Why is it so important to train your core muscles?
Answer:
It helps prevents falls and supports your body. So having a strong core is beneficial to everyone because it allows your body to function properly. Improved Balance and Stability. Core exercises train the muscles in your pelvis, lower back, hips and abdomen to work together.
Scientists have invented the equipment to harness the power of lighting for energy use. True or false
How much time does it take an object to fall 4.9 meter?
A) less than 1 second
B) 1 second
C) more than 1 second
Answer:
C more than 1 second
Explanation:
it will take time since its 4.9 meters and how hard you throw it down
You push against a wall and the wall pushes back on you.
O Newton's 1st Law of Motion
O Newton's 2nd Law of Motion
Newton's 3rd Law of Motion
Answer:
Its the third law of motion.
Explanation:
Newton's third law of motion states that every action has equal and opposite reaction.
In which situation is the net force on the object equal to zero?
A.) a bicycle moving at a constant speed on a straight, level road
B.) an automobile braking to a stop
C.) a satellite moving at a constant speed around Earth in a circular orbit
D.) a pitched baseball being hit by a bat
Answer:
A.) a bicycle moving at a constant speed on a straight, level road.
Explanation:
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
[tex] F = ma[/tex]
Where;
F represents force measured in Newton.
m represents the mass of an object measured in kilograms.
a represents acceleration measured in meter per seconds square.
In Physics, when the net force acting on a body or an object is equal to zero (0); the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.
In this scenario, the situation in which the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.
The net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.
The given problem is based on the Newton's second law to define net force. The net force on any object is an external effort by which the object change its speed with respect to time or tends to change the state of its motion. The mathematical expression for the net force is,
F = ma
Here, F is the net force, m is the mass of object and a is the acceleration of object.
When the net force acting on a body or an object is equal to zero , then the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.In the given problem the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.
Thus, we conclude that the net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.
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Please answer the question 1 ii) please!!! Will mark Brainliest! !
Answer:
I think it's 10 minutes per km
Answer:
1.4 meters per second (5.0 km/h, 3.1 mph, 4.6ft/s
to calculatw the power produced by a force, the size of the force must be known. What else needs to be known to calculate the power
-- The distance the force moved through
-- How long the force lasted
The other thing we need to calculate the power is the "Velocity".
A quantity of labor or work done to be accomplished within a particular period of timeframe is determined as power. It is denoted by "P".According to the given query, we are talking about the relation between Power and Force. Along with simple instances where such an item is moved at continuous speed by a constant force.
The relation can be shown as:
→ [tex]P= Fv[/tex]
where,
P = PowerF = Forcev = VelocityThus the above is the right response.
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Ashley is flying a plane that has to reach a gradient of 360m/km in order to take off and not crash. Her goal is to travel from sea level to an elevation of 1000m at a distance of 2.8km. Calculate the gradient of Ashley’s flight and determine if she will crash!
Answer:
She is likely to crash because her flight gradient is lesser than the flight gradient required gradient to avoid crashing
Explanation:
The given parameters are;
The required gradient of the plane Ashley is flying needs to reach in order to take off and not crash = 360 m/km
The initial elevation of the plane Ashley is flying = Sea level = 0 m
The goal Ashley intends to make = Elevation of 1000 m at 2.8 km. distance
∴ Ashley's goal = Traveling from sea level to 1000 m at 2.8 km horizontal distance
We have;
The gradient = Rate of change of elevation/(Horizontal distance)
Therefore;
The gradient of Ashley's flight = (1000 - 0)/(2.8 - 0) = 357.143 m/km
The gradient of Ashley's flight ≈ 357.143 m/km which is lesser than the required 360 m/km in order to take off and not crash, therefore, she will crash.
The acronym used when referring to the Big Five Factors is OCEAN. True False
true
Explanation:
Because I did the test
Answer:
The right answer is True
find acceleration of block and tension in strings if m1 =8kg m2= 4kg and take g=10m/s²
[tex]\sf{m_1}[/tex] = 8kg
[tex]\sf{m_2}[/tex] = 4kg
g = 10m/s²
[tex]\large\bold{\underline{\underline{To \: Find:-}}}[/tex]→Acceleration of block
→Tension in strings
[tex]\large\bold{\underline{\underline{Solution:-}}}[/tex]Let, the two equation will be ,
[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)
[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)
Putting the value of equation no (1) and (2) we get,
[tex]\implies[/tex] 4g = 12a
[tex]\implies[/tex] 4 × 10 = 12a
[tex]\implies[/tex] 40 = 12a
[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]
[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]
Again, we have to putting the value of a in the equation no (2) we get,
[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]
[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]
[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]
[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40
[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]
[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N
[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².
And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N
Name three ways you could increase the strength of an
electromagnet:
Answer:
adding more turns to the coilwrapping the coil around an iron, more specially a nail ironincreasing the current flow into the coilExplanation:
A 30 kg object has a frictional force of 60 N. It's coefficient of friction must be...?
A) 0.2
B) 2
C) .002
D) 20
mass = 30kg
frictional force = coefficient of friction * (mass * g)
g = 9.8 m/s^2
So:
60N = x * 294 N
x = 60 N / 294 N = 0,2
A satellite was in two separate crashes. In both crashes, the satellite had the same mass. Engineers want to know about the speed and direction of the satellite after the crashes. Why would the crash affect the motion of the satellite, and which crash caused a greater change in motion for the satellite?
Answer & Explanation:
Crashing into the asteroid would cause the satellite to slow down, stop, or reverse direction, because it is a force in the opposite direction to the satellite's motion. Whichever crash was a stronger force would cause it to change motion more. It takes a stronger force to change the velocity of a more massive object.
True or False: In a parallel circuit, if one path is broken, electrons continue to flow to the
other paths
Answer:
false
Explanation:
this is what google said
No because the path the electricity needs to follow is broken. In a parallel circuit, electricity has more than one path to follow. Electrons can follow different paths as they flow from the negative side of the battery to the positive side.
PLZ HELP ME
1. A stone is thrown horizontally from a cliff 30m high with an initial speed of 20m/s. How far from the cliff does the stone strike the ground?
2. A ball rolls off the edge of a table 1.44m above the floor and strikes the floor at a point 2m horizontally from the edge of the table.
A) What is the time the ball was in the air?
B) What is the initial velocity of the ball?
3. A golfer hits a ball and gives it an initial velocity of 40 m/s, at an angle of 30º above the horizontal.
A) How long does the ball stay in the air?
B) How far horizontally (the range) does the ball travel before hitting the ground?
Answer:
1. The stone will strike the ground 49.46 m from the base of the cliff
2. A) Approximately 0.542 seconds
B) Approximately 3.69 m/s
3. A) The time the ball spends in the air is approximately 4.0775 s
B) The horizontal range is approximately 141.25 m.
Explanation:
1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)
∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds
The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m
The stone will strike the ground 49.46 m from the base of the cliff
2. A) The time the ball spends in the air = t = √(h/(1/2 × g)
∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds
B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s
The initial horizontal velocity ≈ 3.69 m/s
3. A) The time the ball spends in the air is given by the following equation;
t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s
t ≈ 4.0775 s
B) The horizontal range, R, of the ball is given by the equation for the range of a projectile as follows;
[tex]Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}[/tex]
Substituting the known values, gives;
[tex]Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m[/tex]
The horizontal range ≈ 141.25 m.
Choose ALL that apply: Read the story below and choose every sphere shown directly in the story. A volcano erupts on a mountain side. It creates a huge cloud of smoke and ash which block out the sun, making it harder for plants to grow.
Question 3 options:
Biosphere
Geosphere
Hydrosphere
Atmosphere
Answer:
biosphere
Explanation:
pretty sure bc it is ground
A stone is thrown straight up in the air. If g represents the acceleration due to
gravity, which one of the following statments about the stone is false?
When the stone reaches the top of its flight, its acceleration is still g.
As the stone rises, its potential energy decreases.
When the stone reaches the top of its flight, its energy is zero.
As the stone rises, it is accelerated downward.
As the stone rises, its kinetic energy decreases.
Answer:
The correct false statement is;
As the stone rises, its potential energy decreases
Explanation:
When the stone is thrown straight up into the air, the initial velocity, u, progressively decreases according to the following equation;
v = u - g·t
Where;
v = The final velocity
g = The acceleration due to gravity = 9.81 m/s²
t = The time taken
Therefore whereby, the kinetic energy. K.E. is given by the equation , K.E. = 1/2 × m × u², as u reduces, the kinetic energy reduces
However, the potential energy, P.E. is given as P.E. = m × g × h
Where;
h = Height
m = The mass of the stone
Therefore, as the stone rises, the potential energy increases.
A dumptruck filled with sand moves 1.8 km/h when it begins to accelerate uniformly at a constant rate. After traveling 4.0 102 m, the truck's speed is 24.0 km/h. What is the magnitude of the truck's acceleration?
The acceleration of the truck is obtained from the calculation done as 0.055 m/s^2.
What is the magnitude of the truck's acceleration?We know that the acceleration is defined as the rate of the change of the velocity of the object with time and we can be able to obtain the acceleration by the use of the equations of kinematics as usual.
Initial velocity = 1.8 km/h or 0.5 m/s
Final velocity = 24.0 km/h or 6.67 m/s
Distance covered = 4.0 * 10^2 m
Then;
v^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance covered
a = v^2 - u^2/2s
a = (6.67)^2 - (0.5)^2/2 * 4.0 * 10^2
a = 44.4 - 0.25/800
a = 0.055 m/s^2
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A sample of oxygen gas occupies a volume of 5.0L at 90kPa pressure. What volume will it occupy at 145kPa?
A. 3.10
B. 5.10
C. 7.0
D. 2.5
Answer:
The answer is option AExplanation:
The new volume can be found by using the formula for Boyle's law which is
[tex]P_1V_1 = P_2V_2[/tex]
Since we are finding the new volume
[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]
From the question we have
[tex]V_2 = \frac{5 \times 90000}{145000} = \frac{450000}{145000} = \frac{450}{145} \\ = 3.103448...[/tex]
We have the final answer as
3.10 LHope this helps you
If Newton's third law was true, then why does a table move when I push it? If the table exerted the same amount of force to me, why does it move?
400 N of load can be overcome by an effort of 50 N by using a lever. Calculate the mechanical advantage of the lever.
Answer:
load (l)=400N
Effort(E)=50N
mechanical advantage (MA)= load ÷Effort
(ma)=400÷50
(ma)=8
Explanation:
I copy pasted from the answer from the same question. Remember to first check if ur question is there
Jen had an average speed of 2.5 m/s when hopping on one foot. If she hopped for 5.0 seconds, for what distance was she hopping?
Explanation:
distance
speed =_________
time
distance = speed × time
= 2.5 × 5.0
distance = 12.5 m
A man is pulling on a rope with a force of 72 N
directed at an angle of 36◦
to the horizontal.
What is the x-component of this force?
Answer in units of N.
Answer:
57,6N
Explanation:
To find the component of a force on the x-axis we can simply do:
F * cos(36) = 72N * 0.8 = 57,6N
The different odds of survival between a preterm and a full-term newborn involve: cephalic development.
the maturation of the skeletal system.
the maturation of the neurological, respiratory, and cardiovascular systems.
proximo-distal development.
Answer: B
Explanation:
1. In your own words explain what happens at a subduction zone. 2. In your own words explain what happens at a mid-ocean ridge. 3. At a subduction zone what causes magma to rise?
Answer:
1. The subduction zone serves as the meeting point for two tectonic plates.
2. At the Mid- Ocean ridge, decompression melting occurs.
3 What causes the magma to rise is the increase in pressure caused by collection of gases by the magma.
Explanation:
Subduction zone is define as a zone where tectonic plates ( an oceanic plate slides beneath a continental plate) meets and contributes to the rise of magma to the surface in geological sciences.
At the Mid - Oceanic ridge, decompression melting occurs. As mantle ascends beneath the mid-ocean ridge, less and less rock lies above it, so large pressure changes occur, which leads to melting. The melt is less dense than the solid, and rises to the surface to form the oceanic crust.
At the subduction zone the magma that is formed is usually made up of silica rich lava. Thick silica rich magma does not release the gasses very easily so they build up inside the magma chamber. As the gasses collect in the chamber, the pressure rises. It is possible for the pressure to rise so much that the chamber cannot contain the magma and it erupts explosively.
You are making s'mores with a friend. When you heat the marshmallow over the fire, what happens to the volume of the air bubbles inside the marshmallows? *
Answer:
Heat was trapped within the marshmallow.
Explanation:
Increasing temperatures make air contained within the marshmallow extend to fill up more room, causing the versatile sugar combination to spread. Eventually, if there is so much tension? It's small explosion. But take the marshmallow out from the heat, and it's going to deflate even if the extended gelatin does not really recover quickly.
Answer:
Heat gets trapped within the marshmallow.
Explanation:
Rickey Henderson, baseball's record holder for stolen bases, approaches third base. He dives head first, hitting the ground at 6.75 m/s and reaching the base with a speed of 5.91 m/s, accelerating at -5.11 m/s 2 . Determine the distance Rickey slides across the ground before touching the base. How much time is he sliding for before touching the base?
Answer:
The distance is 1.04 m and time is 0.16 seconds.
Explanation:
Initial speed, u = 6.75 m/s
Final speed, v = 5.91 m/s
Acceleration, a = -5.11 m/s²
We need to find the distance Rickey slides across the ground before touching the base and the time he sliding for before touching the base.
Let d is the distance. It can be calculated using third equation of motion as follows :
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(5.91)^2-(6.75)^2}{2\times (-5.11)}\\\\d=1.04\ m[/tex]
Let t is the time he slides for before touching the base. Using first equation of motion as follows :
[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{5.91-6.75}{-5.11}\\\\t=0.16\ s[/tex]
So, the distance is 1.04 m and time is 0.16 seconds.
A stunt man launches a car from the edge of a cliff horizontally. If he is launching off a
30-meter high cliff and must hit a mark 268-meters down range, with what speed
must he leave the cliff?
Answer:
All i got to say is that he is dead dead
Explanation:
What is the height of a 50 kg person that has a potential energy of 4900J?
245,000m
98 m
10 m
Answer:
10 m
Explanation:
PE = mgh
m = 50kg
g= 9.8 m/s^2
h=?
so,
4900= 50×9.8× h
50h = 4900/9.8
50h = 500
h = 10 m
Which of the following best describes applying a force over a period of time?
power
energy
Impulse