:
h = 1.91 m
Explanation:
From the law of conservation of energy, we know that:
[tex]Potential\ Energy\ of\ Ball = Elastic\ Petential\ Energy\ of\ Spring\\mgh = \frac{1}{2}kx^2[/tex]
where,
m = mass of ball = 0.3 kg
g = acceleration due to gravity = 9.81 m/s²
h = height of ball = ?
k = spring constant = 450 N/m
x = compressed length = 2.5 cm = 0.025 m
Therefore,
[tex](0.3\ kg)(9.81\ m/s^2)h = \frac{1}{2} (450\ N/m)(0.025\ m)^2\\\\h = \frac{(450\ N/m)(0.025\ m)^}{(2)(0.3\ kg)(9.81\ m/s^2)}[/tex]
h = 1.91 m
what is the difference between impulse and momentum
Answer:
The momentum of the object is given by the product of mass and velocity while the impulse is the change of momentum when a large force is applied on an object for a short interval of time.
I would reword it
Hope this helps!!
Two blocks are connected by a massless rope that passes over a 1 kg pulley with a radius of 12 cm. The rope moves over the pulley without slipping. The mass of block A is 2.1 kg and the mass of block B is 4.1 kg. Block A is also connected to a horizontally-mounted spring with a spring constant of 358 J/m2. What is the angular frequency (in rad/s) of oscillations of this system
Answer:
[tex]F=1.159[/tex]
Explanation:
From the question we are told that:
Mass of pulley [tex]M=1kg[/tex]
Radius [tex]r=12cm[/tex]
Mass of block A [tex]M_a=2.1kg[/tex]
Mass of block B [tex]m_b=4.1kg[/tex]
Spring constant[tex]\mu= 358 J/m2[/tex]
Generally the equation for Torque is mathematically given by
Since [tex]\sumF=ma[/tex]
At mass A
[tex]T_2-f_3=2.1a[/tex]
At mass B
[tex]4.8-T_1=4.1a[/tex]
At Pulley
[tex]R(T_1-T_2)=\frac{1*1*R^2}{2}\frac{a}{R}[/tex]
[tex]R(T_1-T_2)=0.55a[/tex]
Therefore the equation for total force F
At mass A+At mass B+At Pulley
[tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.1a+4.1a+0.55a[/tex]
[tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.7a+4.8a+0.55a[/tex]
[tex]-f_3+4.1=6.75a[/tex]
[tex]-f_3=6.75a+4.8[/tex]
Since From above equation
[tex]M_{eff}=6.7kg[/tex]
Therefore
[tex]T=2\pi \sqrt{{\frac{M_{eff}}{k}}[/tex]
[tex]T=2\pi \sqrt{{\frac{6.75}{\mu}}[/tex]
[tex]T=0.862s[/tex]
Generally the equation for frequency is mathematically given by
[tex]F=\frac{1}{T} \\F=\frac{1}{0.862}[/tex]
[tex]F=1.159[/tex]
A bullet with a mass of 12 g moving horizontally strikes a fixed block of wood and penetrates a distance of 5.2 cm. The speed of the bullet just before the collision is 640 m/s. What is the average force that the wood exerted on the bullet
Answer:
F = 47261.5 N = 47.26 KN
Explanation:
First, we will calculate the deceleration of the bullet by using the third equation of motion:
[tex]2as = v_f^2-v_i^2[/tex]
where,
a = deceleration = ?
s = distace covered = 5.2 cm = 0.052 m
vf = final speed = 0 m/s
vi = initial speed = 640 m/s
Therefore,
[tex]2(a)(0.052\ m) = (0\ m/s)^2-(640\ m/s)^2\\\\a = -\frac{409600\ m^2/s^2}{0.104\ m}\\\\a=-3938461.5\ m/s^2[/tex]
negative sign shows deceleration.
Now for the force, we will use Newton's Second Law of Motion:
F = ma
where,
F = Force = ?
m = mass of bullet = 12 g = 0.012 kg
Therefore,
F = (0.012 kg)(3938461.5 m/s²)
F = 47261.5 N = 47.26 KN
which statement describes the molecules and a reaction once it reaches equilibrium
A. They maintain stable concentrations
B. They stop moving
C. They consist mainly of reactant molecules
D. They react only if they are disturbed
Answer:
They maintain stable concentrations
Explanation:
Just took the test.
The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is option A as the When a chemical reaction reaches equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction.
What is equilibrium?Equilibrium is a dynamic state, meaning that the reaction is still ongoing but the rates of the forward and reverse reactions are equal. This means that molecules are still reacting with each other, but at a constant rate, so that the concentrations of the reactants and products remain stable. When a reaction is not at equilibrium, the concentrations of the reactants and products change as the reaction progresses. However, once equilibrium is reached, the concentrations of the reactants and products no longer change, but the individual molecules are still moving and reacting with each other.
Hence, The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is an option. A
Learn more about equilibrium here.
https://brainly.com/question/19324885
#SPJ5
At the Olympics, high-diving competition,a diver from the top board curves her body in order to?
A. Dive clearly into the water
B. Spin more
C. Increase her energy
D. Spin more slowly
E. Increase her speed
The correct option is E. Increase her speed
High-diving is the process or way in which a person jump into water or swimming pool from a higher heights.
A Diver is a person who dive or Fall into a water from a top board or diving board .
Therefore she was curving her body from the top board in order to Increase her speed which will enable her to spin or flip more faster.
Inconclusion The correct option is E. Increase her speed.
Learn more about Diving here:
https://brainly.com/question/2784286
In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background signal level is 13 mV, the signal is 91 mV with no attenuator and is 25 mV with an attenuator in place. Calculate pt/pi including the background correction.
Answer:
The answer is "[tex]15.38\%[/tex]"
Explanation:
Background[tex]= 13 \ mv\\\\[/tex]
corrected signal[tex]= 91 \ mv-13\ mv= 78\ mv\\\\[/tex]
with attenuator[tex]=25\ mv-13\ mv= 12\ mv\\\\[/tex]
[tex]\to \frac{p_t}{p_i}=\frac{12}{78}\times 100= 15.38\%[/tex]
An electron that has an instantaneous velocity of is moving through the uniform magnetic field (a) Find the force on the electron due to the magnetic field. (b) Repeat your calculation for a proton having the same velocity
Answer:
Explanation:
From the given information:
The missing value are as follows:
The velocity [tex]v ^{\to} = (2.0 \times 10^6 \ m/s) \hat i + (3.0 \times 10^6 \ m.s) \hat j[/tex]
The uniform magnetic field [tex]B^{\to} = (0.030 T)\hat i -(0.15 T) \hat j[/tex]
The force on electron as a result of the Magnetic field is:
[tex]F^\to = q(v^\to \times B^\to)[/tex]
here;
Change of electron [tex]q = -1.6 \times 10^{-19} C[/tex]
Then,
[tex]v^{\to} \times B^{\to} = \left|\begin{array}{ccc}2\times10^6&3\times 10^6&0\\0.03&-0.15&0\end{array}\right|[/tex]
[tex]= \hat i(0-0) -\hat j ( 0-0) +\hat k (-3\times 10^5 -0.9\times 10^5) \\ \\ =-3.9 \times 10^5 \ k[/tex]
∴
[tex]F^\to = q(v^\to \times B^\to)[/tex]
[tex]F^{\to} = -1.6 \times 10^{-19} \times -3.9 \times 10^5 \\ \\ F^{\to} = 6.24 \times 10^{-14 } \ N[/tex]
For the proton with the same velocity:
[tex]q = 1.6 \times 10^{-19 } \ C \\ \\ F = q (v^\to * B^\to) \ \\ \\ F^\to = q(-3.9 \times 10^5) \\ \\ F = (1.6 \times 10^{-19}) (-3.9 \times 10^5) \\ \\ \mathbf{F ^{\to} = -6.24 \times 10^{-14} \ N}[/tex]
5. Stopping a fast-moving object is harder than stopping a slow-moving
one.
True
False
ADHD is triggered ________ by genetic and neurological factors and ________ by social or environmental ones.
A. less; more
B. somewhat; somewhat
C. little; mostly
D. more; less
Answer:
D More: Less
Explanation:
ADHD is triggered more by genetic and neurological factors and less by social or environmental ones.
What is ADHD?ADHD is one of the most common neurodevelopmental disorders of childhood. It is usually first diagnosed in childhood and often lasts into adulthood. Children with ADHD may have trouble paying attention, controlling impulsive behaviors (may act without thinking about what the result will be), or be overly active.
Moreover, ADHD tends to run in families and, in most cases, it's thought the genes you inherit from your parents are a significant factor in developing the condition. Research shows that parents and siblings of someone with ADHD are more likely to have ADHD themselves.
Therefore, adults with attention deficit hyperactivity disorder (ADHD or ADD) lead anxious lives. The nature of ADHD often makes day-to-day life stressful, creating situations and environments fraught with uncertainty – anxiety's primary fuel.
Learn more about ADHD:
https://brainly.com/question/13719580
#SPJ2
Copper zinc and magnesium do not contain any iron. What word is used to describe these types of
metals?
Answer:
Metals that do not contain traces or large proportions of iron in them are called Non-Ferrous metals.
Please helpppppppppp!!!!!!!!!!!
There are three 20.0 Ω resistors connected in series across a 120 V generator
Answer:
That is equal to R1 + R2. If three or more unequal (or equal) resistors are connected in series then the equivalent resistance is: R1 + R2 + R3 +…, etc. One important point to remember about resistors in series networks to check that your maths is correct.
Atoms are composed of protons, ______, and electrons.
Atoms are composed of protons, [tex]\sf\purple{neutrons}[/tex]and electrons. ✅
The [tex]\sf\blue{protons}[/tex] (positively charged) and the [tex]\sf\pink{neutrons}[/tex] (no charge) are in the centre of the atom, making up the nucleus.[tex]\sf\red{Electrons}[/tex] (negatively charged) are present in the outermost shell of the atom.[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]
paano matutugunan o matutulungan ng pamahalaan at ng mga guro yubg mga estudyanteng nakararanas nag stress at anxiety.
Answer: how the government and teachers can address or help students experiencing stress and anxiety.
Explanation:
A thermionic tube with only a cathode and anode is called
Answer:
the simplest vacuum tube, the diode
You have two flashlights that have 0.500-A currents flowing through them. One flashlight has a single 1.50-V battery in its circuit, and the second flashlight has three 1.50-V batteries connected in a chain that provides 4.50 V. How much power is the battery in the first flashlight providing
Answer: 0.75 W
Explanation:
Given
Current flowing [tex]I=0.5\ A[/tex]
The first flashlight has a single 1.5 V battery
The second flashlight has three 1.5 V batteries connected to provide 4.5 V
Power is the product of voltage and current.
For the first flashlight
[tex]\Rightarrow P=1.5\times 0.5\\\Rightarrow P=0.75\ W[/tex]
Thus, the first flashlight providing 0.75 W of power.
A. Obtain the following: microwave, ruler, something meltable (e.g. candy bar, marshmallows) B. A microwave works by setting up a standing electromagnetic wave inside of a box made of conducting materials. What is the value of an electric field inside a conductor
Answer:
E = 124.7 N / C
Explanation:
Let's analyze the exercise: the microwave creates an electromagnetic wave of frequency F = 2.45 GHz, this wave is introduced into the microwave cavity and is reflected on the metal walls, which is why one or more standing waves are formed.
The electric field of the standing wave is
I = E²
E =√I
where I is the intensity of the radiation.
What is it
I = P / A
where P is the effective emission power, almost all the power of the microwave and A is the area of the cavity, in the most used microwaves
P = 700 W and the area is A = 25 x 18 cm² = 0.045 m²
I = 700 / 0.045
I = 15555.56 W/m²
let's calculate the electric field
E = √15555.56
E = 124.7 N / C