A 3.35 g sample of an unknown gas at 81 ∘C and 1.05 atm is stored in a 1.75 L flask.
What is the density of the gas?
density:
g/L
What is the molar mass of the gas?
molar mass:

THIS IS THE COMPLETE QUESTION

Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation.

How much MnO2(s) should be added to excess HCl(aq) to obtain 185 mL of Cl2(g) at 25 °C and 715 Torr?

Answer:

0.62901mol of MnO2(s) should be added

Explanation:

Given:

P = 715/760 = 0.94078atm

v=195ml=0.195l

n = ? moles have to find

R = 0.0821 L atm/K/mole

T = 25 + 273 = 298 K

Then we will make use of below formula

PV = nRT

Insert the values

0.94078*0.195=n 0.0821*298

24.466n=0.1740443

n=0.174/24.466

n=0.007235 nb of moles of cl2

as 1 mole of Cl2 were obtained from 1 mole of MnO2

so 0.007235 of chlorine must have come from

0.007235 moles of MnO2

1 mole of MnO2 = 86.94 g/mole

so 0.007235 moles of MnO2== 86.94* 0.007235

=0.62901

Answer:

According to Le Chatelier's principle, adding additional reactant to a system will shift the equilibrium to the right, towards the side of the products. ... If we add additional product to a system, the equilibrium will shift to the left, in order to produce more reactants.

Answer:

54

Explanation:

Mass number = protones + neutrons

Mass number = 24 + 30

Mass number = 54

Answer:

The answer is option D.

Hope this helps you

Answer:

There are  [tex]\mathbf{8.90172 \times 10^{-14}}[/tex] moles of bactoX present in a 3.0 μL sample volume that contains 7.512×106 bacterial cells

Explanation:

Given that:

The number of molecules present in one bacterial cell is [tex]7.140 \times 10^3[/tex] molecules

and the sample  contains [tex]7.512 \times 10^6[/tex] molecules.

Number of moles = number of molecules /Avogadro's number

where;

Avogadro's number = 6.023 × 10²³

Number of moles = [tex]\dfrac{7.140 \times 10^3}{6.023 \times 10^{23}}[/tex]

Number of moles = [tex]1.185 \times 10^{-20}[/tex] moles

So;  [tex]1.185 \times 10^{-20}[/tex] moles  is present in one bacteria cell

Similarly;  the sample  contains [tex]7.512 \times 10^6[/tex] molecules.

Therefore; the number of moles present in the bactoX is = [tex]1.185 \times 10^{-20} \times 7.512 \times 10^6[/tex]

= [tex]\mathbf{8.90172 \times 10^{-14}}[/tex] moles

Answer:

2415.9g (corrected to 1 d.p.)

Explanation:

(Take the atomic mass of Ga=69.7 and S=32.1)

Assuming Ga is the limiting reagent (because the question did not mention the amount of sulphur burnt),

From the balanced equation, the mole ratio of Ga:Ga2S3 = 4: 2 = 2: 1, which means, every 2 moles of Ga burnt, 1 mole of Ga2S3 is produced.

Using this ratio, let y be the no. of moles of Ga2S3 produced,

[tex]\frac{2}{1} =\frac{20.5}{y}[/tex]

y = 20.5 / 2

= 10.25 mol

Since mass = no. of moles x molar mass,

the mass of Ga2S3 produced = 10.25 x (69.7x2 + 32.1x3)

= 2415.9g (corrected to 1 d.p.)

Answer: It's is called Reaarrangement

Explanation:

Rearrangement is a chemic reaction in which an atom or group of atoms bond migrate from one carbon atom to another. The movement involves two adjacent atoms and move over a large distance. It is important in functional group transformation.

Reaarrangement can be classified based on the atom or group of atoms it migrate.

Nucleophilic rearrangement which involves the migration of atoms with electron pairs.

Electrophilic migration involved the migration of atom or groups without electron pair.

Free radical involves the atom or group of atoms moving with a lone pair of electron.

Answer:

0.45 moles

Explanation:

The computation of the number of moles left in the cylinder is shown below:

As we know that

[tex]\frac{n1}{V1} = \frac{n2}{V2}[/tex]

we can say that

[tex]n2 = n1 \times \frac{V2}{V1}[/tex]

where,

n1 = 1.80 moles of gas

V2 = 12.0 L

And, the V1 = 48.0 L

Now placing these values to the above formula

So, the moles of gas in n2 left is

[tex]= 1.80 \times \frac{12.0\ L}{48.0\ L}[/tex]

= 0.45 moles

We simply applied the above formulas so that the n2 moles of gas could arrive

Answer:

2 PbS(s) + 1.5 O₂(g) + PbO(s) ⇒ 2 SO₂(g) + 3 Pb(s)

Explanation:

Lead can be prepared from galena [lead(II) sulfide] by first heating with oxygen to form lead(II) oxide and sulfur dioxide. The corresponding chemical equation is:

PbS(s) + 1.5 O₂(g) ⇒ PbO(s) + SO₂(g)

Heating the metal oxide with more galena forms the metal and more sulfur dioxide. The corresponding chemical equation is:

2 PbO(s) + PbS(s) ⇒ 3 Pb(s) + SO₂(g)

We can get the overall reaction by adding both steps and canceling what is repeated on both sides.

2 PbS(s) + 1.5 O₂(g) + 2 PbO(s) ⇒ PbO(s) + 2 SO₂(g) + 3 Pb(s)

2 PbS(s) + 1.5 O₂(g) + PbO(s) ⇒ 2 SO₂(g) + 3 Pb(s)

Answer:

Explanation:

the molar mass for Na2CO3 is 2*23+12+3*16=106 g/mole

106*0.251=26.606 grames

Answer:

You require 12.8mL of the 0.500M C₂H₃O₂Na and 7.2mL of the 0.500M C₂H₃O₂H

Explanation:

It is possible to obtain pH of a weak acid using H-H equation:

pH = pKa + log₁₀ [A⁻] / [HA]

For the buffer of acetic acid/acetate, the equation is:

pH = pKa + log₁₀ [C₂H₃O₂Na] / [C₂H₃O₂H]

Replacing:

5.00 = 4.75 + log₁₀ [C₂H₃O₂Na] / [C₂H₃O₂H]

1.7783 =  [C₂H₃O₂Na] / [C₂H₃O₂H] (1)

Buffer strength is the concentration of the buffer, that means:

0.1M = [C₂H₃O₂Na] + [C₂H₃O₂H] (2)

Replacing (2) in (1):

1.7783 =  0.1M - [C₂H₃O₂H] / [C₂H₃O₂H]

1.7783 [C₂H₃O₂H] = 0.1M -  [C₂H₃O₂H]

2.7783 [C₂H₃O₂H] = 0.1M

Also:

[C₂H₃O₂Na] = 0.1M - 0.036M

The moles of both compounds you require is:

[C₂H₃O₂Na] = 0.1L × (0.064mol / L) = 0.0064moles

[C₂H₃O₂H] = 0.1L × (0.036mol / L) = 0.0036moles

Your stock solutions are 0.500M, thus, volume of both solutions you require is:

[C₂H₃O₂Na] = 0.0064moles × (1L / 0.500M) = 0.0128L = 12.8mL

[C₂H₃O₂H] = 0.0036moles × (1L / 0.500M) = 0.0072mL = 7.2mL

Answer:

The type of mixture whose components are seen through our naked eyes is known as heterogeneous mixture. it is a mixture of small constituent parts of substances.

for eg, mixture of sand and sugar.

hope it helps..

Answer:

2 H⁺ + 2e = H₂    ( reduction )

Explanation:

Fe( s ) + 2 CH₃COOH = Fe ( OOCCH₃ ) ₂ + H₂

Fe( s ) = Fe⁺² + 2e     ( oxidation )

2 H⁺ + 2e = H₂    ( reduction )

Answer:

The answer is option A.

Na4C

Hope this helps you

Answer:

CaC₂  +  2H₂O  →  C₂H₂  + Ca(OH)₂

Explanation:

In order to find out the reaction, we must know the reactants.

For this situation, we make acetylene gas from carbide calcium CaC₂ and H₂O (water); therefore the reactants are:

- CaC₂  and  H₂O

Acetylene is one of the products made  →  C₂H₂

So the reaction can be formed as this:  CaC₂  +  H₂O  →  C₂H₂

We missed the calcium, and this reaction also makes, Calcium Hydroxide, so the complete equation must be:

CaC₂  +  H₂O  →  C₂H₂  + Ca(OH)₂

This is unbalanced, because we have 1 O in left side and 2 in right side so we add 2 in water so now, we get the complete reaction:

1 mol of calcium carbide reacts to 2 mol of water in order to produce 1 mol of acetylene and 1 mol of calcium hydroxide.

Answer: CO2(g)+H2O(I) > H2CO3(Aq)

Explanation:

Got it right?

Answer:

- Iron is oxidized from 0 to +2.

- Hydrogen is reduced from +1 to 0.

Explanation:

Hello,

In this case, for the given reaction, we must first indicate the oxidation state of each element (notice that HC2H3O is acetic acid)

[tex]Fe ^0(s)+ 2 H^+(C_2H_3O_2)^-(aq) \rightarrow Fe^{2+}(C_2H_3O_2)_2^-(aq) + H_2^0(g)[/tex]

Thereby, notcing that iron is alone at the beginning, it has zero as its oxidation state, but once the reaction is undergone, it changes to +2, moreover, the displaced hydrogen in the acetic acid is with +1 but after the chemical reaction it becomes alone for which its oxidation state is 0, thereby, we find that:

- Iron is oxidized from 0 to +2.

- Hydrogen is reduced from +1 to 0.

Best regards,

Answer:

#1

Explanation:

molarity of EDTA solution 0.0675

no1

Answer:

2 CH₃OH  +  3 O₂  ⇒  2 CO₂  +  4 H₂O

Explanation:

Methanol is CH₃OH.  Oxygen is O₂.  A combustion produces CO₂ and H₂O.  Create an equation using this information and balance.

CH₃OH  +  O₂  ⇒  CO₂  +  H₂O

2 CH₃OH  +  3 O₂  ⇒  2 CO₂  +  4 H₂O

The balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product is

CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)

From the question,

We are to write a balanced equation for the combustion of liquid methanol in air.

The combustion of liquid methanol in air is the reaction between methanol (CH₃OH) and oxygen (O₂). The reaction yields carbon(IV) oxide and water.

Now, for the balanced equation for the combustion of liquid methanol in air

The balanced chemical equation is

CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)

Hence, the balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product is CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)

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Answer:

Following are the answer to this question:

Explanation:

In the given question an attachment file is missing, that is attached. please find the attached file, and the following are the description of the given points:

a. At 100 degrees in 100 mL 5 g is dissolved.  

For, it required:

[tex]\to 2g = 100 \times \frac{2}{5}[/tex]

         [tex]= 40 \ \ ml \ of \ water.[/tex]  

b. At 0 degrees 100 mL dissolve in 0.3 g.  

So, the dissolve:

[tex]\to 40 \ ml= 0.3\times \frac{40}{100}[/tex]

               [tex]= 0.12g.[/tex]

After refrigeration 0.12 g will still be dissolved.  

c. After dissolving and freezing, precipitation can occur which would still be impure if the cooling is instantaneous. The added solvent was also too hard to recrystallize. The solvent was placed below its place of reservation.  

d. Recovery percentage:

[tex]\to \frac{0.8}{2}\times100[/tex]

[tex]\to 40 \ \%[/tex]

The melting point of acetanilide:

[tex]\to 114.3^{\circ}.[/tex]

Found=109(medium)  

Melting point error percentages:

[tex]= \frac{114.3-109}{114.3}\\\\=4.63 \ \%[/tex]

Answer:

322

Explanation:

This is easy

Answer:

Maximum mass of compound produced = 64 Kg

Explanation:

Carbon monoxide react with hydrogen to produce methanol. Equation for the reaction is given as follows:

CO(g) + 2H₂(g) -----> CH₃OH(l)

From the equation of reaction, 1 mole of CO reacts with 2 moles of Hydrogen gas to produce 1 mole of methanol.

Molar mass of CO = 28 g

Molar mass of H₂ = 2 g

Molar mass of methanol = 32 g

Therefore, 28 g of CO reacts with  4 g of H₂ to produce 32 g of methanol

8.0 Kg of hydrogen will react with 8 * (28/4) Kg of CO = 56 Kg of CO.

therefore, hydrogen is the limiting reactant in the reaction under consideration.

8.0 Kg of Hydrogen will react with 56 Kg of CO to produce 8 * (32/4) Kg of methanol =  64 Kg of methanol

Therefore, maximum mass of compound produced = 64 Kg

Answer:

The next part is 8.8

Explanation:

You're gonna subtract 31.3 by 22.5 which is 8.8

You're welcome :)

The value of q-cal is 142.8 J in the reaction of magnesium and hydrochloric acid in a different constant pressure calorimeter with a calorimeter constant of 12.75 J/degrees Celsius.

A calorimeter is a device that measures the amount of heat in a chemical or physical process.

To calculate the value of q-cal (heat absorbed or released by the calorimeter), we need to use the following equation:

q = C * ΔT

Where q is the heat absorbed or released by the calorimeter, C is the calorimeter constant, and ΔT is the change in temperature.

In this case, we know that the calorimeter constant is 12.75 J/degrees Celsius, the initial temperature is 22.5 degrees Celsius, and the final temperature is 33.7 degrees Celsius.

Therefore, we can calculate ΔT as:

ΔT = final temperature - initial temperature

ΔT = 33.7°C - 22.5°C

ΔT = 11.2°C

Substituting these values into the equation, we get:

q = C * ΔT

q = 12.75 J/°C * 11.2°C

q = 142.8 J

Therefore, the value of q-cal is 142.8 J.

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Your question seems incomplete, the probable complete question is:

Suppose you perform the reaction of magnesium and hydrochloric acid in a different constant pressure calorimeter with a calorimeter constant of 12.75 J/degrees Celsius. The initial temperature in the calorimeter is 22.5 degrees Celsius and the final temperature after the reaction is 33.7 degrees Celsius. What is the value of q-cal?

Answer: The mass percent by volume is 101.6%

Explanation:

The solution concentration expressed in percent by volume means that the amount of solute present in 100 parts volume of solution.

It is represented in formula as :

mass percent by volume =[tex]\frac{\text {mass of solute}\times 100}{\text {Volume of solution in ml}}\%[/tex]

Given : mass of glucose = 330.1 g

volume of solution = 325 ml

Thus mass percent by volume =[tex]\frac{330.1g\times 100}{325ml}=101.6\%[/tex]

Thus the mass percent by volume is 101.6%

Answer:

filter the hot mixture.

Explanation:

Solid is stayed undissolved since the arrangement is gotten super saturated. On the off chance that solid molecule is available recrysallization won't happen in this way we need expel the solid molecule by filtarion in hot condition itself . Subsequently, arrangement become totally homogenous and recrysallization item will shaped by moderate cooling

Answer:

198.56g of GaCl3

Explanation:

We'll begin by calculating the number of mole HCl in 2.25 L of a 1.50 M solution of HCl. This is illustrated below:

Molarity of HCl = 1.50 M

Volume = 2.25 L

Mole of HCl =..?

Molarity = mole /Volume

1.5 = mole /2.25

Cross multiply

Mole = 1.5 x 2.25

Mole of HCl = 3.375 mole

Next, we shall determine the number of mole Gallium chloride, GaCl3 produced from the reaction. This is shown below:

2Ga + 6HCl —> 2GaCl3 + 3H2

From the balanced equation above,

6 moles of HCl reacted to produce 2 moles of GaCl3.

Therefore, 3.375 mole of HCl will react to produce = (3.375 x 2)/6 = 1.125 mole of GaCl3.

Therefore, 1.125 moles of GaCl3 were produced from the reaction.

Next, we shall convert 1.125 mole of GaCl3 to grams. This is illustrated below:

Molar mass of GaCl3 = 70 + (35.5x3) = 176.5g/mol

Mole of GaCl3 = 1.125 mole

Mass of GaCl3 =..?

Mole = mass /Molar mass

1.125 = mass of GaCl3 /176.5

Cross multiply

Mass of GaCl3 = 1.125 x 176.5

Mass of GaCl3 = 198.56g

Therefore, 198.56g of GaCl3 were produced from the reaction.

Answer:

5 degrees Celsius.

Explanation:

Temperature measures the average kinetic energy of  particles of the substances. Therefore a temperature of 41 Fahrenheit is the same as 5 degree Celsius

Temperature is used to measure degree or intensity of heat of a particular substance. Temperature is measured by an instrument called thermometer.

Temperature can be measured in degree celsius °c, Kelvin k or in Fahrenheit. Temperature is a physical quantity. Heat always flow from higher temperature source to lower temperature source.

We can convert these units of temperature into one another. The relationship between degree Celsius and  Fahrenheit can be expressed as:

°C={5(°F-32)}÷9

Substituting given values in above equation

°C= {5(41-32)}÷9

°C= 5°C

Therefore a temperature of 41 Fahrenheit is the same as 5 degree Celsius

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Answer:

8 electrons

Explanation:

The second principal energy level has two sublevels: 2s and 2p

2s : 2 electrons

2p : 6 electrons (3 sublevels × 2 electrons each = 6 electrons)

It can hold a maximum of 8 electrons.

Hope this helps. :)

Answer:

1. Not to have enough salt water on the foil

2.not cleaning the foil well to remove interfering materials

Answer:

160.53L

Explanation:

Since Pressure is kept constant we can use charles law