Answer:
MM = 225.11 g/mol
Explanation:
In this case, let's analyze the data.
We have a 15.2 mg of an unknown electrolyte in 150 mL of solution. The osmotic pressure is 8.44 Torr, and we want the molecular mass of the unknown.
The osmotic pressure can be calculated using the following expression:
π = CRT (1)
π: osmotic pressure (8.44 Torr * 1 atm / 760 Torr = 0.011 atm)
C: Concentration of the unknown in the solution
R: universal constant of gases (0.082 L atm / K mol)
T: temperature in Kelvin (25 + 273 = 298 K)
From this expression, we can either solve for C, and then use another expression to calculate the molecular mass, or we can just replace the expressions in the above formula, to get the direct molecular mass. In this case, we'll follow the second method.
Concentration or molarity of a substance can be calculated using:
C = moles / V (2)
And moles can be calculated using this expression:
moles = m / MM (3)
Replacing (3) in (2), and then in (1) we have:
C = m / MM * V
π = m * RT / MM * V (4)
and now, we can solve for MM:
MM = mRT / π V (5)
Now, we just need to replace the given data into the above expression to get the value of the molecular mass:
MM = (15.2 / 1000) * 0.082 * 298 / 0.011 * 0.150
MM = 225.11 g/molHope this helps
A gas has a pressure of 0.0370 atm at 50.0°C. What is the pressure at 0.00°C?
5. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Without doing a calculation, would you expect C-2 or C-4 (the two end carbons of the allylic cation) to have the most positive charge on it
Answer:
Follows are the solution to this question:
Explanation:
Please find the complete solution in the attached file.
The hybridisation of the central atom in ICL-2
a) sp.
b) sp2
c) sp3d d)sp3
Explanation:
For ICl²-, the central iodine atom is bonded to the 2 chlorine atoms and has 3 lone electron pairs.
Altogether it has 5 electron domains, which means it is sp3d hybridized. (C)
Determine the entropy change for the combustion of gaseous propane, C3H8, under standard state conditions to give gaseous carbon dioxide and water.
Answer:
ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹
Explanation:
The equation for the reaction is given as;
C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g)
In order to determine the entropy change, we have to use the entropy valuues for the species in the reaction. This is given as;
S°[C₃H₈(g)] = 269.9 J K⁻¹ mol⁻¹
S°[O₂(g)] = 205.1 J K⁻¹ mol⁻¹
S°[H₂O(g)] = 188.8 J K⁻¹ mol⁻¹
S°[CO₂(g)] = 213.7 J K⁻¹ mol⁻¹
The unit of entropy is J K⁻¹ mol⁻¹
Entropy change for the reaction is given as;
ΔS°reaction = ΔS°product - ΔS°reactant
ΔS°reaction = [(4 * 188.8) + (3 * 213.7)] - [269.9 + (5 * 205.1)]
ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹
The entropy change for the combustion of gaseous propane, under standard state conditions 100.9 J K⁻¹.
The equation for the combustion of gaseous propane is given as follows:-
C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g)
In order to determine the entropy change, we have to use the entropy values for the species in the reaction. This is as follows:-
S°[C₃H₈(g)] = 269.9 J K⁻¹ mol⁻¹
S°[O₂(g)] = 205.1 J K⁻¹ mol⁻¹
S°[H₂O(g)] = 188.8 J K⁻¹ mol⁻¹
S°[CO₂(g)] = 213.7 J K⁻¹ mol⁻¹
The unit of entropy is J K⁻¹ mol⁻¹
Entropy change for the reaction is given as;
ΔS°reaction =nproduct ΔS°product - nreactantΔS°reactant
ΔS°reaction = [(4mol * 188.8 J K⁻¹ mol⁻¹) + (3 mol * 213.7 J K⁻¹ mol⁻¹)] - [(1 mol*269.9J K⁻¹ mol⁻¹ )+ (5 mol* 205.1 J K⁻¹ mol⁻¹)]
ΔS°reaction = 100.9 J K⁻¹
So, the entropy change for the combustion of gaseous propane is 100.9 J K⁻¹ .
To know more about:-
brainly.com/question/14818671
A low-pressure weather system comes into the city of Denver. The atmospheric pressure is 693 mmHg.693 mmHg. If 78.0%78.0% of dry air is nitrogen, what is the partial pressure of nitrogen in this low-pressure system?
Answer:
540.54 mmHg
Explanation:
We know that the partial pressure of a substance is defined as; Mole fraction * total pressure.
If the total amount of gases in the atmosphere is 100%, the mole fraction of nitrogen gas is now
78/100 = 0.78
Thus, partial pressure of nitrogen gas = 0.78 * 693 = 540.54 mmHg
For the following reaction, 33.7 grams of bromine are allowed to react with 13.0 grams of chlorine gas.
bromine (g) + chlorine (g)>bromine monochloride (g)
What is the maximum amount of bromine monochloride that can be formed? __________grams
What is the FORMULA for the limiting reagent?
What amount of the excess reagent remains after the reaction is complete? __________grams
Explanation:
The reaction is given as;
Br2(g) + Cl2(g) ----> 2BrCl(g)
From the equation;
1 mol of Br2 reacts with 1 mol of Cl2
Converting the masses given to moles, using the formular;
Number of moles = Mass / Molar mass
Br2;
Number of moles = 33.7 g / 159.808 g/mol = 0.21088 mol
Cl2;
Number of moles = 13.0 g / 70.906 g/mol = 0.18334 mol
From the values;
0.18334 mol of Cl2 would react with 0.18334 mol of Br2 with an excess of 0.02754 mol of Br2
What is the maximum amount of bromine monochloride that can be formed? __________grams
1 mol of Cl2 produces 2 mol of Bromine Monochloride
0.18334 mol of Cl2 would produce x
Solving for x;
x = 0.18334 * 2 = 0.36668 mol
Converting to mass;
Mass = Number of moles * Molar mass = 0.36668 mol * 115.357 g/mol
Mass = 42.299 g
What is the FORMULA for the limiting reagent?
The limiting reagent is Cl2 as it determines the amount of product formed. The moment the reaction uses up Cl2, the reaction stops.
What amount of the excess reagent remains after the reaction is complete? __________grams
The excess reagent is Br2
The number of moles left is;
0.02754 mol of Br2
Converting to mass;
Mass = Number of moles * Molar mass = 0.02754 mol * 159.808 g/mol
Mass = 4.401 g
Which elements make up 95 percent (by weight) of the human body?
In a reaction that produces carbon dioxide, the theoretical yield is 59 grams. During the experiment, the reaction actually produced 52.9 grams of carbon dioxide. Determine the percent yield.
Answer:
mole ratio, which is equivalent to a 1;1 mole ratio, to a gram ratio. This means that when the reaction consumes 84.03 g of carbon monoxide, it should theoretically produce 132.03 g of carbon dioxide. Use this gram ratio to calculate the theoretical yield for your reaction.
Explanation:
The yield for a particular well is 280 gallons per minute (gpm). Of the drawdown for this well is 23 feet, what is the specific yield in gpm/ft?
Answer:
[tex]Y=12.2 \frac{gpm}{ft}[/tex]
Explanation:
Hello!
In this case, since we can find that the well produces 280 gpm, and the given drawdown is 23 ft, we need to divide 280 by 23 to obtain the yield in gmp/ft as shown below:
[tex]Y=\frac{280gpm}{23ft} \\\\Y=12.2 \frac{gpm}{ft}[/tex]
Best regards!
Complete the following reaction: Li + S -->
Answer:
Li2S
Explanation:
Hope this helps.
Answer:
can u do an real answer pls so i can help u thanks
Calculate [H+] and [OH-] as required for each of the following
solutions at 25 °C, and state whether the solution is neutral, acidic,
or basic.
a. 1.0x 10-5 MOH-
Q
b. 1.0x 10-7 MOH-
c. 10.0 MH+
Explanation:
The relationship between H+ and OH- at 25 °C is given as;
[H+} x [OH-] = 1.0 x 10-14 M
a. 1.0 x 10-5 M OH-
[OH-] = 1.0 x 10-5 M
[H+] = 1.0 x 10-14 M / [OH-] = 1.0 x 10-14 M / 1.0 x 10-5 M
[H+] = 1.0 x 10^(-14+5)
[H+] = 1.0 x 10^(-9)
pH = - log [H+]
pH = - log [10^(-9)]
pH = 9
This is a basic solution
b. 1.0 x 10-7 M OH-
[OH-] = 1.0 x 10-7 M
[H+] = 1.0 x 10-14 M / [OH-] = 1.0 x 10-14 M / 1.0 x 10-7 M
[H+] = 1.0 x 10^(-14+7)
[H+] = 1.0 x 10^(-7)
This is a neutral solution since [H+] and [OH-] are equal
c. 10.0 M H+
[H+] = 1.0 x 10 M
[OH-] = 1.0 x 10-14 M / [H+] = 1.0 x 10-14 M / 1.0 x 10 M
[OH-] = 1.0 x 10^(-14-1)
[OH-] = 1.0 x 10^(-15)
pH = - log [H+]
pH = - log [10^(1)]
pH = -1
This is an acidic solution since it has a pH of -1
What is the electronegativity and bond polarity like in the "head" vs. the "tail" ends of soap?
Answer:
gay
Explanation:
very gay
10 points Part F
Identify at least two limitations of the simulation. How do these limitations influence the
simulation's ability to model the synthesis of ammonia?
Answer and Explanation:
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
The temperature of an oxyacetylene torch flame can reach as high as 3137 °C. What is this temperature in Fahrenheit and Kelvin? Please show work.
Answer:
A)3410K
B)5678.6 °F
Explanation:
✓ To convert Celcius to Kelvin expression below can be used
K= °C + 273
We were given T=3137 °C
= 3137 + 273= 3410K
✓To convert Celcius to Fahrenheit, expression below can be used
°F =(°C × 9/5) + 32
We were given T=3137 °C
°F= (3137 × 9/5) + 32
= 5646.6+32
=5678.6 °F
The fertilization in __________happens outside the female's body
Answer:
Frogs
Explanation:
Answer:
Hello there! I'm assuming frog and or dog :)
Enter the electron configuration for I+ using noble gas shorthand notation.
In the first box enter the noble gas (notice the brackets). In the following boxes enter the number that goes in front of the orbital followed by the superscript.
For example, the electron configuration for sulfur is: [Ne]3s2 3p4
so the first box would have Ne in it followed by 3, then 2, then 3 then 4.
If you do not need an orbital, just enter 0 (zero) in the boxes for the coefficient and superscript.
[ ] s f d p
Find the element in the periodic table and count over
to the right the number of negative charges on your anion.
This element has the same electron configuration as your anion.
Which noble gas precedes the element? Knowing the s, p, d, and f blocks
of elements in the periodic table, deduce the the electron configuration
of the element from the preceding noble gas. Remember that the
1p 1d, 2d, 1f, 2f, and 3f orbitals are forbidden energy levels (they do not exist).
Answer:
[Kr] 4d10 5s2 5p4
Explanation:
The Symbol I represents Iodine. It has atomic number of 53. The full electronic configuration is given as;
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5
However the question requested for the configuration of I+.
I+ is a cation and it simply refers to an iodine atom that has lost a single electron. The electronic configuration of I+ is given as;
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4
Using Noble gas shorthand representation, we have;
[Kr] 4d10 5s2 5p4
Calculate the mass, in grams, of 912 atoms of iron, Fe (1 mol of Fe
has a mass of 55.85 g).
Answer:
8.45 × 10⁻²⁰ g
Explanation:
Step 1: Given data
Number of atoms of Fe (N): 912 atomsMolar mass of Fe (M): 55.85 g/molStep 2: Calculate the mass, in grams, of 1 atom of Fe
We will use Avogadro's number: there are 6.02 × 10²³ atoms of Fe in 1 mole of Fe.
55.85 g/mol × 1 mol/6.02 × 10²³ atom = 9.27 × 10⁻²³ g/atom
Step 3: Calculate the mass corresponding to 912 atoms
9.27 × 10⁻²³ g/atom × 912 atom = 8.45 × 10⁻²⁰ g
Select the option that best represents recycling food waste
O turning food scraps into biogas
O donating unused food to food pantries
O incinerating leftover food
O feeding scraps to livestock
Answer:
feeding leftover or scraps to livestock
Explanation:
Because feeding leftover healthy food instead of leaving livestock to eat garbage is good for health of the animals and they give good quality of milk, eggs, meat, etc in return
Which statement best describes the coriolis effect
The coriolis effect is responsible for many large scale weather patterns. The coriolis force is responsible for the deflection of objects. It is this effect which drive the global wind and ocean circulation patterns. The correct option is C.
What is coriolis effect?The apparent effect produced by a rotating frame of reference is defined as the coriolis effect. This effect occurs when an object moving along a straight path is viewed from a non-fixed frame of reference.
Because of the earth's rotation, when an object moving in a straight path is viewed from earth, it appears to lose its course. So the travelling long distances around the earth appear to move at a curve instead of a straight line due to coriolis effect.
The coriolis effect is found to be strongest near poles and it is absent at the equator. The coriolis force is an apparent force caused by the rotation of earth.
Thus the correct option is C.
To know more about coriolis effect, visit;
https://brainly.com/question/29780755
#SPJ7
Your question is incomplete, most probably your question was:
Which statement best describes the coriolis effect
A. The oceans that receive more rain have water with lower salinity.
B. Closer to the poles, the temperature of ocean water decreases.
C. The rotation of Earth causes the apparent path of ocean currents
to curve,
D. Ocean water becomes denser the deeper you go underwater.
What is the voltage in a circuit is the current is 3 amps and the resistance is 3 ohms
Answer:
9
Explanation:
V=I*R
3*3
Thats the answer
Describe how naturally
acidic rainwater can affect a
mountain of limestone.
Answer:
The naturally acidic rain will gradually wear the mountain of limestone away.
Hope it helps!
MnO4 - is a stronger oxidizing agent than ReO4 - . Both ions have charge-transfer (LMCT) bands; however, the charge-transfer band for ReO4 - is in the ultraviolet, whereas the corresponding band for MnO4 - is responsible for its intensely purple color. Are the relative positions of the charge-transfer absorptions consistent with the oxidizing abilities of these ions? Explain
Answer:
[tex]$MnO^-_4$[/tex] is a strong oxidizing agent.
Explanation:
The 5d orbitals of Re are higher in energy than 3 d orbitals of Mn. So an LMCT ligand to metal charge transfer excitation requires more energy of [tex]$ReO^-_4$[/tex].
Also, since the molecular orbitals are derived primarily from 3d orbitals of [tex]$MnO^-_4$[/tex] are lower in energy than the corresponding MO's of [tex]$ReO^-_4$[/tex], [tex]$MnO^-_4$[/tex] is better able to accept the electrons.
So it is a better oxidizing agent.
The ligand to metal charge transfer band in ReO4- occurs in the near UV region hence ReO4 - appears colorless.
The electron configuration of Re is Xe 4f14 5d5 6s2 and the electron configuration of Mn is [Ar] 3d5 4s2. We can see that Mn^7+ and Re^7+ have empty d orbitals.
The color of MnO4 - must result from ligand to metal charge transfer hence the purple color of MnO4 -. In the case of ReO4 -, the ligand to metal charge transfer occurs at a much higher energy owing to the fact that 5d orbitals are involved. This transition occurs in the near UV region hence ReO4 - appears colorless. The ligand to metal charge transfer in MnO4- involves lower energy 3d orbitals hence it occurs in the visible region of the spectrum.
Learn more: https://brainly.com/question/8646601
No pain no gain . which figure of speech is this
Answer:
No pain, no gain is a proverb that means in order to make progress or to be successful, one must suffer. This suffering may be in a physical or mental sense. The phrase no pain, no gain was popularized in the 1980s by the American actress, Jane Fonda.
The pain reliever morphine contains 17.900 g C, 1.680 g H, 4.225 g O, and 1.228 g N. Determine the empirical Formula.
Answer: The empirical formula is [tex]C_{17}H_{19}O_3N[/tex]
Explanation:
Mass of C= 17.900 g
Mass of H = 1.680 g
Mass of O = 4.225 g
Mass of N = 1.228 g
Step 1 : convert given masses into moles.
Moles of C =[tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{17.990g}{12g/mole}=1.5moles[/tex]
Moles of H =[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.680g}{1g/mole}=1.680moles[/tex]
Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{4.225g}{16g/mole}=0.264moles[/tex]
Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{1.228g}{14g/mole}=0.087moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = [tex]\frac{1.5}{0.087}=17[/tex]
For H = [tex]\frac{1.680}{0.087}=19[/tex]
For O =[tex]\frac{0.264}{0.087}=3[/tex]
For N = [tex]\frac{0.087}{0.087}=1[/tex]
The ratio of C : H: O: N = 17: 19: 3: 1
Hence the empirical formula is [tex]C_{17}H_{19}O_3N[/tex]
All camels are basically similar in structure. They have developed adaptations for
coping with both heat and dehydration.
Which of the following does not benefit the camel as a means of preventing dehydration?
A. Camels can extract water from their solid wastes.
B. Camels’ ears are lined with fur to keep out sand and other blowing matter.
C. Their kidneys are capable of concentrating urine to reduce water loss.
D. Camels are able to locate water in any environment.
Answer:
B. Camels’ ears are lined with fur to keep out sand and other blowing matter.
Detection of iron ions Fe+3 and Fet+2
Answer:
The diffrence between Fe2+ and Fe3+ is the Fe2+has a pale green color and turns violet when water is added to it. While Fe3+ forms blood red when it reacts with thiocyanate ions.
Fe2+ has paramagnetic properties whereas
Fe3+ has diamagnetic properties.
Explanation:
I may not be correct.
Answer:
ok ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
Please help me I need this really quick
Answer:
The answer is (a)
.
.
......................................................................
According to the graph, what is the instantaneous speed of the object at 5 seconds? *
Captionless Image
4 m/s
7 m/s
0.25 m/s
3 m/s
Answer:4m/s
Explanation:The reason why that the answer is because I am Smart.
what do you mean by PCM
Answer:
Pulse-code modulation
Explanation:
it initiates the healing process?
Answer:
platelets?
Explanation:
the question is vauge. but I hope you got it right!
Answer:
Cell division ?
Explanation: