A 1.95 kg box sits on an incline of 24 ° with the horizontal. If the box accelerates down the incline at 0.245 m/s 2 , what is the coefficient of kinetic friction between the box and the inclined plane?

Answers

Answer 1

Answer:

Explanation:

                            F = ma

mgsinθ - μmgcosθ = ma

      gsinθ - μgcosθ = a

                   μgcosθ = gsinθ - a

                              μ = (gsinθ - a) / gcosθ

                              μ = (9.81sin24 - 0.245) / 9.81cos24

                              μ = 0.4178906...

                              μ = 0.418

Answer 2

The coefficient of kinetic friction will be equal to 0.418.

What is friction?

Friction is the force that prevents solid surfaces, fluid layers, and material elements from sliding against each other. There are various kinds of friction: Dry friction is the force that opposes the relative lateral motion of two in-touch solid surfaces.

Given that a 1.95 kg box sits on an incline of 24 ° with the horizontal. If the box accelerates down the incline at 0.245 m/s 2

The coefficient of kinetic friction will be calculated as,

F = ma

mgsinθ - μmgcosθ = ma

gsinθ - μgcosθ = a

μgcosθ = gsinθ - a

Solve for the value of the coefficient of friction,

μ = (gsinθ - a) / gcosθ

μ = (9.81sin24 - 0.245) / 9.81cos24

μ = 0.4178906...

μ = 0.418

Therefore, the coefficient of kinetic friction will be equal to 0.418.

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Calculate the net force acting on a body of mass 20 kg moving with a
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Answer:

0 N

Explanation:

Uniform velocity means no acceleration and therefore no net force.

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If a person climbed Mt. Everest has a mass of 105 kg and a weight of 625 N what would be the acceleration due to gravity?

Answers

The acceleration due to gravity would be 5.95 m/s²

A force is known to be a push or pull and it is the change in momentum per time. It can be expressed by using the relation.

Force = mass × acceleration.

From the parameters given:

Mass = 105 kgForce = 625 N

By replacing the given values into the above equation, we can determine the acceleration.

625 N = 105 kg × acceleration.

[tex]\mathbf{acceleration = \dfrac{625 \ N}{105 \ kg}}[/tex]

acceleration = 5.95 N/kg

Since 1 N/kg = 1 m/²

acceleration = 5.95 m/s²

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The fastest possible rate of rotation of a planet is that for which the gravitational force on material at the equator just barely provides the centripetal force needed for the rotation. Calculate the minimum rotation period assuming a density of 3.70 g/cm3.

Answers

Answer:

m ω^2 R = centripetal force

G M m / R^2 = gravitational force

ω^2 = G M / R^3    for the forces to be equal

d (density) = M / V = M / (4/3 R^3) = 3/4 M / R^3

or M / R^3 = 4 d / 3

Then

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a plane crashes with a deceleration of 185 m/s. How many g’s is this?

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Answer:

26 g's

Explanation:

Hope this helps~

Have a great day

Zero

What is measurement?​

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Answer:

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help please i don’t know

Answers

Answer:

Explanation:

Potential energy at the top of the slide

PE = mgh = 49(9.8)(3) = 1,440.6 J

Energy converted to work of friction

W = Fd = 35(10) = 350 J

Converted potential that becomes kinetic energy

1440.6 - 350 = 1090.6 J

KE = ½mv²

v = [tex]\sqrt{2KE/m}[/tex]

v = [tex]\sqrt{2(1090.6)/49}[/tex]

v = 6.671902...

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A gazelle is grazing while standing in a fixed location. When it's startled by a predator, the gazelle accelerates uniformly for 16.8 s until it reaches a speed of 21.9 m/s. The gazelle then runs in a straight line at constant speed for an additional 16.4 s. Finally, it uniformly slows to a stop at a rate of 1.8 m/s/s. What is the total distance traveled by the gazelle in meters

Answers

Answer:

Explanation:

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distance covered is 10.95 m/s(16.8 s) = 183.96 m

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total = 183.96 + 359.16 + 133.225 = 676.345 = 676 m

A stereo speaker produces a pure "A" tone, with a frequency of 220.0 Hz.

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T=


What is the wavelength water of the same sound wave as it enters some water, where it has a speed of about 1480 m/s?

λwater=


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Answers

(a) The period of the sound wave is 0.005 s.

(b) The wavelength of the wave when the speed of the wave is 1480 m/s is 6.73 m.

(c) The wavelength of the sound wave as it travels through air is 1.55 m.

The given parameters;

Frequency of the wave, F = 220 Hz

The period of the sound wave is calculated as follows;

[tex]T = \frac{1}{f} \\\\T = \frac{1}{220} \\\\T = 0.005 \ s[/tex]

The wavelength of the wave when the speed of the wave is 1480 m/s is calculated as follows;

[tex]v = f\lambda \\\\\lambda = \frac{v}{f} \\\\\lambda = \frac{1480}{220} \\\\\lambda = 6.73 \ m[/tex]

The wavelength of the sound wave as it travels through air with a speed of about 341 m/s;

[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{341}{220} \\\\\lambda = 1.55 \ m[/tex]

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What are the two fundamental ways energy and momentum are moved from one place to another?​

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The two fundamental ways energy and momentum are moved from one

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The formula for momentum is mass multiplied with velocity.

Momentum= mass × velocity

The two factors in which momentum and energy is moved from one place to

another is however through how much and how fast the object is moving

which validates the answer.

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