Answer:
0
Explanation:
F1 = G•2.2•4.66/3² (pointed right)
F2 = G•2.2•4.66/3² (pointed left)
subtract the two to get zero
The gravitational force on the 2.20 Kg mass is 7.53 × 10⁻¹¹ N to the right and and the same to the left. The same forces are in opposite direction and thus balances each other.
What is gravitational force?The gravitational force is the force by which an object attracts other object into its center of mass. The gravitational force depends on the masses of the objects and distance between them by the equation written below:
g = G m1 m2/r²
where G is the universal gravitational constant equal to 6.67 × 10⁻¹¹ N
Given the mass at the origin = 2.20 kg
mass in right side = 4.66 Kg.
distance = 3 m.
then g = 6.67 × 10⁻¹¹ N × (2.20 × 4.66 kg)/3² = 7.53 × 10⁻¹¹ N
However, the equal force acts from the equal distance by the same mass from the left side also. Therefore, both forces cancel each other in magnitude and the net gravitational force will be zero.
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How old is the earth? PLEASE HELP ME WITH THIS QUESTION BANANAFANART
I’LL GIVE U BRAINLIEST BANANAFANART PLEASE ANSWER IT :(
Answer:
The earth is 4 billion years old.
Explanation:
pls help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
the last answer is correct.
Explanation:
If one team pulls with more force than the middle flag or marker will move
a student does 100 j of work on the handle of a bicycle pump. the pump does 40 j of work pushing the air into the tire. what is the efficiency of the pump? show your work.
Answer:
40%
Explanation:
Student -> Pump = 100j
Pump -> Tire = 40j
Between the two, 60j of energy were lost.
Efficiency = 40/100 = 40%
A 1242 kg car is moving at 22.5 m/s when it skids to a stop. The car's brakes, which caused the stop, applied a force of -7210 N in order to slow down the car. What was the acceleration of the car during it's slowing down to rest?
The work needed to stop the car is
W = ∆K = 0 - 1/2 (1242 kg) (22.5 m/s)² ≈ -314 kJ
A stopping force that does this amount of work, pointing in the opposite direction with magnitude 7210 N, would be exerted over a distance x such that
W = (-7210 N) x ==> x ≈ 43.6 m
how much momentum does a 5 kg object moving at 10 m/s have?
Answer:
p = 50 kg·m/s
Explanation:
attached is a good way to remember the formula!
Question 10 of 20 Which statement describes an example of static electricity? O A. Electric charges move from a position of higher potential energy to a position of lower potential energy. O B. Electrons flow from an outlet into a toaster, causing it to heat a slice of bread. O C. A person rubs a shoe on a rug, causing extra electrons to be transferred to the shoe. O D. A conductor allows electrons to flow through it.
Answer:
C. A person rubs a shoe on a rug, causing extra electrons to be transferred to the shoe
Explanation:
I just took the test
Answer:
C. A person rubs a shoe on a rug, causing extra electrons to be transferred to the shoe.
Explanation:
a pe x
Johanna took her younger brother to the playground because he likes to swing. Look at the diagram below that shows Johanna pushing her brother on a swing.
12. After Johanna pushes for a while, she begins to feel tired. What type of energy is transformed into the kinetic energy she uses? A. chemical B. electrical C. nuclear D. thermal - Help fast I have my test soon!
Answer:
A. chemical
Explanation:
the type of energy our body contain is chemical energy and that chemical energy is the one used while pushing the swing.. so I guess it's chemical energy.. based on my knowledge hope this helps.
Two types of energy can be either kinetic or potential energy. Identify those two types. For each type, explain why it can be either kinetic or potential. -Help fast i have my test soon!
Answer:
All forms of energy are either kinetic or potential. The energy associated with motion is called kinetic energy . The energy associated with position is called potential energy . Potential energy is not "stored energy".
Explanation:
Developing: Ohm’s Law states that Voltage (V) = Current (I) x Resistance (R). You can calculate the voltage. You can also solve for current or resistance if you mathematically rearrange the equation.
Use Ohm’s Law to calculate the missing variable. Be sure to show your work in the space provided. Round to the nearest tenths.
What is the resistance of a light if the voltage is 12 V and the current is 15 A (living room)?
What is the voltage of a circuit with 15 amps (bedroom) of current and a bedroom light with 12 ohms of resistance?
There is a 28 resistance in the dryer. It is plugged into a 240 V circuit. How much current passes through the dryer?
V = I · R
I = V / R
R = V / I
R = V / I
Resistance of the living room light = (12V) / (15A)
Resistance of the light = 0.8 ohm
V = I · R
Voltage of the bedroom circuit = (15 A) · (12 ohms)
Voltage of the bedroom circuit = 180 volts
I = V / R
Current through the dryer = (240V) / (28 ohms)
Current through the dryer = 8.57 A
Is a mirror reflective?
Answer:
A mirror is an image reflecting an object.
Explanation:
yes a mirror is reflective
A mirror is a reflector of the wave. When light waves reflect the flat surface of a mirror, the same curvature and vergence are retained, in equal but opposite direction, by these waves as by the original waves.Coating a piece of glass on one side with glistening metals can convert the glass into a mirror that mirrors light. Window glass may reflect only 8% of the light, while mirrors can display 95% of the light. The glass in a mirror is generally covered in a silver or aluminum layer. dark material is placed on the back to prevent the tearing of the metal (reacting with the air and turning dull). The other side of the glass can be a mirror or a simple glass. This can be used to make windows easily visible, but difficult to view.Answer:
Explanation:
Yes, a mirror is reflective to light. But there are electro magnetic waves of different frequency like radio wave that a mirror is not reflective.
If the same pressure is exerted over a greater area will more of less force result?
more force
less force
the same amount of force
Answer:
less force
Explanation:
less force because they is increase in area and not enough energy to balance the whole equation
Answer:
the same
Explanation:
8. An example of muscular endurance is:
A. Sit and Reach
B. Push Up
C. 100 meter sprint
D. None Of The Above
9. A force is applied horizontally to a 20 kg box on a flat table, if the acceleration of the box is 2 m/s and the
coefficient of friction between the box and the table is 0.5, what was the magnitude (number) of the
applied force?
By Newton's second law,
n + (-w) = 0
p + (-f ) = (20 kg) (2 m/s²)
where n is the magnitude of the normal force, w is the weight of the box, p is the magnitude of the applied force (p for push or pull), and f is the magnitude of the friction force.
Calculate the weight of the box:
w = (20 kg) (9.80 m/s²) = 196 N
Then
n = w = 196 N
and
f = µ n = 0.5 (196 N) = 98 N
Now solve for p :
p - 98 N = 40 N
p = 138 N
) or
The best places to take a pulse are at the radial artery (
the carotid artery (
Answer:
on edge, it is all of them:
carotid
brachial
radial
femoral
popliteal
dorsalis pedis
Explanation:
I need help!!!!
Please and thank u!
Answer:
False
True
False
True
False
True
Explanation:
What tool of dream analysis says that feelings and urges are hidden inside an event? condensation symbolism projection displacement
Answer:
Condensation
Explanation:
Answer:
Condensation! Hope this helps!!!
Explanation:
The weight of a cart with a mass of 150 kg is. _N. (Use 9.8m/s2 for the acceleration due to gravity.)
Answer: it’s 1,470 N
Explanation:
Since F=m*a then 150*9.8=1,470.
Weight of given cart is 1,470 N
Given that:
Mass of cart = 150 kg
Acceleration due to gravity = 9.8 m/s²
Find:
Weight of cart
Computation:
Weight = m × g
Weight of cart = Mass of cart × Acceleration due to gravity
Weight of cart = 150 × 9.8
Weight of cart = 1,470 N
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Which describes the role of oxygen in photosynthesis? *
It is a reactant, so it is released by the plant.
It is a product, so it is released by the plant.
It is a reactant, so it enters the plant.
It is a product, so it enters the plant.
Answer:
It is a product, so it is released by the plant.
Explanation:
[tex]6CO2 + 6H2O[/tex] → [tex]C6H12O6 + 6O2[/tex]
The plant uses water and carbon dioxide to create glucose and oxygen. Glucose is plant food, and Oxygen is given off as a byproduct.
Answer:
It is a product, so it is released by the plant.
Explanation:
Device A has a current of 0.4 A and a resistance of 3 Ω. Device B has a current of 0.6 A and a resistance of 3Ω. Which device would be more energy efficient?
Your answer would be Device A.
Answer:
Device A because it would use more voltage :D
Explanation:
A balloon-powered car rolls across the floor at a speed of 0.711 m/s. How long does it take to cover 8.25 m?
Answer:
Time = 11.60 seconds.
Explanation:
Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.
Mathematically, speed is given by the equation;
[tex]Speed = \frac{distance}{time}[/tex]
Given the following data;
Speed = 0.711m/s
Distance = 8.25m
To find the time;
Making time the subject of formula, we have;
[tex]Time = \frac{distance}{speed}[/tex]
Substituting into the equation, we have;
[tex]Time = \frac{8.25}{0.711}[/tex]
Time = 11.60 secs.
If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 1030 kg, what is the average distance between the planet and the star?
Answer:
9.36*10^11 m
Explanation
Orbital velocity v=√{(G*M)/R},
G = gravitational constant =6.67*10^-11 m³ kg⁻¹ s⁻²,
M = mass of the star
R =distance from the planet to the star.
v=ωR, with ω as the angular velocity and R the radius
ωR=√{(G*M)/R},
ω=2π/T,
T = orbital period of the planet
To get R we write the formula by making R the subject of the equation
(2π/T)*R=√{(G*M)/R}
{(2π/T)*R}²=[√{(G*M)/R}]²,
(4π²/T²)*R²=(G*M)/R,
(4π²/T²)*R³=G*M,
R³=(G*M*T²)/4π²,
R=∛{(G*M*T²)/4π²},
Substitute values
R=9.36*10^11 m
What is the mass of an object that has an acceleration of 2.63 m/s^2 when an unbalanced force of 112 N is applied to it?
Sometimes, I have to take my cat, Gigi, in the car. She doesn’t like this, and tends to hide under the couch when she knows she has to go. This means I have to drag her out. Assuming she is using her claws to try and stop me, identify the forces acting on Gigi, and draw a free body diagram for the situation. Make sure you label each force and identify where it’s coming from.
Answer:
F - fr = ma , N - W = 0
Explanation:
In this exercise we are asked to identify the forces that act on the jack, for this we will use Newton's second law
On the x axis
We have two forces: the friction and the force of the girl who pulls the cat
F - fr = ma
On the y axis
There are two forces: normal and weight
N - W = 0
A diagram of these forces can be seen in the attachment
A 5.0kg concrete block accelerates down a 34 degree slope at 4.2 m/s^2. Find the Coefficient of friction between the block and the slope.
Answer:
The coefficient of friction between the block and the slope is 0.16.
Explanation:
We can find the coefficient of friction between the block and the slope by using Newton's second law:
[tex] \Sigma F = ma [/tex]
[tex]P_{x} -\mu N = ma[/tex]
[tex] mgsin(\theta) - \mu mgcos(\theta) = ma [/tex] (1)
Where:
m: is the mass of the block = 5.0 kg
a: is the acceleration = 4.2 m/s²
θ: is the angle = 34°
μ: is the coefficient of friction =?
g: is the gravity = 9.81 m/s²
By entering the above values into equation (1) we have:
[tex] gsin(\theta) - \mu gcos(\theta) = a [/tex]
[tex] \mu = \frac{gsin(\theta) - a}{gcos(\theta)} = \frac{9.81 m/s^{2}*sin(34) - 4.2 m/s^{2}}{9.81 m/s^{2}*cos(34)} = 0.16 [/tex]
Therefore, the coefficient of friction between the block and the slope is 0.16.
I hope it helps you!
A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete is = 0.02. (a) What is the cart's acceleration if rolling friction is neglected? (b) What is the cart's acceleration if rolling friction is included?
Answer:
(a) 5.62 m/s²
(b) 5.46 m/s²
Explanation:
The given values are:
mass,
m = 50 kg
angle
= 35°
(a)
If friction neglected,
⇒ [tex]F_x=mgSin \theta=ma[/tex]
⇒ [tex]a_x=gSin \theta[/tex]
[tex]=9.8 \ Sin35^{\circ}[/tex]
[tex]=5.62 \ m/s^2[/tex]
(b)
If friction present,
⇒ [tex]F_x=mgCos \theta[/tex]
⇒ [tex]F_x=mgSin \theta-\mu_r mgCos \theta[/tex]
⇒ [tex]a=gSin \theta-\mu_rgCos \theta[/tex]
[tex]=9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}[/tex]
[tex]=5.46 \ m/s^2[/tex]
Two forces, F1 and F2, are applied to a block on a frictionless, horizontal surface
as shown below. If the magnitude of the block's acceleration is 2.0 meters per
second2, what is the mass of the block? *
F, = 12 N
F2 =2N
Block
Frictionless surface
Answer:
F, = 12N. F, = 2 N. Block. 4) a 20.0-kg mass moving at 1.00 m/s.
Explanation:
The mass of the block on the frictionless horizontal surface is 5 kg.
The given parameters;
magnitude of the first force, F₁ = 12 Nmagnitude of the second force, F₂ = 2 Nacceleration of the block, a = 2 m/s²The mass of the block is determined by applying Newton's second law of motion;
F = ma
[tex]\Sigma F = ma\\\\F_1 - F_2 = ma\\\\12 - 2 = 2m\\\\10 = 2m\\\\m = 5 \ kg[/tex]
Thus, the mass of the block on the frictionless horizontal surface is 5 kg.
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The image below shows a model of the atom which subatomic particle does the arrow in the image below identify ?
Answer:it’s a
Explanation:
Answer:
A electrons
Explanation:
bcs
Sam stands on a 20 m high cliff and throws a 45 g rock with an initial velocity of 5 m/s [forward] to the water below. Use the conservation of energy to determine the speed of the rock when it has fallen 12 m.
Answer:
v = 12.52 [m/s]
Explanation:
To solve this problem we must use the energy conservation theorem. Which tells us that potential energy is transformed into kinetic energy or vice versa. This is more clearly as the potential energy decreases the kinetic energy increases.
Ep = Ek
where:
Ep = potential energy [J] (units of joules]
Ek = kinetic energy [J]
Ep = m*g*h
where:
m = mass of the rock = 45 [g] = 0.045 [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = (20 - 12) = 8 [m]
Ek = 0.5*m*v²
where:
v = velocity [m/s]
The reference level of potential energy is taken as the ground level, at this level the potential energy is zero, i.e. all potential energy has been transformed into kinetic energy. In such a way that when the Rock has fallen 12 [m] it is located 8 [m] from the ground level.
m*g*h = 0.5*m*v²
v² = (g*h)/0.5
v = √(9.81*8)/0.5
v = 12.52 [m/s]
A circus performer walked up and to the right for a total displacement of 10\,\text m10m10, start text, m, end text along a diagonal tightrope angled 30 \degree30°30, degree above the ground.
Answer: 5m
(10m) sin 30
=5m
The vertical displacement of the circus performer in m is 5m.
What is displacement?The displacement is the shortest distance travelled by the particle. It is the vector quantity which represents both the magnitude and direction.
A circus performer walked up and to the right for a total displacement of 10 m along a diagonal tightrope angled 30° above the ground.
We know the hypotenuse is 10m (diagonal) and the angle above the ground is 30°
The displacement will be sin (30) of hypotenuse.
Displacement = 10 sin (30)
d = 5m
Thus, the vertical displacement of the circus performer is 5 m.
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Space-shuttle astronauts experience accelerations of about 35 m/s2 during takeoff. What force does a 75 kg astronaut experience during an acceleration of this magnitude?
Answer:
The answer is 2625 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 75 × 35
We have the final answer as
2625 NHope this helps you