A beaker of cold water is placed in a hot water bath at 90•C..
Descibe the final temperature after diffusion??​

Answers

Answer 1

Answer:All matter consists of particles, which vibrate (wiggle about a fixed position), translate (move from one location to another) and even rotate (revolve about an imaginary axis). An object ... or a particle ... that is moving has kinetic energy. A warm cup of water on a countertop may appear to be as still as can be; yet the particles that are contained within it have kinetic energy. At the particle level, there are atoms and molecules that are vibrating, rotating and moving through the space of its container. Stick a thermometer in the cup of water and you will see the evidence that the water possesses kinetic energy. The water's temperature, as reflected by the thermometer's reading, is a measure of the average amount of kinetic energy possessed by the water molecules.

Explanation:

Answer 2

A beaker of cold water is placed in a hot water bath at 90°C. The final temperature after diffusion will be below 90°C.

What is temperature?

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points or thermometric substances.

The most popular scales are the Kelvin scale (K), which is mostly used for scientific purposes, the Fahrenheit system (°F), as well as the Celsius scale, which has the unit symbol °C. A beaker of cold water is placed in a hot water bath at 90°C. The final temperature after diffusion will be below 90°C.

Therefore, the final temperature after diffusion will be below 90°C.

To know more about temperature, here:

https://brainly.com/question/23411503

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Related Questions

Could a child inherit a dominant trait if neither of her parents express the dominant trait? show the cross

Answers

Answer:

yes it does

Explanation:

I searched it up

make a prediction about the relationship between electrons and molecular shapes ​

Answers

Answer:

★ Molecular geometry is described by VSEPR theory, which basically states that electron pairs around a central atom will repel each other, and get as far apart as possible, in three dimensions.

Explanation:

Hope you have a great day :)

1.5 atm is the same pressure as... (1 atm
760 mmHg)

Answers

Answer:

1100 mmHg

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Gas Laws

Pressure

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 1.5 atm

[Solve] mmHg

Step 2: Identify Conversions

1 atm = 760 mmHg

Step 3: Convert

[DA] Set up:                                                                                                     [tex]\displaystyle 1.5 \ atm(\frac{760 \ mmHg}{1 \ atm})[/tex][DA] Multiply/Divide [Cancel out units]:                                                        [tex]\displaystyle 1140 \ mmHg[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1140 mmHg ≈ 1100 mmHg

Name an example of a molecule

Answers

Answer:

N2 (nitrogen) O3 (ozone) CaO (calcium oxide) C6H12O6 (glucose, a type of sugar)

Answer:

dihydrogen monoxide

dinitrogen monosulfide

3. When 10.0 g of a pure compound was analyzed, it was found to contain 3.65 g of K, 3.33 g of CI,
and 3.02 g of O. Determine the empirical formula of the compound.

Answers

Convert all the grams to moles first.

K - 3.65 g / 39.1 g/mol = 0.0934 mol
Cl - 3.33 g / 35.45 g/mol = 0.0939 mol
O - 3.02 g / 16 g/mol = 0.189 mol

Divide them all by the smallest number of moles (0.0934 moles of K) to get whole numbers.

K - 0.0934/0.0934 = 1
Cl - 0.0939/0.0934 ≈ 1
O - 0.189/0.0934 ≈ 2

KClO2

 A student finds the mass of an empty 50-mL beaker to be 36.52 g. She then uses a 25.0- mL volumetric pipet to transfer a sample of an organic liquid to the beaker. The beaker and its contents now have a mass of 53.25 g. what is the density of the liquid?


Answers

Answer:

density = 0.669 but see below.

Explanation:

Mass of Beaker and the liquid = 53.25

Mass of just the beaker =           36.52       Subtract

Mass of the liquid                         16.73

Density =  mass / volume

mass =         16.73

volume =    25.0 mL

You have to assume that the pipette was filled right to the top.

Density = 16.73 / 25.0 = 0.6692 grams / mL

Since this only has 3 places of accuracy, the answer should be 0.669

Write down the names of the elements

Answers

Answer:

Carbon and hydrogen

Explanation:

C = Carbon

H = Hydrogen

A gas with a volume of 4.0 L at a pressure of 2.02 atm is allowed to expand to a volume of 12.0
L. What is the pressure in the container if the temperature remains constant

Answers

Answer:

P₂ = 0.67 atm

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right  

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Chemistry

Gas Laws

Boyle's Law: P₁V₁ = P₂V₂

P₁ is pressure 1V₁ is volume 1P₂ is pressure 2V₂ is volume 2Explanation:

Step 1: Define

[Given] P₁ = 2.02 atm

[Given] V₁ = 4.0 L

[Given] V₂ = 12.0 L

[Solve] P₂

Step 2: Solve

Substitute in variables [Boyle's Law]:                                                              (2.02 atm)(4.0 L) = P₂(12.0 L)[Pressure] Multiply:                                                                                           8.08 atm · L = P₂(12.0 L)[Pressure] [Division Property of Equality] Isolate unknown:                          0.673333 atm = P₂[Pressure] Rewrite:                                                                                           P₂ = 0.673333 atm

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs as our smallest.

0.673333 atm ≈ 0.67 atm

a 0.25kg shoe is thrown out a window during a physical class. the shoe attains an acceleration of 9.8m/s before hitting an inspecting individual standing on a sidewalk. how much Force(In Newton's) did the shoe hit with?​

Answers

Explanation:

Here is a history of questions and answers processed by "Ask the Physicist!". If you like my answer, please consider making a donation to help support this service.

If there is a link to a previously answered question, be patient. Since the files containing the older answers are rather large, it takes some time (maybe as much as 15 seconds or so) to find the appropriate bookmark.

F = ma = 0.25 kg • 9.8 m/s = 2.45 N

Part A
Consider the following neutral electron configurations in which n has a constant value. Which configuration
would belong to the element with the most negative electron affinity, Eea?
View Available Hint(s)
a 2s2
b 2s²2p2
c 2s²2p5
d 2s²2p6

Answers

Answer:

c. 2s2 2p5

Explanation:

2s2 2p5 has 7 valence electrons and only needs one electron to complete the octet.  This element will be the most electronegative.

write an apology letter to your principal telling him why you were not in the mathematics competition.in 4000 words​

Answers

OK now that’s a lot to ask for but if you want someone to actually do that you’re gonna need a lot more points

Which two parts of sedimentary rock formation include the breakdown and carrying away of existing rock?

Answers

Answer:

Cementation

Erosion

Explanation:

Cementation refers to hardening and welding of those sediments which are formed from preexisting rock fragments as a result of the precipitation of mineral matter in the spaces between the pore. The last stage in the formation of a sedimentary rock is Cementation.

Erosion is the geological process in which soil, rock, or dissolved material are worn away and transported from one location to another location by natural forces such as wind or water.

The two parts of sedimentary rock formation which include the breakdown and carrying away of existing rock are cementation and erosion.

Answer: The answer is A: Cementation and Erosion

Explanation: Hope this helps! happy new year

How can you tell if the equations in this simulation are following the law of conservation of mass?

Answers

Answer:

can u mark me brainliest

Explanation:

Following the Law

Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions

Which of the following is NOT a property of matter?
solubility
Hardness
Mass
Density

Answers

Answer:

hardness im sure

Explanation:

Use the following equation to answer the questions below:

Be + 2HCl → BeCl2 + H2

Answers are rounded.. pick the closest to your answer.

What is the mass of beryllium required to produce 25.0g of beryllium chloride? g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

Answers

Explanation:

The equation of the reaction is given as;

Be + 2HCl → BeCl2 + H2

What is the mass of beryllium required to produce 25.0g of beryllium chloride?

1 mol of Be produces 1 mol of BeCl2

Converting to mass;

Mass = Molar mass  *  Number of moles

9.01g of Be produces 79.92g of BeCl2

xg of Be produces 25g of BeCl2

Solving for x;

x = 25 * 9.01 / 79.92

x = 2.82 g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

Converting 25.0g of beryllium chloride to moles;

Number of moles = Mass / Molar mass

Number of moles = 25 / 79.92 = 0.3128 mol

2 mol of HCl produces 1 mol of BeCl2

x mol of HCl would produce 0.3128 mol of BeCl2

solving for x;

x = 0.3128 * 2 = 0.6256 mol

Converting to mass;

Mass = 0.6256 * 36.5 = 22.83 g

What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

25g of BeCl2 = 0.3128 mol of BeCl2

From the equation;

1 mol of H2 is produced alongside 1 mol of BeCl2

This means;

0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

Mass = Number of moles * Molar mass

Mass = 0.3128mol * 2.0159 g/mol = 0.6306 g

Need help asap! Will give brainliest!!!!! (15pt)

Which scenario has been theorized as the possible fate of the universe?
A.
the big chill
B.
the big bang
C.
the big expansion
D.
the big heat

Answers

Answer:

Big Chill

Explanation:

Answer:

it's big chill or big freeze

When a metal reacts with oxygen gas what is the product formed

Answers

Answer:

Metal + Oxygen -> Metal Oxide

Explanation:

It's pretty self-explanatory. However, let me show you an example:

Iron + Oxygen -> Iron Oxide

Iron rusts. When iron rusts, it comes in contact with air to form Iron Oxide, which is rust itself.

What energy is using the telephone?
1.electrical
2.sound
3.thermal
4.light
5.mechanical

Answers

Answer:

electrical

Explanation:

i kinda guessed.

Answer:

electrical energy is changed into sound energy

please answer it quickly

Answers

Answer:

B.

A.

D.

A.

C.

Hope it helps..

Have a great day : )

Calculate the mass of chromium produced from 50g of Cr2O3.

Answers

Answer: 34 gram of chromium produced from 50g of [tex]Cr_2O_3[/tex]

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Cr_2O_3=\frac{50g}{152g/mol}=0.33moles[/tex]

The decomposition of [tex]Cr_2O_3[/tex] follows the equation :

[tex]2Cr_2O_3\rightarrow 4Cr+3O_2[/tex]  

According to stoichiometry :

2 moles of [tex]Cr_2O_3[/tex] produce = 4 moles of [tex]Cr[/tex]

Thus 0.33 moles of [tex]Cr_2O_3[/tex] will produce=[tex]\frac{4}{2}\times 0.33=0.66moles[/tex]  of [tex]Cr[/tex]

Mass of [tex]Cr=moles\times {\text {Molar mass}}=0.66moles\times 52g/mol=34g[/tex]

Thus 34 gram of chromium produced from 50g of [tex]Cr_2O_3[/tex]

Easy Chem, Will Give brainliest

Answers

Answer:

3.94 L

Explanation:

From the question given above, the following data were obtained:

Mass of O₂ = 5.62 g

Volume of O₂ =?

Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:

Mass of O₂ = 5.62 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 5.62 / 32

Mole of O₂ = 0.176 mole

Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.

Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP

A random radioisotope has a decay constant of 0.00238 years-1. If
1165 years have past, and there was originally 80 grams of it,
roughly how many grams of the original radioisotope remain?

Answers

Answer:

5 grams remain

Explanation:

A = A₀exp(-k·t) 80g·exp(-0.00238yr⁻¹)(1165yrs) = 80g x 0.063 = 5 grams remain

convert to moles:
100.0g Ca3(PO4)2

Answers

Answer:

0.322 moles

Explanation:

Given Mass, m = 100 g

The molar mass of Ca₃(PO₄)₂

Ca₃(PO₄)₂ = (3 x 40.08) + (2 x 30.97) + (8 x 16.00)

M = 310.18 g/mol

Let there are n number of moles,

n = given mass/ molar mass

[tex]n=\dfrac{100 }{310.18 }\\\\n=0.322\ mol[/tex]

So, there are 0.322 moles.

3. Consider the reaction of methane, CH4, burning in the presence of oxygen at constant pressure. Given the following equation, how much heat could be obtained by the combustion of 8.0 grams CH4? Given the thermochemical equation: CH4(g)+2O2→CO2(g)+2H2O(l); ΔH0=890.3kJ;

Answers

Answer: 445.15 kJ of heat could be obtained by the combustion of 8.0 grams [tex]CH_4[/tex]

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} CH_4=\frac{8.0g}{16.04g/mol}=0.50moles[/tex]

The given thermochemical equation is:

[tex]CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)[/tex]  [tex]\Delta H=890.3kJ[/tex]

According to stoichiometry :

1 mole of [tex]CH_4[/tex] on combustion produce heat = 890.3 kJ

Thus 0.50 moles of [tex]CH_4[/tex] on combustion produce heat =[tex]\frac{890.3}{1}\times 0.50=445.15kJ[/tex]

Thus 445.15 kJ of heat could be obtained by the combustion of 8.0 grams [tex]CH_4[/tex]

What is the second most consume grain in the world?

Answers

Answer:

Wheat!

Explanation:

Corn ranks first, Wheat, then Rice!

I honestly don’t know I just want Brainly points if I had to guess it would be rice

How many grams are in 6.60 moles of ZnO?

Answers

Answer:

6.60 moles of ZnO have 537,108 g.

Explanation:

What are the reactants in the following reaction?
2FeS + 302 → 2FeO + 2502
iron (II) sulfide and oxygen
iron (II) sulfide and iron (II) oxide
oxygen and sulfur dioxide
iron (11) oxide and sulfur dioxide

Answers

Answer:

Iron (II) sulfide and oxygen

Which of the following organisms carry out photosynthesis?

Answers

Plants, algae, and a group of bacteria called cyanobacteria are the only organisms capable of performing photosynthesis. They use light to manufacture their own food, they are called photoautotrophs (literally, “self-feeders using light”).

What is the [SO32-) in the 0.080 M H2SO3 .080 M Solution?

Answers

Answer:

0.080 M

Explanation:

From the question given above, the following data were obtained:

Concentration of H₂SO₃ = 0.080 M

Concentration of SO₃²¯ =…?

The concentration of SO₃²¯, can be obtained as follow:

H₂SO₃ (aq) <==> 2H⁺ (aq) + SO₃²¯ (aq)

From the balanced equation for above,

1 mole of H₂SO₃ produced 1 mole of SO₃²¯.

Therefore, 0.080 M H₂SO₃ will also produce 0.080 M SO₃²¯.

Thus, the concentration of SO₃²¯ is 0.080 M

10-14 is smaller than 107​

Answers

Answer:

it is true because if you subtract 10 - 14 you will get -4 so it is less than 107.

Explanation:

Hope this helps!

Substract 10-14 you will get -4 so less than 107 !! Hope you have a great day ☺️
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