A 1.5 V battery is connected to a 1,000 μF capacitor in series with a 150 Ω resistor. a. What is the maximum current that flows through the resistor during charging? b. What is the maximum charge on the capacitor? c. How long does the capacitor take to reach a potential of 1.0V?

Answers

Answer 1

Answer:

[tex]0.01\ \text{A}[/tex]

[tex]0.0015\ \text{C}[/tex]

[tex]0.0608\ \text{s}[/tex]

Explanation:

[tex]V_0[/tex] = Voltage = 1.5 V

[tex]C[/tex] = Capacitance = [tex]1000\ \mu\text{F}[/tex]

[tex]R[/tex] = Resistance = [tex]150\ \Omega[/tex]

Current is given by

[tex]I=\dfrac{V_0}{R}\\\Rightarrow I=\dfrac{1.5}{150}\\\Rightarrow I=0.01\ \text{A}[/tex]

Current flowing in the resistor is [tex]0.01\ \text{A}[/tex].

Charge is given by

[tex]Q=CV\\\Rightarrow Q=1000\times 10^{-6}\times 1.5\\\Rightarrow Q=0.0015\ \text{C}[/tex]

The charge on the capacitor is [tex]0.0015\ \text{C}[/tex].

Voltage is given by

[tex]V=V_0e^{-\dfrac{t}{RC}}\\\Rightarrow t=-RC\ln\dfrac{V}{V_0}\\\Rightarrow t=-150\times 1000\times 10^{-6}\times\ln\dfrac{1}{1.5}\\\Rightarrow t=0.0608\ \text{s}[/tex]

Time taken to reach 1 V is [tex]0.0608\ \text{s}[/tex].


Related Questions

You drop a 10 kg bowling ball off a 2 story building, what is the force generated by
the bowling ball when it hits the ground

Answers

Answer:i

Explanation:

You are standing outside with two speakers. The temperature is 0 degrees C. The two speakers are playing sound of the same frequency: a pure sinusoidal sound of the same frequency at the same phase. The speakers are playing at different amplitudes. One speaker is 1.230 meters from you and one is 1.425 meters from you. You hear no sound. Which of the following is a possible frequency of the sound being played?

a. 993 Hz
b. 331 Hz
c. 4965 Hz
d. 1655 Hz
e. 662 Hz

Answers

Answer:

Explanation:

No sound is heard , that means there is destructive interference at the place where sound is heard .

Path difference of the source of sound = 1.425 m - 1.230 m

= 0.195 m

Let frequency of sound be n .

wave length = velocity of sound at 0°C / n

λ = 330 / n

for destructive interference ,

path difference = ( 2m+1) λ /2 , where λ is wave length of sound.

0.195 m = ( 2m+1) λ /2

0.195 m = ( 2m+1)330 / 2n

2n = 1692.3 (2m+1)

If m = 0

n = 846 . which is nearest to given frequency of 993 Hz

So 993 Hz is the answer.

Explain the mode of operation of x-ray​

Answers

Answer:

If x-rays get in touch with our body tissues, they create a picture of a metal film. The high energizing rays are unable to penetrate soft tissue, such as skin and organs and travel through the laser. The places where the x-rays pass soft tissues are Black areas of an X-ray.

Answer:

Explanation:

Mode of Operation: In the X-ray tube a Low voltage high p.d is applied between the hot cathode and the anode. Electrons are emitted from the cathode and are accelerated to an extremely high speed. ... They are produced by increasing the p.d. between the cathode and anode.

An 80 kg astronaut has gone outside his space capsule to do some repair work. Unfortunately, he forgot to lock his safety tether in place, and he has drifted 5.0 m away from the capsule. Fortunately, he has a 1000 W portable laser with fresh batteries that will operate it for 1.0 h. His only chance is to accelerate himself toward the space capsule by firing the laser in the opposite direction. He has a 10-h supply of oxygen. His only chance is to accelerate himself toward the space capsule by firing the laser in the opposite direction. He has a 10-h supply of oxygen.

Required:
How long will it take him to reach safety?

Answers

Answer:

t = 3.924 s

Explanation:

First, we will calculate the amount of work required to get the astronaut back to the capsule:

[tex]W = Fd\\[/tex]

where,

W = work required = ?

F = Force = Weight = mg = (80 kg)(9.81\ m/s²) = 784.8 N

d = distance = 5 m

Therefore,

[tex]W = (784.8\ N)(5\ m)\\W = 3924 J[/tex]

Now the time can be calculated as:

[tex]Power = \frac{W}{t}\\t = \frac{W}{Power}\\\\t = \frac{3924\ J}{1000\ W}\\\\[/tex]

t = 3.924 s

The instrument measuring the temperature change between inspired cool air and expired warm air is called?​

Answers

Answer:

It's called a Spirometer

Claire pushes a box to the left while Jamie pushes the same box to the right. The box stays in
between them in the same position.
Which best explains why Claire and Jamie are unable to move the box?
A. They are applying an unbalanced force.
B. They are applying a balanced force.
C. They are applying gravity.
D. They are applying friction.

Answers

A there applying balanced force
Explanation:
The box is not able to move Becouse there both putting the same amount of force into pushing the box making the box unable to move

If 03.4 kg of water at 69°C is changed into steam at 100°C, how will the energy be used? specific heat capacity of water is 4200J/kg C and latent heat is 2,260 000J/Kg.

A. 7864513 J
B. 8126680 J
C. 329758 J
D. 742976 J

With explanation please

Answers

Answer:

The answer is B.

Explanation:

مافيني اشرح

a particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity​

Answers

Answer:

vi =2

Explanation:

Δx = 1/2 (vi + vf) t

10 = 1/2 ( vi + 8 ) 2

10 = vi + 8

10-8 = vi

vi = 2 m/s

vi= initial velocity

vf= final velocity

Δx= distance

t= time

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 48.0 cm . The explorer finds that the pendulum completes 93.0 full swing cycles in a time of 141 s.

Required:
What is the value of g on this planet?

Answers

Answer:

8.24 m/s²

Explanation:

Applying,

T = 2π√(L/g).................... Equation 1

Where T = period of the pendulum, L = Length of the pendulum, g = acceleration due to gravity of the planet, π = pi

From the question, we were asked to  find the value of g,

There we make g the subject of the equation

g = 4π²L/T²..................... Equation 2

Given: L= 48 cm = 0.48 m, T = (141/93) s = 1.516 s

Constant: π = 3.14

Substitute these values into equation 2

g = 4(3.14²)(0.48)/(1.516²)

g = 18.93/2.298

g = 8.24 m/s².

Hence the acceleration of the planet is 8.24 m/s²

which choice displays the effects of quantum mechanics? check all that apply

atoms

subatomic particles

particles that are 10^-9m

microtechnology systems

protons

neutrons

particles that are 10^-3m

Answers

Answer:

A,B,C,D,F,G

Explanation:

Edge 2021

The atoms, subatomic particles, particles that are 10^-9m, microtechnology systems, neutrons and particles that are 10^-3m  will displays the effects of quantum mechanics.

What is Quantum Mechanics?​

Quantum Mechanics is the branch of mechanics deals with the mathematical description of the motion and interaction of subatomic particles, incorporating the concepts of quantization of energy, wave–particle duality, the uncertainty principle, and the correspondence principle is Quantum Mechanics.

It is theory says at subatomic level, energy exists in discrete levels as "quanta" and particles behave as waves.

A Subatomic particles are the particle that are present inside an atom. These particles are electrons, protons, and neutrons.

Thus, atoms, subatomic particles, particles that are 10^-9m, microtechnology systems, neutrons and particles that are 10^-3m  will displays the effects of quantum mechanics.

Learn more about Quantum Mechanics;

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Select the correct answer from each drop-down menu.
After World War II, political leaders from various countries discussed ways to strengthen individual-as well as
economies. They began promoting
to boost production and exports,

Answers

Answer: I think it’s Global for the 1st one

And free trade for the 2nd one

Explanation:

The correct answer is: "After World War II, political leaders from various countries discussed ways to strengthen individual economies." They began promoting economic policies to boost production and exports.

What happened after World War II?

After World War II, many countries were left with weakened economies and infrastructure, and there was a need for economic recovery and growth. To achieve this, political leaders from different countries came together to discuss ways to strengthen their individual economies and also promote international economic cooperation. One of the ways they did this was by promoting economic policies that aimed to boost production and exports. This involved policies that encouraged businesses to increase their output and create more jobs, as well as policies that made it easier for countries to trade with each other.

Hence, after World War II, political leaders from various countries discussed ways to strengthen their individual economies. They began promoting economic policies to boost production and exports.

Learn more about World War II's aftermath here.

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A uniform rod of length 80cm rotated in the xy plane about a frictionless pin passing through one end (as shown in figure). If the angular
velocity of the rod is 4rad/s, find the linear velocity (in m/s) of its mid-point C
Rod
Pin
С
Select one:
O a. 0.5
O b. 1.6
O c. 1.3
O d. 0.8​

Answers

Answer:

Linear velocity (in m/s) = 1.6 m/s

Explanation:

Given:

Length of rotational plane = 80 cm

Angular  velocity of the rod = 4rad/s

Find:

Linear velocity (in m/s)

Computation:

Radius from mid point C = Length of rotational plane / 2

Radius from mid point C = 80 / 2

Radius from mid point C = 40 cm

Radius from mid point C = 0.4 m

Linear velocity (in m/s) = Angular  velocity of the rod x Radius from mid point C

Linear velocity (in m/s) = 0.4 x 4

Linear velocity (in m/s) = 1.6 m/s

Pre-laboratory Assignment: Experiment 20 Reflection and Refraction of Light 1. When light is incident on a reflective surface, what can be said about the angle and speed at which the light is reflected? (Information is in your ‘General Physics Laboratory Manual’ Chapt. 20) 2. At what angle is the normal drawn to the reflective surface or air-medium interface? 3. How are angles of incidence, angles of reflection and of refraction measured? 4. Describe what happens to a light ray as it enters from a medium of greater refractive index to a medium of lesser refractive index

Answers

Answer:

1) ngle of incidence and reflection are equal,  light carries does not change

2) the angle of this line with respect to the surface is 90º

3) protractor

4)    n₂  sin θ₂ = n_1 sin θ₁,  light ray must have a greater angle than the incident ray ,

Explanation:

1) When light falls on a reflective surface, the angle of incidence and reflection are equal and as it travels in the same medium, the speed that the light carries does not change

2) The normal is a line perpendicular to the point of incidence of light, so the angle of this line with respect to the surface is 90º

3) Angles are measured with a protractor

4) When light passes from one medium to another, the speed of the ray changes due to the difference in the refractive index in each medium, due to this change in speed the transmitted light ray must have a greater angle than the incident ray , since the speed increases as the density of the medium decreases

           [tex]\frac{sin \theta _2}{ sin \theta_1} = \frac{v_2}{v_1}[/tex]

          [tex]\frac{c}{v_2} \ sin \theta_2 = \frac{c}{v_1} \ sin \theta_1[/tex]

          n₂  sin θ₂ = n_1 sin θ₁

oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student observes that a particular spring-mass system has a frequency of oscillation of 10 Hz. the spring constant of the spring is 250 N/m. what is the mass?​

Answers

Answer:

Mass, m = 6.18 kg

Explanation:

Given the following data;

Frequency, F = 10 Hz

Spring constant, k = 250 N/m

We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

10 = 22/14 * √250/m

Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

40.45 = 250/m

Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

what determines the strength of a base?

Answers

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

20/05/2021
BP102T
- Which one of the following statements about reaction rate is false?
3253505030
Reaction rates are not sensitive to temperature.
Reaction rate is governed by the energy barrier between reactants and products.
Reaction rate is the speed at which the reaction proceeds.
Enzymes can accelerate the rate of a reaction.​

Answers

Answer:

Reaction rate are not sensitive to temperature.

Does the law of attraction actually have a basis in physics?

Answers

Answer:

Scientific theories are cited by proponents of the Law of Attraction as evidence in its favor. It, on the other hand, has no theoretical basis. A variety of scientists have questioned the promoters' abuse of scientific principles.

Un corredor hace los 400 metros lisos en 50 seg. Calcula la velocidad en la carrera.

Answers

Answer:

8 meters/second

Explanation:

Rate x Time = Distance

R x T = D

R x 50sec = 400meters

R x 50sec/50sec = 400meters/50sec

R = 8meters/sec

Phase portraits (or phase diagrams) provide a powerful tool to visualize the dynamics of ODE systems.

a. True
b. False

Answers

the answer is True. hope i helped

If the frequency of a wave is doubled, what happens to that waves energy

Answers

Answer:

If the frequency of a wave is doubled, what happens to its wavelength? If the frequency is doubled, the wavelength is only half as long. 3. ... As the frequency slows down, the wavelength increases.

Explanation:

If the height is 10m, what is the potential energy? Asuming that the mass is 10

Answers

[tex]\huge{\textit{\sf{{\color{m}{Answer}}{\color{b}{࿐}}}}}[/tex]

we know,

[tex] \boxed{potential \: energy = mgh}[/tex]

So,

[tex]\longmapsto10 \times 9.8 \times 10[/tex]

[tex]\longmapsto980 \: joules[/tex]

If a body of mass 2 kg is moving with a velocity of 30 m/s, then on doubling its velocity the momentum becomes______.
a-60kgm/s
b-120kgm/s
c-90kgm/s
D-30kgm/s​

Answers

I think it’s B. So 120kgm/s

The planets and the asteroid belt orbit the Sun in __________. Multiple Choice a spherical distribution, whereas the Oort cloud of comets orbits in a plane planes, whereas the Oort cloud of comets has a spherical distribution orbits nearly identical to the Oort cloud of comets planes tilted at an angle to the plane of the Oort cloud of comets a spherical distribution similar to that of the Oort cloud of comets

Answers

Answer:

planes, whereas the Oort cloud of comets has a spherical distribution.

Explanation:

A planet can be defined as a large celestial body having sufficient mass to allow for self-gravity and make it assume a nearly circular shape (hydrostatic equilibrium), revolves in an orbit around the Sun in the solar system and has a cleared neighborhood.

Basically, the planets are divided into two (2) main categories and these includes;

I. Outer planets: these planets are beyond the asteroid belt and comprises of jupiter, saturn, uranus and neptune, from left to right of the solar system.

II. Inner planets: these planets are the closest to the sun and comprises of mercury, venus, earth and mars.

These outer planets are made mostly of gases (hydrogen and helium) causing them to be less dense than the solid inner planets. These gases are generally known to be less dense in terms of physical properties.

Oort cloud is also referred to as Opik and it typically comprises of icy pieces of planetesimals (space debris) that spherically surrounds the sun at distances ranging from about 3000 to 100,000 AU.

Hence, the planets and the asteroid belt orbit the Sun in planes, whereas the Oort cloud of comets has a spherical distribution.

What is the frequency of microwaves of wavelength 3 cm?
Give your answer to the
nearest GHz and without units.

Answers

Answer:

10 GHz

Explanation:

Applying,

v = λf.................... Equation 1

Where v = speed of microwave, λ = wavelength, f = frequency.

make f the subject of the equation

f = v/λ................ Equation 2

Note: Microwave is an electromagnetic wave, and all electromagnetic wave have the same speed, which is 3×10⁸ m/s

From the question,

Given: λ = 3 cm = 0.03 m

Constant; v = 3×10⁸ m/s

Substitute these values into equation 2

f = 3×10⁸/(0.03)

f = 10¹⁰ Hz

f = (10¹⁰/10⁹) GHz

f = 10 GHz

Which of the following rays is NOT possible for a converging lens?

Answers

Ray B. isn't possible for a converging lens, because after passing through focus ot would go parallel to the principal axis,

So, Correct option is :

=》Option B.)

A solid, uniform sphere of mass 2.0 kg and radius 1.8 m rolls from rest without slipping down an inclined plane of height 7.5 m. What is the angular velocity of the sphere at the bottom of the inclined plane

Answers

Answer:

[tex]w^2=5.5rads/s[/tex]

Explanation:

From the question we are told that:

Mass [tex]m=2.0kg[/tex]

Radius [tex]r=1.8m[/tex]

Height [tex]h=7.5m[/tex]

Generally the equation for Potential energy is mathematically given by

Potential energy=Kinetic energy+Rotational energy

 [tex]mgh=\frac{1}{2}mv^2+\frac{1}{2}Iw^2[/tex]

Since there is no slipping

 [tex]v=rw[/tex]

Therefore

 [tex]mgh=\frac{1}{2}mr^2w^2+\frac{1}{2}Iw^2[/tex]

Where

      [tex]I=\frac{1}{2}mr^2[/tex]

      [tex]l=3.24m[/tex]

 [tex]2*9.81*7.5=\frac{1}{2}(2)(1.8)^2w^2+\frac{1}{2}(3.24)w^2\\\\[/tex]

 [tex]147.15=3.24w^2+1.62w^2[/tex]

 [tex]w^2=\frac{147.15}{4.86}[/tex]

 [tex]w^2=\sqrt{\frac{147.15}{4.86}}[/tex]

 [tex]w^2=5.5rads/s[/tex]


State the
the properties of magnets.

Answers

Answer:

All magnets have two poles: the North Pole and the South Pole.

Magnets attract ferromagnetic materials such as iron, nickel, and cobalt.

The magnetic force of a magnet is stronger at its poles than in the middle.

A freely suspended magnet always points in North-South direction.

Hope this helps

You throw a ball straight up. Compare the sign of the work done by gravity while the ball goes up with the sign of the work done by gravity while it goes down.

a. Work is + on the way up and + on the way down
b. Work is + on the way up and - on the way down
c. Work is - on the way up and + on the way down
d. Work is - on the way up and - on the way down

Answers

Answer:

c. Work is - on the way up and + on the way down

Explanation:

Work done is given as the product of the applied force and the displacement of the object.

Work done = F x d

Work done = mg x d

where;

g is acceleration due to gravity = 9.8 m/s²

When the ball goes up, it moves against the force of gravity which tends to pull every object downwards. Since the ball moves against gravity, the work done is negative.

Also, when the ball goes down, it moves in the direction of gravity which acts downwards. Since the ball moves in the same direction as gravity, the work done is positive.

The correct option is "C. Work is negative (-) on the way up and positive (+) on the way down"

Which of these devices is a type of aerobic exercise machine?

Answers

Answer:

Aerobic exercise is an important component of a healthy lifestyle. Find out more about aerobic equipment that can help keep you fit.

Aerobic equipment simulates the movements of aerobic exercises such as walking, jogging, rowing, skiing, hiking, biking, and climbing. These activities rhythmically and continuously move your large muscles — the key to getting your heart beating fast enough and long enough for aerobic conditioning.

A horizontal wire supports it weight in a 0.001T magnetic field, oriented orthogonally to the wire. This is due to current running from left to right in the wire. Calculate the current through this wire that will just support the weight of the wire (over the length of the wire). The length of the wire is 0.5 m, and the mass of the 0.5 m section is 50 g. [give your answer in units of Amps]

Answers

Answer:

Explanation:

Force on a current carrying wire in a magnetic field

= B i L where B is magnetic field , i is current and L is length of the wire .

Putting in the given values in the question

force on a current carrying wire in a magnetic field  = .001 T x i x .5 m

5 x 10⁻⁴ i  N .

weight of the wire = .050 kg x 9.8 m/s²

= .49 N .

For equilibrium

5 x 10⁻⁴ i  = .49

i = 980 A .

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