7.4 A six-pulse rectifier supplies 8.8 kW to a resistive load. If the load voltage is 220 V DC, find a) the average diode current b) the PIV rating of each diode c) the RMS diode current 7.5 A three-pulse rectifier supplies a resistive load of 10 2 from a 220 V source. Find
a) the average load voltage b) the average load current c) the maximum load current d) the PIV rating of the diode e) the maximum diode current f) the average load power 7.6 Repeat problem 7.5 after adding a large inductance in series with the load resistance. 7.7 A three-pulse rectifier is connected to a 220 V source. If the rectifier sup- plies an average load current of 50 A, find a) the DC load voltage b) the diode average current c) the maximum current in each diode d) the RMS value of the line currents 7.8 The six-pulse rectifier in Figure 7.6 is connected to a 220 V source. If the rectifier supplies an average load current of 50 A, find a) the DC load voltage b) the diode average current c) the maximum current in each diode d) the RMS value of the line current

Answers

Answer 1

7.4 Given:Power, P = 8.8 kWLoad Voltage, VL

= 220 V DCNumber of pulses, n

= 6Load, RLoad current, I

= VL / RThe average voltage of the rectifier is given by;Vdc

= (2 / π) VL ≈ 0.9 VL The power input to the rectifier is the output power.

Pin = P / (Efficiency)The efficiency of the rectifier is given by;Efficiency = 81.2% = 0.812 = 81.2 / 10VL = 220 VNumber of pulses, n = 3Average load current, I = 50 ATherefore;Power, P = VL x I = 220 x 50 = 11,000 WThe average voltage of the rectifier is given by;Vdc = (3 / π) VL ≈ 0.95 VLPower input to the rectifier;Pin = P / (Efficiency)The efficiency of the rectifier is given by;

Efficiency = 81.2% = 0.812

= 81.2 / 100Therefore,P / Pin

= 0.812Average diode current, I

= P / Vdc

= 11,000 / 209

= 52.63 AMax. diode current, I

= I / n

= 52.63 / 3

= 17.54 ARMS value of the current in each diode;Irms =

I / √2 = 12.42 ALoad resistance, Rload = VL / I

= 220 / 50

= 4.4 Ω7.8Given:Load Voltage, VL

= 220 VNumber of pulses, n

= 6Average load current, I

= 50 ATherefore;Power, P

= VL x I = 220 x 50

= 11,000 WThe average voltage of the rectifier is given by;Vdc

= (2 / π) VL ≈ 0.9 VLPower input to the rectifier;Pin

= P / (Efficiency)The efficiency of the rectifier is given by;Efficiency = 81.2%

= 0.812

= 81.2 / 100Therefore,P / Pin

= 0.812Average diode current, I

= P / Vdc

= 11,000 / 198

= 55.55 AMax. diode current, I

= I / n = 55.55 / 6

= 9.26 ARMS value of the current in each diode;Irms

= I / √2

= 3.29 ALoad resistance, Rload

= VL / I

= 220 / 50

= 4.4 Ω.

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Related Questions

QUESTION 1 Which of the followings is true? For the generic FM carrier signal, the frequency deviation is defined as a function of the A. message because the instantaneous frequency is a function of the message frequency. B. message because it resembles the same principle of PM. C. message frequency. D. message. QUESTION 2 Which of the followings is true? The concept of "power efficiency may be useful for A. linear modulation. B. non-linear modulation. C. multiplexing. D. convoluted multiplexing. QUESTION 3 Which of the followings is true? A. Adding a pair of complex conjugates gives double the real part. B. Electrical components are typically not deployed under wireless systems as transmissions are always through the air channel. C. Adding a pair of complex conjugates gives the real part. D. Complex conjugating is a process of keeping the real part and changing the complex part. QUESTION 4 Which of the followings is true? A. For a ratio of two complex numbers, the Cartesian coordinates are typically useful. B. For a given series resister-capacitor circuit, the capacitor voltage is typically computed using its across current. C. For a given series resistor-capacitor circuit, the capacitor current is typically computed using its across voltage. D. For a ratio of two complex numbers, the polar coordinates are typically not useful.

Answers

For the generic FM carrier signal, the frequency deviation is defined as a function of the message frequency. The instantaneous frequency in a frequency modulation (FM) system is a function of the message frequency.

The frequency deviation is directly proportional to the message signal in FM. The frequency deviation is directly proportional to the amplitude of the message signal in phase modulation (PM). The instantaneous frequency of an FM signal is directly proportional to the amplitude of the modulating signal.

As a result, the frequency deviation is proportional to the message signal's amplitude

The concept of "power efficiency" may be useful for linear modulation. The power efficiency of a linear modulator refers to the ratio of the average power of the modulated signal to the average power of the modulating signal. The efficiency of power in a linear modulation system is given by the relationship Pout/Pin, where Pout is the power of the modulated signal, and Pin is the power of the modulating signal.

Adding a pair of complex conjugates gives the real part. Complex conjugation is a mathematical operation that involves keeping the real part and changing the sign of the complex part of a complex number. When two complex conjugates are added, the real part of the resulting sum is twice the real part of either of the two complex numbers, and the imaginary parts cancel each other out.

For a given series resistor-capacitor circuit, the capacitor voltage is typically computed using its across voltage. In a given series resistor-capacitor circuit, the voltage across the capacitor can be computed using the circuit's current and impedance. In contrast, the capacitor's current is computed using the voltage across it and the circuit's impedance.

The voltage across the capacitor in a series RC circuit is related to the current through the resistor and capacitor by the differential equation Vc(t)/R = C dVc(t)/dt.

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How would you link the capacity decision being made by Fitness Plus to other types of operating decisions?

Answers

Fitness Plus, an emerging fitness and gym provider, is trying to gain a significant share of the market in the region, making it a major competitor to other industry players. Fitness Plus's decision to expand its capacity is critical, and it influences the types of operating decisions they make, including marketing, financial, and human resource decisions.


Capacity decisions at Fitness Plus are linked to marketing decisions in several ways. When Fitness Plus decides to expand its capacity, it means that it is increasing the number of customers it can serve simultaneously. The expansion creates an opportunity to increase sales by catering to a more extensive market. Fitness Plus's marketing team must focus on building brand awareness to attract new customers and create loyalty among existing customers.The expansion also influences financial decisions. Fitness Plus must secure funding to finance the expansion project.

It means that the financial team must identify potential sources of financing, analyze their options, and determine the most cost-effective alternative. Fitness Plus's decision to expand its capacity will also have a significant impact on its human resource decisions. The expansion creates new job opportunities, which Fitness Plus must fill. Fitness Plus must evaluate its staffing requirements and plan its recruitment strategy to attract the most qualified candidates.

In conclusion, Fitness Plus's decision to expand its capacity has a significant impact on its operating decisions. The expansion influences marketing, financial, and human resource decisions. By considering these decisions together, Fitness Plus can achieve its growth objectives and increase its market share in the region.

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Combustion in the gas turbine In the combustor, the initial temperature and pressure are 25°C and 1 atm. Natural gas reacts with moist air with a relative humidity of 80%. The air is excessive for the complete combustion of the fuel, with 110% of stoichiometric air. After combustion, products reach a temperature of 1400 K at the combustor exit. Making necessary assumptions as you deem appropriate, complete the following tasks. a) Determine the balanced reaction equation. [6 marks] b) Calculate the mole fraction of each gas in the products. [3 marks] c) Determine the enthalpy of reaction for combustion products at a temperature of 1400 K (in kJ/kmol). [6 marks] d) Suggest two strategies to make the power plant zero-carbon emissions. [2 marks]

Answers

a) Balanced reaction equation depends on the composition of the natural gas.

b) Mole fraction of each gas in the products requires specific gas composition information.

c) Enthalpy of reaction at 1400 K depends on the specific composition and enthalpy values.

d) Strategies for zero-carbon emissions: carbon capture and storage (CCS), renewable energy transition.

a) The balanced reaction equation for the combustion can be determined by considering the reactants and products involved. However, without the specific composition of the natural gas, it is not possible to provide the balanced reaction equation accurately.

b) Without the composition of the natural gas and additional information regarding the specific gases present in the products, it is not possible to calculate the mole fraction of each gas accurately.

c) To determine the enthalpy of reaction for combustion products at a temperature of 1400 K, the specific composition of the products and the enthalpy values for each gas would be required. Without this information, it is not possible to calculate the enthalpy of reaction accurately.

d) Two strategies to make the power plant zero-carbon emissions could include:

1. Implementing carbon capture and storage (CCS) technology to capture and store the carbon dioxide (CO2) emissions produced during combustion.

2. Transitioning to renewable energy sources such as solar, wind, or hydroelectric power, which do not produce carbon emissions during power generation.

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a) (10 pts). Using a decoder and external gates, design the combinational circuit defined by the following three Boolean functions: F1 (x, y, z) = (y'+ x) z F2 (x, y, z) = y'z' + xy + yz' F3 (x, y, z) = x' z' + xy

Answers

Given Boolean functions are:F1 (x, y, z) = (y'+ x) z F2 (x, y, z) = y'z' + xy + yz' F3 (x, y, z) = x' z' + xyThe Boolean function F1 can be represented using the decoder as shown below: The diagram of the decoder is shown below:

As shown in the above figure, y'x is the input and z is the output for this circuit.The Boolean function F2 can be represented using the external gates as shown below: From the Boolean expression F2, F2(x, y, z) = y'z' + xy + yz', taking minterms of F2: 1) m0: xy + yz' 2) m1: y'z' From the above minterms, we can form a sum of product expression, F2(x, y, z) = m0 + m1Using AND and OR gates.

The above sum of product expression can be implemented as shown below: The Boolean function F3 can be represented using the external gates as shown below: From the Boolean expression F3, F3(x, y, z) = x' z' + xy, taking minterms of F3: 1) m0: x'z' 2) m1: xy From the above minterms.

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A force F = Fxi + 8j + Fzk lb acts at a point (3, -10, 9) ft. it has a moment 34i + 50j + 40k lb · ft about the point (-2, 3, -3) ft. Find Fx and Fz.

Answers

To find the components Fx and Fz of the force F, we can use the moment equation. Hence, the values of Fx and Fz are approximately Fx = 79.76 lb and Fz = 27.6 lb, respectively.

The equation for the moment:

M = r x F

where M is the moment vector, r is the position vector from the point of reference to the point of application of the force, and F is the force vector.

Given:

Force F = Fx i + 8 j + Fz k lb

Moment M = 34 i + 50 j + 40 k lb · ft

Position vector r = (3, -10, 9) ft - (-2, 3, -3) ft = (5, -13, 12) ft

Using the equation for the moment, we can write:

M = r x F

Expanding the cross product:

34 i + 50 j + 40 k = (5 i - 13 j + 12 k) x (Fx i + 8 j + Fz k)

To find Fx and Fz, we can equate the components of the cross product:

Equating the i-components:

5Fz - 13(8) = 34

Equating the k-components:

5Fx - 13Fz = 40

Simplifying the equations:

5Fz - 104 = 34

5Fz = 138

Fz = 27.6 lb

5Fx - 13(27.6) = 40

5Fx - 358.8 = 40

5Fx = 398.8

Fx = 79.76 lb

Therefore, the values of Fx and Fz are approximately Fx = 79.76 lb and

Fz = 27.6 lb, respectively.

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3. (30pts) Given the displacement filed u₁ = (3X²³X₂ +6)×10-² u₂ = (X² +6X₁X₂)×10-² u3 = (6X² +2X₂X₂ +10)x10-² 1) 1) Obtain Green strain tensor E at a point (1,0,2) 2) What is the extension of a line at this point? (Note: initial length and orientation of the line is dx₁) 3) What is the rotation of this line?

Answers

Given the displacement filed [tex]u₁ = (3X²³X₂ +6)×10-² u₂ = (X² +6X₁X₂)×10-² u3 = (6X² +2X₂X₂ +10)x10-²[/tex]To find Green strain tensor E at a point (1,0,2).

The Green-Lagrange strain tensor, E is defined as:E = ½(F^T F - I)Where F is the deformation gradient tensor and I is the identity tensor.The deformation gradient tensor, F is given by:F = I + ∇uwhere u is the displacement vector.In the given displacement field.

The components of displacement vector are given by:[tex]u₁ = (3X²³X₂ +6)×10-²u₂ = (X² +6X₁X₂)×10-²u₃ = (6X² +2X₂X₂ +10)x10-²[/tex]Therefore, the displacement vector is given by[tex]:u = (3X²³X₂ +6)×10-² i + (X² +6X₁X₂)×10-² j + (6X² +2X₂X₂ +10)x10-² k∇u = ∂u/∂X[/tex]From the displacement field.

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A nozzle 0.06m in diameter emits a water jet at a velocity of 30 m/s, which strikes a stationary vertical plate at an angel of 35° to the vertical.
Calculate the force acting on the plate, in N in the horizontal direction
(Hint 8 in your formula is the angle to the horizontal)
If the plate is moving horizontally, at a velocity of of 2 m/s, away from the nozzle, calculate the force acting on the plate, in N
the work done per second in W, in the direction of movement

Answers

The force acting on the plate, in N in the horizontal direction is 41.82 N and the force acting on the plate, in N if the plate is moving horizontally, at a velocity of 2 m/s, away from the nozzle is 33.69 N.

What is a nozzle?

A nozzle is a simple mechanical device that controls the flow of a fluid.

Nozzles are used to convert pressure energy into kinetic energy.

Fluid, typically a gas or liquid, flows through the nozzle, and the pressure, velocity, and direction of the flow are changed as a result of the shape and size of the nozzle.

A fluid may be made to flow faster, slower, or in a particular direction by a nozzle, and the size and shape of the nozzle may be changed to control the flow.

The formula for calculating the force acting on the plate is given as:

F = m * (v-u)

Here, m = density of water * volume of water

= 1000 * A * x

Where

A = πd²/4,

d = 0.06m and

x = ABcosθ/vBcos8θv

B = Velocity of the jet

θ = 35°F

= 1000 * A * x * (v - u)N,

u = velocity of the plate

= 2m/s

= 2000mm/s,

v = velocity of the jet

= 30m/s

= 30000mm/s

θ = 35°,

8θ = 55°

On solving, we get

F = 41.82 N

Work done per second,

W = F × u

W = 41.82 × 2000

W = 83,640

W = 83.64 kW

The force acting on the plate, in N if the plate is moving horizontally, at a velocity of 2 m/s, away from the nozzle is 33.69 N.

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Connect a resistor of value 20 Ω
between terminals a-b and calculate i10
a) Using mesh method
b) Using node method

Answers

a) Using mesh method:

Mesh analysis is one of the circuit analysis methods used in electrical engineering to simplify complicated networks of loops when using the Kirchhoff's circuit laws

b) Using node method

Node analysis is another method of circuit analysis. It is used to determine the voltage and current of a circuit.

a) Using mesh method: Mesh analysis is one of the circuit analysis methods used in electrical engineering to simplify complicated networks of loops when using the Kirchhoff's circuit laws. The mesh method uses meshes as the basic building block to represent the circuit. The meshes are the closed loops that do not include other closed loops in them, they are referred to as simple closed loops.

Connect a resistor of value 20 Ω between terminals a-b and calculate i10

a) Using mesh method

1. Assign a current in every loop in the circuit, i1, i2 and i3 as shown.

2. Solve the equation for each mesh using Ohm’s law and KVL.

The equation of each loop is shown below.

Mesh 1:

6i1 + 20(i1-i2) - 5(i1-i3) = 0

Mesh 2:

5(i2-i1) - 30i2 + 10i3 = 0

Mesh 3:

-10(i3-i1) + 40(i3-i2) + 20i3 = 103.

Solve the equation simultaneously to obtain the current

i2i2 = 0.488A

4. The current flowing through the resistor of value 20 Ω is the same as the current flowing through mesh 1

i = i1 - i2

= 0.562A

b) Using node method

Node analysis is another method of circuit analysis. It is used to determine the voltage and current of a circuit.

Node voltage is the voltage of the node with respect to a reference node. Node voltage is determined using Kirchhoff's Current Law (KCL). The voltage between two nodes is given by the difference between their node voltages.

Connect a resistor of value 20 Ω between terminals a-b and calculate i10

b) Using node method

1. Apply KCL at node A, and assuming the voltage at node A is zero, the equation is as follows:

i10 = (VA - 0) /20Ω + (VA - VB)/5Ω

2. Apply KCL at node B, the equation is as follows:

(VB - VA)/5Ω + (VB - 10V)/30Ω + (VB - 0)/40Ω = 0

3. Substitute VA from Equation 1 into Equation 2, and solve for VB:

VB = 4.033V

4. Substitute VB into Equation 1 to solve for i10:

i10 = 0.202A.

Therefore, the current flowing through the resistor is 0.202A or 202mA.

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Each cell of an automobile 12 volt battery can produce about volts. A) 4.2 B) 4 C) 1.2 D) 2.1

Answers

The correct answer is D) 2.1 volts. Each cell of an automobile 12-volt battery typically produces around 2.1 volts.


Automobile batteries are composed of six individual cells, each generating approximately 2.1 volts. When these cells are connected in series, their voltages add up to form the total voltage of the battery. Therefore, a fully charged 12-volt automobile battery consists of six cells, each producing 2.1 volts, resulting in a total voltage of 12.6 volts (2.1 volts x 6 cells).

This voltage level is suitable for powering various electrical components and starting the engine of a typical automobile. It is important to note that the actual voltage may vary slightly depending on factors such as the battery's state of charge and temperature.

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Exercises on fluid mechanics. Please, What assumptions/assumptions were used in the solution.
Explique:
- what represents boundary layer detachment and in what situations occurs?
- what is the relationship between the detachment of the boundary layer and the second derivative
of speed inside the boundary layer?
- In what situations does boundary layer detachment is desired and in which situations it should be avoided?

Answers

To answer your questions, let's consider the context of fluid mechanics and boundary layers:

Assumptions in the solution: In fluid mechanics, various assumptions are often made to simplify the analysis and mathematical modeling of fluid flow. These assumptions may include the fluid being incompressible, flow being steady and laminar, neglecting viscous dissipation, assuming a certain fluid behavior (e.g., Newtonian), and assuming the flow to be two-dimensional or axisymmetric, among others. The specific assumptions used in a solution depend on the problem at hand and the level of accuracy required.

Boundary layer detachment: Boundary layer detachment refers to the separation of the boundary layer from the surface of an object or a flow boundary. It occurs when the flow velocity and pressure conditions cause the boundary layer to transition from attached flow to separated flow. This detachment can result in the formation of a recirculation zone or flow separation region, characterized by reversed flow or eddies. Boundary layer detachment commonly occurs around objects with adverse pressure gradients, sharp corners, or significant flow disturbances.

Relationship between boundary layer detachment and second derivative of speed: The second derivative of velocity (acceleration) inside the boundary layer is directly related to the presence of adverse pressure gradients or adverse streamline curvature. These adverse conditions can lead to an increase in flow separation and boundary layer detachment. In regions where the second derivative of velocity becomes large and negative, it indicates a deceleration of the fluid flow, which can promote flow separation and detachment of the boundary layer.

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Q10. Select and sketch an appropriate symbol listed in Figure Q10 for ench geometric chracteristic listed below. OV Example: Perpendicularity a) Straightness b) Flatness c) Roundness d) Parallelism e) Symmetry f) Concentricity 수 오우 ㅎㅎ V Figure Q10 10 (6 Marks)

Answers

Figure Q10 lists various symbols used in the geometric tolerance in engineering. The symbols used in engineering indicate the geometrical shape of the object. It is a symbolic representation of an object's shape that is uniform.

Geometric tolerances are essential for ensuring that manufactured components are precise and will work together smoothly. Perpendicularity is shown by a square in Figure Q10. Straightness is represented by a line in Figure Q10.Flatness is indicated by two parallel lines in Figure Q10. Roundness is shown by a circle in Figure Q10. Parallelism is represented by two parallel lines with arrows pointing out in opposite directions in Figure Q10.Symmetry is indicated by a horizontal line that runs through the centre of the shape in Figure Q10. Concentricity is shown by two circles in Figure Q10, with one inside the other. In conclusion, geometric tolerances are essential in engineering and manufacturing. They guarantee that the manufactured components are precise and will function correctly.

The symbols used in engineering represent the geometrical shape of the object and are used to describe it. These symbols make it easier for manufacturers and engineers to understand and communicate the requirements of an object's shape.

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An insulated, rigid tank whose volume is 0.5 m³ is connected by a valve to a large vesset holding steam at 40 bar, 400°C. The tank is initially evacuated. The valve is opened only as long as required to fill the tank with steam to a pressure of 30 bar Determine the final temperature of the steams in the tank, in °C, and the final mass of the steam in the tank, in kg

Answers

The final temperature of steam in the tank is 375/V1°C, and the final mass of steam in the tank is 1041.26 V1 kg.

The given problem is related to the thermodynamics of a closed system. Here, we are given an insulated, rigid tank whose volume is 0.5 m³, and it is connected to a large vessel holding steam at 40 bar and 400°C. The tank is initially evacuated. The valve is opened only as long as required to fill the tank with steam to a pressure of 30 bar. Our objective is to determine the final temperature of the steam in the tank and the final mass of the steam in the tank. We will use the following formula to solve the problem:

PV = mRT

where P is the pressure, V is the volume, m is the mass, R is the gas constant, and T is the temperature.

The gas constant R = 0.287 kJ/kg K for dry air. Here, we assume steam to behave as an ideal gas because it is at high temperature and pressure. Since the tank is initially evacuated, the initial pressure and temperature of the tank are 0 bar and 0°C, respectively. The final pressure of the steam in the tank is 30 bar. Let's find the final temperature of the steam in the tank as follows:

P1V1/T1 = P2V2/T2

whereP1 = 40 bar, V1 = ?, T1 = 400°CP2 = 30 bar, V2 = 0.5 m³, T2 = ?

Rearranging the above formula, we get:

T2 = P2V2T1/P1V1T2 = 30 × 0.5 × 400/(40 × V1)

T2 = 375/V1

The final temperature of steam in the tank is 375/V1°C.

Now let's find the final mass of the steam in the tank as follows:

m = PV/RT

where P = 30 bar, V = 0.5 m³, T = 375/V1R = 0.287 kJ/kg K for dry air

We know that the mass of steam is equal to the mass of water in the tank since all the water in the tank has converted into steam. The density of water at 30 bar is 30.56 kg/m³. Let's find the volume of water required to fill the tank as follows:

V_water = m_water/density = 0.5/30.56 = 0.0164 m³

where m_water is the mass of water required to fill the tank. Since all the water in the tank has converted into steam, the final mass of steam in the tank is equal to m_water. Let's find the final mass of steam in the tank as follows:

m = PV/RT = 30 × 10^5 × 0.5/(0.287 × 375/V1) = 1041.26 V1 kg

The final mass of steam in the tank is 1041.26 V1 kg.

Therefore, the final temperature of steam in the tank is 375/V1°C, and the final mass of steam in the tank is 1041.26 V1 kg.

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Draw the following sinusoidal waveforms: 1. e=-220 cos (wt -20°) 2. i 25 sin (wt + π/3) 3. e = 220 sin (wt -40°) and i = -30 cos (wt + 50°)

Answers

Sinusoidal waveforms are waveforms that repeat in a regular pattern over a fixed interval of time. Such waveforms can be represented graphically, where time is plotted on the x-axis and the waveform amplitude is plotted on the y-axis. The formula for a sinusoidal waveform is given as:

A [tex]sin (wt + Φ)[/tex]

Where A is the amplitude of the waveform, w is the angular frequency, t is the time, and Φ is the phase angle. For a cosine waveform, the formula is given as: A cos (wt + Φ)To draw the following sinusoidal waveforms:

1. [tex]e=-220 cos (wt -20°).[/tex]

The given waveform can be represented as a cosine waveform with amplitude 220 and phase angle -20°. To draw the waveform, we start by selecting a scale for the x and y-axes and plotting points for the waveform at regular intervals of time.

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(DT) Consider a large parallel plate capacitor with a hemispherical bulge on the grounded plate. The bulge has radius a and bulges toward the second plate. The distance between the plates is b.b> a. The second plate is at potential V.. 1. Find the potential everywhere inside the capacitor. 2. Determine the surface charge density on the flat portion of the grounded plate. 3. Determine the surface charge density on the bulge.

Answers

In a large parallel plate capacitor with a hemispherical bulge on the grounded plate, the potential everywhere inside the capacitor can be obtained by solving the Laplace's equation.

The Laplace's equation is a second-order partial differential equation that describes the behavior of the electric potential.

It is given by the equation ∇2V = 0, where V is the electric potential and ∇2 is the Laplacian operator.

The Laplace's equation can be solved using the method of separation of variables.

We can assume that the electric potential is of the form

V(x,y,z) = X(x)Y(y)Z(z),

where x, y, and z are the coordinates of the capacitor.

Substituting this expression into the Laplace's equation, we get:

X''/X + Y''/Y + Z''/Z = 0.

Since the left-hand side of this equation depends only on x, y, and z separately, we can write it as

X''/X + Y''/Y = -Z''/Z = λ2,

where λ is a constant. Solving these equations for X(x), Y(y), and Z(z), we get:

X(x) = A cosh(μx) + B sinh(μx)

Y(y) = C cos(nπy/b) + D sin(nπy/b)

Z(z) = E cosh(λz) + F sinh(λz),

where μ = a/√(b2-a2), n = 1, 2, 3, ..., and E and F are constants that depend on the boundary conditions.

The potential everywhere inside the capacitor is therefore given by:

V(x,y,z) = ∑ Anm cosh(μmx) sin(nπy/b) sinh(λmz),

where Anm are constants that depend on the boundary conditions.

To find the surface charge density on the flat portion of the grounded plate, we can use the boundary condition that the electric field is normal to the surface of the plate.

Since the electric field is given by

E = -∇V,

where V is the electric potential, the normal component of the electric field is given by

E·n = -∂V/∂n,

where n is the unit normal vector to the surface of the plate.

The surface charge density is then given by

σ = -ε0 E·n,

where ε0 is the permittivity of free space.

To find the surface charge density on the bulge, we can use the same method and the boundary condition that the electric field is normal to the surface of the bulge.

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The manufacturer of a component that will be subjected to fatigue from -0 MPa to 50 MPa, specifies that it must be changed when it has been detected that the crack has advanced up to 40% of its critical value. The manufacturing process of the component leaves cracks on the surface of 0.1mm. The material has the following properties: KIC = 70MPam1/2 and crack growth is characterized by n=3.1 and C= 10E-11. Assume f=1.12.
How many life cycles did the component have left after it had been removed as directed by the manufacturer?
Indicate your answer without decimals.

Answers

Fatigue is the weakening of a material caused by cyclic loading, resulting in the formation and propagation of cracks.

Fatigue fracture failure is a type of failure that is caused by cyclic loading, which is the progressive growth of an initial crack until it reaches a critical size and a fracture occurs. In this question, we are given the following information.

The manufacturing process of the component leaves cracks on the surface of 0.1mm.The material has the following properties: [tex]KIC = 70 MPam1/2[/tex], and crack growth is characterized by n = 3.1 and C = 10E-11. Assume f = 1.12.Calculations:In this question.

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Question 3: Design Problem (2 Points) 1. In which of the application below would you allow for overshoot? State why (2) and why not. (tick the ones that doesn't allow overshoot) • Water Level . Elevator . Cruise Control • Air Conditioning Water flow rate into a vessel

Answers

Among the given applications (Water Level, Elevator, Cruise Control, Air Conditioning, and Water flow rate into a vessel), the application that allows for overshoot is Cruise Control.

Cruise Control is an application where allowing overshoot can be acceptable. Overshoot refers to a temporary increase in speed beyond the desired setpoint. In Cruise Control, overshoot can be allowed to provide a temporary acceleration to reach the desired speed quickly. Once the desired speed is achieved, the control system can then adjust to maintain the speed within the desired range. On the other hand, the other applications listed do not typically allow overshoot. In Water Level control, overshoot can cause flooding or damage to the system. Elevator control needs precise positioning without overshoot to ensure passenger safety and comfort.

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Given that v(t) = 120 sin(300t + 45°) V and i(t) = 10 cos(300t – 10°)A, find the followings
A. Whats the phasor of V(t)
B. Period of the i(t)
C. Phasor of i(t) in complex form

Answers

A. Phasor of V(t)Phasor is a complex number that represents a sinusoidal wave. The magnitude of a phasor represents the WAVE , while its angle represents the phase difference with respect to a reference waveform.

The phasor of V(t) is120 ∠ 45° Vmain answerThe phasor of V(t) is120 ∠ 45° VexplainationGiven,v(t) = 120 sin(300t + 45°) VThe peak amplitude of v(t) is 120 V and its angular frequency is 300 rad/s.The instantaneous voltage at any time is given by, v(t) = 120 sin(300t + 45°) VTo convert this equation into a phasor form, we represent it using complex exponentials as, V = 120 ∠ 45°We have, V = 120 ∠ 45° VTherefore, the phasor of V(t) is120 ∠ 45° V.B. Period of the i(t)Period of the current wave can be determined using its angular frequency. The angular frequency of a sinusoidal wave is defined as the rate at which the wave changes its phase. It is measured in radians per second (rad/s).The period of the current wave isT = 2π/ω

The period of the current wave is1/50 secondsexplainationGiven,i(t) = 10 cos(300t – 10°)AThe angular frequency of the wave is 300 rad/s.Therefore, the period of the wave is,T = 2π/ω = 2π/300 = 1/50 seconds.Therefore, the period of the current wave is1/50 seconds.C. Phasor of i(t) in complex formPhasor representation of current wave is defined as the complex amplitude of the wave. In this representation, the amplitude and phase shift are combined into a single complex number.The phasor of i(t) is10 ∠ -10° A. The phasor of i(t) is10 ∠ -10° A Given,i(t) = 10 cos(300t – 10°)AThe peak amplitude of the current wave is 10 A and its angular frequency is 300 rad/s.The instantaneous current at any time is given by, i(t) = 10 cos(300t – 10°)A.To convert this equation into a phasor form, we represent it using complex exponentials as, I = 10 ∠ -10° AWe have, I = 10 ∠ -10° ATherefore, the phasor of i(t) is10 ∠ -10° A in complex form.

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A block of iron weighs 100 kg and has a temperature of 100°C. When this block of iron is immersed in 50 kg of water at a temperature of 20°C, what will be the change of entropy of the combined system of iron and water? For the iron dq = 0.11dT, and for the water dq = 1.0dT, wherein q denotes heat transfer in cal/g and 7 denotes temperature in °K.

Answers

The change of entropy for the combined system of iron and water is approximately -0.015 cal/K.

We have,

To calculate the change of entropy for the combined system of iron and water, we can use the equation:

ΔS = ΔS_iron + ΔS_water

where ΔS_iron is the change of entropy for the iron and ΔS_water is the change of entropy for the water.

Given:

Mass of iron (m_iron) = 100 kg

Temperature of iron (T_iron) = 100°C = 373 K

Specific heat capacity of iron (C_iron) = 0.11 cal/g°C

Mass of water (m_water) = 50 kg

Temperature of water (T_water) = 20°C = 293 K

Specific heat capacity of water (C_water) = 1.0 cal/g°C

Let's calculate the change of entropy for the iron and water:

ΔS_iron = ∫(dq_iron / T_iron)

= ∫(C_iron * dT / T_iron)

= C_iron * ln(T_iron_final / T_iron_initial)

ΔS_water = ∫(dq_water / T_water)

= ∫(C_water * dT / T_water)

= C_water * ln(T_water_final / T_water_initial)

Substituting the given values:

ΔS_iron = 0.11 * ln(T_iron_final / T_iron_initial)

= 0.11 * ln(T_iron / T_iron_initial) (Since T_iron_final = T_iron)

ΔS_water = 1.0 * ln(T_water_final / T_water_initial)

= 1.0 * ln(T_water / T_water_initial) (Since T_water_final = T_water)

Now, let's calculate the final temperatures for iron and water after they reach thermal equilibrium:

For iron:

Heat gained by iron (q_iron) = Heat lost by water (q_water)

m_iron * C_iron * (T_iron_final - T_iron) = m_water * C_water * (T_water - T_water_final)

Solving for T_iron_final:

T_iron_final = (m_water * C_water * T_water + m_iron * C_iron * T_iron) / (m_water * C_water + m_iron * C_iron)

Substituting the given values:

T_iron_final = (50 * 1.0 * 293 + 100 * 0.11 * 373) / (50 * 1.0 + 100 * 0.11)

≈ 312.61 K

For water, T_water_final = T_iron_final = 312.61 K

Now we can substitute the calculated temperatures into the entropy change equations:

ΔS_iron = 0.11 * ln(T_iron / T_iron_initial)

= 0.11 * ln(312.61 / 373)

≈ -0.080 cal/K

ΔS_water = 1.0 * ln(T_water / T_water_initial)

= 1.0 * ln(312.61 / 293)

≈ 0.065 cal/K

Finally, the total change of entropy for the combined system is:

ΔS = ΔS_iron + ΔS_water

= -0.080 + 0.065

≈ -0.015 cal/K

Therefore,

The change of entropy for the combined system of iron and water is approximately -0.015 cal/K.

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2.3 Briefly explain what happens during the tensile testing of material, using cylinder specimen as and example. 2.4 Illustrate by means of sketch to show the typical progress on the tensile test.

Answers

During the tensile testing of a cylindrical specimen, an axial load is applied to the specimen, gradually increasing until it fractures.

The test helps determine the material's mechanical properties. Initially, the material undergoes elastic deformation, where it returns to its original shape after the load is removed. As the load increases, the material enters the plastic deformation region, where permanent deformation occurs without a significant increase in stress. The material may start to neck down, reducing its cross-sectional area. Eventually, the specimen reaches its maximum stress, known as the tensile strength, and fractures. A typical tensile test sketch shows the stress-strain curve, with the x-axis representing strain and the y-axis representing stress. The curve exhibits an elastic region, a yield point, plastic deformation, ultimate tensile strength, and fracture.

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An airplane flying at an altitude of z=2000 m with a horizontal velocity V=120 km/h pulls an advertising banner with a height of h=3 m and a length of l=5m. If the banner acts as a smooth flat plate, find the following a. The critical length (Xcr) in meters b. Drag coefficient of the banner c. Drag force acting on the banner in Newtons d. The power required to overcome banner drag in Watts

Answers

Given: Altitude of the airplane, z = 2000m

Horizontal velocity of airplane, V = 120 km/h = 33.33 m/s

Height of the banner, h = 3 m

Length of the banner, l = 5 m

Density of the air, ρ = 1.23 kg/m³

Dynamic viscosity of air, μ = 1.82 × 10⁻⁵ kg/m-s

Part (a): Critical length of the banner (Xcr) is given as:

Xcr = 5.0h

= 5.0 × 3.0

= 15.0 m

Part (b):The drag coefficient (Cd) is given as:

Cd = (2Fd)/(ρAV²) ... (1)Where,

Fd is the drag force acting on the banner in Newtons

A is the area of the banner in m²V is the velocity of airplane in m/s

From Bernoulli's equation,The velocity of air flowing over the top of the banner will be more than the velocity of air flowing below the banner.

As a result, the air pressure on top of the banner will be lesser than the air pressure below the banner. This produces a net upward force on the banner called lift.

To simplify the problem, we can ignore the lift forces and assume that the banner acts as a smooth flat plate.

Now the drag force acting on the banner is given as:

Fd = (1/2)ρCDAV² ... (2)

where, Cd is the drag coefficient of the banner.

A is the area of the banner

= hl

= 3.0 × 5.0

= 15.0 m²

Substituting equation (2) in (1),

Cd = (2Fd)/(ρAV²)

= (2 × (1/2)ρCDAV²)/(ρAV²)Cd

= 2(Cd)/(A)V²

From equation (2),

Fd = (1/2)ρCDAV²

Substituting the values, Cd = 0.603

Part (c):The drag force acting on the banner is given as:

Fd = (1/2)ρCDAV²

Substituting the values, we get;

Fd = (1/2) × 1.23 × 0.603 × 15.0 × 33.33²

= 1480.0 N

Part (d):The power required to overcome the banner drag is given by:

P = FdV = 1480.0 × 33.33 = 49331.4 WP

= 49.3 kW

Given the altitude and horizontal velocity of an airplane along with the banner's length and height, we found the critical length, drag coefficient, drag force and power required to overcome the banner drag.

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5. Perform addition and multiplication of the following numbers a. 58.3125 10

and BD 16

b. C9 16

and 28 10

c. 1101 2

and 72 8

Solution:

Answers

Addition and multiplication of numbers are among the fundamental operations in mathematics. The following are the addition and multiplication of the given numbers:
a) 58.3125 10 + BD 16 = 58.3125 10 + 303 10 = 361.3125 10
Multiplication 58.3125 10 × BD 16 = 58.3125 10 × 303 10 = 17662.0625 10
b) C9 16 + 28 10 = 201 16 + 28 10 = 245 10
Multiplication: C9 16 × 28 10 = 3244 16
c) 1101 2 + 72 8 = 13 10 + 58 10 = 71 10
Multiplication: 1101 2 × 72 8 = 101100 2 × 58 10 = 10110000 2

Performing addition and multiplication is an essential mathematical operation that is used in solving different problems. In the above question, we have shown how to perform addition and multiplication of different numbers, including decimals and binary numbers. Therefore, students should have an in-depth understanding of addition and multiplication to solve more complex mathematical problems.

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The gas-turbine cycle of a combined gas-steam power plant has a pressure ratio of 8. Air 300k 1500 enters the compressor at 290 K and the turbine at 1400 K. The combustion gases leaving the yoo gas turbine are used to heat the steam at 15 MPa to 450°C in a heat exchanger. The combustion 120k gases leave the heat exchanger at 247°C. Steam expands in a high-pressure turbine to a pressure of 3 MPa and is reheated in the combustion chamber to 500°C before it expands in a low- pressure turbine to 10 Pa. The mass flow rate of steam is 30 kg/s. Assuming all the compression and expansion processes to be isentropic. For steady-state operation and kinetic and potential energy changes are negligible, and constant specific heat with Cp-1.023 kJ/kg.K. k=1.4 is used. Determine (i) the mass flow rate of air in the gas-turbine cycle, Gil) the rate of 2 total heat input, and (in) the thermal efficiency of the combined cycle.

Answers

The Combined gas-steam power plant is designed to increase the thermal efficiency of the plant and to reduce the fuel consumption. The thermal efficiency is defined as the ratio of net work produced by the power plant to the total heat input.

The heat transferred to the steam per kg of steam is given by: Q/m = h5 - h4 Q

= m(h5 - h4) The temperature of the steam T5 can be calculated using the steam tables. At a pressure of 15 MPa, the enthalpy of the steam h4 = 3127.1 kJ/kg The temperature of the steam T5

= 450 °C

= 723 K At state 5, the steam is expanded isentropically in a high-pressure turbine to a pressure of 3 MPa. The work done by the high-pressure turbine per kg of steam is given by: Wh/m = Cp(T5 - T6) Wh

= mCp(T5 - T6) The temperature T6 can be calculated as: T6/T5 = (3 MPa/15 MPa)k-1/k T6

= T5(3/15)0.4

= 533.16 K The temperature T5 can be calculated using the steam tables.

The rate of total heat input to the cycle is given by: Qh = mCp(T3 - T2) + Q + m(h5 - h4) + mCp(T7 - T6) Qh

= 35.046 × 1.023 × (977.956 - 698.54) + 35.046 × 728.064 + 30 × (3127.1 - 2935.2) + 30 × 1.023 × (746.624 - 533.16) Qh = 288,351.78 kJ/s Thermal efficiency: The thermal efficiency of the cycle is given by: ηth

= (Wh + Wl)/Qh ηth

= (18,449.14 + 22,838.74)/288,351.78 ηth

= 0.1426 or 14.26 % The mass flow rate of air in the gas-turbine cycle is 35.046 kg/s.The total heat input is 288,351.78 kJ/s.The thermal efficiency of the combined cycle is 14.26 %.

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Assume that we have the following bit sequence that we want to transmit over a cable by using the Gaussian pulse as the basis signal. 0011001010 and the Guassian pulse is the same as before g(t) = e⁻ᶜ¹ᵗ² (a) Plot the signal sent if Manchester Encoding is used. (b) Plot the signal sent if Differential Encoding is used. (c) What is the data rate you get based on your coefficients for Part (a) and Part (b)? You can assume some overlapping between the pulses in time domain but your assumption must be the same for both cases. (d) compare these two encodings in terms of different system parameters like BW, data rate, DC level, and ease of implementation.

Answers

(a) Plot the signal sent if Manchester Encoding is usedIf Manchester Encoding is used, the encoding for a binary one is a high voltage for the first half of the bit period and a low voltage for the second half of the bit period. For the binary zero, the reverse is true.

The bit sequence is 0011001010, so the signal sent using Manchester encoding is shown below: (b) Plot the signal sent if Differential Encoding is used.If differential encoding is used, the first bit is modulated by transmitting a pulse in the initial interval.

To transfer the second and future bits, the phase of the pulse is changed if the bit is 0 and kept the same if the bit is 1. The bit sequence is 0011001010, so the signal sent using differential encoding is shown below: (c) Data rate for both (a) and (b) is as follows:

Manchester EncodingThe signal is transmitted at a rate of 1 bit per bit interval. The bit period is the amount of time it takes to transmit one bit. The signal is repeated for each bit in the bit sequence in Manchester Encoding. The data rate is equal to the bit rate, which is 1 bit per bit interval.Differential EncodingThe signal is transmitted at a rate of 1 bit per bit interval.

The bit period is the amount of time it takes to transmit one bit. The signal is repeated for each bit in the bit sequence in Differential Encoding. The data rate is equal to the bit rate, which is 1 bit per bit interval.

(d)Comparison between the two encodings:

Manchester encoding and differential encoding differ in several ways. Manchester encoding has a higher data rate but a greater DC offset than differential encoding. Differential encoding, on the other hand, has a lower data rate but a smaller DC offset than Manchester encoding.

Differential encoding is simpler to apply than Manchester encoding, which involves changing the pulse's voltage level.

However, Manchester encoding is more reliable than differential encoding because it has no DC component, which can cause errors during transmission. Differential encoding is also less prone to noise than Manchester encoding, which is more susceptible to noise because it uses a narrow pulse.

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which of the following is the True For Goodman diagram in fatigue ? a. Can predict safe life for materials. b. adjust the endurance limit to account for mean stress c. both a and b d. none

Answers

The correct option for the True For Goodman diagram in fatigue is (C) i.e. Both a and b, i.e.Can predict safe life for materials. b. adjust the endurance limit to account for mean stress.

The Goodman diagram is a widely used tool in the industry to analyze the fatigue behavior of materials. In the engineering sector, this diagram is commonly employed in the evaluation of mechanical and structural component materials that are subjected to dynamic loads. In a Goodman diagram, the load range is plotted along the x-axis, while the midrange of the load is plotted along the y-axis.

On the same graph, the diagram includes the alternating and static stresses. A dotted line connects the point where the material's fatigue limit meets the horizontal x-axis to the alternating stress line. It ensures that no additional material damage occurs due to the changes in the mean stress. The correct statement for the True For Goodman diagram in fatigue is option C, Both a and b. The Goodman diagram can predict a safe life for materials and adjust the endurance limit to account for mean stress.

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You have identified a business opportunity in an underground mine where you work. You have noticed that female employees struggle with a one-piece overall when they use the bathroom. So, to save them time, you want to design a one-piece overall that offers flexibility without having to take off the whole overall. You have approached the executives of the mine to pitch this idea and they requested that you submit a business plan so they can be able to make an informed business decision.
Use the information on pages 460 – 461 of the prescribed book to draft a simple business plan. Your business plan must include all the topics below.
1. Executive summary
2. Description of the product and the problem worth solving
3. Capital required
4. Profit projections
5. Target market
6. SWOT analysis

Answers

Business Plan for a Female One-piece Overall Design Executive SummaryThe company will be established to manufacture a one-piece overall for female employees working in the underground mine. The product is designed to offer flexibility to female employees when they use the bathroom without removing the whole overall.

The product is expected to solve the problem of wasting time while removing the overall while working underground. The overall product is designed with several features that will offer value to the customer. The company is expected to generate revenue through sales of the overall to female employees in the mine.

2. Description of the Product and the Problem Worth SolvingThe female one-piece overall is designed to offer flexibility to female employees working in the underground mine when they use the bathroom. Currently, female employees struggle with removing the whole overall when they use the bathroom, which wastes their time. The product is designed to offer value to the customer by addressing the challenges that female employees face while working in the underground mine.

3. Capital RequiredThe company will require a capital investment of $250,000. The capital will be used to develop the product, manufacture, and distribute the product to customers.

4. Profit ProjectionsThe company is expected to generate $1,000,000 in revenue in the first year of operation. The revenue is expected to increase by 10% in the following years. The company's profit margin is expected to be 20% in the first year, and it is expected to increase to 30% in the following years.

5. Target MarketThe target market for the female one-piece overall is female employees working in the underground mine. The market segment comprises of 2,500 female employees working in the mine.

6. SWOT AnalysisStrengths: Innovative product design, potential for high-profit margins, and an untapped market opportunity. Weaknesses: Limited target market and high initial investment costs. Opportunities: Ability to diversify the product line and expand the target market. Threats: Competition from existing companies that manufacture overalls and market uncertainty.

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Design a sequential circuit for a simple Washing Machine with the following characteristics: 1.- Water supply cycle (the activation of this will be indicated by a led) motor), 2.- Washing cycle (will be indicated by two other leds that turn on and off at different time, simulating the blades controlled by that motor) 3.- Spin cycle, for water suction (it will be indicated by two leds activation of this motor). Obtain the K maps and the state diagram.

Answers

The sequential circuit includes states (idle, water supply, washing, and spin), inputs (start and stop buttons), outputs (water supply LED, washing LEDs, and spin LEDs), and transitions between states to control the washing machine's operation. Karnaugh maps and a state diagram are used for designing the circuit.

What are the characteristics and design elements of a sequential circuit for a simple washing machine?

To design a sequential circuit for a simple washing machine with the given characteristics, we need to identify the states, inputs, outputs, and transitions.

1. States:

  a. Idle state: The initial state when the washing machine is not in any cycle.

  b. Water supply state: The state where water supply is activated.

  c. Washing state: The state where the washing cycle is active.

  d. Spin state: The state where the spin cycle is active.

2. Inputs:

  a. Start button: Used to initiate the washing machine cycle.

  b. Stop button: Used to stop the washing machine cycle.

3. Outputs:

  a. Water supply LED: Indicate the activation of the water supply cycle.

  b. Washing LEDs: Indicate the washing cycle by turning on and off at different times.

  c. Spin LEDs: Indicate the activation of the spin cycle for water suction.

4. Transitions:

  a. Idle state -> Water supply state: When the Start button is pressed.

  b. Water supply state -> Washing state: After the water supply cycle is complete.

  c. Washing state -> Spin state: After the washing cycle is complete.

  d. Spin state -> Idle state: When the Stop button is pressed.

Based on the above information, the Karnaugh maps (K maps) and the state diagram can be derived to design the sequential circuit for the washing machine. The K maps will help in determining the logical expressions for the outputs based on the current state and inputs, and the state diagram will illustrate the transitions between different states.

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15.31 Design a parallel bandreject filter with a center fre- quency of 1000 rad/s, a bandwidth of 4000 rad/s, and a passband gain of 6. Use 0.2 μF capacitors, and specify all resistor values.

Answers

To design a parallel bandreject filter with the given specifications, we can use an RLC circuit. Here's how you can calculate the resistor and inductor values:

Given:

Center frequency (f0) = 1000 rad/s

Bandwidth (B) = 4000 rad/s

Passband gain (Av) = 6

Capacitor value (C) = 0.2 μF

Calculate the resistor value (R):

Use the formula R = Av / (B * C)

R = 6 / (4000 * 0.2 * 10^(-6)) = 7.5 kΩ

Calculate the inductor value (L):

Use the formula L = 1 / (B * C)

L = 1 / (4000 * 0.2 * 10^(-6)) = 12.5 H

So, for the parallel bandreject filter with a center frequency of 1000 rad/s, a bandwidth of 4000 rad/s, and a passband gain of 6, you would use a resistor value of 7.5 kΩ and an inductor value of 12.5 H. Please note that these are ideal values and may need to be adjusted based on component availability and practical considerations.

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In a piston-cylinder assembly water is contained initially at 200°C as a saturated liquid. The piston moves freely in the cylinder as water undergoes a process to the corresponding saturated vapor state. There is no heat transfer with the surroundings. This change of state is brought by the action of paddle wheel. Determine the amount obowa of entropy produced per unit mass, in kJ/kg · K.

Answers

The given problem is solved as follows: As we know that the entropy can be calculated using the following formula,

[tex]S2-S1 = integral (dq/T)[/tex]

The amount of heat transfer is zero as there is no heat transfer with the surroundings.

The work done during the process is given by the area under the

P-V curve,

w=P(V2-V1)

As the process is isothermal,

the work done is given by the following equation

w=nRT ln (V2/V1)

For a saturated liquid, the specific volume is

vf = 0.001043m³/kg and for a saturated vapor, the specific volume is vg = 1.6945m³/kg.

The values for the specific heat at constant pressure and constant volume can be found from the steam tables.

Using these values, we can calculate the change in entropy.Change in entropy,

S2-S1 = integral(dq/T)

= 0V1 = vf

= 0.001043m³/kgV2 = vg

= 1.6945m³/kgw

= P(V2-V1)

= 100000(1.6945-0.001043)

= 169.405 J/moln

= 1/0.001043

= 958.86 molR

= 8.314 JK-1mol-1T = 200 + 273

= 473 KSo, w = nRT ln (V2/V1)

=> 169.405

= 958.86*8.314*ln(1.6945/0.001043)

Thus, ΔS = S2 - S1

= 959 [8.314 ln (1.6945/0.001043)]/473

= 8.3718 J/Kg K

∴ The amount of entropy produced per unit mass is 8.3718 J/Kg K

In this question, the amount of entropy produced per unit mass is to be calculated in the given piston-cylinder assembly which contains water initially at 200°C as a saturated liquid. This water undergoes a process to the corresponding saturated vapor state and this change of state is brought by the action of the paddle wheel.

It is given that there is no heat transfer with the surroundings. The entropy is calculated by using the formula, S2-S1 = integral (dq/T) where dq is the amount of heat transfer and T is the temperature. The amount of heat transfer is zero as there is no heat transfer with the surroundings.

The work done during the process is given by the area under the P-V curve. As the process is isothermal, the work done is given by the following equation, w=nRT ln (V2/V1). For a saturated liquid, the specific volume is vf = 0.001043m³/kg and for a saturated vapor, the specific volume is vg = 1.6945m³/kg. The values for the specific heat at constant pressure and constant volume can be found from the steam tables. Using these values, we can calculate the change in entropy.

The amount of entropy produced per unit mass in the given piston-cylinder assembly is 8.3718 J/Kg K.

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1. The adiabatic turbine of a gas turbine engine operates at steady state. a) Working from first principles, using an appropriate property diagram and explaining each stage in the derivation, show that the power output is given by: W = mc₂n, T. (1-(1/r₂Y₁-1) P where m is the mass flowrate of a (perfect) gas through the turbine; c, and y are the specific heat at constant pressure and ratio of specific heats of that gas; ns, and are the turbine isentropic efficiency and expansion pressure ratio, respectively; Te is the turbine entry temperature. Gas velocity may be assumed to be low throughout. Assume universal gas constant R = 8.3145 J.K-1.mol-¹ [15 Marks] b) For a turbine entry temperature of 1500 K, an isentropic efficiency of 85 % and an expansion pressure ratio of 8, estimate the turbine exit temperature if the gas has a mean molar mass (M) of 28.6 kg/kmol and a mean specific heat at constant pressure of 1.23 kJ/kgK. [10 Marks]

Answers

The equation will involve parameters such as mass flow rate, specific heat at constant pressure, ratio of specific heats, turbine isentropic efficiency, expansion pressure ratio, and turbine entry temperature.  

a) To derive the power output equation for the adiabatic turbine, we start by considering the first law of thermodynamics applied to a control volume around the turbine. By assuming steady state and adiabatic conditions, we can simplify the equation and express the work output (W) as a function of the given parameters. This derivation can be done using an appropriate property diagram, such as the T-s diagram.

Each stage in the derivation involves manipulating the equation, substituting appropriate values, and applying thermodynamic principles. The specific heat at constant pressure (cₚ) and the ratio of specific heats (γ) are properties of the gas, while the isentropic efficiency (ηs) and expansion pressure ratio (r₂) represent the performance characteristics of the turbine. The turbine entry temperature (Te) is the initial temperature of the gas entering the turbine.

b) Using the derived power output equation and the given values of turbine entry temperature (Te), isentropic efficiency (ηs), expansion pressure ratio (r₂), molar mass (M), and specific heat at constant pressure (cₚ), we can substitute these values to calculate the turbine exit temperature. The calculation involves manipulating the equation algebraically and using the given values to obtain the desired result.

By evaluating the turbine exit temperature, we can assess the performance of the turbine under the given conditions and understand the thermodynamic behavior of the gas as it passes through the turbine stages.

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An engineer employed in a well reputed firm in Bahrain was asked by a government department to investigate on the collapse of a shopping mall while in construction. Upon conducting analysis on various raw materials used in construction as well as certain analysis concerning the foundation strength, the engineer concluded that the raw materials used in the construction were not proper. Upon further enquiry it was found out that the supplier of the project was to be blamed. The supplying company in question was having ties with the company the engineer was working. So upon preparation of final report the engineer did not mention what is the actual cause of the collapse or the supplying company. But when it reached the higher management they forced engineer to *include* the mentioning of the supplying company in the report. Conduct an ethical analysis in this case with a proper justification of applicable 2 NSPE codes.

Answers

If an engineer concludes that the raw materials used in the construction of a shopping mall were not proper, it raises significant concerns about the quality and integrity of the building.

In such a situation, the engineer should take the following steps.Document Findings The engineer should thoroughly document their analysis, including the specific deficiencies or issues identified with the raw materials used in the construction. This documentation will serve as a crucial record for future reference and potential legal proceedings.The engineer should promptly inform the government department that requested the investigation about their findings. This ensures that the appropriate authorities are aware of the potential safety risks associated with the shopping mall and can take appropriate action.

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