a 64 kg person rides in an elevator. if the elevator has a downward acceleration of 3.0 , what is the magnitude of the force of the person on the elevator floor?

The current that passes through the hole is 3.5A

Here given ,

Charge = 14 coulomb

Time = 4 sec

We have to current,

I = Q/t

Where Q is the charge and t is time in seconds.

By substituting the values,

I = 14/4

I = 3.5A

Therefore the current through the hole is 3.5A.

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Answer: B. Muscular fitness training increases muscle mass, which increases your metabolism

From the first law of thermodynamics, we have 100 J of heat that we would dump in the hot reservoir.

We know that thermodynamics has to do with the area of science that studies the exchange of heat. Heat is that which could  cause the temperature of an object to rise. Thus heat can also be defined as a form of energy that owes to the difference in temperature between the objects.

From the first law of thermodynamics, we have been told that energy is neither created nor destroyed but we can convert it from one form to another in the system. Here we are told that you perform 100 J of work on a refrigerator that extracts heat from a cold reservoir and dumps heat into a hot reservoir.

This implies that the same amount of heat is dumped.

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As a participant in a research study, Jolan must report what he is doing and how he feels using a smartphone app when he receives an alert. He receives alerts at two random times each day. Jolan is most likely participating in participatory research.

Participant observation (PO) is a research technique in which the researcher actively participates in the daily activities of the participants. The objective is to record conduct under the widest range of possible settings.

Researchers work with community members to understand and resolve community problems, empower community members, and democratize research. The participatory research methods include group discussions of personal experience, interviews, surveys, and analysis of public documents.

The question is incomplete. The correct question is

As a participant in a research study, Jolan is required to report what he is doing and how he is feeling using a smartphone app when he receives an alert. He receives alerts at two random times each day. Jolan is most likely participating in ______ research.

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The inductive reactance is 4.00 times as large as the capacitive reactance is 10.1 Hz or 6.26 radians/sec.

What is inductive reactance?
The resistance provided by the inductor inside an AC circuit to a flow of ac current is known as inductive reactance. Its measurement unit is the ohm (Ω), and its symbol is (XL). For lower frequencies, inductive reactance is typically low, and for higher frequencies, it is high. However, it is insignificant for constant DC current.

The angular frequency (ω) at which the inductive reactance (XL) is 4.00 times as large as the capacitive reactance (XC) is given by the following equation:
XL = 4.00 XC
ωL= 4.00 ωC

where ωL is the angular frequency for the inductor and ωC is the angular frequency for the capacitor.
The angular frequency for the capacitor is given by the following equation:

ωC = 1/(2πRC)
where R is the resistance in ohms and C is the capacitance in farads.
Therefore, substituting the given values of R = 85.0 ohms and C = 14.0 μF, we have:
ωC = 1/(2π*85.0*14.0*10-6) = 2.47 radians/sec
The angular frequency for the inductor is given by the following equation:
ωL = 2πFL

where F is the frequency of the AC source in hertz and L is the inductance in henries.
Therefore, substituting the given values of F = variable and L = 1.50 mH, we have:
ωL = 2π*variable*1.50*10-3 = 6.28*variable radians/sec
Combining the two equations, we have:
6.28*variable = 4.00*2.47
Solving for the variable, we get:
variable = 6.28*4.00/2.47 = 10.1 Hz
Therefore, the angular frequency at which the inductive reactance is 4.00 times as large as the capacitive reactance is 10.1 Hz or 6.26 radians/sec.

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Image distance changes with change in object distance.

What is object and image distance?

The object distance is the distance of the object to the center line of the lens

The image distance is the distance of the image to the center line of the lens

Now lets discuss the image variation with change in distance:

As the distance  between an object and a lens is increased, the image size decreases. This is due to the fact that the light rays from the object are diverging more at a greater distance, and thus the lens is not able to focus them as much. The result is a smaller image.

Moving the object further from the lens causes the image to become smaller and closer to the lens. The image becomes smaller and smaller as we move the object further and further away. It will move closer and closer to the focal point of the image as it approaches.

A lower distance between an object and a lens can increase the size of an image.

In other words, as the object distance decreases , the image distance increases; in other words, the image height rises as well.

When the distance of an object from one’s eye is increased, the image distance remains the same as the original size of the image.

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The shortest distance in which you can stop an automobile by locking the brakes is 59.3m

The frictional force acting on the car is

F(f) = -μmg

where

μ = 0.81 is the coefficient of friction

m is the mass of the car

g = 9.8 m/s^2 is the acceleration due to gravity

According to Newton's second law, the acceleration of the car is equal to the frictional force divided by the mass, so:

a = F(f)/m = -μg = -(0.81) (9.8m/s²) =

-7.9m/s²

So we can find the distance travelled by the car using the equation

v^2 - u^2 = 2ad

where v = 0 is the final velocity of the car, when it comes to a stop

u = 30.6 m/s is the initial velocity

Solving the equation for d, we find

d = v^2 - u^2/2a = 0-(30.6m/s)^2/2(-7.9m/s^2) = 59.3m

Hence, The shortest distance in which you can stop an automobile by locking the brakes is 59.3m

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The moment of inertia can be given as the sum of the moments of inertia of each of the end cylinders plus the moment of inertia of the axle is[tex]{a_y = \frac{g}{1+\frac{R^2}{2r^2}}}[/tex]

Imagine the YoYo When yoyo is falling

In Linear downward direction,

mg-T=ma_y

ay = is linear acceleration

now

[tex]T*r=I_c_m \alpha[/tex]

but from we also know [tex]\alpha =\frac{a_y}{r}[/tex]

[tex]T*r=I_c_m \frac{a_y}{r}[/tex]

substiting above equation in beggining eqyation.

[tex]mg-I_c_m \frac{a_y}{r^2} = ma_y[/tex]

[tex]a_y = \frac{mg}{m+\frac{I_c_m}{r^2}} .......................(1)[/tex]

Icm --> The moment of inertia can be given as the sum of the moments of inertia of each of the end cylinders plus the moment of inertia of the axle:

and mass ofcylinders will half of total mass as spindle mass is negigible. i.e cylinders masses = m/2

[tex]I_c_m =2* \frac{\frac{m}{2}R^2}{2} = \frac{mR^2}{2}...............(2)[/tex]

Substituting 2 in 1 we get

[tex]{ a_y = \frac{g}{1+\frac{R^2}{2r^2}}}[/tex]

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It will take 267 milliseconds for a sample of radon-218 to decay from 99 grams to 0. 50 grams.

We know that half life of a first order reaction is given by: [tex]t_{1/2} = 0.693/k[/tex]

where k = rate of reaction

Given half life = 35 milliseconds

So from this we get k = 0.0198

Now we know that rate of first order reaction is given by: [tex]kt= 2.303 * log(R'/R)[/tex]

where t= time

R'= initial amount = 99 g

R= final amount= 0.50 g

k= rate of reaction = 0.0198

Putting values of these in above equation we get t=267 milliseconds.

i.e. It will take 267 milliseconds for a sample of radon-218 to decay from 99 grams to 0. 50 grams.

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The maximum speed of the electron after collision is

1,258,107 m/s

What is collision?

Any instance in which two or more bodies exert forces on one another quickly is referred to as a collision in physics.

What are the 3 types of collision?

There are three different types of collisions: elastic collisions and inelastic collisions. collision with perfect inelasticity.

I understand that the question you are looking for

The allowed energies of a simple atom are 0.0 eV, 3.5 eV and 5.0 eV . An electron traveling at a speed of 1.5×106 m/s collisionally excites the atom. Part A What is the minimum speed the electron could have after the collision?What is the maximum speed the electron could have after the collision?

The electrons can move from 0.0 eV to 5.5 eV and from 5.5 eV to 9.0 eV, respectively.

The smallest energy difference, from 5.5 to 9.0, is 4.5 ev.

Then, using the equation KE = (1/2)m*v2, we must determine the electron's speed to obtain a kinetic energy of 4.5 ev.

Where,

KE = 4.5 ev * 1 J / (6.242*1018) ev = 7.2098*10 19 J

m = 9.11 x 10 -31 kg, where m is the mass of the electron.

v = (2 * KE/m) = [2*7.2098* 10-19 kg/(9.11*10-31 kg)] = 1,258,107 m/s

In response, 1,258,107 m/s

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The negative sign indicates that the rotations are clockwise i.e. -872.206rad/s

We are given that,

Mass A = m = 2.0kg

Radius A = r = 90cm

Radius B = 40cm

Let's apply the idea of angular number conservation to the rotation of a disc. We construct a system composed of the two discs, where the forces that last the shock are internal at the beginning.

L₀ = I₀ w₀ + I₁ w₁

Thus the instate final. Right after crash

Lf = (I₀ + I1) w

angular momentum is conserved

I₀ w₀ + I₁ w₁ = (I₀ + I₁) w

w = I₀ w₀ + I₁ w₁ / Io + I1

The moment of inertia of a disk with an axis passing through its thermometric center can be calculated by ,

I₀ = ½ m² r₀²

I₁ = ½ m₁ r₁

I₀ = ½ 2.0 × 0.90²

I₀ = 0.81 kg. m

I₁ = ½ 2.0 0.4²

I₁ = 0.16 kg .m

Therefore ,let's reduce the magnitudes the SI system

w₀ = -40rev / (2πrad / 1rev) = -251.2rad/s

w₁ = 90rev (2πrad / 1rev) = 565.2 rad/s

we will assume that the counterclockwise turns are positive

w = (-0.81) (251.2) + (0.16)(565.2) / (0.81 + 0.16)

w = (- 203.47 + 90.432)/ .1296

w = - 113.038/.1296

w = - 872.206rad/s

The negative sign indicates that the rotations would be in clockwise direction.

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Force acting on the wire is 0.243N

One of the four fundamental forces of nature, the electromagnetic force, results in the magnetic force, which is brought about by the motion of charges. When two charge-containing objects move in the same direction, a magnetic attraction pulls them together.

According to the given information

We are given that

Current in, the segment is [tex]$I=1.8$[/tex] amps

Length of segment is[tex]$l=0.3 \mathrm{~m}$[/tex]

Magnetic field [tex]$B=0.45 T^2$[/tex]

In vector form

[tex]$I \vec{l}=1.8 \times 0.3 \hat{j}$[/tex]

    [tex]=0.54 \hat{\jmath} \mathrm{A} \cdot \mathrm{m}$[/tex]                      

[tex]B$\vec{B}=0.45 \hat{k} T$[/tex]

So

Magnetic force on wire is

[tex]& \vec{F}=\overrightarrow{I l} \times \vec{B}=(0.54 \hat{\jmath} \times 0.45 \hat{k}) \mathrm{N} \\[/tex]

[tex]& \vec{F}=0.54 \times 0.45 \hat{\jmath} \times \hat{k} \mathrm{~N} \\[/tex]

[tex]& \vec{F}=(0.243 \mathrm{~N}) \hat{\imath}[/tex]

So

[tex]$F=0.243[/tex] in the positive x - axis direction

Force acting on the wire is 0.243N

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Friction is a self adjusting force. In plain words, it means that if there is an increase in linear velocity, then there shall be an increase in angular velocity as well.

Friction is a self adjusting force . It adjusts with appreciate to external force. Importantly, the static friction is any intermediate value less than the most static friction. In simple phrases, it approach that if there is an boom in linear pace, then there will be an increase in angular velocity as nicely.

Paintings accomplished through force is calculated as the dot manufactured from pressure and displacement of point of software of force. In case of angular motion, force is changed by way of torque and linear displacement is replaced by angular displacement.

The conventional instance of that is a spinning ice skater or a person spinning in an office chair. via pulling in her arms, the skater decreases her second of inertia, so her angular speed has to boom so that it will keep her angular momentum constant.

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The concepts used to solve this problem are force, apparent weight, true weight and circular motion.

When the object is at swing and at the bottom of the swing trajectory, we can predict that the object is in uniform circular motion. To maintain the circular motion, a force acts towards the center of the path. Hence, the object has two forces acting on it. The two forces are, force due to gravity and the centripetal force. At the bottom of the arc, the object requires a maximum force to hold it in its circular path.

Apparent weight defines the heaviness of a given object. When the force of gravity and normal force does not balance each other, the apparent weight of an object will differ from the weight of an object.

When an object is in uniform circular motion, it will experience a centripetal force towards the center of circular path.

The expression for force due to gravity is,

F = mg

The second one is centripetal force along with the force due to gravity which is exerted by swing directed upwards.

F = mg + mv²/r

Therefore, the swing must exert a larger force on the object in an upward direction than to the earth in the downward direction.

At the lowest point, the resultant force is,

Fr = N-mg

The resultant force supplies the centripetal force:

N=mg + mv²/r

Here, mg is the actual weight.

An additional centrifugal force also acts with the actual weight.

Therefore, the apparent weight is greater than true weight.

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The wire bends more than it did before when the switch is closed and the direction of the current is reversed in the wire.

A stream of charged particles such as electrons or ions moving through a conductor for electricity or into empty space is known as an electric current. The net rate of passage of electric charge through a surface or into a control volume is used to measure it. Charge carriers are the moving particles, which depending on the conductor could be any number of different types of particles. Often, electrons flowing over a wire serve as the charge carriers in electric circuits. They may be holes or electrons in semiconductors. Ions are the charge carriers in an electrolyte, while electrons and ions make up plasma, an ionized gas.

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A force of 8.8 N is required to horizontally push a 6kg box across the floor with frictional force of 4N and acceleration of 0.8 [tex]m/s^{2}[/tex].

We know that [tex]F = m*a[/tex] ,where m = mass and a= acceleration.

When a frictional force acts, then

[tex]F = m*a + F_{friction}[/tex]

Given m = 6kg

          a = 0.8 [tex]m/s^{2}[/tex]

          [tex]F_{friction}[/tex] = 4N

Putting these values in above equation we get F = 8.8N.

i.e. A force of 8.8 N is required to horizontally push a 6kg box across the floor with frictional force of 4N and acceleration of 0.8 [tex]m/s^{2}[/tex].

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An ion pore is created in the receptor as a result of a conformational shift brought on by the binding of two acetylcholine molecules to a nicotinic AchR.

Acetylcholine binds to the nicotinic receptors localized on the motor end plate, a specific region of the post-synaptic membrane of the muscle fiber. The nicotinic receptor channels open as a result of this binding, allowing sodium ions to pass into the muscle fiber. Acetylcholine diffuses across the synaptic cleft after being released from synaptic vesicles and binds to acetylcholine receptors on the postsynaptic membrane. The acetylcholine receptor is a pentameric protein made up of five subunits. Acetylcholine binds to the nicotinic receptors concentrated on the motor end plate, a specific region of the post-synaptic membrane of the muscle fiber. The nicotinic receptor channels open as a result of this binding, allowing sodium ions to pass into the muscle fiber. The adrenal cortex contains nicotinic cells, which produce hormones. Both sympathetic and parasympathetic preganglionic neurons are all nicotinic.

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For (a) effect on density when weighing volumetric flask full of water, is that it comes out to be falsely high.

For (b) effect on density when weighing an empty beaker, the density of water would be falsely low.

Now, let's see the given two cases:

(a) If when weighing the flask full of water, there are some droplets of water on the outside, we realize that these droplets would contribute to the mass being measured, but would not be factored in the volume of water (which is the volume of the flask). Hence, the mass in the expression above would be larger than expected.

The effect on the density is that it would turn out to be falsely high.

(b) In this case, we are at the stage of the procedure where we have emptied the beaker and need to ascertain its mass. The purpose for this step is to find out the mass of the water alone. We would subtract the mass of the beaker alone from the mass of the beaker with water. Now, if there is some little water inside the beaker which the student assumes to be empty, the mass of the beaker alone would turn out slightly higher than is true. Hence, the mass of the water alone would in turn come out to be slightly lower than accurate.

Now, Observing the formula for density, the mass would be smaller than accurate, and the density of water would be falsely low.

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Statisticians say that this type of regression equation is linear in the parameters. However, it is possible to model curvature with this type of model. While the function must be linear in the parameters, you can raise an independent variable by an exponent to fit a curve.

Define Linear regression?

Linear regression is easier to use, simpler to interpret, and you obtain more statistics that help you assess the model. While linear regression can model curves, it is relatively restricted in the shapes of the curves that it can fit. Sometimes it can’t fit the specific curve in your data.

Define Nonlinear regression?

Nonlinear regression can fit many more types of curves, but it can require more effort both to find the best fit and to interpret the role of the independent variables.

Thus, Statisticians say that this type of regression equation is linear in the parameters. However, it is possible to model curvature with this type of model. While the function must be linear in the parameters, you can raise an independent variable by an exponent to fit a curve.

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None of the options are appropriate in In a bowling alley with no friction, the force required to keep a ball rolling is minimal.

What Is a Customer Experience Without Friction? Friction is any obstacle that slows down or dissatisfies a customer during their interaction with a business. The simplest definition of frictionless customer service is monitoring the customer journey and improving the customer experience.

By frictionless, what do you mean? A frictionless surface is not possible since a smooth surface will have greater static friction than a rough surface because there will be more electromagnetic forces acting on both surfaces. Additionally, the author just wants to disregard friction on flat surfaces.

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If a student uses two strong forces to lift a 1 kg book using two cables, the tension in the cable will be 562.1 N if the cables are at a 1 degree angle with the horizontal.

Tension is a pulling force that operates in one dimension along the cables' axes in the opposite direction from the direction of the applied force. The combined weight of the elevator box and the person riding inside it, in the case of an elevator, provides the pulling force in the cables is called as Tension.

There are four basic interactions that encompass all known forces in the cosmos. The interactions between subatomic particles are caused by the strong and weak forces, which only operate over very small distances.

F1 sin(tetha)+F2 sin(tetha) = F3

F1 cos(tetha) =  F2cos(tetha)

2F1 sin (tetha) = 2*9.81

F1 sin (1) = 9.81

F1 = 9.81/sin(1)

=562.1N

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Given:

Mass of the merry-go-round, m= 1640 kg

Radius of the merry-go-round, r = 7.50 m

Angular speed,  = ω = (1/8) rev/sec

                             = (2π * 7.8) / 8 rad/sec

                             = 5.89 rad/sec

Therefore, force required,    

F = m * ω² * r

   = 1640 * (5.89)² * 7.5

  = 427126.9 N

Thus, the net work done for the acceleration is given by :

W = F x r

  = 427126.9 x 7.5

  = 3,203,451.75 J

Therefore, the net work done is 3,203,451.75 J

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS : A 1640 kg merry-go-round with a radius of 7.50 m accelerates from rest to a rate of 1.00 revolution per 8.00 s. Estimate the merry-go-round as a solid cylinder and determine the net work needed for this acceleration.]

The total volume of steel can be used in making the drum if the gasoline-filled drum is to float in fresh water is 9 L

The space occupied within an object's borders in three dimensions is referred to as its volume. It is referred to as the object's capability on occasion.

Assuming that gasoline has a density of 750 kg/m3 and steel has a density of 7800 kg/m3 as the density of gasoline is not specified.

There are 2 constraints: 1.  volume of steel + volume of gasoline = volume of water and at the threshold of sinking, 2.  mass of steel + mass of gasoline = mass of water

240L * 1m³ / 1000L = 0.240 m³

first: Vs + Vg = Vw = Vs + 0.240m³

second: ρs*Vs + ρg*Vg = ρw*Vw → substitute for Vw, Vg and all the densities

7800*Vs + 750*0.240 = 1000*(Vs + 0.240) (7800 - 1000)*Vs = 240 - 750*0.240 Vs = 60 / 6800 = 0.00882 m³ = 8.82 L ≈ 9 L

Therefore total volume of steel can be used in making the drum if the gasoline-filled drum is to float in fresh water is 9 L

The complete question is : Because gasoline is less dense than water, drums containing gasoline will float in water. suppose a 240-l steel drum is completely full of gasoline. part a what total volume of steel can be used in making the drum if the gasoline-filled drum is to float in fresh water?

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For a laminar airflow over flat plates with a constant surface temperature, the curve that best represents how the average heat transfer coefficient declines with plate length increases.

In fluid dynamics, laminar flow is characterized by fluid particles passing each other in layers along straight paths with little to no mixing in between. When the fluid is traveling at moderate speeds, it tends to Laminar flow without lateral mixing, which causes adjacent layers to slip past one another like playing cards. The heat transfer coefficient measures the convective heat transfer between a fluid medium (a fluid) and the surface (a wall) it flows over. The Newton-Richmann relation shows the heat transfer coefficient as a proportionality factor.

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The gravitational force between two objects increase if one object doubles in mass and the distance between them decreases by half F = 8G m1 m2 / r^2.

Because F = G*m1*m2/r2,

G * 2m1 * m2 / (r/2)2 = 8G m1 m2 / r2, which is the right answer if m1 doubles and r falls by half.

Objects with mass are drawn toward one another by the gravitational attraction, also known as the force of gravity. The gravitational force of the Earth is something we consider frequently. Your body is kept stationary on the ground by this force. However, every other mass-containing item experiences a gravitational pull from every other mass-containing object. Gravity is a fundamental interaction in physics that produces mutual attraction between all things having mass or energy (from the Latin gravitas, "weight". By far the weakest of the four fundamental interactions, gravity is 1038 times weaker than the strong interaction, 1036 times weaker than the electromagnetic force, and 1029 times weaker than the weak interaction. As a result, it has no discernible impact on the level of subatomic particles. But the most important relationship is gravity.

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Answer:

Simple harmonic motion is a type of periodic motion where the restoring force on the moving particle is proportional to the magnitude of the objects displacement and acts towards the particle's equilibrium position.  

Explanation:

The capacitance of a parallel plate capacitor is 3.612×10⁻¹⁰ohm if the area of each plate is 0.1m² and distance between plate is 0.1inch.

Capacitance is the capacity of a material item or gadget to store electric charge. It is estimated by the adjustment of charge because of a distinction in electric potential, communicated as the proportion of those amounts. Regularly perceived are two firmly related thoughts of capacitance: self capacitance and shared capacitance.

An article that can be electrically charged shows self capacitance, for which the electric potential is estimated between the item and ground. Common capacitance is estimated between two parts, and is especially significant in the tasks of the capacitor, a gadget intended for this reason as a rudimentary straight electronic part.

We know that 1inch=2.54cm

Therefore,0.1inch=2.54×0.1cm=0.245cm=0.00245m

Now, we know that capacitance=∈[tex]_o[/tex]×A /d where

∈[tex]_o[/tex] is the permittivity of free space,

A is the area of cross-section,

d is the distance between two plates.

We know that value of ∈[tex]_o[/tex]=8.85×10⁻¹² Farad/meter

Therefore, C = (8.85×10⁻¹²×0.1)/0.00245

=>C=(8.85×10⁻¹³)/0.00245

=>C=3.612×10⁻¹⁰ohm

Hence, value of capacitance is 3.612×10⁻¹⁰ohm.

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Half of 20mAs is 10mAs, should be the new mAs.

In the first experiment, it was shown that, when the film density is maintained constant, the resolution decreases with rising kVp and increases with increasing mAs, respectively, and that the picture contrast percentage increases with increasing kVp.

Several mAs were chosen for the second part of the experiment, and several kVps were used for each mAs. Five observers read the radiographs.

The second experiment showed that when the film density was not kept constant, the correlations between kVp and resolution and between kVp and the picture contrast percentage were the same as in the first experiment.

However, there was little correlation between MAs and picture contrast % and MAs and resolution.

So when the lateral skull is 68kvp then 20mas and when kvp is increased to 78kvp then new mas will be half that is 10mas

Half of 20mas is 10mas, should be the new mas.

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The speed of the potato at the lowest point of its motion is calculated to be 7 m/s.

The total energy of an object remains constant or changes its form from one energy to another in an isolated system as per the law of conversation of energy.

Therefore, in this case, the potential energy of the potato will be equal to its kinetic energy when the sting is pulled taut and the potato will be released.

Potential Energy = Kinetic Energy

mgh = 1/2 ( mv^2)

Here m represents the mass of the potato,g is the gravitational force on the potato, h is the height of the string, and v represents the velocity of the potato

Substituting the values to determine the speed of the potato at the lowest point of its motion as follows;

0.260 × 9.80 × 2.50 = 1/2 × (0.260 × v^2)

v^2 = 49

v = √49

v = 7 m/s

Therefore, at the lowest point, the potato's speed will be 7 meters per second.

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