A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

Answers

Answer 1

The sum of the given series can be found by simplification of the number

of terms in the series.

A is approximately 2020.022

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

[tex]\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}[/tex]

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

[tex]\displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}[/tex]

Therefore, for the last term we have;

[tex]\displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}[/tex]

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

[tex]\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}[/tex]

[tex]\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)[/tex]

Which gives;

[tex]\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2022} \right)[/tex]

[tex]\displaystyle A = 2 \times 1011 \cdot \left(1 - \frac{1}{2022} \right) = \frac{1032231}{511} \approx \mathbf{2020.022}[/tex]

A ≈ 2020.022

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Answer 2

A is equal to 1,685.00049.

Given that A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021, the following calculation must be performed to determine the result of this operation:

337/2 = 168.5 1011/10 = 101.1 337/5 = 67.4 1/2021 = 0.00049  1011 + 337 + 168.5 + 101.1 + 67.4 + 0.00049 = A 1685.00049 = A

Therefore, A is equal to 1,685.00049.

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Answers

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Answers

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Answer:

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Answer
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Answers

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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f(x)=x^2-7 and h(x)=7x-5, then f(h(2))= ?

Answers

Answer:    74

==================================================

Work Shown:

h(x) = 7x-5

h(2) = 7(2)-5

h(2) = 14-5

h(2) = 9

f(h(2)) = f(9)

f(x) = x^2-7

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f(h(2)) = 74

-----------

Here's a slightly alternative approach:

f(x) = x^2 - 7

f(h(x)) = ( h(x) )^2 - 7

f(h(x)) = ( 7x-5 )^2 - 7

f(h(2)) = ( 7*2-5 )^2 - 7

f(h(2)) = ( 14-5 )^2 - 7

f(h(2)) = ( 9 )^2 - 7

f(h(2)) = 81 - 7

f(h(2)) = 74

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