Answer:
The angular displacement is 37.5 radian.
Explanation:
Given that,
The radius of the car, r = 0.3 m
The acceleration of the car, [tex]\alpha =3\ rad/s^2[/tex]
The initial speed of the car, [tex]\omega_i=0[/tex]
Time, t = 5 s
The angular displacement can be calculated using second equation of motion i.e.
[tex]\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\\theta=\dfrac{1}{2}\alpha t^2\\\\\theta=\dfrac{1}{2}\times 3\times (5)^2\\\\\theta=37.5\ rad[/tex]
So, it will make 37.5 radians.
The resistivity of a material is 2x10-3Ωm. What is the conductivity\n
Answer:
Conductivity, [tex]\sigma=500\ (\Omega-m)^{-1}[/tex]
Explanation:
Given that,
The resistivity of a material, [tex]\rho=2\times 10^{-3}\ \Omega-m[/tex]
We need to find the conductivity of the material.
We know that the reciprocal of resistivity is called conductivity.
[tex]\sigma=\dfrac{1}{\rho}\\\\\sigma=\dfrac{1}{2\times 10^{-3}}\\\\\sigma=500\ (\Omega-m)^{-1}[/tex]
So, the conductivity of the material is [tex]500\ (\Omega-m)^{-1}[/tex].
A boat moves up and down as water waves pass under the boat. If the amplitude of the wave gets bigger, then
A)
the boat will rise up higher.
B)
the boat will not rise up as high.
C)
the boat will go up and down more often.
D)
the boat will continue to move the same way.
Answer: The Boat will rise
Explanation: Because high amplitude means high in heights.
Billy is trying to shine a laser off a mirror at the end of a basketball court into Sam's eyes to distract him (Billy is evil). Sam is at a 38 degree reflection angle from the mirror. At what angle does Billy need to shine the laser at the mirror to get it in Sam's eyes.
Answer:
When we have a plane interface, the angle of incidence of the ray is the same as the angle of reflection.
In this case, we have a mirror (we assume that it is plane) and we know that we need to have an angle of reflection equal to 38° in order to reach Sam.
Then the angle of incidence of the ray must also be exactly 38°.
Then Billy needs to shine his laser at an angle of 38° at the mirror.
(where the angle is measured between the normal line to the surface of the mirror and the incident ray)
Billy needs to shine the laser at an incident angle of 38 degrees.
LASER is an acronym that stands for “light amplification by the stimulated emission of radiation.” We know that according to the laws of reflection, the angle of incidence is equal to the angle of reflection.
As such, knowing that Sam is at a 38 degree reflection angle from the mirror, Billy needs to shine the laser at an incident angle of 38 degrees.
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What is a measure of how much matter an object is made of?
Answer:
grams
Explanation:
Calculate the change in momentum of a ball has 35 kg mass and it changed its velocity from 3m/s to 6 m/s
please hellllpppppp
Answer:
105 kg.m/s
Explanation:
Formula for change in momentum is given as;
ΔP = m(v - u)
We are given;
Mass; m = 35 kg
Initial velocity; u = 3 m/s
Final velocity; v = 6 m/s
Thus;
ΔP = 35(6 - 3)
ΔP = 35 × 3
ΔP = 105 kg.m/s
diffraction of light is the __________ of light as it passes through the Edges of a barrier or a slit.
1, reflections
2, refraction
3,bending
4,absorbing
Answer:
3 bending
Explanation:
Imagine that I have a ping-pong ball and a bowling ball resting on the floor of our classroom. I go up to the bowling ball and give it a push so that it starts rolling. If I give a push of the exact same strength to the ping-pong ball, how will the resulting motion of the ping-pong ball be different
Answer:
the speed and aceleration of the ping pong ball is greater than that of the bowling ball.
Explanation:
We can analyze this exercise from several points of view, if we use Newton's second law
Bowling ball
F = M a₁
pingpongg ball
F = m a₂
as the forces the same
M a₁ = m a₂
a₂ = [tex]\frac{M}{m}[/tex] a₁
Since the mass of the bowling ball is much greater than the ping pong ball,
a₂ »a₁
so the acceleration of the ping pong ball is much greater than the acceleration of the bowling ball.
If we use the relationship of momentum and momentum, assuming that the time for the two cases is the same and that both start from rest
Bowling ball
I = F t = Δp
I = M (v₁ - v₀)
Ping pong ball
I = F t = Δp
I = m (v₂ -v₀)
the impulse itself
M v₁ = m v₂
v₂ = [tex]\frac{M }{ m}[/tex] v₁
so we conclude that the speed of the ping pong ball is much greater than the speed of the bowling ball.
In conclusion the speed and aceleration of the ping pong ball is greater than that of the bowling ball.
You are driving up a long, inclined road. After 1.50mi you notice that signs along the roadside indicate that your elevation has increased by 510ft . b) How far do you have to drive to gain an additional 110ft of elevation
Answer:
1.825 miles
Explanation:
Given that :
Distance driven = hypotenus = 1.5 miles
Elevation at distance of 1.5 miles = 510 feets
Converting miles to feets for the hypotenus :
1 mile = 5280 feets
1.5 miles = (5280 * 1.5) = 7920 feets
To obtain the angle of inclination :
Using Pythagoras rule :
Sinθ = opposite / hypotenus
θ = Sin^-1(510 / 7920)
θ = 3.692°
For an additional elevation of 110 ft ; new height = 110 + 510 = 620 feets
Distance driven, d =?
Sin 3.69 = (620 / d)
0.0643581 * d = 620
d = 620 / 0.0643581
d = 9633.5970 feets
Converting to feets :
9633.5970 / 5280 = 1.8245448
= 1.825 miles
Describe how global context (scientific and technical innovation) is connected with force, friction,energy and motion in 200 words.
2. What is the cheetah's speed for the first four seconds. She
Explanation:
Cheetahs can go from 0 to 60 miles per hour in just 3.4 seconds and reach a top speed of 70 miles per hour. While they are the fastest land animal in the world, they can only maintain their speed for only 20 to 30 seconds.
What recreational drug does an alcopop contain?
An "alcopop" is a term used to describe a flavored alcoholic beverage that typically resembles a soft drink or a fruit juice in appearance and taste. It is also referred to as a "ready-to-drink" (RTD) beverage.
Alcopops are often targeted toward younger consumers and are known for their sweet and fruity flavors, which can mask the taste of alcohol.
The specific recreational drug that an alcopop contains is alcohol itself. Alcohol, or ethanol, is a psychoactive substance that can have intoxicating effects when consumed.
It is considered a recreational drug because of its ability to alter consciousness, impair judgment and coordination, and produce pleasurable or mood-altering effects.
The alcohol content in alcopops can vary, but it is typically lower than in pure spirits or liquors. This is often achieved through dilution with other ingredients, such as carbonated water or fruit juices, to create a milder alcoholic beverage.
Alcopops may also contain additional flavorings, sweeteners, and additives to enhance their taste and appeal.
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Does light travel faster in seawater or in fresh water? Does light travel faster in seawater or in fresh water? Light travels faster in seawater, because the index of refraction is smaller in seawater. Light travels faster in fresh water, because the index of refraction is smaller in fresh water. Light travels faster in fresh water, because the index of refraction is larger in fresh water. Light travels faster in seawater, because the index of refraction is larger in seawater.
No
because that is a light
The light travel faster in fresh water as compare to sea water.
When light goes from denser to rare medium the speed of light is increases.When light travel from rare to denser medium the speed of light is decreases.The reflective index of denser medium is more as compare to rare medium.The reflective index of sea water is more as compare to fresh water.Hence, the light travel faster in fresh water as compare to sea water.
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Which two options are homogeneous mixtures?
A. Sand
B. A wet sponge
C. Liquid dishwashing soap
O D. Vinegar
Answer:
Liquid dishwashing soap
Vinegar
A motorcycle passes over the top of a hill that has a radius of curvature of 100 m. The mass of the motorcycle plus rider is 300 kg. The motorcycle is moving at a speed of 30 m/s. The surface exerts a normal force of magnitude FN on the motorcycle.The motorcycle passes over the top of the hill again but now is moving at a speed of 33 m/s. How does the new normal force exerted on the motorcycle compare to FN
Answer:
[tex]F_N>F_N'[/tex]
Explanation:
From the question we are told that
Radius of curvature[tex]r=100m[/tex]
Mass [tex]M=300kg[/tex]
initial Speed of Motorcycle [tex]V_1=30m/s[/tex]
Final Speed of Motorcycle [tex]V_2=33m/s[/tex]
Generally the equation Force at initial speed is mathematically given as
[tex]F_N=mg-\frac{mv^2}{R}[/tex]
[tex]F_N=300*9.8-\frac{(300*30)^2}{100}[/tex]
[tex]F_N=240N[/tex]
Generally the equation Force at Final speed is mathematically given as
[tex]F_N'=mg-\frac{mv'^2}{R}[/tex]
[tex]F_N'=300*9.8-\frac{(300*33)^2}{100}[/tex]
[tex]F_N'=-327N[/tex]
Therefore
[tex]F_N>F_N'[/tex]
Following are the calculation to the given question:
Solution:
Using formula:
[tex]\to mg - F^{'}_N=\frac{mv^{2}}{R} \\[/tex]
Calculating the Initial value:
[tex]\to F_N = mg - \frac{mv^2}{R}\\\\[/tex]
[tex]= 300 \times (9.8 - \frac{(30)^2}{100}) \\\\= 300 \times (9.8 - \frac{900}{100}) \\\\= 300 \times (9.8 - 9) \\\\= 300 \times (0.8) \\\\ = 240\ N \\\\[/tex]
Calculating the Final value:
[tex]\to F^{'}_{N}= 300 (9.8 -\frac{33^2}{100})\\\\[/tex]
[tex]= 300 (9.8 -\frac{1089}{100})\\\\= 300 (9.8 - 10.89)\\\\= 300 (- 1.09)\\\\=-327[/tex]
Therefore, the answer is "the new normal force is less than [tex]F_{N}[/tex]" or [tex]\bold{F^{'}_{N}< F_{N}}[/tex].
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According to the law of conservation of energy, how will the sum of the kinetic
and potential energies compare at the four points?
Can you also answer questions 1-5
Answer:
I think that this ans may help you
g A boat is anchored 2000 ft from shore anddirects its searchlight towards an automobile travelingdown the straight road. At the particular moment whenthe distance rfrom the searchlight to the automobile is3000 ft, the automobile has speed 80 ft/s and increasesits speed at a rate of 15 ft/s2 down the road.Find the required angular velocity and angularacceleration of the boat's searchlight to track the automobile at this instant.(Answers: 0.018 rad/s CCW, 0.004 rad/s2 CCW)
Answer:
Explanation:
The distance of searchlight will act as radius R and velocity of car may be supposed to be tangential velocity v . We are required to calculate angular velocity ω .
v = 80 ft /s
R = 3000 ft
ω = v / R
= 80 / 3000 = .027 rad / s
For angular acceleration the formula is
angular acceleration α = a / R
a is linear acceleration = 15 ft / s²
α = 15 / 3000 = .005 rad / s².
Explain why objects in water appear to be a different size then the same objects above the water.
Answer:
the answer is the third one since water reflects it
Explanation:
What is light? Let's tallk about anything
Calculate the amount of potential difference in a capacitor of 0.9 MF , If the amount of charge is 1.4x10^-4 C .(Show all the work)
Answer:
1.56×10¯¹⁰ V.
Explanation:
From the question given above, the following data were obtained:
Capicitance (C) = 0.9 MF
Quantity of electricity (Q) = 1.4x10¯⁴ C
Potential difference (V) =?
Next, we shall convert 0.9 MF to farad (F). This can be obtained as follow:
1 MF = 10⁶ F
Therefore,
0.9 MF = 0.9 MF × 10⁶ F / 1 MF
0.9 MF = 9×10⁵ F
Finally, we shall determine the potential difference. This can be obtained as follow:
Capicitance (C) = 9×10⁵ F
Quantity of electricity (Q) = 1.4x10¯⁴ C
Potential difference (V) =?
Q = CV
1.4x10¯⁴ = 9×10⁵ × V
Divide both side by 9×10⁵
V = 1.4x10¯⁴ / 9×10⁵
V = 1.56×10¯¹⁰ V
Therefore, the potential difference is 1.56×10¯¹⁰ V.
Someone help me with this PE question?
Answer:
Your abdominals
Explanation:
What is an
example of a force?
Pressure
Power
Energy
Weight
Answer:
weight
Explanation:
weight is the pull of gravity so its a force !!
What three factors determine the amount of potential energy in a object are ______,______,and ______.
Answer:
It should be Mass, Gravity and Height
Explanation:
1. State the law of conservation of energy and what it means for you as a human considering how energy works.
2. Explain how different forms of energy are related.
PLEASE I NEED HELP!! I NEED IT NOW!! AND PLEASE DO IT IN YOUR OWN WORDS!! THANK YOU!
Answer: 1. The law of consevation of energy sates that energy can neither be created nor destroyed. It can only be transformed or transfered from one form to another. The law of conservation of energy is found everywhere for example, Water falls from the sky, converting potential energy to kinetic energy.
2. Different forms of energy are related because energy cannot be created or destroyed. they can all be transformed into from one form to another.
Explanation:
A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.
Tara goes kayaking at sunrise. She rows 50 feet in 20 seconds. She transfers
100 joules of energy. What is Tara's power?
5 W 10 W
50 W
2 W
help would be greatly appreciated
How does an unbalanced force cause a change in direction of an object?
Answer:
Explanation:
The net force is in the same direction of the acceleration. Acceleration changes the speed of an object.
Consider a collection of charges in a given region and suppose all other charges are distant and have a negligible effect. Further, the electric potential is taken to be zero at infinity. If the electric potential at a given point in the region is zero, which of the following statements must be true?
A. The electric field is zero at that point.
B. The charges have the same sign and are symmetrically arranged around the given point.
C. The electric potential energy is a minimum at that point.
D. There is no net charge in the region.
E. Some charges in the region are positive, and some are negative.
Answer:
E. Some charges in the region are positive, and some are negative.
Explanation:
Electric potential is given as;
[tex]V = \frac{W}{Q}[/tex]
where;
W is the work done in moving a charge between two points which have a difference in potential
Q is quantity of charge in the given region
If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.
Therefore, the correct statement in the given options is "E"
E. Some charges in the region are positive, and some are negative.
Two positive charges are fixed a distance apart.the sun of their charges is Qt.what charge must each have in order to maximise the electric force between them
Answer:
Both charges must have the same charge, Qt/2.
Explanation:
Let the two charges have charge Q1 and Q2, respectively.
Use Coulombs's Law to find an expression for the force between the two charges.
[tex]F = k_e\frac{Q_1Q_2}{r^2}[/tex], where
Ke is Coulomb's contant and
r is the distance between the charges.
We know from the question that
Q1 + Q2 = Qt
So,
Q2 = Qt - Q1
[tex]F = k_e\frac{Q_1(Q_t - Q_1)}{r^2}[/tex]
Simplify to obtain,
[tex]F = \frac{k_e}{r^2} (Q_tQ_1 - Q_1^2)[/tex]
In order to find the value of Q1 for which F is the maximum, we will use the optimization technique of calculus.
Differentiate F with respect to Q1,
[tex]\frac{dF}{dQ_1} = \frac{k_e}{r^2} (Q_t - 2Q_1)[/tex]
Equate the differential to 0, to obtain the value of Q1 for which F is the maximum.
[tex]\frac{k_e}{r^2} (Q_t - 2Q_1) = 0\\Q_t - 2Q_1 = 0\\2Q_1 = Q_t\\Q1 = \frac{Q_t}{2}[/tex]
It follows that
[tex]Q_2 = \frac{Q_t}{2}[/tex].
A 1.0 C charged object and a 2.0 C charged object are separated by 100 m. Where should a -1.0x10-3 C charged object be placed on a line between the positively charged objects so that the net electrical force exerted on the negatively charged object is zero
Answer:
x = 41.2 m
Explanation:
The electric force is a vector magnitude, so it must be added as vectors, remember that the force for charges of the same sign is repulsive and for charges of different sign it is negative.
In this case the fixed charges (q₁ and q₂) are positive and separated by a distance (d = 100m), the charge (q₃ = -1.0 10⁻³ C)) is negative so the forces are attractive, such as loads q₃ must be placed between the other two forces subtract
F = F₁₃ - F₂₃
let's write the expression for each force, let's set a reference frame on the charge q1
F₁₃ = [tex]k \frac{q_1 q_3}{x^2}[/tex]
F₂₃ = [tex]k \frac{q_2 q_3}{(d-x)^2}[/tex]
they ask us that the net force be zero
F = 0
0 = F₁₃ - F₂₃
F₁₃ = F₂₃
k \frac{q_1 q_3}{x^2} =k \frac{q_2 q_3}{(d-x)^2}
[tex]\frac{q_1}{x^2} = \frac{q_2}{(d-x)^2 }[/tex]q1 / x2 = q2 / (d-x) 2
(d-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
we substitute
(100 - x)² = 2/1 x²
100- x = √2 x
100 = 2.41 x
x = 41.2 m
S
m
On a frictionless toy race track, a 0.035 kg toy car moving right at 0.30 collides with another 0.040 kg toy
m
car moving left at 0.20 After the collision, the 0.035 kg car moves left at 0.20
S
m
S
What is the final speed of the 0.040 kg toy car?
Answer: 0.24 m/s
Explanation: