Dominic is cutting a rectangular hole in his paper, from top left corner to the bottom right corner. The rectangle will be 4.5 cm long and 3.5 cm wide. which of the following is closest to the distance between the corners of the rectangle?
Answer:
Step-by-step explanation:
So initially you have a square piece of metal, 15" x 15". You cut out squares from the corners of each side with side length x.
So you'll have a sheet that looks something like this now (assuming the formatting works):
_____
__| |__
| |
|__ __|
|____|
Your original side length was 15, but it has now been reduced by x on each side, so you're now going to have a new side length of 15 - 2x
When you fold the box up, the box will have a height of just x.
So you have a base with lengths (15 - 2x) and (15 - 2x), and a height which is just x.
V = l*w*h
So
V = (15 - 2x)(15 - 2x)(x)
= 225x - 60x^2 + 4x^3
Hope this helps
PLEASE SOMEONE HELP ME. I WILL BRAINLIEST YOU AND GIVE YOU POINTS.
Answer:
option D is the answer
Step-by-step explanation:
3n + 5
_______
n² + 5
Find the equation that represnts the graph.
Answer:y=x+3
Step-by-step explanation:
10 CDs costs $2.30. A package of 50 CDs costs $10.50. Which is the better buy?
To get the answer to this question we would have to calculate how much each DVD costs in each scenario.
To do this we will divide each cost by the total number of CDS:
[tex]\frac{2.30}{10} = .23[/tex]
[tex]\frac{10.50}{50} = .21[/tex]
For the pack of 10 CDS each CD costs 23 cents. On the contrary, for the pack of 50 CDs each CD costs 21 cents. Therefore to get a better deal, you would want to go with the 50 CDs.
Hope this helps!
- Kay
The cost per CD is lower when buying the package of 50 CDs, it is the better buy. You would save money by purchasing the package of 50 CDs for $10.50.
To determine which is the better buy, we need to compare the cost per CD in both scenarios.
Let's first calculate the cost per CD when buying 10 CDs:
Cost for 10 CDs = $2.30
Cost per CD = $2.30 / 10 CDs = $0.23 per CD
Now, let's calculate the cost per CD when buying a package of 50 CDs:
Cost for 50 CDs = $10.50
Cost per CD = $10.50 / 50 CDs = $0.21 per CD
Comparing the two options:
- Buying 10 CDs individually costs $0.23 per CD.
- Buying a package of 50 CDs costs $0.21 per CD.
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If two triangles are congruent, which of the following statements must be
true? Check all that apply.
Answer:
A, C, D are true.
Step-by-step explanation:
Answer: A,B,C,D
Step-by-step explanation:
ALL ARE TRUE I JUST TOOK THE TEST A P E X
the first blank is 25 the second blank is 10 what is the slope
Answer:
5/2
Step-by-step explanation:
25 and 10 so 25/10 or 5/2 or 2 1/2
-7q + 12r = 3q - 4r what dose r equal
Answer:
r = 5y/8
Step-by-step explanation:
isolate the variable by dividing each side by factors that contain the variable.
Find the slope of the line without graphing using the 2 points below.
(-3 , 4) & (13 , 8)
m = _______
Answer:
Step-by-step explanation:
1. use the slope formula --> (y2-y1)/(x2-x1)
2. (8 - 4)/(13 -(-3))
3. 4/16
4. m = 1/4
Felix deposited $1,340 into a savings account that earns 6% simple interest for 3 years. Find how much interest will he have earned.
Answer:
542
Step-by-step explanation:
divide it I hope it helps
Answer:
241.20 dollars
Step-by-step explanation:
Use the equation I=prt, where I is the interest and p is the percentage of simple interest, which is 6% or 0.06. T is the rate of time in years. R is the amount Felix deposited. Our equation would be:
I=(0.06)(1340)(3)
I=(0.18)(1340)
I=$241.20
Meteorology A Weather forecaster uses a barometer to measure air pressure and make weather predictions. Suppose a standard mercury barometer reads 29.8 in. The mercury rises 0.02 in. And then false 0.09 in . The mercury falls again 0.18 in. Before rising 0.07 in. What does the word "rise" suggest? What does the word "fall" suggest?
Answer:
rise : atmospheric pressure increases
fall : atmospheric pressure decreases
Step-by-step explanation:
In the context, it is given that a weather forecaster takes the help of the barometer to check the air pressure and predicts the weather. The column of mercury level in the barometer shows a rise or fall in the glass tube as the weight of the atmosphere falling on the mercury surface changes.
Here it is given that the mercury rises for 0.02 in, then it falls 0.09 in, it then rises by 0.07 in and then again falls by 0.18 in. The word "rise" here shows that the weight of the atmosphere is more. In other words, increase in atmospheric pressure increases the level of mercury in the glass tube and the decrease in or "fall" in the mercury level shows the drop in atmospheric pressure.
What is the rectangular form of r=8sin(0)
Step-by-step explanation:
the regular form of r=8
= 118
1=52
Ms. Boyd has 9 bills in her purse that consist
of five-dollar bills and twenty-dollar bills. The
value of the bills is worth $105. How many
five-dollars bills and twenty-dollar bills does
Ms. Boyd have?
Answer:
number of $20 bill = 4
Number of $5 bill = 5
Step-by-step explanation:
Given that:
Total number of $5 and $20 bills = 9
Let :
Number of $5 bills = x
Number of $20 bills = y
Combined worth of all bills = $105
x + y = 9 - - - (1)
5x + 20y = 105 - - - (2)
From (1)
x = 9 - y
Substitute x = 9 - y into (2)
5(9 - y) + 20y = 105
45 - 5y + 20y = 105
15y = 105 - 45
15y = 60
y = 60/15
y = 4
x = 9 - y
x = 9 - 4 = 5
Hence,
number of $20 bill = 4
Number of $5 bill = 5
Given the formula for volume of a box, V=lwh, which answer would you get if you solve for h?
Answer:
Step-by-step explanation:
h=V/lw
AB←→ intersects PQ←→ at point M;
Point C is on AB←→ ;
Point R is on PQ←→ ;
△CMR is a right triangle.
Which statement describes the relationship between AB←→ and PQ←→ ?
A.
AB←→ and PQ←→ are skew
B.
AB←→ and PQ←→ are collinear
C.
AB←→⊥PQ←→
D.
AB←→∥PQ←→
Answer:
(C). AB←→⊥PQ←→
Step-by-step explanation:
This is the only suitable answer to produce a triangle △CMR which is a right triangle.
When we will draw Line AB And PQ which they are intersecting And to produce a right triangle by taking two random points ( C on AB and P on PQ).
Then AB and PQ must be Perpendicular to each other, only then a triangle CMR will be right angled at M.
A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, & 82% gold. Choose 2 different alloys that can be used to create one that is 75% gold. pls try to explain with a system of equations ; ;
Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.
As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.
One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.
Case 1: 82% gold + 50% gold
Let x grams of 82% gold and y grams of 50% gold added to make x+y=14 grams of 75% gold, so
75% of 14 = 82% of x + 50% of y
[tex]\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\[/tex]
[tex]\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)[/tex] [as x+y=14]
[tex]\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\[/tex]
[tex]\Rightarrow x =(25 \times 14)/32=10.9375[/tex] grams
and [tex]y = 14-x= 14-10.9375=3.0625[/tex] grams.
Hence, 10.9375 grams of 82% gold and 3.0625 grams of 50% gold added to make 14 grams of 75% gold.
Case 2: 82% gold + 25% gold
Let x grams of 82% gold and y grams of 25% gold added to make x+y=14 grams of 75% gold, so
75% of 14 = 82% of x + 25% of y
[tex]\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\[/tex]
[tex]\Rightarrow x =(50 \times 14)/57=12.28[/tex] grams
and [tex]y = 14-x= 14-12.28=1.72[/tex] grams.
Hence, 12.28 grams of 82% gold and 1.72 grams of 50% gold added to make 14 grams of 75% gold.
PLEASE HELP ME WITH MY MATHE HOMEWORK!
Answer:
59/6
Step-by-step explanation:
9x6=54
54+5= 59
put the denominator of the fraction to the denominator to the new fraction. I hope this helps.
HELP PLEASE!!!!
Ray created the list of factors for 48 below
43 1,2,3,4,6,7,8, 12, 16, 24,48
Which number should be removed from his list to make the list accurate?
10
Answer:
7
Step-by-step explanation:
7 is not a factor of 48, since 7 can not be multiplied by another whole number to get 48. (48 divided by 7 is 6.8)
Answer:
7
Step-by-step explanation:
When you flip a biased coin the probability of getting a tail is 0.35.
Find the probability of getting a head.
Answer:
0.65
Step-by-step explanation:
a coin has 2 sides so there is two outcomes
1-0.35=0.65
102 is 0.6% of what number
102 is 60% 170. Divide 102 by 0.6, which results in 102. Hope this helps! Have an amazing rest of your day and please mark brainliest! xx
I WILL MARK BRAINIEST
please tell me what type of angle it is
Answer:
alternate exterior angles
Step-by-step explanation:
Answer: adjacent angles
explanation: both angles share the same side.
can someone please help me
Answer:
a=5
Step-by-step explanation:
18-2a=8
-18 -18
-2a=-10
/-2 /-2
a=5
Please help! It's about systems of equations. Answer correctly i will mark brainliest
Answer:
Step-by-step explanation:
Y= -6
X=-2
The school track is 7/8 of a mile in length. Den ran 1/4 of a mile. How much more will he need to run to go all the way around the track?
Answer:
5/8
Step-by-step explanation:
1/4=2/8
7/8-2/8=5/8
What is the slope of the line below
Answer:-1/2
Step-by-step explanation:
Look at the points
Keith decided to do pushups everyday as part of his exercise routine. He started to do 10 pushups today and he will be adding 3 additional counts for each day that his exercise continues. How many pushups will Keith do if he is exactly on his 3rd week of his exercise routine?
Answer:
55 push ups
Step-by-step explanation:
Given that:
Starting count = 10
Additional count = 3
Starting count + (additional count * number of days)
Exactly on the 3rd week = on the 15th day
10 + (3 * 15)
10 + 45
= 55 push ups
There are 625 students at Median middle school. If 8% of the students were absent on Tuesday , how many students were absent?
If 8% of students were absent on Tuesday no. of students that were absent was 50.
What is the percentage?A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.
Given, There are 625 students at Median middle school and 8% of the students were absent on Tuesday.
∴ No. of students that were absent on Tuesday is 8% of 625 which is,
= (8/100)×625.
= 50.
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PLEASE HELP MEH!!!!!!!!!:
Answer:
A
Step-by-step explanation:
Point slope form
x, y
[tex](y-x)= (slope)(x-y)[/tex]
So its
[tex]y-6=\frac{1}{2}(x+3)[/tex]
So option 1.
Hope this helps plz hit the crown :D
Answer:
B
Step-by-step explanation:
y=mx +b
y= 1/2x = b
y intercept (0,-6)
Determine the input UNITS of ITEM and the output UNITS of ITEM for the statement
below:
It is a lovely time of year on the Serengeti Desert. Every time Simba washes his clothes,
he has to use 1 capful of detergent for each load of wash.
Answer:
For statement 1 :
INPUT UNIT OF ITEM : Time of the year on Serengeti Desert
OUTPUT UNIT OF ITEM : Simba washes his clothes
For statement 2
INPUT UNIT OF ITEM : 1 capful of detergent
OUTPUT UNIT OF ITEM : each load of wash
Step-by-step explanation:
For statement 1 :
INPUT UNIT OF ITEM : Time of the year on Serengeti Desert
OUTPUT UNIT OF ITEM : Simba washes his clothes
For statement 2
INPUT UNIT OF ITEM : 1 capful of detergent
OUTPUT UNIT OF ITEM : each load of wash
From answers provided above the basis for the answers is that an input unit of item will have to result to a reaction which is an output unit of item hence the answers above
2 of 6
Given that a = 12 cm and b = 17 cm, work out the area of the triangle.
Give your answer rounded to 1 DP.
Answer:
102 cm²Step-by-step explanation:
area of a triangle = 1/2 * base * height
= 1/2 * 12 * 17
= 102 cm²
If it exists, solve for the inverse function of each of the following:
1. f(x) = 25x - 18
6. gala? +84 - 7
7. 10) = (b + 6) (6-2)
3. A(7)=-=-
4. f(x)=x
9. h(c) = V2c +2
+30
10. f(x) =
5. f(a) = a +8
ox-1
2. 9(x) = -1
2x+17
8. () - 2*
Answer:
The solution is too long. So, I included them in the explanation
Step-by-step explanation:
This question has missing details. However, I've corrected each question before solving them
Required: Determine the inverse
1:
[tex]f(x) = 25x - 18[/tex]
Replace f(x) with y
[tex]y = 25x - 18[/tex]
Swap y & x
[tex]x = 25y - 18[/tex]
[tex]x + 18 = 25y - 18 + 18[/tex]
[tex]x + 18 = 25y[/tex]
Divide through by 25
[tex]\frac{x + 18}{25} = y[/tex]
[tex]y = \frac{x + 18}{25}[/tex]
Replace y with f'(x)
[tex]f'(x) = \frac{x + 18}{25}[/tex]
2. [tex]g(x) = \frac{12x - 1}{7}[/tex]
Replace g(x) with y
[tex]y = \frac{12x - 1}{7}[/tex]
Swap y & x
[tex]x = \frac{12y - 1}{7}[/tex]
[tex]7x = 12y - 1[/tex]
Add 1 to both sides
[tex]7x +1 = 12y - 1 + 1[/tex]
[tex]7x +1 = 12y[/tex]
Make y the subject
[tex]y = \frac{7x + 1}{12}[/tex]
[tex]g'(x) = \frac{7x + 1}{12}[/tex]
3: [tex]h(x) = -\frac{9x}{4} - \frac{1}{3}[/tex]
Replace h(x) with y
[tex]y = -\frac{9x}{4} - \frac{1}{3}[/tex]
Swap y & x
[tex]x = -\frac{9y}{4} - \frac{1}{3}[/tex]
Add [tex]\frac{1}{3}[/tex] to both sides
[tex]x + \frac{1}{3}= -\frac{9y}{4} - \frac{1}{3} + \frac{1}{3}[/tex]
[tex]x + \frac{1}{3}= -\frac{9y}{4}[/tex]
Multiply through by -4
[tex]-4(x + \frac{1}{3})= -4(-\frac{9y}{4})[/tex]
[tex]-4x - \frac{4}{3}= 9y[/tex]
Divide through by 9
[tex](-4x - \frac{4}{3})/9= y[/tex]
[tex]-4x * \frac{1}{9} - \frac{4}{3} * \frac{1}{9} = y[/tex]
[tex]\frac{-4x}{9} - \frac{4}{27}= y[/tex]
[tex]y = \frac{-4x}{9} - \frac{4}{27}[/tex]
[tex]h'(x) = \frac{-4x}{9} - \frac{4}{27}[/tex]
4:
[tex]f(x) = x^9[/tex]
Replace f(x) with y
[tex]y = x^9[/tex]
Swap y with x
[tex]x = y^9[/tex]
Take 9th root
[tex]x^{\frac{1}{9}} = y[/tex]
[tex]y = x^{\frac{1}{9}}[/tex]
Replace y with f'(x)
[tex]f'(x) = x^{\frac{1}{9}}[/tex]
5:
[tex]f(a) = a^3 + 8[/tex]
Replace f(a) with y
[tex]y = a^3 + 8[/tex]
Swap a with y
[tex]a = y^3 + 8[/tex]
Subtract 8
[tex]a - 8 = y^3 + 8 - 8[/tex]
[tex]a - 8 = y^3[/tex]
Take cube root
[tex]\sqrt[3]{a-8} = y[/tex]
[tex]y = \sqrt[3]{a-8}[/tex]
Replace y with f'(a)
[tex]f'(a) = \sqrt[3]{a-8}[/tex]
6:
[tex]g(a) = a^2 + 8a- 7[/tex]
Replace g(a) with y
[tex]y = a^2 + 8a - 7[/tex]
Swap positions of y and a
[tex]a = y^2 + 8y - 7[/tex]
[tex]y^2 + 8y - 7 - a = 0[/tex]
Solve using quadratic formula:
[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]
[tex]a = 1[/tex] ; [tex]b = 8[/tex]; [tex]c = -7 - a[/tex]
[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes
[tex]y = \frac{-8 \±\sqrt{8^2 - 4 * 1 * (-7-a)}}{2 * 1}[/tex]
[tex]y = \frac{-8 \±\sqrt{64 + 28 + 4a}}{2 * 1}[/tex]
[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 * 1}[/tex]
[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 }[/tex]
Factorize
[tex]y = \frac{-8 \±\sqrt{4(23 + a)}}{2 }[/tex]
[tex]y = \frac{-8 \±2\sqrt{(23 + a)}}{2 }[/tex]
[tex]y = -4 \±\sqrt{(23 + a)}[/tex]
[tex]g'(a) = -4 \±\sqrt{(23 + a)}[/tex]
7:
[tex]f(b) = (b + 6)(b - 2)[/tex]
Replace f(b) with y
[tex]y = (b + 6)(b - 2)[/tex]
Swap y and b
[tex]b = (y + 6)(y - 2)[/tex]
Open Brackets
[tex]b = y^2 + 6y - 2y - 12[/tex]
[tex]b = y^2 + 4y - 12[/tex]
[tex]y^2 + 4y - 12 - b = 0[/tex]
Solve using quadratic formula:
[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]
[tex]a = 1[/tex] ; [tex]b = 4[/tex]; [tex]c = -12 - b[/tex]
[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes
[tex]y = \frac{-4\±\sqrt{4^2 - 4 * 1 * (-12-b)}}{2*1}[/tex]
[tex]y = \frac{-4\±\sqrt{4^2 - 4 *(-12-b)}}{2}[/tex]
Factorize:
[tex]y = \frac{-4\±\sqrt{4(4 - (-12-b))}}{2}[/tex]
[tex]y = \frac{-4\±2\sqrt{(4 - (-12-b))}}{2}[/tex]
[tex]y = \frac{-4\±2\sqrt{(4 +12+b)}}{2}[/tex]
[tex]y = \frac{-4\±2\sqrt{16+b}}{2}[/tex]
[tex]y = -2\±\sqrt{16+b}[/tex]
Replace y with f'(b)
[tex]f'(b) = -2\±\sqrt{16+b}[/tex]
8:
[tex]h(x) = \frac{2x+17}{3x+1}[/tex]
Replace h(x) with y
[tex]y = \frac{2x+17}{3x+1}[/tex]
Swap x and y
[tex]x = \frac{2y+17}{3y+1}[/tex]
Cross Multiply
[tex](3y + 1)x = 2y + 17[/tex]
[tex]3yx + x = 2y + 17[/tex]
Subtract x from both sides:
[tex]3yx + x -x= 2y + 17-x[/tex]
[tex]3yx = 2y + 17-x[/tex]
Subtract 2y from both sides
[tex]3yx-2y =17-x[/tex]
Factorize:
[tex]y(3x-2) =17-x[/tex]
Make y the subject
[tex]y = \frac{17 - x}{3x - 2}[/tex]
Replace y with h'(x)
[tex]h'(x) = \frac{17 - x}{3x - 2}[/tex]
9:
[tex]h(c) = \sqrt{2c + 2}[/tex]
Replace h(c) with y
[tex]y = \sqrt{2c + 2}[/tex]
Swap positions of y and c
[tex]c = \sqrt{2y + 2}[/tex]
Square both sides
[tex]c^2 = 2y + 2[/tex]
Subtract 2 from both sides
[tex]c^2 - 2= 2y[/tex]
Make y the subject
[tex]y = \frac{c^2 - 2}{2}[/tex]
[tex]h'(c) = \frac{c^2 - 2}{2}[/tex]
10:
[tex]f(x) = \frac{x + 10}{9x - 1}[/tex]
Replace f(x) with y
[tex]y = \frac{x + 10}{9x - 1}[/tex]
Swap positions of x and y
[tex]x = \frac{y + 10}{9y - 1}[/tex]
Cross Multiply
[tex]x(9y - 1) = y + 10[/tex]
[tex]9xy - x = y + 10[/tex]
Subtract y from both sides
[tex]9xy - y - x = y - y+ 10[/tex]
[tex]9xy - y - x = 10[/tex]
Add x to both sides
[tex]9xy - y - x + x= 10 + x[/tex]
[tex]9xy - y = 10 + x[/tex]
Factorize
[tex]y(9x - 1) = 10 + x[/tex]
Make y the subject
[tex]y = \frac{10 + x}{9x - 1}[/tex]
Replace y with f'(x)
[tex]f'(x) = \frac{10 + x}{9x -1}[/tex]