Answer:
Explanation:
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help fast I want the correct answer please does spectral diffusion cause light to scatter
Answer: No
Explanation:
Whenever light travelling on a straight line encounters obstruction, it diffracts and scatter.
Scattering of light occurs when light passes through a rough path or a diffused surface.
But in case of spectral diffusion, which is the fluctuation in spectroscopy as a result of time dependent frequency shifts.
Spectral diffusion occurs in particular molecules initiated by excessive excitation energy.
Fluctuation in frequency does not mean diffraction of light or particles
Therefore, spectral diffusion does not cause light to scatter.
Convert Gravitational constant (G) = 6.67×10^-11 Nm²kg^-2 to cm³ g ^-1 s^-2.
Answer:
6.67×10⁻⁸ cm³/g/s²
Explanation:
6.67×10⁻¹¹ Nm²/kg²
= 6.67×10⁻¹¹ (kg m/s²) m²/kg²
= 6.67×10⁻¹¹ m³/kg/s²
= 6.67×10⁻¹¹ m³/kg/s² × (100 cm/m)³ × (1 kg / 1000 g)
= 6.67×10⁻⁸ cm³/g/s²
A body is acted upon by a force of 4N.
As a result, the velocity of the body has
changed from 0.3 m/s to 0.1 m/s passing
through a certain distance. If the mass
of the body is 1 kg, find the distance travelled.
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Kinematics.
so here we get as,
V^2 = U^2 + 2as
so here, a = -0.2 m/s^2
(0.1)^2 = (0.3)^2 + (-0.2)(s)
=> 0.01 = 0.09 - 0.2s
=> 0.2s = 0.08
=> s = 0.08/0.2
=> s = 0.4 m
Derive the following equations for uniformly accelerated motion by graphical method. a) Velocity -time relation b) Position - time relation 3) Position – velocity relation.
Answer:
a) velocity - time realation
that graph's gradient gives the uniform acceleration
A football player kicks a ball at a 30o angle from the ground with an initial velocity of 15 m/s. What is the final velocity of the ball when it hits the ground?
Given that,
Angle = 30°
Initial velocity = 15 m/s
We need to calculate the time of flight
Using formula of time of flight
[tex]T=\dfrac{2u\sin\theta}{g}[/tex]
Where, u = initial velocity
g = acceleration due to gravity
Put the value into the formula
[tex]T=\dfrac{2\times15\sin30}{9.8}[/tex]
[tex]T=1.5\ sec[/tex]
We need to calculate the final velocity of the ball
Using equation of motion
[tex]v=u+gt[/tex]
[tex]v=15+9.8\times1.5[/tex]
[tex]v=29.7\ m/s[/tex]
Hence, The final velocity of the ball is 29.7 m/s.
What is the meaning of refraction
Answer:
A change of direction that light undergoes when it enters a medium with a different density from the one through which it has been traveling.
Answer:
the fact or phenomenon of light radio waves etc being deflected in passing obliquely through the interface between one ,medium and another or through a medium of varying density
Explanation:
Pluto was first observed in 1930, and its largest moon, Charon, was discovered in 1978. A few years after Charon’s discovery, astronomers were able to observe a series of eclipses as Pluto and Charon passed in front of one another. By studying how the brightness of Pluto and Charon changed as they eclipsed each other, astronomers were able to measure the masses and radii of both Pluto and its moon. What did these measurements imply about the average densities of Pluto and Charon?
Answer:
The average densities of both matches the expected density for objects made from water ice.
Explanation:
Charon's density is 1.2 to 1.3 g / cm3, while Pluto's density is 1.8 to 2.1 g / cm3. This was discovered in many researches and measurements of these two celestial bodies, with the objective of understanding them and promoting efficient scientific knowledge.
With the measurements of the average densities between pluto and Charon it was possible to conclude several statements about them. Firstly, it is possible to see that the two formed independently and at different times, in addition to indicating the existence of few rocks in charon, which is consistent with the average density of objects made mostly of water ice.
A toboggan with two riders has a total mass of 87.0 kg. A third person is pushing the toboggan with a force of 42.5 N at the top of a hill with an angle of 16°. The force of friction on the toboggan is 36.0 N. Which statement describes an accurate free-body diagram to represent the situation? (Choose one of the forces acting on the system with correct magnitude and direction.)
Options:
a) An arrow of magnitude 852.6 N points perpendicular to the slope of the hill.
b) An arrow of magnitude 6.50 N points down the slope of the hill.
c) An arrow of magnitude 78.5 N points down the slope of the hill.
d) An arrow of magnitude 852.6 N points straight down.
Answer:
d) An arrow of magnitude 852.6 N points straight down.
Explanation:
The total mass of the two riders, m = 87.0 kg
The free body diagrams of the situation described are drawn and contained in the files attached to this solution.
Note that the weight of the toboggan will act directly downwards.
Therefore, the weight of the toboggan, W = mg
W = 87 * 9.8
W = 852.6 N
Since the arrow representing the weight of the toboggan points straight down, the correct answer is that an arrow of magnitude 852.6 N points straight down.
If I were to fill a water bottle full of air and go up in elevation, would the water bottle expand or shrink? If I were to fill a water bottle full of air and go down in elevation, would the water bottle expand or shrink? I am at elevation 20000 I think.
Answer:
a. It would shrink
b. It would expand
Explanation:
a. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure decreases with altitude, when we go up in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go higher. Since the atmospheric pressure exerted by the molecules of air in the atmosphere are greater than that exerted by the molecules of air in the water bottle, this causes the volume of the water bottle to decrease and thus shrinks the water bottle until the pressure balances out
b. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure increases with decreasing altitude, when we go down in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go lower. The water bottle expands until the atmospheric pressure outside equals the pressure inside the water bottle.this causes the volume of the water bottle to increase and thus expands the water bottle until the pressure balances out
how does gravitational pull affect planets with the same mass but different distance from the sun?
Answer:
it just pulls them at the same time
Explanation:
A water pipe tapers down from an initial radius of R1 = 0.2 m to a final radius of R2 = 0.09 m. The water flows at a velocity v1 = 0.87 m/s in the larger section of pipe. What is the volume flow rate of the water?
Answer:
0.109 m/s
Explanation:
The calculation of the volume flow rate of the water is shown below:-
Av = Velocity ([tex]\pi[/tex])(Radius)^2
= 0.87([tex]\pi[/tex])(0.2)^2
= 0.135258 m^3 / sec
= 0.109371429 m/s
or
= 0.109
So, for calculating the volume flow rate of the water we simply applied the above formula i.e by multiplying the velocity with pi and squaring of radius so that the volume could come
5. A bus starting from rest accelerates in a straight line at a constant rate of 3m/s2 for 8s. Calculate the distance travelled by the bus during this time interval.
Answer:
d = 96 meters
Explanation:
a = acceleration
t = time
d = distance
[tex]d = \frac{1}{2} \times a \times {t}^{2} [/tex]
[tex]d = \frac{1}{2} \times 3 \times {8}^{2} [/tex]
[tex]d = 96[/tex]
A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that its tires will not leave the track? Round to one decimal place and include units. Image:
Answer:
see explanations below
Explanation:
At the point when the car leaves the track, the reaction on the road is zero, meaning that the centrifugal force equals the gravitation force, namely
mv^2/r = mg
Solve for v in SI units
v^2 = gr = 9.81 m/s^2 * 14.2 m = 139.302 m^2/s^2
v = sqrt(139.302) = 11.8 m/s
Answer: at 11.8 m/s (26.4 mph) car will leave the track.
differences between concave and convex meniscus
Explanation:
A concave meniscus,(normally seen) occurs when the molecules of the liquid are attracted to those of the container. This occurs with water and a glass tube. A convex meniscus occurs when the molecules have a stronger attraction to each other than to the container, as with mercury and glass.
Answer:
there are differences between concave and convex menuscus
Explanation:
A concave meniscus, which is what you normally will see, occurs when the molecules of the liquid are attracted to those of the container. This occurs with water and a glass tube. A convex meniscus occurs when the molecules have a stronger attraction to each other than to the container, as with mercury and glass.
A gas is held at atmospheric pressure, approximately 100kPa, and room temperature, 298K,
in a container closed with a piston. The piston is initially in a fixed position so the container has a volume of 2.0dm3.
The gas is heated to a temperature of 100∘C
What is the pressure in the container?
Answer:
125 KPa
Explanation:
Data obtained from the question include:
Initial pressure (P1) = 100 KPa
Initial temperature (T1) = 298 K
Final temperature (T2) = 100°C = 100°C + 273 = 373 K
Final pressure (P2) =..?
Since the volume of the container is fixed, the final pressure in the container can be obtained as follow:
P1/T1 = P2/T2
100/298 = P2/373
Cross multiply
298 x P2 = 100 x 373
Divide both side by 298
P2 = (100 x 373) / 298
P2 = 125.2 ≈ 125 KPa
Therefore, the final pressure in the container is approximately 125 KPa.
0.0000302 in scientific notation
Answer:
3.02x10^-5
Explanation:
A scientific notation consists of
c x 10^n
the c must be a number between 1-9, while n must be an integer.
it indicates the c being multiplied by the nth power of 10.
From 0.0000302, we need to move the decimal to after 3 so that 3.02 can be a number between 1-9. When moving the decimal point to the right side, each digit moved counts as -1 power of 10.
So, to give 3.02, we need to move the decimal by 5 digits. hence, we can conclude n = -5.
0.0000302 = 3.02x10^-5
A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the speed of the satellite.
Answer:
Speed of the satellite V = 6.991 × 10³ m/s
Explanation:
Given:
Force F = 3,000N
Mass of satellite m = 500 kg
Mass of earth M = 5.97 × 10²⁴
Gravitational force G = 6.67 × 10⁻¹¹
Find:
Speed of the satellite.
Computation:
Radius r = √[GMm / F]
Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)
Radius r = 8.146 × 10⁶ m
Speed of the satellite V = √rF / m
Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500
Speed of the satellite V = 6.991 × 10³ m/s
What is the formula for calculating the efficiency of a heat engine? Answers:
Write one or two sentences to compare the internal energy of a molecular gas with the internal energy of a monatomic gas.
What is electronic configuration?
Answer:
Electronic Configuration is the distribution of electrons in sub shells (s,p,d,f).
For Example,
The electronic configuration of Carbon (6 electrons) is [tex]1s^22s^22p^2[/tex]
The coil of wire in the center of the screen encompasses an area through which magnetic field lines pass, so there is a magnetic flux through those coils. With the magnet stationary, is this magnetic flux producing any flow of current or potential difference?
Answer:
No, the coil will produce no flow of current or potential difference.
Explanation:
Magnetic field flux is the number of magnetic field line passing through a given area. It depends on the area and the magnetic field strength through this area. For electromagnetic induction to occur, there must be a constantly changing magnetic field. This is according to Faraday's law of electromagnetic induction that states that the induced EMF is directly proportional to the rate of change in flux ΔФ/Δt, and is also proportional to the number of turns on the coil. A changing magnetic field will lead to a break in the flux linkage, which induces current or potential difference on the coil. A stationary coil through a magnetic filed will therefore produce no electric flow of current or potential difference on the coil.
An apple falls out of a tree from a height of 2.3 m What is the impact speed of the apple?
Answer:
6.72 m/s
Explanation:
recall that the equations of motion may be expressed as
v² = u² + 2as
where,
v = final velocity,
u = initial velocity = 0 m/s because it is stationary before it starts falling
a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)
s = distance traveled = 2.3m
in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.
v² = u² + 2as
v² = 0² + 2(9.81)(2.3)
v² = 45.126
v = √45.126
v = 6.72 m/s
WILL GIVE BRANLIET PLS HELP!!!!! AT LEAST TAKE A LOOK!!!!! I REALLY COULD USE THE HELP!!! SHARE YO SMARTNESSS!!! Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern. Do this using three different methods. The angle to the eighth maximum is 1.12°. The distance from the slits to the screen is 302.0 cm. The distance from the central maximum to the fifth minimum is 3.33 cm. The distance between the slits is 0.000250 m.
Answer:
λ = 6,108 10⁻⁷ m = 610.8 nm
λ = 5.513 10⁻⁷ m = 551.3 nm
Explanation:
Young's double slit experiment results in a pattern consisting of maxima and minima of interference, the maximums are described by the expression
d sin θ = m λ
where d of the distance between the two slits, θ is the angle from the central maximum to the given interference line, λ the wavelength of the radiation and an integer indicating the order of interference
In this exercise they give us several conditions
The first
the angle is 1.12º to the maximum m = 8
the distance between the slits d = 0.000250 m
of the initial equation
λ = d sin θ / m
λ = 0.000250 sin 1.12 / 8
λ = 6,108 10⁻⁷ m = 610.8 nm
The second
the distance from the slits to the screen is L = 302.0 cm = 3.020 m
the distance from the central maximum is y = 3.33 cm = 0.0333 m for interference m = 5
in this case we use that the angle in the experiment is small
tan θ = y / L
tan θ = sin θ / cos θ = sin θ
we substitute
sin θ = y / L
d y / L = m λ
λ = d y / L m
we calculate
λ = 0.000250 0.0333 / (3,020 5)
λ = 5.513 10⁻⁷ m = 551.3 nm
Will Mark Brainliest if Correct PLZ!!!!! A bullet is shot at some angle above the horizontal at an initial velocity of 87m/s on a level surface. It travels in the air for 13.6 seconds before it strikes the ground 760 m from the shooter. At what angle above the horizontal was the bullet fired? Round to the nearest whole number and include units in your answer Use g= -9.8 m/s2 for the acceleration of gravity.
Answer:
≅50°
Explanation:
We have a bullet flying through the air with only gravity pulling it down, so let's use one of our kinematic equations:
Δx=V₀t+at²/2
And since we're using Δx, V₀ should really be the initial velocity in the x-direction. So:
Δx=(V₀cosθ)t+at²/2
Now luckily we are given everything we need to solve (or you found the info before posting here):
Δx=760 mV₀=87 m/st=13.6 sa=g=-9.8 m/s²; however, at 760 m, the acceleration of the bullet is 0 because it has already hit the ground at this point!With that we can plug the values in to get:
[tex]760=(87)(cos\theta )(13.6)+\frac{(0)(13.6^{2}) }{2}[/tex]
[tex]760=(1183.2)(cos\theta)[/tex]
[tex]cos\theta=\frac{760}{1183.2}[/tex]
[tex]\theta=cos^{-1}(\frac{760}{1183.2})\approx50^{o}[/tex]
A box of mass 4.5 kg is pushed across a rough surface (μK = 0.18) for a distance of 2.0 m by a constant force of 10 N. If the object reaches a speed of 2.0 m/s by the end of the push, what was its speed at the beginning of the push?
Answer:
Explanation:
Work done by force applied = force x displacement
= 10 x 2 = 20 J
Negative work done by frictional force
= μ mg x d where μ is coefficient of kinetic friction , m is mass and d is displacement
= - .18 x 4.5 x 9.8 x 2
= - 15.87 J
Net positive work done on the mass = 4.13 J
If v was the initial velocity
increase in kinetic energy = positive work done on mass
= 1 / 2 m v² - 1/2 m u² = 4.13 where v is final and u is initial velocity
1 /2 x 4.5 x 2 ² - 1/2 x 4.5 u² = 4.13
9 - 2.25 u² = 4.13
2.25 u² = 4.87
u² = 2.16
u = 1.47 m /s .
A force of 6 N is used to open a door, wherein the distance of the force to the axis of rotation is 80 cm. If the angular acceleration it acquires is 0.5 rad/s 2, determine the moment of inertia of the door.
Explanation:
∑τ = Iα
(6 N) (0.80 m) = I (0.5 rad/s²)
I = 9.6 kg m²
What will happen to the astronaut when the jets produce these four forces: 10N, 10N, 9N, 9N?
A cars start from rest . after 10 seconds its acceleration become 2 meter per second find its final velocity
Answer:
[tex] \boxed{\sf Final \ velocity = 20 \ m/s} [/tex]
Given:
Initial velocity (u) = 0 m/s
Acceleration (a) = 2 m/s²
Time taken (t) = 10 seconds
To Find:
Final velocity (v)
Explanation:
[tex]\sf From \ equation \ of \ motion: \\ \sf v = u + at \\ \\ \sf v = 0 + 2(10) \\ \\ \sf v = 2 \times 10 \\ \\ \sf v = 20 \ m/s[/tex]
how does an electric iron work when the power is on
Answer:
The basic principle on which the electric iron works is that when a current is passed through a piece of wire, the wire heats up. This heat is distributed to the sole (base) plate of the electric iron through conduction.
A 28-turn circular coil of radius 4.40 cm and resistance 1.00 Ω is placed in a magnetic field directed perpendicular to the plane of the coil. The magnitude of the magnetic field varies in time according to the expression B = 0.010 0t + 0.040 0t2, where B is in teslas and t is in seconds. Calculate the induced emf in the coil at t = 4.20 s.
Answer:
ε = -0.0589V = -58.9mV
Explanation:
In order to calculate the induced emf in the coil, you use the following formula:
[tex]\epsilon=-N\frac{d\Phi_B}{dt}=-N\frac{d(SBcos\alpha)}{dt}[/tex] (1)
ε: induced emf = ?
N: turns of the coil = 28
ФB: magnetic flux trough the coil
S: cross sectional area of the circular coil = π.r^2
r: radius of the cross sectional area of the coil = 4.40cm = 0.044m
B: magnetic field
α: angle between the direction of the magnetic field and the direction of the normal to the cross area of the coil = 0°
You take into account that the area is constant respect to the magnetic field that cross it. Only the magnetic field is changing with time. The magnetic field depends on time as follow:
[tex]B(t)=0.010t+0.040t^2[/tex] (2)
You replace the expression (2) into the equation (1), evaluate the derivative, and replace the values of the other parameters for t =4.20s:
[tex]\epsilon=-NS\frac{dB}{dt}=-NS\frac{d}{dt}[0.010t+0.040t^2]\\\\\epsilon(t)=-NS(0.010+0.080t)\\\\\epsilon(t)=-(28)(\pi(0.044m)^2)(0.010T/s+0.080T/s^2(4.20s))\\\\\epsilon(t)=-0.0589V=-58.9mV[/tex]
The induced emf in the coil is -58.9mV