Advanced Placement (AP) High School

A basketball is rolling rightward onto the court with a speed of 4.0 m/s and slows down with a constant leftward acceleration of magnitude 0.50 m/s^2 over 14 m. What is the velocity of the basketball after rolling for 14 m?

Answers

Answer 1

Answer:

1.4

Explanation:

I just did it

Answer 2

The final velocity of the basketball can be calculated by the formula used for calculation of acceleration (v²-u² = 2as). The final velocity of the basketball will be 1.41m/s.

What is Acceleration?

Acceleration of a body is the change in the velocity of an object with respect to time elapsed. Acceleration of an object depends upon initial velocity, final velocity, and distance travelled by the body.

In the given question, it has been stated that the basketball slows down with a constant leftward acceleration of magnitude 0.50m/s². As the speed slows down, the acceleration of the body will be considered as negative.

Therefore, acceleration = -0.50m/s²

initial velocity = 4.0m/s

distance = 14m

Formula for the calculation of acceleration is as follows:

(v²-u² = 2.a.s)

where, v = final velocity of the object,

u = initial velocity of the object,

a = acceleration of the object,

s = distance travelled by the object

By putting the given values, we can calculate the final velocity of the ball:

(v²- u² = 2as)

v²- (4)² = 2 × (-0.50) × 14

(v²- 16) = -14

v² = 16 - 14

v² = 2

v = √2

v = 1.41m/s

Hence, the final velocity of the basketball will be 1.41m/s.

Learn more about Acceleration here:

https://brainly.com/question/3046924

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