Answer:
222 g
Explanation:
First we convert 500.0 mL to L:
500.0 mL / 1000 = 0.500 LThen we use the definition of molarity to calculate how many calcium chloride moles are required:
Molarity = moles / litersMolarity * liters = moles4.0 M * 0.500 L = 2.00 molNow we convert 2.00 moles of calcium chloride into grams, using its molar mass:
2.00 mol * 111 g/mol = 222 g