Find the number of grams of calcium chloride needed to prepare 500.0ml of a 4.0m solution

Answers

Answer 1

Answer:

222 g

Explanation:

First we convert 500.0 mL to L:

500.0 mL / 1000 = 0.500 L

Then we use the definition of molarity to calculate how many calcium chloride moles are required:

Molarity = moles / litersMolarity * liters = moles4.0 M * 0.500 L = 2.00 mol

Now we convert 2.00 moles of calcium chloride into grams, using its molar mass:

2.00 mol * 111 g/mol = 222 g

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