A barrel of crude oil has a volume of 42 gallons, only approximately 45% of which is processed into gasoline. If your car achieves 31 mi/gal, and you drive 36,000 miles in one year, how many barrels of crude oil are required to run your car for a year?

Hi

500 *1.025^10 ≈ 640.04

Answer:

1. -6.5x+11

2. 6b-5

3. 3p-5.1

Step-by-step explanation:

[tex]1. \\(x-1)+(12-7.5x)=\\x-1+12-7.5x=\\x-7.5x-1+12=\\-6.5x-1+12=\\-6.5x+11\\\\2.\\b-(4-2b)+(3b-1)=\\b-4+2b+3b-1=\\b+2b+3b-4-1=\\3b+3b-4-1=\\6b-4-1=\\6b-5\\\\3.\\(2p+1.9)-(7-p)=\\2p+1.9-7+p=\\2p+p+1.9-7=\\3p+1.9-7=\\3p-5.1[/tex]

Answer:

Step-by-step explanation:

Everything to know about a and b!

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex: (0, −5)

Focus: (0, [tex]-\frac{19}{4\\}[/tex]−)

Axis of Symmetry: x = 0

Directrix: y = [tex]-\frac{21}{4}[/tex]

For Part b

Table:

x    |     y

______

−2      −1

−1      −4

0       −5

1        −4

2       −1

Answer:

The correct answer is the first one of your list of options:

"Locate the ordered pair (0, –6). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points."

Step-by-step explanation:

Since the y-intercept is -6, then the point (0, -6) is a point on the line.That is x = 0 and y = -6. From there you move according to the slope value "2 = 2/1" which means two units of rise when the run is one.

Then, from (0, -6) move up 2 units and then right one unit. The new point should also be a point on the line. Join the two points with a line to graph the function.

Answer:

81/4

Step-by-step explanation:

From the given information; we are to use Lagrange multipliers to find the volume of the largest rectangular box

The coordinate planes and the vertex given in the plane is x + 9y + 4z = 27.

By applying Lagrange multipliers, we have;

[tex]fx = \lambda gx[/tex]

where;

[tex]f: V = xyz[/tex]

[tex]g : x + 9y + 4z = 27[/tex]

From; [tex]fx = \lambda gx[/tex]

[tex]yz = \lambda[/tex]    --------- equation (1)

From; [tex]fy = \lambda gy[/tex]

[tex]xz = 9 \lambda[/tex]  --------- equation (2)

From; [tex]fz = \lambda gz[/tex]

[tex]xy = 4 \lambda[/tex] --------- equation (3)

Comparing and solving equation (1),(2) and (3);

[tex]\lambda x = 9 \lambda y = 4 \lambda z[/tex]

divide through by [tex]\lambda[/tex]

x = 9 y = 4z

3x = 27

x = 27/3

x = 9

From x = 9y

9 = 9 y

y = 9/9

y = 1

From

x = 4z

9 = 4 z

z = 9/4

Thus; the Volume of the largest rectangular box = 9 × 1  × 9/4

= 81/4

Answer:

√75 = 5√3 and √12 = 2√3 so √75 + √12 = 5√3 + 2√3 = 7√3.

Answer:

[tex] 7\sqrt{3} [/tex]

Step-by-step explanation:

[tex] \sqrt{12} \: can \: be \: simplified \: as \: 2 \sqrt{3} \: and \: \sqrt{75} \: canbe \: simplified \: as \: 5 \sqrt{3} \\ after \: simplifying \: we \: can \: add \: them \: up \\ 2 \sqrt{3} + 5 \sqrt{3} = 7 \sqrt{3} [/tex]

Answer:

Step-by-step explanation:

GCF: -6x^2 and 15x^3  the GCF is 3x^2

the GCF for this polynomial is 2x(16y-9x)

Answer:

(B) 25%

Step-by-step explanation:

Answer:

104 degrees

Step-by-step explanation:

The angle of the whole set of lines is 140 degrees. In addition, the partial angle of it is also given--which is 36 degrees. In order to solve for the remaining part, Subtract 36 degrees from 140 degrees to get 104 degrees.

Answer:

[tex]\dfrac{1213}{9999}[/tex]

Step-by-step explanation:

We are required to express [tex]0.\overline{1}+0.\overline{01}+0.\overline{0001}[/tex] as a common fraction.

The bar on top of the decimal part indicates the decimal number is a repeating decimal.

Therefore:

[tex]0.\overline{1}=\dfrac{1}{10-1}= \dfrac{1}{9}\\\\0.\overline{01}=\dfrac{1}{100-1}= \dfrac{1}{99}\\\\0.\overline{0001}=\dfrac{1}{10000-1}= \dfrac{1}{9999}\\\\\\$Therefore$:\\0.\overline{1}+0.\overline{01}+0.\overline{0001} \\=\dfrac{1}{9}+\dfrac{1}{99}+\dfrac{1}{9999}\\\\=\dfrac{1213}{9999}[/tex]

Answer:

A margin of error of +/- 3%

Step-by-step explanation:

Strenght of surveys:

The lesser the margin of error, the more precise, stronger, the confidence interval is.

The margin of error depends of the number of people surveyed. The more people are surveyed, lower the margin of error is, giving a stronger interval.

In this question:

We want the smaller margin of error, which is given by:

A margin of error of +/- 3%

Answer: x = 15, y = 12.5

Step-by-step explanation:

The sum of the three angle measures of a triangle equals 180ᴼ

Since these triangles are vertical, the measures are congruent.

45 + 60 = 105

180 - 105 = 75

So now we know that 5x = 75ᴼ and 6y = 75ᴼ.

To find x, divide 75 by 5

75 / 5 = 15

x = 15

To find y, divide 75 by 6

75 / 6 = 12.5

y = 12.5

The value of root 10 is between 3 and 3.5

Answer:

Option D

Step-by-step explanation:

A sample can be described as a small part or potion that is intended to describe what the whole population is like.

In this study, the sample is a group of the children taking skiing or snowboarding lessons: this group is taken out of the whole population of children taking skiing or snowboarding lessons.

Answer:

9.35

Step-by-step explanation:

AAS formula is easier if you add 12+90 then subtract it from 180, thats angle A.

then just write out the formula

sinA/a = sinB/b

Answer:

W = (18,0)

Step-by-step explanation:

I found the slope of the line from point M to point V. The slope is -3.875. I continued this slope starting with point V to find the coordinates of point W. The coordinates of point W are (18,0).

I graphed the coordinates and the line of VW on the graph below.

Answer:

4

Step-by-step explanation:

C1= 2π*8= 16π

C2= 2π*2= 4π

C1/C2= 16π/4π= 4

Answer:

4

Step-by-step explanation:

The circumference is pi*d.

pi*16/pi*4

Cancel pi.

16/4

= 4

Answer:

V = 18125 in^3

Step-by-step explanation:

Surface Area of Rectangular Prism:

V = 18125 in^3

Step-by-step explanation:

Surface Area of Rectangular Prism:

S = 2(lw + lh + wh)

length l = 25 in

width w = 25 in

height h = 29 in

diagonal d = 45.7274535 in

total surface area S_tot = 4150 in^2

lateral surface area S_lat = 2900 in^2

top surface area S_top = 625 in^2

bottom surface area S_bot = 625 in^2

volume V = 18125 in^3

Answer:

i think it might be A. 0.2

Step-by-step explanation:

Answer:

5/7

Step-by-step explanation:

4/7 < x < 6/7

Let x be the middle value of 4/7 and 6/7.

(4/7 + 6/7)/2

(10/7)/2

10/14 = 5/7

4/7 < 5/7 < 6/7

Answer:

The 95 percent confidence interval for the true mean metal thickness is between 0.2903 mm and 0.2907 mm

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96\frac{0.000586}{\sqrt{59}} = 0.0002[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 0.2905 - 0.0002 = 0.2903 mm

The upper end of the interval is the sample mean added to M. So it is 0.2905 + 0.0002 = 0.2907 mm

The 95 percent confidence interval for the true mean metal thickness is between 0.2903 mm and 0.2907 mm

Answer:

Step-by-step explanation:

In an isosceles triangle, the base angles are equal. This also means that the length of two sides of the triangle are equal. Looking at triangle ABC, to prove that it is an isosceles triangle, then

Angle CAB = angle CBA

For the second question, to determine how it is known that QS is equivalent to YT, we would recall that the diameter of a circle passes through the center and from one side of the circle to the other side. Assuming R is the center of the circle, then QS and YT are the diameters of the circle and also the diagonals of the rectangle. Thus, the correct option is

The diameters act as diagonals

Answer:

V  = 23π/6

Step-by-step explanation:

V = 2π ∫ [a to b] (r * h) dx

y = −x² + 23x − 132

y = −(x² − 23x + 132)

y = −(x − 11) (x − 12)

Parabola intersects x-axis (line y = 0) at x = 11 and x = 12 ----> a = 11, b = 12

r = x

h = −x² + 23x − 132

V = 2π ∫ [11 to 12] x (−x² + 23x − 132) dx

V  = 23π/6

Answer:

The curvature is modelled by [tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex].

Step-by-step explanation:

The equation of the curvature is:

[tex]\kappa = \frac{|\dot {x}\cdot \ddot {y}-\dot{y}\cdot \ddot{x}|}{[\dot{x}^{2}+\dot{y}^{2}]^{\frac{3}{2} }}[/tex]

The parametric componentes of the curve are:

[tex]x = 6\cdot e^{t} \cdot \cos t[/tex] and [tex]y = 6\cdot e^{t}\cdot \sin t[/tex]

The first and second derivative associated to each component are determined by differentiation rules:

First derivative

[tex]\dot{x} = 6\cdot e^{t}\cdot \cos t - 6\cdot e^{t}\cdot \sin t[/tex] and [tex]\dot {y} = 6\cdot e^{t}\cdot \sin t + 6\cdot e^{t} \cdot \cos t[/tex]

[tex]\dot x = 6\cdot e^{t} \cdot (\cos t - \sin t)[/tex] and [tex]\dot {y} = 6\cdot e^{t}\cdot (\sin t + \cos t)[/tex]

Second derivative

[tex]\ddot{x} = 6\cdot e^{t}\cdot (\cos t-\sin t)+6\cdot e^{t} \cdot (-\sin t -\cos t)[/tex]

[tex]\ddot x = -12\cdot e^{t}\cdot \sin t[/tex]

[tex]\ddot {y} = 6\cdot e^{t}\cdot (\sin t + \cos t) + 6\cdot e^{t}\cdot (\cos t - \sin t)[/tex]

[tex]\ddot{y} = 12\cdot e^{t}\cdot \cos t[/tex]

Now, each term is replaced in the the curvature equation:

[tex]\kappa = \frac{|6\cdot e^{t}\cdot (\cos t - \sin t)\cdot 12\cdot e^{t}\cdot \cos t-6\cdot e^{t}\cdot (\sin t + \cos t)\cdot (-12\cdot e^{t}\cdot \sin t)|}{\left\{\left[6\cdot e^{t}\cdot (\cos t - \sin t)\right]^{2}+\right[6\cdot e^{t}\cdot (\sin t + \cos t)\left]^{2}\right\}^{\frac{3}{2}}} }[/tex]

And the resulting expression is simplified by algebraic and trigonometric means:

[tex]\kappa = \frac{72\cdot e^{2\cdot t}\cdot \cos^{2}t-72\cdot e^{2\cdot t}\cdot \sin t\cdot \cos t + 72\cdot e^{2\cdot t}\cdot \sin^{2}t+72\cdot e^{2\cdot t}\cdot \sin t \cdot \cos t}{[36\cdot e^{2\cdot t}\cdot (\cos^{2}t -2\cdot \cos t \cdot \sin t +\sin^{2}t)+36\cdot e^{2\cdot t}\cdot (\sin^{2}t+2\cdot \cos t \cdot \sin t +\cos^{2} t)]^{\frac{3}{2} }}[/tex]

[tex]\kappa = \frac{72\cdot e^{2\cdot t}}{[72\cdot e^{2\cdot t}]^{\frac{3}{2} } }[/tex]

[tex]\kappa = [72\cdot e^{2\cdot t}]^{-\frac{1}{2} }[/tex]

[tex]\kappa = 72^{-\frac{1}{2} }\cdot e^{-t}[/tex]

[tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex]

The curvature is modelled by [tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex].

Answer:

10 rows with 6 passengers per row

Step-by-step explanation:

Let x be the number of rows and y the number of passengers per row.

Then we can interpret the story as the following two equations:

xy=60

(x+2)(y-1)=60

Solving these two equations:

y=60/x

(x+2)(60/x-1)=60     (substitute y)

60 - x + 120/x - 2 = 60 (multiply by -x)

x² + 2x - 120 = 0     (factor)

(x-10)(x+12) = 0

x = 10

y = 60/10 = 6

and indeed 10 * 6 = 60 and also 12 * 5 = 60

Answer:

C(x) = 0.2x^5 - x^2 + 6000

Step-by-step explanation:

Given in the question are restated as follows:

Marginal cos = C'(x) = x^4 - 2x ...................... (1)

Note that marginal cost (C'(x)) refers to the change in the total cost (C(x)) as a result of one more unit increase in the quantity produced. That is, MC refers to the additional cost incurred in order to produce one more unit of a good.

Therefore, TC can be obtained by integrating equation (1) as follows:

C(x) = ∫C'(x) = ∫[x^4 - 2x]dx

C(x) = 1/5x^5 - 2/2x^2 + F ................................ (2)

Where F is the fixed cost. Since the fixed cost is given as $6,000 in the question, we substitute it for F into equation (2) and solve as follows:

C(x) = 0.2x^5 - x^2 + 6000 ......................... (3)

Equation (3) is the total cost function​ C.

Correct question:

The vector matrix [ [tex] \left[\begin{array}{ccc}2\\7\end{array}\right] [/tex] is dilated by a factor of 1.5 and then reflected across the x axis. If the resulting matrix is [a/b] then a=??? and b=???

Answer:

a = 3

b = 10.5

Step-by-step explanation:

Given:

Vector matrix = [tex] \left[\begin{array}{ccc}2\\7\end{array}\right] [/tex]

Dilation factor = 1.5

Since the vector matrix is dilated by 1.5, we have:

[tex] \left[\begin{array}{ccc}1.5 * 2\\1.5 * 7\end{array}\right] [/tex]

= [tex] \left[\begin{array}{ccc}3\\10.5\end{array}\right] [/tex]

Here, we are told the vector is reflected on the x axis.

Therefore,

a = 3

b = 10.5

Answer:

a = 3

b = -10.5

Step-by-step explanation:

got a 100% on PLATO

Answer:

  30 miles

Step-by-step explanation:

Jose's charges are ...

  j = 5 + 0.30m . . . . . for m miles

Kathy's charges are ...

  k = 8 +0.20m . . . . . for m miles

The charges are the same when ...

 j = k

  5 +0.30m = 8 + 0.20m

  0.30m = 3 + 0.20m . . . . subtract 5

  0.10m = 3 . . . . . . . . . . . . subtract 0.20m

  m = 30 . . . . . . . . . . . . . . . multiply by 10

The charges will be the same for a distance of 30 miles.

Answer:

Step-by-step explanation:

Given that:

[tex]E( \hat \theta _1) = \theta \ \ \ \ E( \hat \theta _2) = \theta \ \ \ \ V( \hat \theta _1) = \sigma_1^2 \ \ \ \ V(\hat \theta_2) = \sigma_2^2[/tex]

If we are to consider the estimator [tex]\hat \theta _3 = a \hat \theta_1 + (1-a) \hat \theta_2[/tex]

a. Then, for  [tex]\hat \theta_3[/tex] to be an unbiased estimator ; Then:

[tex]E ( \hat \theta_3) = E ( a \hat \theta_1+ (1-a) \hat \theta_2)[/tex]

[tex]E ( \hat \theta_3) = aE ( \theta_1) + (1-a) E ( \hat \theta_2)[/tex]

[tex]E ( \hat \theta_3) = a \theta + (1-a) \theta = \theta[/tex]

b) If [tex]\hat \theta _1 \ \ and \ \ \hat \theta_2[/tex] are independent

[tex]V(\hat \theta _3) = V (a \hat \theta_1+ (1-a) \hat \theta_2)[/tex]

[tex]V(\hat \theta _3) = a ^2 V ( \hat \theta_1) + (1-a)^2 V ( \hat \theta_2)[/tex]

Thus; in order to minimize the variance of [tex]\hat \theta_3[/tex] ; then constant a can be determined as :

[tex]V( \hat \theta_3) = a^2 \sigma_1^2 + (1-a)^2 \sigma^2_2[/tex]

Using differentiation:

[tex]\dfrac{d}{da}(V \ \hat \theta_3) = 0 \implies 2a \ \sigma_1^2 + 2(1-a)(-1) \sigma_2^2 = 0[/tex]

⇒

[tex]a (\sigma_1^2 + \sigma_2^2) = \sigma^2_2[/tex]

[tex]\hat a = \dfrac{\sigma^2_2}{\sigma^2_1+\sigma^2_2}[/tex]

This implies that

[tex]\dfrac{d}{da}(V \ \hat \theta_3)|_{a = \hat a} = 2 \ \sigma_1^2 + 2 \ \sigma_2^2 > 0[/tex]

So, [tex]V( \hat \theta_3)[/tex] is minimum when [tex]\hat a = \dfrac{\sigma_2^2}{\sigma_1^2+\sigma_2^2}[/tex]

As such; [tex]a = \dfrac{1}{2}[/tex]       if   [tex]\sigma_1^2 \ \ = \ \ \sigma_2^2[/tex]

Answer:

a) 100 $

b) 566,66 $

c) 566,66 $

Step-by-step explanation:

Mak 85,000 $ /per year, means 85000/12 per month that is 7083,33

8% of 7083,33 is  566,66 $ . Then

a) 200 < 566,33 then my company will contribute with 0,5*200 = 100 $

b) If I contribute with 830 $  ( 830 > 566,66 ) then my company will contribute with 566,66 $ the biggest amount

c) 566,66 s the maximm amount of money